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Discussion: If you put something like a piece of cardboard between a magnet and an iron nail, the magnet still holds the nail in place, even though the magnet is not touching the nail Explain how that happens. Use the words induce, magnetic field, permanent magnet and temporary magnet in your response.​

Acceleration can be calculated by dividing the change in velocity by the change in time. If we have a mass and force that makes the acceleration, the divide the force by mass to get the acceleration.

Acceleration is a physical quantity which describes the rate of change in velocity. Like velocity, acceleration is a vector quantity having both magnitude and direction.

If both speed and direction are changing and  if we want to know the acceleration at any particular moment in time, calculating acceleration can be challenging.

However, since just speed is changing, it is quite simple to determine average acceleration over time. After then, acceleration is equal to the time change divided by the velocity change.

a = ΔV/Δt

Similarly if have the force which accelerates a body of mass m, then the acceleration is the ratio of that force to the mass.

a = F/m

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Answer:

True

Explanation:

hope I could help :)

Answer:

true

Explanation:

i know my stuff

Answer:

2,8

Explanation:

The first electron shell would have 2 electrons, the second shell would have 8 electrons. This is because Neon has a relative charge of 10.

Answer: C. Balanced

Explanation:

I took the test and got it right.

Answer:

v_y = 10 - 10t

v_x = 10 m/s

Explanation:

This is a projectile launch where the x axis and y axis will be treated independently.

Now, towards the north on the x-axis, there will be no acceleration and so the speed is constant

So, vₓ = v₀ₓ

Whereas, on the vertical y - axis, the acceleration due to gravity with be negative since it's in a downward direction.

Thus, the equation is;

v_y  =  v_oy - gt

Now, the initial velocity component will be;

cos 45 = v₀ₓ/v₀

And sin 45 = v_₀y/v₀

Thus, we have;

v₀ₓ = v₀(cos 45)

Also, v_oy = v₀(sin 45)

Now, the initial velocity would be gotten from the equation of range which is;

R = (v₀² × sin 2θ)/g

Making v₀ the subject, we have;

v₀ = √(Rg/sin 2θ)

We are given;

R = 20 m

g = 10 m/s²

θ = 45°

Thus;

v₀ = √[20 × 10/(sin (2 × 45))]

v₀ = √200

v₀ = 14.14 m/s

Thus;

v₀ₓ = 14.14(cos 45) = 10 m/s

v_oy = 14.14(sin 45) = 10 m/s

Earlier we saw that;

v_y  =  v_oy - gt

Thus;

v_y = 10 - 10t

Also,we saw that;

vₓ = v₀ₓ

Thus;

v_x = 10 m/s

For the graph, we will use times of  t = 0, 0.2, 0.4, 0.6, 0.8, 1.0, 1.2

Thus, for each of those values of t, we will have the following values of v_oy

t (s)       v_oy (m / s)

0           10

0.2         8

0.4          6

0.6         4

0.8          2

1.0         0

1.2          -2

Graph is attached

Answer:

403 kg is the diffrence

Answer:

with what? I can help but with what

Answer:

2

Explanation:

The driver speeds up with acceleration a so that

35 m/s = 15 m/s + a (10.0 s)

Solve for a :

20 m/s = a (10.0 s)

a = (20 m/s) / (10.0 s)

a = 2 m/s²

Answer:

[tex]h_p = 30.46\ m[/tex]

Explanation:

Free Fall Motion

A free-falling object refers to an object that is falling under the sole influence of gravity. If the object is dropped from a certain height h, it moves downwards until it reaches ground level.

The speed vf of the object when a time t has passed is given by:

[tex]v_f=g\cdot t[/tex]

Where [tex]g = 9.8 m/s^2[/tex]

Similarly, the distance y the object has traveled is calculated as follows:

[tex]\displaystyle y=\frac{g\cdot t^2}{2}[/tex]

If we know the height h from which the object was dropped, we can solve the above equation for t:

[tex]\displaystyle t=\sqrt{\frac{2\cdot y}{g}}[/tex]

The stadium is h=32 m high. A pair of glasses is dropped from the top and reaches the ground at a time:

[tex]\displaystyle t_1=\sqrt{\frac{2\cdot 32}{9.8}}=2.56\ sec[/tex]

The pen is dropped 2 seconds after the glasses. When the glasses hit the ground, the pen has been falling for:

[tex]t_2=2.56 - 2 = 0.56\ sec[/tex]

Therefore, it has traveled down a distance:

[tex]\displaystyle y=\frac{9.8\cdot 0.56^2}{2} = 1.54\ m[/tex]

Thus, the height of the pen is:

[tex]h_p = 32 - 1.54\Rightarrow h_p=30.46\ m[/tex]

The pen is 30.52 m above the ground.

Given that the height of the stadium is h = 32m

The initial velocity of the glasses will be 0.

[tex]h=\frac{1}{2}gt^{2} \\t=\sqrt{\frac{2h}{g} } \\t=\sqrt{\frac{2*32}{9.8} }\\t=2.55s[/tex]is the time taken for the glasses to hit the ground.

Now the pen is released 2 seconds later. So by the time the glasses hit the ground the pen has spent:

[tex]t^{'}=2.55-2\\t^{'}=0.55s[/tex]in the air

distance traveled by the pen:

[tex]d=\frac{1}{2}gt^{2}\\\\d=\frac{1}{2}*9.8*0.55*0.55\\\\d=1.48m[/tex]

So the pen is  [tex]h-d=32-1.48=30.52m[/tex]  above the ground.

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Answer:

Blank 1 (asteroids)

Blank 2 (Ceres)

Explanation:

Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.

Asteroids are stony elements that circle the Sun. Although asteroids circle the Sun in the same way as planets, they are considerably smaller.]

A dwarf planet located between Mars and Jupiter in the asteroid belt. Ceres was the first asteroid discovered, it was originally classed as a planet,

Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.

The correct option from the drop-down menu is asteroids and ceres.

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Answer:

easy thats

13

Explanation:

Answer:

Net force= 14 units

The object is unbalanced

Explanation:

The net force refers to the sum of all forces applied to an object. However, the direction of force applied determine the net force. In this question, a boy and girl is pulling a heavy crate at the same time.

This means that the force is in the same direction, hence, the net force will be:

F(N) = 7 + 7 = 14 unit

However, since the pull is occuring at the same direction. This means that the object has a net force, therefore, will move in a particular direction. This means that the OBJECT IS UNBALANCED

Answer:

I agree with student 1

Explanation:

This is because, the magnitude of the gravitational force on both Earth and Moon depends on the product of their masses. Also, both Earth and Moon exert the same force but in opposite directions.

Student 2 is wrong because the gravitational force is the only force acting between the Earth and Moon, and from Newton's third law, it follows an action-reaction pair. But, student 2 got it wrong in the sense that the magnitude of the action and reaction forces are the same and are equal to the gravitational force.

So, the gravitational force acting on each object is the same and doesn't vary for each mass.  

We should agree with the student 1.

This is to be done due to the magnitude of the force since earth and moon should be based on the masses' product. Moreover, the earth and moon exert a similar force but that should be in inverse directions. Here student 2 should be wrong because the gravitational force is that force that acted between the earth and moon. Based on this, we can say that it should be acted on each object when it is the same also it should not be changed for every mass.

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Answer:

0.6 m/s 2

Explanation:

Answer:

a. the amount of work done on a system is dependent of pathway

Explanation:

The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system.

ΔU = Q - W

Where;

Q, the net heat transfer into the system depends on the pathway

W, the net work done by the system also depends on the pathway

But, ΔU, the change in internal energy is independent of pathway

Therefore, the correct option is "A"

a. the amount of work done on a system is dependent of pathway

Answer:

  about -1.26 m/s²

Explanation:

The acceleration can be found from the formula ...

  a = (v2² -v1²)/(2d)

Here, we have the initial velocity v1=23 m/s, the final velocity v2=0, and teh distance d=210 m. Using the formula, we find the acceleration to be ...

 a = (0 -23²)/2(210) ≈ -1.2595 . . . m/s²

Answer:

D. Return to the original position

Explanation:

I took the test

Answer:

Explanation:

The Newtons unit is kg. m/s2

Option A is the correct answer

Which object? More information is needed to answer this question

Answer:

they will drop at the same time

Explanation:

projectile motion consists of two components, horizontal and vertical, which are independent of one another. That means that if you drop a ball and kick another one straight out, they will both hit the ground at the same time so long as they have the same initial drop height .

Answer:

SUGGGA

Explanation:

Answer:

  19.  down

  20.  True

Explanation:

The examples I saw were projectiles launched at different angles and speeds. In each case, the only acceleration was ...

  19:  down

  20:  due to gravity (true)

Answer: D. 14 m/s west

Explanation:

I just did it on A p e x

Answer:

A. Digestive

Explanation:

Answer:

digestive system

Explanation:

since the digestive system secretes enzymes like amylase,lipase etc. required by the body for the proper breakdown of food.

Answer:

Fx = 32.14 [N]

Fy  = 38.3 [N]

Explanation:

To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.

F = 50 [N]

Fx = 50*cos(50) = 32.14 [N]

Fy = 50*sin(50) = 38.3 [N]

We can verify this result using the Pythagorean theorem.

[tex]F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N][/tex]

Explanation:

The magnetic field at the center of a current-carrying circular loop is given by :

[tex]B=\dfrac{\mu_o I}{2r}[/tex]

Where, I is current and r is radius of loop

We have, two current-carrying circular loops. Both are made from one strand of wire and both carry the same current, but one has twice the radius of the other.

For smaller loop, the magnetic field is B (with radius r)

For larger loop, let the magnetic field be B' (with radius r', r'=2r). So,

[tex]B'=\dfrac{\mu_o I}{2r'}\\\\B'=\dfrac{\mu_o I}{2(2r)}\\\\B'=\dfrac{1}{2}\times \dfrac{\mu_o I}{2r}\\\\B'=\dfrac{1}{2}B[/tex]

Hence, the magnetic field strength at the center of the larger loop is half of the magnetic field strength at the center of the smaller loop.

Answer:

Column 1 should be titled “Time,” and Column 2 should be titled “Velocity.”

Explanation: