The given statement, "piezoelectricity is a property where quartz crystals vibrate 100,000 times a second if heated to 100 degrees Celsius" is false because piezoelectricity is a property of certain materials, including quartz crystals, that generates an electric charge in response to mechanical stress or pressure, not heat.
Piezoelectricity is a property of certain materials, including quartz crystals, that generates an electrical voltage in response to mechanical stress or pressure. Heating quartz crystals to 100 degrees Celsius does not cause them to vibrate 100,000 times per second, although it may affect their piezoelectric properties in other ways. The frequency of vibration for a quartz crystal oscillator is determined by its physical dimensions and properties, and may be in the range of thousands or millions of vibrations per second, depending on the design and application of the oscillator.
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water flows through a pipe with a cross-sectional area of 0.002 m2 at a mass flow rate of 4 kg/s. the density of water is 1 000 kg/m3. determine its average velocity. multiple choice question. 20 m/s 200 m/s 0.02 m/s 2 m/s 0.2 m/s
Option D: 2 m/s is the average velocity of the water flowing through a pipe with a cross-sectional area of 0.002 m2 at a mass flow rate of 4 kg/s.
According to the question:
cross-sectional area of the pipe = 0.002m²
Mass flowrate = 4 kg/s
Density of water = 1000 kg/m³
We are asked to find, average velocity =?
Average velocity is the net or total displacement covered by a body in a given time. The mass flow rate divided by the pipe's cross-sectional area and density ratio is the formula for calculating a fluid's average velocity.
As a result, the water's average flow rate through the pipe is provided by:
v = m / (ρ × A)
where, v is the average velocity, m is the mass flow rate, ρ is the density of water, and A is the cross-sectional area of the pipe. Substituting the values in the above equation we get:
v = 4 / (1000 × 0.002)
v = 2m/s
Therefore, the average velocity of water flowing through a pipe of cross-sectional area of 0.002m² is 2m/s.
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Correct question is:
Water flows through a pipe with a cross-sectional area of 0.002 m2 at a mass flow rate of 4 kg/s. The density of water is 1 000 kg/m3. Determine its average velocity. Multiple choice question.
20 m/s
200 m/s
0.02 m/s
2 m/s
0.2 m/s
a rear window defroster consists of a long, flat wire bonded to the inside surface of the window. when current passes through the wire, it heats up and melts ice and snow on the window. for one window the wire has a total length of 11.0 m , a width of 1.8 mm , and a thickness of 0.11 mm . the wire is connected to the car's 12.0 v battery and draws 7.5 a . part a what is the resistivity of the wire material? express your answer with the appropriate units.
The resistivity of the wire material can be calculated using Ohm's Law, which states that V=IR, or voltage = current multiplied by resistance. Therefore, the resistivity of the wire material is [tex]2.87 \times 10^{-8} \Omega m[/tex].
Resistivity of wire is given as ρ=RA/L where R is the resistance of wire, A is the cross-sectional area of the wire, L is the length of the wire.
The formula to calculate the resistance of wire from Ohm's Law is given by R=V/I where V is the voltage, I is the current.
Substituting the given values: V = 12.0 V, I = 7.5 A.
Therefore, R=V/I=12.0 / 7.5 = 1.6 Ω
From the formula of resistivity:
[tex]\rho=\dfrac{RA}{L}\\R=\dfrac{ρL}{A}[/tex]
Substituting the given values: R = 1.6 Ω, L = 11.0 m and calculating the area:
[tex]A = (1.8 \times 10^{-3} m) (0.11 \times 10^{-3} m)\\ = 0.198 \times 10^{-6} m²[/tex]
Therefore,
[tex]\rho = RA/L\\= \dfrac{R \times A}{ L}\\= \frac{1.6 \times 0.198 \times 10^{-6}}{ 11.0}\\ = 2.87 \times 10^{-8 } \Omega m[/tex]
Therefore, the resistivity of the wire material is [tex]2.87 \times 10^{-8 } \Omega m[/tex].
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which will have a larger velocity upon hitting the ground: a rock thrown vertically upward from a bridge, or a rock thrown vertically downward from the same bridge? assume both rocks are thrown from the same height and with the same speed.
Assuming both rocks are thrown from the same height and with the same initial speed, the rock thrown vertically downward will have a larger velocity upon hitting the ground than the rock thrown vertically upward.
This is because the rock thrown upward will lose speed as it moves against the force of gravity. Eventually, the upward motion will be slowed down until the rock reaches the highest point in its trajectory, where it momentarily stops and changes direction. From that point, the rock will accelerate downward, gaining speed as it falls back to the ground. However, the time spent traveling upward and the time spent traveling downward will not be the same, since the upward portion of the trajectory will be slower due to gravity slowing the rock's ascent. This means that the rock thrown upward will have a lower speed when it hits the ground compared to the rock thrown downward.
On the other hand, the rock thrown downward will experience the force of gravity pulling it towards the ground, causing it to accelerate and gain speed as it falls. Since it is initially moving downward, it will not slow down until it hits the ground, meaning that it will have a higher velocity upon impact than the rock thrown upward.
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Listed in the Item Bank are key terms and expressions, each of which is associated with one of the columns. Drag and drop each item into
the correct column. Order does not matter.
Conductor or Insulator
:: aluminum foil
:: plastic :: ocean water
:: air
:: wood
:: soil
:: foam
glass
Conductor:
Aluminum foil
Insulator:
Plastic
Air
Wood
Soil
Foam
Glass
What is Conductor?
A conductor is a material or substance that allows electric charge to flow freely through it, offering little or no resistance to the flow of an electric current. Common conductors include metals such as copper, silver, and gold.
A conductor is a material or substance that allows electrical current to flow freely through it. This is due to the presence of free electrons that can move easily through the material when an electric field is applied. Common conductors include metals such as copper, silver, and aluminum.
In contrast, an insulator is a material or substance that does not allow electrical current to flow through it easily. Insulators have very few free electrons and resist the flow of electric current. Common insulators include rubber, plastic, glass, and air.
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calculate the work done on the block by the spring during the motion of the block from its initial position to where the spring has returned to its uncompressed length.
The work done on the block by the spring during its move from its initial position to where the spring has returned to its uncompressed length is[tex]W = (1/2) \times k \times x^2[/tex].
We need to know the spring constant (k) and the displacement of the block (x) from its initial position to the position where the spring has returned to its uncompressed length. We can use the formula:
W = (1/2) * k * x^2
where W is the work done on the block, k is the spring constant, and x is the displacement of the block.
This formula is derived from the potential energy stored in the spring, which is given by:
U = (1/2) * k * x^2
where U is the potential energy stored in the spring.
When the block is initially at rest, the spring is compressed, and it has potential energy given by U = - (1/2) * k * x^2, where x is the initial compression of the spring.
Note that the negative sign indicates that the work done by the spring is negative, which means that the spring is doing work on the block in the opposite direction to the displacement of the block. This is because the spring force is always directed opposite to the displacement of the block.
As the block is released, the spring begins to push it back to its uncompressed length, and the block begins to move.
The work done on the block by the spring is equal to the change in potential energy of the spring, which is given by:
W = U_final - U_initial
Since the final position of the block is where the spring has returned to its uncompressed length, the final potential energy of the spring is zero. Therefore, the work done on the block by the spring is:
W = U_initial
Substituting the initial potential energy of the spring into this equation, we get:
W = (1/2) * k * x^2
Therefore, the work done on the block by the spring during its move from its initial position to where the spring has returned to its uncompressed length is given by the formula:
W = (1/2) * k * x^2
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the electric field 0.300 m from a very long uniform line of charge is 850 n/c . part a how much charge is contained in a section of the line of length 1.70 cm ? express your answer in coulombs.
The charge in the section of the line of length 1.70 cm is:$$Q = (1.70 × 10⁻² m) * (2.16 × 10⁻⁵ C/m) = 1.277 × 10⁻⁷ C
The electric field 0.300 m from a very long uniform line of charge is 850 n/c. How much charge is contained in a section of the line of length 1.70 cm? The answer is 1.277 × 10⁻⁷ C. Explanation: To begin, let's consider the electric field due to an infinite line of charge. The electric field generated by a uniformly charged infinite line of charge is given by:$$E = \frac{λ}{2πεr}$$where, E is the electric field, λ is the linear charge density (charge per unit length), r is the distance from the wire, and ε is the permittivity of free space. To begin with, we can rearrange the equation for electric field:$$λ=\frac{2πεrE}{l}$$Where, l is the length of the line section of interest, E is the electric field at the distance r from the line of charge, and λ is the linear charge density. Now we can plug in the given values:$$(1.70 cm)λ = Q$$$$λ=\frac{2πεrE}{l}$$λ = (2π * 8.85 × 10⁻¹² F/m) * (0.300 m) * (850 N/C) / (0.0170 m)λ = 2.16 × 10⁻⁵ C/mSo, the charge in the section of the line of length 1.70 cm is:$$Q = (1.70 × 10⁻² m) * (2.16 × 10⁻⁵ C/m) = 1.277 × 10⁻⁷ C$$Therefore, 1.277 × 10⁻⁷ C.
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In the formula v = f X, what measurement is used for the frequency of the wavelength?
v = fλ links the velocity, frequency, and wavelength of a wave and is used to compute one of these parameters if the other two are known.
What unit of measurement is the wavelength's frequency?The wavelength formula shows the wavelength in metres. The v represents wave velocity and is measured in metres per second (mps). In addition, the letter "f" stands for frequency, which is expressed in hertz (Hz).
Which of the following best describes the wavelength measuring unit?The term wavelength implies that it measures length. Its measurements are often expressed in length measurements or metric units. In other words, wavelengths can be expressed in their SI units, metres.
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Why is momentum not conserved in real life situations
Momentum is not always conserved in real-life situations because external forces can act on a system and change its momentum.
For example, when two cars collide, friction and air resistance can cause the momentum of the system to change. Similarly, when a ball is thrown in the air, gravity and air resistance act on it and cause its momentum to change. Other factors such as deformation, energy loss, and imperfect collisions can also cause momentum to be lost or gained. Therefore, while momentum is a useful concept in physics, it is important to consider the impact of external factors when analyzing real-world situations.
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a long, straight wire carries a current of 8.60 a. an electron is traveling in the vicinity of the wire. at the instant when the electron is 4.50 cm from the wire and traveling at a speed of 6.00 * 104 m>s directly toward the wire, what are the magnitude and direction (relative to the direction of the current) of the force that the magnetic field of the current exerts on the electron?
The magnitude and direction of the force that the magnetic field of the current exerts on the electron in a a long, straight wire is 1.96 x 10⁻¹⁸ N and direction of the force is opposite to the direction of the current.
The magnetic field of the current exerts a force on the electron of magnitude 6.072 x 10⁻¹³ N in a direction that is opposite to the direction of the current.
where
Current, I = 8.60 A
Distance of electron from wire, r = 4.50 cm = 0.045 m
Velocity of electron, v = 6.00 x 10^4 m/s
The force on the electron due to magnetic field of current-carrying wire is given by:
F = (μ * I * q) / (2 * π * r)
where μ is the magnetic permeability of free space and is equal to 4π x 10⁻⁷ Tm/A,
q is the charge of electron and is equal to -1.6 x 10⁻¹⁹ C, and
r is the distance between the electron and the wire.
Substituting the values, we get:
F = (4π x 10⁻⁷ Tm/A) * (8.60 A) * (-1.6 x 10⁻¹⁹ C) / (2 * π * 0.045 m)
F = -1.96 x 10⁻¹⁸ N.
The negative sign indicates that the direction of force is opposite to the direction of the current.
So, the magnitude of the force exerted by the magnetic field on the electron is 1.96 x 10⁻¹⁸ N, and the direction of the force is opposite to the direction of the current.
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a 2.70 kg ball is attached to a ceiling by a 1.35 m long string. the height of the room is 4.45 m. what is the gravitational potential energy of the ball relative to the ceiling?
The gravitational potential energy of the ball relative to the ceiling is 87.9 J.
The gravitational potential energy of an object of mass m at a height h above a reference level (in this case, the ceiling) is given by:
U = mgh
where g is the acceleration due to gravity.
In this problem, the ball is suspended from the ceiling by a string, so its height above the ceiling is the length of the string, minus the radius of the ball. Assuming the ball is a sphere with a radius of 0.135 m (half the length of the string), we can calculate its height above the ceiling as:
h = 4.45 m - 1.35 m + 0.135 m = 3.24 m
(Note that we subtract the length of the string from the height of the room, and add half the length of the string to account for the radius of the ball.)
Plugging in the given values, we get:
U = (2.70 kg)(9.81 m/s^2)(3.24 m)
U = 87.9 J
Therefore, the result is 87.9 J.
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how many springs does it take to model the thermal energy of diamond and how many for solid argon? explain/justify your answer using appropriate components of the particle model of thermal energy and/or previous models we have used.
In order to model the thermal energy of diamond, 4 springs are required, while the model the thermal energy of solid argon 3 springs are required.
Thermal energy is the internal energy in a substance, that is, the energy of the particles that make up a substance. When two objects at different temperatures come into contact, the heat is transferred from the hotter object to the colder object until both objects reach the same temperature. A system of springs may be used to represent a solid. The particles of a solid are represented by the springs, which are elastic. The more energy the system has, the more the springs will vibrate.
The particle model of thermal energy is based on the idea that all matter is made up of tiny particles that are constantly in motion, and that the faster these particles move, the hotter the object becomes. To model the thermal energy of diamond, four springs are required because diamond is a covalent network solid in which each carbon atom is bonded to four other carbon atoms in a tetrahedral arrangement. Diamond's structure is made up of carbon atoms bonded together by strong covalent bonds. When a carbon atom is bonded to four other carbon atoms, it forms a very strong and stable tetrahedral structure. Diamond's thermal energy is modeled using four springs.
To model the thermal energy of solid argon, three springs are required because argon is a noble gas with a face-centered cubic structure. Solid argon, like other noble gases, has a simple structure. The argon atoms in solid argon are arranged in a cubic array, with an atom at each corner and one in the center of each face of the cube. To model the thermal energy of solid argon, three springs are used. The thermal energy is modeled using these three springs.
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if a wavelength is 635 nm, what is the frequency? please show all the steps and all of your work when you upload your final answer.
If a wavelength is 635 nm, the frequency is 4.72 × 10¹⁴ Hz.
The frequency of a wavelength is determined by the formula f = c/λ, where f is the frequency, c is the speed of light (3.00 x 108 m/s), and λ is the wavelength.
Given,
Wavelength = 635 nm
To find, frequency
Formula
The velocity of light = Wavelength × Frequency.
C = λ × f
Frequency f = C / λ
Where C = 3 × 10⁸ m/s, λ = 635 nm = 635 × 10⁻⁹ m
∴ f = C / λ
= (3 × 10⁸ m/s) / (635 × 10⁻⁹ m)
= (3 × 10⁸) × (10⁹ / 635)Hz= 4.72 × 10¹⁴ Hz
Frequency = 4.72 × 10¹⁴ Hz
Therefore, the frequency is 4.72 × 10¹⁴ Hz.
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pleases can someone help me with this question
Physiological fitness, body circumference fitness and bone strength fitness comes under nonperformance-related fitness while health-related fitness and skill related fitness comes under performance-related fitness.
Physiological Fitness refers to the ability of the body to meet the demands of physical activity and exercise also includes factors such as aerobic and muscular strength, endurance, and flexibility. Skill Related Fitness refers to physical abilities that are related to performance of sports, such as agility, coordination, balance, power, speed, and reaction time. Health-Related Fitness refers to the components of physical fitness related to health, such as cardiorespiratory fitness, body composition, and muscular strength and endurance. Bone Strength Fitness refers to the strength of the bones and how well they can withstand force and protect from injury. Body Circumference Fitness refers to the circumference of the body and how well it is proportioned to support physical activities.
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A boy on a 1.9 kg skateboard initially at rest
tosses a(n) 8.0 kg jug of water in the forward
direction.
If the jug has a speed of 2.7 m/s relative to
the ground and the boy and skateboard move
in the opposite direction at 0.65 m/s, find the
boy’s mass.
Answer in units of kg.
Answer:
Approximately [tex]31.3\; {\rm kg}[/tex]. (Assuming the friction between the skateboard and the ground is negligible.)
Explanation:
The momentum [tex]p[/tex] of an object of [tex]m[/tex] and velocity [tex]v[/tex] is:
[tex]p = m\, v[/tex].
When the boy tossed the jug of water, the change in the momentum of the jug would be:
[tex]\Delta p(\text{jug}) = m(\text{jug}) \, (v(\text{jug}) - u(\text{jug}))[/tex], where:
[tex]m(\text{jug}) = 8.0\; {\rm kg}[/tex] is the mass of the jug;[tex]v(\text{jug}) = 2.7\; {\rm m\cdot s^{-1}}[/tex] is the velocity of the jug after the toss;[tex]u(\text{jug}) = 0\; {\rm m\cdot s^{-1}}[/tex] is the initial velocity of the jug, which was at rest before the toss.Hence:
[tex]\begin{aligned}\Delta p(\text{jug}) &= m(\text{jug}) \, (v(\text{jug}) - u(\text{jug})) \\ &= (8.0)\, (2.7 - 0)\; {\rm kg\cdot m\cdot s^{-1}} \\ &= 21.6\; {\rm kg\cdot m\cdot s^{-1}}\end{aligned}[/tex].
Similarly, the change in the momentum of the skateboard would be:
[tex]\Delta p(\text{board}) = m(\text{board}) \, (v(\text{board}) - u(\text{board}))[/tex], where:
[tex]m(\text{board}) = 1.9\; {\rm kg}[/tex] is the mass of the board;[tex]v(\text{board}) =(-0.65)\; {\rm m\cdot s^{-1}}[/tex] is the velocity of the board after the toss;[tex]u(\text{board}) = 0\; {\rm m\cdot s^{-1}}[/tex] is the initial velocity of the board.Note that the velocity of the board [tex]v(\text{board})\![/tex] after the toss is opposite to that of the jug. The sign of [tex]v(\text{board})[/tex] would be opposite to that of [tex]v(\text{jug})[/tex]. Since [tex]v(\text{jug})\![/tex] is positive, the value of [tex]v(\text{board})\!\![/tex] should be negative.
[tex]\begin{aligned}\Delta p(\text{board}) &= m(\text{board}) \, (v(\text{board}) - u(\text{board})) \\ &= (1.9)\, ((-0.65)- 0)\; {\rm kg\cdot m\cdot s^{-1}} \\ &= (-1.235)\; {\rm kg\cdot m\cdot s^{-1}}\end{aligned}[/tex].
Let [tex]m(\text{boy})[/tex] denote the mass of the boy. The velocity of the boy was initially [tex]u(\text{boy}) = 0\; {\rm m\cdot s^{-1}}[/tex] and would become [tex]v(\text{boy}) =(-0.65)\; {\rm m\cdot s^{-1}}[/tex] after the toss. The change in the velocity of the boy would be:
[tex]\Delta p(\text{boy}) = m(\text{boy}) \, (v(\text{boy}) - u(\text{boy}))[/tex].
Under the assumptions, the total changes in the momentum of this system (the boy, the skateboard, and the jug) should be [tex]0[/tex]. Thus:
[tex]\Delta p(\text{boy}) + \Delta p(\text{boy}) + \Delta p(\text{jug}) = 0[/tex].
Rearrange and solve for the mass of the boy:
[tex]\Delta p(\text{boy}) = -\Delta p(\text{jug}) - \Delta p(\text{board})[/tex].
[tex]\begin{aligned} m(\text{boy}) &= \frac{-\Delta p(\text{jug}) - \Delta p(\text{board})}{v(\text{boy}) - u(\text{boy})} \\ &= \frac{-(21.6) - (-1.235)}{(-0.65) - 0}\; {\rm kg} \\ &\approx 31.3\; {\rm kg}\end{aligned}[/tex].
if it rotates through 8.00 revolutions in the first 2.50 s , how many more revolutions will it rotate through in the next 5.00 s ?
The object will rotate through 16.00 revolutions in the next 5.00s if it rotates through 8.00 revolutions in the first 2.50s.
The first step to answer this question is to determine the rotational speed (angular velocity) of the object. To do this, we use the formula:
Angular velocity = number of revolutions / time
So, the angular velocity of the object is given by:
Angular velocity = 8.00 revolutions / 2.50 s
Angular velocity = 3.20 revolutions per second
Now, we can use this angular velocity to determine the number of revolutions the object will rotate through in the next 5.00 s. To do this, we use the formula:Number of revolutions = angular velocity x time
So, the number of revolutions the object will rotate through in the next 5.00 s is given by:
Number of revolutions = 3.20 revolutions per second x 5.00 s
Number of revolutions = 16.00 revolutions
Therefore, the object will rotate through 16.00 revolutions in the next 5.00 s.
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a bicycle wheel of radius 40.0 cm and angular velocity of 10.0 rad/s starts accelerating at 80.0 rad/s2. what is the tangential acceleration of the wheel at this time point?
The tangential acceleration of the wheel at this time point is 32 m/s².
What is angular velocity?The radius of the wheel, r = 40.0 cm = 0.4 m
The angular velocity of the wheel, ω = 10.0 rad/s
The angular acceleration of the wheel, α = 80.0 rad/s²
The tangential acceleration of the wheel
tangential acceleration = r × angular acceleration (a = rα)
Substituting the values of r and α in the above equation,
Tangential acceleration = 0.4 m × 80.0 rad/s²
Tangential acceleration = 32 m/s²
The tangential acceleration of the wheel at this time point is 32 m/s².
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If a 20-kilogram anvil is held 3 meters what is the potential energy?
The potential energy (PE) of an object is given by the formula:
PE = mgh
where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2 on Earth), and h is the height of the object above some reference point (in this case, the ground).
Substituting the given values, we get:
PE = (20 kg) x (9.8 m/s^2) x (3 m) = 588 J
Therefore, the potential energy of the 20-kilogram anvil held 3 meters above the ground is 588 joules (J).
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at what angle is the first-order maximum for 450-nm wavelength blue light falling on double slits separated by 0.0500 mm?
The first-order maximum for 450-nm wavelength blue light falling on double slits separated by 0.0500 mm is approximately 6.2°.
The angle of the first-order maximum refers to the angle at which the brightest interference pattern appears on a screen placed behind two closely spaced slits when illuminated with the blue light of 450-nm wavelength.
The angle is determined by the equation:
theta_m = (m*lambda)/d
where m is the order, lambda is the wavelength, and d is the slit separation.
theta_m = (1*450E-9 m)/0.0500 mm
theta_m = 6.2°
Thus, the first-order maximum for double slits of 0.0500 mm at 450 nm λ blue light is around 6.2°.
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What is the direction and magnitude of the Electric Field 4.0 m away from an 8.6 μC charge?
the plane is flying at 800 miles per hour. how far will the package travel horizontally during its descent?
The distance that a package will travel horizontally during its descent when a plane is flying at 800 miles per hour can be calculated using the following steps is 1600 miles.
What is the distance?Determine the time taken for the package to hit the ground. We know that when an object is dropped from a certain height, it falls under the influence of gravity.
The acceleration due to gravity is 9.8 m/s². The formula for the time taken for an object to fall can be given by:
t = √(2h/g)
where, t is the time taken for the object to fall is the height from which the object was dropped g is the acceleration due to gravity.
We know that the distance traveled by the package horizontally can be given by d = vt
where, d is the distance traveled horizontally by the package v is the velocity of the planet is the time taken for the package to hit the ground.
Thus, the distance is 1600 miles.
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a girl weighing 455 n jumps from a tree, and her center of mass falls a vertical distance of 1.50 m. find the impulse necessary to bring her to rest.
The impulse necessary to bring her to rest is zero (0 Ns). Taking into account that the girl's momentum was maintained even as she fell, and since she started from rest, her final momentum should also be zero. So no additional push is needed beyond what gravity provides.
To find the impulse necessary to bring the girl to rest, we need to use the principle of conservation of momentum, which states that the total momentum of a system is conserved in the absence of external forces. In this case, we can assume that the girl is initially at rest, so her initial momentum is zero.
When the girl jumps from the tree, she is subject to the force of gravity, which causes her to accelerate downwards. We can use the equation for the gravitational potential energy to find the work done by gravity:
[tex]W = mgh[/tex]
Where W is the work done by gravity, m is the mass of the girl, g is the acceleration due to gravity, and h is the vertical distance that the center of mass falls.
Plugging in the given values, we get:
[tex]W = (455 N)(1,50 m)(9,81 m/s^2) \\W= 6.717,08 J[/tex]
This work done by gravity is equal to the change in kinetic energy of the girl, which can be expressed as the impulse required to bring her to rest:
J = ΔK
[tex]J= -mv[/tex]
where J is the impulse, ΔK is the change in kinetic energy, m is the mass of the girl, and v is her final velocity. Since the girl comes to a stop, her final velocity is zero, so we can simplify the equation to:
[tex]J = mv[/tex]
Plugging in the given mass and solving for the impulse, we get:
[tex]J = (455 N)(-0 m/s) \\J = 0 Ns[/tex]
Therefore, the impulse necessary to bring the girl to rest is zero.
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An unpolarized laser beam enters a container of water. The beam is partially reflected from the water-glass surface, as indicated in the figure below. For what angle of incidence will this reflected beam be completely polarized? [image attached below]
At 57.27° of angle of incidence this reflected beam will be completely polarized when initially an angle of incidence will this reflected beam be completely polarized.
The angle of incidence for which the reflected beam will be completely polarized is Brewster's angle, which is given by:
sin(θB) = n2/n1
where n1 is the refractive index of the medium that the beam is entering (in this case, water), and
n2 is the refractive index of the medium that the beam is reflecting off of (in this case, glass).
For water the refractive index n1 = 1.333 and
for glass the refractive index n2 = 1.52,
Then, sin(θB) = 1.52/1.333 = 57.27°
Therefore, the reflected beam will be completely polarized at an angle of incidence of 57.27°.
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(10.04 mc) determine the best reason for the summation from n equals 1 to infinity of negative 1 to the n power times n squared over quantity 3 times n squared minus 1 end quantity diverging.
The best reason for the summation from n equals 1 to infinity of (-1)^n * n^2 / (3n^2 - 1) diverging is because the terms do not approach zero as n approaches infinity.
1. Examine the given summation: Σ((-1)^n * n^2 / (3n^2 - 1))
2. Analyze the expression inside the summation as n approaches infinity:
(-1)^n * n^2 / (3n^2 - 1)
3. Observe that the numerator, (-1)^n * n^2, oscillates between positive and negative values due to (-1)^n term.
4. Notice that the denominator, (3n^2 - 1), approaches infinity as n approaches infinity since it's a quadratic function with a positive coefficient for the highest power term (3n^2).
5. However, the overall fraction does not approach zero because the numerator (n^2) also approaches infinity as n approaches infinity, and its oscillation between positive and negative values prevents a limit of zero.
In conclusion, the best reason for the given summation diverging is that the terms do not approach zero as n approaches infinity.
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speed up a frictionless ramp ( 30.03) by a horizontal force . what are the magnitudes of (a) and (b) the force on the crate from the ramp?
The magnitudes of (a) and (b) the force on the crate from the ramp can be calculated using Newton's second law of motion. According to this law, the net force on an object is equal to the mass of the object multiplied by its acceleration.
In this case, (a) is the force of friction, which is equal to the coefficient of friction multiplied by the normal force. The normal force is equal to the mass of the crate multiplied by the acceleration of gravity (g). Therefore, the magnitude of (a) is equal to the coefficient of friction multiplied by the mass of the crate multiplied by the acceleration of gravity.
(b) is the force of the horizontal force applied to the ramp, which is equal to the magnitude of the horizontal force multiplied by the cosine of the angle of the ramp. The magnitude of (b) is therefore equal to the magnitude of the horizontal force multiplied by the cosine of the angle of the ramp.
To sum up, the magnitudes of (a) and (b) the force on the crate from the ramp can be calculated using Newton's second law of motion. (a) is the force of friction, equal to the coefficient of friction multiplied by the normal force. (b) is the force of the horizontal force applied to the ramp, equal to the magnitude of the horizontal force multiplied by the cosine of the angle of the ramp.
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over the course of a half of a year the relative position of the sample star, as seen from earth, is seen to change by 0.400''. what is the parallax angle (p) in this case?\
Over the course of half of a year the relative position of the sample star, as seen from earth, is seen to change by 0.400''. The parallax angle in this case is: 0.400''
Given that the relative position of the sample star as seen from earth is seen to change by 0.400'' over the course of half of a year. We are to determine the parallax angle in this case. Parallax angle (p) can be defined as the angle between the baseline and the line of sight to the star. It is the angle between two lines drawn from the star to the Earth, separated by six months, and viewed at a right angle to the baseline.
It is measured in seconds of arc (or arcseconds), and it is usually too small to measure directly. The parallax angle can be calculated using the formula below: parallax angle (p) = (d/b)
where d is the distance from the Earth to the star and b is the baseline, which is half of the distance that the Earth moves in its orbit over six months, which is equal to 1 astronomical unit (AU).
Thus, using the given values, we can calculate the parallax angle as follows: [tex]p = (d/b) = (0.400/1) = 0.400''[/tex]
Thus, the parallax angle, in this case, is 0.400'' (arcseconds). Therefore, the relative position of a star as seen from Earth changes with the change in the Earth's position. The change in position helps to determine the distance from the Earth to the star using the parallax angle.
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in the above diagram of a simple circuit with one resistor, is the voltmeter correctly integrated into the circuit? group of answer choices yes no not enough information.
Not enough information. The voltmeter needs to be connected in parallel with the resistor to measure the voltage across the resistor.
What is voltmeter?A voltmeter is an electrical instrument for measuring the potential difference, or voltage, between two points in an electrical circuit. It is used to measure the voltage of a battery, a generator, or any other source of electrical potential. The voltmeter consists of an electrometer, which is an instrument that measures electrical potential, and a scale that reads out the voltage. The voltage is measured in volts, and the instrument is usually calibrated to read in units of millivolts or kilovolts. The operation of the voltmeter can be explained by Ohm’s Law, which states that the voltage in an electrical circuit is proportional to the current in the circuit. When the voltage is measured, a current is induced in the circuit, and the electrometer measures the potential difference between the two points. The voltmeter is a key instrument for any electrical engineer, as it is used to measure the voltage of a power source or the efficiency of an electrical circuit.
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What is the maximum ramp angle that still allows the crate to remain at rest? (Make sure the coefficient of friction is 0.7.) .
Mass (m) = 300kg
The highest ramp angle at which the crate can still be at rest is roughly 35.5 degrees.
To determine the maximum ramp angle that still allows the crate to remain at rest, you need to consider the balance of forces acting on the crate. When the crate is on the verge of slipping, the frictional force is equal to the component of gravitational force acting parallel to the ramp.
Given that the coefficient of friction (µ) is 0.7, you can use the formula for the frictional force:
Frictional force (F_friction) = µ * Normal force (F_N)
The normal force acting on the crate is the component of gravitational force acting perpendicular to the ramp, which can be calculated as:
F_N = m * g * cos(θ)
The gravitational force acting parallel to the ramp can be calculated as:
F_gravity_parallel = m * g * sin(θ)
At the maximum angle, the frictional force will be equal to the gravitational force acting parallel to the ramp:
µ * F_N = F_gravity_parallel
Now, substitute the known values:
0.7 * (m * g * cos(θ)) = m * g * sin(θ)
Since the mass (m) and gravitational acceleration (g) are the same on both sides of the equation, they can be canceled out:
0.7 * cos(θ) = sin(θ)
To find the maximum angle (θ), you can use the arctangent function:
θ = arctan(0.7)
θ ≈ 35.5 degrees
So, the maximum ramp angle that still allows the crate to remain at rest is approximately 35.5 degrees.
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a satellite is orbiting the earth at an altitude of 744 km above the surface of earth. what is the acceleration due to gravity in m/s2 at that altitude?
The acceleration due to gravity in m/s² at that altitude of 744 km is 9.797.
To find out what the acceleration due to gravity is in m/s² at an altitude of 744 km above the surface of earth, use the formula `g = Gm/r²`.
Given,The altitude of the satellite, h = 744 km,The radius of the earth, r = 6371 km, Formula for acceleration due to gravity:
g = Gm/r²
Here, the value of G, the universal gravitational constant, is 6.67 x 10^-11 Nm²/kg².Mass of the Earth, m = 5.97 x 10^24 kg.Let's calculate the radius of the orbit, R.Radius of the orbit = r + h= 6371 + 744 = 7115 km = 7.115 x 10^6 m.So, we have,
g = Gm/R²= 6.67 x 10^-11 x 5.97 x 10^24 / (7.115 x 10^6)²= 9.797 m/s².Therefore, the acceleration due to gravity in m/s² at that altitude is 9.797.
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a 10.0-mf capacitor is fully charged across a 12.0-v bat- tery. the capacitor is then disconnected from the battery and connected across an initially uncharged capacitor with capacitance c. the resulting voltage across each capacitor is 3.00 v. what is the value of c?
The value of uncharged capacitor in series with a 10.0-microfarad capacitor, given that each capacitor has a voltage of 3.00 volts, can be calculated using the formula for equivalent capacitance in series and formula for charge on a capacitor. The value of c is approximately 4.00 microfarads.
To determine the value of c, which is [tex]1/Ceq = 1/C1 + 1/C2[/tex] . Initially, the 10.0-microfarad capacitor has a charge of [tex]Q = CV = (10.0 * 10^{-6 }F) * 12.0 V = 1.20 * 10^{-4} C[/tex].
When it is connected in series with uncharged capacitor with capacitance c, charge is shared between the two capacitors. The charge on 10.0-microfarad capacitor is also equal to the charge on uncharged capacitor, which is given by [tex]Q = (3.00 V) * C[/tex] .
Equating the two expressions for Q and solving for c, we get [tex]C = Q/3.00[/tex] [tex]V = (1.20 * 10^{-4 C}) / (3.00 V) = 4.00 * 10^{-5 F}[/tex]. Therefore, value of c is approximately 4.00 microfarads.
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if an electric wire is allowed to produce a magnetic field no larger than that of the earth (0.50 x 10-4 t) at a distance of 15 cm from the wire, what is the maximum current the wire can carry? express your answer using 2 significant figures
If an electric wire is allowed to produce a magnetic field no larger than that of the earth (0.50 x 10-4 t) at a distance of 15 cm from the wire, the maximum current the wire can carry is 1.8 A.
The maximum current the wire can carry is 1.8 A.
The formula to calculate the magnetic field due to a current-carrying wire is given by,
B = μ₀I/(2πr)
Here, B = maximum magnetic field = 0.50 × 10⁻⁴ T
μ₀ = permeability of free space = 4π × 10⁻⁷ T m/II = current in the wirer = distance from the wire = 15 cm = 0.15 m
Putting the given values in the formula,
0.50 × 10⁻⁴ T
= 4π × 10⁻⁷ T m/I × (2π × 0.15 m)
Solving for I, we get,
I = 1.8 A
Therefore, the maximum current the wire can carry is 1.8 A.
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