Answer: B $2,251.80
Step-by-step explanation:
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in a congressional district, 55% of the registered voters are democrats. which of the following is equivalent to the probability of getting less than 50% democrats in a random sample of size 100?
A. P( z< 50 — 55/ 100 )
B. P( z< 50 — 55/ √55(45)/100)
C. P( z< 55 — 5 / √55(45)/100)
D. P( z< 50 — 55/√100(55) (45))
The correct answer to the question, "Which of the following is equivalent to the probability of getting less than 50% democrats in a random sample of size 100?" is: B. P( z < 50 — 55/ √55(45)/100).
To find the probability, we first calculate the z-score using the formula:
z = (x - μ) / σ
where x is the value (50%), μ is the mean (55%), and σ is the standard deviation.
The standard deviation can be calculated as:
σ = √(np(1-p))
where n is the sample size (100) and p is the proportion of democrats (0.55).
Now, plug in the values into the z-score formula:
z = (50 - 55) / √(100 * 0.55 * 0.45)
The probability is then found as P(z < z-score), which is represented by the option B.
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after a (not very successful) trick or treating round, candice has 12 tootsie rolls and 10 twizzlers in her pillow case. her mother asks her to share the loot with her three younger brothers. (a) how many different ways can she do this?
Using the stars and bars technique, Candice can distribute her 24 pieces of candy among her four siblings in 2,925 different ways. If she must give each sibling at least one of each type of candy, there are 67,200 ways to distribute the candy among the four siblings.
(A) To solve this problem, we can use the technique of stars and bars. We have a total of 24 pieces of candy to share among four children. We can represent this using 24 stars, with 3 bars to separate the stars into four groups, one for each child. For example, the following arrangement represents giving 6 pieces of candy to the first child, 10 pieces to the second child, 3 pieces to the third child, and 5 pieces to the fourth child:
*****|**********|***|****
The number of ways to arrange the stars and bars is equal to the number of ways to choose 3 positions out of the 27 possible positions for the stars and bars. Therefore, the number of different ways that Candice can share her candy with her three younger brothers is:
C(27, 3) = 27! / (3! * 24!) = 2925
(B) Now, we need to ensure that each child receives at least one Tootsie roll and one Twizzler. We can give each child one of each candy to start, and then distribute the remaining 13 Tootsie rolls and 7 Twizzlers using the stars and bars technique. We have 13 Tootsie rolls and 7 Twizzlers to distribute among four children, which can be represented using 13 stars and 3 bars for the Tootsie rolls, and 7 stars and 3 bars for the Twizzlers. The number of ways to arrange the stars and bars for each type of candy is:
C(16, 3) = 560 for the Tootsie rolls
C(10, 3) = 120 for the Twizzlers
To find the total number of ways to distribute the candy, we can multiply the number of ways for each type of candy:
560 * 120 = 67200
Therefore, there are 67,200 different ways for Candice to share her candy with her three younger brothers after her mother asks her to give at least one of each type of candies to each of her brothers.
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Complete question:
After a (not very successful) trick or treating round, Candice has 15 Tootsie rolls and 9 Twizzlers in her pillow case. Her mother asks her to share some of the loot with her three younger brothers.
(A) How many different ways can she do this?
(B) How many different ways can she do this after her Mother asks her to give at least one of each type of candies to each of her brothers?
the 98.4% confidence interval for snapdragons grown in compost is (20.91, 38.43). what is the margin of error of this confidence interval?
The margin of error of the 98.4% confidence interval for snapdragons is 3.71.
The midpoint of the range is calculated by adding the upper and lower bounds and then dividing by two. So, the sample mean is `(20.91 + 38.43) / 2 = 29.67`.
The margin of error is calculated by multiplying the critical value of z* (1.96 for a 98.4% confidence level) by the standard error of the mean. The formula for calculating the margin of error is:
`Margin of error z*(standard deviation/√n`).
The formula is `range/4 = 1.96 * standard deviation/√n`.Now, solve for the standard deviation:
`standard deviation = (range/4) * √n / 1.96`
Substituting the values: `(38.43 - 20.91)/4 = 1.96 * standard deviation/√n`
Simplifying the equation: `4.26 = (1.96*standard deviation)/√n`
Squaring both sides: `4.26^2 = 3.8416 = (1.96^2 * standard deviation^2)/n`
Substituting the value of the standard deviation: `3.8416 = (1.96^2 * ((38.43 - 20.91)/4)^2) / n`
Solving for n: `n = ((1.96^2 * ((38.43 - 20.91)/4)^2) / 3.8416) = 31.54`
Now that we know the sample size, we can calculate the standard error of the mean:
`standard error = standard deviation/√n = ((38.43 - 20.91)/4)/√31.54 = 1.89`.
The margin of error is `1.96 * 1.89 = 3.71`.
The 98.4% confidence interval for snapdragons grown in compost is (20.91, 38.43). The margin of error of this confidence interval is 3.71.
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what is the probability that a customer purchases biography book given that they purchase cooking and bobvilla books? round your answer to two decimal places.
The probability that a customer purchases a biography book given that they purchase cooking and BobVilla books is 0.08.
To calculate this probability, we need to consider the following components:
1. The total number of customers purchasing cooking and BobVilla books: This is the denominator of our equation, and it represents the total number of customers who purchased the two books.
2. The number of customers purchasing the biography book: This is the numerator of our equation, and it represents the number of customers who purchased the biography book.
3. The probability that a customer purchases a biography book given that they purchase cooking and BobVilla books: This is the fraction of customers who purchased the biography book over the total number of customers who purchased the two books.
To calculate the probability that a customer purchases a biography book given that they purchase cooking and BobVilla books, we need to divide the numerator (the number of customers purchasing the biography book) by the denominator (the total number of customers purchasing the two books).
This probability can be expressed as a decimal, which is 0.08. This value can also be rounded to two decimal places, which is 0.08.
In conclusion, the probability that a customer purchases a biography book given that they purchase cooking and BobVilla books is 0.08.
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