Answer:
it,s is so many people do you want to go then
you are not study then stage change of it
The volume of a gas is 3.0 L, the pressure is 1.0 atm, and the temperature is 300 K. A chemist changes one factor while keeping another constant so that the new volume is 2.0 L. Which of the following could be the new conditions?
Group of answer choices
The final pressure is 0.5 atm, while temperature is kept constant.
The final temperature is 200 K, while pressure remains constant.
The final pressure is 0.2 atm, while temperature is kept constant.
The final temperature is 350 K, while pressure remains constant.
Given the data from the question, the final temperature is 200 K, while pressure remains constant.
Basic conceptsTo obtain the correct answer to the question, we shall consider two conditions:
Case 1 (temperature is constant) Case 2 (pressure is constant) Case 1 (Temperature is constant)We shall determine the new pressure by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:
Initial volume (V₁) = 3 LInitial pressure (P₁) = 1 atmTemperature = constant New Volume (V₂) = 2 L New pressure (P₂) =?P₁V₁ / T₁ = P₂V₂ / T₂
Since temperature is constant, we have:
P₁V₁ = P₂V₂
3 × 1 = P₂ × 2
3 = P₂ × 2
Divide both side by 2
P₂ = 3 / 2
P₂ = 1.5 atm
Case 2 ( pressure is constant)We shall determine the new temperature by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:
Initial volume (V₁) = 3 LInitial pressure (T₁) = 300 KPressure = constant New Volume (V₂) = 2 L New pressure (T₂) =?P₁V₁ / T₁ = P₂V₂ / T₂
Since pressure is constant, we have:
V₁ / T₁ = V₂ / T₂
3 / 300 = 2 / T₂
1 / 100 = 2 / T₂
Cross multiply
T₂ = 100 × 2
T₂ = 200 K
SUMMARY
when the temperature is constant, the new pressure is 1.5 atmWhen the pressure is constant, the new temperature is 200 KFrom the calculations made above, we can conclude that the correct answer is:
The final temperature is 200 K, while pressure remains constant.
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Answer:
b
Explanation:
explain how sound is produced and travel from one place to another.
Answer:
vibration of particles...........
Which would lower the reaction rate?
A. Increasing the concentration of reactants.
B. Increasing the temperature of the system.
C. Raising the value of k.
D. Decreasing the temperature of the system.
Answer:
D. Decreasing the temperature of the system
Explanation:
A buffer was prepared containing 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). The Ka of formic acid is 1.7 x 10-4. What will be the pH after 0.010 mol of NaOH(s) is added to 100.0 mL of the buffer
For a buffer that was prepared contain 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). the pH is mathematically given as
pH=3.95
What is the pH after 0.010 mol of NaOH(s) is added to 100.0 mL of the buffer?Generally, the equation for the Hendersons equation is mathematically given as
pH=pKa+log(SALT)/(ACID)
Where
moles of (NaCOOH)=100*0.05/1000
moles of (NaCOOH)=0.05moles
and formic acid
moles of formic acid=100*0.05/1000
moles of formic acid=0.05moles
Therefore
pKa=-logka
pKa=1.4*10*3.77
pH=3.77+log{0.06/0.04}
pH=3.95
In conclusion, the pH is
pH=3.95
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Which of the following mainly drives surface runoff?
A. magnetism
B. gravity
C. electricity
D. thermal energy
Identify the independent /manipulated variable
Answer:
independent- test variable
manipulated - outcome variable; if needed, there could be changes.
Explanation:
knowledge
(Squirrels gather and store acorns for the winter, which is an example of a ___________ adaptation.)
A. Mimicry
B. Behavioral
C. Structural
D. Environmental
Answer:
C
Explanation:
9. Using the balanced equation from Question #8, how many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to the correct number of significant figures and you must show all work in the form of dimensional analysis as shown in Lesson 4. (Hint: be sure to work the problem with both PbS and O2).
Answer: 2.24 grams of Pb
Explanation:
Step 1
Balanced chemical reaction;
2PbS + 3O2 → 2Pb + 2SO3
Step 2
Moles of both PbS and O2
Moles = mass / molar mass
Moles of PbS = 2.54 g / 239.3 g/mol = 0.0108 moles
Moles of O2 = 1.88 / 32 g/mol = 0.0588 moles
Step 3
Finding the limiting reactant.
Limiting reactant, is that reactant which is completely used in the reaction;
If we assume that PbS is the limiting reactant;
We have 0.0588 moles of O2. This needs ( 0.0588 * 2) / 3 = 0.0392 moles of PbS to fully react. But we have only 0.0108 moles of PbS available. That means that the PbS will be completely consumed hence the limiting reactant
If we assume O2 is the limiting reactant;
We have 0.0108 moles of PbS. That needs ( 0.0108 * 3) / 2 = 0.0162 moles of O2. But we have 0.0588 moles of O2 which is in excess further confirming that PbS is the limiting reactant since it will be depleted in the reaction.
Step 4
Moles of lead
For this step we apply the mole ratios with the limiting reactant;
Mole ratio of PbS : Pb = 2 : 2 = 1 : 1
Therefore;
Moles of Pb = (0.0108 moles * 1 ) 1
Moles of Pb =0.0108 moles
Step 5
Mass of Pb
Mass = moles * molar mass
Mass of Pb =0.0108 moles * 207.2 g/mol
Mass of Pb = 2.24 grams
73.5 mol of P4O10 contains how many moles of P ? moles of P:
Answer:
294 moles of P
Explanation:
For every 1 mol of P4O10 contains 4 mol of P
so;
73.5 mol P4O10 × 4 mol P
1 mol P4O10
= 73.5 × 4
= 294 moles of P
73.5 mol of [tex]P_4O_{10}[/tex] contains 294 moles of P. In 1 mole of [tex]P_4O_{10}[/tex], there are 4 moles of P.
The International System of Units (SI) uses the mole (abbreviated as mol) as its basic unit to measure the amount of a substance. It is mostly used in chemistry and is defined as the volume of a substance that contains exactly 12 grammes of pure carbon-12 in terms of atoms (or equivalent amounts of molecules, ions, or particles). The fundamental notion that atoms combine in whole-number ratios to form compounds serves as the foundation for the concept of the mole. It makes it simple for scientists to convert between a substance's mass and the quantity of atoms or molecules it contains.
In 1 mole of [tex]P_4O_{10}[/tex], there are 4 moles of P.
=4 × 73.5 moles of P.
= 294 moles of P
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When a sodium atom becomes an ion, the size of the atom
A
decreases by losing an electron,
B
decreases by gaining an electron,
с
increases by losing an electron,
D
increases by gaining an electron,
the ability of atoms to attract electrons from surrounding atoms is called
Answer:
Electronegativity
Explanation:
The ability of an atom to attract itself an electron pair shared with another atom in a chemical bond.
If 1.76 g of an ideal gas occupy 1.0 L at standard temperature and pressure (STP), what is the molar mass of the gas?
Answer:
Explanation:
Whenever you see molar masses in gas law questions, more often than not density will be involved. This question is no different. To solve this, however, we will first need to play with the combined ideal gas equation PV=nRT to make it work for density and molar mass. The derivation is simple but for the sake of time and space, I will skip it. Hence, just take my word for it that you will end up with the equation:M=dRTPM = molar mass (g/mol)d = density (g/L)R = Ideal Gas Constant (≈0.0821atm⋅Lmol⋅K) T = Temperature (In Kelvin) P = Pressure (atm)As an aside, note that because calculations with this equation involve molar mass, this is the only variation of the ideal gas law in which the identity of the gas plays a role in your calculations. Just something to take note of. Back to the problem: Now, looking back at what we're given, we will need to make some unit conversions to ensure everything matches the dimensions required by the equation:T=35oC+273.15= 308.15 KV=300mL⋅1000mL1L= 0.300 LP=789mmHg⋅1atm760mmHg= 1.038 atmSo, we have almost everything we need to simply plug into the equation. The last thing we need is density. How do we find density? Notice we're given the mass of the sample (0.622 g). All we need to do is divide this by volume, and we have density:d=0.622g0.300L= 2.073 g/LNow, we can plug in everything. When you punch the numbers into your calculator, however, make sure you use the stored values you got from the actual conversions, and not the rounded ones. This will help you ensure accuracy.M=dRTP=(2.073)(0.0821)(308.15)1.038= 51 g/molRounded to 2 significant figuresNow if you were asked to identify which element this is based on your calculation, your best bet would probably be Vandium (molar mass 50.94 g/mol). Hope that helped :)
What is molarity of 47.0 g KCl dissolved in enough water to give 375 mL of solution?
This question provides us –
Weight of [tex] \bf KCl [/tex] is = 47 gVolume, V = 375 mL__________________________________________
Molar Mass of [tex]\bf KCl [/tex] –[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf 39.0983 \times 35.453 [/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf 74.5513[/tex]
Using formula –
[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ W\times 1000}{MV}}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ 47 \times 1000}{74.5513\times 375}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{47000}{27956.7375}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \cancel{\dfrac{47000}{27956.7375}}[/tex]
[tex]\qquad[/tex] [tex] \twoheadrightarrow\bf Molarity _{(Solution)} = 1.68117M [/tex]
[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf Molarity _{(Solution)} = 1.7M} [/tex]
Henceforth, Molarity of the solution is = 1.7M___________________________________________
write an equation to show the effect of heat on the nitrate of silver
Answer:
2AgNO³(l) → 2Ag(s) + O²(g) + 2NO²(g)
Explanation:
I used powers ³,²,²
So change them to be down
2. The gas from an erupting volcano had the following composition: 494 torr CO₂, 0.054 atm HCI, 0.028 atm HF, 0.017 atm 50₂. 0.76 mmHg H₂5, and H₂. If the total pressure is 1.00 atm, what is the partial pressure of H₂?
3. When a 10L balloon is heated from 22.0°C to 97.0°C, to what volume does it inflate?
4. Calculate the pressure of a gas in a 205 mL container at 0.0°C when the container was initially at a volume of 300.0 mL and a pressure of 1.05 atm
Answer: The gas from an erupting volcano had the following composition: 494 torr CO₂, 0.054 atm HCI, 0.028 atm HF, 0.017 atm 50₂. 0.76 mmHg H₂5, and H₂. If the total pressure is 1.00 atm, what is the partial pressure of H₂?
Explanation:
Determine the molar solubility of BaF2 in a solution containing 0.0550 M LIF. Ksp (BaF2) = 2.45 x 10^-5
Answer:
8.1*10^-3 or 0.00809917
Explanation:
Step 1: Identify the common ion
LiF and BaF2 both share the ion F^- therefore we can interchange the molarity of LiF for F.
Step 2: Set up a balanced equation
BaF2---Ba2+ + 2F
Step 3: Set up a solubility ice table
initial- Ba^2+: 0 2F: 0.0550
change- S 2F: S^2(exponent is result of coefficient)
Step 4: Set up Ksp equation
2.45*10^-5=[S][S]^2
Step 5: Plug in values
2.45*10^-5=[S][0.0550]^2
S=8.1*10^-3
A 25 L tank of oxygen under a pressure of.80 atm would require what pressure to
decrease the volume to 1.0 L?
Answer:
20 atm
Explanation:
Use the equation P1 x V1 = P2 x V2.
1) Rearrange the equation with algebra to solve for P2.
P2 = (P1 x V1)/ V2
2) Plug in to the equation where V1 = 25L, P1 = 0.80 atm, and, V2 = 1 L
P2 = (25L x 0.80 atm)/ 1L
3) Solve: P2 = 20 atm
The pressure required to reduce the oxygen's volume to 1 L would be 20 atm.
Which color object would be the hottest? A violet object, a red object or a green object? Why?
Answer:
A Violet object
Explanation:
An Violet object attracts the heat after white objects, followed by orange, yellow, green, blue, indigo and violet, which attracts the most heat of any visible color other than black.
What type of reaction is 2NaBr+Cl2-NaCl+Br2
Answer:
An anionic single replacement reaction.
Explanation:
Hope this helps!!!
Answer:
Substitution or Displacement maybe?
0.75 mol hydrogen sulfide (H2S)
Answer:
• Information and media literacy
Directions
Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write
brief evaluation of your work.
Activity
Part A
Now that you have analyzed the resources provided in the lesson, write your own response to the question, What is the main reason the US Civil
War started? Base your
Explanation:
• Information and media literacy
Directions
Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write
brief evaluation of your work.
Activity
Part A
Now that you have analyzed the resources provided in the lesson, write your own response to the question, What is the main reason the US Civil
War started? Base your
Answer: =378.94000053g
Explanation:
I think that explains it
Why do we have to decide what to do in a day?
Answer:
otherwise you will be bord and have nothing to do
Explanation:
one revolution of the moon around earth takes_______ days.
Answer:It’s important to know WHY. Great explanations are what makes Brainly awesomeExplain everything. Imagine that the person who was asking, knows nothing at all so you need to start from the very beginningAlways include the steps and/or background required to get to the final answer. Let’s help other people understand and solve future problems on their ownShow all the calculation if it is a numerical question.
Explanation:
how many grams of lead II chloride are produced from the reaction of 15.3 g of NaCl and 60.8 gr of Pb(NO3)2?
The mass, in grams, of lead that will be produced from the illustrated reaction would be 71.47 grams
Stoichiometric reactionsFrom the balanced equation of the reaction:
Pb(NO3)2 + 2NaCl ---> PbCl2 + 2NaNo3
Mole ratio of Pb(NO3)2 and NaCl = 1:2
Mole of 15.3 g NaCl = 15.3/58.4
= 0.257 moles
Mole of 60.8 g PbCl(NO3)2 = 60.8/331.2
= 0.184 moles
Thus, NaCl is limiting.
Mole ratio of NaCl to PbCl2 = 1:1
Mas of 0.257 moles PbCl2 = 0.257 x 278.1
= 71.47 grams
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Oxidation Number of Carbon in C6H12O6
Correct option is C)
C
6
H
12
O
6
6x+12−12=0
C has oxidation number = 0
Sorry if my answers wrong.
An atom with more electrons than protons has an overall positive charge and is called a
positive ion
That is correct! It is a positive ion!
A compound is 69.9% Fe and 30.1% O. What is the empirical formula?
Answer:
Fe2O3
Explanation:
get the ratio for both Fe and O using relative atomic mass and the percent as the mass
What type of molecule is cis-2-pentene?
O A. Alkane
B. Alkyne
C. Branched alkane
D. Alkene
The given molecule, cis-2-pentene, is an Alkene. The correct option is D. Alkene
Saturated & Unsaturated HydrocarbonsAlkanes, Alkenes, and Alkynes are examples of simple hydrocarbons.
Alkanes are the simplest organic compounds. They have only single bonds between carbon atoms and are called saturated hydrocarbons. Their nomenclature usually ends in -ane.Alkenes on the other hand have at least one carbon-carbon double bond. Their nomenclature usually ends in -ene. Alkynes have one or more carbon-carbon triple bonds.Their nomenclature usually ends in -yne. Alkenes and alkynes are called as unsaturated hydrocarbons.The given molecule is cis-2-pentene
Since the name of the molecule ends in "ene", the molecule is an Alkene.
Hence, the given molecule, cis-2-pentene, is an Alkene. The correct option is D. Alkene
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Answer: Alkene
Explanation: just took tha test
how do the parts of the liverworts above the soil get the minerals from the soil that are needed for plant processes
Answer:
I don't know but I'm curious now
Which of the following represents the velocity of a moving object?
Select one:
40 m north.
40.
40 m/s north.
40 m/s.
Answer:
The correct answer would be 40 m/s
Explanation:
The reason 40 m/s is the correct answer is because m/s stands for meters per second.
Hope this helps you with what you're working on! :D
Answer:
40 m/s north
Explanation:
Velocity is a vector quantity, so it have both direction and magnitude.
A 0.205 g sample of CaCO3 (Mr = 100.1 g/mol) is added to a flask along with 7.50 mL of 2.00 M HCl. CaCO3(aq) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)Enough water is then added to make a 125.0 mL solution.
The volume of the NaOH used is calculated as 14 mL.
What is stoichiometry?The term stoichiometry has to do with the calculation of the amount of substance in a reaction using mass - mole or mass - volume relationship.
Here;
Number of moles of CaCO3 = 0.205 g/100.1 = 0.00205 moles
Number of moles of HCl = 2.00 M * 7/1000 L = 0.014 moles
2 moles of HCl reacts with 1 mole of CaCO3
x moles of HCl reacts with 0.00205 moles of CaCO3
x = 0.00205 moles * 2/1 = 0.0041 moles
Hence HCl is the excess reactant
Amount of excess HCl = 0.014 moles - 0.0041 moles = 0.0099 moles
Concentration of excess HCl reacted = 0.0099 moles/125 * 10^-3 = 0.0792 M
Using;
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
VB = CAVANB/CBNA
VB = 0.0792 M * 10 mL * 1/ 0.058 M
VB = 14 mL
Missing parts;
A 0.205 g sample of caco3 (mr = 100.1 g/mol) is added to a flask along with 7.50 ml of 2.00 m hcl. caco3(aq) + 2hcl(aq) → cacl2(aq) + h2o(l) + co2(g) enough water is then added to make a 125.0 ml solution. a 10.00 ml aliquot of this solution is taken and titrated with 0.058 m naoh. naoh(aq) + hcl(aq) → h2o(l) + nacl(aq) how many ml of naoh are used?
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