Seth earns $25 a day and also she earns $3 for each ticket he sells at the local theatre.
Therefore $25 is the independent value and $3 is the dependent value because it depends on how many tickets are sold.
We can write the next expression:
[tex]25+3x[/tex]Now, we need to make an inequality about he must sell at least $115 in a day.
The word "at least" means greater than or equal to, therefore:
[tex]25+3x\ge115[/tex]Now, let's solve the inequality:
Subtract both sides by 25:
[tex]25-25+3x\ge115-25[/tex][tex]3x\ge90[/tex]Then, divide both sides by 3:
[tex]\frac{3x}{3}\ge\frac{90}{3}[/tex]Simplify:
[tex]x\ge30[/tex]Determine the missing coordinates in the ordered pair (-1,?) so that it will satisfy the given equation
we have the equation
2x-3y=4
Remember that
if the ordered pair is a solution of the given equation, then the ordered pair must satisfy the given equation
we have the ordered pair (-1,a)
substitute the given coordinates in the equation
2(-1)-3(a)=4
-2-3a=4
solve for a
3a=-2-4
3a=-6
a=-2
therefore
the missing coordinate is -2
Solve triangle EFG with the given parts.f = 17.78, F = 27.3°, G = 102.1°
STEP - BY - STEP EXPLANATION
What to find?
g, E and e
Given:
Step 1
Find the measure of side g using the sine ratio.
[tex]\begin{gathered} \frac{sinF}{f}=\frac{sinG}{g} \\ \\ \frac{sin27.3}{17.78}=\frac{sin102.1}{g} \\ \\ gsin27.3=17.78sin102.1 \\ \\ g=\frac{17.78sin102.1}{sin27.3} \\ \\ g\approx37.9 \end{gathered}[/tex]Step 2
Find angle E.
[tex]E+F+G=180(sum\text{ of interior angle in a triangle\rparen}[/tex][tex]\begin{gathered} E+27.3+102.1=180 \\ \\ E=180-102.1-27.3 \\ \\ E=50.6° \end{gathered}[/tex]Step 3
Find side e using the sine ratio.
[tex]\begin{gathered} \frac{sinE}{e}=\frac{sinF}{f} \\ \\ \frac{sin50.6}{e}=\frac{sin27.3}{17.78} \\ \\ esin27.3=17.78sin50.6 \\ \\ e=\frac{17.78sin50.6}{sin27.3} \\ \\ e\approx29.96 \end{gathered}[/tex]ANSWER
g=37.9
E=50.6°
e = 29.96
IF G and R denote the grade and the radian measure of an angle, then prove that G/200 = R/pie
Solution:
Given;
IF G and R denote the grade and the radian measure of an angle, i.e.
Where
[tex][/tex]I’m not firmiliar with the sun or difference of cubes (HW assignment)
Given:
[tex]125r^3-216[/tex]Find-: Factor using the formula of the sum or difference of cube.
Sol:
Factoring sum and differences of cubs is:
[tex]\begin{gathered} x^3-y^3=(x-y)(x^2+y^2+xy) \\ \\ x^3+y^3=(x+y)(x^2+y^2-xy) \end{gathered}[/tex]Apply for the given information.
[tex]\begin{gathered} =125r^3-216 \\ \\ =(5r)^3-(6)^3 \end{gathered}[/tex][tex]\begin{gathered} x^3-y^3=(x-y)(x^2+y^2+xy) \\ \\ (5r)^3-(6)^3=(5r-6)((5r)^2+(6)^2+(5r)(6)) \\ \\ =(5r-6)(25r^2+36+30r) \end{gathered}[/tex]What is the value of x in the proportion2 1/4 = 1 1/2_________x = 3 3/5A. 2 2/5B. 5 2/5C. 8 1/10D. 12 3/20
First, we transform the mixed fractions
[tex]\begin{gathered} 2\frac{1}{4}=2+\frac{1}{4}=\frac{8}{4}+\frac{1}{4}=\frac{9}{4} \\ 1\frac{1}{2}=1+\frac{1}{2}=\frac{2}{2}+\frac{1}{2}=\frac{3}{2} \\ 3\frac{3}{5}=3+\frac{3}{5}=\frac{15}{5}+\frac{3}{5}=\frac{18}{5} \end{gathered}[/tex]Then, we use cross multiplication
[tex]\begin{gathered} \frac{\frac{9}{4}}{x}=\frac{9}{4}\times\frac{1}{x}=\frac{9}{4x} \\ \frac{\frac{5}{2}}{\frac{18}{5}}=\frac{3}{2}\times\frac{5}{18}=\frac{15}{36} \end{gathered}[/tex]so, we have
[tex]\frac{9}{4x}=\frac{15}{36}[/tex]Finally, we solve for x, we multiply x on both sides
[tex]\begin{gathered} \frac{9}{4x}x=\frac{15}{36}x \\ \frac{15}{36}x=\frac{9}{4} \\ x=\frac{\frac{9}{4}}{\frac{15}{36}} \\ x=\frac{9}{4}\times\frac{36}{15} \\ x=\frac{9\times9\times4}{15\times4} \\ x=\frac{81}{15} \\ x=\frac{27}{5} \end{gathered}[/tex]Since 27/5 = 5+2/5.Then,
[tex]x=5\frac{2}{5}[/tex]Then the answer is the second one.
Given a regular octagon and a regular nonagon, which one has the greater interior angle?(Type your answer as the name of the polygon)
Answer:
Nonagon
Explanation:
Each of the interior angles of a polygon is calculated using the formula:
[tex]\frac{180^0\mleft(n-2\mright)}{n}[/tex]An Octagon has 8 sides, therefore:
[tex]\begin{gathered} Each\; \text{Interior Angle=}\frac{180^0(8-2)}{\square} \\ =\frac{180\times6}{8} \\ =\frac{1080^0}{8} \\ =135^0 \end{gathered}[/tex]A Nonagon has 9 sides, therefore:
[tex]\begin{gathered} Each\; I\text{nterior Angle=}\frac{180^0(9-2)}{9} \\ =\frac{180\times7}{9} \\ =\frac{1260^0}{9} \\ =140^0 \end{gathered}[/tex]Therefore, the nonagon has a greater interior angle.
use properties of operations to write an equivalent expression. will sand image
Use properties of operations to write equivalent expressions
WRITING EQUIVALENT EXPRESSIONS USING PROPERTIES
Commutative Property of Addition :
When adding, changing the order of the numbers does not change the sum. ...
Commutative Property of Multiplication : ...
Associative Property of Addition : ...
Associative Property of Multiplication : ...
Distributive Property :
2.8 w + 5.6
= 2.8 ( w + 2 ) ----------- OPTION B
Lisa played 42 of thepossible 60 minutes of asoccer game. Whatpercent did she notplay?
Lisa played 42 minutes of a 60 minutes match. This means that she didn't play 18 minutes of the game; to find what percent this represents we can use the rule of three:
[tex]\begin{gathered} 60\rightarrow100 \\ 18\rightarrow x \end{gathered}[/tex]Then:
[tex]\begin{gathered} x=\frac{18\cdot100}{60} \\ =30 \end{gathered}[/tex]Therefore, Lisa didn't play 30% of the game.
What’s the correct Answer answer asap for brainlist please
Answer:
A. accuracy
Step-by-step explanation:
precise means to be accurate
College students are offered a 6% discount on a textbook that sells for
$32.50. If the sales tax is 6%, find the cost of the textbook including the sales
tax.
32.383 is the cost of the textbook including the sales tax.
How does sales tax work?
Government-imposed consumption taxes on the purchase of goods and services are known as sales taxes. A typical sales tax is imposed at the moment of sale, paid for by the shop, and then given to the government.The original price of the textbook = $32.50
Also, the discount percentage = 6%
Thus, the price of the textbook after discount = 32.50 - 6 % of 32.50
= 32.50 - 6 * 3250/100
= 32.50 - 1.95
= 30.55
Now, the sales tax = 6 %
Hence, the cost of the textbook including sales tax
= 30.55 + 6 % of 30.55
= 30.55 + 6 * 30.55/100
= 30.55 + 1.833
= 32.383
Learn more about sales tax
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(If there is more than one answer, use the "or" button.)Round your answer(s) to the nearest hundredth.A ball is thrown from a height of 141 feet with an initial downward velocity of 21 ft/s. The ball's height h (in feet) after t seconds is given by the following.h = 141 - 21t - 16t ^ 2How long after the ball is thrown does it hit the ground?
Solution:
Given:
[tex]h=141-21t-16t^2[/tex]To get the time the ball hit the ground, it hits the ground when the height is zero.
Hence,
[tex]\begin{gathered} At\text{ h = 0;} \\ h=141-21t-16t^2 \\ 0=141-21t-16t^2 \\ 141-21t-16t^2=0 \\ 16t^2+21t-141=0 \end{gathered}[/tex]To solve for t, we use the quadratic formula.
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{where;} \\ a=16,b=21,c=-141 \\ t=\frac{-21\pm\sqrt[]{21^2-(4\times16\times-141)}}{2\times16} \\ t=\frac{-21\pm\sqrt[]{441+9024}}{32} \\ t=\frac{-21\pm\sqrt[]{9465}}{32} \\ t=\frac{-21\pm97.288}{32} \\ t_1=\frac{-21+97.288}{32}=\frac{76.288}{32}=2.384\approx2.38 \\ t_2=\frac{-21-97.288}{32}=\frac{-118.288}{32}=-3.6965\approx-3.70 \end{gathered}[/tex]
Since time can't be a negative value, we pick the positive value of t.
Therefore, to the nearest hundredth, it takes 2.38 seconds for the ball to hit the ground.
11) What is the area of the composite figure? *7 points6 ftT T2 ft5 ft3ft220O 212223
Answer: 22
Step-by-step explanation:
Riley read 1 book in 2 months. If she reads at a constant rate, how many books did she read in one month? Give your answer as a whole number or a FRACTION in simplest form.On the double number line below, fill in the given values, then use multiplication or division to find the missing value.
To find out the unit rate
Divide the total books by the total months
so
1/2=0.5 books per month
the answer is 0.5 books per monthIn the double number line
we have
books 0 0.5 1
months 0 1 2
Stephanie dilated the rectangle below and dimensions of the image were 24 ft by 6ft. What was the scale of the factor used?
In order to determne the scale factor, calculate the quotient in between the lengths of the sides of the rectangles, as follow:
32 ft/24 ft = 4/3
8 ft/ 6 ft = 4/3
Hence, the scale factor is 4/3
Just give me the answer please, my device is at 10%
Solve for x
We can use sine
[tex]\begin{gathered} \sin 48^0=\frac{x}{17} \\ \text{Cross multiply} \\ x=17\times\sin 48^0 \\ x\text{ =17}\times0.7431448 \\ x=12.6\text{ } \end{gathered}[/tex]Hi, I’m really confused with this question and I’m not sure how to solve it!
SOLUTION
The figure below would help in answering the question
Let's get the slopes of the line for company G and company H
Slope m is given as
[tex]m=\frac{rise}{run}[/tex]For company G, we have slope as
[tex]m=\frac{5}{1}=5[/tex]For Company H, we have
[tex]m=\frac{4}{1}=4[/tex]From the graph
Cab fare for 1 mile with company G is $7
Cab fare for 10 miles with company H is?
To get this we need to get the equation of the line H
From
[tex]\begin{gathered} y=mx+b \\ where\text{ m is slope and b is the y-intercept, we have } \\ y=4x+2 \end{gathered}[/tex]Now substituting x for 10 in the equation, we have
[tex]\begin{gathered} y=4x+2 \\ y=4(10)+2 \\ y=40+2 \\ y=42 \end{gathered}[/tex]Hence the cab fare for 10 miles with Company H is $42
The rate charge per mile by Company G is the slope we got as 5.
Hence the answer is $5 per mile
The rate charge per mile by Company H is the slope we got as 4.
Hence the answer is $4 per mile
1 Ms. Signer has to buy pencils for her class. She goes to CVS and buys 15 pencils for $2.50. How much did she spend per pencil?*
She bought pencils for her class. She bought 25 pencils for $2.50 . The amount for each pencil can be computed below
[tex]\begin{gathered} 25\text{ pencils = \$2.50} \\ 1\text{ pencil = ?} \\ \text{cross multiply} \\ \cos t\text{ of each pencil=}\frac{2.50}{25} \\ \text{ cost of each pencil = \$}0.1 \end{gathered}[/tex]you can make pancakes with just bananas and eggs : serves 4 people with 6 eggs 2 bananas. how many eggs and bananas do u need to serve 6 people?
Given:
To prepare a pancake that serves 4 people, we need 6 eggs and 2 bananas.
Required:
The number of eggs and bananas that serves 6 people
By comparison,
If we need 6 eggs to prepare a pancake that serves 4 people, the number of people that 1 egg would serve is:
[tex]\begin{gathered} k\text{ = }\frac{4\text{ people}}{6\text{ eggs}} \\ =\text{ }\frac{2}{3}\text{ people/ egg} \end{gathered}[/tex]Similarly, If we need 2 bananas to prepare a pancake that serves 4 people, the number of people that 1 banana would serve is:
[tex]\begin{gathered} k_2\text{ = }\frac{4\text{ people}}{2\text{ bananas}} \\ =\text{ 2 people/banana} \end{gathered}[/tex]The number of eggs that serves 6 people:
[tex]\begin{gathered} =\text{ 6 people }\times\frac{3}{2}\text{ egg/people} \\ =\text{ 9 eggs} \end{gathered}[/tex]The number of bananas that serves 6 people:
[tex]\begin{gathered} =\text{ 6 people }\times\text{ }\frac{1}{2}\text{ banana/ people} \\ =\text{ 3 bananas} \end{gathered}[/tex]Answer:
9 eggs are needed
3 bananas are needed
A number multiplied by 2/5 is 3/20, Find the number
Answer:
3/8
Explanation:
Let the number be x.
A number multiplied by 2/5 = (2/5)x
Therefore:
[tex]\frac{2}{5}x=\frac{3}{20}[/tex]To solve for x, first, we cross-multiply.
[tex]\begin{gathered} 2x\times20=3\times5 \\ 40x=15 \end{gathered}[/tex]Next, we divide both sides of the equation by 40.
[tex]\begin{gathered} \frac{40x}{40}=\frac{15}{40} \\ x=\frac{3}{8} \end{gathered}[/tex]The number is 3/8.
Use the graph of the function y= f(x) below to answer the questions
a)
We need to find the value of f(-3), that means we need to find the value of the y-coordinate when the x-coordinate is -3
As we can see in the graph
f(-3)=-5
Therefore f(-3) is negative
The answer for this part is NO
b)
if f(x)=0, that means that we are looking for the x-intercepts
x=-2
x=1
x=4
The answer is -2,1,4
c)
We need to know for what values of x f(x)<0
In this case in interval notation
[tex]\lbrack-3,2)\cup(1,4)[/tex]If the area of the rectangle is 4836 square feet find the length of the rectangle
Solution
- Let the length of the rectangle be x
- Let the width of the rectangle be y.
- Thus, we can interpret the lines of the question as follows:
[tex]\begin{gathered} \text{ The length is 30 less than 6 times the width can be written as} \\ x=6y-30\text{ (Equation 1)} \\ \\ \text{The area of the rectangle is 4836. This is written as:} \\ xy=4836\text{ (Equation 2)} \end{gathered}[/tex]- Now, let us solve these two equations simultaneously.
- We shall proceed by solving the system of equations graphically.
- Wherever the graphs of Equation 1 and Equation 2 intersect represents the solution to the system of equations
- The plot of the equations is given below
- Observe that the graphs cross at two points. The first point is positive and the other, negative.
- Since we cannot have negative lengths (x) or width (y), we can discard the negative coordinates.
- Thus, the length (x) and width (y) are given below:
[tex]\begin{gathered} \text{length(x)}=156 \\ \text{width(y)}=31 \end{gathered}[/tex]Final Answer
The length of the rectangle is 156 feet
Find the equation of the linear function represented by the table below in slope-intercept form. Answer: y=
Answer:
y = 2x + 6
Explanation:
The slope-intercept form of a linear equation can be found as:
[tex]y=m(x-x_1)+y_1[/tex]Where m is the slope and it is calculated as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]And (x1, y1) and (x2, y2) are values from the table. So, we can replace (x1, y1) by (0,6) and (x2, y2) by (1, 8):
Then, the slope is:
[tex]m=\frac{8-6}{1-0}=\frac{2}{1}=2[/tex]Therefore, the equation of the line is:
[tex]\begin{gathered} y=2(x-0)+6 \\ y=2x+6 \end{gathered}[/tex]So, the answer is y = 2x + 6
9km 87 m equals
option A = 9.087km
option B= 90.87km
option c = 0.9087km
option D= 908.7km
option e= none of these
please don't give wrong answer
Learn with an example v Sharon has a red ribbon and an indigo ribbon. The red ribbon is 6 1/4 inches long. The indigo ribbon is 6 1/4 inches longer than the red ribbon. How long is the indigo ribbon?
Let R be the length of the red ribon and let I be the length of the indigo ribbon. We have that the red ribbon is 6 1/4 inches long, then:
[tex]R=6\frac{1}{4}=\frac{25}{4}[/tex]Then, the indigo ribbon is 6 1/4 inches longer than the red ribbon. Then we have:
[tex]I=R+6\frac{1}{4}[/tex]therefore:
[tex]I=\frac{25}{4}+\frac{25}{4}=\frac{50}{4}=\frac{25}{2}=12\frac{1}{2}[/tex]finally, we have that the indigo ribbon is 12 1/2 inches long
Convert 253 inches to yards using dimensional analysis.
As given by the question
There are given that the 253 inches
Now,
To convert the inches to yards, multiply the value in inches by the conversion factor 0.0277777787.
So,
[tex]253\times0.0277777787=7.0277778.[/tex]Hence, the value of the given inches is 7.0278 yards.
Solve the inequality and write the solution using:
the inequality
What are all the rational roots of the polynomial f(x) = 20x4 + x3 + 8x² + x - 12?
Answer:
All the rational roots of the polynomial f(x) = 20x4 + x3 + 8x2 + x - 12 are 3/4 and -4/5.
The resale value V, in thousands of dollars, of a boat is a function of the number of years since the start of 2011, and the formula isV = 10.5 - 1.1t.(a) Calculate V(3).________thousand dollarsExplain in practical terms what your answer means.This means that the resale value of the boat will be______thousand dollars at the start of the year_______(b) In what year will the resale value be 6.1 thousand dollars?______(c) Solve for t in the formula above to obtain a formula expressing t as a function of V. t=______(d) In what year will the resale value be 2.8 thousand dollars?_______
Answer
a) V (3) = 7.2 thousand dollars.
In practical terms, the resale value of the boat will be 7.2 thousand dollars at the start of the year 2014.
b) t = 4years.
The resale value will be 6.1 thousand dollars in the year 2015.
c) t = 9.545 - 0.909V
d) t = 7 years.
7 years after the start of 2011 = 2018.
Explanation
We are given that the resale value (V), in thousands of dollar, of a boat is given as
V = 10.5 - 1.1t
where t = number of years since the start of 2011.
a) We are told to calculate V(3).
V = 10.5 - 1.1t
t = 3
V = 10.5 - 1.1 (3)
V = 10.5 - 3.3
V = 7.2 thousand dollars.
In practical terms, the resale value of the boat will be 7.2 thousand dollars at the start of the year 2014.
b) In what year will the resale value be 6.1 thousand dollars.
V = 10.5 - 1.1t
what is t when V = 6.1
6.1 = 10.5 - 1.1t
1.1t = 10.5 - 6.1
1.1t = 4.4
Divide both sides by 1.1
(1.1t/1.1) = (4.4/1.1)
t = 4 years.
4 years afther the start of 2011 = 2015.
c) We are asked to solve for t and obtain a formula expressing t as a function of V.
V = 10.5 - 1.1t
1.1t = 10.5 - V
Divide through by 1.1
[tex]\begin{gathered} \frac{1.1t}{1.1}=\frac{10.5}{1.1}-\frac{V}{1.1} \\ t=9.545-\frac{V}{1.1} \\ t=9.545-0.909V \end{gathered}[/tex]t, expressed in terms of V, is t = 9.545 - 0.909V
d) We are now asked to calculate in what year will the resale value be 2.8 thousand dollars.
t = 9.545 - 0.909V
t = 9.545 - 0.909 (2.8)
t = 9.545 - 2.545
t = 7 years.
7 years after the start of 2011 = 2018.
Hope this Helps!!!
I need help with this problem.
Using tangent function:
[tex]\begin{gathered} \tan (\theta)=\frac{opposite}{adjacent} \\ \tan (T)=\frac{16}{32}=\frac{1}{2}=0.5 \end{gathered}[/tex]Give the point-slope form of the equation of the line that is perpendicular to y= -4x/5+10 and contains P(5,6)
You have to write the equation of a line perpendicular to
[tex]y=-\frac{4}{5}x+10[/tex]That crosses the point (5, 6)
A caracteristic of a line permendicular to another one is that its slope pf the perpendicular line is the negative inverse of the slope of the first line.
So for example if you have two lines:
1_ y=mx+b
and
2_ y=nx+c
And both lines are perpendicular, the slope of the second one will be the negative inverse of the slope of the first one, that is:
[tex]n=-\frac{1}{m}[/tex]The slope of the given line is m=-4/5
The negative inverse is
[tex]-(\frac{1}{-\frac{4}{5}})=-(-\frac{5}{4})=\frac{5}{4}[/tex]Now that you know the slope of the perpendicular line, use it along with the given point (5, 6)
in the slope-point formula:
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-6=\frac{5}{4}(x-5) \end{gathered}[/tex]