One of the properties of a parabola is that it can act as a reflector. In a reflector, any ray that is __________ to the axis of symmetry will be reflected off the surface to the focus. A. a bisector B. parallel C. perpendicular D. similar

On solving this trigonometry, we find that (a) sec(sin⁻¹ [tex]\frac{12}{13}[/tex]) = [tex]\frac{13}{5}[/tex] and (b) tan(sin⁻¹ [tex]\frac{12}{13}[/tex]) = [tex]\frac{12}{5}[/tex]

(a) To find the exact value of sec(sin⁻¹ [tex]\frac{12}{13}[/tex]), we can use the fact that sec(x) = [tex]\frac{1}{cos}[/tex](x). Let's draw a right triangle with opposite side 12 and hypotenuse 13. Using the Pythagorean theorem, we can find the adjacent side:

a² + b² = c²

a² + 12² = 13²

a² = 169 - 144

a = √25

a = 5

So our triangle has sides of length 5, 12, and 13. Now we can find cos(sin⁻¹  [tex]\frac{12}{13}[/tex]) by looking at the adjacent/hypotenuse ratio in this triangle:

cos(sin⁻¹ [tex]\frac{12}{13}[/tex]) =  [tex]\frac{5}{13}[/tex]

Therefore, sec(sin⁻¹(12/13)) = 1/cos(sin⁻¹ [tex]\frac{12}{13}[/tex])

                                            = 1/[tex]\frac{5}{13}[/tex]

                                            = [tex]\frac{13}{5}[/tex].

So the exact value of sec(sin⁻¹ [tex]\frac{12}{13}[/tex]) is [tex]\frac{13}{5}[/tex].

(b) To find the exact value of tan(sin⁻¹ [tex]\frac{12}{13}[/tex]), we can use the fact that tan(x) = sin(x)/cos(x). Let's use the same right triangle as before.

Then sin(sin⁻¹ [tex]\frac{12}{13}[/tex])=  [tex]\frac{12}{13}[/tex] and cos  [tex]\frac{12}{13}[/tex]) = [tex]\frac{5}{13}[/tex]  , so

tan(sin⁻¹ [tex]\frac{12}{13}[/tex]) = sin(sin⁻¹ [tex]\frac{12}{13}[/tex])/cos(sin⁻¹[tex]\frac{12}{13}[/tex])

                        = [tex]\frac{12}{13}[/tex] / [tex]\frac{5}{3}[/tex]

                        = [tex]\frac{12}{5}[/tex]

So the exact value of tan(sin⁻¹ [tex]\frac{12}{13}[/tex]) is [tex]\frac{12}{5}[/tex].

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Answer:

To find the dimensions of the actual painting, we need to use the scale factor of 4:1. This means that the actual dimensions of the painting are four times larger than the scaled dimensions.

Let's start with the width of the actual painting:

8 inches (scaled width) × 4 = 32 inches (actual width)

Now, let's find the height of the actual painting:

10 inches (scaled height) × 4 = 40 inches (actual height)

Therefore, the dimensions of the actual painting are 32 inches by 40 inches.

The answers are explained in the solution.

Given is a circle F,

The central angle = ∠GFH

The semicircle = arc GJI

The major arc = arc GJH

Since, the measure of semicircle is 180°, therefore,

The semicircle = arc GJI = 180°

We know that the measure of arc intercepted by the central angle is equal to the measure of the central angle.

Therefore, ∠GFH = 125°

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The time it would take to run 625,000 miles depends on several factors such as the speed at which one is running and how often they take breaks.

Assuming a constant speed of 6 miles per hour, which is a moderate running pace, it would take approximately 104,166.67 hours or 4,340.28 days or 11.89 years to run 625,000 miles without taking any breaks. However, in reality, one would need to take breaks for rest and recovery, so the actual time it would take to cover this distance would be longer.

Assuming a constant speed of 6 miles per hour, it would take approximately 104,166.67 hours to run 625,000 miles without taking any breaks. This equates to 4,340.28 days or 11.89 years. However, in reality, taking breaks for rest and recovery is necessary, so the actual time it would take to cover this distance would be longer.

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Answer:

The formula for the volume of the cylinder is =²ℎ, which is equivalent to =²ℎ, where is the radius of the cylinder, is the diameter of the cylinder, and ℎ is the height of the cylinder. Therefore, the correct answer is d. V=pix^2.

Step-by-step explanation:

B. The data shows a positive, linear association.

To determine the association between height and weight of the ten boys, we will first observe the data points provided. We can compare the increase or decrease in height with the corresponding increase or decrease in weight to identify a pattern.

Here's a list of height and weight pairs:
(60, 125), (63, 139), (65, 155), (61, 136), (70, 170), (55, 108), (58, 116), (61, 139), (64, 129), (57, 121)

Upon observing these pairs, we can see that as height increases, weight generally increases as well. For example, when height increases from 55 inches to 70 inches, weight increases from 108 pounds to 170 pounds. This pattern can also be seen in other data pairs.

This means that there is a direct relationship between the height and weight of the boys, where taller boys tend to weigh more, and shorter boys tend to weigh less.

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The factors to the given expression are -1(x+3)(x-8)

The x-intercepts of the quadratic relationship are -3, 8. When we write an expression in its factors and multiplying those factors gives us the original expression, then this process is known as factorization.

How do we factorize the given expression?

We equate the given expression to f(x)

   (-[tex]x^{2}[/tex] + 5x + 24) = f(x)

⇒ -1([tex]x^{2}[/tex] - 5x - 24) = f(x)

⇒ -1([tex]x^{2}[/tex] - (8-3)x - 24) = f(x)

⇒ -1([tex]x^{2}[/tex] + 3x - 8x -24) = f(x)

⇒ -1(x(x+3) -8(x+3)) = f(x)

⇒ -1(x+3)(x-8) = f(x)

∴The factor to the given expression is -1(x+3)(x-8)

How do we find the x-intercepts?

We equate f(x) = 0 to find the x-intercepts.

⇒ -1(x+3)(x-8) = 0

⇒ (x+3)(x-8) = 0

The roots of the above equation are x-intercepts.

Therefore, the x-intercepts occur where x = -3 and x = 8

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The complete question is "Factor the expression (-x^2 + 5x + 24.) and use the factors to find the x-intercepts of the quadratic relationship it represents.

Type the correct answer in each box, starting with the intercept with the lower value.

The x-intercepts occur where x =

and x = "

The points of inflection are (0, 3π), (π, 4π), and (2π, 9π).

To find the maximum/minimum and inflection points of the function y = 5 sin x + 3x, we need to take the first and second derivatives of the function with respect to x, and then find the critical points and points of inflection by setting these derivatives equal to zero.

First derivative:

y' = 5 cos x + 3

Setting y' = 0 to find critical points:

5 cos x + 3 = 0

cos x = -3/5

Using a calculator or reference table, we can find the two values of x between 0 and 2π that satisfy this equation: x ≈ 2.300 and x ≈ 3.840.

Second derivative:

y'' = -5 sin x

At x = 2.300, y'' < 0, so we have a local maximum.

At x = 3.840, y'' > 0, so we have a local

To check whether these are global maxima/minima, we need to examine the behavior of the function near the endpoints of the interval 0 < x < 2π.

When x = 0, y = 0 + 0 = 0.

When x = 2π, y = 5 sin (2π) + 6π = 6π, since sin(2π) = 0.

So the function is increasing on the interval [0, 2.300], reaches a local maximum at x = 2.300, is decreasing on the interval [2.300, 3.840], reaches a local minimum at x = 3.840, and then is increasing on the interval [3.840, 2π]. Therefore, the maximum value of the function occurs at x = 2π, where y = 6π, and the minimum value of the function occurs at x = 3.840, where y ≈ 1.221.

To find the points of inflection, we set y'' = 0:

-5 sin x = 0

This equation is satisfied when x = 0, π, and 2π. We can use the second derivative test to determine whether these are points of inflection or not.

At x = 0, y'' = 0, so we need to examine the behavior of the function near x = 0.

When x is close to 0 from the right, y is positive and increasing, so we have a point of inflection at x = 0.

At x = π, y'' = 0, so we need to examine the behavior of the function near x = π.

When x is close to π from the left, y is negative and decreasing, so we have a point of inflection at x = π.

At x = 2π, y'' = 0, so we need to examine the behavior of the function near x = 2π.

When x is close to 2π from the right, y is positive and increasing, so we have a point of inflection at x = 2π.

Therefore, the points of inflection are (0, 3π), (π, 4π), and (2π, 9π).

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To find the average number of bits required to encode this source using a Huffman code, we need to first construct the Huffman code for the given probabilities. The Huffman code assigns shorter codes to more probable values and longer codes to less probable values. We can start by listing the probabilities in descending order:

0.2, 0.15, 0.15, 0.15, 0.15, 0.1, 0.1

Next, we group the two least probable values and assign them a code of 0. We then repeat this process, grouping the next two least probable values and assigning them a code of 10. We continue until we have assigned codes to all values:

7: 0
1: 1000
2: 1001
3: 1010
4: 1011
5: 110
6: 111

We can see that the average number of bits required to encode this source using the Huffman code is:

(0.2 x 1) + (0.1 x 4) + (0.1 x 4) + (0.15 x 4) + (0.15 x 4) + (0.15 x 3) + (0.2 x 3) = 2.771 bits

Therefore, the correct answer is b) 2.771 bits.
To find the average number of bits required to encode this source using a Huffman code, follow these steps:

1. Arrange the probabilities in descending order: 0.2, 0.15, 0.15, 0.15, 0.15, 0.1, 0.1.

2. Build the Huffman tree:
- Combine the two smallest probabilities (0.1 and 0.1) into a single node with a probability of 0.2.
- Combine the next two smallest probabilities (0.15 and 0.15) into a single node with a probability of 0.3.
- Combine the next smallest probability (0.2) with the previously created 0.2 nodes to create a node with a probability of 0.4.
- Combine the remaining 0.3 and 0.4 nodes to create the root node with a probability of 0.7.

3. Assign binary codes to each value based on the Huffman tree:
- Value 1: 111
- Value 2: 110
- Value 3: 101
- Value 4: 100
- Value 5: 011
- Value 6: 010
- Value 7: 00

4. Calculate the average number of bits required to encode the source using the assigned binary codes and their probabilities:
- (3 * 0.1) + (3 * 0.1) + (3 * 0.15) + (3 * 0.15) + (3 * 0.15) + (3 * 0.15) + (2 * 0.2) = 0.9 + 0.9 + 1.35 + 1.35 + 0.4 = 2.771 bits

So, the average number of bits required to encode this source using a Huffman code is 2.771 bits, which corresponds to option (b).

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Answer:

1) 4 pounds / $5.48 = .73 pounds / dollar

2) 5 pounds / $4.85 = 1.03 pounds / dollar

3) $3.51 / 3 pounds = $1.17 / pound

4) $9.12 / 6 pounds = $1.52 / pound

The solution to the system is [tex]$\$\left(x_{-} 1, x_{-} 2\right)=(4,-3) \$$[/tex].

To solve the system, we can use the method of elimination or Gaussian elimination.

We start by writing the system in augmented matrix form:

[tex]$$\left[\begin{array}{cc|c}2 & 4 & -4 \\5 & 7 & 11\end{array}\right]$$[/tex]

We can eliminate the [tex]$\$ x_{-} 1 \$$[/tex] variable from the second equation by subtracting 5 times the first equation from the second:

[tex]$$\left[\begin{array}{cc|c}2 & 4 & -4 \\5-5(2) & 7-5(4) & 11-5(-4)\end{array}\right] \Rightarrow\left[\begin{array}{cc|c}2 & 4 & -4 \\-3 & -13 & 31\end{array}\right]$$[/tex]

Next, we can eliminate the [tex]$\$ x_{-} 2 \$[/tex]$ variable from the first equation by subtracting twice the second equation from the first:

[tex]$$\left[\begin{array}{cc|c}2-2(-13) & 4-2(7) & -4-2(31) \\-3 & -13 & 31\end{array}\right] \Rightarrow\left[\begin{array}{cc|c}28 & -10 & -66 \\-3 & -13 & 31\end{array}\right]$$[/tex]

We can simplify this further by dividing the first row by 2 :

[tex]$$\left[\begin{array}{cc|c}14 & -5 & -33 \\-3 & -13 & 31\end{array}\right]$$[/tex]

Now we can solve for [tex]$\$ x_{-} 2 \$$[/tex] in terms of [tex]$\$ x_{-} 1 \$$[/tex] by multiplying the first equation by 13 and adding it to the second equation:

[tex]$$13(14) x_1-13(5) x_2-13(33)-3(-13) x_1-3(-13) x_2=13(31)-3(14) x_1$$[/tex]

Simplifying:

[tex]$$\begin{aligned}& 169 x_1-91 x_2-429+39 x_1+39 x_2=403 \\& 208 x_1=832 \\& x_1=4\end{aligned}$$[/tex]

Substituting back into the first equation, we get:

[tex]$$2(4)+4 x_2=-4 \Rightarrow x_2=-3$$[/tex]

Therefore, the solution to the system is [tex]$\$\left(x_{-} 1, x_{-} 2\right)=(4,-3) \$$[/tex].

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The angle at which the brace meets the wall is approximately 56.51 degrees.

To calculate the angle at which the brace meets the wall at a construction site, we can use the right triangle trigonometry. Here, the brace is the hypotenuse of a right-angled triangle, with the distance from the wall to the lower end of the brace being one of the legs. We will use these terms: construction, brace, and angle in our explanation.

Step 1: Identify the given measurements
- Length of the brace (hypotenuse) = 9.6 m
- Distance from the wall to the lower end of the brace (adjacent leg) = 5.3 m

Step 2: Use the cosine function to find the angle
cos(angle) = adjacent leg / hypotenuse
cos(angle) = 5.3 m / 9.6 m

Step 3: Calculate the angle using the inverse cosine function
angle = cos^(-1)(5.3 m / 9.6 m)

Step 4: Find the angle using a calculator
angle ≈ cos^(-1)(0.5521) ≈ 56.51°

So, at the construction site, the angle at which the brace meets the wall is approximately 56.51 degrees.

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Answer:

6.03

Step-by-step explanation:

In math terms, we can model the area left when cutting a circle out of a triangle as subtracting the area of a circle inscribed in a triangle.

There was only one side length of the triangle given (its base), so we can assume that it is an isosceles triangle with the given height.

To find the radius of the triangle, we can use the formula:

r = (A / s)

where r is the radius of the inscribed circle, A is the area of the triangle, and s is the semiperimeter (half-perimeter) of the triangle.

Finding the area of the triangle:

A = (1/2) * b * h

A = (1/2) * 6 * 5

A = 15

Finding the length of the congruent sides of the triangle:

[tex]a^2 + b^2 = c^2[/tex]

[tex]c^2 = 5^2 + 3^2[/tex]

[tex]c^2 = 34[/tex]

[tex]c \approx 5.83[/tex]

Finding the semiperimeter:

s = (side1 + side2 + side3) / 2

s = (5.83 + 5.83 + 6) / 2

s ≈ 8.83

Plugging these values into the radius formula:

r = A / s

r = 15 / 8.83

r ≈ 1.69

From here, we can get the area of the circle cutout:

A(circle) = πr²

A(circle) = π(1.69)²

A(circle) ≈ 8.97

Finally, we can get the leftover area by subtracting the area of the circle from the area of the triangle:

A = A(triangle) - A(circle)

A = 15 - 8.97

A = 6.03

The time taken by the train to pass the man is 54 seconds

To find the time taken by the train to pass a man standing near the railway line, we need to convert the train's speed to meters per second and then use the formula time = distance/speed.

1. Convert the speed of the train from km/hr to m/s: 40 km/hr * (1000 m/km) / (3600 s/hr) = 40000/3600 = 40/3.6 = 10/0.9 = 100/9 m/s.

2. Now, use the formula: time = distance/speed. The distance is the length of the train (600 m) and the speed is 100/9 m/s.

time = 600 m / (100/9 m/s) = 600 * 9 / 100 = 54 seconds.

Therefore, the time taken by the train to pass the man is 54 seconds (Option A).

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Given the linear inequality graph, which two statements are true include the following:

B) The graph represents y < −1/3(x) + 5.

D) All points in the blue area are solutions.

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):

y - y₁ = m(x - x₁)

Where:

First of all, we would determine the slope of this line;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (4 - 7)/(3 + 6)

Slope (m) = -3/9

Slope (m) = -1/3

At data point (3, 4) and a slope of -1/3, a linear equation for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 4 = -1/3(x - 3)  

y - 4 = x/3 + 1

y = x/3 + 5

y < x/3 + 5

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The equation of circle P include the following: D. x² + (y - 3)² = 4

In Mathematics and Geometry, the standard form of the equation of a circle is represented by the following mathematical equation;

(x - h)² + (y - k)² = r²

Where:

By critically observing the graph of this circle, we have the following parameters:

By substituting the given parameters into the equation of a circle formula, we have the following;

(x - h)² + (y - k)² = r²

(x - 0)² + (y - 3)² = 2²

x² + (y - 3)² = 4.

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The conversions are :

a) 2.8 km =  2800 m.

b) 27.55 dm =   2.755 m.

c) 27.9 hm =   2790 m.

d) 275 dam =   2750 m.

By multiplying the value by 1000 will help us to change kilometers (km) to meters (m). In order to change decimeters into meters, it is necessary to divide the figure by 10.

To convert, Note that:

a) 2.8 km to m:

= 2.8 x 1000 m

= 2800 m

b) 27.55 dm to m:

= 27.55 ÷ 10 m

= 2.755 m

c) 27.9 hm to m:

= 27.9 x 100 m

= 2790 m

d) 275 dam to m:

= 275 x 10 m

= 2750 m

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Convert the following to meter

2,8km

27,55dm

27,9hm

275dam

Answer:

The area of the pool is 10*20 = 200 square meters. Let's assume the width of the path is x. Then the dimensions of the entire region would be (10+2x) by (20+2x). The area of the entire region would be (10+2x)*(20+2x) = 400 + 60x + 4x^2. We know that the area of the pool and the path combined is 1200 square meters. So we can set up the equation as follows:

200 + 1200 = 400 + 60x + 4x^2

Simplifying the equation, we get:

4x^2 + 60x - 1000 = 0

Dividing both sides by 4, we get:

x^2 + 15x - 250 = 0

Factoring the equation, we get:

(x + 25)(x - 10) = 0

x = 10 or x = -25

Since the width of the path can't be negative, the width of the path is 10 meters.

Step-by-step explanation:

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The correct answer is d. The significance level tests for the coefficients are not valid.

Multicollinearity is a statistical term that refers to the presence of high correlation among predictor variables in a regression model. This can cause issues in the model, such as unstable or unreliable coefficients, and can lead to incorrect conclusions about the relationships between the predictors and the response variable.

When multicollinearity is present, the R-squared value of the model can become inflated because the model is able to explain more of the variation in the response variable due to the high correlation among the predictor variables. This can give the impression that the model is a good predictor when in fact it may not be. Additionally, multicollinearity can cause the F-test significance level to be low, indicating that the model is a good fit, even though the individual coefficients may not be statistically significant.

Multicollinearity can cause inflated R-squared values and low F-test significance levels. However, it does not necessarily mean that the model is a poor predictor. The interpretation of coefficients may also be affected by multicollinearity.

However, the most significant issue with multicollinearity is that it can lead to unreliable significance tests for individual coefficients, making it difficult to determine which predictors are contributing significantly to the model.

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Answer:

A. 4^2 - 4(2)(26) = 16 - 208 = -192

B. This equation has no real roots.

C. (-4 + √-192)/(2×2) = (-4 + 8i√3)/4

= -1 + (2√3)i

The balance point of the data, given the number of hours rehearsed and the score would be (5, 50).

The balance point on the graph is simply the average of the x vertices and the y vertices.

The average of the x vertices is:

= ( 1 + 3 + 4 + 8 + 9 )  / 5

= 25 / 5

= 5

The average of the y vertices is:

= ( 30 + 50 + 20 + 90 + 60 ) / 5

= 250 / 5

= 50

This then means that the balance point would be ( 5, 50 ).

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Hi, I'm glad to help you with this question. To determine if the normal distribution gives a reasonable approximation using the given data, we need to calculate the mean and standard deviation. Here are the steps:

1. Calculate the mean (average): Add all the data points together and divide by the number of data points.
(71+42+77+84+46+93+94+63+82+88+57+32+79+67+68+83+60+65+58+70) / 20 = 1380 / 20 = 69

Mean = 69

2. Calculate the standard deviation: First, find the difference between each data point and the mean, square the differences, and then find the average of those squared differences. Finally, take the square root of that average.
a. Differences from the mean: (-2, 27, 8, 15, -23, 24, 25, -6, 13, 19, -12, -37, 10, -2, -1, 14, -9, -4, -11, 1)
b. Squared differences: (4, 729, 64, 225, 529, 576, 625, 36, 169, 361, 144, 1369, 100, 4, 1, 196, 81, 16, 121, 1)
c. Average of squared differences: (4520) / 20 = 226
d. Square root of the average: √226 ≈ 15.03

Standard Deviation ≈ 15.03

Now that we have the mean (69) and the standard deviation (15.03), you can compare these values to the distribution line that you draw through the data by eye. If the distribution line follows a bell-shaped curve with the mean at the center and the data points spread around it following the standard deviation, then the normal distribution provides a reasonable approximation for this data set.

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The time for which plane B will take to refuel plane A is equals to 10 minutes. The two points who satisfy the equation, y = x + 1, are (0, 1), (-1,0). The two points who satisfy the equation, y = -x + 21, are (0,21), (21,0).

We have a fuel left in Plane A = 1 ton

fuel left in Plane B = 21 tons

Fuel transfer rate = 1 ton per minute

In order that for them to have the same amount of fuel, We add up the fuel left in Plane A and Plane B = 21 + 1 = 22 tons. This implies each plane will have fuel of 11 tons. Time that plane B will take to refuel plane A until both planes have the same amount of fuel is calculated by : Plane B will transfer 10 tons of fuel to A.

Plan A has a total of 11 tons. Since, the transfer rate = 1 ton per minute

=> 1 ton will transfer in 1 minute

So, 10 tons fuel will need 10 minutes. Hence, required time value is 10 minutes. Now, The equation for quantity of fuel with respect to time in plane A is, y = x + 1 --(1). If x = 0 => y = 1

and y = 0 => x = -1. So, (0, 1) and (-1,0).

The equation for quantity of fuel with respect to time in plane B is, y = -x + 21 --(2). For it, x = 0 => y = 21 and y= 0 => x = 21. Hence, two points that satisfy the equation(1) and equation(2) are (0, 1), (-1,0) and (0,21), (21,0) respectively.

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The answer for the following inequality expressed in interval notation is (-77/3, infinity)

To solve the inequality 2x - 75 < 5x + 2,

we need to isolate the variable x on one side of the inequality sign.

Starting with 2x - 75 < 5x + 2:

Subtracting 2x from both sides:
-75 < 3x + 2

Subtracting 2 from both sides:
-77 < 3x

Dividing both sides by 3 (and flipping the inequality sign because we are dividing by a negative number):
x > -77/3

So the solution to the inequality is x > -77/3.

Expressing this in interval notation, we have:

(-77/3, infinity)

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Answer:

Let x be the length of Danika's old running route in miles.

Then, her new running route can be represented by x + 4, since it is 4 miles longer than her old route.

Step-by-step explanation:

Answer:

21

Step-by-step explanation:

35% of 60=60% of 35

10% of 35=3.5

3.5*6=21

The probability is approximately 0.0549 or 5.49%. So, there is a 5.49% probability that all three randomly selected homes in the Quail Creek area have a security system.

To answer your question, we'll use the concept of probability. In this case, we want to find the probability that all three randomly selected homes in the Quail Creek area have a security system.

1. First, determine the probability that the first home has a security system:
There are 5 homes with security systems out of 14 total homes, so the probability is 5/14.

2. Next, determine the probability that the second home also has a security system:
Since one home with a security system has been "selected," there are now 4 homes with security systems out of the remaining 13 homes. So, the probability is 4/13.

3. Finally, determine the probability that the third home has a security system:
Since two homes with security systems have been "selected," there are 3 homes with security systems left out of the remaining 12 homes. So, the probability is 3/12, which simplifies to 1/4.

4. Multiply the probabilities from steps 1, 2, and 3 to get the probability that all three selected homes have a security system:
(5/14) * (4/13) * (1/4) = 20/364.

5. Round your answer to 4 decimal places:
The probability is approximately 0.0549 or 5.49%.

So, there is a 5.49% probability that all three randomly selected homes in the Quail Creek area have a security system.

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The 6 criteria are Internal consistency, Contextual consistency, Intelligibility, Mathematical plausibility, Historical plausibility and Replicability.

According to Eleanor Robson's interpretation of Plimpton 322, she lists six criteria for interpreting ancient mathematical texts. These six criteria are as follows:
1. Internal consistency: The mathematical text should be internally consistent and coherent in its logic.
2. Contextual consistency: The mathematical text should be consistent with the historical and cultural context in which it was written.
3. Intelligibility: The mathematical text should be understandable and intelligible to the intended audience.
4. Mathematical plausibility: The mathematical content of the text should be mathematically plausible and in line with known mathematical principles.
5. Historical plausibility: The mathematical text should be historically plausible and fit within the known historical context.
6. Replicability: The mathematical text should be replicable, meaning that other mathematicians should be able to reproduce the calculations and results presented in the text.

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a. The nth term of the sequence is  11 - 3n.

b. The nth term of the sequence is  14- 5n.

The sequence is an arithmetic progression. Therefore, the expression for the sequence can be represented as follows:

nth term = a + (n + 1)d

where

Therefore,

a.

a = 8

d = 11 - 8 = - 3

Therefore,

nth term = 8 + (n - 1)-3

nth term = 8  - 3n + 3

nth term = 11 - 3n

b.

a = 19

d = 14 - 19 = -5

nth term = 19 + (n - 1)-5

nth term = 19 - 5n - 5

nth term =  14 - 5n

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