puck b has five times the mass of puck a . starting from rest, both pucks are pulled the same distance across frictionless ice by strings with the same tension. part a compare the final kinetic energies of pucks a and b . compare the final kinetic energies of pucks and . ka

It's initial speed is 308 m/s.

The kinetic energy of the bullet is converted to potential energy for the whole system therefore we have:

                                [tex]\frac{1}{2}(m_{1} + m_{2} )V^{2} = (m_{1} + m_{2} )gh[/tex]

                                              i.e. [tex]V = \sqrt{2gh}[/tex]

Now by conservation of momentum,

[tex]m_{1} v = (m_{1}+ m_{2} )V[/tex]

[tex]v = (m_{1}+ m_{2} )V / m_{1}[/tex]

[tex]v = (m_{1}+ m_{2} )\sqrt{2gh} / m_{1}[/tex]

Where,

v = initial speed

m1 = mass of pendulum = 2 kg

m2 = mass of bullet = 10 g = 0.01 kg

h = vertical distance = 12 cm = 0.12m

Putting these values in above equation we get : V  = 308 m/s

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Answer:

66 m/s

Explanation:

Since momentum of the body is conserved

mv=mv

0.25 kg×66m/s=0.25 kg×v

v =0.25kg×66m/s

0.25 kg

v =66m/s

The amount of alcohol consumed will be b. independent variable when participants are tested in a driving simulator after and get a score for accuracy.

What is an Independent variable?

An independent variable is a variable that is manipulated or changed by the researcher in an experiment in order to observe its effect on the dependent variable. In other words, it is a variable that the researcher has control over and changes to test its impact on the outcome.

In this case, the independent variable is the amount of alcohol consumed, as the researcher is manipulating this variable to see how it affects driving performance (the dependent variable).

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The Power is equal to 300 J/s or 300 Watts.

A force that causes a displacement is what the term "quantity work" refers to. The duration of this force's action to produce the displacement has nothing to do with work or power. Sometimes the task is completed quite fast, and other times it is completed fairly slowly. For instance, it takes an unusually long time for a rock climber to raise her body a few meters up the cliff's edge. A trail hiker, on the other hand, could quickly raise her body a few meters if she chooses the simpler route up the mountain. Even though they both perform the same amount of labor, the hiker completes it in a lot less time than the rock climber.

The formula for power is ( P = [tex]\frac{W}{t}[/tex] ) or ( P = [tex]\frac{m \times a \times d}{t}[/tex]  )

m ( mass ) = 60 kg

a ( acceleration ) = 10 m/s²

d ( distance ) =  5 m

t ( time ) = 10 s

P ( Power ) = ?

P = [tex]\frac{m \times a \times d}{t}[/tex]

= [tex]\frac{60\times 10 \times 5}{10}[/tex]

= [tex]\frac{3000}{10}[/tex]

= 300 J/s

= 300 Watts

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The Spring constant k (Stiffness ) will be 6.8 Ib/in for the spring which has an unstretched length of 8 in for 10 lb when d = 4in as given in the problem.

As shown in the picture attached the net force on the y-axis is 0. And Fab*4/[tex]\sqrt{160\\}[/tex]} = 10

Fab = 31.61 Ib.

Fab = K(L-L0)

31.62 = k ([tex]\sqrt{160}[/tex] -8 => 6.8 Ib/in

As spring force is a conservative force where each spring has its own k(Spring constant ) which depends upon the material, Turns, and Size of the spring. To calculate Spring force F = -kx, where k is constant and x, is the length displayed by the force (Stretched or unstretched). The Force might be affected by the temperature around as of material used for making the spring.

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The labeled parts of microscope that you would adjust to move the specimen left, right, forward, and backward are called the stage controls.

Microscope is an instrument that is used to observe small objects, even the cells. The lens bends light toward the eye and makes object appear larger than it actually is.

The stage controls consist of two knobs, one for moving the specimen left and right (x-axis), and one for moving specimen forward and backward (y-axis). The knobs are located on the lower part of the microscope's base, near stage where the specimen is placed. These controls allow you to position specimen correctly under the objective lens for observation.

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The gratis diagram idea, force equilibrium, arrive at a solution. To find the stress in rod AB, first design a model of the free items but then apply equilibria. Next, calculate the stress using the rod's diameter and force.

a straight line that cuts through the middle of a body or figure. especially: the distance along a line passing thru the center of the circle and having its endpoints on the circumference.

A circle's circumference is indeed the width of one full "lap," and its diameter is indeed the length of line segment that divides it in half. Imagine that diameter is an interior measurement, whereas circumference is an outside measurement.

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Answer:

two hunnid fornd qlojm qksil coo looo woo

Explanation:

foe nem

The ratio of the mass of oxygen inhaled for each breath at high altitude and at sea level is 0.629.

Let the mass of oxygen inhaled at sea level, = m₀

Let the mass of oxygen inhaled at 15000 ft, = m₁₅

The volume of air inhaled is same for both case, = v

Density of the air at mean seal level, ρ₀ = 2.337 × 10⁻³ sl/m³

Density of the air at 15000 ft, ρ₁₅ = 1.469 × 10⁻³ sl/m³

m₀ = ρ₀V,     m₁₅ = ρ₁₅V

m₁₅/m₀ = ρ₁₅V/ρ₀V

m₁₅/m₀ = (1.469 × 10⁻³)/(2.337 × 10⁻³)

m₁₅/m₀ = 0.629

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When rotating the device 360 degrees, as long as the does not extend outside the base of stability, the apparatus should remain stable: gravity circle.

The Centre of gravity is a theoretical point in the body where the body’s total weight is thought to be concentrated. It is important to know the centre of gravity because it predicts the behaviour of a moving body when acted on by gravity. It is also useful in designing static structures such as buildings and bridges.

In a uniform gravitational field, the centre of gravity is identical to the centre of mass. Yet, the two points do not always coincide. For the Moon, the centre of mass is very close to its geometric centre. However, its centre of gravity is slightly towards the Earth due to the stronger gravitational force on the Moon’s near side.

In a symmetrically shaped object formed of homogenous material, the centre of gravity may match the body’s geometric centre. However, an asymmetrical object composed of various materials with different masses is likely to have its centre of gravity located at some distance away from its geometric centre. In hollow bodies or irregularly shaped bodies, the centre of gravity lies at a point external to the physical material.

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The agents or mechanisms which are not testable, and therefore cannot provide a scientific explanation are spiritual beliefs.

Spiritual beliefs pertain to an existentialist view of life, death, and the essence of existence and involve a connection to a higher power. These  beliefs also include ceremonies and behaviours like meditative practices or prayer as well as interaction with other believers.

Global warming is the gradual heating of the Earth's surface that has been seen ever since pre-industrial era (between 1850 and 1900), and is attributed to human activity, particularly the combustion of fossil fuels, which raises the concentrations of heat-trapping greenhouse gases.

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Determine the normal force, shear force and moment at a section passing through (a) point C, which is just to right of bearing at A, and (b) point D, which is just to the left of the Force F2.

What is thrust bearing ?

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The correct option is B. Earth is the size of the tip of the ballpoint pen about 15 metres away from the Sun.

Radius of the sun = 7× 10⁸ m

Radius of the earth = 6.37 × 10⁶ m

Radius of the grape fruit = 7.6 × 10⁻² m

As the sun is said to be the size of the grapefruit, scale = (7.6 × 10⁻²)/(7× 10⁸) = 10⁻¹⁰

This means the scale is approximately, 1: 10⁻¹⁰

So, the size of the earth = 6.37× 10⁶ ×10⁻¹⁰ = 6.37×10⁻⁴ m (size of ballpoint)

As we know that the distance between the sun and the earth = 14.9 × 10¹⁰ m

So, in our scale, distance between the sun and the earth = 14.9× 10¹⁰× 10⁻¹⁰  = 14.9 m

which is approximately 15 meters.

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A point charge of 0.06 c at coordinates (0, 0) will create an electric field at coordinates (2.3, -4.1), which will be directed away from the charge and whose magnitude will decrease as distance from the charge rises.

A point charge generates an electric field that is inversely proportional to the square of the distance from the charge. The electric field at that location will have non-zero x and y components because the point charge is at coordinate (0, 0) and the field is being assessed at coordinate (2.3, -4.1). As the distance from the charge grows, the magnitude of the electric field will diminish. The vector pointing from charge to the location where we wish to locate the E-field may be used to calculate the direction of the electric field at (2.3,-4.1).

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The expressions are [tex]F = m g[/tex] , [tex]F = \frac{m v^{2} }{r}[/tex].

The frictional force: This force opposes motion and is created as a result of friction between two surfaces.

[tex]F = m g[/tex]

where m is the object's mass and g is the acceleration brought on by gravity, is a formula for expressing the frictional force.

The centripetal force: To keep an object moving in a circular path, the centripetal force, which is directed toward the centre of the path, must be present.

[tex]F = \frac{m v^{2} }{r}[/tex]

where m is the object's mass, v is its speed, and r is its circular path's radius, is a formula for the centripetal force.

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From pressure definition,  the area of the car tires that are in contact with the road is 0.079 m

Pressure can be defined as the ratio of force to area. It is measured in Pascal.

Given that a car weighs 15,000 N and its tires are I flared to a pressure of 190 kPa. How large is the area of the cars tires that are in contact with the road ?

From the definition of Pressure, P = F/A

Where

190000 = 15000/A

A = 15000/190000

A = 0.079 m

A car will have 4 tires. The area of one in contact with the road will be

A = 0.079/4

A = 0.02 m

Therefore, the area of the car tire that is in contact with the road is 0.02 m

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The Earth's orbit around the Sun is almost circular, therefore, Earth receives about same amount of year-round a.) heat and light

Earth's orbit defines a two-dimensional plane which we call the ecliptic. It takes almost 365 days for the Earth to go around the Sun once.

The Earth's orbit around the Sun is almost circular, Thus, Earth receives about the same amount of year-round sunlight (or known as  solar energy).

Earth's orbit is not a perfect circle and is elliptical, or slightly oval-shaped. This means that there is one point in the orbit where Earth is closest to the Sun, and one where Earth is farthest from the Sun.

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Single-touch method: The magnetic substance is moved from one end to the other by rubbing a magnet along it.

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"laser beam" can be handled as "light".

Speed of light in vacuum = 300,000 km/sec

Distance = (speed) x (time)

Distance light traveled = (300,000 km/sec) x (2.63 sec)

Distance the light traveled = 789,000 km

But this is DOUBLE the distance to the moon, because the laser light had to GO and COME BACK in order to be detected back on Earth.

So the distance to the moon was (1/2) of (789,000 km) = 394,500 km

A) The initial velocity of the ball is 20.14 m/s, B) the height of the ball when it passes over player B is 11.36 ft.

Let the initial velocity of the basketball, = v

Horizontal component, = vcos30 = 0.866 v

Vertical component, = vsin30 = 0.5 v

Horizontal distance travelled by the ball, H = 25 + 4.5 = 29.5 ft

We know vcos30 × t = 29.5

vt = 29.5/0.866 = 34.06 ft

vt = 34.06

Now by the third equation of motion, vertical height(10 - 7 =3 ft) travelled by the vertical component of the ball

(10 - 7) = vsin30 × t - 0.5gt²

3 = 0.5vt - 0.5 × 9.81 × t²

we know vt = 34.06

3 = 0.5 × 34.06 - 4.9t²

t = 1.69 sec

So, v = 34.06/1.69 = 20.14 m/s

Now part B,

Height of the ball above the player B, = h

horizontal range, R = 25 ft

Time taken to reach 25 ft = 25/(20.14 cos30)

= 25/17.44 = 1.43 sec

vertical distance travelled by the ball in 1.43 sec,

d = 20.14×sin30×1.43 - 0.5 × 9.81 × 1.43²

d = 4.37 ft

Total height above the ground, H = 7 + 4.37 = 11.34 ft.

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The P-waves are the primary waves that are the fastest and the first to arrive at the seismometer.

Seismic waves, which are vibrations caused by the movement of the Earth's crust, are recorded at various locations after an earthquake has occurred. The type of seismic waves recorded at a particular location depends on its distance from the epicenter (point X) of the earthquake.

There are two main types of seismic waves: body waves and surface waves. Body waves, such as P-waves and S-waves, travel through the Earth's interior and can be recorded at any location. Surface waves, such as Love waves and Rayleigh waves, travel along the Earth's surface and are typically recorded closer to the epicenter.

The P-waves are the primary waves that are the fastest and the first to arrive at the seismometer. The S-waves are the secondary waves that are slower and arrive later than P-waves.

In general, the closer a location is to the epicenter, the stronger and more frequent the seismic waves will be.

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"I understand how to properly use the PEFM to measure my peak expiratory flow and will use it daily to track my lung function," the newly diagnosed asthmatic states in the statement.

Option B is correct.

A peak flow meter measures how quickly you can expel air from your lungs by blowing as forcefully and quickly as you can. This is what peak flow means.

This drop indicates the possibility of an asthma attack. You can figure out what "triggered" the drop in blood pressure by measuring your peak flow, which medications to add or take off, and when you might need emergency care.

A peak flow meter is simple to use. How to figure out your peak flow:

which statement shows that the newly diagnosed asthma patient understands how to use a peak expiratory flow meter (pefm)?

A. Wear gloves during blood glucose monitoring and during any other procedure that involves potential exposure to blood or body fluids.

B. "I understand how to properly use the PEFM to measure my peak expiratory flow and will use it daily to track my lung function."

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A stone is dropped from rest at an initial height h above the surface of the earth. Show that the speed with which it strikes the ground is v= 2gh.

Let x(t) be the position of the stone above the ground.

The differential equation x'= - g relates the position of the stone to the acceleration due to gravity.

A differential equation is an equation which contains one or more terms and the derivatives of one variable (i.e., dependent variable) with respect to the other variable (i.e., independent variable)

dy/dx = f(x)

Here “x” is an independent variable and “y” is a dependent variable

For example, dy/dx = 5x

A differential equation contains derivatives which are either partial derivatives or ordinary derivatives. The derivative represents a rate of change, and the differential equation describes a relationship between the quantity that is continuously varying with respect to the change in another quantity. There are a lot of differential equations formulas to find the solution of the derivatives.

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The acceleration of a cheetah is higher than that of a Thomson's gazelle but lower than that of the space shuttle during takeoff.

The amount upon which velocity decreases is known as accelerate. Acceleration typically indicates that the speed is changing, but not necessarily. An item that is moving in a circle while maintaining a constant speed is still accelerating because the direction of its motion is shifting.

The measurement of a change in an object's velocity is known as acceleration. A car accelerates faster and quicker when the gas pedal is depressed. Acceleration is indicated by this change in velocity.

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The acceleration of the car if the mass of the cart is doubled is ½a (option A).

Acceleration refers to change of velocity with respect to time (can include deceleration or changing direction).

Newton's first law of motion explains the relationship between the mass, force and acceleration of a body using the following expression;

Force = mass × acceleration

Mass and acceleration of a body are indirectly related. This means that if mass increases, acceleration decreases, hence, the acceleration in this question will decrease by half i.e. ½a.

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To measure the voltage across an LED using a digital multimeter (DMM), follow these steps:

1. Turn the dial on the DMM to the voltage measurement setting.

2. Place the DMM black test lead on the LED cathode terminal and the red lead on the LED anode terminal.

3. The DMM should display the threshold voltage of the LED.

It is important to note that the cathode is the negative terminal, and the anode is the positive terminal of the led.

Electric potential energy per unit charge in an electrical circuit is measured by voltage, sometimes referred to as electric potential difference. It is commonly measured in units of volts (V). Voltage is the force that causes electric current to flow in a circuit, and it can be thought of as the "pressure" that pushes the electrons through the circuit.

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Answer:

a) 54.13m

Explanation:

The formula for horizontal range is R = v2 (sin 2θ)/g. Here, v = 25, θ = 60°, g = 10. Hence, on solving we will get range as 54.13 m.

The buoyant force forms a newton's third law pair with the force of gravity on the object helps explain why the buoyant force exerted on an object submerged in a fluid on earth is always directed upward.

The term "buoyancy" refers to the upward push a liquid applies to an object submerged in it. An upward force is imposed on an object when you try to submerge it in water, and this force grows as the object is pushed deeper. The tendency of a fluid to exert an upward force on an item that is partially or completely submerged in that fluid is known as buoyancy or a buoyant force. Newton is the SI unit for buoyant force. An object in water experiences an upward force known as buoyancy that is equal to the weight of the water that the object has displaced.

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