Other than temperature, which property also has an effect on the rates of chemical reactions?
A.Color of reactants
B.Concentration of reactants
C.Solubility of reactants
D.Volume of reactants

Answers

Answer 1

Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants. The correct answer is B

The rate of chemical reaction means how chemical react with respect to time or as a function of time. The rate of chemical reaction tells us the speed or how fast chemicals react.

There are many factors that can affect the rate of chemical reaction. Temperature is one of them. Increase in temperature will increase the rate at which chemical react.

The color of reactants, solubility of reactants and volume of reactants have nothing to do with the rate of chemical reaction.

Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants.

Other factors affecting the rate of chemical reaction are:

the physical state of the reactants surface area temperature and the presence of a catalyst

Therefore, the correct answer is option B

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Related Questions

Find the gravitational force between Earth (5.97 x 1024 kg) and the Sun (1.99 x 1030 kg) knowing they are 1.48 x 1011 m apart.

Answers

Using the gravitational force of F= G(m1*m2/r^2)

m1= 5.97 x 10^24 kg (Earth)

m2= 1.99 x 10^30 kg (Sun)

r= 1.48 x 10^11 m

G is a known value, it is 6.672 x 10^-11

All units are proper. Therefore plug in the values and you get 3.16 x 10^22 N.

Let me know if I calculated this wrong and it is something else so I can delete this. Thank you. I don't want to make other students put down the wrong answer.

Answer:

[tex]\boxed {\boxed {\sf F_g \approx 3.62 *10^{22} \ N}}[/tex]

Explanation:

We are asked to find the gravitational force between Earth and the Sun. Use the following formula:

[tex]F_g= \frac{Gm_1m_2}{r^2}[/tex]

G is the universal gravitational constant. One mass (m₁) is the Earth and the other (m₂) is the Sun. r is the distance between the planets.

G= 6.67 * 10⁻¹¹ N*m²/kg²m₁ = 5.97 * 10²⁴ kg m₂= 1.99 * 10³⁰ kg r= 1.48 *10¹¹ m

Substitute the values into the formula.

[tex]F_g = \frac{ (6.67*10^{-11} N*m^2/kg^2)(5.97*10^{24} \ kg)(1.99*10^{30} \ kg) }{ (1.48 *10^{11} \ m)^2}}[/tex]

Multiply the numerator. The units of kilograms cancel.

[tex]F_g = \frac {7.9241601 *10^{44} \ N*m^2}{ (1.48 *10^{11} \ m)^2 }[/tex]

Solve the exponent in the denominator.

[tex]F_g= \frac {7.9241601 *10^{44} \ N*m^2}{ 2.1904*10^{22} \ m^2}[/tex]

Divide. The units of meters squared cancel.

[tex]F_g=3.61767718 *10^{22} \ N[/tex]

The original values all have 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 7 in the thousandth place tells us to round the 1 up to a 2.

[tex]F_g \approx 3.62 *10^{22} \ N[/tex]

The gravitational force between Earth and the Sun is approximately 3.62 *10²² Newtons.

What is the distance traveled by the elevator between 8 s and 24 s?
m

Answers

Answer: The displacement of the elevator between 8 s and 24 s is 6 m. Explanation: Given that,. Initial time = 8 s. Final time = 24 s.

The distance is equal to 6 m traveled by elevator between 8 s and 24 s.

What are distance and displacement?

The distance is described as the total length covered by an object. Distance is a scalar parameter with no direction. The distance covered by an object is always +ve, it can never be zero.

The displacement is described as the shortest length between two points by the object. The displacement is a vector parameter with direction & magnitude. The displacement can be +ve, -ve, or zero and can increase or decrease over time.

Given the position of the elevator at time t = 8 s at d = 9 m

The position of the elevator at time t = 24 s at d = 15 m

The distance covered by the elevator = 15 - (9) =  15 - 9 = 6 m

Therefore, the distance traveled by an elevator between 8 s and 24 s is equal to 6 m.

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#SPJ2

The magnitude of acceleration due to gravity is

Select one:
a. 9.8 m/s

b. 8.9 m/s2

c. 4.6 m/s

Answers

Answer:

The magnitude of a gravity is always 9.8 which is later approximated to 10m/s.

Answer:

a. 9.8

Explanation:

The magnitude of acceleration due to gravity is 9.8

write the resistivity of gold, iron ,Mercury, silver,copper? which is bad conductor?​

Answers

Answer:

Mercury is a bad conductor of heat but a fair conductor of electricity

By the way PURE SILVER is the best conductor of electricity

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Va A rail wagon of mass
5000 kg moving at a velocity
of 1.6 ms-1 collides with a
stationary wagon of mass
3000 kg (see Figure 4). After
the collision, the 3000 kg wagon
moves away at a velocity of
1.5 ms-1. Calculate the speed
and direction of the 5000 kg
wagon after the collision.

Answers

Answer:

0.7m/s

Explanation:

According to the conservation of linear momentum, the moment before a collision is equal to the moment after the collision. The equation is written as follows: [tex]m_{a}u_{a} + m_{b}u_{b} = m_{a}v_{a} + m_{b}v_{b}[/tex], where [tex]m[/tex] is the mass of the object, [tex]u[/tex] is the initial velocity, and [tex]v[/tex] is the final velocity.

Let's say the object [tex]a[/tex] is our moving wagon and the object [tex]b[/tex] is our stationary wagon. [tex]m_{a} = 500kg, u_{a} = 1.6ms^{-1}[/tex],  [tex]m_{b} = 3000kg, u_{b} = 0[/tex], since the wagon is stationary, it doesn't have any initial velocity. After collision, the mass remains the same, but the velocity changes: [tex]v_{a} = ?, v_{b} = 1.5ms^{-1}[/tex]

We can observe that [tex]v_{a}[/tex] is what we're looking for according to the question. Now let's substitute our values.

[tex](5000 * 1.6) + (0) = 5000v_{a} + (3000 * 1.5)[/tex]

[tex]v_{a} = \frac{(5000 * 1.6) - (3000*1.5)}{5000}[/tex] = 0.7m/s

define the unit of work​

Answers

[tex]\text{The unit of work is same as energy. Newton-meters(Nm) or Joules(J).}\\[/tex]

Drag each tile to the correct location.
Match each process to where it occurs in the carbon cycle.
Ingestion
fossilization
decomposition
combustion
light
energy
oxygen
carbon
dicadde
- sugar
minerak
water
All rights reserved

Answers

The order of the location of each process in the carbon cycle are as follows;

Ingestion → Decomposition → Fossilization → Combustion

Reasons:

Ingestion; During the ingestion process, the products of the direct Sunlight and photosynthesis, which

are energy rich chemical substances are ingested by herbivores.

Decomposition; The plants and animals die and undergo decomposition.

Fossilization; A long period the decomposed plants and animals manifest

into hard petrified materials, with their parts transformed to fossils.

Combustion; The remains of plants and animals, subjected to heat and

pressure due to compression, as when as bacteria decomposition that

removes several other elements, leaving a carbon and hydrogen rich

sludge that can be processed into fuel used for combustion. The

combustion process produces carbon dioxide which restarts the cycle.

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4) What is the kinetic energy of a 5 kg object moving ot a velocity of 25 m/s?
Help me please I’m confused

Answers

Kinetic Energy (KE)
Mass(m)
Velocity(V)

KE= 1/2 (m) (V^2)
KE=(.5)(5kg)(25^2m/s)
KE= (.5)(5kg)(625m/s^2)
KE= (.5)(3125kgm/s^2)
KE=1562.5 (kgm/(s^2))

how to prove sand is not a fluid even if it takes the shape of a container

Answers

Solids can be any size or shape. Sand is a solid that has the ability to be poured like a liquid and take the shape of its container. It is still a solid, as each individual grain of sand has a shape of its own and keeps that shape.

Say you were at mission control on
Earth. You use radio waves to say "Hello" to an
astronaut on Mars when Mars is 84,000,000
km from Earth. The astronaut hears your "Hello"
280 seconds after you spoke the word. How do
you explain this time lag?

Answers

Answer:

because mars is far

Explanation:

so if he shouts louder than he will hear it quicker

Two horizontal curves on a bobsled run are banked at the same angle, but one has twice the radius of the other. The safe speed (no friction needed to stay on the run) for the smaller radius curve is v. What is the safe speed on the larger radius curve?
A) v/2
B) v /√ 2
C) 2v
D) v√2



I shall answer it here so this can help other students out
First, FN = mg/cos
On a banked curve, FNx is the only acceleration force
FNx = mv^2/r
FNx = FNsin
mg/cos * sin = mv^2/r
cancel out the mass (m) and sin*1/cos is tan
gtan = v^2/r
rgtan = v^2
√(rgtan) = v (this is the velocity for the smaller radius.)
call larger radius velocity X

for larger radius, it becomes 2r, so √(2rgtan) = X

understand you can do √xy = √x * √y

√(rgtan) * √2 = X (√(rgtan) = v)
v * √2 = X (where X is velocity with larger radius)

Answers

Answer:

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

r

1

mv

2

=

r

2

mu

2

................ii

form i and ii we can write

v^2= \frac{1}{2} u^2v

2

=

2

1

u

2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

sue and betti both ski straight down a hill, both starting from rest. sue weighs more than betti. neglecting friction and wind resistance, which skier will be moving the fastest at the bottom of the hill?

Answers

Answer:

They are both moving at the same speed since they will have the same acceleration

F = M a    describes acceleration

M a = M g sin theta    where theta is the slope

One can easily see that

a = g sin theta   and the weight does not enter into the equation


A racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction). It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/a to the left (-x direction).what is the magnitude of the racquetball's change in momentum?

Answers

The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).

mass m  = 42g = 42/1000 = 0.042kg

initial velocity before collision u = 7 m/s

It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,

velocity after collision v = 7 m/s

To calculate the magnitude of the racquetball's change in momentum, we will use the formula below

Change in momentum = Mv - Mu

Since momentum is a vector quantity, we will consider the direction.

Change in momentum = 0.042 x 7 - ( 0.042 x - 7)

Change in momentum = 0.294 + 0.294

Change in momentum = 0.588 kgm/s

Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

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"true wisdom is knowing what you don't know"

Reader's Response/explanation


(Y'all I need help) ​

Answers

Answer:

“The only true wisdom is in knowing you know nothing.” ― Socrates. Socrates had it right. Remain humble and appreciate the fact that you don't know everything. ... Thankfully, one's search for knowledge has no end as there is always something new to learn, giving one's life meaning and purpose.

Explanation:

Answer:

knowing wisdom cool

Explanation:

lol

A car moving at 60 mph slams on its brakes to stop before hitting a deer. Another identical car traveling at 60 mph slows to a stop at a stop sign. Who experiences the greatest impulse during the stop

Answers

Happy Holidays!

Recall that:

Impulse = Change in Momentum = mass × change in velocity

Since both cars are identical and have the same initial velocity of 60 mph, them breaking to a stop means that they both experience the same change in velocity.

Thus, both of the cars' impulses are equal.

where in space did the expansion of the universe begin?

Answers

Answer:

The big bang

Explanation:

It is theorized the expansion of the universe began with the big bang, the universes expansion therefore did not begin in a spot of the universe rather the universe expanded from the big bang.

moving east with a constant velocity of 30 m/s for 5 seconds. What is the object's
acceleration?
a. O m/s/s
C. 30 m/s/s
b. 6 m/s/s
d. 150 m/s/s

Answers

Ok, so you multiply them so it would be 30x5 so you will get 150.

3) A 14 kg object is sitting at the top of a hill that is 100 m high. What is the potential energy of the
object?

Answers

Answer:

13,720 joules

Explanation:

Epotential = mgh

mass x gravity x height

Ep= 14 x 9.8 x 100

Ep=13,720 joules

The magnitude of acceleration due to gravity is

Select one:
a. 9.8 m/s

b. 8.9 m/s?

c. 4.6 m/s?

d. 9.8 m/s2

Answers

Answer:

The magnitude of acceleration is 9.8 m/s

Explanation:

Its not always in m/s^2 but in m/s due to the unit of distance and time

N
Select the correct answer.
In which situation is no work considered to be done by a force?
A.
when the angle between the force and displacement is 180°
OB.
when the angle between the force and displacement is 90°
Ос.
when the angle between the force and displacement is 45°
OD.
when the angle between the force and displacement is 0°

Answers

C is the answer duhhh

a galaxy that is a featureless spherical ball of stars would be called a type

Answers

Answer:

E0

Explanation:

Yes. The "0" indicates that it is spherical

Suppose two objects are gravitationally attracted to each other with some force F. If the mass of object 1 is multiplied by a factor of five and the mass of object 2 is multiplied by a factor of two, what will the new gravitational force be between the objects?

A. F2

B. 1/2F

C. 0.1F

D. 2F/5

E. 5F

J. 10F

Please help will mark brainliest

Answers

If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is

F' = G (5m₁) (2m₂) / d²

F' = 10  Gm₁m₂ / d²

but this is really just F' = 10F. So J is the correct choice.

Hi there!

Using Newton's Law of Universal Gravitation:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{d^2}}[/tex]

Fg = Force of gravity (N)

G = Gravitational Constant

m₁ = mass of object 1 (kg)

m₂ = mass of object 2 (kg)

d = distance between the objects (m)

There is a direct relationship between the masses of the objects and the resulting force of gravity, so we can plug new values in:

[tex]F_g = G\frac{5m_12m_2}{d^2}} = 10G\frac{m_1m_2}{d^2}} = 10F_g[/tex]

Thus, the correct answer is J. 10Fg.

ASAP!!! Imagine you are about to purchase a new refrigerator. There are two models that you are considering. Each
refrigerator is required to have an energy efficiency sticker on the door so that the buyer can be aware of the
cost of running the refrigerator. Refrigerator (A) costs $10.00 a month to operate and $700.00 to buy.
Refrigerator (B) costs $15.00 a month to run and $600.00 to buy. Decide which refrigerator you would purchase,
(A or B) and indicate in the answer box why it would be better for the environment

Answers

Answer:

model A

Explanation:

model A is more expensive to buy but you pay less per month to run it making it a better purchase in the long run. The cheaper cost of running it is better for the environment due to there being less electricity needed to power it.

What is the energy of a 5 kg object that is held at a height of 3 m above the ground?

Formula
substitute
answer

Answers

Answer:

147 Joules

Explanation:

It would be potential energy because it is stored. Potential energy = gravity * mass * height. Gravity is 9.8 m/s² or more specific 9.807 m/s². Potential energy is written in Joules.

9.8 * 5 * 3 = 147 Joules

More specific:

9.807 * 5 * 3 = 147.105 Joules

effect of looping the loop​

Answers

Answer:

What does this mean? please provide more explanation when asking for help

An object’s mechanical energy is

a
its energy of motion.
b
the sum of its potential (position) energy and kinetic (motion) energy.
c
the waste energy it produces by friction.
d
not related to the object’s mass.

Answers

Explanation:

the sum of its potential (position) energy and kinetic (motion) energy.

the federal government sets upper limits for exposure to electromagnetic energy from _____ known as the sar.

Answers

The federal government sets upper limits for exposure to electromagnetic energy from telephones known as the SAR.

-
In the balanced equation, 4KO2 + 2CO2 = 2K2CO3 + 302, which two chem-
icals have a molar ratio of 1:1?

Answers

The two chemical compounds having a molar ratio of 1 : 1 is CO₂ and K₂CO₃

                4KO₂ + 2CO₂ —> 2K₂CO₃ + 3O₂

                4       :    2         :   2       :       3

From the balanced equation above, the coefficients are 4, 2, 2, 3

A careful observation of the equation shows that CO₂ and K₂CO₃ exist in ratio 2 : 2 which can be simplified as 1 : 1

Therefore, we can conclude that CO₂ and K₂CO₃ has molar ratio of 1 : 1

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draw the following vector quantity Using the coordinate system.
a. 190 newton east
b. 120km/hr, 250 north of east
c. 60 meters southwest​

Answers

The given vectors quantities can be described by their properties of both

magnitude and direction.

a. The drawing of the vector extending from point (0, 0) to (190, 0) on the coordinate plane is attached.b. The velocity vector extending from  (0, 0) to (108.76, 50.714) on the coordinate plane is attached.c. The displacement vector extending from (0, 0) to (30·√2, 30·√2) is attached.

Reasons:

a. The magnitude of the vector = 190 N

The direction in which the vector acts = East

Therefore, in vector form, we have;

[tex]\vec{F}[/tex] = 190 × cos(0)·i + 190 × sin(0)·j = 190·i

The vector can be represented by an horizontal line, 190 units long

Coordinate points on the vector = (0, 0) and (190, 0)

The drawing of the vector with the above points using MS Excel is attached.

b. Magnitude of the velocity vector = 120 km/hr. 25° North of east

Solution;

The vector form of the velocity is; [tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j, which gives;

[tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j ≈ 108.76·i + 50.714·j

[tex]\vec{v}[/tex] ≈ 108.76·i + 50.714·j

Therefore, points that define the vector are; (0, 0) and (108.76, 50.714)

The drawing of the vector is attached

c. The magnitude of the vector = 60 m

The direction of the vector is southwest = West 45° south

The vector form of the displacement is [tex]\vec{d}[/tex] = 60 × cos(45°)·i + 60 × sin(45°)·j

Which gives;

[tex]\vec{d}[/tex] = 30·√2·i + 30·√2·j

Points on the vector are therefore; (0, 0), and (30·√2, 30·√2)

The drawing of the vector is attached

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on what factors does the quantity of heat of an object depend​

Answers

Answer:

The quantity of heat given to body depends on: (i) The mass of the body, (ii) The rise (or fall) in the temperature of the body, and (iii) Nature of the material of the body.

Explanation:

Hope this helps

have a great day

~Zero

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