-Quadratic Equations- Solve each by factoring, write each equation in standard form first.

-Quadratic Equations- Solve Each By Factoring, Write Each Equation In Standard Form First.

Answers

Answer 1

Answer

The solutions to the quadratic equations are

[tex]\begin{gathered} a^2-4a-45 \\ \text{Solution: }a=-5\text{ or }9 \\ \\ 5y^2+4y=0 \\ \text{Solution: }y=0\text{ or }-\frac{4}{5} \end{gathered}[/tex]

SOLUTION

Problem Statement

The question gives us 2 quadratic equations and we are required to solve them by factoring, first writing them in their standard forms.

The quadratic equations given are:

[tex]\begin{gathered} a^2-4a-45=0 \\ 5y^2+4y=0 \end{gathered}[/tex]

Method

To solve the questions, we need to follow these steps:

(We will represent the independent variable as x for this explanation. We know they are "a" and "y" in the questions given)

The steps outlined below are known as the method of Completing the Square.

Step 1: Find the square of the half of the coefficient of x.

Step 2: Add and subtract the result from step 1.

Step 3: Re-write the Equation. This will be the standard form of the equation

Step 4. Solve for x

We will apply these steps to solve both questions.

Implementation

Question 1:

[tex]\begin{gathered} a^2-4a-45=0 \\ \text{Step 1: Find the square of the half of the coefficient of }a \\ (-\frac{4}{2})^2=(-2)^2=4 \\ \\ \text{Step 2: Add and subtract 4 to the equation} \\ a^2-4a-45+4-4=0 \\ \\ \text{Step 3: Rewrite the Equation} \\ a^2-4a+4-45-4=0 \\ (a^2-4a+4)-49=0 \\ (a^2-4a+4)=(a-2)^2 \\ \therefore(a-2)^2-49=0 \\ \text{ In standard form, we have:} \\ (a-2)^2=49 \\ \\ \text{Step 4: Solve for }a \\ (a-2)^2=49 \\ \text{ Find the square root of both sides} \\ \sqrt[]{(a-2)^2}=\pm\sqrt[]{49} \\ a-2=\pm7 \\ \text{Add 2 to both sides} \\ \therefore a=2\pm7 \\ \\ \therefore a=-5\text{ or }9 \end{gathered}[/tex]

Question 2:

[tex]\begin{gathered} 5y^2+4y=0 \\ \text{ Before we begin solving, we should factorize out 5} \\ 5(y^2+\frac{4}{5}y)=0 \\ \\ \text{Step 1: Find the square of the coefficient of the half of y} \\ (\frac{4}{5}\times\frac{1}{2})^2=(\frac{2}{5})^2=\frac{4}{25} \\ \\ \text{Step 2: Add and subtract }\frac{4}{25}\text{ to the equation} \\ \\ 5(y^2+\frac{4}{5}y+\frac{4}{25}-\frac{4}{25})=0 \\ \\ \\ \text{Step 3: Rewrite the Equation} \\ 5((y^2+\frac{4}{5}y+\frac{4}{25})-\frac{4}{25})=0 \\ 5(y^2+\frac{4}{5}y+\frac{4}{25})-5(\frac{4}{25})=0 \\ 5(y^2+\frac{4}{5}y+\frac{4}{25})-\frac{4}{5}=0 \\ \\ (y^2+\frac{4}{5}y+\frac{4}{25})=(y+\frac{2}{5})^2 \\ \\ \therefore5(y+\frac{2}{5})^2-\frac{4}{5}=0 \\ \\ \text{ In standard form, the Equation becomes} \\ 5(y+\frac{2}{5})^2=\frac{4}{5} \\ \\ \\ \text{Step 4: Solve for }y \\ 5(y+\frac{2}{5})^2=\frac{4}{5} \\ \text{ Divide both sides by 5} \\ \frac{5}{5}(y+\frac{2}{5})^2=\frac{4}{5}\times\frac{1}{5} \\ (y+\frac{2}{5})^2=\frac{4}{25} \\ \\ \text{ Find the square root of both sides} \\ \sqrt[]{(y+\frac{2}{5})^2}=\pm\sqrt[]{\frac{4}{25}} \\ \\ y+\frac{2}{5}=\pm\frac{2}{5} \\ \\ \text{Subtract }\frac{2}{5}\text{ from both sides} \\ \\ y=-\frac{2}{5}\pm\frac{2}{5} \\ \\ \therefore y=0\text{ or }-\frac{4}{5} \end{gathered}[/tex]

Final Answer

The solutions to the quadratic equations are

[tex]\begin{gathered} a^2-4a-45 \\ \text{Solution: }a=-5\text{ or }9 \\ \\ 5y^2+4y=0 \\ \text{Solution: }y=0\text{ or }-\frac{4}{5} \end{gathered}[/tex]


Related Questions

There are 3 consecutive even integers that have a sum of 6. What is the value of the least integer?

Answers

We can express this question as follows:

[tex]n+(n+2)+(n+4)=6[/tex]

Now, we can sum the like terms (n's) and the integers in the previous expression. Then, we have:

[tex](n+n+n)+(2+4)=6=3n+6\Rightarrow3n+6=6[/tex]

Then, to solve the equation for n, we need to subtract 6 to both sides of the equation, and then divide by 3 to both sides too:

[tex]3n+6-6=6-6\Rightarrow3n=0\Rightarrow n=\frac{3}{3}n=\frac{0}{3}\Rightarrow n=0_{}[/tex]

Then, we have that the three consecutive even integers are:

[tex]0+2+4=6[/tex]

Therefore, the least integer is 0.

Find the y-intercept of the line represented by the equation: -5x+3y=30

Answers

We need to find the y-intercept of the equation.

For this, we need to use the slope-intercept form:

[tex]y=mx+b[/tex]

Where m represents the slope and b the y-intercept.

Now, to get the form, we need to solve the equation for y:

Then:

[tex]-5x+3y=30[/tex]

Solving for y:

Add both sides 5x:

[tex]-5x+5x+3y=30+5x[/tex][tex]3y=30+5x[/tex]

Divide both sides by 3

[tex]\frac{3y}{3}=\frac{30+5x}{3}[/tex][tex]\frac{3y}{3}=\frac{30}{3}+\frac{5x}{3}[/tex][tex]y=10+\frac{5}{3}x[/tex]

We can rewrite the expression as:

[tex]y=\frac{5}{3}x+10[/tex]

Where 5/3x represents the slope and 10 represents the y-intercept.

The y-intercept represents when the graph of the equations intersects with the y-axis, therefore, it can be written as the ordered pair (0,10).

what is the better buy 4GB flash drive for $8 2 GB for $6 or 8 GB for $13

Answers

In order to find out which of the options would be better to buy we would have to calculate the better unit price that eacho of the following options offer.

So, unit price for the offers would be:

For 4GB flash drive for $8, unit price=$8/4

unit price=$2

For 2 GB for $6, unit price=$6/2=$3

For 8 GB for $13, unit prince=$13/8=$1.625

Therefore, as the unit price of 8 GB for $13 is the lower one, then the better choice to buy would be 8 GB for $13

Determine the required value of a missing probability to make the distribution a discrete probability distribution… p(4) =

Answers

The table given showed the discrete probability distribution for random variables 3 to 6 and their corresponding probability except for the probability of 4

It should be noted that for a probability distribution, the cummulative probabibility (that is the sum of all the probability) must be equal to one.

This means that

[tex]P(3)+P(4)+P(5)+P(6)=1[/tex]

From the given table, it can be seen that

[tex]\begin{gathered} P(3)=0.32 \\ P(4)=\text{?} \\ P(5)=0.17 \\ P(6)=0.26 \end{gathered}[/tex]

Then, p(4) is calculated below

[tex]\begin{gathered} P(3)+P(4)+P(5)+P(6)=1 \\ 0.32+P(4)+0.17+0.26=1 \\ P(4)+0.32+0.17+0.26=1_{} \\ P(4)+0.75=1 \\ P(4)=1-0.75 \\ P(4)=0.25 \end{gathered}[/tex]

Hence, P(4) is 0.25

Identity the triangle congruence postulate (SSS,SAS,ASA,AAS, or HL) that proves the triangles are congruent. I will mark brainliest!!!

Answers

These are my old notes, I hope they can help.

SSS, or Side Side Side

SAS, or Side Angle Side

ASA, or Angle Side Side

AAS, or Angle Angle Side

HL, or Hypotenuse Leg, for right triangles only

Side Side Side Postulate

A postulate is a statement taken to be true without proof. The SSS Postulate tells us,

If three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent.

Congruence of sides is shown with little hatch marks, like this: ∥. For two triangles, sides may be marked with one, two, and three hatch marks.

If △ACE has sides identical in measure to the three sides of △HUM, then the two triangles are congruent by SSS:

Side Angle Side Postulate

The SAS Postulate tells us,

If two sides and the included angle of a triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.

△HUG and △LAB each have one angle measuring exactly 63°. Corresponding sides g and b are congruent. Sides h and l are congruent.

A side, an included angle, and a side on △HUG and on △LAB are congruent. So, by SAS, the two triangles are congruent.

Angle Side Angle Postulate

This postulate says,

If two angles and the included side of a triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent.

We have △MAC and △CHZ, with side m congruent to side c. ∠A is congruent to ∠H, while ∠C is congruent to ∠Z. By the ASA Postulate these two triangles are congruent.

Angle Angle Side Theorem

We are given two angles and the non-included side, the side opposite one of the angles. The Angle Angle Side Theorem says,

If two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent.

Here are congruent △POT and △LID, with two measured angles of 56° and 52°, and a non-included side of 13 centimeters:

[construct as described]

By the AAS Theorem, these two triangles are congruent.

HL Postulate

Exclusively for right triangles, the HL Postulate tells us,

Two right triangles that have a congruent hypotenuse and a corresponding congruent leg are congruent.

The hypotenuse of a right triangle is the longest side. The other two sides are legs. Either leg can be congruent between the two triangles.

Here are right triangles △COW and △PIG, with hypotenuses of sides w and i congruent. Legs o and g are also congruent:

[insert congruent right triangles left-facing △COW and right facing △PIG]

So, by the HL Postulate, these two triangles are congruent, even if they are facing in different directions.

Proof Using Congruence

Proving Congruent Triangles 5

Given: △MAG and △ICG

MC ≅ AI

AG ≅ GI

Prove: △MAG ≅ △ICG

Statement Reason

MC ≅ AI Given

AG ≅ GI

∠MGA ≅ ∠ IGC Vertical Angles are Congruent

△MAG ≅ △ICG Side Angle Side

If two sides and the included angle of a triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.

Use the distance formula to find the distance between the points given.(3,4), (4,5)

Answers

Solution:

To find the distance between two points, the formula is

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Where

[tex]\begin{gathered} (x_1,y_1)=(3,4) \\ (x_2,y_2)=(4,5) \end{gathered}[/tex]

Substitute the values of the variables into the formula above

[tex]d=\sqrt{(4-3)^2+(5-4)^2}=\sqrt{1^2+1^2}=\sqrt{1+1}=\sqrt{2}\text{ units}[/tex]

Hence, the answer is

[tex]\sqrt{2}\text{ units}[/tex]

the population of a town grows at a rate proportional to the population present at time t. the initial population of 500 increases by 15% in 10 years. what will be the pop ulation in 30 years? how fast is the population growing at t 30?

Answers

Using the differential equation, the population after 30 years is 760.44.

What is meant by differential equation?In mathematics, a differential equation is a relationship between the derivatives of one or more unknown functions. Applications frequently involve a function that represents a physical quantity, derivatives that show the rates at a differential equation that forms a relationship between the three, and a function that represents how those values change.A differential equation is one that has one or more functions and their derivatives. The derivatives of a function define how quickly it changes at a given location. It is frequently used in disciplines including physics, engineering, biology, and others.

The population P after t years obeys the differential equation:

dP / dt = kP

Where P(0) = 500 is the initial condition and k is a positive constant.

∫ 1/P dP = ∫ kdtln |P| = kt + C|P| = e^ce^kt

Using P(0) = 500 gives 500 = Ae⁰.

A = 500.Thus, P = 500e^kt

Furthermore,

P(10) = 500 × 115% = 575sO575 = 500e^10ke^10k = 1.1510 k = ln (1.15)k = In(1.15)/10 ≈ 0.0140Therefore, P = 500e^0.014t.

The population after 30 years is:

P = 500e^0.014(30) = 760.44

Therefore, using the differential equation, the population after 30 years is 760.44.

To learn more about differential equations refer to:

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1 pts
4. If line segment AB has coordinates A(-2,4) and B(2,0) and line segment
CD has coordinates C(3,4)and D(-3,-2), how would you describe these two
line segments?

A: neither
B: perpendicular
C: parallel

Answers

Answer:

B

Step-by-step explanation:

[tex]m_{\overline{AB}}=\frac{4-0}{-2-2}=-1 \\ \\ m_{\overline{CD}}=\frac{-2-4}{-3-3}=1 [/tex]

Since the slopes are negative reciprocals of each other, and since they intersect, they are parallel.

A yogurt stand gave out 200 free samples of frozen yogurt, one free sample per person. The three sample choices were vanilla, chocolate, or chocolate & vanilla twist. 115 people tasted the vanilla and 137 people tasted the chocolate, some of those people tasted both because they chose the chocolate and vanilla twist. How many people chose chocolate and vanilla twist?

Answers

GivenA yogurt stand gave out 200 free samples of frozen yogurt, one free sample per person. The three sample choices were vanilla, chocolate, or chocolate & vanilla twist. 115 people tasted the vanilla and 137 people tasted the chocolate, some of those people tasted both because they chose the chocolate and vanilla twist. How many people chose chocolate and vanilla twist?

So we are to find x

[tex]137-x+x+115-x=200[/tex][tex]\begin{gathered} 137+115-x=200 \\ 252-x=200 \\ -x=200-252 \\ -x=-52 \\ x=52 \end{gathered}[/tex]The final answer52 people chose chocolate and vanilla twist

6. A line goes through these two points, (-4, -1) anti (-9,-5).A. Find an equation for this line in point slope form.B. Find the equation for this line in slope intercept form. Be sure to show your work.C. If the y-coordinate of a point on this line is 7, what is the x-coordinate of this point?

Answers

A. In order to find the equation, first we need to find the slope

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

m is the slope

(-4, -1)=(x1,y1)

(-9,-5)=(x2,y2)

we substitute the values

[tex]m=\frac{-5+1}{-9+4}=\frac{-4}{-5}=\frac{4}{5}[/tex]

then we use the point-slope form

[tex]y-y_1=m(x-x_1)[/tex]

we substitute the values

[tex]y+1=\frac{4}{5}(x+4)[/tex]

B. in order to find the slope-intercept form we need to isolate the y

[tex]y=\frac{4}{5}x+\frac{11}{5}[/tex]

C. if the y coordinate is 7

[tex]7=\frac{4}{5}(x)+\frac{11}{5}[/tex]

then we isolate the x

[tex]\frac{4}{5}x=7-\frac{11}{5}[/tex][tex]\begin{gathered} \frac{4}{5}x=\frac{24}{5} \\ x=\frac{5\cdot24}{5\cdot4} \\ x=6 \end{gathered}[/tex]

the value of the x-coordinate is 6 when the y-coordinate is 7

Can you explain this math to me please I’ve never seen it before and don’t understand

Answers

For a quadratic function in standard form,

[tex]\begin{gathered} \text{a = coefficient of x}^2 \\ b\text{ = coeffcient of x} \\ c=\text{ the constant term} \end{gathered}[/tex]

For the polynomial f(x),

a = 2, b = -3 and c = 4

For the polynomial g(x)

a = 4, b = -6, c = 10

For the polunomial h(x),

a = 7, b = 0, c = 8

For the polynomia p(x),

a = 1, b = -10, c = 0

Hi, I need help on this. the sentence says Write the Numbers that represent each Expression

Answers

H = 1, P =2, R = 3 B = -1, C = -2, A = -3, Q = -5

Explanation:

For the first number line:

From the tick mark to the tick mark with 4, there are 4 tick marks

Distance from 0 to 4 = 4 - 0 = 4

Each tick mark = 4/4 tick marks

Each tick mark = 1

This means each tick mark increases by 1 to the right after 0 and decreases by one to the left before zero.

H, P and R are after 0

H = 0 + 1 = 1

P = 1 + 1 = 2

R = 2 + 1 = 3

B, C, A and Q are all before 0

B = 0 - 1 = -1

C = -1 - 1 = -2

A = -2 - 1 = -3

Q = -4 - 1 = -5

For the 2nd number line:

from 0 to 100, there 5 tick marks

Distance from 0 to 100 = 100 - 0 = 100

Each tick mark = 100/5 tick marks

Each tick mark = 20

This means each tick mark after zero increases by 20 to the right and decreases to the before 0 by 20.

A, L and M are after zero

Number before A is 20, increasing the number by 20

A = 20 + 20 = 40

L = 40 + 20 = 60

M = 60 + 20 = 80

J, P, T, V are before zero

Number before J = 0, decreasing by 20

J = 0 - 20 = -20

P = -20 - 20 = -40

T = -40 - 20 = -60

V = -60 - 20 = -80

Transform y f(x) by translating it right 2 units. Label the new functiong(x). Compare the coordinates of the corresponding points that makeup the 2 functions. Which coordinate changes. x or y?

Answers

If we translate y = f(x) 2 units to the right, we would have to sum and get g(x) =f(x+2).

That means the x-coordinates of g(x) are going to have 2 extra units than f(x).

[tex](x,y)\rightarrow(x+2,y)[/tex]

Therefore, with the given transformation (2 units rightwards) the function changes its x-coordinates.

In how many ways can the letters in the word PAYMENT be arranged using 4 letters?A. 42B. 840C. 2520D. 1260

Answers

The word PAYMENT has 7 letters. They can be arranged in groups of 4 like shown below:

PYNT, TA

Determine whether a tangent line is shown in this figure

Answers

Given:

Required:

To determine whether a tangent line is shown in the given figure.

Explanation:

By the definition of tangent line, we know that tangent line is a straight line that touches the circle at one point.

Now consider the given figure, there is a tangent line in the given figure.

Final Answer:

Yes.

Miguel made $17.15 profit from selling 7 custom t-shirts through a website. Miguel knows the total profit he earns is proportional to the number of shirts he sells, and he wants to create an equation which models this relationship so that he can predict the total profit from selling any number of t-shirts.

Answers

Let:

[tex]\begin{gathered} P(x)=\text{profit} \\ k=\text{price of each t-shirt} \\ x=\text{Number of t-shirts sold} \end{gathered}[/tex]

Miguel made $17.15 profit from selling 7 custom t-shirts, therefore:

[tex]\begin{gathered} P(7)=17.15=k(7) \\ 17.15=7k \\ \text{Solving for k:} \\ k=\frac{17.15}{7}=2.45 \end{gathered}[/tex]

Therefore, the equation that models this relationship is:

[tex]P(x)=2.45x[/tex]

For each ordered pair, determine whether it is a solution.

Answers

To determine which ordered pair is a solution to the equation we shall substitute the values of x and y in the ordered pair.

Taking the first ordered pair;

[tex]\begin{gathered} \text{For;} \\ 3x-5y=-13 \\ \text{Where;} \\ (x,y)\Rightarrow(9,8) \\ 3(9)-5(8)=-13 \\ 27-40=-13 \\ -13=-13 \end{gathered}[/tex]

This means the ordered pair (9, 8) is a solution.

We can also solve this graphically a follows;

Observe from the graph attached that the solution to the equation shown above is indicated at the point where x = 9 and y = 8.

The other ordered pairs in the answer options cannot be found on the line which simply mean they are not solutions to the equation given.

ANSWER:

The ordered pair (9, 8) is a solution to the equation 3x - 5y = -13

The length of a rectangle is 2 inches more than its width.If P represents the perimeter of the rectangle, then its width is:oAB.O4Ос. РOD.P-2 별O E, PA

Answers

Given:

a.) The length of a rectangle is 2 inches more than its width.

Since the length of a rectangle is 2 inches more than its width, we can say that,

Width = W

Length = L = W + 2

Determine the width with respect to its Perimeter, we get:

[tex]\text{ Perimeter = P}[/tex][tex]\text{ P = 2W + 2L}[/tex][tex]\text{ P = 2W + 2(W + 2)}[/tex][tex]\text{ P = 2W + 2W + }4[/tex][tex]\text{ P = 4W + }4[/tex][tex]\text{ P - 4 = 4W}[/tex][tex]\text{ }\frac{\text{P - 4}}{4}\text{ = }\frac{\text{4W}}{4}[/tex][tex]\text{ }\frac{\text{P - 4}}{4}\text{ = W}[/tex]

Therefore, the answer is D.

I wondered if you could teach me how to do this so I can do these problems independently.

Answers

Answer

a)

A' (-2, 6)

B' (7, 3)

C' (4, 0)

b)

D' (3, 3)

E' (-5, 0)

F' (2, 2)

c)

G' (3, 1)

H' (0, 4)

P' (-2, -3)

Explanation

For the coordinate (x, y)

A transformation to the right adds that number of units to the x-coordinate.

A transformation to the left subtracts that number of units from the x-coordinate.

A transformation up adds that number of units to the y-coordinate.

A transformation down subtracts that number of units from the y-coordinate.

For this question,

a) The coordinates are translated to the right by 4 units and upwards by 1 unit

That is,

(x, y) = (x + 4, y + 1)

A (-6, 5) = A' (-6 + 4, 5 + 1) = A' (-2, 6)

B (3, 2) = B' (3 + 4, 2 + 1) = B' (7, 3)

C (0, -1) = C' (0 + 4, -1 + 1) = C' (4, 0)

When a given point with coordinates P (x, y) is reflected over the y-axis, the y-coordinate remains the same and the x-coordinate takes up a negative in front of it. That is, P (x, y) changes after being reflected across the y-axis in this way

P (x, y) = P' (-x, y)

For this question,

b) The coordinates are reflected over the y-axis

D (-3, 3) = D' (3, 3)

E (5, 0) = E' (-5, 0)

F (-2, 2) = F' (2, 2)

In transforming a point (x, y) by rotating it 90 degrees clockwise, the new coordinates are given as (y, -x). That is, we change the coordinates and then add minus to the x, which is now the y-coordinate.

P (x, y) = P' (y, -x)

For this question,

c) The coordinates are rotated about (0, 0) 90 degrees clockwise.

G (-1, 3) = G' (3, 1)

H (-4, 0) = H' (0, 4)

I (3, -2) = P' (-2, -3)

Hope this Helps!!!

how long will it take for $2700 to grow to $24500 at an interest rate of 2.2% if the interest is compounded quarterly? Round to the nearest hundredth.

Answers

Let n be the number of quarterlies.

Then

[tex]\begin{gathered} 24500=2700(1+0.022)^n \\ \Rightarrow1.022^n=\frac{245}{27} \\ \Rightarrow n=\frac{\log _{10}\frac{245}{27}}{\log _{10}1.022} \end{gathered}[/tex]

Hence the number of months = 3n = 304.04 months

and the number of years = n / 4 = 25.34 years

currently, Yamir is twice as old as pato. in three years, the sum of their ages will be 30. if pathos current age is represented by a, what equation correctly solves for a?

Answers

The given situation can be written in an algebraic way.

If pathos age is a, and Yamir age is b. You have:

Yamir is twice as old as pato:

b = 2a

in three years, the sum of their ages will be 30:

(b + 3) + (a + 3) = 30

replace the b = 2a into the last equation, and solve for a, just as follow:

2a + 3 + a + 3 = 30 simplify like terms left side

3a + 6 = 30 subtract 6 both sides

3a = 30 - 6

3a = 24 divide by 3 both sides

a = 24/3

a = 8

Hence, the age of Pato is 8 years old.

which expressions are equivalent to 9 divided by 0.3

Answers

Answer:

Step-by-step explanation:

So the answer would be 90 divided by 3 because all you have to do is multiply 0.3 times 10 and 9 times 10 simple hope this was understandable

30 will be the expressions that are equivalent to 9 divided by 0.3.

What is an equivalent expression?

In general, something is considered equal if two of them are the same. Similar to this, analogous expressions in maths are those that hold true even when they appear to be distinct. However, both forms provide the same outcome when the values are entered into the formula.

An expression is equivalent even when both sides are multiplied or divided with the same non-zero value.

The expression 9 divided by 0.3 can be written as 9/0.3

The expression that will be equivalent will be determined as:

= 9/0.3

= 90/3

= 30

Learn more about equivalent expression, Here:

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Dalia works mowing lawns and babysitting. She earns $8.40 an hour for mowing and $7.90 an hour for babysitting . How much will ahe earn for 7 hours of mowing and 1 hour of babysitting?

Answers

Given that she earns $8.40 an hour for mowing then for 7 hours of mowing, the amount earned

= 7 * $8.40

=$58.80

Furthermore, given that she earns $7.90 for baby sitting for an hour

Hence for mowing for 7 hours and baby sitting for 1 hour, the total amount she will earn

= $58.80 + $7.90

= $66.70

Suppose that a household's monthly water bill (in dollars) is a linear function of the amount of water the household uses (in hundreds of cubic feet, HCF). When graphed, the function gives a line with a slope of 1.45. See the figure below.

If the monthly cost for 22 HCF is $45.78, what is the monthly cost for 19 HCF?

Answers

Using a linear function, it is found that the monthly cost for 19 HCF is of $41.43.

What is a linear function?

A linear function, in slope-intercept format, is modeled according to the rule presented below:

y = mx + b

In which the parameters of the function are described as follows:

The coefficient m is the slope of the function, representing the rate of change of the function, that is, the change in y divided by the change in x.The coefficient b is the y-intercept of the function, which is the value of y when the function crosses the y-axis(x = 0).

As stated in the problem, the slope is of 1.45, hence:

y = 1.45x + b.

The monthly cost for 22 HCF is $45.78, hence when x = 22, y = 45.78, meaning that the intercept b can be found as follows:

45.78 = 1.45(22) + b

b = 45.78 - 1.45 x 22

b = 13.88.

Then the function is:

y = 1.45x + 13.88.

And the cost for 19 HCF is given by:

y = 1.45(19) + 13.88 = $41.43.

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To the function attached,Is f(x) continuous at x=1? Please explain

Answers

Recall that a function is continuous at a point if the limit as the variable approaches a value is the same as the value of the function at that point.

Now, notice that, using the definition of the function:

[tex]\begin{gathered} \lim_{x\to1^+}f(x)=\sqrt{1}+2=3, \\ \lim_{x\to1^-}f(x)=3, \end{gathered}[/tex]

therefore:

[tex]\lim_{x\to1}f(x)=3.[/tex]

Given that the limit and the value of the function at x=1 are equal, the function is continuous at x=1.

Answer: It is continuous at x=1.

5. Joseph Cheyenne is earning an annual salary of $24,895. He has been offered the job in the ad. How much more would he earn per month if he is paid: a. the minimum? b. the maximum

Answers

Joseph has an annual salary of $24895 dollars and she get the new job that is between 28000-36000 dollars so:

the minimum will be:

[tex]24895+28000=52000[/tex]

and the maximun will be:

[tex]24895+36000=60895[/tex]

The floor of a shed has an area of 80 square feet. The floor is in the shape of a rectangle whose length is 6 feet less than twice the width. Find the length and the width of the floor of the shed. use the formula, area= length× width The width of the floor of the shed is____ ft.

Answers

Given:

The area of the rectangular floor is, A = 8- square feet.

The length of the rectangular floor is 6 feet less than twice the width.

The objective is to find the measure of length and breadth of the floor.

Consider the width of the rectangular floor as w, then twice the width is 2w.

Since, the length is given as 6 feet less than twice the width. The length can be represented as,

[tex]l=2w-6[/tex]

The general formula of area of a rectangle is,

[tex]A=l\times w[/tex]

By substituting the values of length l and width w, we get,

[tex]\begin{gathered} 80=(2w-6)\times w \\ 80=2w^2-6w \\ 2w^2-6w-80=0 \end{gathered}[/tex]

On factorizinng the above equation,

[tex]\begin{gathered} 2w^2-16w+10w-80=0 \\ 2w(w-8)+10(w-8)=0 \\ (2w+10)(w-8)=0 \end{gathered}[/tex]

On solving the above equation,

[tex]\begin{gathered} 2w+10=0 \\ 2w=-10 \\ w=\frac{-10}{2} \\ w=-5 \end{gathered}[/tex]

Similarly,

[tex]\begin{gathered} w-8=0 \\ w=8 \end{gathered}[/tex]

Since, the magnitude of a side cannot be negative. So take the value of width of the rectangle as 8 feet.

Substitute the value of w in area formula to find length l.

[tex]\begin{gathered} A=l\times w \\ 80=l\times8 \\ l=\frac{80}{8} \\ l=10\text{ f}eet. \end{gathered}[/tex]

Hence, the width of the floor of the shed is 8 ft.

Write the following number as a fraction:

0.27

Answers

Step-by-step explanation:

27/100 is the fraction of 0.27

What is the equation in slope-intercept form of the line that passes through the points (-4,8) and (12,4)?

Answers

ANSWER

y = -0.25 + 7

EXPLANATION

The line passes through the points (-4, 8) and (12, 4).

The slope-intercept form of a linear equation is written as:

y = mx + c

where m = slope

c = y intercept

First, we have to find the slope of the line.

We do that with formula:

[tex]\begin{gathered} m\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ \text{where (x}_1,y_1)\text{ = (-4, 8) } \\ (x_2,y_2)\text{ = (12, 4)} \end{gathered}[/tex]

Therefore, the slope is:

[tex]\begin{gathered} m\text{ = }\frac{4\text{ - 8}}{12\text{ - (-4)}}\text{ = }\frac{-4}{12\text{ + 4}}\text{ = }\frac{-4}{16}\text{ = }\frac{-1}{4} \\ m\text{ = -0.25} \end{gathered}[/tex]

Now, we use the point-slope method to find the equation:

[tex]\begin{gathered} y-y_{1\text{ }}=m(x-x_1) \\ \Rightarrow\text{ y - 8 = -0.25(x - (-4))} \\ y\text{ - 8 = -0.25(x + 4)} \\ y\text{ - 8 = -0.25x - 1} \\ y\text{ = -0.25x - 1 + 8} \\ y\text{ = -0.25x + 7} \end{gathered}[/tex]

That is the equation of the line. It is not among the options.

b. Function h will begin to exceed f and g around x = [. (Round up to the nearest whole number.)

Answers

If we evaluate x = 10 on all the functions, we have:

[tex]\begin{gathered} h(10)=1.31^{10}=14.88 \\ f(10)=1.25(10)=12.5 \\ g(10)=0.1562(10)^2=15.625 \end{gathered}[/tex]

and then, evaluating x = 11, we get:

[tex]\begin{gathered} h(11)=1.13^{11}=19.49 \\ f(11)=1.25(11)=13.75 \\ g(11)=0.15625(11)^2=18.9 \end{gathered}[/tex]

notice that on x = 10, h(x) does not exceed g(x), but on x = 11, h(x) exceeds the other functions. Therefore, h will begin exceed f and g around 11

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