Party. Elena is buying cups and plates for her party. Cups are sold in packs of 8 and plates are sold in packs of 6. She wants to have the same number of plates and cups.
Find a number of plates and cups that meet her requirement.

How many packs of each supply will she need to buy to get that number?

Name two other quantities of plates and cups she could get to meet her requirement.

​Tiles. A restaurant owner is replacing the restaurant’s bathroom floor with square tiles. The tiles will be laid side-by-side to cover the entire bathroom with no gaps, and none of the tiles can be cut. The floor is a rectangle that measures 24 feet by 18 feet.
What is the largest possible tile size she could use? Write the side length in feet. Explain how you know it’s the largest possible tile.

How many of these largest size tiles are needed?

Name more tile sizes that are the whole number of feet that she could use to cover the bathroom floor. Write the side lengths (in feet) of the square tiles.

Stickers. To celebrate the first day of spring, Lin is putting stickers on some of the 100 lockers along one side of her middle school’s hallway. She puts a skateboard sticker on every 4th locker (starting with locker 4), and a kite sticker on every 5th locker (starting with locker 5).
Name three lockers that will get both stickers.
After Lin makes her way down the hall, will the 30th locker have no stickers, 1 sticker, or 2 stickers? Explain how you know.

Kits. The school nurse is assembling first-aid kits for the teachers. She has 75 bandages and 90 throat lozenges. All the kits must have the same number of each supply, and all supplies must be used.
What is the largest number of kits the nurse can make?
How many bandages and lozenges will be in each kit?

What kind of mathematical work was involved in each of the previous problems? Put a checkmark to show what the questions were about.

Evaluation: What Kind of Problem?
1. For each problem, tell whether finding the answer requires finding a greatest common factor or a least common multiple. You do not need to solve the problems.
a. Elena has 20 apples and 35 crackers for making snack bags. She wants to make as many snack bags as possible and wants each bag to have the same combination of apples and crackers. What is the largest number of snack bags she could make?

b. A string of holiday lights at a store has three colors that flash at different times. Red lights flash every fifth second. Blue lights flash every third second. Green light flashes every four seconds. The store owner turns on the lights. After how many seconds will all three lights flash at the same time for the first time?

c. A florist orders sunflowers every 6 days, starting from the sixth day of the year, and daisies every 4 days, starting from the fourth day of the year. When (or on which day) will she order both kinds of flowers on the same day?

d. Noah has 12 yellow square cards and 18 green ones. All the cards are the same size. He would like to arrange the square cards into two rectangles—one of each color. He wants both the yellow and green rectangles to have the same height and to be as tall as possible. What is the tallest possible height for the two rectangles?

2. Explain how you know which problem(s) involves finding the greatest common factor.

Using algebraic equations:

the number of sessions that will give same cost for both plans is: 1

the cost is: $96

Translate the situation into algebraic equations.

Equation for total cost of the first plan:

y = 41x + 55

Equation for the total cost of the second plan:

y = 46x + 50

To find the number of sessions that would yield same cost for both plans, make both equations equal to each other and solve for x.

41x + 55 = 46x + 50

41x - 46x = - 55 + 50

-5x = -5

x = 1

For a session, both plans will yield the same cost.

The cost 1 session will yield for both:

41x + 55 = 46x + 50

41(1) + 55 = 46(1) + 50

96 = 96

Therefore, using algebraic equations:

the number of sessions that will give same cost for both plans is: 1

the cost is: $96

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Answer:

the correct answer is -8

Step-by-step explanation:

Raise -2 to the power of 3.

Answer:

Step-by-step explanation:

(-2)*(-2)*(-2) = -8

Answer:

22.5 centimetres per second.

Step-by-step explanation:

To get the awnser for this you do the highest length of centimetre which is 90 divided by how many seconds it took to get to 90 centimetres, then we do 90÷4 which equals to 22.5, so the awnser is 22.5 centimetres per second. Hope this helps.

Answer:

no

Step-by-step explanation:

The ratio of width to height for the different photos are ...

 student: 1 : 3/2 = (2/2):(3/2) = 2 : 3

 small: 2 : 5/2 = (4/2):(5/2) = 4 : 5

 medium: 4 : 5 . . . (same as small)

 large: 8 : 10 = 4 : 5 . . . (same as small and medium)

The small, medium, and large photos all have proportional dimensions, but those are not proportional to the dimensions of the student photo.

S/O:  sqdancefan

Answer:

50,000

Step-by-step explanation:

The little 5 is called an exponent, so it would be 0.5*10^5.

Ten to the fifth power. you can take the ten and do this. 10x10x10x10x10. The answer would be fifty thousand

The percentage is the indicating hundredth thus the percentage of winning is 58.33%.

The percentage is also called the indicating hundredths. Thus, 2% is two-hundredth, which means 2%=2/100=0.02.

The percentage is just like the amount of that value but between 1 to 100 and it is very useful to predict for example if you say 678 then we have to know about the full number also but if you say 80% then it becomes clear.

As per the given,

Total matches = 120

Number of lost matches = 50

Number of winning match = 120 - 50 = 70

Winning percentage = (70/120) x 100 = 58.33%

Hence "The percentage is the indicating hundredth thus the percentage of winning is 58.33%".

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Answer:

they are not similar

Step-by-step explanation:

MN/VW=16/22=8/11

LN/UW=20/28=5/7

LM/UV=25/35=5/7

there is no information about the angles, you apply SSS but in this situation not all sides are proportional

Answer:

The slope is 0.8 or 4/5.

Step-by-step explanation:

Let's take two points on a line. (-2,0) and (3,4).

Now, determine the rise and run.

Slope = Rise/Run

Conclusion:

Therefore, the slope is 0.8 or 4/5.

Hoped this helped.

[tex]BrainiacUser1357[/tex]

Answer:

The answer is rise over run

Step-by-step explanation:

You divide the rise coordinate on the Y axis of the X coordinate

Answer:

The answer is t = 0.25

Step-by-step explanation:

Answer:

t = 0.25

Step-by-step explanation:

Answer:

4/8 (2/4)

Step-by-step explanation:

1/4 is 2/8

He ate 2/8 pizza for dinner

Then he ate 1/4 (2/8) the next day

So he has 4/8 (2/4) pizza left

Answer:

[tex]12,000\geq 4t+8,000[/tex]

Step-by-step explanation:

Candi would be taken medicine A for 11 days for her to complete the medication.

1 L = 1000 ml

Candi needs to take 15 ml of Medicine A three times daily. Therefore:

Amount of drug taken by Candi daily = 15 ml * 3 times = 45 ml = 0.045 L

Since the bottle contains 5 L, The number of days she needs to take the madication is:

Number of days = 5 L / 0.045 L = 11 days

Candi would be taken medicine A for 11 days for her to complete the medication.

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Answer:

x=0.4

Step-by-step explanation:

ubtract

0.43

from both sides of the equation.

−

8.5

x

=

−

2.97

−

0.43

Subtract

0.43

from

−

2.97

.

−

8.5

x

=

−

3.4

Divide each term in

−

8.5

x

=

−

3.4

by

−

8.5

.

−

8.5

x

−

8.5

=

−

3.4

−

8.5

Divide

−

3.4

by

−

8.5

.

x

=

0.4

Answer: 36.4 seconds

(Unitary method)

5 meters take 2 seconds

1 meter takes 2/5 seconds

91 meter takes 2/5 * 91 --> 36.4 seconds

The time taken by Andre to run 91 meters is 36.5 seconds.

Speed is the rate at which an object's position changes, measured in meters per second. For example, if an object starts at the origin, and then moves three meters in three seconds, its speed is one meter per second. The equation for speed is simple: distance divided by time

Given here: Distance travelled by Andre=5 meters in time t=2seconds

Thus Andre's speed = 5/2

                                  =2.5 m/sec

Thus time taken to run 91 m is = 91/2.5

                                                  =36.5 seconds

Hence, The time taken by Andre to run 91 meters is 36.5 seconds.

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Work Shown:

(3 mm)/(17 m) = (x mm)/(55 m)

3/17 = x/55

3*55 = 17*x

165 = 17x

17x = 165

x = 165/17

x = 9.706 approximately

Side note: I used the cross multiplication rule for the third step.

Answer:

  g(f(x)) = 8x^3-24x^2+34x-18

Step-by-step explanation:

The composition is ...

  [tex](g\circ f)(x)=g(f(x))=g(2x-2)\\\\=(2x-2)^3+5(2x-2)\\\\=(2x)^3 +3(-2)(2x)^2+3(-2)^2(2x)+(-2)^3+10x-10\\\\=8x^3-24x^2 +24x-8+10x-10\\\\\boxed{(g\circ f)(x)=8x^3-24x^2+34x-18}[/tex]

Answer:

Draw a straight line through these two points (0, 0) and (1, 3).

Step-by-step explanation:

"Proportional relationship" implies line or curve that goes through the origin; there is no "y-intercept" in this case.  

Plot a dot at (0, 0).  Next, move your pencil point 1 unit to the right (you'll end up at (1, 0), and then move it from there up to (1, 3).  Draw a straight line through these two points (0, 0) and (1, 3).

Answer:

original price of a cd is 12.50. what is the price with a discount of 39%

Step-by-step explanation:

Answer:

Step-by-step explanation:

-16.51

---------

2.54

-16.51

--------

2.54

1651

------

254

-13

-----

2

Answer: -13

----

2

[tex]2x^2-x=21\\\\\implies 2x^2 -x -21 =0\\\\\text{Apply quadratic formula},~ x = \dfrac{-b \pm \sqrt{b^2 -4ac}}{2a}\\\\\text{In this case,}~ a =2 , b =-1, c =-21}\\\\\implies x = \dfrac{-(-1) \pm \sqrt{(-1)^2 - 4\cdot 2 \cdot (-21)}}{2(2)}\\\\\implies x =\dfrac{1 \pm \sqrt{169}}{4}\\\\\\\implies x = \dfrac{ 1 \pm 13}4\\\\\\\text{Hence,}\\\\x =\dfrac{1+13}4 = \dfrac{14}4 = \dfrac 72\\\\\text{or}\\\\x =\dfrac{1-13}4 = -\dfrac{12}4 =-3[/tex]

Answer:

x1=7/4, x2=-3

Step-by-step explanation:

[tex]2x^{2} - x - 21 = 0\\x1,2 = (1±\sqrt{-168-1})/4\\x1,2 = (1±13)/4\\x1 = 14/4 -> x1 = 7/2\\x2 = -12/4 -> x2 = -3[/tex]

Answer:

1 1/2

Step-by-step explanation:

7 6/11 is close to 7 1/2

5 13/15 is close to 6

7 1/2 - 6 = 1 1/2

[tex]\huge \bf༆ Answer ༄[/tex]

The Correct choice is ~

Answer:

19/15 is the answer

Answer: C. Distributive Property

Step-by-step explanation: To simplify this expression, you would multiply 6 by y and 2.

Answer:

-5

Step-by-step explanation:

considering they are counting in whole numbers it should be -5

Answer: The two specific conjectures are in the first image, and the two general conjectures are in the second image.

Answer:

c=10cm

Step-by-step explanation:

a²+b²=c²

6²+8²=c²

36+64=c²

100=c²

10=c

Answer:

If one bunch is two dollars even, then you could buy 10 bunches.

Step-by-step explanation:

20 divided by 2 = 10

So, you could buy ten bunches of grapes.

Answer:

the answer is 10 because 2 goes into 20 10 times.

Step-by-step explanation:

p=49 1/2 that's the answer i got you lil guy

Answer:

Step-by-step explanation:

you add 8,14, and 11 to get 33 then you divide it by 3, because there are 3 numbers meaning the average is 11.

If that makes, all you have to do is add up all the numbers then divide by the amount of numbers you see to find the average of the numbers.

[tex]\huge\text{\bf Hey there!}[/tex]

[tex]\large\text{The word \underline{average} is basically the \boxed{\bf mean} of a data set. When you }\\\large\text{hear or see the word \underline{average} in math think of its asking you to \boxed{\bf find \ your \ total}}\\\large\text{in your data set.}[/tex]

[tex]\large\text{Here is the formula to make it easier to solve}\downarrow[/tex]

[tex]\mathbf{mean = \dfrac{sum\ of\ all\ terms}{number\ of\ terms}}}[/tex]

[tex]\large\text{YOUR EQUATION:}[/tex]

[tex]\mathbf{average = \dfrac{8 + 14 + 11}{3}}[/tex]

[tex]\mathbf{\dfrac{8 + 14 + 11}{3}}[/tex]

[tex]\mathbf{= \dfrac{22 + 11}{3}}[/tex]

[tex]\mathbf{= \dfrac{33}{3}}[/tex]

[tex]\mathbf{= \dfrac{33\div3}{3\div3}}[/tex]

[tex]\mathbf{= \dfrac{11}{1}}[/tex] [tex]\mathbf{\rightarrow 11\div1}[/tex]

[tex]\mathbf{= 11}[/tex]

[tex]\huge\boxed{\text{Therefore, your answer should be: \textsf{11}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]