Assume the height of the box is x.
5 reams of paper have 5 x 500 = 2500 sheets of paper.
This means that each sheet of paper has a thickness of x/2500.
Two sheets of paper have a thickness of 2 times x/2500.
Simplifying the fraction:
[tex]2\cdot\frac{x}{2500}=\frac{x}{1250}[/tex]Two sheets of paper have a thickness of 1/1250th of the height of the box.
Assume the height is x = 20 cm, then two sheets are 20/1250 = 0.016 cm thick.
Question 12 pls help
The equation of the line is found as y + 2 = (-2/3)(x - 5).
What is termed as the equation of a line?The equation of line is just an algebraic representation of a set of points in a coordinate system that form a line. The numerous points in the coordinate axis that form a line are depicted as a set of factors x, y to form an algebraic expression known as an equation of a line.For the given question.
The passing coordinates of the line is given as;
(x1, y1) = (-1, 7)
(x2, y2) = (5, -2)
Find the slope using the equation.
slope = m = (y2 - y1)/(x2 - x1)
Put the values.
m = (-2 - 7)/(5 + 1)
m = -9/6
m = -3/2
Use the point slope formula to find the equation of line in slope intercept form.
y - y1 = m(x - x1)
y + 2 = (-2/3)(x - 5)
Thus, the equation of the line is found as y + 2 = (-2/3)(x - 5).
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The width of a rectangle measures (8u - 2v) centimeters, and its length meas(5u +9v) centimeters. Which expression represents the perimeter, in centimof the rectangle?
The perimeter of a rectangle is given by two times the length plus two times the width, so we have:
[tex]\begin{gathered} P=2L+2W\\ \\ P=2(5u+9v)+2(8u-2v)\\ \\ P=10u+18v+16u-4v\\ \\ P=26u+14v \end{gathered}[/tex]Therefore the perimeter's expression is 26u + 14v
f(1)=-12 and f(n)=2f(n-1) then find the value of f(6).
Notice that from the definition of f(n):
[tex]f(6)=2f(5)=2(2f(4))=2(2(2f(3)))=2(2(2(2f(2))))=2(2(2(2(2f(1)))))\text{.}[/tex]Therefore:
[tex]f(6)=2^5f(1)=2^5(-12)=32(-12)=-384.[/tex]Answer:
[tex]f(6)=-384.[/tex]2/4 turn into decimal
Answer:
The decimal form of 2/4 is;
[tex]0.5[/tex]Explanation:
We want to turn the fraction to decimal.
[tex]\frac{2}{4}=0.5[/tex]it can be obtained by;
Therefore, the decimal form of 2/4 is;
[tex]0.5[/tex]Finding the Midpoint of a Line
Segment
To find the midpoint, M, of AB we can use
formula for finding point C. This works
because the M lies along AB and divides it in
a fixed ratio. So, if the midpoint of AB is point M, what must the ratio of a : b be? Since we know the ratio of a to b, we can substitute the values you wrote above back into the formula for finding a point along a line segment.
please solve quickly and give solution first then explain if possible
Solution
[tex]undefined[/tex]The final answer
[tex]x=10[/tex]. Estimate the area of a parallelogram with a base of 3 ¼ yards and a height of 5 ½ yards.
We are given the dimensions of a parallelogram and are asked to estimate its area
Recall that the area of a parallelogram of base b and height h is given by the formula
[tex]A=b\cdot h[/tex]So the area of the parallelogram would be
[tex]3\frac{1}{4}\cdot5\frac{1}{2}[/tex]as 3 1/4 and 5 1/2 are mixed numbers, we need to transform them to fractions
Recall that given a mixed number of the form
[tex]a\frac{b}{c}[/tex]we can transform it into a fraction by multiplying the whole number by the denominator and adding the result to the numerator while leaving the denominator fixed. In this case, that is
[tex]a\frac{b}{c}=\frac{a\cdot c+b}{c}[/tex]So, applying this formula to both numbers, we get
[tex]3\frac{1}{4}=\frac{3\cdot4+1}{4}=\frac{13}{4}[/tex]and
[tex]5\frac{1}{2}=\frac{5\cdot2+1}{2}=\frac{11}{2}[/tex]so the area of the parallelogram would be
[tex]\frac{13}{4}\cdot\frac{11}{2}=\frac{143}{8}\approx18[/tex]so the area of the parallelogram is approximately 18 square yards
You pick a card at random.
1 2 3 4
What is P(factor of 24)?
Write your answer as a percentage rounded to the nearest tenth
Answer:
100%
Step-by-step explanation:
All of the numbers are factors of 24. So, picking a factor of 24 is guaranteed, so the probability is 1.
This is equal to 100%.
Quadrilateral ABCD with vertices A(0,7) B(1,3), C(-1,-4), and D(-5,1): <7,-3>
We will have the following:
2)
A(0, 7) : <7, -3>
[tex]A^{\prime}(7,4)[/tex]B(1, 3) : <7, -3>
[tex]B^{\prime}(8,0)[/tex]C(-1, -4) : <7, -3>
[tex]C^{\prime}(6,-7)[/tex]D(-5, 1) : <7, -3>
[tex]D^{\prime}(2,-2)[/tex]3)
From the graph we will have the following:
a.
[tex](x,y)\to(x+7,y+5)[/tex]b.
[tex]\langle7,5\rangle[/tex]***Explanation***
For point 2, we will simply apply the vector to the corresponding coordinates, that is:
We have the coordinates:
[tex]A(a,b)[/tex]and the vector:
[tex]\langle c,d\rangle[/tex]So, in order to determine the final image we will have to follow the transformation rule:
[tex]A^{\prime}(a+c,b+d)[/tex]*For point 3, we will simply count the number of units the image has moved to the left or rigth and that will be our transformation rule for the x-axis, and the number of units the image has moved up or down and that will be our transformation rule for the y-axis.
In the case of the problem, the images moved 7 units to the rigth (+7) and then moved 5 units up (+5), so the transformation rule in coordinate notation is given by:
[tex](x,y)\to(x+7,y+5)[/tex]And in order to write it in vector notation, we simply write the units the images move:
[tex]\langle7,5\rangle[/tex]which of the following describe ✓2) Irrational number) Whole number ) Integer) Real number
Okay, here we have this:
Considering that a real number is said to be irrational if it cannot be expressed as a quotient of whole numbers. ✓2 is an irrational number, and as all the irrational number are real numbers ✓2 is also a real number.
please show me how to solve this triangle, thank you!
Statement Problem: Solve for the missing sides of the triangle;
Solution:
The sum of angles in a triangle is 180degrees. Thus,
[tex]\begin{gathered} \angle A+\angle B+\angle C=180^o \\ \angle B=180^o-\angle A-\angle C \\ \angle B=180^o-42^o-96^o \\ \angle B=42^o \end{gathered}[/tex]Since measure angle A and measure angle B are equal. Thus, the triangle is isosceles and the two sides are equal.
[tex]a=b[/tex]We would apply sine rule to find the missing side a.
[tex]\begin{gathered} \frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c} \\ \frac{\sin A}{a}=\frac{\sin C}{c} \end{gathered}[/tex][tex]\begin{gathered} \frac{\sin42^o}{a}=\frac{\sin96^o}{12} \\ a=\frac{12\sin42^o}{\sin96^o} \\ a=8.07 \\ a\approx8.1 \end{gathered}[/tex]Thus,
[tex]a=b=8.1[/tex]CORRECT ANSWERS:
[tex]\begin{gathered} a=8.1 \\ b=8.1 \\ m\angle B=42^o \end{gathered}[/tex]Louis and Jenny each wrote an equation to represent the graphed linear function. Louis’s answer is y=2x. Jenny’s answer is y=x+2. Which student is correct?
Concept
First, find the slope of the line, and secondly use a slope-intercept form of the equation to find the equation of the line.
Step 1: find the slope
From the graph, choose two coordinates at the intercept
( 0, 2 ) and ( -2, 0 )
x1 = 0
y1 = 2
x2 = -2
y2 = 0
Substitute the values in slope equation
[tex]\begin{gathered} \text{Slope m = }\frac{rise}{\text{run}}\text{ }=\text{ }\frac{y_2-y_1}{x_2-x_1} \\ \\ \text{Slope = }\frac{0-2}{-2-\text{ 0}} \\ \text{m = 1} \end{gathered}[/tex]Step 2: Find the intercept c
The intercept on the y-axis is c = 2
Step 3: Write the equation of a line in slope-intercept form
y = mx + c
Step 4: substitute the values of m and c to find the equation
y = 1(x) + 2
y = x + 2
Final answer
y = x + 2 Jenny's is correct
Evaluate the following definite integral using a geometric formula. You must show all work including the geometry area formula .
Given the Definite Integral:
[tex]\int_0^1\sqrt{1-x^2}dx[/tex]You can identify that the interval is:
[tex]\lbrack0,1\rbrack[/tex]By definition, if the function is continuous and positive in a closed interval, then:
[tex]\int_a^bf(x)dx=Area[/tex]In this case, you can identify that the function is:
[tex]y=\sqrt{1-x^2}[/tex]You can graph it using a graphic tool:
Since the closed interval goes from 0 to 1, you need to find this area:
You can identify that you have to find the area of a quarter circle. In order to do it, you can use this formula:
[tex]A=\frac{\pi r^2}{4}[/tex]Where "r" is the radius of the circle.
In this case, you can identify that:
[tex]r=1[/tex]Therefore, you get:
[tex]A=\frac{\pi(1)^2}{4}=\frac{\pi}{4}[/tex]Then:
[tex]\int_0^1\sqrt{1-x^2}dx=\frac{\pi}{4}[/tex]Hence, the answer is: Option D.
help me please if you can A.(0, 3)B. (-1, 5)C.(1, 1.5)
Answer:
A. (0, 3)
C. (1, 1.5)
Explanation:
A point is a solution to the system if it satisfies both inequalities.
So for each option, we get:
Replacing (x, y) = (0, 3)
y ≥ -2x + 3
3 ≥ -2(0) + 3
3 ≥ 3
y ≤ -x² - x + 4
3 ≤ -0² - 0 + 4
3 ≤ 4
Since both inequalities are satisfied, (0, 3) is a solution.
For (x, y) = (-1, 5)
y ≥ -2x + 3
5 ≥ -2(-1) + 3
5 ≥ 2 + 3
5 ≥ 5
y ≤ -x² - x + 4
5 ≤ -(-1)² - (-1) + 4
5 ≤ -1 + 1 + 4
5 ≤ 4
Since 5 is not lower than 4, (-1, 5) is not a solution
For (x, y) = (1, 1.5)
y ≥ -2x + 3
1.5 ≥ -2(1) + 3
1.5 ≥ -2 + 3
1.5 ≥ 1
y ≤ -x² - x + 4
1.5 ≤ -(1)² - (1) + 4
1.5 ≤ -1 - 1 + 4
1.5 ≤ 2
Since both inequalities are satisfied, (1, 1.5) is a solution.
Therefore, the answers are
A. (0, 3)
C. (1, 1.5)
Write an inequality:Carlos was going to sell all of his stamp collection to buy a video game. After selling half of them he changed his mind. He then bought twelve more. How many did he start with if he now has at least 29?
Answer:
He started with at least 34 stamp collection
Explanation:
Let x represent Carlos' initial stamp collection.
From the question, we're told that he sold half of them, bought twelve more, and currently has at least 29, we can go ahead and set up an inequality as shown below;
[tex]\frac{x}{2}+12\ge29[/tex]We can go ahead and solve for x following the below steps;
Step 1: Subtract 12 from both sides of the equation;
[tex]\begin{gathered} \frac{x}{2}+12-12\ge29-12 \\ \frac{x}{2}\ge17 \end{gathered}[/tex]Step 2: Multiply both sides by 2;
[tex]\begin{gathered} \frac{x}{2}\times2\ge17\times2 \\ x\ge34 \end{gathered}[/tex]From the above, we can say that Carlos started with at least 34 stamp collection
anumeha mows lawns she charges an initial fee and constant fee for each hour of work
Given the function:
[tex]F(t)=6+12t[/tex]Where F represents Anumeha's fees (in dollars) for working t hours. The initial fee can be calculated for t = 0:
[tex]F(0)=6+12\cdot0=6[/tex]So the constant fee is $6. Now, we need to calculate how much does she charges each hour. We can calculate the values at t = 1, t = 2, and t = 3:
[tex]\begin{gathered} F(1)=6+12\cdot1=18 \\ F(2)=6+12\cdot2=30 \\ F(3)=6+12\cdot3=42 \end{gathered}[/tex]As we can see, there is a constant increment of $12 for each hour. Then, Anumeha charges $12 for each hour of work.
Elena has two aquariums each shaped like a rectangular prism. For each question explain or show your reasoning. A) One aquarium has a length of 7/2 feet a width of 4/3 feet and a height of 3/2 feet. What is the volume of the aquarium.
The current population of a threatened animal species is 1.3 million, but it is declining with a half-life of 25 years. How many animals will be left in 35 years? in 80 years?Question content area bottom(Round to the nearest whole number as needed.)
Given:
it is given that the current population of a threatened animal species is 1.3 million, but it is declining with a half-life of 25 years.
Find:
we have to find that how many animals will be left in 35 years and in 80 years.
Explanation:
we know 1.3million = 1300000
The decay law is
[tex]P(t)=1300000\times(\frac{1}{2})^{\frac{t}{25}}[/tex]
where t is in years and p(t) is the population at time t.
Now, the number of animals left in 35 years is
[tex]\begin{gathered} P(35)=1300000\times(\frac{1}{2})^{\frac{35}{25}} \\ P(35)=1300000\times(\frac{1}{2})^{1.4} \\ P(35)=492608(by\text{ rounded to nearest whole number\rparen} \end{gathered}[/tex]Therefore, 492608 animals will be left in 30 years.
Now, the number of elements left in 80 years is
[tex]\begin{gathered} P(80)=1300000\times(\frac{1}{2})^{\frac{80}{25}} \\ P(80)=1300000\times(\frac{1}{2})^{3.2} \\ P(80)=141464(by\text{ rounded to nearest whole number\rparen} \end{gathered}[/tex]According to a 2017 Wired magazine article, 40% of emails that are received are tracked using software that can tell the email sender when, where, and on what type of device the email was opened (Wired magazine website). Suppose we randomly select 70 received emails.
(a)
What is the expected number of these emails that are tracked?
(b)
What are the variance and standard deviation for the number of these emails that are tracked? (Round your answers to three decimal places.)
Var(x)
=
=
Using the binomial distribution, the measures are given as follows:
a) Expected value: 28.
b) Variance of 16.8 and standard deviation of 4.099.
What is the binomial distribution formula?The formula for the probability of x successes is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are given by:
n is the number of trials of the experiment.p is the probability of a success on a single trial of the experiment.Hence, in the context of this problem, the values of these parameters are given as follows:
p = 0.4, n = 70.
The expected value of the distribution is calculated as follows:
E(X) = np.
Hence:
E(X) = 70 x 0.4 = 28.
The variance of the distribution is calculated as follows:
V(X) = np(1 - p) = 70 x 0.4 x 0.6 = 16.8.
The standard deviation of the distribution is calculated as follows:
sqrt(V(X)) = sqrt(16.8) = 4.099.
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Can a triangle be formed with side lengths 13, 7, and 5? Explain.
Answer: The answer is no
Step-by-step explanation:
this is because the two short side lengths, which is 5 and 7, they have to be added together, which is 12, and 12 is smaller than 13 (the largest side)
Answer:
No, because 5 + 7 < 13
Step-by-step explanation:
Describe the difference on table, graph and equation between discrete and continuous functions.
REmember that
A continuous function allows the x-values to be ANY points in the interval, including fractions, decimals, and irrational values
A discrete function allows the x-values to be only certain points in the interval, usually only integers or whole numbers.
Discrete functions have scatter plots as graphs and continuous functions have lines or curves as graphs
The two angles shown are supplementary.162°Which equation can be solved to find the value of x, and what is the value of x?A.162° + Xo = 90°; x = 72B.162° + x° = 180°; x = 18C.162° + x = 360°; x= 198D.162° + x = 180°; x = 242
Supplementary angles are two angles whose sum is exactly 180, therefore:
162 + x = 180
Solving for x:
subtract 162 from both sides:
x = 180 - 162
x = 18
A storm is moving at 30km/hr .it is 60 km away. What time will it arrive
From the information provided, the storm is travelling at a speed of 30km/hr. In other words, its travelling 30 kilometers every hour. If the storm is 60 kilometers away, then we have the following ratio;
[tex]undefined[/tex]Home Liquidators marks up its merchandise 35% on cost. What is the company’s equivalent markup on selling price?
Based on the fact that Home Liquidators marked up their merchandise by 35% on cost, the company equivalent markup on selling price is 26%.
How to find the equivalent markup?The equivalent markup by Home Liquidators on the selling price can be found by the formula:
= Percentage markup / Percentage selling price x 100%
The percentage markup = 35%
Percentage selling price = (100% + 35%) = 135%
The equivalent markup by Home Liquidators is therefore:
= 35% / 135% x 100%
= 26%
In conclusion, the Home Liquidators has an equivalent markup of 26% on selling price.
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What value of Y makes this equation true?6y/-2 = 8 (-4/2)
Step 1
Given;
[tex]\frac{6y}{-2}=8(-\frac{4}{2})[/tex]Required; To find the value of y that makes the equation true
Step 2
Find the value of y
[tex]\begin{gathered} \text{Simplify} \\ -3y=4(-4) \end{gathered}[/tex][tex]\begin{gathered} \text{expand} \\ -3y=-16 \end{gathered}[/tex][tex]\begin{gathered} \text{Divide both sides by -3} \\ \frac{-3y}{-3}=\frac{-16}{-3} \end{gathered}[/tex][tex]\begin{gathered} \text{Simplify} \\ y=\frac{16}{3} \end{gathered}[/tex]Hence, the value of y that makes the equation true is 16/3
Solve x4 + 8x2 + 15 = 0.X = +15 and x = 113x = 5 and x = 13x = 113 and x = 15X = 3/1/3 and x = 1115
Answer
Option D is correct.
x = ±i√(5) OR ±i√(3)
Explanation
The question wants us to solve
x⁴ + 8x² + 15 = 0
To solve this, we first say that
Let x² = y
So that,
x⁴ = (x²)² = y²
So, the equation becomes
y² + 8y + 15 = 0
This is a simple quadratic equation, we then solve this
y² + 8y + 15 = 0
y² + 3y + 5y + 15 = 0
y (y + 3) + 5 (y + 3) = 0
(y + 5) (y + 3) = 0
y + 5 = 0 OR y + 3 = 0
y = -5 OR y = -3
But, Recall that x² = y
If y = -5
x² = y = -5
x² = -5
x = √(-5)
If y = -3
x² = y = -3
x² = -3
x = √(-3)
So,
x = √(-5) OR x = √(-3)
Note that
√(-1) = i
√(-5) = √(-1) × √(5)
= i√5
And
√(-3) = √(-1) × √(3)
= i√3
Hence
x = ±i√(5) OR ±i√(3)
Hope this Helps!!!
a survey of 240 households.91 had a dog. 70 had a cat. 31 had a cat and dog. 91 had neither a cat or a dog and did not have a parakeet. 7 had a cat, a dog and a parakeet. how many had a parakeet only?
A total of 240 households participated in the survey.
91 of then had neither a cat, a dor or a parakeet.
Then, 159 of them had at least one animal.
7 of then had a cat, a dog and a parakeet.
Then, 152 of them had one or two animals between a cat, a dog and a parakeet.
31 of them had a cat and a dog.
Then, 121 of then had a dog only, a cat only, a dog and a parakeet, a cat and a parakeet or a parakeet only. Between these, we want to find the ones who had a parakeet only. Only 91 - 31 = 60 of these 121 households must had at least a dog and only 70 - 31 = 39 of these had at least a cat.
Therefore, the number of households that had a parakeet only is 121 - 60 - 39 = 22
6+|2x-11|=-37
Solve for x
Answer:
X=16 and X=21
Step-by-step explanation:
6 + 2x-11 = -37
-6 -6 2x-11 =-43
+11 +11 2x =32
x=16
6+ 2x- 11 = 37
2x-11=31
+11 +11 2x=42
x =21
Select the correct location on the image. Click the digit in the hundred millions place. 7,7 7 8,7 6 8,2 4.9 Reset Next
In this case you need to click the 7 which is in the hundred millions place
Let S be the universal set, where: S = { 1 , 2 , 3 , ... , 18 , 19 , 20 } Let sets A and B be subsets of S , where: Set A = { 2 , 5 , 9 , 11 , 12 , 14 , 15 , 17 , 18 } Set B = { 4 , 7 , 8 , 9 , 10 , 12 , 15 , 17 , 18 , 19 , 20 } Find the following: LIST the elements in the set ( A ∪ B ): ( A ∪ B ) = { } Enter the elements as a list, separated by commas. If the result is the empty set, enter DNE LIST the elements in the set ( A ∩ B ): ( A ∩ B ) = { } Enter the elements as a list, separated by commas. If the result is the empty set, enter DNE
The elements that are in ( A ∪ B ) = { 2, 4, 5, 7, 8, 9, 10 , 11, 12, 14, 15, 17, 18, 19, 20}
The elements of the set that are in ( A ∩ B ) = {9, 12, 15, 17, 18 }
What is a the union of a set?This is the term that is used to refer to all of the elements that are contained in a two or more sets which are a subset of the Universal set.
In this case, the union of the set is given as the elements in both A and B written together as { 2, 4, 5, 7, 8, 9, 10 , 11, 12, 14, 15, 17, 18, 19, 20}. All of these values are in A and B.
What is the intersection of a set?This is the term that is used to refer to all of the values that would appear in the two sets that are in the subset of the universal set.
Here we have the value of A ∩ B = {9, 12, 15, 17, 18 }
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