Parallelogram ABCD has vertex coordinates A(0, 1), B(1,3), (4,3), and D(3,1). It is translated 1 unit to the right and 3 units down and then rotated 180°clockwise around the origin. What are the coordinates of A?

Step-by-step explanation:

Very quick and effortless example of vertical angles in the attached image. When 2 straight lines intersect, the 2 angles opposite each other at that point are vertical angles, and they are always congruent.

I'd say it's the 3rd option:

"Vertical angles are a pair of non-adjacent angles formed by two intersecting lines."

but any of the first three could be technically true really. Adjacent angles are 2 angles that share a side, and vertical angles cannot share one.

Answer:

I believe the answers are

B) 1

D) $1,000

Step-by-step explanation:

Answer:

Step-by-step explanation:         The four numbers:  - 34, -0.4, 0.4, 3.4

so if you look at it it  The answer is -34

Answer:

-34

Step-by-step explanation:

this is because an integer is a negative or positive whole number, and in this case, -0.4, 0.4 and 3.4 are decimal numbers

Answer:She will have:

N = 200 smaller lots

Step-by-step explanation: N = (total acres of land) / (smaller lots of land)

Substituting the values we have:

N = 10 / (1/20)

Rewriting we have:

N = 10 * 20

N = 200 lots

Hope you could get an idea from here.

Doubt clarification - use comment section.

The equation [tex]p^3+q^3+r^3=(\frac{1}{p^3}+\frac{1}{q^3}+\frac{1}{r^3})p^2q^2r^2[/tex] has been proved to be true

The equation is given as:

[tex]\frac pq = \frac qr[/tex]

Cross multiply

[tex]pr = q^2[/tex]

Rewrite as:

[tex]q^2 = pr[/tex]

Also, we have:

[tex]p^3+q^3+r^3=(\frac{1}{p^3}+\frac{1}{q^3}+\frac{1}{r^3})p^2q^2r^2[/tex]

Substitute [tex]q^2 = pr[/tex]

[tex]p^3+q^3+r^3=(\frac{1}{p^3}+\frac{1}{q^3}+\frac{1}{r^3})p^3r^3[/tex]

Expand

[tex]p^3+q^3+r^3=\frac{1}{p^3} \times p^3r^3 +\frac{1}{q^3} \times p^3r^3 +\frac{1}{r^3} \times p^3r^3[/tex]

Simplify

[tex]p3+q3+r3=r^3 +\frac{1}{q^3} \times p^3r^3 + p^3[/tex]

Rewrite as:

[tex]p3+q3+r3=r^3 +\frac{1}{q^3} \times (pr)^3 + p^3[/tex]

Substitute [tex]pr = q^2[/tex]

[tex]p3+q3+r3=r^3 +\frac{1}{q^3} \times (q^2)^3 + p^3[/tex]

[tex]p3+q3+r3=r^3 +\frac{1}{q^3} \times q^6 + p^3[/tex]

Divide q^6 by q^3

[tex]p3+q3+r3=r^3 +q^3 + p^3[/tex]

Rewrite the equation as:

[tex]p3+q3+r3=p^3 +q^3 + r^3[/tex]

Hence, the equation has been proved

Read more about equations at:

https://brainly.com/question/13729904

Answer:

You would be able to afford 9 gallons of gas.

Step-by-step explanation:

34.83 divided by 3.87 is 9. Have a nice day!

Answer:

$1.90

10xx+25yy cents

Step-by-step explanation:

9 dimes (10 cents each) = 90 cents = 0.9 dollars

4 quarters (25 cents each) = 100 cents = 1 dollar

Making $1.90

xx dimes (10 cents each) = 10xx cents

yy quarters (25 cents each) = 25yy cents

Making 10xx+25yy cents in total I believe..

Hope this helps :)

Answer    g

Step-by-step explanation:

g

Answer:

don't know i tell true

Step-by-step explanation:

Answer:

2,309.2

This could be wrong but I'm pretty sure it's right

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

[tex]\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}[/tex]

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

[tex]\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}[/tex]

Another identity is:

[tex]\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}[/tex]

Therefore:

[tex]\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}[/tex]

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

[tex]\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}[/tex]

Another identity:

[tex]\displaystyle \large{\sin^2x+\cos^2x=1}[/tex]

Therefore:

[tex]\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}[/tex]

Hence proved, this is proof by using identity helping to find the specific identity.

Answer:

D

Step-by-step explanation:

Process of Elimination:

A: 3.976 is greater than 3.97

B: 1.025 is lesser than 1.25

C: 9.145 is greater than 9.14

All of the options checked are true, leaving the answer only to be D.

Answer:

-d+3.5≥4

Step-by-step explanation:

Just ask.

Hope this helps! :)

Answer:

Answer:

28+66+86=180

180=180

Step-by-step explanation:

Since there is a triangle and the 3 measures from the angles we can find the value of x using the hint given that the sum of the interior angles must be 180°

Write the equation

\begin{gathered}x+(2x+10)+(3x+2)=180\\\end{gathered}

x+(2x+10)+(3x+2)=180

Simplify left side of the equation

\begin{gathered}6x+12=180\\\end{gathered}

6x+12=180

Solve equation for x

\begin{gathered}6x=180-12\\6x=168\\x=28\end{gathered}

6x=180−12

6x=168

x=28

Replace x into the 3 angles and find their respectives values

\begin{gathered}A=x\\A=28\\\\B=2x+10\\B=2*28+10\\B=56+10\\B=66\\\\C=3x+2\\C=84+2\\C=86\end{gathered}

A=x

A=28

B=2x+10

B=2∗28+10

B=56+10

B=66

C=3x+2

C=84+2

C=86

Check if the answers are correct

\begin{gathered}28+66+86=180\\180=180\end{gathered}

28+66+86=180

180=180

PLEASE MARK ME AS BRAINLIEST

Answer:

Step-by-step explanation:

3(m-2)+2(m-2)

3m-6+2m-4

3m+2m-6-4

5m-6-4

5m-10

The expressions 3(m-2)+2(m-2) and 50m-2 are not equivalent expressions.

After simplifying the first expression 3(m-2)+2(m-2) in part (a), we got 5m-10, which is different from the second expression, 50m-2.

we have: ∠A + ∠B = 90°

<=> (2x-14) + (3x-6) = 90° <=> 2x - 14 + 3x - 6 = 90°

<=> 5x + 20 = 90°

<=> 5x = 70°

<=> x = 14°

So: ∠A = 2x - 14 = 2.14 - 14 = 14°

Ok done. Thank to me :>

Answer:

i got 47/88

Step-by-step explanation:

Divide each number by two

Step-by-step explanation:

24 cans cost $8.

so, 1 can is 1/24 if the total, and that applies then also to the price.

so, the cost of 1 can is 8/24 = 1/3 ≈ $0.33

Answer:

Cost per can = $0.33.

Step-by-step explanation:

8 / 24

= 1/3

= 0.333....

Answer:

g=6

Step-by-step explanation:

6.4×6-1.4×6=

38.4-8.4=30

its true if it is not the result is incorrect

Answer:

- 1/4

Step-by-step explanation:

Where you see X, substitute with 1/3

Solve the power/exponent first:

6(1/3) = 2

That is ; - 4(1/4)^2

Solve the parenthesis:

(1/4)^2 = 1/16

-4(1/16)

= - 1/4

I hope this helps. Comment if any doubt.

Answer:

C

Step-by-step explanation:

Answer:

f(-2) = -12

Step-by-step explanation:

f(x)= x² + 8x

We want to find f(-2)

f(-2) = (-2)² + 8(-2)

Apply exponent : (-2)² = 4

f(-2) = 4 + 8(-2)

multiply 8 and - 2 : 8 * -2 = -16

f(-2) = 4 - 16

subtract 16 from 4 : 4 - 16 = -12

f(-2) = -12

Step-by-step explanation:

f(-2) = (-2)² + 8(-2) = 4 - 16 = -12

Answer:

By:Parrain

Step-by-step explanation:

The probability that the selected tile will be green is 0.5.

The probability that a tile will be green can be calculated by the formula:

= Number of green tiles / Total number of tiles

Total number of tiles is:

= 3 + 6 + 3

= 12 tiles

Probability of picking green tile is therefore:

= 6 / 12

= 50%

= 0.50

The probability of picking a green tile is 0.50

Answer:

I did most of the work 4 u :3

Step-by-step explanation:

Just do the last question

HOPE THIS HELPED :DDDDDDD

Answer:

1. 3^4 x 3^3 < 3^12

2. 3^3 x 4^3 < 12^4

3. 3^4 x 4^3 > 12^3

Answer:

The answer is 9 ( C on edge)

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

C on edge

I took the test

Answer:

-6

Step-by-step explanation:

-2(-12 - u )

u = -15

-2 ( -12 - (-15))

remove parenthesis.

-2 ( -12 + 15 )

add -12 and 15

-2 ( 3 )

multiply -2 and 3

= -6

Step-by-step explanation:

-2(-12 - u) = -2(-12 + 15) = -2(3) = -6