Answers
Answer:C
Step-by-step explanation:
Extinct species tend to be fully gone or not seen in the wild for quite some time endangered would be a better answer for A
Hope this helps
Related Questions
a cylinder has a diameter of 12 and height of 12. the volume of the cylinder is:
A. 1728π cubic units
B. 288π cubic units
C. 144π cubic units
D. 432π cubic units
Answers
Find the perimeter of a rectangle with a base of 12 ft and a height of 5 ft.
Answers
Answer:
P=34ft
Step-by-step explanation:
Solution
P=2(l+w)=2·(12+5)=34ft
Please help soon- The weight of oranges growing in an orchard is normally distributed with a mean
weight of 6 oz. and a standard deviation of 1 oz. From a batch of 2500 oranges, how
many would be expected to weight less than 4 oz., to the nearest whole number?
Answers
Simran has a bag containing white and yellow marbles. Simran randomly selects one marble from the bag,
records the result, and returns the marble to the bag. The results of the first 65 selections are shown below.
A white marble was selected 41 times.
A yellow marble was selected 24 times.
Based on these results, what is the probability that the next marble Simran selects, rounded to the nearest
Answers
Answer:
d. 63%
Step-by-step explanation:
percent, will be white?
A41% b50% c59% d63%
The probability of white = P (w) = 41/65= 0.63
The probability of yellow = P (y)= 24/65= 0.369=0.37
The probability of choosing white is 0.63 . When rounded to nearest percent gives
0.63*100/100
=0.63*100 percent
= 63 percent
= 63%
the probability of getting the next marble white is the same as the probability of getting a white.
If Bill hiked 6.5 miles at a rate of 10.4 mph, how long did it take him to complete his hike?
Answers
Answer:
I think it depends how far bill wants to hike..
Step-by-step explanation:
OR
37 minutes and 30 seconds
Hi, i need to calculate roots x1 and x2 using the vieta theorem, can anyone help me? I have found the answer for x1 and x2, its 1,5 and 2, all i need is a solution on how to get this answer, the equation is in the picture, will give you brainliest if you type down the correct solution for me, thanks.
I have left a similar equation that i did. The only thing why i cant do the equation, because in front of x2 there’s an number, so i don’t understand.
Answers
Answer:
Solution given:
x²-12x+11=0
Comparing above equation with ax²+bx+c
we get
a=1
b=-12
c=11
By using Vieta's theorem
X1+X2=[tex] \frac{-b}{a} [/tex]=[tex] \frac{- -12}{1} [/tex]=12
again
X1X2=[tex] \frac{c}{a} [/tex]=[tex] \frac{11}{1} [/tex]=11
x1.x2=11
x1+x2=12
Consider the initial value problem my''+cy'+ky=F(t), y(0)=0, y'(0)=0, modeling the motion of a spring mass dashpot system initially at rest and subjected to an applied force F(t), where the unit of force is the Newton (N). Assume that m=2 kilograms, c=8 kilograms per second, k=80 Newtons per meter, and F(t)=20 sin(6t) Newtons.
1. Solve the initial value problem. y(t)=?
2. Determine the long term behavior of the system. Is lim as t goes to infinity of y(t)=0? If it is, enter zero. If not, enter a function that approximates y(t) for very large positive values of t. For very large positive values of t, y(t) is approximately.. ?
Answers
Answer:
Hence, the [tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex] and approximately value of [tex]y(t)[/tex] is [tex]-0.844[/tex].
Given :
[tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]
Where [tex]m=2[/tex] kilograms
[tex]c=8[/tex] kilograms per second
[tex]k=80[/tex] Newtons per meter
[tex]F(t)=20\sin (6t)[/tex] Newtons
Explanation :
(1)
Solve the initial value problem. [tex]y(t)[/tex]
[tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]
[tex]\Rightarrow 2y''+8y'+80y=20\sin (6t)[/tex]
[tex]\Rightarrow y''+4y'+40y=10\sin (6t)[/tex]
Auxilary equations :[tex]F(t)=0[/tex]
[tex]\Rightarrow r^2+4r+40=0[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{4^2-4\times 1\times 40}}{2\times 1}[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{16-160}}{2}[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{-144}}{2}[/tex]
[tex]\Rightarrow r=\frac{-4\pm12i}{2}[/tex]
[tex]\Rightarrow r=-2\pm6i[/tex]
The complementary solution is [tex]y_c=e^{-2t}\left(c_1\cos 6t+c_2\sin 6t\right)[/tex]
The particular Integral, [tex]y_p=\frac{1}{f(D)}F(t)[/tex]
[tex]y_{y} &=\frac{1}{D^{2}+4 D+40} 25 \sin (6 t) \\\\ y_{y} &=\frac{25}{-6^{2}+4 D+40} \sin (6 t) \quad\left(D^{2} \text { is replaced with }-6^{2}=-36\right) \\\\y_{y} &=\frac{25}{4 D+4} \sin (6 t) \\\\y_{y} &=\frac{25}{4(D+1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(D+1)(D-1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4\left(D^{2}-1\right)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(-36-1)} \sin (6 t) \\\\y_{y} &=-\frac{25}{148}(D-1) \sin (6 t) \\y_{y} &=-\frac{25}{148}\left(\frac{d}{d t} \sin (6 t)-\sin (6[/tex]
Hence the general solution is :[tex]y=y_c+y_p=e^{-2t}(c_1\cos 6t+c_2\sin 6t)-\frac{25}{148}(6\cos 6t-\sin 6t)[/tex]
Now we use given initial condition.
[tex]y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\\y(0) &=e^{-\alpha 0)}\left(c_{1} \cos (0)+c_{2} \sin (0)\right)-\frac{25}{148}(6 \cos (0)-\sin (0)) \\\\0 &=\left(c_{1}\right)-\frac{25}{148}(6) \\\\c_{1} &=\frac{75}{74} \\\\y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\[/tex]
[tex]y^{\prime}(t)=-2 e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)+e^{-2 t}\left(-6 c_{1} \sin 6 t+6 c_{2} \cos 6 t\right)-\frac{25}{148}(-36 \sin (6 t)-6 \cos (6 t)) \\\\y^{\prime}(0)=-2 e^{0}\left(c_{1} \cos 0+c_{2} \sin 0\right)+e^{0}\left(-6 c_{1} \sin 0+6 c_{2} \cos 0\right)-\frac{25}{148}(-36 \sin 0-6 \cos 0) \\\\0=-2\left(c_{1}\right)+\left(6 c_{2}\right)-\frac{25}{148}(-6) \\\\0=-2 c_{1}+6 c_{2}+\frac{75}{74} \\\\0=-2\left(\frac{75}{74}\right)+6 c_{2}+\frac{75}{74} \\\\[/tex][tex]\begin{array}{l}0=-\frac{150}{74}+6 c_{2}+\frac{75}{74} \\\\\frac{150}{74}-\frac{75}{74}=6 c_{2}\end{array}[/tex]
[tex]\begin{array}{l}c_{2}=\frac{25}{148}\\\\\text { Substitute } c_{1} \text { and } c_{2} \text { in } y(t) \text { . Then }\\\\y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex]
(2)
[tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\left(\frac{75}{74} e^{-2 t} \cos 6 t+\frac{75}{148} e^{-2 t} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\frac{75}{74}\left(e^{-2 t}-1\right) \cos 6 t+\frac{25}{148}\left(3 e^{-2 t}+1\right) \sin 6 t \\\\|y(t)| \leq \frac{75}{74} e^{-2 t}-1|\cos 6 t|+\frac{25}{148}\left|3 e^{-2 t}+1\right||\sin 6 t| \\\\[/tex]
[tex]|y(t)| \leq \frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right| \\\\\lim _{t \rightarrow \infty} y(t) \leq \lim _{t \rightarrow \infty}\left\{\frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right|\right\} \\\\\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}\left|\lim _{t \rightarrow \infty}\left(e^{-2 t}-1\right)\right|+\frac{25}{148}\left|\lim _{t \rightarrow \infty}\left(3 e^{-2 t}+1\right)\right|\right\} \\[/tex]
[tex]\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}(-1)+\frac{25}{148}(1)\right\}=-\frac{75}{74}+\frac{25}{148}=-\frac{-150+25}{148}=-\frac{125}{148} \approx-0.844[/tex]
Identify a second of transformations that maps triangle ABC onto triangle A"B"C in the image below.
Answers
Answer: The answer is B because the triangle rotated a 90 degrees counterclockwise then got a reduction.
Step-by-step explanation:
1+1 why does my dog not love me?
Answers
Answer:
2
Step-by-step explanation:
your dog doesn't love you because it saw what you did. it knows. be cautious around your dog from now on. it knows more than you think and sees all. I'm warning you
can someone help me :(
Answers
Answer:
A is the correct answer
.......................
Answer:
A. y+116+30=180
Step-by-step explanation:
A straight angle is 180°.
all the given angles make up a straight angle, so they add to 180°.
PLSSSSSSSSSSS ASAP!!!!! Find the area of the figure shown below.
Answers
Answer:
54 square ft
Step-by-step explanation:
Find missing sides:
8+6 = 14
9-6 = 3
Find area of full rectangle:
9×8 = 72
Find the area of the missing part of the full rectangle
3×6 = 18
Find the area of the actual shape:
72-18 = 54
Area = 54 square ft
Find the exact value of sin A in simplest radical form.
Answers
Using the sine rule,
[tex] \frac{a}{sin(a)} = \frac{b}{sin(b)} = \frac{c}{sin(c)} [/tex]
Here we are going to use the values of A and C,
[tex] \frac{12}{sin(a)} = \frac{14}{sin(90)} \\ \frac{12}{sin(a)} = \frac{14}{1} \\ sin(a) = 12 \div 14 \\ sin(a) = 0.8571[/tex]
So sin(A) = 12/14 = 6/7 = 0.8571, but since the question says in its simplest radical form, I think the closest answer to it should be
[tex] \frac{ \sqrt{3} }{2} [/tex]
which best describes a rectangle with diagonals that are perpendicular
Answers
Answer: If a parallelogram has diagonals that are perpendicular, it is a rhombus. … This definition can also be stated as: A square is a quadrilateral that is also a rectangle and a rhombus.
Step-by-step explanation:
Calculate the volume of this can of baked beans:
Choices:
120.95cm3
38.5cm3
77cm3
423.32cm3
Answers
Answer:
423.32cm³
Step-by-step explanation:
Volume of a cylinder = [tex]V=\pi r^2h[/tex]
where r = radius and h = height
Given height = 11 cm
Given radius = 3.5 cm
* plug in these values into the formula *
[tex]V=\pi 3.5^211\\3.5^2=12.25 \\12.25\pi =38.48\\34.48*11=423.32\\V=423.32[/tex]
So we can conclude that the answer would be D
The times that a cashier spends processing individual customers' orders are independent random variables with mean 3.5 minutes and standard deviation 3 minutes. Find the number of customers n such that the probability that the orders of all n customers can be processed in less than 2 hours, is approximately 0.1. (Round your answer to the nearest integer.)
Answers
Answer:
26 customers
Step-by-step explanation:
First: determine the z score from standard normal probability table with an indicative area of 0.1
Z-score from probability table = - 1.28
mean = 3.5 minutes
std = 3 minutes
next determine the Z-score based on the information given in the question
Z = ( std - mean ) / processing time
= ( 3 - 3.5 ) / 2 = -0.25
Finally determine the number of customers
N = [tex](\frac{-1.28}{-0.25} )^2[/tex] = 1.6384 / 0.0625 = 26.21 ≈ 26 customers
Which statement describes whether the function is continuous at x = 2?
O The function is continuous at x = 2 because f(2) exists.
O The function is continuous at x = 2 because lim f(x) exists.
X-2
The function is not continuous at x = 2 because f(2) does not exist.
The function is not continuous at x = 2 because lim f(x) does not equal f(2).
X-2
Answers
Answer: (b)
Step-by-step explanation:
Given
The function is given as
[tex]f(x)=\dfrac{x^2-12x+20}{x-2}[/tex]
Solving the function
[tex]f(x)=\dfrac{x^2-2x-10x+20}{x-2}\\\\f(x)=\dfrac{(x-2)(x-10)}{(x-2)}\\\\f(x)=x-10[/tex]
for [tex]x=2[/tex]
[tex]f(2)=2-10\\f(2)=-8[/tex]
The function is continuous at [tex]x=2[/tex] because [tex]\lim_{x \to 2} f(x)[/tex] exists.
If the limit exists at a point, then the function is continuous.
Answer:
on edge its fs not b or c
Step-by-step explanation:
Find the length of arc AB.
Answers
Answer:
11.17
Step-by-step explanation:
arc length = 2πr(θ/360)
= 2π(8)(80/360)
= 11.1701072...
= 11.17 to nearest hundredth
What is the volume of a sphere with a radius of 3.1 cm, rounded to the nearest tenth
of a cubic centimeter?
Answers
Rounded to the nearest tenth It’s 124.8
PLEASE HELP FAST WILL MARK BRAINLIEST PLEASEEE
Answers
Answer:
[tex]\frac{8x^{18} }{y^{2} }[/tex]
Step-by-step explanation:
Which of the following names the figure in the diagram below?
A. pentagon
B. prism
C. triangle
D. polygon
E.pyramid
F. square
Answers
Answer: Prism
Step-by-step explanation:
21. A Figure is shown below.
What is the area of the figure, in square inches?
Answers
Answer:
[tex]36+27\pi\:\mathrm{in^2}[/tex]
Step-by-step explanation:
The figure consists of a square and a sector. We can add the areas of the square and sector to get the total area of the figure.
The area of a sector with measure [tex]\theta[/tex] in a circle of radius [tex]r[/tex] is equal to [tex]\frac{\theta}{360}\cdot r^2\pi[/tex]. Since there are 360 degrees in a circle and 90 degrees in each corner of a square, the measure of the sector is [tex]270^{\circ}[/tex].
Thus, its area is:
[tex]\frac{270}{360}\cdot6^2\cdot pi=\frac{3}{4}\cdot 6^2\cdot \pi=27\pi[/tex].
The area of a square with side length [tex]s[/tex] is given by [tex]s^2[/tex]. Therefore, the area of the circle is [tex]6^2=36[/tex] and the total area of the figure is [tex]\boxed{36+27\pi\:\mathrm{in^2}}[/tex]
Answer: 36+27in2
Step-by-step explanation:
b)
Simplify 5x2 - x2
Answers
Answer: the answer is 4x^2
Step-by-step explanation:
hope it help
Find the quotient: 28 ÷ 4 2/3
Answers
Answer:
6
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
Is the line a good fit for the data points plotted in the scatter plot below?
Answers
pls help me loves :((
Answers
Answer:
609 m²
Step-by-step explanation:
Area of unshaded:
(6 x 18) + ((13-6) x 7) = 157
Area of overall rectangle:
36 x 28 = 1008
Area of the chunck of rectangle not included:
11 x 22 = 242
Area of shaded:
1008 - 157 - 242 = 609
Type the integer in the box.
Solve:: t/2 + 10 =-40
Answers
Answer:
t = -100
Step-by-step explanation:
Simplify to isolate t:
[tex]\frac{t}{2}+10-10=-40-10[/tex]
[tex]\frac{t}{2} * \frac{2}{1} = -50 * 2[/tex]
[tex]t = -100[/tex]
Pls help math lol. Yeah
Answers
Answer:
X = 65 degrees
Step-by-step explanation:
180 = 70 + 45 + X
180 = 115 + X
X = 65 degrees
What is the expanded form of 8,609?
A 8,000+600+ 90
8,000+60+9
8,000 +900+ 6
8,000+600 +9
Answers
The last one 8,000 + 600 + 9
Caroline has a rock stuck in her Jeep’s tire
Answers
Answer:
oh no
Step-by-step explanation:
sorry about that I guess
I need this please help me
Answers
Answer:
A. Right 6, Down 5
Step-by-step explanation:
I don't know how to explain this