Oscar is raising monarch caterpillars for a summer science project. Every day, he feeds 4 fresh milkweed leaves to each caterpillar. Oscar wants to know how many caterpillars he can feed in a day with a total of 28 leaves. Which equation can Oscar use to find n, the number of caterpillars he can feed in a day?

Answer:

1 in 47.

Step-by-step explanation:

Add all of the outcomes (28 + 2 + 3 + 14).

You'll get 47.

Do not add the 1s.

There is your answer.

1 in 47.

Answer:

(5 q^2 - r^2 s) (25 q^4 + 5 q^2 r^2 s + r^4 s^2)

Step-by-step explanation:

Factor the following:

125 q^6 - r^6 s^3

Hint: | Express 125 q^6 - r^6 s^3 as a difference of cubes.

125 q^6 - r^6 s^3 = (5 q^2)^3 - (r^2 s)^3:

(5 q^2)^3 - (r^2 s)^3

Hint: | Factor the difference of two cubes.

Factor the difference of two cubes. (5 q^2)^3 - (r^2 s)^3 = (5 q^2 - r^2 s) ((5 q^2)^2 + 5 q^2 r^2 s + (r^2 s)^2):

(5 q^2 - r^2 s) ((5 q^2)^2 + 5 q^2 r^2 s + (r^2 s)^2)

Hint: | Distribute exponents over products in (5 q^2)^2.

Multiply each exponent in 5 q^2 by 2:

(5 q^2 - r^2 s) (5^2 q^(2×2) + 5 q^2 r^2 s + (r^2 s)^2)

Hint: | Multiply 2 and 2 together.

2×2 = 4:

(5 q^2 - r^2 s) (5^2 q^4 + 5 q^2 r^2 s + (r^2 s)^2)

Hint: | Evaluate 5^2.

5^2 = 25:

(5 q^2 - r^2 s) (25 q^4 + 5 q^2 r^2 s + (r^2 s)^2)

Hint: | Distribute exponents over products in (r^2 s)^2.

Multiply each exponent in r^2 s by 2:

(5 q^2 - r^2 s) (25 q^4 + 5 q^2 r^2 s + r^(2×2) s^2)

Hint: | Multiply 2 and 2 together.

2×2 = 4:

Answer: (5 q^2 - r^2 s) (25 q^4 + 5 q^2 r^2 s + r^4 s^2)

Answer:

17

Step-by-step explanation:

3(2)^2 - 5(-1)^3

3(4) - 5(-1)

12 + 5

17

Answer:

If one angel is 74 so the solution is

[tex]74 + 2x = 180 \\ 2x = 180 - 74 \\ x = 106 \div2 \\ \: x = 53 \\ u = 74 \\ v = 53 \\ w = 53[/tex]

Step-by-step explanation:

Please mark as brainliest

Answer:

[tex] \huge{ \boxed{ \bold{ \text{7x + 9}}}}[/tex]

Step-by-step explanation:

[tex] \text{5x + 4 + 2x + 5}[/tex]

[tex] \text{Combine \: like \: terms} : [/tex]

[tex] \text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}[/tex]

[tex] ➝ \: \text{5x + 2x + 4 + 5}[/tex]

➝ [tex] \text{ 7x + 4 + 5}[/tex]

[tex] \text{Add \: the \: numbers : 4 \: and \: 5}[/tex]

[tex] ➝ \: \text{7x + 9}[/tex]

[tex] \text{Hope \: I \: helped}[/tex]!

[tex] \text{Best \: regards}[/tex]!

~[tex] \mathfrak{TheAnimeGirl}[/tex]

Answer:

7x + 9

Step-by-step explanation:

Combine like terms, means put the ones that have something in common together; in this case they are the terms with an 'x' value, and a regular numeric value.

5x+2x = 7x

5+4 = 9

therefore:

7x+9  

Answer:

Y=-2/5x

Step-by-step explanation:

Y-int: (0,0)

x-int:(-2,5)

Answer:

x= c/a+b

Step-by-step explanation:

Answer:

x = -1

Step-by-step explanation:

3(x+1) = -2(x-1) - 4 (Use the distributive property on both sides)

3x + 3 = -2x + 2 - 4 (collect like terms on the right side)

3x + 3 = -2x - 2 ( add 2x on both sides)

5x + 3 = -2 ( subtract 3 on both sides)

5x = - 5 (divide by 5 on both sides)

x = -1

Answer:

1. 32

2. 75

3. 384

Step-by-step explanation:

I did the assignment, on EDGE2020 and got it correct

Answer:

35 and 37

Step-by-step explanation:

Answer:

35 and 37

Step-by-step explanation:

Answer:

i was taught it would be answer D

Step-by-step explanation:

Answer:

The right answer is C

and this how it looks like on the graph

Answer:

Step-by-step explanation:

[tex]\sqrt{18}=\sqrt{2*3*3}=3\sqrt{2}[/tex]

[tex]\sqrt{12}=\sqrt{2*2*3}=2\sqrt{3}[/tex]

[tex]A=\sqrt{2}+\sqrt{18}\\\\=\sqrt{2}+3\sqrt{2}\\\\=(1+3)\sqrt{2}\\\\=4\sqrt{2}[/tex]

[tex]B=\sqrt{3}+\sqrt{12}=\sqrt{3}+2\sqrt{3}\\\\ = (1+2)\sqrt{3}\\\\ = 3\sqrt{3}[/tex]

[tex]\sqrt{B^{2}+A^{2}-2*B*A}=\sqrt{(B-A)^{2}}\\\\=B-A\\\\=3\sqrt{3}-4\sqrt{2}[/tex]

= 3* 1.732 - 4 *1.4142

= 5.196 - 5.6568

= -0.4608

Exact Answer:   [tex]4\sqrt{2} - 3\sqrt{3}[/tex]

Approximate Answer:  0.46070182678574

Round the approximate value however you need to.

=================================================

Work Shown:

[tex]C = \sqrt{ B^2 + A^2 - 2BA}\\\\C = \sqrt{ B^2 - 2BA + A^2}\\\\C = \sqrt{ (B-A)^2 }\\\\C = -(B-A) \ \ \text{ see note below}\\\\C = -B+A\\\\C = A-B\\\\C = (A) - (B)\\\\[/tex]

[tex]C = (\sqrt{2}+\sqrt{18}) - (\sqrt{3}+\sqrt{12})\\\\C = \sqrt{2}+\sqrt{18} - \sqrt{3}-\sqrt{12}\\\\C = \sqrt{2}+\sqrt{9*2} - \sqrt{3}-\sqrt{4*3}\\\\C = \sqrt{2}+\sqrt{9}*\sqrt{2} - \sqrt{3}-\sqrt{4}*\sqrt{3}\\\\C = \sqrt{2}+3\sqrt{2} - \sqrt{3}-2\sqrt{3}\\\\C = 4\sqrt{2} - 3\sqrt{3} \ \ \text{ ..... exact value}\\\\C \approx 0.46070182678574 \ \ \text{ ..... approximate value}[/tex]

-------------------

Note: The rule used here is

If x is positive then [tex]\sqrt{x^2} = x[/tex]

Or if x is negative, then [tex]\sqrt{x^2} = -x[/tex]

Since B-A = -0.4607 approximately, we will use the second version of the rule above.

See attachment for math work and answer.

Answer:

x< 3/2 hope this helps <3

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

Step 2: Subtract x from both sides.

Step 3: Subtract 3/2 from both sides.

Answer:

60 minutes

Step-by-step explanation:

Given the schedule above :

Red line arrives every 4 minutes

Blue line arrives every 5 minutes

Yellow line arrives every 6 minutes

All three just arrives at the train station ; when next will they all arrive at the train station at the same time.

Obtain the lowest common multiple of each arrov time :

Lowest common multiple of 4, 5, 6

_2___4___5___6

_2___2___5___3

_3___1___ 5 __ 3

_5___1___ 5 __ 1

_____1 ___1 ___1

Hence, lowest common multiple :(2 * 2 * 3 * 5) = 60

Hemce, they all arrive at the train station at the same time after 60 minutes

Answer:

−2(−x+4) − 3x+2= −5 what is x? Well i might be wrong but i think its 2x

Step-by-step explanation:

PEMDAS USE THAT METHOD

Answer: x=-1

Step-by-step explanation:

Answer:

(1,6)

Step-by-step explanation:

Since the parabola is symmetrical at x=-2, we know that if you take the value for (x-a) and (x+a) where a is any constant, the y values will be the same for both of those x coordinates. so, we can take the coordinate that we know, (-5,6), realize that it is -3 away from -2. then we can add three to get 1 and use the same y coordinate, getting (1,6)

Answer:

880,000

Step-by-step explanation:

Move the decimal in 8.8 five places to the right.

Answer:

C. 2^10

Step-by-step explanation:

Law of indices

a^x + a^y = a^(x+y)

2^3 × 2^7

=2^(3+7)

=2^10

Answer:

9.05 is my estimate

Step-by-step explanation:

The actual answer should be 9.08 etc....cause its a repeating decimal.

Answer:

-5 (3b+4)

Step-by-step explanation:

-15b - 20

-5 (3b+4)

Answer:

96436-329 = 96107

Step-by-step explanation:

Answer:

f(3) = 4(3)-2 = 12-2 = 10

Step-by-step explanation:

By comparing f(3) and f(x), you can see that it is basically replacing the x in the equation with the value of 3.

Answer:

a)Robert pay $12 to rent shoes for  everyone

b)Cost of each game is 4.5

c)y = 4.5x+12

Step-by-step explanation:

Refer the attached graph

a)How much did Robert pay to rent shoes for  everyone ?

y - intercept will give the rent shoes for everyone

y intercept is point where the graph of a function or relation intersects the y -axis of the coordinate system.

So, from the graph we can see that at x = 0 , y = 12

So, from the graph we can see that the no. of games is 0 . So, Total cost is 12

Thus Robert pay $12 to rent shoes for  everyone

b)What was the cost per game at the  bowling alley?

So, we are supposed to find the slope

Two pints from graph :

[tex](x_1,y_1)=(0,12)(x_2,y_2)=(2,21)m = \frac{y_2-y_1}{x_2-x_1}=\frac{21-12}{2-0}=4.5[/tex]

So, Cost of each game is 4.5

c)Write an equation to represent the situation  Number of Gomes

General equation : y = mx+c

So, y = 4.5x+12

Answer:

b

Step-by-step explanation:

Answer:

$0.75 per pound

Step-by-step explanation:

To find the unit rate, divide the price by the amount you have.

14.99/20 = 0.7495

Answer:

C. 24 inches by 15 inches

Step-by-step explanation:

Given

[tex]Rectangle: 8\ by\ 5\ inches[/tex]

Required

Determine the scale copies

To do this, we calculate the ratio.

[tex]Ratio = \frac{Actual}{Measured}[/tex]

Analyzing A.

Sides: 1.4 by 2.5 inches

We start by calculating ratio of each sides;

Length:

[tex]Ratio =\frac{8}{1.4}[/tex]

[tex]Ratio = \frac{40}{7}[/tex]

Width:

[tex]Ratio = \frac{5}{2.5}[/tex]

[tex]Ratio = 2[/tex]

Analyzing B.

Sides: 15 inches by 10 inches

Length

[tex]Ratio = \frac{8}{15}[/tex]

Width:

[tex]Ratio = \frac{5}{10}[/tex]

[tex]Ratio = \frac{1}{2}[/tex]

Both ratios are not equal

Analyzing C.

24 inches by 15 inches

Length

[tex]Ratio = \frac{8}{24}[/tex]

[tex]Ratio = \frac{1}{3}[/tex]

Width:

[tex]Ratio = \frac{5}{15}[/tex]

[tex]Ratio = \frac{1}{3}[/tex]

Both ratios are equal

Analyzing D.

Sides: 9 inches by 6 inches

Length

[tex]Ratio = \frac{8}{9}[/tex]

Width

[tex]Ratio = \frac{5}{6}[/tex]

Both ratios are not equal

Option C answers the question because both ratio are equal