Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and find the proportion of presidents who were taller than their opponents. Use that result to construct a​ 95% confidence interval estimate of the population percentage. Based on the​ result, does it appear that greater height is an advantage for presidential​ candidates? Why or why​ not?

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Answer 1

Complete Question

The data for this question is shown on the first uploaded image

Answer:

The 95% confidence interval estimate of the population percentage is  

   [tex] 33.2\% <  p < 76.8 \% [/tex]

Step-by-step explanation:

On the data the first value is the height of the president while the other value is the height of his opponent

    The sample size is  n  =  20  

Looking at the data we see that out of the 20  presidents that only 11 is taller than their opponent

 So the proportion of presidents that are taller than their opponents is  

      [tex]\^ p = \frac{11}{20}[/tex]  

=>   [tex]\^ p = 0.55[/tex]

From the question we are told the confidence level is  95% , hence the level of significance is    

      [tex]\alpha = (100 - 95 ) \%[/tex]

=>   [tex]\alpha = 0.05[/tex]

Generally from the normal distribution table the critical value  of   is  

   [tex]Z_{\frac{\alpha }{2} } =  1.96[/tex]

Generally the margin of error is mathematically represented as  

   [tex]E = Z_{\frac{\alpha }{2} } *  \sqrt{\frac{\^ p (1- \^ p) }{n}} [/tex]

  [tex]E = 1.96 *  \sqrt{\frac{0.55 (1- 0.55) }{20}} [/tex]

   [tex]E = 0.218[/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\r p -E <  p <  \r p +E[/tex]

=>    [tex]0.55-0.218 <  p < 0.55+ 0.218 [/tex]

=>    [tex]0.332 <  p < 0.768 [/tex]

Converting to percentage

        [tex](0.332*100)\% <  p < (0.768 *100) \% [/tex]

=>    [tex] 33.2\% <  p < 76.8 \% [/tex]

Refer To The Data Set Of 20 Randomly Selected Presidents Given Below. Treat The Data As A Sample And

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Step-by-step explanation:

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