Select three expressions equivalent to 28xy + 16x.

Select Three Expressions Equivalent To 28xy + 16x.

Answers

Answer 1

Answer:

B,C,D

Step-by-step explanation:

Answer 2

Answer:

number 2

number 3

number 4

Step-by-step explanation:


Related Questions

three machines, a, b, c produce a large number of identical products. 60% of the products come from machine a, 30% from b and 10% from c. historical records indicate that 10% of the parts produced by machine a are defective, compared with 30% for machine b and 40% for machine c. what is the probability that a randomly chosen part is defective?

Answers

The probability that a randomly chosen part is defective is 0.16, or 16%.

The probability that a randomly chosen part is defective, we need to use the law of total probability.

Let [tex]$D$[/tex] be the event that a part is defective and let [tex]$M_i$[/tex] be the event that the part came from machine [tex]$i$[/tex], for [tex]$i = A, B, C$[/tex].

Then we have:

[tex]$P(D) = P(D|M_A)P(M_A) + P(D|M_B)P(M_B) + P(D|M_C)P(M_C)$[/tex]

60% of the products come from machine A, 30% from machine B, and 10% from machine C.

Therefore:

[tex]$P(M_A) = 0.6$[/tex]

[tex]$P(M_B) = 0.3$[/tex]

[tex]$P(M_C) = 0.1$[/tex]

The probability of a part being defective is 10% if it comes from machine A, 30% if it comes from machine B, and 40% if it comes from machine C.

Therefore:

[tex]$P(D|M_A) = 0.1$[/tex]

[tex]$P(D|M_B) = 0.3$[/tex]

[tex]$P(D|M_C) = 0.4$[/tex]

Substituting these values into the law of total probability, we get:

[tex]$P(D) = 0.1 \cdot 0.6 + 0.3 \cdot 0.3 + 0.4 \cdot 0.1 = 0.16$[/tex]

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A car travels 3 miles in 5 minutes. A subway train travels 4 miles in 6 minutes. How much longer does it take to travel 7 miles in the slower vehicle

Answers

The slower vehicle is the car, and it would take (11.67 - 10.5) = 1.17 minutes longer to travel 7 miles compared to the subway train.

To find out how much longer it would take to travel 7 miles in the slower vehicle, we need to calculate the speed of

each vehicle first.

The car travels 3 miles in 5 minutes, which means it travels at a speed of 3/5 miles per minute.

The subway train travels 4 miles in 6 minutes, which means it travels at a speed of 4/6 miles per minute. Simplifying

this, we get a speed of 2/3 miles per minute.

Now, we can calculate how long it would take each vehicle to travel 7 miles:

The car travels at a speed of 3/5 miles per minute, so it would take (7 / (3/5)) = 11.67 minutes to travel 7 miles.

The subway train travels at a speed of 2/3 miles per minute, so it would take (7 / (2/3)) = 10.5 minutes to travel 7 miles.

Therefore, the slower vehicle is the car, and it would take (11.67 - 10.5) = 1.17 minutes longer to travel 7 miles compared to the subway train.

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from his house, duncan could drive due north to get to his parents' house or he could drive due east to get to his grandparents' house. it is 6 kilometers from duncan's house to his parents' house and a straight-line distance of 9 kilometers from his parents' house to his grandparents' house. how far is duncan from his grandparents' house? if necessary, round to the nearest tenth.

Answers

Duncan is approximately 10.8 kilometers away from his grandparents' house, if necessary, rounding to the nearest tenth.

Based on the given information, we can use the Pythagorean theorem to find the distance between Duncan's house and his grandparents' house. The theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In this case, the distance from Duncan's house to his parents' house (6 km) and the distance from his parents' house to his grandparents' house (9 km) form the two shorter sides of the triangle. To find the distance between Duncan's house and his grandparents' house, we will calculate the hypotenuse:
h² = 6² + 9²
h² = 36 + 81
h² = 117
h ≈ 10.8

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Duncan is approximately 6.7 km from his grandparents' house (rounded to the nearest tenth).

We can use the Pythagorean theorem to find the distance between Duncan's house and his grandparents' house.
Identify the triangle
In this problem, we have a right triangle with legs of 6 km (due north) and an unknown length (due east).

The hypotenuse is the straight-line distance of 9 km from his parents' house to his grandparents' house.
Apply the Pythagorean theorem.
The Pythagorean theorem states that a² + b² = c², where a and b are the legs of the triangle, and c is the hypotenuse. In this case, a = 6 km, b = unknown, and c = 9 km.
Solve for the unknown distance (b)
6² + b² = 9²
36 + b² = 81
b² = 81 - 36
b² = 45
b = √45
b ≈ 6.7 km.

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the in song the twelve days of christmas, my true love gave to me first 1 gift, then 2 gifts and 1 gift, then 3 gifts, 2 gifts and 1 gift, and so on. how many gifts did my true love give me all together during the twelve days?

Answers

In a song the twelve days of christmas, my true love gave to me, then total number of possible gifts that my true love give me all together during the twelve days is equal to the 364.

We have There are twelve days of Christmas in a song and my true love gives me presents every day. We have to calculate total number of gifts my true love give me all together during the twelve days. Now, according to the song, on the first day of Christmas my true love gave me: a partridge on a pear tree 1 gift. On the second day of Christmas, my love really gave me: two doves and a gift. cake etc. Mathematically, gifts by true love are written as 1+2+3+... n gifts per day. Number of gifts per day: 1 to 1, 2 to 3, 3 to 6 and 4 to 10. The amount of mis N (N + 1) (N + 2) / 6. Number of parts This form is called tetrahedral number. Change the value N = 12, then N (N + 1) (N + 2) / 6

= 12 × 13 × 14 / 6

= 364

Hence, 364, the total number of gifts, almost one for each day of the year.

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find the missing value of x,y and z

Answers

Answer:

x=60

y=30

z=64

Step-by-step explanation:

By using triangle sum theorem, 84+36+x=180

You then isolate the variable, resulting in x=60

x and y are complementary, therefore, x+y=90

Since x is already known, y must be isolated, resulting in 60+y=90 then y=30

By using triangle sum theorem, 86+y+z=180

Since y is already known, z must be isolated, resulting in 86+30+z=180 then z=64

What is the length of XW and what is the length of WV?

Answers

The value of length XW and WV are 20 and 25 respectively.

What are similar triangles?

Similar triangles are triangles that have the same shape, but their sizes may vary. The ratio of corresponding sides of similar triangles are equal.

Therefore XW/VW = XY/XZ

= XW/45 = 24/54

54(XW) = 45× 24

54(XW) = 1080

divide both sides by 54

XW = 1080/54

XW = 20

Therefore WV can be found by subtracting XW for VX

= 45-20 = 25

therefore the value of XW and WV are 20 and 25 respectively.

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A circular garden is surrounded by a fence that is 47. 1 feet long. The surface soil Of the entire garden within the fencing needs to be turned prior to planting. Calculate the square feet of soil that must be turned. Use 3. 14 as a substitute for a. Show your work

Answers

The required square feet of soil that must be turned in the circular garden is 176.625 square feet.

A circular garden is surrounded by a fence that is 47.1 feet long.

That is, circumference of a circle = 2 π r = 2(3.14) r = 6.28r (in feet)

where,  r represents the radius of the circular garden in feet.

Thus,

6.28r = 47.1

r=7.5 feet

Area of the circular garden is measured by the formula as,

= π r^2  square unit

= (3.14)( 7.5^2) square feet  

= 176.625 square feet

Hence, the required square feet of soil that must be turned in the circular garden is 176.625 square feet.

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HELP PLS EXPLAIN THISSSSS

Answers

Plugging in the values given into the expression, and simplifying, we would have our answer as: B.  [tex]\frac{9}{25}[/tex]

How to Evaluate an Expression?To evaluate an expression, follow these steps:Identify the variables and constants in the expression.Substitute the given values for each variable in the expression.Simplify the expression until there are no more operations left.

Given that, a = 5 and k = -2, substitute the values into the expression given and simplify:

[tex](\frac{3^2(5^{-2})}{3(5^{-1})} )^{-2}[/tex]

Simplify:

[tex](\frac{9 * \frac{1}{25} }{3* \frac{1}{5} } )^{-2}[/tex]

[tex](\frac{\frac{9}{25} }{\frac{3}{5} } )^{-2}\\\\(\frac{9}{25} * \frac{5}{3} } )^{-2}\\\\(\frac{3}{5} )^{-2}\\\\ = \frac{9}{25}[/tex]

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What is the mode for the data set? 49, 47, 46, 40, 48, 41, 44, 49, 45, 42, 43

Answers

The mode of a data set is the value that appears most frequently. In the given data set, the value 49 appears twice, and all other values appear only once. Therefore, the mode for this data set is 49.

Answer:

49

Step-by-step explanation:

The mode is the number that appears most often in a set of data. In this case, 49 appears twice while all the other numbers only appear once.

carmen bought 3 cds that were each the same price. including sales tax, she paid a total of $49.50. each cd had a tax of 0.70 . what was the price of each cd before tax?

Answers

If Carmen paid a total of $49.50 for 3 CD's, then the price of each CD before the tax is $15.80.

The "Sales-Tax" is $0.70 per CD, which is added to the original price of each CD to arrive at the total cost of the CDs including sales tax

Let the price of each CD before tax be = "x",

Carmen bought 3 CDs, so the total cost of the CDs without tax would be 3x.

The "Sales-Tax" on each CD is $0.70, and Carmen bought 3 CDs,

The "total-sales" tax will be = 3 × $0.70 = $2.10,

So, the "total-cost" of the CDs including sales tax is "3x + $2.10", and

We know this total cost is = $49.50,

The equation to represent the cost is written as :

⇒ 3x + $2.10 = $49.50

Now, Solving for "x", the price of each CD before tax.

⇒ 3x = $49.50 - $2.10

⇒ 3x = $47.40

⇒ x = ($47.40)/3,

⇒ x ≈ $15.80

Therefore, the price of each CD is $15.80.

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bout 1.02 X 102 times farther away from the sun than Mercury.
out how many kilometers is Pluto from the sun?
about 5.91 X 1014 kilometers
about 4.77 X 10⁹ kilometers
about 5.91 X 10⁹ kilometers
about 5.68 x 105 kilometers
wa chose D as the correct answer. How did she get that answer?
Show work

Answers

If bout 1.02 X 102 times farther away from the sun than Mercury. The number of kilometers is: C. about 5.91 X 10⁹ kilometers.

How many kilometers is Pluto from the sun?

If Pluto is 1.02 x 10² times farther away from the Sun than Mercury, we can use the average distance of Mercury from the Sun, which is approximately 57.91 million km (5.791 x 10⁷ km) to calculate the distance of Pluto from the Sun.

Distance of Pluto from the Sun = (1.02 x 10²) x (57.91 x 10⁶ km)

Distance of Pluto from the Sun = 5.91 x 10⁹ km

Therefore, the correct option is: about 5.91 x 10⁹ kilometers.


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6. ____ tales and _____ tales
folk tales are storues with no known creator. they were originally passed down from one generation to another by word of mouth.

fairytales were often created to teach children behavior in an entertaining way.

what is the blank fictions/nonfictions?

Answers

The complete statement is folk tales and fairy tales

Both folk tales and fairy tales are types of fiction because they are imaginative stories that are not based on factual events or characters.

Explaining fictions and nonfictions?

Folk tales

Folk tales are stories with no known creator. They were originally passed down from one generation to another by word of mouth. Folk tales are a type of traditional literature that is deeply rooted in the culture of a particular region or community.

They often feature supernatural elements, and their origins can be traced back many centuries.

Because they were passed down orally, different versions of the same tale may have developed in different regions, with variations in characters, plot, and theme.

Fairy tales

Fairy tales were often created to teach children behavior in an entertaining way. Fairy tales are a type of story that typically features magical creatures or events and often have a moral or lesson to teach. They were originally intended for both adults and children and were used as a way to teach moral values, societal norms, and important life lessons in an entertaining way.

The fairy tale genre has evolved over time, and modern fairy tales may have different themes and messages than traditional ones.

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Circle A has radius AB and Circle X has radius XY. Points A and X are distinct points. Complete the statements below describing how to prove that the circles are similar.

Translate the center of circle A onto point __ __.

Then dilate the image of circle A about its center by a scale factor of __ __.

Answers

Translate the center of circle A onto point X.Then dilate the image of circle A about its center by a scale factor of XY/AB.

What is circle?

A circle is a geometric shape consisting of points in a plane that are equidistant from a fixed point called the center, forming a closed curve.

According to the given information :

To prove that circles A and X are similar, we can follow the steps below:

1) Translate the center of circle A onto point X. This can be done by moving the center of circle A to point X while keeping the radius AB the same.

2) Dilate the image of circle A about its center by a scale factor of XY/AB. This means that we multiply the radius of the image of circle A by XY/AB.  The result is a new circle that is similar to circle A and has the same center as circle X.

To summarize, the statements to complete are:

Translate the center of circle A onto point X.

Then dilate the image of circle A about its cent er by a scale factor of XY/AB.

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Translate the center of circle A onto point X.Then dilate the image of circle A about its center by a scale factor of XY/AB.

What is circle?

A circle is a geometric shape consisting of points in a plane that are equidistant from a fixed point called the center, forming a closed curve.

According to the given information :

To prove that circles A and X are similar, we can follow the steps below:

1) Translate the center of circle A onto point X. This can be done by moving the center of circle A to point X while keeping the radius AB the same.

2) Dilate the image of circle A about its center by a scale factor of XY/AB. This means that we multiply the radius of the image of circle A by XY/AB.  The result is a new circle that is similar to circle A and has the same center as circle X.

To summarize, the statements to complete are:

Translate the center of circle A onto point X.

Then dilate the image of circle A about its center by a scale factor of XY/AB.

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As a nurse working in a hospital one of the jobs is to give appropriate doses of medicine
before surgery so the patient doesn't wake up during surgery. 4cc of this particular medicine is
meant for a 180lb man, what would be the correct dosage for a 145 lb. woman?

Answers

Answer:

the correct dosage of the medicine for a 145 lb. woman would be approximately 3.22 cc

Step-by-step explanation:

To calculate the correct dosage of the medicine for a 145 lb. woman, we can use the following formula:

dosage = (weight of patient / weight of reference patient) x reference dosage

where the weight of the reference patient is 180 lb. and the reference dosage is 4 cc.

Plugging in the given values, we get:

dosage = (145 / 180) x 4

      = 3.22 cc (rounded to two decimal places)

Therefore, the correct dosage of the medicine for a 145 lb. woman would be approximately 3.22 cc. However, it's important to note that dosages of medications should only be determined by a qualified medical professional based on a number of factors, including the patient's weight, medical history, and current condition.

was solving an equation, but when he checked his answer, he saw his solution was incorrect.
He knows he made a mistake, but he can't find it. Where is Diego's mistake and what is the solution to the equation?
- 4(7 - 2x) = 3(x + 4)
-28-8x = 3x + 12
- 28 = 11x + 12
- 40 = 11x
06
11
ーン

Answers

The solution to the equation is x = 16/11.

what is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas. It involves the study of variables, expressions, equations, and functions.

Diego's mistake is in the step where he subtracts 3x from both sides of the equation. The correct subtraction should be 28, not 12.

Here's the correct solution:

4(7 - 2x) = 3(x + 4)

28 - 8x = 3x + 12

28 - 12 = 3x + 8x

16 = 11x

x = 16/11

Therefore, the solution to the equation is x = 16/11.

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Eli's house is due west of Yardley and due south of Salem. Yardley is 7 miles from Eli's house and 9 miles from Salem. How far is Salem from Eli's house, measured in a straight line? If necessary, round to the nearest tenth

Answers

By Pythagorean , Eli's home is thus roughly **11.4 miles** from Salem when viewed from a straight line.

Define Pythagorean theorem?

A fundamental relationship between a right triangle's three sides in Euclidean geometry is known as the Pythagorean theorem. The hypotenuse is the side that forms the right angle, and the rule says that the square of its length is equal to the sum of the squares of the lengths of the other two sides. In other words, if the hypotenuse is length c and the legs of a right triangle are lengths a and b, then a²+ b² = c² .

Call Yardley Y, Salem S, and Eli's home E. As far as we are aware, Y is located 7 miles from E and 9 miles from S.

We can check that the distance between Eli's house and Salem is the hypotenuse of a right triangle with Yardley as one of the vertices because Eli's house is located due west of Yardley and due south of Salem. The Pythagorean theorem can be used to determine this distance.

Eli's home is 11.4 miles from Salem at a distance of√(7 + 9 ) = √(130).

√(130) = 11.4miles

Eli's home is thus roughly **11.4 miles** from Salem when viewed from a straight line.

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the starting sales price of a new car on monticello car lot is normally distributed with a mean of $40,000 and a standard deviation of $5,000. what is the probability that a randomly selected individual will buy a car that costs at least $30,000?

Answers

The chance that a randomly selected individual will buy a car that charges at the least $30,000 is 0.9772, or approximately 97.72%.

To clear up this problem, we need to discover the probability that a randomly selected person will purchase a vehicle that prices as a minimum $30,000, given that the starting income rate of a new automobile on the Monticello vehicle lot is usually dispensed with a mean of $forty,000 and a preferred deviation of $5,000.

We can use the same Standard normal distribution to solve this problem with the aid of changing the beginning sales price of $30,000 to a z-score, and then using a standard normal distribution table or calculator to discover the corresponding opportunity.

The z-rating for a starting sales rate of $30,000 is:

z = (30,000 - 40,000) / 5,000 = -2

Using a standard normal distribution table or calculator, we will locate that the opportunity of a z-score less than or identical to -2 is approximately zero.0228.

But, we need to find the possibility that the starting sales price is at the least $30,000, so we want to subtract this chance from 1:

P(X ≥ 30,000) = 1 - P(X < 30,000)

P(X ≥ 30,000) = 1 - 0.0228

P(X ≥ 30,000) = 0.9772

Therefore, the chance that a randomly selected individual will buy a car that charges at the least $30,000 is 0.9772, or approximately 97.72%.

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Determine the reduced exact values for the root of f(x) = x^2+10x-5

Answers

The  reduced exact values for the root of f(x) = x² + 10·x - 5, obtained using the quadratic formula are; x = (-5 + √(30)) and x = (-5 - √(30))

What is the quadratic formula?

The quadratic formula is a formula that is used to find the roots of a quadratic equation, by plugging in the coefficients of a quadratic equation into the formula.

The roots of the quadratic function, f(x) = x² + 10·x - 5, can be obtained using the quadratic formula as follows;

The quadratic formula, which can be used to find the roots of the quadratic function, f(x) = a·x² + b·x + c is; x = (-b ± √(b² - 4·a·c))/(2·a)

The function f(x) = x² + 10·x - 5, indicates;

a = 1, b = 10, and c = -5, therefore;

x = (-10 ± √(10² - 4 × 1 × (-5)))/(2 × 1) = (-10 ± √(120))/2

(-10 ± √(120))/2 = (-5 × 2 ± 2 × √(30))/2

(-5 × 2 ± 2 × √(30))/2 =  (-5 ± √(30))/2


The roots of the quadratic function are;

x = (-5 + √(30))/2, and x = (-5 - √(30))/2

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Solve the following problem. Be sure to show all the steps (V. E. S. T. ) and work in order to receive full credit.

The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the numbers. ​

Please help due tomorrow

Answers

The three numbers are 4, 8, and 14.

Let's use variables to represent the three numbers

Let x be the first number.

Then the second number is twice the first, so it is 2x.

The third number is 6 more than the second, so it is 2x + 6.

We know that the sum of the three numbers is 26, so we can write an equation:

x + 2x + (2x + 6) = 26

Now we can solve for x

5x + 6 = 26

5x = 20

x = 4

So the first number is 4.

To find the second number, we can use the equation we wrote earlier:

2x = 2(4) = 8

So the second number is 8.

To find the third number, we can use the other equation we wrote earlier

2x + 6 = 2(4) + 6 = 14

So the third number is 14.

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If r=0.5 m, A = ???
(Use the r key.)

Answers

The calculated value of the angular velocity of the object is 2 rad/s.

Calculating the angular velocity

The angular velocity, denoted by the Greek letter omega (ω), represents the rate of change of the angle with respect to time.

For an object moving in a circular path, the angular velocity is related to the linear speed and the radius of the circle by the equation:

ω = v/r

where v is the linear speed and r is the radius.

In this case, the radius is 0.5m and the speed is 1ms−1. Thus, the angular velocity is:

ω = v/r = 1/0.5 = 2 radians per second (rad/s)

Therefore, the angular velocity of the object is 2 rad/s.

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Complete question

An object moves in a circular path of radius 0.5m with a speed of 1ms−1. What is its angular velocity (A)?

If r = 0.5 m, A = ???

90%; n = 10; σ is unknown; population appears to be normally distributed

Answers

With 90% confidence, we can estimate that the true population mean lies between 13.96 and 16.04.

If the population appears to be normally distributed, and σ (population standard deviation) is unknown, we can use a t-distribution to calculate the confidence interval.

To find the confidence interval, we need to use the following formula

CI = X' ± t_(α/2, n-1) × (s/√n)

Where X' is the sample mean, t_(α/2, n-1) is the critical t-value based on the desired confidence level (α) and the sample size (n-1), s is the sample standard deviation, and √n is the square root of the sample size.

Given that we have a confidence level of 90%, α = 0.10, and we need to find the critical t-value for a two-tailed test with 10-1=9 degrees of freedom. Using a t-distribution table, we find that the critical t-value is approximately 1.833.

Assuming that we have a sample mean of X' = 15 and a sample standard deviation of s = 2, we can now calculate the confidence interval

CI = 15 ± 1.833 × (2/√10)

CI = 15 ± 1.04

CI = (13.96, 16.04)

Therefore, with 90% confidence, we can estimate that the true population mean lies between 13.96 and 16.04.

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Find the surface area and the volume of the cement block in the figure shown.

Answers

The surface area and volume of cement block is  1336 in² and 880 in³

What is Surface area of Cuboid ?

To find the total surface area of a cuboid, add the areas of all six faces. Suppose l, b and h be the length, breadth and height of a cuboid, then the total surface area will be 2(lb + bh + hl). The surface area of any given object is the area or region occupied by the surface of the object. Whereas volume is the amount of space available in an object.

Surface area of given cement block is = 10×8×2+20×10×2+(20×8 - 6×4×3)×2 + 4×10×2×3 +6×10×2×3

= 160 + 400 + 176 + 240 + 360

= 1336 in²

Volume of cement block is 20 × 8× 10 - 3×6×4×10

= 1600 - 720

= 880 in³

Hence, the surface area and volume of cement block is  1336 in² and 880 in³

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Carlos has 32 iris bulbs and 40 tulip bulbs to plant. He wants to plant them in rows with one
type of bulb in each row. He wants all of the rows to have the same number of bulbs.

Answers

Carlos can plant 8 bulbs in each row.

Given that, Carlos is having 32 iris bulbs and 40 tulip bulbs he wants to plant them, he chose to plant them in rows with alternate pattern, also wants all of the rows to have the same number of bulbs.

So, we need to find the number of the rows to have the same number of bulbs,

To find the same we will find the GCF of the two number,

GCF = The GCF is also known as the Highest Common Factor (HCF).

Find the GCF of 32, and 40

32 = 2 × 2 × 2 × 2 × 2

40 = 2 × 2 × 2 × 5

The greatest common factor = 2 × 2 × 2 = 8

Hence, he can plant 8 bulbs in each row.

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The data for the height and weight of different people was collected the line of best fit for this date it was determined to be Y equals 0. 9 1X -65. 5 where X is the height in centimeters and why is the weight in kilograms is in the equation predict the height of a person who weighs 63 kg

Answers

According to the equation, a person who weighs 63 kg is predicted to be approximately 141 centimeters tall.

The equation given is Y = 0.91X - 65.5, where X represents the height in centimeters and Y represents the weight in kilograms. To predict the height of a person who weighs 63 kg, we need to solve for X, the height in centimeters.

To do this, we can plug in the given weight of 63 kg for Y in the equation and then solve for X. So, we have:

63 = 0.91X - 65.5

Adding 65.5 to both sides, we get:

63 + 65.5 = 0.91X

Simplifying, we have:

128.5 = 0.91X

Finally, to solve for X, we divide both sides by 0.91, giving:

X = 141.21

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Given the following code fragment, which of the following expressions is always true?
int x;
scanf("%d", &x);
A) if( x = 1)
B) if( x < 3)
C) if( x == 1)
D) if((x/3) > 1)

Answers

If the expressions given, only C) if( x == 1) is always true.

In the given code fragment, the value of x is read from the user using the scanf() function. The value of x can be any integer value, depending on what the user enters. After the value of x is read, the program checks the value of x using a conditional statement (if statement) and executes the code inside the if statement only if the condition is true.

Expression A) if( x = 1) assigns the value 1 to x and then checks if x is true. This means that the condition is always true, because the assignment operation (=) returns the assigned value (in this case, 1), which is a non-zero value and therefore considered true in C programming.

Expression B) if( x < 3) checks if x is less than 3. This expression is not always true, as x can be any value greater than or equal to 3, in which case the condition would be false.

Expression C) if( x == 1) checks if x is equal to 1. This expression is always true if the user enters the value 1 for x.

Expression D) if((x/3) > 1) checks if the integer division of x by 3 is greater than 1. This expression is not always true, as x can be any value less than or equal to 3, in which case the result of the integer division by 3 would be 1 or less, in which case the condition would be false.

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the only expression that is always true in this code fragment is option C) if( x == 1).

The expression that is always true in this code fragment is option C) if( x == 1).

Option A) if( x = 1) is not always true because it is an assignment statement instead of a comparison statement. It assigns the value 1 to x instead of checking if x is equal to 1.

Option B) if( x < 3) is also not always true because x could be any number less than 3.

Option D) if((x/3) > 1) is not always true because x could be any number less than or equal to 3, in which case the expression would evaluate to false.

Therefore, the only expression that is always true in this code fragment is option C) if( x == 1).

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There are 10 councillors and 12 planning department staff available to serve on a committee to look into re- establishing two way traffic on the streets of St. Catharines. If the committee will consist of 3 councillors and either 1 or 2 planning staff, how many different committees could the council choose?

Answers

The council could choose 14,040 different committees.

To form a committee, we need to choose 3 councillors out of 10 and either 1 or 2 planning staff out of 12.

Number of ways to choose 3 councillors out of 10 = 10C3 = (1098)/(321) = 120

Number of ways to choose 1 planning staff out of 12 = 12C1 = 12

Number of ways to choose 2 planning staff out of 12 = 12C2 = (1211)/(21) = 66

Therefore, the total number of different committees that the council could choose is the sum of the number of ways to choose 3 councillors and either 1 or 2 planning staff:

Total number of committees = (Number of ways to choose 3 councillors) x (Number of ways to choose 1 planning staff) + (Number of ways to choose 3 councillors) x (Number of ways to choose 2 planning staff)

Total number of committees = 120 x 12 + 120 x 66

Total number of committees = 14,040

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For the first half of a baseball season, a player had 90 hits out of 270 times at bat. The player's batting average was
90
270
≈ 0. 333. During the second half of the season, the player had 64 hits out of 276 times at bat. The player's batting average was
64
276
≈ 0. 232. (Round your answers to three decimal places. )
(a) What is the average (mean) of 0. 333 and 0. 232?

Answers

The issue inquires to discover the normal (cruel) of two values:

0.333 and 0.232. To do this, able to essentially include the two values together and partition them by 2. Including the two values gives us:

0.333 + 0.232 = 0.565

Separating by 2 gives us:

0.565 / 2 = 0.2825

So the normal of 0.333 and 0.232 is 0.2825.

In any case, the issue inquires to circular our answer to three decimal places, which suggests we have to be circular 0.2825 to the closest thousandth. The third decimal put maybe a 2, which implies we circular down. Hence, the ultimate reply is roughly 0.283, adjusted to three decimal places.

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call a positive integer kinda-prime if it has a prime number of positive integer divisors. if there are $168$ prime numbers less than $1000$, how many kinda-prime positive integers are there less than $1000$?

Answers

There are 173 kinda-prime positive integer less than 1000.

To find the number of kinda-prime positive integer less than 1000, we'll follow these steps:

1. Understand the definition of a kinda-prime number: A positive integer is kinda-prime if it has a prime number of positive integer divisors.
2. Determine the number of prime numbers less than 1000: There are 168 prime numbers less than 1000, as given.
3. Determine the possible prime number of divisors: Since 168 is not too large, we only need to consider 2 and 3 as possible prime numbers of divisors for a kinda-prime number.
4. Analyze the cases:

Case 1: Kinda-prime numbers with 2 divisors (prime numbers)
All prime numbers have exactly 2 divisors (1 and itself). Thus, all 168 prime numbers less than 1000 are kinda-prime.

Case 2: Kinda-prime numbers with 3 divisors
Let N be a kinda-prime number with 3 divisors. Then, N = p^2 for some prime number p. To find the suitable prime numbers p, we need[tex]p^2 < 1000[/tex]. The prime numbers that meet this condition are 2, 3, 5, 7, and 11 (since 13^2 = 169 > 1000). Therefore, there are 5 additional kinda-prime numbers ([tex]2^2, 3^2, 5^2, 7^2, and 11^2[/tex]).

5. Add the total number of kinda-prime numbers from both cases: 168 + 5 = 173.

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[tex]$(\pi(1000)-1)+11=\boxed{177}$[/tex] "kind a-prime" positive integers less than $1000$.

Let [tex]$n$[/tex] be a positive integer with[tex]$k$[/tex] positive integer divisors.

If [tex]$k$[/tex] is prime, then.

[tex]$n$[/tex] is a "kind a-prime" integer.

[tex]$k$[/tex] must be of the form.

[tex]$k=p$[/tex] or [tex]$k=p^2$[/tex] for some prime [tex]$p$[/tex].

If [tex]$k=p$[/tex], then [tex]$n$[/tex] must be of the form.

[tex]$p^{p-1}$[/tex] for some prime [tex]$p$[/tex]. Since [tex]$p < 1000$[/tex], there are.

[tex]$\pi(1000)$[/tex]possible values of [tex]$p$[/tex].

[tex]$p=2$[/tex] gives [tex]$2^1$[/tex], which is not prime, so we have to subtract.

[tex]$1$[/tex] from [tex]$\pi(1000)$[/tex] to get the number of possible.

[tex]$p$[/tex].

[tex]$\pi(1000)-1$[/tex] values of [tex]$p$[/tex] that give a "kind a-prime" integer of this form.

If [tex]$k=p^2$[/tex], then [tex]$n$[/tex] must be of the form.

[tex]$p^{p^2-1}$[/tex] for some prime[tex]$p$[/tex].

There are.

[tex]$\pi(31)=11$[/tex] primes less than [tex]$31$[/tex], and each of them gives a different "kind a-prime" integer of this form.

Since [tex]$31^5 > 1000$[/tex], no primes larger than [tex]$31$[/tex]can be used to form a "kind a-prime" integer of this form.

[tex]$11$[/tex] possible values of [tex]$p$[/tex] that give a "kind a-prime" integer of this form.

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What is the slope of the line?

-2

-1

1

2

Answers

Answer: positive 2

Step-by-step explanation:

The answer to their question is positive 2

Please help Which of the following is equal to 2?

Answers

Answer:

The third equation is equal to 2.

Step-by-step explanation:

6 times one third is equal to 6 divided by three, which equals two. Using order of operations, 5 times 2 equals 10, and that divided by 5 is 2, so that equation is equal to 2.

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