Solve for a.
60°
a
60°
a = [? ]°

The equation of the dilated line is 9x + 15y = 10.

In Geometry, a scale factor can be defined as the ratio of two corresponding side lengths or diameter in two similar geometric objects, which can be used to either vertically or horizontally enlarge (increase) or reduce (compress) a function representing their size.

Generally speaking, the transformation rule for the dilation of a geometric object or equation based on a specific scale factor of 3 is given by this mathematical expression:

(x, y)      →    (SFx, SFy)

Where:

Therefore, the transformation rule for this dilation is given by;

(x, y)      →    (3x, 3y)

3(3x + 5y) = 10

9x + 15y = 10.

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Answer:

It is a function

Step-by-step explanation:

It's a function because it does not over lapp

Answer: Linear

Step-by-step explanation:

I can tell from the table because there is a difference of 4 between each y value.

I dont know what the other blanks will be because i cant see the options. But it shouldnt be too hard to fill out

The expressions for [tex]x^6[/tex] can be varied, one such basic expression is [tex](x^n)^m[/tex], where n and m are positive integers equal to 2 and 3.

A grouping of numbers, variables, and operations like addition, subtraction, multiplication, division, exponentiation and more is known as an expression. A single number or variable can be an expression it can also include a combination of terms or functions.

By simplifying the [tex]x^6[/tex] we can get the expression-

[tex]x^6=(x^2)^3 \\\\x^6=(x^3)^2\\\\x^6=x^2 * x^4 \\\\x^6=(x^2 + 1 - 1)^6\\\\x^6=(x^3 - x^2 + x - 1 + 1)^2[/tex]

all these expressions represent [tex]x^6[/tex].

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The volume of the image is given as follows:

10626 ft³.

The volume of a prism is calculated as the multiplication of the base area of the prism by the height of the prism.

The bottom of the prism in this problem square base of side length 23 ft, along with height of 18 ft, hence:

Bottom volume = 18 x 18 x 23

Bottom volume = 7452 ft³.

The top of the prism also has square base of side length 23 ft, along with triangular height of 12 ft, hence:

Top volume = 0.5 x 12 x 23 x 23 (multiplies by 0.5 as the top is a triangle).

Top volume = 3174 ft³.

Hence the total volume of the prism is given as follows:

7452 + 3174 = 10626 ft³.

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Answer:To solve this problem, we need to use the formulas for the area and perimeter of a triangle.

Let's start by using the formula for the area of a triangle:

Area = (base x height) / 2

where base and height are the length and height of the triangle's base, respectively.

Let's assume that the base of the triangle is x meters, and the height is y meters. Then we have:

Area = (x*y)/2 = 0.45 m²

Solving for y, we get:

y = (2*0.45)/x

y = 0.9/x

Now, let's use the formula for the perimeter of a triangle:

Perimeter = a + b + c

where a, b, and c are the lengths of the three sides of the triangle.

Since we know that the perimeter is about 325 cm, we can assume that the three sides are close to each other in length. Let's assume that each side has a length of 325/3 = 108.33 cm.

Converting to meters, we get:

a = b = c = 108.33/100 = 1.0833 m

Now, we can use the formula for the area of a triangle again to solve for x:

Area = (base x height) / 2

0.45 = (x * 0.9/x) / 2

0.9 = x²

x = √0.9 = 0.9487 m

Therefore, the base of the triangle is approximately 0.9487 meters, and the height is approximately 0.9/0.9487 = 0.9487 meters.

So the triangle has sides of length 1.0833 meters and a base of length 0.9487 meters, which gives us a perimeter of approximately 3.215 meters (rounded to three decimal places).

Step-by-step explanation:

Answer:16.484

Step-by-step explanation:

find the area of a regular polygon with n sides and radius r, we can use the formula:

Area = (n * r^2 * sin(2*pi/n)) / 2

where pi is the mathematical constant pi (approximately equal to 3.14159).

Plugging in n = 14 and r = 1, we get:

Area = (14 * 1^2 * sin(2*pi/14)) / 2

= (14 * sin(pi/7)) / 2

≈ 16.484

Therefore, the area of the polygon with 14 sides and a radius of 1 unit is approximately 16.484 square units.

Answer:

Step-by-step explanation:The function y=log(x) is translated 1 unit right and 2 units down.

Answer: Given the following equations, determine the x value(s) that result in an equal output for both functions. f(x) = 3* g(x)=4x+1. C0 and 2.

Step-by-step explanation:

Given the following equations, determine the x value(s) that result in an equal output for both functions. f(x) = 3* g(x)=4x+1. C0 and 2.

Transformation is a function that takes points on the plane and maps them to other points on the plane.

Transformations can be applied one after the other in a sequence where you use the image of the first transformation as the pre image for the next transformation.

Find the image for each sequence of transformations.

 Using geometry software, draw a triangle and label the

vertices A, B, and C. Then draw a point outside the

triangle and label it P.

Rotate △ABC 30° around point P and label the image as

△A′B′C ′. Then rotate △A′B′C ′ 45° around point P and

label the image as △A″B″C ″. Sketch your result.

 Make a conjecture regarding a single rotation that will map △ABC to △A″B″C″.

Check your conjecture, and describe what you did.

 Using geometry software, draw a triangle and label the

vertices D, E, and F.

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(1) F(s) = 5+1 / (s^2 + 28s + 2)

To perform partial fraction expansion, we first need to factor the denominator:

s^2 + 28s + 2 = (s + 14 - sqrt(194))(s + 14 + sqrt(194))

We can then write:

F(s) = A / (s + 14 - sqrt(194)) + B / (s + 14 + sqrt(194))

where A and B are constants to be determined.

Multiplying both sides by the denominator and simplifying, we get:

5+1 = A(s + 14 + sqrt(194)) + B(s + 14 - sqrt(194))

Setting s = -14 - sqrt(194), we get:

5+1 = B(2sqrt(194))

Solving for B, we get:

B = (5+1) / (2sqrt(194))

Setting s = -14 + sqrt(194), we get:

5+1 = A(2sqrt(194))

Solving for A, we get:

A = (5+1) / (2sqrt(194))

Thus, the partial fraction expansion of F(s) is:

F(s) = [(5+1) / (2sqrt(194))] / (s + 14 + sqrt(194)) + [(5+1) / (2sqrt(194))] / (s + 14 - sqrt(194))

To find the inverse Laplace transform, we can use the table of Laplace transforms or MATLAB. Using MATLAB, we get:

ilaplace(F(s)) = (5+1) / (2sqrt(194)) * (exp(-14t) / sqrt(194)) * (cosh(sqrt(194)t) + sinh(sqrt(194)t))

(2) F(s) = s^2 + 3s + 1 / (s + 2)(s^2 + 8s + 1)

To perform partial fraction expansion, we first need to factor the denominator:

s^2 + 8s + 1 = (s + 4 - sqrt(15))(s + 4 + sqrt(15))

We can then write:

F(s) = A / (s + 2) + B / (s + 4 - sqrt(15)) + C / (s + 4 + sqrt(15))

where A, B, and C are constants to be determined.

Multiplying both sides by the denominator and simplifying, we get:

s^2 + 3s + 1 = A(s + 4 - sqrt(15))(s + 4 + sqrt(15)) + B(s + 2)(s + 4 + sqrt(15)) + C(s + 2)(s + 4 - sqrt(15))

Setting s = -4 + sqrt(15), we get:

-4 + sqrt(15) = A(-4 + sqrt(15) + 4 + sqrt(15))

Solving for A, we get:

A = (-4 + sqrt(15)) / (2sqrt(15))

Setting s = -4 - sqrt(15), we get:

-4 - sqrt(15) = A(-4 - sqrt(15) + 4 + sqrt(15))

Solving for A, we get:

A = (-4 - sqrt(15)) / (-2sqrt(15))

Setting s = -2, we get:

-1 = B(-2)(-2 + 4 + sqrt(15))

Solving for B, we get:

B = (-1) / (2sqrt(15) + 4)

Setting s =

The essay, "I, Pencil," illustrates that production of an ordinary wood pencil used for writing d. involves the cooperative efforts of millions of people, whose actions are directed through markets.

I, Pencil, an essay by Leonard Read portrays that the manufacture of a common wood pencil utilized for writing necessitates the collective efforts of millions of human beings whose activities are strictly regulated through markets.

The paper conveys that though an ordinary pencil looks like such a straightforward item, it is actually created from a complex system of people, procedures, and materials from far and wide. From timber harvesters who procure the wood, to the miners who take graphite out from the ground, to the employees in manufacturing plants who produce the finished article, the lead holder necessitates the orderly collaboration of multiple individuals and enterprises.

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The graph that correctly shows the boundary line for y ≤ 2x − 4, is B. Graph B.

The inequality y ≤ 2x − 4, shows that the y - intercept is - 4. What this means is that the boundary line must pass through ( 0, - 4 ). As Graphs C and D do not cross ( 0, - 4 ), neither of them can be the boundary line.

Also, when representing an inequality on a graph, the signs of ≤ and ≥ are presented with a solid line. > and < are the ones presented with a broken line. This means that Graph A cannot the boundary line for the inequality.

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6,000 mL is equal to 6 litres

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

We know that 6,000 mL  is equal to 6L

One litre is equal to 1000 ml

1 l = 1000 ml

6 l=6000 ml

Hence,  6,000 mL is equal to 6 litres

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Answer:

The result for the difference in lung cancer worry between males and females was not statistically significant in Hahn's (2017) study (t(45)=0.69, p > 0.05). The results for the differences in worry between smokers and nonsmokers, and those who did and did not graduate high school, were statistically significant with p values less than 0.05.

Step-by-step explanation:

Answer:

If 2:3 = x:12, then:

2/3 = x/12

Multiplying both sides by 12, we get:

x = 2/3 x 12 = 8

Therefore, the value of x is 8.

The velocity of the two cars are 50km/hr and 60km/h

Velocity is the rate of change of distance with time. it is measured in meter per second and it is a vector quantity.

let the faster car be A and slower car be B

V(A) = V(B) +10

S( A) = v × t

S(B) = v(b) × t

S( A) = 5( v(b) +10)

S(A) +S(B) = 550

5v(b) +50+5vb = 550

10v(b) = 550-50

v(b) = 500/10

v(b) = 50km/h

v(a) = 50 +10

v(a) = 60km/h

Therefore the velocity of the two cars are 50km/h and 60 km/h

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To calculate the three-sigma control limits, we first need to find the mean and standard deviation of the sample.

Here, we have,

The mean is:

μ = (4 + 12 + 16 + 8 + 9 + 6 + 5 + 12 + 15 + 7 + 6 + 4 + 2 + 11) / 14 = 8.071

The standard deviation is calculated using the standard deviation formula and is arrived at:

σ = 4.319

The three-sigma control limits are:

Upper control limit = μ + 3σ = 8.071 + (3 × 4.319) = 20.027

Lower control limit = μ - 3σ = 8.071 - (3 × 4.319) = -3.886

b. We can check if the process is in control by looking at whether any of the data points fall outside of the control limits.

From the given data, we can see that the maximum number of complaints is 16, which is well within the upper control limit of 20.027. The minimum number of complaints is 2, which is also well within the lower control limit of -3.886.

Therefore, based on the given data, we can conclude that the process is in control.

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Answer:

One.

Step-by-step explanation:

This polynomial has only one variable, which is x*. We can treat z and 7 as constants. Therefore, the polynomial is linear and can be written as:

5x* + c

where c = 7 - 3z.

A linear polynomial has either one root (when the coefficient is non-zero) or zero roots (when the coefficient is zero). Therefore, the given polynomial has exactly one root, which is:

x* = -c/5 = -(7 - 3z)/5 = (3z - 7)/5

Answer:

I am not sure if you wanted the answer in mm or m.  I gave the answer is m

v =  0.58875[tex]m^{3}[/tex]

Step-by-step explanation:

v = 1/3[tex]\pi r^{2} h[/tex]

v = 1/3 (3.14)([tex].075^{2}[/tex])(100)    The diameter 150mm is .0150m  Take have of that to find the radius

v =  0.58875[tex]m^{3}[/tex]

Answer:

I think its 221

Step-by-step explanation:

Answer:

The common ratio is 5.

30 ÷ 5 = 6.

Let n = 1 be the first term of this sequence.

[tex]a(n) = 6( {5}^{n} )[/tex]

The period of the function is 1/60 minutes

As a result, blood pressure changes between each heartbeat as a consequence of these oscilllations happening every second.

Max value = 110 mmHg

the minimum = 50 mmHg.

This suggests that systolic pressure remains at 110 mmHg and diastolic pressure is still maintained at 50 mmHg.

blood pressure peaks occur at times t = (1/2 + 2 * k) / 120 seconds.

(a) The given function is:

p(t) = 80 + 30 * sin(120 * pi * t)

This is equivalent to sinusoidal function in the form of:

p(t) = A + B * sin(C * t)

Where:

A is the baseline value,

B is the amplitude, and

C determines the frequency of the function.

Information given in the problem

A = 80, B = 30, and C = 120 * pi.

The period of a sinusoidal function is given by:

Period = 2 * pi / C

Period = 2 * pi / (120 * pi) = 1/60 minutes

The period of the function is 1/60 minutes, which means that the blood pressure oscillates every 1/60 minutes or 1 second. As a result, blood pressure changes between each heartbeat as a consequence of these oscilllations happening every second.

(b) maximum and minimum values of a sinusoidal function

Max value = A + B

Min value = A - B

Substituting the values of A and B:

Max value = 80 + 30 = 110 mmHg

Min value = 80 - 30 = 50 mmHg

Max value = A + B giving values of 110 mmHg

the minimum is A - B delivering 50 mmHg.

This suggests that systolic pressure remains at 110 mmHg and diastolic pressure is still maintained at 50 mmHg.

(c)  the time at which the blood pressure is at its maximum, we solve for t when the sinusoidal function is at its peak.

sin(120 * pi * t) = 1

Taking the inverse sine of both sides:

120 * pi * t = pi/2 + 2 * pi * k (where k is an integer)

Solving for t:

t = (1/2 + 2 x k)/120 (for k = 0, 1, 2, ......)

implying that blood pressure peaks occur at times t = (1/2 + 2 * k) / 120 seconds.

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The determinant of each of the given matrices are:

1) -4269

2) -1988

3) -68.92

The determinant of a matrix is a number that is specially defined only for square matrices. Determinants are mathematical objects that are very useful in the analysis and solution of systems of linear equations.

Thus:

1) [tex]\left[\begin{array}{ccc}7&&31\\142&&19\\\end{array}\right][/tex]

The determinant of this 2 x 2 matrix is:

(7 * 19) - (142 * 31) = -4269

2) [tex]\left[\begin{array}{ccc}7&11&21\\55&8&2\\-16&1&-9\end{array}\right][/tex]

The determinant of this 3 x 3 matrix is:

7((8*-9) - (1*2)) + 11((55*-9) - (2*-6)) + 21((55*1) - (8*-16)) = -1988

3) [tex]\left[\begin{array}{ccc}5.07&6.02&2.01\\-30.7&2.5&3.5\\3.55&-1.1&2.35\end{array}\right][/tex]

The determinant of this 3 x 3 matrix is:

5.07[(2.5 * 2.35) - (-1.1 *  3.5)] + 6.02[(-30.7 * 2.35) - (3.5 * 3.55)] + 2.01[(-30.7 * -1.1) - (2.5 * 3.55)] = -68.92

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Answer:

see explanation

Step-by-step explanation:

given a parabola in standard form

f(x) = ax² + bx + c ( a ≠ 0 )

then the equation of the axis of symmetry is

x = - [tex]\frac{b}{2a}[/tex]

f(x) = 2x² + 8x - 4 ← is in standard form

with a = 2, b = 8 , then equation of axis of symmetry is

x = - [tex]\frac{8}{2(2)}[/tex] = - [tex]\frac{8}{4}[/tex] = - 2

that is equation of axis of symmetry is x = - 2

the axis of symmetry passes through the vertex of the parabola

substitute x = - 2 into f(x) for corresponding y- coordinate

f(- 2) = 2(- 2)² + 8(- 2) - 4 = 2(4) - 16 - 4 = 8 - 20 = - 12

vertex = (- 2, - 12 )

the y- intercept is on the y- axis, where the x- coordinate is zero

substitute x = 0 into f(x)

f(0) = 2(0)² + 8(0) - 4 = 0 + 0 - 4 = - 4

y- intercept = - 4

The solution is,  the domain is: x ∈ (-∞, ∞).

Here, we have,

When we have two functions, f(x) and g(x), the composite function:

(f°g)(x)

is just the first function evaluated in the second one, or:

f( g(x))

And the domain of a function is the set of inputs that we can use as the variable x, we usually start by thinking that the domain is the set of all real numbers, unless there is a given value of x that causes problems, like a zero in the denominator, for example:

f(x) = 1/(x + 1)

where for x = -1 we have a zero in the denominator, then the domain is the set of all real numbers except x = -1.

Now, we have:

f(x) = x^2

g(x) = x + 9

then:

(f ∘ g)(x) = (x + 9)^2

And there is no value of x that causes problems here, so the domain is the set of all real numbers, that, in interval notation, is written as:

x ∈ (-∞, ∞)

(g ∘ f)(x)

this is g(f(x)) = (x^2) + 9 = x^2 + 9

And again, here we do not have any problem with a given value of x, so the domain is again the set of all real numbers:

x ∈ (-∞, ∞)

(f ∘ f)(x) = f(f(x)) = (f(x))^2 = (x^2)^2 = x^4

And for the domain, again, there is no value of x that causes a given problem, then the domain is the same as in the previous cases:

x ∈ (-∞, ∞)

(g ∘ g)(x) = g( g(x) ) = (g(x) + 9) = (x + 9) +9 = x + 18

And again, there are no values of x that cause a problem here,

so the domain is:

x ∈ (-∞, ∞)

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complete question:

Consider the following functions. f(x) = x2, g(x) = x + 9 Find (f ∘ g)(x). Find the domain of (f ∘ g)(x). (Enter your answer using interval notation.) Find (g ∘ f)(x). Find the domain of (g ∘ f)(x). (Enter your answer using interval notation.) Find (f ∘ f)(x). Find the domain of (f ∘ f)(x). (Enter your answer using interval notation.) Find (g ∘ g)(x). Find the domain of (g ∘ g)(x). (Enter your answer using interval notat

Answer:

C is correct because parallel lines cut by a transversal form congruent alternate interior angles.