please help me with these questions plaese hurry need these today

The standard form of a quadratic function is:

`f(x) = ax^2 + bx + c`

If the zeros of the function are 3 and 1/2, then the factors of the function are:

`(x - 3)` and `(x - 1/2)`

To find the quadratic function using these factors, you can first multiply them together:

`(x - 3)(x - 1/2) = x^2 - 7/2x + 3/2`

Now we have:

`f(x) = x^2 - 7/2x + 3/2`

This is the quadratic function in standard form that has zeros of 3 and 1/2.

Answer:

(2, 180)

Step-by-step explanation:

w(x)=-5x^2+20x+160

a=-5 b=20

x=-20/2x(-5)

x=2

w(2)=180

2, 180

The appropriate measure of variability for the data shown is the range, and its value is 48. The answer is: "The range is the best measure of variability, and it equals 48."

What is variability?

To determine the appropriate measure of variability for the data shown, we need to consider the characteristics of the data set. Since the data set is relatively small and discrete, the range would be an appropriate measure of variability.

To calculate the range, we subtract the smallest value from the largest value:

Largest value: 58

Smallest value: 10

Range = Largest value - Smallest value = 58 - 10 = 48

Therefore, the appropriate measure of variability for the data shown is the range, and its value is 48. The answer is: "The range is the best measure of variability, and it equals 48."

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The expression for the total amount of shoes for both people is 4X + 2.

As a result, total cost is the sum of fixed and variable costs, or TC = FC + VC = Kr+Lw.

Say Person 1 owns X pairs of shoes. So, Person 2 has two to three times as much as Person 1. This can be said as follows:

Person 2 possesses at least two more than three times Person 1's amount, so Person 2's amount is equal to 3X + 2.

By simply adding Person 1's and Person 2's shoe counts, we can determine the total number of shoes for both individuals, which results in:

Total equals the sum of the amounts given by Persons 1 and 2.

When we replace the value of Person 2's contribution, we obtain:

Amount total = X + (3X + 2)

If we simplify, we get:

Total = 4X plus 2

Hence, 4X + 2 is the total number of shoes for both individuals.

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It will take approximately 23.1 years for 60% population of the species to remain, assuming that the decrease rate remains constant over time.

We can utilize the exponential decay formula, which is given by, to respond to this question.

[tex]N(t) = N0 * e^(-rt) (-rt)[/tex]

N(t) is the population at time t, where N(t) is the population at time t, t is the time in years, and r is the yearly growth rate (or in this example, the annual drop rate).

Assuming that t is the number of years it will take for 60% of the species to survive, let's divide the drop rate by 100 to convert it from a percentage to a decimal. As a result, we have:

[tex]N(t) = 5000 * e^(-0.03t) \s0.6 * 5000 = 3000[/tex]

Given that N(t) is equal to 3000, we can solve for t by using the following method:

[tex]3000 = 5000 * e^(-0.03t) (-0.03t)\\t = ln(0.6) / -0.03 0.6 = e(-0.03t) ln(0.6) = -0.03t[/tex]

Calculating the answer, we obtain:

t = 23.1

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Answer:

180 dollars

Step-by-step explanation:

270 for 16 hours = 16.875 dollars for each hour

15.00 an hour will be paid to larry

larry is doing 3/4 of those 16 hours

12 hours

15 x 12

larry gets 180 dollars for 12 hours of work

hope this helps x

[tex]\qquad \qquad \textit{Inverse Trigonometric Identities} \\\\ \begin{array}{cccl} Function&Domain&Range\\[-0.5em] \hrulefill&\hrulefill&\hrulefill\\ y=cos^{-1}(\theta)&-1 ~\le~ \theta ~\le~ 1& 0 ~\le~ y ~\le~ \pi \\\\ y=tan^{-1}(\theta)&-\infty ~\le~ \theta ~\le~ +\infty &-\frac{\pi}{2} ~\le~ y ~\le~ \frac{\pi}{2} \end{array} \\\\[-0.35em] ~\dotfill[/tex]

[tex]cos^{-1}\left( -\cfrac{\sqrt{2}}{2} \right)\implies \theta \hspace{5em}\stackrel{\textit{so we can say}}{cos(\theta )=-\cfrac{\sqrt{2}}{2}} \\\\\\ \theta =cos^{-1}\left( -\cfrac{\sqrt{2}}{2} \right)\implies \stackrel{ \textit{on the II Quadrant} }{\theta =\cfrac{3\pi }{4}} \\\\[-0.35em] ~\dotfill\\\\ sin\left[ cos^{-1}\left( -\cfrac{\sqrt{2}}{2} \right) \right]\implies sin\left( \cfrac{3\pi }{4} \right)\implies \boxed{\cfrac{\sqrt{2}}{2}}[/tex]

now let's find the angle for the inverse tangent

[tex]sin\left( \cfrac{\pi }{2} \right)\implies 1\hspace{5em}\stackrel{\textit{so we can say}}{tan^{-1}\left[ sin\left( \frac{\pi }{2} \right) \right]}\implies tan^{-1}(1) \stackrel{ \textit{on the I Quadrant} }{\implies\boxed{\cfrac{\pi }{4}}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin\left[ cos^{-1}\left( -\frac{\sqrt{2}}{2} \right) \right]~~ + ~~tan^{-1}\left[ sin\left( \frac{\pi }{2} \right) \right]\implies \cfrac{\sqrt{2}}{2}~~ + ~~\cfrac{\pi }{4} \implies \boxed{\cfrac{2\sqrt{2}+\pi }{4}}[/tex]

for the sine function we end up in the II Quadrant because the inverse cosine function range is constrained to the I and II Quadrants only, so our angle comes from that range.

Likewise, our angle from the inverse tangent comes from the I Quadrant, because inverse tangent range is only I and IV Quadrants.

The system of equations that has only one solution is the one where the equations have different slopes, it is the one in option C.

y = 4x - 5

y = -x - 5

A system of linear equations will have only one solution always that the lines are neither parallel nor the same line.

So, one way to check this, is to write both lines in the slope intercept form, and check that the two lines have different slopes.

For example, the first option will give.

y = -4x - 2

y = -4x + 5

These are parallel (same  slope different intercept), then this systm has no solutions.

The correct option will be C, where the system is:

y = 4x - 5

y = -x - 5

The slopes are different.

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According to the solution we have come to find that, The missing sides are t=ST=9 and s=RT=12.

what is right angle triangle?

A right angle triangle, also known as a right triangle, is a triangle that has one angle measuring 90 degrees, which is also known as a right angle. The side opposite to the right angle is called the hypotenuse, and the other two sides are called legs or catheti. The Pythagorean theorem, which states that the sum of the squares of the two legs of a right triangle is equal to the square of the hypotenuse, is a fundamental property of right triangles. Right triangles are important in mathematics and physics, and they have many applications in geometry, trigonometry, and calculus.

We can use the fact that the two triangles are similar to set up a proportion and solve for the missing sides.

AB/RS = BC/ST = AC/RT

Substituting the given values:

5/RS = 3/9 = 4/s

Solving for RS:

RS = (5/3) * 9 = 15

Solving for RT:

RT = (4/5) * 15 = 12

Therefore, the missing sides are t=ST=9 and s=RT=12.

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The trade balance must be negative.

If Canada imports more goods and services than it exports, the trade balance must be negative.

Here's a step-by-step explanation of why this is true and why options A and E are wrong:

1. The trade balance is calculated as the value of exports minus the value of imports. If imports are greater than exports, the trade balance will be negative (C). This m that Canada is seen spending more on goods and services from other countries than it is receiving from the sale of its own goods and services to other countries.

2. The current account balance includes the trade balance, but also considers other transactions such as income from investments and transfers like foreign aid. While it is possible that a negative trade balance could be offset by other positive inflows, we do not have enough information to determine whether the current account balance must be negative (A) or positive (B). Therefore, we cannot definitively say that A or B is true.

3. The financial account (formerly called capital account) balance records the net change in ownership of financial assets, such as stocks and bonds, between a country and the rest of the world. A negative financial account balance means that a country's residents are purchasing more foreign assets than foreign residents are purchasing of that country's assets. A positive financial account balance means the opposite. Since we only have information about the trade balance and not the financial transactions, we cannot determine whether the financial account balance must be negative (D) or positive (E).

Based on the information given, we can only conclude that the trade balance must be negative (C) if Canada imports more goods and services than it exports.

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Answer: A - addition property of equality

Explanation: because -8x - 42 = -22

+42 +42

____________

-8x = 20

__ __

-8 -8

x = -2.5

The measure of the angle the cable car track makes with the valley floor is approximately 38.7 degrees.

The slope or inclination of a line or surface is sometimes referred to as the grade in mathematics. The ratio of the vertical change (rise) to the horizontal change (run) between any two locations on a line or surface is what is meant by this term. Usually, the grade is given as a percentage or a fraction. In engineering, building, and transportation, grades are frequently used to define the slope of roads, railroads, and other infrastructure. The grade, which refers to how steep the slope is when referring to a cable car, is a crucial element in determining the safety and effectiveness of the system.

To find the angle we use the trigonometric functions:

tan(θ) = grade = rise/run

Given that, the grade of the incline is 78%, then grade = 0.78.

θ = arctan(0.78) ≈ 38.7 degrees.

Hence, the measure of the angle the cable car track makes with the valley floor is approximately 38.7 degrees.

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Answer:

Proofs attached to answer

Step-by-step explanation:

Proofs attached to answer

The answer of the given question based on the trigonometry is , to calculate YZ, we should use the cosine function with the angle 35.5°.

The sine function is a mathematical function that relates the ratios of the lengths of two sides of a right triangle with the measure of one of its non-right angles. Specifically, the sine of an angle in a right triangle is defined as the ratio of the length of the side opposite to the angle to the length of the hypotenuse.

To use trigonometry to calculate YZ, we need to find a trigonometric ratio that involves the given side XZ and the angle opposite the requested side, which is angle YXZ. We don't have the measure of this angle, but we know that it is supplementary to the given angle 35.5°, so it must measure:

180° - 35.5° = 144.5°

We can use this angle and the given side XZ to find the length of YZ using the sine or cosine function.

In this case, the length of the opposite side is YZ, the length of the hypotenuse is XZ, and the measure of the angle is 144.5°. So we can write:

sin(144.5°) = YZ / XZ

Solving for YZ, we get:

YZ = XZ * sin(144.5°)

On the other hand, the cosine function , this case, the length of the adjacent side is YZ, the length of the hypotenuse is XZ, and the measure of the angle is 35.5°. So we can write:

cos(35.5°) = YZ / XZ

Solving for YZ, we get:

YZ = XZ * cos(35.5°)

Therefore, to calculate YZ, we should use the cosine function with the angle 35.5°.

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The corticospinal tracts carry information from the motor cortex, which is responsible for coordinating the movement of muscles, to the lower motor neurons. The extra-pyramidal tracts are made up of several types of neurons that play a role in modulating and fine-tuning the movement of muscles.

Neurons in the central nervous system (CNS) send instructions to muscles along a descending neural network called the descending motor pathways, which decussate in the medulla oblongata. This means that information from the brain travels down the spinal cord on both sides of the body, and crosses over to the opposite side at the medulla. The descending pathways start from the brainstem and motor cortex, and control the contraction of skeletal muscles, which are responsible for body movements.

The descending motor pathways are a series of neurons that connect the CNS to the muscles, transmitting the information required for voluntary body movements. Through the descending pathways, the brain can communicate with the muscles and control them. The pathways are divided into two parts, the corticospinal tracts and the extra-pyramidal tracts.

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Answer:

Step-by-step explanation:

Circle centre: (4,7)

Radius: 3

Equation is:

  [tex](x-h)^2+(y-k)^2=r^2[/tex]   (where (h,k) is center, r is radius)

  [tex](x-4)^2+(y-7)^2=3^2[/tex]

  [tex](x-4)^2+(y-7)^2=9[/tex]     (This is the general standard form )

in expanded form,

  [tex](x^2-8x+16)+(y^2-14y+49)=9[/tex]

  [tex]x^2+y^2-8x-14y+56=0[/tex]

Note: Unless stated either form is an acceptable answer.

The dimension of the solution space for 3 linearly independent equations in 5 unknowns is 2.

The dimension of the solution space for 3 linearly independent equations in 5 unknowns is 2. This is because, when solving a system of equations, the number of equations must match the number of unknowns; otherwise, it is impossible to solve. In this case, the number of equations (3) is less than the number of unknowns (5), meaning that the system is underdetermined. This means that there are infinite solutions, and the dimension of the solution space is 2 (the number of free variables).

In other words, the solution space is a two-dimensional plane where each point represents a possible solution to the system of equations. As the equations are linear, the solution space forms a linear subspace, which means that it is a flat surface.

It is also important to note that the linear independence of the equations is crucial to this solution. If the equations are dependent, then the solution space can have a dimension of 1, 0, or even a negative number. So, the dimension of the solution space for 3 linearly independent equations in 5 unknowns is 2.

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0.4

The probability that an undergraduate business major intends to attend classes full-time in pursuit of an MBA degree depends on the individual student's preferences and situation. Generally speaking, studies have shown that about 40% of undergraduate business majors choose to pursue an MBA degree full-time after graduating. Therefore, the probability of an undergraduate business major pursuing an MBA degree full-time can be estimated at 0.4.

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Answer:  SORRY THIS TOOK FOREVER ITS SO HARD- THE ANSWER IS F, C, D, H, E, A, G, B!!!

Step-by-step explanation:

THE LEAST TO GREATEST ARE F, C, D, H, E, A, G, B! HOPE IT HELPED!! :D

The solution of the match is

(1) Orthocenter          (C) The point at which the altitudes of a triangle                                                

                                              meet.

(2) Centroid                 (D) The point at which the medians of a triangle

                                             meet.

(3) Circumcenter         (A) The point of intersection of the perpendicular                  

                                             bisectors of the sides of a triangle.

(4) Incentre                 (B) The point at which the three angle bisectors      

                                             of a triangle meet.

The orthocenter of a triangle is the point where the altitudes of the triangle intersect. The orthocenter is not always inside the triangle, and in some cases, it may lie outside the triangle.

The centroid of a triangle is the point where the three medians of the triangle intersect. The centroid is always inside the triangle, and it is also the center of mass of the triangle.

The circumcenter of a triangle is the point where the perpendicular bisectors of the sides of the triangle intersect.  The circumcenter is not always inside the triangle, and in some cases, it may lie outside the triangle.

The incentre of a triangle is the point where the three angle bisectors of the triangle intersect. The incentre is always inside the triangle, and it is also the center of the circle that is inscribed inside the triangle.

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Complete Question:

Match the following.

(1) Orthocenter         (A) The point of intersection of the perpendicular                  

                                             bisectors of the sides of a triangle.

(2) Centroid                 (B) The point at which the three angle bisectors of

                                             a triangle meet.

(3) Circumcenter         (C) The point at which the altitudes of a triangle

                                              meet.

(4) Incentre                 (D) The point at which the medians of a triangle

                                             meet.

A. The equation of the line that passes through the point (4,3) and has a slope of -5/2 is y = (-5/2)x + 13.

B. The x-intercept of the equation is x = 26/5 or 5.2

A. To find the equation of a line that passes through the point (4,3) and has a slope of -5/2, we can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

where m is the slope, and (x1, y1) is the given point.

Substituting the values, we get:

y - 3 = (-5/2)(x - 4)

Expanding the right side:

y - 3 = (-5/2)x + 10

Adding 3 to both sides:

y = (-5/2)x + 13

B. To find the x-intercept of this equation, we need to set y = 0 and solve for x:

0 = (-5/2)x + 13

Multiplying both sides by -2/5:

0 = x - (26/5)

Adding (26/5) to both sides:

x = 26/5

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