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The Hamptons Family has a fish tank holding 10,450 ml of water. The water is leaking at a rate of 270 ml per minute.

Part A: Define the input and output in the given scenario.


Part B: Write a function to model this situation.


Part C: How many liters of water will be left in the tank after 10 minutes
(hint: liters, not milliliters)

Answer:

The output would depend on the input so relating this to the question, the input is the time (in minute) and the output is the amount of water left in the tank

We can give a letter 't' for the time, the input, and f(t) for the output

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The original amount of water in the tank is 10450, so this will be the fixed constant.

The amount of water lost per minute is 270 so this will be the term that varies depends on the variable of time, we write this as 270t

The function is given f(t) = 10450 - 270t

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Given, t = 10

f(10) = 10450 - 270(10)

f(10) = 7750 ml

Step-by-step explanation:

Answer:

 Part A:

Since the rate of 270 ml per minute has units of ml per minute, then yy must have units of ml and x must have units of minutes. The input must then be the number of minutes the tank is leaking for and the output is the number of ml of water remaining in the tank.

Part B:

Since the tank is leaking 270 ml per minute, then after x minutes, 270x ml of water has leaked out of the tank. The tank initially has 10,450 ml of water so after x minutes, there is y=10,450−270x ml remaining in the tank.

Part C:

After x=10 minutes, the amount of water remaining in the tank is y=10,450−270(10)=10,450−2,700=7,750 ml. There are 1,000 ml in 1 liter so 7,750 ml = 7.75 liters. There are then 7.75 liters of water left in the tank after 10 minutes.

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