Question 11 . 2 p Brent is considering buying a new circular track for his model train. He estimates that the model's circumference is about 3 times the measure of the circle's diameter. With this information, Brent could derive the value of OT O length O width area Previous Next > No new data to save. Last checked at 9:51am Submit​

Answer:

4

Step-by-step explanation:

Function: y = 5 sin (2(x))+ 12

Find y-intercept:

y = 5 sin 2(0)+ 12

y = 12

​[tex]\sf Y\:Intercepts}:\:\left(0,\:12\right)[/tex]

→ Formula for maximum: M = A + |B|

Maximum:

12 + |5|

17

When y = 17

[tex]\rightarrow \sf 17 = 5 sin (2(x))+ 12[/tex]

[tex]\rightarrow \sf \sf 5 sin (2(x)) = 5[/tex]

[tex]\rightarrow \sf sin (2(x)) = 1[/tex]

[tex]\rightarrow \sf 2x = sin^{-1}(1)[/tex]

[tex]\rightarrow \sf 2x = 90^{\circ \:}, \ \ 450^{\circ \:}[/tex]

[tex]\rightarrow \sf x = 45^{\circ \:}, \ \ 225^{\circ \:}[/tex]

maximum: ( 45° , 17 ), (225° , 17), .....

==========================================================

→  Formula for minimum: m = A ‐ |B|

Minimum:

12 - |5|

7

When y = 7

[tex]\rightarrow \sf 7 = 5 sin (2(x))+ 12[/tex]

[tex]\rightarrow \sf 5 sin (2(x)) = -5[/tex]

[tex]\rightarrow \sf 2(x) = sin^{-1}(-1)[/tex]

[tex]\rightarrow \sf x = -45^{\circ \:} , \ \ 135^{\circ \:}[/tex]

minimum: ( -45°,7), (135°, 7), .....

Repeat the same process for finding more values on the x-axis, or just follow the trend of the curve from the points found and sketch the graph easily.

[tex]\sf Domain\:\left(-\infty \: < x < \infty )[/tex]

[tex]\sf Range : 7\le \:f\left(x\right)\le \:17[/tex]

Sketched below:

The total harvested area is 232 acres .

To determine the number of acres harvested, we simply have to divide the bushels of soybean by the crop yield.

Mathematically we can write it as,

The total land area = bushels of soybean / bushels per acre

Substituting the known values,

[tex]Total land area = 9396 / 40.5 = 232[/tex]

Therefore, 232 acres were harvested.

To learn more about the area visit:

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Answer:The total harvested area is 232 acres

Step-by-step explanation:

Answer:

The answer is (3).

Step-by-step explanation:

Ron and Harry have ages that are consecutive odd integers. The product of their ages is 783. So, the ron's age r is 27.

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

Ron and harry have ages that are consecutive odd integers. The product of their ages is 783.

r is younger

r + 2 = s

product is 783

783 = rs

s = r +2

783 = r(r+2)

So, the quadratic equation form

783 = r^2 + 2r

0 = r^2 + 2r -783

0 = (r -27)(r +29)

set to zero

r-27 = 0

r = 27

and

r + 29 = 0

r = -29

thus, The age of ron is 27 years old.

Learn more about quadratic equations;

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Answer:

please rate and mark as brainlest.

Step-by-step explanation:

(i) 1/20

(ii)

a.708.22

b.8635.4

c.147.392

please rate and mark as brainlest.

Answer:

2.23

Step-by-step explanation:

we get this by making the fraction a decimal and finding out the value of each section

x=37.5

if you need an explanation i can type it in the comments

Answer:

19 boxes, but only 18 of them will be completely full

Step-by-step explanation:

Divide 75 by 4 to see how many boxes you can completely fill. You get 18 and 3/4, so there will be 18 boxes of four muffins (completely full), and one box with 3 muffins in it.

Hopefully this helps - let me know if you have any questions!

Answer:

Answer is 138

Step-by-step explanation:

I took the test and it was 138

Answer:

Add 5 to both sides

Step-by-step explanation:

x-5=16

+5  +5

x=21

Answer:

Addition

Step-by-step explanation:

x - 5 = 16

x - 5 + 5 = 16 + 5

x = 21

Answer:

(2,11 2/3)  or (2,(35/3))

Step-by-step explanation:

5x-3y=-25

For x = 2:  

5(2)-3y=-25

10-3y=-25

-3y=-35

y = (35/3) or 11 2/3

(2,11 2/3)

Answer:

X = -2

Y= 5

You use:

5x-3(5)=-25

and

5(-2)-3y=-25

Answer:

10:48 pm will be your answer

The required values are :

[tex]\qquad \sf  \dashrightarrow \:x = 4[/tex]

and

[tex]\qquad \sf  \dashrightarrow \:y = 1[/tex]

Check the attachment for solution ~

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Answer:

C: 28 inches

Step-by-step explanation:

Perimeter is when you add the length of each sides together.

Answer:

c

Step-by-step explanation: Because to get the perimeter you need to add all the sides of the figure for example 9+9+5+5=28 :]

Answer:

The last one

Step-by-step explanation:

Look at A and A'

It moved 4 units to the right and 1 unit down

The same with B, B' and C, C'

Can you please show me what angle?

Answer:

To find the surface area of a cuboid, add the areas of all 6 faces.

Explanation:

There are many approaches you can take. Perhaps one of the easiest is to show the sides of the rhombus are all the same length. This can be done several ways. Here are a couple of them.

__

A square has degree 4 rotational symmetry, so will map to itself when rotated by any multiple of 90°. This means the midpoints of adjacent sides will map to themselves, and any segment joining the midpoints of adjacent sides will map to itself. When segments map to themselves, they are congruent, hence the four sides of EFGH are congruent, and the figure is a rhombus.

__

The sides of a square are the same length and all corner angles are right angles. Midpoints of the sides divide the sides into congruent parts, so all of the segments PF, FQ, QG, GR, and so on are congruent. This means all of the triangles PFE, QGF, RHG, and SEH are congruent by the LL postulate. Corresponding sides of congruent triangles are congruent, so the sides of EFGH are congruent, and the figure is a rhombus.

Answers:

5.) [tex]\displaystyle \pm{1\frac{2}{3}}[/tex]

4.) [tex]\displaystyle 2[/tex]

3.) [tex]\displaystyle \pm{1\frac{2}{3}}[/tex]

2.) [tex]\displaystyle 2[/tex]

1.) [tex]\displaystyle \pm{2}[/tex]

Step-by-step explanations:

5.) [tex]\displaystyle \frac{\sqrt{75}}{\sqrt{27}} \hookrightarrow \sqrt{2\frac{7}{9}} \hookrightarrow \frac{\pm{5\sqrt{3}}}{\pm{3\sqrt{3}}} \\ \\ \boxed{\pm{1\frac{2}{3}}}[/tex]

4.) [tex]\displaystyle \frac{\sqrt[5]{96}}{\sqrt[5]{3}} \hookrightarrow \sqrt[5]{32} \hookrightarrow \frac{2\sqrt[5]{3}}{\sqrt[5]{3}} \\ \\ \boxed{2}[/tex]

3.) [tex]\displaystyle \frac{\sqrt{125}}{\sqrt{45}} \hookrightarrow \sqrt{2\frac{7}{9}} \hookrightarrow \frac{\pm{5\sqrt{5}}}{\pm{3\sqrt{5}}} \\ \\ \boxed{\pm{1\frac{2}{3}}}[/tex]

2.) [tex]\displaystyle \frac{\sqrt[3]{24}}{\sqrt[3]{3}} \hookrightarrow \sqrt[3]{8} \hookrightarrow \frac{2\sqrt[3]{3}}{\sqrt[3]{3}} \\ \\ \boxed{2}[/tex]

1.) [tex]\displaystyle \frac{\sqrt{8}}{\sqrt{2}} \hookrightarrow \sqrt{4} \hookrightarrow \frac{\pm{2\sqrt{2}}}{\pm{\sqrt{2}}} \\ \\ \boxed{\pm{2}}[/tex]

I am joyous to assist you at any time.

Answer:

A

Step-by-step explanation:

The zeros are the roots or x-intercepts

They are located at coordinate points (0, 0) and (6, 0)

This means the answer is A

Hope it makes sense!

Answer:

A. x = 0 and x = 6

Step-by-step explanation:

So, the zeroes of a quadratic are the parts of it that touch the x-axis. When you find those parts, take their x value and you will get the zero.

So, in this parabola, it touches the x-axis at (0, 0) and (6, 0).

The x-values of these are 0 and 6, respectively.

Answer:

Step-by-step explanation:

2+4(4x49)=4+39(563x7)

2+4x196=4+39x3941

2+784=4+153699

786=153703

This equation is

not possible because

786≠153703

The approximate decimal value of tan(α) is -3.274, α intersects the unit circle at point (-0.292, 0.956)

A circle is the locus of a point such that its distance from a fixed point (center) is always constant.

A unit circle is a circle with a unit radius.

Given that:

The terminal side of angle α intersects the unit circle at point (-0.292, 0.956).

Hence:

tan(α) = (0.956 / -0.292) = -3.274

The approximate decimal value of tan(α) is -3.274, α intersects the unit circle at point (-0.292, 0.956)

Find out more on unit circle at: https://brainly.com/question/23989157

Because we know one point and an axis of symmetry, we know that the point (2, -7) must lie on the graph.

If a function has a line of symmetry at x = x₀, then we know that:

f(x₀ + x) = f(x₀ - x).

So we have symmetry around that line.

Then, if the line of symmetry is at x = 5 and we know that:

f(8) = f(5 + 3) = -7

We also must have:

f(2) = f(5 - 3) = -7

Then the point (2, - 7) must be on the graph.

If you want to learn more about symmetry you can read:

https://brainly.com/question/11408596

Answer:

A. 2086 yd²

Step-by-step explanation:

SA = 2lw + 2wh + 2lh
SA = 2*17*20 + 2*20*19 + 2*17*19
SA = 680 + 760 + 646
SA = 2086
Hope this helps :)

Answer:

D. 16 square cm

Step-by-step explanation:

To solve this problem, we will have to look at the Scale factor.

1 : 8 =  1 cm (in the scale drawing) = 8cm (in the real object)

Since the area of the scale drawing is 2 cm, the equation will be 2 x 8 = 16.

Therefore, 16 will be the area of the real object.

-kiniwih426

Answer:

C

Step-by-step explanation:

If we have 5 packages and each contains 80, we are basically doing 80+80+80+80+80 (5 TIMES) which is referred to as 80×5=400

Answer:

1 package contain 80 sheets of paper.

If there is 5 packages, there will be 'x' sheets of paper.

We replace the sheets of paper with 'x', because the value of x is unknown.

Now we set up the equation:

__________   _________ = _________, solve for x;

80/1 = x/5

*5        *5

400 = x

Answer:

They have more resources and yeah they just do

Step-by-step explanation:

I have no clue why im just guessing

Answer:

[tex]\sf \dfrac{x}{8}-22[/tex]

Explanation:

[tex]\rightarrow \sf \left(\dfrac{7}{8}x-4\right)-3\left(\dfrac{1}{4}x+6\right)[/tex]

remove parenthesis

[tex]\sf \rightarrow \dfrac{7}{8}x-4-\dfrac{3x}{4}-18[/tex]

expand

[tex]\rightarrow \sf \dfrac{7x}{8}-\dfrac{3x}{4}-22[/tex]

simplify

[tex]\rightarrow \sf \dfrac{x}{8}-22[/tex]

Answer:

[tex]\frac18x-22[/tex]

Step-by-step explanation:

Given expression:

[tex](\frac78x-4)-3(\frac14x+6)[/tex]

Expand:

[tex]\implies \frac78x-4-\frac34x-18[/tex]

Gather like terms:

[tex]\implies \frac78x-\frac34x-4-18[/tex]

Change 3/4 into eighths:

[tex]\implies \frac78x-\frac68x-4-18[/tex]

Combine like terms:

[tex]\implies \frac18x-22[/tex]