Sasha's SUV has a 17-gallon gas tank. The SUV gets an estimated 24 miles per gallon.

Approximately how many miles can the SUV run on half a tank of gas?

Answer: The answer is seventeen

Step-by-step explanation:

i just answered this question

93.06% of the race is longer than 236 minutes.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

[tex]z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean,\sigma=standard\ deviation[/tex]

Given that μ = 310, σ = 50

For x > 236:

[tex]z=\frac{236-310}{50}=-1.48[/tex]

From the normal distribution table:

P(x > 236) = P(z > -1.48) = 1 - P(z < -1.48) = 1 - 0.0694 = 0.9306 =  93.06%

93.06% of the race is longer than 236 minutes.

Find out more on z score at: https://brainly.com/question/25638875

Answer:

a. Write an equation that represents the amount of cleaner in the tank after x minutes

y= -4x + 128

b. How much cleaner is in the tank when the cleaning begins?

128

c. After how many minutes is the tank empty?

The tank is empty in 32 minutes

Answer:

12/13

Sine is opposite over hypotenuse. The opposite side of U is 12 and the hypotenuse is 13, so the answer is 12/13

Answer: 25 units squared

Step-by-step explanation:

1) A square has 4 equal sides.

2) The area of a square is length x width.

3) Therefore, 5x5 = 25 units squared (area is always reported in units squared).

Answer:

Step-by-step explanation:

A + B = 90

A/6(15.25) = 3B/4

61A/18 = B

18A/18 + 61A/18 = 90

A = 90(18)/79

A = 20 40/79°

B = 90 -A = 69 39/79°

Answer:

I think its 86

Step-by-step explanation:

As the two lines going in the same direction are parallel and angles within parallel lines add to 180.

so 180-94=86

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A.  ​Yes, using the additional survey information from part​ (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which z is the z-score that has a p-value of [tex]\frac{1+\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so [tex]z = 1.96[/tex].

For this problem, we consider that we want it to be within 4%.

Item a:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}[/tex]

[tex]0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}[/tex]

[tex]\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2[/tex]

[tex]n = 600.25[/tex]

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is [tex]\pi = 0.96[/tex], hence:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}[/tex]

[tex]0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}[/tex]

[tex]\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2[/tex]

[tex]n = 92.2[/tex]

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to [tex]\pi = 0.5[/tex], the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151  

Answer:

(7,10)

Step-by-step explanation:

The x coordinate is the first coordinate, it is how far you go across

X = 7

The next coordinate is the y coordinate, it is how for you go up or down

y = 10

(7,10)

Answer:

Add 2/3

Step-by-step explanation:

2/3 + 2/3 = 4/3 + 2/3 = 6/3 (or 2) + 2/3 = 8/3 +2/3 = 10/3