A chemical property of isopropanol : D. Isopropanol is flammable.
Further explanationThere are changes that occur in the mater: physical changes and chemical changes
Classification uses the principle of the initial and final state of the substance.
Physical changes do not form new substances, so the properties of the particles remain the same.(size,volume,shape)
Example : boiling and freezing, just change its phase form from liquid to gas or from liquid to solid
Chemical changes/reaction form new substances(products) that are different from the initial substances(reactants)
Example : toxic, corroded
So :
the physical properties of isopropanol :mass, density, evaporation
the chemical properties of isopropanol :highly flammable
Answer:
D. Isopropanol is flammable.
Explanation:
Mass, volume, temperature, phase of matter, color, texture, density, and hardness are all examples of physical properties. However, flammability is an example of a chemical property.
Chemical properties describe an object's potential to change its chemical composition. These properties depend on the types of atoms found in the object and the arrangement of those atoms (and their subatomic particles).
what is atomic radius
Explanation:
The atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons. Since the boundary is not a well-defined physical entity, there are various non-equivalent definitions of atomic radius. Three widely used definitions of atomic radius are: Van der Waals radius, ionic radius, and covalent radius
Which statement desrcribes an intensive property of matter? -it is the same for every sample of a single substance -it depends on how a substance was formed -it is the same for every sample of every substances -it depends on the amount of substances present
Answer:
The statement which describes an intensive property of matter is - :
it is the same for every sample of a single substance.
Explanation:
It is the same for every sample of a single substance. -: Since a substance 's intense property does not depend on either mass or volume, it is the same for each sample of a single substance. Hence , this statement is correct .It depends on how a substance was formed -: Intensive property do not depend upon the amount of the substance or the formation of the sample . Therefore this statement ifs wrong about intensive property .It is the same for every sample of every substances -: This is not possible to be for every sample of the substance , a every substance have different qualities. Hence this statement is also incorrect.it depends on the amount of substances present -: This is the characteristic of a extensive property of matter that relies on the amount of the material/substance. This assertion is, therefore, not valid.Hence , the correct option is A (it is the same for every sample of a single substance).
Is burning the glass plate is physical or chemical change?
6. Now, revise your definition for waves to include energy and matter.
A wave is a phenomenon that...
Answer:
A wave is phenomenon that transfers energy from one point to another through a disturbance without affecting the matter.
Explanation:
A wave is phenomenon that transfers energy from one point to another through a disturbance without affecting the matter.
There are two main types of waves Longitudinal waves travels parallel to their source. For example, sound waves. Through a series of rarefactions and compressions, longitudinal waves are propagated. Transverse waves travel perpendicular to their source.What is Chlorofluorocarbons?
Answer:
Chlorofluorocarbons and hydrochlorofluorocarbons are fully or partly halogenated paraffin hydrocarbons that contain only carbon, hydrogen, chlorine, and fluorine, produced as volatile derivative of methane, ethane, and propane. They are also commonly known by the DuPont brand name Freon.
Explanation:
Answer:
Explanation: Chlorofluorocarbons and hydrochlorofluorocarbons are fully or partly halogenated paraffin hydrocarbons that contain only carbon, hydrogen, chlorine, and fluorine, produced as volatile derivative of methane, ethane, and propane. They are also commonly known by the DuPont brand name Freon
hope that helps.↑Identify the heterogeneous mixtures.
Group of answer choices
salad
water
vegetable soup
apple juice
trail mix
brass
A cube of metal has a mass of 5.05 x 10°g and its density is known to be 12.77 g/mL, what is the volume of this metal?
A 395.5 mL
B. 2.529 mL
C. 63,910 mL
D. 64.48 ml
Answer:
Explanation:
option A is correct
Two compounds of phosphorus and fluorine have the following
mass ratios.
Compound 1: 10.14 g fluorine for every 3.38 g phosphorus
Compound 2: 8.42 g fluorine for every 4.21 g phosphorus
Find the whole number ratio of masses of fluorine in compound
1 to compound 2.
Help me please
Answer: 3:2
Explanation: (10.14÷3.38)÷(8.42÷4.21)=1.5=3/2
The
force acting on an object is the combination of
all of the individual forces acting on it.
Check it
2 SCRATCHPAD
~ Improve this questio
Answer:
Yes as you can improve The invisible to human eye force or physical force if any being applied to a object of any mass and with all individual forces as they are acting on this object
Explanation:
Scientists have changed the model of the atom as they have gathered new evidence. One of the atomic models is shown below. A purple center outlined in black with two concentric black circles around the center, the inner circle having 2 small green balls on it and the outer circle having 8 small green balls on it. What experimental evidence led scientists to change from the previous model to this one? A few of the positive particles aimed at a gold foil seemed to bounce back. The colors of light emitted from heated atoms had very specific energies. Experiments with water vapor showed that elements combine in specific proportions. Cathode rays were bent in the same way whenever a magnet was brought near them.
Answer:
B: The colors of light emitted from heated atoms had very specific energies.
Explanation:
dont know if its the same question i had on edg but i think its B. Sorry if i didnt understand the question :)
Answer:
b
Explanation:
HELP!! URGENT ASAP!! WILL GIVE BRAINLIEST TO FASTEST ANSWER!!
Answer:
This shoes the soda lime defusing to limewater turning into germinating seeding which defuses back to limewater
Explanation:
How many carbon atoms are there in 2.23 grams of propane (C3H8)?
Answer:
3.05x10²³ (3 sig. fig.)
Explanation:
Propane (C₃H₈) is a colorless alkane gas with three carbons and eight hydrogen atoms. In 2.23 grams of propane, there are 3.05 x 10²³ carbon atoms present.
What is the number of particles/atoms?
The number of atoms or the particles being the smallest units is estimated by the product of the number of moles and Avogadro's number.
The Avogadro's number (Na) is used to determine the number of particles that have been present in a mole of a substance. A mole of a substance is said to have 6.022 × 10²³ ions, atoms, electrons, molecules, etc.
Moles of propane are calculated as,
Moles = mass ÷ molar mass
= 2.23 ÷ 440.094
= 0.05057
Now, the number of particles is calculated as,
Number = moles × Avogadro's number
= 0.05057 × 6.022 × 10²³
= 3.05 x 10²³
Therefore, 3.05 x 10²³ carbon atoms are present in 2.23 grams of propane.
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how many picoliters are in 3.16 mL
Answer:
3.16×10⁹ pL
Explanation:
Given data:
Volume in mL = 3.16
Volume in picoliters = ?
Solution:
Picoliter and milliliters are units of volume. Milliliter is greater unit than picoliter.
1 mL = 10⁹ pL
Now we will convert the 3.16 mL into pL.
3.16 mL × 10⁹ pL/ 1 mL
3.16×10⁹ pL
Please help!!!
When 38 g of a metal at 92 °C is added to
43 g of water at 22°C, the temperature of the
water rises to 30°C. What is the specific heat
capacity of the metal? Assume no heat was
lost to the surroundings.
Answer in units of
J/g degrees C
The specific heat capacity of the metal : 0.610 J/g° C
Further explanationThe law of conservation of energy can be applied to heat changes, i.e. the heat received/absorbed is the same as the heat released
Q abs = Q received
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
∆T = T(final temp) - T(initial temp)
mass of metal = 38 g
T initial metal = 92 °C
mass of water = 43 g
T final water = 30 °C
T initial water = 22°C
c water = 4.18 J/g° C
Heat absorbed by water[tex]\tt Q=m.c.\Delta T\\\\Q=43\times 4.18\times (30-22^oC)\\\\Q=1437.92~J[/tex]
the specific heat capacity of the metalQ water = Q metal
[tex]\tt 1437.92=38\times c\times (92-30)\\\\c=0.610~J/g^oC[/tex]
how does litmus indicator work
The first chemists, philosophers like, Aristotle were from which country?
Answer:
greece
Explanation:
aristole was particularly from stagria, greece. but most early philosophers are from greece
Which of the following is true about metals?
A. They are usually less reflective in luster than metalloids.
B.
They are usually better conductors than nonmetals.
C. They are usually less malleable than nonmetals.
D.
They are usually more brittle than metalloids.
After lab, all of Darrel's friends looked at his data and laughed and laughed. They told him that he was 30.8% too low in the boiling point he had just recorded. He had recorded a boiling point of 50o C on his data sheet. What is the correct boiling point of the liquid he was working with in lab?
Answer:
100°
Explanation:
For a boiling point is it always 100°
explanation of atomic radius
Ah yes.
The atomic radius is basically the distance between the nucleus of the atom and the outermost electron in the farthest orbital of the atom. The more bigger the atomic radius , the less powerful is the force that holds together the nucleus and its electrons.
What is the name of this ionic compound (Fr2SO4)
Answer:
3.5: Ionic Compounds- Formulas and Names
Last updatedAug 25, 2020
3.4: An Atomic-Level Perspective of Elements and Compounds
3.6: Molecular Compounds- Formulas and Names
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6.9: Binary Ionic Compounds and Their Properties
6.18: Ionic Compounds Containing Polyatomic Ions
Learning Objectives
Derive names for common types of inorganic compounds using a systematic approach
Nomenclature, a collection of rules for naming things, is important in science and in many other situations. This module describes an approach that is used to name simple ionic and molecular compounds, such as NaCl, CaCO3, and N2O4. The simplest of these are binary compounds, those containing only two elements, but we will also consider how to name ionic compounds containing polyatomic ions, and one specific, very important class of compounds known as acids (subsequent chapters in this text will focus on these compounds in great detail). We will limit our attention here to inorganic compounds, compounds that are composed principally of elements other than carbon, and will follow the nomenclature guidelines proposed by IUPAC. The rules for organic compounds, in which carbon is the principle element, will be treated in a later chapter on organic chemistry.
Ionic Compounds
To name an inorganic compound, we need to consider the answers to several questions. First, is the compound ionic or molecular? If the compound is ionic, does the metal form ions of only one type (fixed charge) or more than one type (variable charge)? Are the ions monatomic or polyatomic? If the compound is molecular, does it contain hydrogen? If so, does it also contain oxygen? From the answers we derive, we place the compound in an appropriate category and then name it accordingly.
Compounds Containing Only Monatomic Ions
The name of a binary compound containing monatomic ions consists of the name of the cation (the name of the metal) followed by the name of the anion (the name of the nonmetallic element with its ending replaced by the suffix –ide). Some examples are given in Table 3.5.2 .
Table 3.5.1 : Names of Some Ionic Compounds
NaCl, sodium chloride Na2O, sodium oxide
KBr, potassium bromide CdS, cadmium sulfide
CaI2, calcium iodide Mg3N2, magnesium nitride
CsF, cesium fluoride Ca3P2, calcium phosphide
LiCl, lithium chloride Al4C3, aluminum carbide
Compounds Containing Polyatomic Ions
Compounds containing polyatomic ions are named similarly to those containing only monatomic ions, except there is no need to change to an –ide ending, since the suffix is already present in the name of the anion. Examples are shown in Table 3.5.2 .
Table 3.5.2 : Names of Some Polyatomic Ionic Compounds
KC2H3O2, potassium acetate (NH4)Cl, ammonium chloride
NaHCO3, sodium bicarbonate CaSO4, calcium sulfate
Al2(CO3)3, aluminum carbonate Mg3(PO4)2, magnesium phosphate
Ionic Compounds in Your Cabinets
Ionic Compound Use
NaCl, sodium chloride ordinary table salt
KI, potassium iodide added to “iodized” salt for thyroid health
NaF, sodium fluoride ingredient in toothpaste
NaHCO3, sodium bicarbonate baking soda; used in cooking (and as antacid)
Na2CO3, sodium carbonate washing soda; used in cleaning agents
NaOCl, sodium hypochlorite active ingredient in household bleach
CaCO3 calcium carbonate ingredient in antacids
Mg(OH)2, magnesium hydroxide ingredient in antacids
Al(OH)3, aluminum hydroxide ingredient in antacids
NaOH, sodium hydroxide lye; used as drain cleaner
K3PO4, potassium phosphate food additive (many purposes)
MgSO4, magnesium sulfate added to purified water
Na2HPO4, sodium hydrogen phosphate anti-caking agent; used in powdered products
Na2SO3, sodium sulfite preservative
Table 3.5.3 : Names of Some Transition Metal Ionic Compounds
Transition Metal Ionic Compound Name
FeCl3 iron(III) chloride
Hg2O mercury(I) oxide
HgO mercury(II) oxide
Cu3(PO4)2 copper(II) phosphate
Naming Ionic Compounds
Name the following ionic compounds, which contain a metal that can have more than one ionic charge:
Fe2S3
CuSe
GaN
CrCl3
Ti2(SO4)3
Solution
The anions in these compounds have a fixed negative charge (S2−, Se2− , N3−, Cl−, and SO2−4 ), and the compounds must be neutral. Because the total number of positive charges in each compound must equal the total number of negative charges, the positive ions must be Fe3+, Cu2+, Ga3+, Cr4+, and Ti3+. These charges are used in the names of the metal ions:
iron(III) sulfide
copper(II) selenide
gallium(III) nitride
chromium(III) chloride
titanium(III) sulfate
Exercise 3.5.1
Write the formulas of the following ionic compounds:
(a) chromium(III) phosphide
(b) mercury(II) sulfide
(c) manganese(II) phosphate
(d) copper(I) oxide
(e) chromium(VI) fluoride
Answer
(a) CrP; (b) HgS; (c) Mn3(PO4)2; (d) Cu2O; (e) CrF6
Explanation:
The given compound is francium sulfate.
Explanation:
While naming ionic compounds :
First, write the name of cation Then after that name of the anion.Given
The molecule formula of a compound[tex]Fr_2SO_4[/tex]:
To find:
The name of the given compound formula
Solution:
Cation in formula = [tex]Fr^+[/tex] = Francium cation
Anion in the formula= [tex]SO_4^{-2}[/tex] = Sulfate anion
So, the name of the given compound is francium sulfate.
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Synthesis
1 point
Balance the following chemical equation. What are the final coefficients
starting from the left and going to the right? *
AICI:
+
H2O
_Al(OH)3 +
НСІ
1,1,1,1
1, 2, 1, 2
2, 2, 2, 2.
1,3,1,3
Answer:
nãosecoi m fazoe isrspoo rqe a perugtunat iomkplnetacá
Explanationveja qeuastã onvamoetn e depois recoepe-a qui aipis onãestoácpletoma :
348 g of water starting at 4.0°Celsius is heated until his temperature is 37°Celsius. Calculate the amount of heat energy needed to cause this rise in temperature
STEP BY STEP EXPLANATION!!
Answer:
48.049 kJ or 48049 J
Explanation:
Hello again.
So we know the formula [tex]q = mc\Delta t[/tex]. c is the heat capacity but this time, it is not given. However, water has a very well known heat capacity which is 4.184 J/(g°C). This is in fact the number we refer to a calorie which is the amount of energy you burn that can raise the temperature of 1g of water by 1°C. So, plugging in values, you get the above. But double check if I am wrong.
The amount of heat energy needed to cause this rise in temperature is 48.049 kJ or 48049 J.
What is heat energy?Heat is the energy that moves from one body to another when temperatures are different. Heat passes from the hotter to the colder body when two bodies with different temperatures are brought together.
A given amount of matter's heat capacity is the amount of energy needed to raise its temperature by one degree Celsius.
The heat energy will be calculated by the formula
Q = m•C•ΔT
Where c is the heat capacity.
The m is the mass
T is the time
Mass is 348 grams
Temperature is 37°C
The change in temperature is 4.0°C to 37°C
The heat capacity of water is 4.184
Q = 348 x 4.184 x -33 = 48049.056.
Therefore, the amount of heat energy needed is 48.049 kJ or 48049 J.
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Name for each compoud
1.CO
2.H2SO4
3CaCO3
4 H202
5NaF
Identify the reaction type shown and describe the clues that were used to identify it.
Fe2O3 + 2SiO2 → Fe2Si2O7
50 POINTS: PLEASE ANSWER AS QUICK AS POSSIBLE!
Question:
After getting their results in, a group of scientists went back and looked at their study. As planned, their experiment consisted of three groups. The first group received a new medicine at a normal dose, the second group received the medicine at half the dose, and the third group received the medicine at twice the dose.
Which of the following best describes what went wrong with the scientists’ study?
Choices:
- an improper experimental procedure
- the lack of a control group
- selection bias
- human error
Explanation:
The lack of a control group
Which pair of symbols represents nuclei with the same number of neutrons?
A. 56 Co and 580
B. 57Co and 58Ni
c. 57Fe and 58 Ni
D. 57Mn and 57Fe
Answer:
B
Explanation:
Mass number = number of neutrons + number of protons
Atomic number is the number of protons in the nucleus.
58Ni : 58 is the number of neutrons + number of protons
atomic number of Ni is 28. Thus, 58 -28 = 30 neutrons
57Co ; 57 is the number of neutrons + number of protons
number of Co is 27. Thus, 57 – 27 = 30 neutrons
How many electrons are there in the only energy level of helium, a noble gas? * Two Three Six Eight
Answer:
Explanation:
Noble gases are the least reactive of all known elements. That's because with eight valence electrons, their outer energy levels are full. The only exception is helium, which has just two electrons.
How to separate these pure substance?if it is not possible, please write cannot be separate
Oxgen
Water
Gold
Carbon Dioxide
Carbon
Answer:
Oxgen- cannot be separated
Water - chemical change
Gold - cannot be separated
Carbon Dioxide - chemical change
Carbon - cannot be separated
Explanation:
A pure substance, which can either be an element or a compound, contains only one type of such element or compound. In opposition to a mixture, pure substances cannot be separated by physical means.
- Elements as a pure substance cannot be separated because it contains only one type of atom. However, compounds contain two or more types of atoms, and hence, can only be separated into its individual atoms via chemical means.
In this question, oxygen (O2), Gold (Au) and carbon (C) are all elements and hence cannot be separated. Carbon dioxide (CO2) and water (H2O) are compounds because they contain two different atoms respectively, hence, can be separated into individual atoms.
Do 2. A student determines that there are 1.3 x 1025 molecules of an unknown
substance in a 968 g sample. Which compound most likely represents this
unknown substance?
CO
CIO
2)
CO2
N203
CLEAR ALL
Answer:
The correct option is;
CO₂
Explanation:
The given information are;
The number of molecules in the substance = 1.3 × 10²⁵
The mass of the substance = 968 g
Therefore, we have;
The number of molecules in one mole of a substance = 6.02 × 10²³
The number of moles present = (1.3 × 10²⁵)/(6.02 × 10²³) ≈ 21.595 moles
Therefore, 968 g = 21.595 moles
1 mole = 968/21.595 = 44.826 g
The mass of one mole of the substance = 44.826 g
Therefore the mass of one mole of the substance is closely related to the mass of one mole of CO₂ which is 44.01 g/mol.
The correct option is CO₂
The calculation is as follows:The number of molecules in one mole of a substance should be = 6.02 × 10²³
And,
The number of moles present is
= (1.3 × 10²⁵)/(6.02 × 10²³)
≈ 21.595 moles
Now
1 mole = 968/21.595 = 44.826 g
The mass of one mole of the substance = 44.826 g
So, the mass of one mole of the substance is closely related to the mass of one mole of CO₂ i.e. 44.01 g/mol.
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The diagram shows a model of an animal cell. Explain how you'd modify the model to show the structures in a plant cell.
Answer:to show the structures of a plant cell,add a cell wall around the membrane and increase the size of the vaculoe insidethe cell, draw green ovals to represent chloroplasts.
Explanation: