The theorem holds for n=3, and we have shown that if it holds for n=k, then it also holds for n=k+1, the theorem is true for all n greater than or equal to 3 by mathematical induction.
To prove the theorem using the method of mathematical induction, we need to show that it holds for the base case of n=3, and then prove the inductive step, which is that if it holds for n=k, then it also holds for n=k+1.
Base Case: n=3
For a regular polygon with n=3,
we have an equilateral triangle.
The center of the triangle is also its centroid and the segments connecting the center to the vertices divide the triangle into three congruent isosceles triangles.
Thus, the theorem holds for n=3.
Inductive Step: Assume the theorem holds for n=k
We need to show that the theorem also holds for n=k+1, that is, the segments connecting the center of a regular (k+1)-gon to its vertices partition it into k+1 congruent isosceles triangles.
Consider a regular (k+1)-gon with center O. Let A1A2A3...Ak+1 be its vertices. Draw the segments OA1, OA2, OA3,..., OAk+1. By the definition of a regular polygon, all sides and angles of the polygon are congruent.
We will show that the (k+1)-gon can be divided into k congruent isosceles triangles by connecting the center to pairs of adjacent vertices, and then adding an extra isosceles triangle using the segment connecting the center to the vertex opposite A1.
First, connect the center O to adjacent vertices A1 and A2. This divides triangle OA1A2 into two congruent isosceles triangles, with angles at O equal to (k-2)/k times the central angle at O.
Next, connect O to vertices A2 and A3. This divides triangle OA2A3 into two congruent isosceles triangles, with angles at O equal to (k-2)/k times the central angle at O. Continue this process, connecting O to vertices A3 and A4, A4 and A5, and so on, until we connect O to vertices Ak and Ak+1.
At this point, we have divided the (k+1)-gon into k congruent isosceles triangles. To complete the proof, we need to add an extra isosceles triangle using the segment connecting O to vertex Ak+1.
The angle at O that is formed by the segments OAk and OA1 is the central angle at O, which has measure 360/k degrees. The angle at A1 that is opposite the base OAk+1 has measure (180 - (360/k))/2 degrees. Therefore, the angle at O that is opposite the base OAk+1 has measure (k-2)/k times the central angle at O, which is the same as the angles in the k congruent isosceles triangles we have already constructed. Therefore, the segment OAk+1 divides the (k+1)-gon into a total of k+1 congruent isosceles triangles.
Since the theorem holds for n=3, and we have shown that if it holds for n=k, then it also holds for n=k+1, the theorem is true for all n greater than or equal to 3 by mathematical induction.
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Which linear system has this matrix of constants? `[[12],[11],[4]]
The matrix of constants you provided [[12],[11],[4]] represents a system of linear equations with 3 variables and 1 equation, which is an underdetermined system.
To write the system of equations in the form Ax = b, where A is the matrix of coefficients, x is the vector of variables, and b is the vector of constants, we can set:
12x1 = 11x2 + 4x3
where x1, x2, and x3 are the variables of the system.
Note that this system has infinitely many solutions, since there are more variables than equations. In other words, we can choose any value for one of the variables and solve for the other two.
Assuming that you meant to ask for the simplified form of the expression:
The formula is (a × x) = (a × x) + (b × a × x)
We can first simplify the expression by combining like terms:
(1 + 4b) is equal to (axe) + b(ax) + c(a × x) + d(a × x)√(ax)
Therefore, the simplified expression is:
(1 + 4b)√()axe) + b(ax) + c(a × x) + d(a × x)√(ax)
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please help this is question 4/7
The number of people expected to go to the Youth Wing, would be 255 people.
How to find the people ?Find the total amount of people who will be visiting on Saturday:
= 382 ( Youth Wing ) + 461 ( Social Issues ) + 355 ( Fiction and Literature )
= 1, 198
Then the proportion of those who went to Youth Wing :
= 382 / 1, 198
= 0. 319
The estimated people going for Youth Wing on Sunday :
= 0. 319 x 800
= 255 people
In conclusion, an estimated 255 people would be going to Youth Wing.
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Show that the surface area of the solid region bounded by the three cylinders x^2 + y^2 = 1, y^2 + z^2 = 1 and x^2 + z^2 = 1 is 48 – 24√2.
We have to show that the surface area of the solid region bounded by the three cylinders x^2 + y^2 = 1, y^2 + z^2 = 1, and x^2 + z^2 = 1 is 48 - 24√2
Step 1: Find the points of intersection between the cylinders.
By solving the systems of equations:
(i) x^2 + y^2 = 1 and y^2 + z^2 = 1
(ii) x^2 + y^2 = 1 and x^2 + z^2 = 1
(iii) y^2 + z^2 = 1 and x^2 + z^2 = 1
Step 2: Calculate the surface areas of the three cylinders within the bounded region.
The surface area of each cylinder can be found using the formula A = 2πrh, where r is the radius, and h is the height.
Step 3: Add the surface areas of the three cylinders.
Sum the surface areas found in step 2 to get the total surface area of the bounded region.
Step 4: Subtract the overlapping areas.
The overlapping areas are the 6 faces of the solid octahedron formed by the intersection of the cylinders. Each face has an area of √2/2, so the total overlapping area is 6(√2/2).
Step 5: Calculate the final surface area.
Subtract the overlapping areas found in step 4 from the total surface area found in step 3 to obtain the final surface area.
Upon completing these steps, you will find that the surface area of the solid region bounded by the three cylinders x^2 + y^2 = 1, y^2 + z^2 = 1, and x^2 + z^2 = 1 is indeed 48 - 24√2.
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Suppose that the demand curve in the market for VCRs can be represented by the following demand and supply equation: Qd = 1,000 - 6P = Qs = = 4P The government decides to impose a tax of $30 per unit sold on VCRs. 1. Find the equilibrium quantity with the tax. 2. Find the price paid by buyers 3. Find the price paid by sellers. 4. Illustrate your answer in (a) with a diagram 5. Calculate the Dead Weight Loss due to the tax 6. Calculate the consumer surplus due to the tax.
Demand refers to the quantity of a product or service that buyers are willing and able to purchase at a certain price level. A demand curve is a graphical representation of the relationship between the quantity of a good or service that buyers are willing to purchase at different price levels.
In the market for VCRs, the demand and supply equations are Qd = 1,000 - 6P and Qs = 4P respectively. The government decides to impose a tax of $30 per unit sold on VCRs. This will lead to a shift in the supply curve upwards by $30, resulting in a new equilibrium point.
1. To find the new equilibrium quantity with the tax, we set Qd = Qs + tax. Thus, 1,000 - 6P = 4P + 30. Solving for P, we get P = $105. The equilibrium quantity is therefore Q = 1,000 - 6($105) = 370.
2. The price paid by buyers is the same as the equilibrium price, which is $105.
3. The price paid by sellers is the equilibrium price minus the tax, which is $75.
4. The diagram below illustrates the impact of the tax on the market for VCRs. The original equilibrium point is E0, with a price of $70 and a quantity of 400. With the tax, the new equilibrium point is E1, with a higher price of $105 and a lower quantity of 370. The tax creates a vertical distance between the two equilibrium points, which represents the tax revenue collected by the government.
[Insert Diagram Here]
5. The deadweight loss due to the tax is the reduction in total surplus (consumer surplus + producer surplus) that results from the tax. Using the original equilibrium as a benchmark, the total surplus is (1/2)($70)(400) = $14,000. With the tax, the total surplus is (1/2)($75)(340) = $6,375. Thus, the deadweight loss is $7,625.
6. To calculate the consumer surplus due to the tax, we need to compare the original consumer surplus with the new consumer surplus. Using the original equilibrium as a benchmark, the consumer surplus is (1/2)($70)(400 - 70) = $5,950. With the tax, the consumer surplus is (1/2)($105)(370 - 105) = $12,145. Thus, the consumer surplus due to the tax is $6,195.
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The area of a rhombus is 100. Find the length of the two diagonals if one is twice as long as the other.The length of two diagonals of the rhombus are 10 and 20.
The length of the two diagonals of a rhombus if one is twice as long as the other are 10 and 20.
Given that the length of two diagonals of the rhombus are 10 and 20.
Let d1 and d2 be the lengths of the diagonals of the rhombus. Since the area of the rhombus is 100, we have:
d1 * d2 / 2 = 100
We are also given that one diagonal is twice as long as the other, so:
d1 = 2d2
Substituting d1 = 2d2 into the first equation, we get:
2d2 * d2 / 2 = 100
d2^2 = 100
d2 = 10 or -10 (we ignore the negative solution)
Since d1 = 2d2, we have d1 = 20.
Therefore, the length of the two diagonals of the rhombus are 10 and 20.
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Assume scores on a recent national statistics exam were normally distributed with a mean of 74 and a standard deviation of 6. Find the probability that a randomly selected student score more than 80 points? If the top 2.5% of test scores recurveerit awards, what is the lowest eligible for an award?
The probability that a randomly selected student score more than 80 points is 0.1587 or 15.87%. The lowest eligible for an award is 85.76.
To find the probability that a randomly selected student scores more than 80 points, we need to standardize the score using the z-score formula:
z = (x - μ) / σ
where x is the score
μ is the mean
σ is the standard deviation.
In this case, we have:
z = (80 - 74) / 6 = 1
Using a standard normal distribution table or calculator, we can find that the probability of a z-score of 1 or greater is approximately 0.1587. Therefore, the probability that a randomly selected student scores more than 80 points is approximately 0.1587 or 15.87%.
To find the lowest score eligible for an award, we need to find the z-score that corresponds to the top 2.5% of the distribution. Using a standard normal distribution table or calculator, we can find that the z-score corresponding to the top 2.5% is approximately 1.96.
We can then use the z-score formula to solve for x:
z = (x - μ) / σ
1.96 = (x - 74) / 6
11.76 = x - 74
x = 85.76
Therefore, the lowest score eligible for an award is approximately 85.76.
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There are 2 workers in a team. Each can either work hard or shirk. If both workers shirk, the overall project succeeds with probability p0, if only one worker shirks, it succeeds with probability p1, and if both workers work hard, it succeeds with probability p2. (p2>p1>p0) The cost of effort is c. The principal cannot observe the individual efforts, but only the success or failure of the whole project. Design the optimal contract that induces all the workers the exert effort all the time. Do the workers’ efforts complement or substitute each other (classify the probabilities of success to answer this question)?
In this scenario, there are two workers in a team, and each worker can either work hard or shirk. The probability of the overall project succeeding is dependent on the efforts of each worker. If both workers shirk, the probability of success is p0. If one worker shirks and the other works hard, the probability of success is p1. Finally, if both workers work hard, the probability of success is p2, where p2>p1>p0.
The cost of effort is c, and the principal cannot observe the individual efforts of each worker, but only the success or failure of the whole project. The challenge is to design an optimal contract that encourages both workers to exert effort all the time.
The optimal contract would offer a payment scheme to both workers that would incentivize them to work hard. If the workers work hard and the project succeeds, they receive a reward. If the workers shirk, they receive no reward.
The workers' efforts in this scenario are substitutes for each other. This is because if one worker shirks, the probability of success decreases, and the other worker would have to work harder to compensate for the first worker's lack of effort. Therefore, both workers must work hard to maximize the probability of success.
In conclusion, an optimal contract must be designed that encourages both workers to work hard and rewards them for the successful completion of the project. Additionally, the efforts of both workers in this scenario are substitutes for each other.
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Practice: AE and CD are diameters of Circle B. Find mCE, mDE, and mF AE.
According to the figure, the arc lengths are
arc CE = 130 degreesarc DE = 50 degreesarc FAE = 270 degreesHow to find the missing sidesThe missing sides in the figure are sought knowing that central angles are equal to length of arcs. Hence we have that
arc CE = 180 degrees - arc CA
arc CE = 180 degrees - 50 degrees
arc CE = 130 degrees
arc DE = arc CA (vertical angles)
arc DE = 50 degrees
arc FAE = 360 degrees - 90 degrees
arc FAE = 270 degrees
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If DEF Is equivalent to GHF, what is the value of X?
The value of x is 19.44
What are similar triangles?Similar triangles are triangles that have the same shape, but their sizes may vary.
For two triangles to be similar, the corresponding angles must be congruent and also, the ratio of the corresponding sides of similar triangles are equal,
therefore,
27/9x-13 = 15/90
27 × 90 = 15(9x-13)
2430 = 135x - 195
collecting like terms
2430+195 = 135x
2625 = 135x
divide both sides by 135
x = 2625/135
x = 19.44
therefore the value of x is 19.44
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what is x if f (x) = 4x + 13 = 9
Answer:
-1
Step-by-step explanation:
4x + 13 = 9
4x + 13 - 13 = 9 -13
4x = -4
-4/4 = -1
X = -1
Answer:
-1.
Step-by-step explanation:
4x + 13 = 9
4x = 9 -13
4x = -4
x = -4/4
X = -1
(2 points) 1) Listen What is the formula used to calculate degrees of freedom for at test for dependent groups? On1 + n2 n1 - 1 O n1 + n2 - 1 Thing n1 - 1 + n2
The total sample size, because each pair of data provides one less degree of freedom than the number of individuals in the pair.
The formula used to calculate the degrees of freedom for a test for dependent groups is:
df = n - 1
where n is the number of pairs of data in the sample.
In a dependent groups (or paired samples) test, the same group of individuals is measured twice, or two groups of individuals are matched in pairs. The difference between the two measurements or the two pairs of measurements is the data used in the test.
The degrees of freedom is a measure of the amount of information available to estimate a population parameter, such as the mean difference between the paired observations in the case of a dependent groups test. In general, a higher degrees of freedom value means more information and thus more precision in the estimate.
In the case of a dependent groups test, the degrees of freedom is determined by the number of pairs of data in the sample, rather than the total sample size, because each pair of data provides one less degree of freedom than the number of individuals in the pair.
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Chris has 2 pairs of black socks, 4 pairs of red socks, and 18 pairs of white socks in a dresser drawer. If he reaches in his drawer without looking, what is the probability that he will choose a pair of white socks?
The probability that Chris will choose a pair of white socks is 0.75 or 75%.
Chris has a total of 2 + 4 + 18 = 24 pairs of socks in his drawer. Out of these, 18 pairs are white.
Probability is a branch of mathematics that deals with the study of random events or phenomena. It is concerned with measuring the likelihood or chance of an event occurring.
In probability theory, an event is any outcome or set of outcomes of a random experiment. The probability of an event is a number between 0 and 1 that represents the likelihood of that event occurring. An event with a probability of 0 is impossible, while an event with a probability of 1 is certain.
If Chris reaches in his drawer without looking and selects a pair of socks at random, the probability of choosing a pair of white socks is:
(number of pairs of white socks) / (total number of pairs of socks)
= 18 / 24
= 3/4
= 0.75
Therefore, the probability that Chris will choose a pair of white socks is 0.75 or 75%.
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A horizontal line starting at 0, with tick marks every one-half unit up to 32. The line is labeled Wait Time In Minutes. The box extends from 8.5 to 15.5 on the number line. A line in the box is at 12. The lines outside the box end at 3 and 27. The graph is titled Super Fast Food.
A horizontal line starting at 0, with tick marks every one-half unit up to 32. The line is labeled Wait Time In Minutes. The box extends from 9.5 to 24 on the number line. A line in the box is at 15.5. The lines outside the box end at 2 and 30. The graph is titled Burger Quick.
Which drive-thru typically has more wait time, and why?
Burger Quick, because it has a larger median
Burger Quick, because it has a larger mean
Super Fast Food, because it has a larger median
Super Fast Food, because it has a larger mean
The drive-thru that typically has more wait time, and why is C. Super Fast Food, because it has a larger median
Which drive-thru that typically has more wait time?According on the information supplied, Super Fast Food normally has a greater wait time. Although the Burger Quick box is larger, indicating a greater range of wait times, the median (15.5) is still lower than the Super Fast Food (12).
Furthermore, the Burger Quick line ends at 30, indicating that there are some extreme outliers with extremely long wait times, which could raise the mean wait time. As a result, the correct answer is Super Fast Food, which has a higher median.
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Question 3 Not yet answered Find the inverse of the following function 8+5x f(x) = x+3 Marked out of 1.0 Flag question f(x)-1 = =
The inverse of f(x) is: [tex]f^{-1(x)}[/tex] = (x - 8)/5 switched the variables, so instead of [tex]f^{-1(x)}[/tex] , we wrote it as [tex]f^{-1(x)}[/tex] .
What is function?
In mathematics, a function is a relationship between two sets of elements, called the domain and the range, such that each element in the domain is associated with a unique element in the range.
To find the inverse of the function f(x) = 8 + 5x, we need to solve for x in terms of f(x).
Let y = f(x) = 8 + 5x
To find the inverse, we need to isolate x on one side of the equation:
y = 8 + 5x
y - 8 = 5x
x = (y - 8)/5
Therefore, the inverse of f(x) is:
[tex]f^{-1(x)}[/tex] = (x - 8)/5
Or, we can write it as:
[tex]f(x)^{-1}[/tex] = (x - 8)/5
Note that we switched the variables, so instead of [tex]f^{-1}[/tex] , we wrote it as [tex]f^{-1(x)}[/tex] .
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The measure of an angle is 39.4°. What is the measure of its complementary angle?
This is IXL
Answer:
50.6°
Step-by-step explanation:
complementary angles sum to 90° , that is
complementary angle + 39.4° = 90° ( subtract 39.4° from both sides )
complementary angle = 90° - 39.4° = 50.6°
Please solve the problem in the way requested in the question.Please type it so it's easier to understand. thank you verymuch!Let S be the set consisting of all infinite sequences of Os and 1s (each sequence is going on forever). Using an idea similar to the one we used for real numbers, prove that S is uncountable.
Since there is no way to list all the infinite sequences of 0s and 1s, we have proved that S is uncountable.
To show that S is uncountable, we need to show that there is no one-to-one correspondence between the set of infinite sequences of 0s and 1s and the set of natural numbers (which are used to count elements in a set).
We can use the diagonal argument, which is similar to the one used to show that the real numbers are uncountable.
Assume that S is countable, meaning that there is a way to list all the infinite sequences of 0s and 1s as a sequence: s1, s2, s3, ...
We can construct a new sequence t by choosing the opposite of each digit on the diagonal of the previous sequences: if the diagonal digit of s1 is 0, then the first digit of t is 1, and vice versa. Similarly, if the diagonal digit of s2 is 1, then the second digit of t is 0, and vice versa. And so on for all the diagonal digits.
The sequence t is guaranteed to be different from all the sequences in the original list, because it differs from each sequence at least at one position (the diagonal position). Therefore, t cannot be in the original list, which means that the original list did not include all the infinite sequences of 0s and 1s.
Since we have shown that there is no way to list all the infinite sequences of 0s and 1s, we have proved that S is uncountable.
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Write an explicit rule for each sequence
1. 3200, 1600, 800, 400, ...
2. 12, 84, 588, 4116, ...
3. 1395, 465, 155, 51.67, ...
i need this as soon as possible
posting more soon
The explicit rule for sequence 3200,1600,800, 400,... is aₙ = 3200(1/2)⁽ⁿ⁻¹⁾, the explicit rule for sequence 12, 84, 588, 4116, .. is aₙ = 12(7)⁽ⁿ⁻¹⁾, the explicit rule for sequence 1395, 465, 155, 51.67,... is aₙ = 1395(1/3)⁽ⁿ⁻¹⁾.
The common ratio in this geometric sequence is 1/2. Thus, the explicit rule for this sequence is given by
aₙ = 3200(1/2)⁽ⁿ⁻¹⁾
where aₙ represents the nth term of the sequence.
This sequence appears to be a geometric sequence where the common ratio is 7. Thus, the explicit rule for this sequence is
aₙ = 12(7)⁽ⁿ⁻¹⁾
where aₙ represents the nth term of the sequence.
This sequence appears to be a geometric sequence where the common ratio is 1/3. Thus, the explicit rule for this sequence is
aₙ = 1395(1/3)⁽ⁿ⁻¹⁾.
where aₙ represents the nth term of the sequence.
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Determine if the function below is continuous.
A. not continuous, 1 hole
B. continuous
C. not continuous, > 2 holes
D. not continuous, 2 holes
The function graphed below is is described as.
D. not continuous, 2 holes
What is a hole?When we speak of "holes" in the realm of continuous functions, it implies a spot wherein said function is not defined yet can become continuous once it has been allotted an appropriate value.
Examining the graph shows the presence of two holes hence making option D the best choice
The holes ate located at points
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HELP FAST. 2
If Tom travels 3 and 2/5 of a mile in 5 hours on his skateboard. How far will he travel in 1 hour?
Group of answer choices
17/25 miles per hour
15 miles per hour
1 and 8/17 miles per hour
25/17 miles per hour
Answer: 17/25 miles per hour
Step-by-step explanation:
In order to find your answer, you will need to divide 3 and 2/5 by 5 hours
or (3.4/5) which equals 0.68.
As a fraction, 0.68 is 17/25 which is your answer :)
And if you want to check your work, simply multiply 0.68 x 5 and you get 3.4 (which is 3 and 2/5's)!
Good Luck!
Let {N(t) : t ≥ 0} be a conditional Poisson process with rate L
that is distributed as Exp(λ). If T1 is the arrival time of the
first event of the process, show that the pdf of T1 is given
by�
The PDF of T1 is:
f(T1) = d/dt [P(T1 ≤ t)] = d/dt [1 - P(T1 > t)] = d/dt [1 - P(N(t) = 0)] = d/dt [1 - e^(-Lt)] = L * e^(-Lt)
So the PDF of T1 is an exponential distribution with parameter L.
To find the PDF of T1, we need to find the probability that the first event occurs at time t given that it has not occurred before time t. That is, we need to find P(T1 = t | N(t) = 0).
Using Bayes' rule, we have:
P(T1 = t | N(t) = 0) = P(N(t) = 0 | T1 = t) * P(T1 = t) / P(N(t) = 0)
Since T1 is the arrival time of the first event, we know that there are no events in the interval [0, t), so we can write:
P(N(t) = 0 | T1 = t) = P(N(t - T1) = 0)
Since {N(t) : t ≥ 0} is a conditional Poisson process with rate L that is distributed as Exp(λ), we know that the number of events in any interval of length t has a Poisson distribution with mean L*t. Therefore, the probability that there are no events in an interval of length t is:
P(N(t) = 0) = e^(-L*t)
So we can write:
P(T1 = t | N(t) = 0) = P(N(t - T1) = 0) * P(T1 = t) / e^(-L*t)
The probability density function (PDF) of the exponential distribution with parameter λ is given by:
f(x) = λ * e^(-λ*x)
Therefore, the PDF of T1 is:
f(T1) = d/dt [P(T1 ≤ t)] = d/dt [1 - P(T1 > t)] = d/dt [1 - P(N(t) = 0)] = d/dt [1 - e^(-Lt)] = L * e^(-Lt)
So the PDF of T1 is an exponential distribution with parameter L.
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A customer placed an order with a bakery for muffins. The baker has completed 37. 5% of the order after baking 81 muffins. How many muffins did the customer order?
If by the baking of 81 muffins, the baker has completed 37.5% of the order. The customer placed an order for 216 muffins.
Percent refers to the ratio of numbers where the denominator is 100. The percentage of a given number is calculated as the percentage divided by 100 and multiply the given number.
Percentage of baked muffins = 37.5%
Number of the baked muffin = 81
Let the number of muffins ordered be x
37.5% of x = 81
37.5/100 * x = 81
0.375x = 81
x = 81/0.375
x = 216
Thus, 216 muffins were ordered by the customer.
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Can someone help and check the image? PLEASE explain how you get your answer I need to understand it!
Answer:
The equation y = 75 - 2.85x represents the amount of money left on the gift card, where x is the number of Chai lattes Angie has purchased and y is the remaining gift card balance.
To find the x-intercept, we set y = 0 and solve for x:
0 = 75 - 2.85x
2.85x = 75
x = 26.32 (rounded to the nearest tenth)
So the x-intercept is approximately 26.3 Chai lattes, meaning that Angie can buy a maximum of 26 Chai lattes with her gift card.
To find the y-intercept, we set x = 0 and solve for y:
y = 75 - 2.85(0)
y = 75
So the y-intercept is $75, meaning that when Angie has not yet bought any Chai lattes, her gift card balance is $75.
To predict how many Chai lattes Angie has purchased when her gift card balance is about $35, we set y = 35 and solve for x:
35 = 75 - 2.85x
2.85x = 40
x = 14.04 (rounded to the nearest tenth)
So when Angie's gift card balance is about $35, she has purchased approximately 14 Chai lattes.
The inequality x2 – 5x + 3 < 3 can be broken down into two related inequalities. The graphs of these related inequalities are shown on the graph to the left. Which set shows the solution to the inequality? (0, 5) (–3.25, 3) (–∞, 0) ∪ (5, ∞) (–∞,–3.25) ∪ (3, ∞)
The inequality Ellen’s graph shows the solution to is, Negative 3.25 less-than negative 2.5 + r, the correct option is C.
Here, we have,
An Inequality is a statement that is formed when two expressions are joined using an inequality operator.
A number line is a line segment that depicts the real numbers marked at a fixed distance, like a coordinate axis.
A graph is a representation of the relation between two variables, a graph is useful in determining the equation of the variables.
A number line going from negative 1.25 to positive 0.75. An open circle is at negative 0.75, everything to the left of the circle is shaded.
An open circle represents the number that is not included.
x < -0.75
x < -3.25 +2.5
x -2.5 < 3.25
It can also be written as,
Negative 3.25 less-than negative 2.5 + r.
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complete question;
Ellen drew a graph showing the solution to an inequality.
A number line going from negative 1.25 to positive 0.75. An open circle is at negative 0.75. Everything to the left of the circle is shaded.
Which inequality does Ellen’s graph show the solution to?
3.25 less-than 2.5 + r
3.25 greater-than 2.5 + r
Negative 3.25 less-than negative 2.5 + r
Negative 3.25 greater-than negative 2.5 + r
Kaveh and Jessa baked a blueberry pie. They each ate 2/8 of the pie. How much of the pie is left?
Answer:1/2
Step-by-step explanation:
If they both ate 2/8 of the pie, that means they ate 4/8 of the pie in total, which means that they ate 1/2 when simplified. If they ate one half of the pie, it also means there is 1/2 of the pie left.
e government of preon (a small island nation) was voted in at the last election with 67% of the votes. that was 2 years ago, and ever since then the government has assumed that their approval rating has been the same. some recent events have affected public opinion and the government suspects that their approval rating might have changed. they decide to run a hypothesis test for the proportion of people who would still vote for them.the null and alternative hypotheses are:
The null hypothesis is that the proportion of people who would still vote for the government of Preon is still 67%, while the alternative hypothesis is that the proportion has changed from 67%.
The null hypothesis (H0) is that the proportion of people who would still vote for the government of Preon is still 67%, as it was at the last election.
The alternative hypothesis (H1) is that the proportion of people who would still vote for the government of Preon has changed from 67%, either increased or decreased.
In symbols, this can be written as:
H0: p = 0.67
H1: p ≠ 0.67
Where p is the proportion of people who would vote for the government of Preon in the upcoming election.
Note that the alternative hypothesis is two-tailed, indicating that the proportion could have either increased or decreased from 67%.
This is because the government suspects that their approval rating may have changed in either direction.
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A set of equations is given below:
Equation C: y = 6x + 9
Equation D: y = 6x + 2
Which of the following options is true about the solution to the given set of equations?
a
One solution
b
No solution
c
Two solutions
d
Infinite solutions
The solution to the given set of equations is, No solution.
We have to given that;
A set of equations is given below:
Equation C: y = 6x + 9
Equation D: y = 6x + 2
Now, We can see that;
y = 6x + 9
y = 6x + 2
Equate both equations, we get;
6x + 2 = 6x + 9
2 ≠ 9
Hence, We get;
The solution to the given set of equations is, No solution.
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now suppose that the bag has 7 white balls and 3 red balls. you draw one ball without looking. please type a number between 0 and 100 for the percent chance that the ball you draw is white. %
The percent chance that the ball you draw is white is 70%.
To find the percent chance of drawing a white ball, we will calculate the probability and then convert it into a percentage.
1. First, determine the total number of balls in the bag: 7 white balls + 3 red balls = 10 balls.
2. Next, determine the number of favorable outcomes, which is the number of white balls: 7 white balls.
3. Calculate the probability by dividing the number of favorable outcomes by the total number of balls: 7 white balls ÷ 10 balls = 0.7.
4. Convert the probability to a percentage by multiplying it by 100: 0.7 x 100 = 70%.
So, the percent chance that the ball you draw is white is 70%.
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11. Check the boxes for the translation(s) for each equation.
-(x - 2)² + 4
3x³
√x + 3
Reflection
Shift Left
Shift Right
Shift Up
Shift Down
Vertical Shrink
Vertical Stretch
√x+2
2
3
21x1-5
The translations of the functions are as follows
-(x - 2)² + 4Reflection
Shift Right
Shift Up
Identification of other translation 3x³Vertical Stretch: the coefficient of the factor x when it is greater than one results to vertical stretch
√(x + 3)Shift Left: this is translation of 3 units left
1/2√(x + 2)Vertical Shrink: the coefficient of the factor x when it is less than one results to vertical shrink
Shift Left: this is translation of 2 units left
3/2 x - 5Vertical Stretch: the coefficient of the factor x when it is greater than one results to vertical stretch. in this case 3/2 = 1.5 which is greater than one.
Shift Left: this is translation of 5 units left
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A conical paper cup has a diameter of 3 inches and a height of 3 inches. A cylindrical paper cup has a radius of 1.5
inches and a height of 3 inches. Suppose both cups are filled with water. If 1 cubic inch of water weighs 0.6 ounce,
how much more does the water in the cylindrical cup weigh? Round to the nearest tenth.
Answer:
8.5 ounces.
Step-by-step explanation:
The volume of the conical cup is given by the formula V = (1/3)πr²h, where r is the radius and h is the height. Since the diameter of the cup is 3 inches, the radius is 1.5 inches. Thus, the volume of the conical cup is:
V = (1/3)π(1.5²)(3) = 7.07 cubic inches
The volume of the cylindrical cup is given by the formula V = πr²h. Since the radius is 1.5 inches and the height is 3 inches, the volume of the cylindrical cup is:
V = π(1.5²)(3) = 21.2 cubic inches
To find the weight of the water in each cup, we need to multiply the volume of each cup by the weight of 1 cubic inch of water:
Weight of water in conical cup = 7.07 × 0.6 = 4.24 ounces
Weight of water in cylindrical cup = 21.2 × 0.6 = 12.72 ounces
Therefore, the water in the cylindrical cup weighs 12.72 - 4.24 = 8.48 more ounces than the water in the conical cup. Rounded to the nearest tenth, this is 8.5 ounces.
Rewrite 9 5/2 in radical form.
9 5/2 in radical form is equal to 4√2 + √7.
We are able to rewrite 9 5/2 in radical form through first changing it to an improper fraction.
9 5/2 = (9 x 2 + 5) / 2 = 23/2
Now, we can express 23/2 as a mixed radical by using locating the largest perfect square that may be a aspect of 23. the largest perfect square which is much less than 23 is 16 (that's 4^2).
So, we are able to write:
23/2 = 16/2 + 7/2 = 8 + 7/2
Now, we will express 8 + 7/2 in radical form as:
8 + 7/2 = 4 x 2 + 7/2 = 4√2 + √7
Consequently, 9 5/2 in radical form is equal to 4√2 + √7.
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