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Healthy human lungs look pink and spongy from the outside. The left lung is a little smaller than the right lung to make room for the heart. The lungs and heart are both protected by the rib cage. In the lungs, each main bronchus branches off into many smaller bronchi. The bronchi become smaller and smaller, and the smallest bronchi are called bronchioles. There are about 30,000 bronchioles in each lung, each about the same thickness as a strand of hair. The inhaled air eventually ends up in tiny air sacs called alveoli at the end of each bronchiole. There are about 300 million alveoli in each lung. They are covered with capillaries, tiny blood vessels that are only one cell thick. Oxygen travels from the alveoli through the capillaries to the bloodstream, heart and other cells


Which of these best represents the progression of bronchi, bronchioles and alveoli in the lungs?

A tree trunks that become smaller branches and twigs

B a tight flower bud that has opened into a full bloom

C whole apples that are sliced into separate wedges

D a bridge that crosses two rivers

Answer:

12 ohms

Explanation:

you just divide 240 and 20

240 V/ 20 A = 12 ohms

Answer:

gas

Explanation:

gasoline will never freeze up

Answer:

Alcohol

Explanation: I'm not sure

Answer: 0.04139m

Explanation:

First, we need to calculate the weight of the man which will be:

Weight = mass × acceleration due to gravity

Weight = mg

Weight = 92.5 × 9.8

Weight = 906.5N

Then, we calculate the force which will be:

F = kx

mg = kx

x = mg/k

x = 906.5/21900

x = 0.04139m.

The spring stretched for 0.04139m.

Answer:

1. Static Friction

2. Sliding friction

3. Fluid friction

4. is rolling friction

Sorry if i am wrong

Explanation:

Answer:A and C

Explanation: I took the test lol

Two statement that are correct based on graph are A, At point 4, the concentration of NH₄, NH₂ and H₂ remain constant, and C, Equilibrium is reached after point 3.

Graphs are the mathematical representation of the data that is easy to understand.

The reaction is [tex]\rm 3H_2 + N_2= 2NH_3[/tex]

The graph shows time on x-axis and concentration on y-axis.

Thus, the correct options are A and C.

Learn more about graphs

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Answer:

Systemic racism

Explanation:

Answer:

Final velocity of ball = 20 m/s

Explanation:

Given:

Height when ball released = 20meter

Find;

Time taken to fall

Final velocity of ball

Computation:

Initial velocity of ball = 0 m/s

Acceleration due to gravity = 10 m/s²

Using equation of motion;

S = ut + (1/2)(g)(t²)

20 = (0)(t) + (1/2)(10)(t²)

20 = 5(t²)

(t²) = 20 / 5

(t²) = 4

Time taken to fall = 2 second

V = u + at

V = 0 + (10)(2)

Final velocity of ball = 20 m/s

Answer: The potential energy associated with a mass attached to a spring depends on how much the spring is stretched or compressed. ... The gravitational force on the mass is −mg (“−” because the force points down). The force is the negative of the slope on the potential energy versus position graph.

Explanation:

:)

By getting the data from the graph of force versus displacement we can calculate the Potential energy of the spring.

As we know that potential energy is defined as the energy possessed by the body due to its position with respect to other positions.

For an example the potential energy of an object if it is placed at height h will be due to the gravitational acceleration of the earth and is given by  [tex]PE=mgh[/tex]

Similarly, for a spring-mass system, the potential energy will be due to the weight of the mass that will be the force exerted by the mass on the spring so there will be an extension in the spring.

So this extension will be found out by the force and displacement  graph as the position of the mass attached to the spring goes down so the potential energy can be calculated as the

[tex]PE= F\times X[/tex]

[tex]F=mg[/tex]  weight of the mass

X= deflection of the spring

Thus by getting the data from the graph of force versus displacement we can calculate the Potential energy of the spring.

To know more about potential energy follow

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Answer:

First, we can define the North as the positive y-axis, and the East as the positive x-axis.

Here we have two forces:

F₁ = 14N to north

F₂ = 9.2 N to west.

Then the free body diagram will be the one that can be seen below:

Now we want to find the acceleration that the ball experiences if the mass is 225g

Knowing that 1k = 1000g, we can rewrite the mass as:

M = 0.225g

Here we also need to remember the second Newton's law:

F = M*a

Net force equals mass times acceleration.

First, let's find the net force:

F = F₁ + F₂ = 14N*(0, 1) + 9.2N*(-1, 0 )

F = (-9.2N, 14N)

The module of the force is then:

I F I = √( (-9.2N)^2 + (14N)^2) = 16.75 N

Then the acceleration is given by

16.75 N = 0.225kg*a

(16.75 N)/(0.225 kg) = a = 74 m/s^2

Answer:10

Explanation:acellus

Answer:

as we move away from the sun the velocity of the planet decreases

Answer:

175

Explanation:

its for Acellus

The potential difference is V=1.743*10^-7

The voltage is generally referred to as the electric potential difference and  it can be measured using a voltmeter. The electrical potential difference between the two plates is expressed as q=CV.

CALCULATION

we know,

q=CV

q={EA/d}*V

here q= 5.24*10^-8C

       A=8.22*10^-5m^2

       d=2.42*10^-8m

therefore , C={( 8.85*10^-12)*(8.22*10^-5)}/(2.42*10^-8)

                 C=3.006*10^-1

q=CV

q/C=V

V=1.743*10^-7

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Answer:

Es la energía cinética interna total de un objeto debido al movimiento aleatorio de sus ... a es la energía que posee un objeto o cuerpo en virtud del movimiento de sus ... Si el movimiento de estas moléculas y átomos es más rápido, se dice que el ... Por lo tanto, la energía térmica asociada con la conducción resulta de la .

Explanation:

Answer:

[tex]E=8.13\times 10^{12}\ J[/tex]

Explanation:

Given that,

The mass of a Hubble Space Telescope, [tex]m_1=1.16\times 10^4\ kg[/tex]

It orbits the Earth at an altitude of [tex]5.68\times 10^5\ m[/tex]

We need to find the potential energy the telescope at this location. The formula for potential energy is given by :

[tex]E=\dfrac{Gm_1m_e}{r}[/tex]

Where

[tex]m_e[/tex] is the mass of Earth

Put all the values,

[tex]E=\dfrac{6.67\times 10^{-11}\times 1.16\times 10^4\times 5.97\times 10^{24}}{5.68\times 10^5}\\\\E=8.13\times 10^{12}\ J[/tex]

So, the potential energy of the telescope is [tex]8.13\times 10^{12}\ J[/tex].

Answer:

pool

Explanation:

I think

Answer:

b

Explanation:

sorry if im wrong