Answers
Answer:
a) 8x + 5x = 13x
b) 9f + 10f - 12f = 7f
Step-by-step explanation:
For part b, just solve from left to right normally, since adding and subtracting are inverse operations. (Inverse operation; meaning they are opposites of each other.)
So 9 + 10 = 19, and 19 - 12 = 7.
Hope this helps you :)
Step-by-step explanation:
(a) 8x + 5x = 13x....simplified
(b) 9f + 10f - 12f = 7f.....simplified
Hope it helps you!Related Questions
Solve:
A.152
B.176
C.5
D.27
Answers
Answer:
Option B
176
Step-by-step explanation:
take 11 to the next side of the equation making the division multiplication getting us 16×11=176
A= 3x3x3x3x3x5x7x7x7
B= 2x2x2x3x7x7x7x7
Find the Lowest Common Multiple (LCM) of A and B.
Please help
Answers
Answer:
LCM(57624, 416745) = 23,337,720 or LCM = 23337720
Step-by-step explanation:
List all prime factors for each number.
Prime Factorization of 57624 is:
2 x 2 x 2 x 3 x 7 x 7 x 7 x 7 => 23 x 31 x 74
Prime Factorization of 416745 is:
3 x 3 x 3 x 3 x 3 x 5 x 7 x 7 x 7 => 35 x 51 x 73
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 2, 3, 3, 3, 3, 3, 5, 7, 7, 7, 7
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 5 x 7 x 7 x 7 x 7 = 23337720
In exponential form:
LCM = 23 x 35 x 51 x 74 = 23337720
LCM = 23337720
Therefore,
LCM(57624, 416745) = 23,337,720
I have three bits of tinsel measuring the following: 2.3m, 45cm and 750mm. How long is my tinsel altogether in metres?
Answers
——————-
750 mm = 0.75 m
45 cm = 0.45 m
2.3 m
——————
Add and you should get 3.5. The tinsel is 3.5 meters long.
What are coordinate of (2,-3) when it is reflected over X axis.
Answers
Answer:
the asnwer is (2,3)
Step-by-step explanation:
if m * n = √(m²-n²) then 5 * 3 =
Answers
[tex]m \cdot n = \sqrt{m^2 -n^2}\\\\\text{When m =5 and n =3,}\\\\\\5\cdot 3 = \sqrt{5^2 -3^2} =\sqrt{25 -9} = \sqrt{16} = 4[/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Assuming:}[/tex]
[tex]\mathbf{m\times n = \sqrt{(m^2 - n^2)}}[/tex]
[tex]\huge\textbf{Solving:}[/tex]
[tex]\mathbf{\rightarrow 5\times 3 = \sqrt{(5^2 - 3^2)}}[/tex]
[tex]\mathbf{\rightarrow 15 = \sqrt{(5\times5 - 3\times3)}}[/tex]
[tex]\mathbf{\rightarrow 15 = \sqrt{(25 - 9)}}[/tex]
[tex]\mathbf{\rightarrow 15 = \sqrt{16}}[/tex]
[tex]\mathbf{15\neq4}[/tex]
[tex]\huge\textbf{Thus, this answer should be:}[/tex]
[tex]\huge\boxed{\boxed{\textsf{This statement is most likely: \boxed{\textsf{FALSE}}}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
[tex]\frak{Amphitrite1040:)}[/tex]
ok i rly need help w this PLZ HELPPP
1. 2(x−4 1/2)=−6.
2. 3(p+2.55)=9 3/4
Answers
Answer:
1)x=1.5
2) p=0.7
Step-by-step explanation:
Find the value of each variable in the given figures
Answers
Answer:
q = 22
Step-by-step explanation:
(7q - 46)° + (3q+6)° = 180 (linear pair property)
7q - 46 + 3q + 6 = 180
10q - 40 = 180
10q = 180 + 40
10q = 220
q = 220/10 = 22
m∠ABD = (7q - 46)° = 7(22) - 46 = 154 - 46 = 108°
m∠DBC = (3q + 6)° = 3(22) + 6 = 66 + 6 = 72°
THE AREA OF A LAKE ON THE MAP IS 12CM SQUARE CALCULATE THE ACTRUAL AREA OF THE LAKE IN KM
SQUARE
Answers
Answer:
if 1cm is for 1km there are 12km
Step-by-step explanation:
it can depend on the size of the map but if there is a scale which shows how many km per cm then multiply by 12
Boris made $306 for 18 hours of work. At the same rate, how many hours would he have to work to make $119?
Answers
Answer:
[tex]18 = 306 \\ x = 119 \\ \\ 306x = 2142 \\ x = \frac{2142 }{306 } \\ x = 7[/tex]
If you can help, I’ll give brainliest
Answers
Answer:
sum of interior angles =180×3= 540°
m<F= 540-105-113-107-87
=128°
m<F= 128°
How many solutions does the equation 6(x -2) = 8 + 6x have?
Answers
Answer:
There are no solutions.
Step-by-step explanation:
First simplify the equation.
6(x - 2) = 8 + 6x
Distribute.
6x - 12 = 8 + 6x
Adding 8 to a number and subtracting 12 from the same number to get the same answer doesn't make sense so there are no solutions.
I really tend this answer fast
Answers
Answer:9.1 units
Step-by-step explanation: Hope you get it right :D
A river flows at the rate of 12 feet per minute. What is the rate in second per foot?
Answers
Explanation:
There are 60 seconds in a minute. We know the river flows 12 ft per 1 minute. So in order to find the rate per seconds, divide: 60/12. You get the answer: 1/5 or 0.2 in decimal form.
Choose the correct transformation.
Answers
simplify (89^6x91^3)^0
Answers
i dont know but i do know that OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO
ABC is a triangle. AC=19cm, BC=17cm and angle BAC=60
Answers
Answer:
In the picture
Step-by-step explanation:
it's an acute triangle
more information in the picture
A college is currently accepting students that are both in-state and out-of-state. They plan to accept two times as many in-state students as out-of-state, and they only have space to accept 200 out-of-state students. Let x = the number of out-of-state students and y = the number in-state students. Write the constraints to represent the incoming students at the college. X > 0 and y > 0 0 < x ≤ 200 and y > 400 0 < x and y < 200 0 < x ≤ 200 and 0 < y ≤ 400.
Answers
The constraints to represent the incoming students at the college are [tex]0<x \leq 200[/tex] and [tex]0<y \leq 400[/tex] and this can be determined by using the given data.
Given :
College plans to accept two times as many in-state students as out-of-state, and they only have space to accept 200 out-of-state students.x is the number of out-of-state students and y is the number of in-state students.The following steps can be used in order to determine the constraints to represent the incoming students at the college:
Step 1 - The inequalities are formed in order to determine the constraints to represent the incoming students at the college.
Step 2 - The linear equation that represents the situation "two times as many in-state students as out-of-state" is:
[tex]y = 2x[/tex]
Step 3 - The inequality that represents the situation "college only have space to accept 200 out-of-state students" is:
[tex]0<x \leq 200[/tex]
Step 4 - So, the inequality that represents the maximum number of in-state students that college can take is:
[tex]0<y \leq 400[/tex]
Therefore, the correct option is D).
For more information, refer to the link given below:
https://brainly.com/question/19491153
i dont know someone help pls
Answers
Answer:
The answer is $242
Step-by-step explanation:
We can set up two equations for this one:
286 = 13 * (rate per hour)
divide both sides by 13:
22 = rate per hour
Then knowing her rate per hour is 22 dollars
22 * 11 hours of work = $242
At the same rate she will make $242 in 11 hours.
Kala made $286 for 13 hours of work . Therefore, let's find the rate.
What is rate:Rate is simply the ratio between two values with different units. In our case, its the amount made in dollars versus the time taken to make that amount.
Therefore,
rate = amount made(dollars)/ time taken(hours)
rate = 286 / 13
rate = 22 dollars per hour
At the same rate the amount she will make in 11 hours can be calculated as follows:
rate = amount / 11
22 = amount(dollars) / 11
cross multiply
amount(dollars) = 22 × 11
amount(dollars) = $242
learn more on rate here: https://brainly.com/question/8062121?referrer=searchResults
The area of a rhombus is 40 sq cm and one of its diagonals is 8 cm long. Find the length of the other diagonal.
Answers
Answer: The length of the other diagonal is 10 cm...
So the diagonal formula is - 1/2* (d1*d2) d1 is the first diagonal and d2 is the second diagonal.
So,
1/2 * (8*d2) = 40
8d2= 40*2
d2= 80/8
d2= 10
Which statement is necessarily true if is an altitude to the hypotenuse of right ?
Answers
Step-by-step explanation:
it's b
i relly don't know cause theres no image
Use <, >, or = to make the
statement true.
20[?]-1
Answers
Answer:
20 > -1
Step-by-step explanation:
Well 20 is a positive integer that is 20 units from 0 whereas -1 is a negative integer that is 1 unit behind zero.
what is the solution to this equation 4x -6 + 2x =18
Answers
Answer:
x=12
Step-by-step explanation:
4x-6+2x=18
2x-6=18
2x=24
x=12
Someone help pleaseeeee
Answers
Answer:
[tex]1. \: \: \: a = \frac{5}{7} \\ 2. \: \: \: 4 \\ 3. \: \: \: 15 {x}^{2} + 60x + 135 \\ 4. \: \: \: m = {75}^{o} \\ [/tex]
Step-by-step explanation:
[tex]1. \: \: 7a - 8 = 13 \\ 7a - 8 + 8 = 13 + 8 \\ 7a = 5 \\ \frac{7a}{7} = \frac{5}{7} \\ a = \frac{5}{7} \\ [/tex]
[tex]2. \: \: \: 4 = 2 \times 2 \\ 8 = 2 \times 2 \times 2 \\ 4 \\ [/tex]
[tex]3. \: \: \: 15 {(x + 3)}^{2} \\ 15(x + 3)(x + 3) \\15 (x + 3)(x + 3) \\ 15 |x(x + 3) + 3(x + 3)| \\ 15 ({x}^{2} + 3x + 3x + 9 )\\ 15( {x}^{2} + 6x + 9) \\ {15x}^{2} + 60x + 135 \\ [/tex]
[tex]4. \: \: \: m = {75}^{o} (opposite \: angles)[/tex]
I don't know the answer to y=48,000(1-13.2)6
Answers
22/7 x 1.4
Plz explain this step by step
Answers
Answer:
22/5 (or) 4.4
Step-by-step explanation:
22/7 × 1.4
=22/7 × 1.4/1 <-- to change the decimal into a fraction multiply it with ×10 so the numerator 1.4 will become 14 and the denominator 1 will be 10
=22/7 × 14/10 <-- now you can cancel out as usual
=22/5 (or) 4.4
PLEASE I NEED HELP, ILL MARK AS BRAINLIEST!!
Raul  is filling a 55 gallon fish tank with water. There are 18.5 gallons of water in the take 2.5 gallons of water flows from the hose each minute how many gallons of water are in the fish tank after 12 minutes
Answers
Answer:
All you do is multiply 2.5 x 12
Step-by-step explanation:
multiplying both numbers gets you a toltal of 24.60 or 24.6
The price of an item has been reduced by 45%. The original price was $60. What is the price of the item now?
Answers
Answer:
the answer to the question is 15$
Anna and Sam each want to run for president of their school's student body council. In order
to do so, they must collect a certain number of signatures and get a nomination. So far, Anna
has 20 signatures, and Sam has 25. Anna is collecting signatures at an average rate of 6 per
day, whereas Sam is averaging 5 signatures every day. Assuming that their rate of collection
stays the same, eventually the two will have collected the same number of signatures. How
long will that take?
Time
elapsed
Write a system of equations, graph them, and type the solution.
Answers
Answer:
6x+20=5x+25
5 days
Step-by-step explanation:
Let x = the days that they have the same amount of signatures
We know Anna has 20 currently and gets 6 per day, so we can use y=mx+b to describe her linear relationship.
We also know that Sam has 25 and gets 5 per day, so we can again use y=mx+b to describe his linear relationship.
Since both equations equal the variable y, we can say they equal each other and set up 6x+20=5x+25.
Then you subtract 20 from both sides and subtract 5x, so you are left with x =5, or 5 days until they have the same amount of signatures
Hope this made sense :D
6 pounds of candy cost 22.44. What is the cost of one pound
Answers
Answer:
$3.74
Step-by-step explanation:
Proportions:
6 pounds ⇔ $22.44
1 pound ⇔ $ C
C = 22.44*1/6
C = $3.74
(3^3 times 6^6)^-3 in fraction form
Answers
Use cymath! It's free to use and can easily help you with math like this.
[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{(3^3 \times6^6)^{-3}}\\\\\mathsf{3^3}\\\mathsf{=3\times3\times3}\\\mathsf{= 9\times3}\\\mathsf{= 27}\\\\\mathsf{(\bold{27}\times6^6)^{-3}}\\\\\mathsf{6^6}\\\mathsf{= 6\times6\times6\times6\times6\times6}\\\mathsf{= 36\times36\times36}\\\mathsf{= 1,296\times36}\\\mathsf{= 46,656}\\\\\mathsf{(27\times \bold{46,656)}^{-3}}\\\\\mathsf{= \dfrac{1}{1,256,712\times1,256,715\times1,259,712}}\\\\\mathsf{=\dfrac{1}{1,999,004,627,104,432,128}}[/tex]
[tex]\large\text{Therefore, your answer is: }\mathsf{ \dfrac{1 }{1,999,004,627,104,432,128}\ }}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]