"Solve for x. Enter as a decimal not as a fraction. Round to the nearest hundredth if necessary."

"Solve For X. Enter As A Decimal Not As A Fraction. Round To The Nearest Hundredth If Necessary."

Answers

Answer 1

Answer:

x =

5

Explanation

From the given diagram, it can be infered that WY = 2QR

From the diagram

WY = x+9

QR = 2x-3

substitute into the expression

x+9 = 2(2x-3)

x+9 = 4x - 6

Collect the like terms

x-4x = -6-9

-3x = -15

x = -15/-3

x = 5

Hence the value of x is 5


Related Questions

Find the limit. (If an answer does not exist, enter DNE.)

Answers

Given:

[tex]\lim _{\Delta x\to0}\frac{6(x+\Delta x)-6x_{}}{\Delta x}[/tex]

Solve as:

[tex]\begin{gathered} \lim _{\Delta x\to0}\frac{6x+6\Delta x-6x}{\Delta x}=\lim _{\Delta x\to0}\frac{6\Delta x}{\Delta x} \\ =6 \end{gathered}[/tex]

Hence, the required answer is 6.

5. Monty compared the minimum of the function f(x) = 2x2 - x + 6 to theminimum of the quadratic function that fits the values in the table below.X-3-2-101g(x)0-5-6-34What is the horizontal distance between the minimums of the twofunctions?A 0.25B. 1C. 1.5D. 12

Answers

The function f is given by:

[tex]\begin{gathered} f(x)=2x^2-x+6 \\ \text{ Rewrite the quadratic function in vertex form} \\ f(x)=2(x^2-\frac{1}{2}x)+6 \\ =2((x-\frac{1}{4})^2-(-\frac{1}{4})^2)+6 \\ =2(x-\frac{1}{4})^2-2(\frac{1}{16})+6 \\ =2(x-\frac{1}{4})^2+\frac{47}{8} \end{gathered}[/tex]

If a quadratic function is written in the form:

[tex]\begin{gathered} a(x-h)^2+k \\ where: \\ a>0 \end{gathered}[/tex]

Then the function has a minimum point at (h,k)

And the minimum is k

In this case,

[tex]\begin{gathered} a=2\gt0 \\ h=\frac{1}{4}=0.25 \\ k=\frac{47}{8}=5.875 \end{gathered}[/tex]

Therefore, the minimum of the function f is at (0.25, 5.875)

The minimum of the function given by the table is at (-1, -6).

Therefore, the required horizontal distance is given by:

[tex]0.25-(-1)=1.25[/tex]

Therefore, the horizontal distance is 1.25

Hi, can you help me to solve this exercise please, it’s about Function Evaluation & Applications!

Answers

Given

[tex]f(x)=\lvert x\rvert+4[/tex]

Part A

[tex]\begin{gathered} we\text{ want to find f(4)} \\ we\text{ only n}eed\text{ to substitute the value of 4 to x in the given function} \\ f(4)=\lvert4\rvert+4 \\ f(4)=4+4_{} \\ f(4)=8 \end{gathered}[/tex]

Part B

[tex]\begin{gathered} we\text{ want to evaluate f(-4)} \\ \text{note that the absolute value returns postive values} \\ \text{thus, }\lvert-4\rvert=4 \\ f(-4)=\lvert-4\rvert+4 \\ f(-4)=4+4 \\ f(-4)=8 \end{gathered}[/tex]

Part C

[tex]\begin{gathered} To\text{ find f(t), we only n}eed\text{ to replace t with x} \\ f(t)=\lvert t\rvert+4 \end{gathered}[/tex]

What is the value of y in the solution set of the system of linear equations shown below?y = -x + 124x - 2y = 36A.10B. 8C. 6D. 2

Answers

y = 2 (option D)

Explanation:

y = -x + 12

4x - 2y = 36

rewriting the equations:

y + x = 12 ....equation 1

-2y + 4x = 36 ....equation 2

Using elimination method:

we will be eliminating y. So we need to make the coefficient of y to be the same in both equation. We will be multiplying the first equation by 2.

2y + 2x = 24 ....equation 1

-2y + 4x = 36 ....equation 2

Add both equations:

2y + (-2y) + 2x + 4x = 24 + 36

2y-2y + 6x = 60

6x = 60

x = 60/6 = 10

Insert the value of x in any of the equation. Using equation 2:

4(10) - 2y = 36

40 -2y = 36

-2y = 36 - 40

-2y = -4

y = -4/-2

y = 2 (option D)

ranslateSave & Exit CertifyLesson: 10.2 Parabolas11/15Question 9 of 9, Step 1 of 1CorrectFind the equationof the parabola with the following properties. Express your answer in standard form.

Answers

Given

[tex]undefined[/tex]

Solution

Standard from of a parabola

[tex](x-H-h)^2=4p(y-k)[/tex]

csc 0 (sin2 0 + cos2 0 tan 0)=sin 0 + cos 0= 1

Answers

Okay, here we have this:

Considering the provided expression, we are going to prove the identity, so we obtain the following:

[tex]\frac{csc\theta(sin^2\theta+cos^2\theta tan\theta)}{sin\theta+cos\theta}=1[/tex][tex]\frac{\frac{1}{sin\vartheta}(sin^2\theta+cos^2\theta\frac{sin\theta}{cos\theta})}{sin\theta+cos\theta}=1[/tex][tex]\frac{\frac{1}{sin\vartheta}(sin^2\theta+cos\text{ }\theta sin\theta)}{sin\theta+cos\theta}=1[/tex][tex]\frac{(\frac{sin^2\theta}{sin\theta}+\frac{cos\text{ }\theta sin\theta}{sin\theta})}{sin\theta+cos\theta}=1[/tex][tex]\frac{(sin\text{ }\theta+cos\text{ }\theta)}{sin\theta+cos\theta}=1[/tex][tex]\frac{1}{1}=1[/tex][tex]1=1[/tex]

Find the midpoint M of the line segment joining the points R = (-5. -9) and S = (1. -1).

Answers

Answer:

(-2,-5)

Step-by-step explanation:

(-5+1÷2, -9+(-1)÷2)

=(-4÷2, -10÷2)

=(-2,-5)

If the price of bananas goes from $0.39 per pound to $1.06 per pound, what is the likely effect of quantity demanded?

Answers

When the price of bananas goes from $0.39 per pound to $1.06 per pound, the likely effect of quantity demanded is that it will reduce.

What is demand?

The quantity of a commodity or service that consumers are willing and able to acquire at a particular price within a specific time period is referred to as demand. The quantity required is the amount of an item or service that customers will purchase at a certain price and period.

Quantity desired in economics refers to the total amount of an item or service that consumers demand over a given time period. It is decided by the market price of an item or service, regardless of whether or not the market is in equilibrium.

A price increase nearly invariably leads to an increase in the quantity supplied of that commodity or service, whereas a price decrease leads to a decrease in the quantity supplied. When the price of good rises, so does the quantity requested for that good. When the price of a thing declines, the demand for that good rises.

Learn more about demand on:

https://brainly.com/question/1245771

#SPJ1

Ary is writing thank you cards to everyone who came to her wedding. It takes her of an hour to write one thank you card. If it took her 8 hours to finish writing all of the cards, how many thank you cards did she write?

Answers

From the question, It takes Ary an hour to write one thank you card.

So, the rate at which she writes the thank you card is;

[tex]\text{Rate R}=1\text{ card/hour}[/tex]

To determine the number N of thank you card she would write in 8 hours.

[tex]N=R\times T[/tex]

Where;

R is the rate = 1 card/hour

T is the time taken = 8 hours

Substituting the values we have;

[tex]\begin{gathered} N=1\text{ card/hour}\times8\text{ hours} \\ N=8\text{ cards} \end{gathered}[/tex]

The number of thank you cards she write is 8 cards

9. Solve the system of equations algebraically. Show your reasoning.2y = x -44x + 3y = 5

Answers

I) 2y = x - 4

II) 4x + 3y = 5

First, we put all the variables on the same side subtracting x from both sides of equation I:

I) 2y - x = -4

II) 3y + 4x = 5

Now, we multiply equation I by 4:

I) 8y - 4x = -16

II) 3y + 4x = 5

Then, we add equation I to equation II:

I) 8y - 4x = -16

II) 11y = -11

Therefore, we got from equation II:

y = -11/11 = -1

Applying this result on equation I, we got:

-8 - 4x = -16

4x = 8

x = 8/4 = 2

Final answer: (x,y) = (2,-1)

2x^2 +6x=-3 can you compute this?

Answers

The general formula for a quadratic equation is ax² + bx + c = 0.

To solve

[tex]2x^2+6x=-3[/tex]

You can follow the steps.

Step 01: Write the equation in the general formula.

To do it, add 3 to each side of the equation.

[tex]\begin{gathered} 2x^2+6x+3=-3+3 \\ 2x^2+6x+3=0 \end{gathered}[/tex]

Step 02: Use the Bhaskara formula to find the roots.

The Bhaskara formula is:

[tex]x=\frac{-b\pm\sqrt[]{\Delta}}{2\cdot a},\Delta=b^2-4\cdot a\cdot c[/tex]

In this question,

a = 2

b = 6

c = 2

So, substituting the values:

[tex]\begin{gathered} \Delta=b^2-4\cdot a\cdot c \\ \Delta=6^2-4\cdot2\cdot3 \\ \Delta=36-24 \\ \Delta=12 \\ \\ x=\frac{-6\pm\sqrt[]{12}}{2\cdot2} \\ x=\frac{-6\pm\sqrt[]{2\cdot2\cdot3}}{4} \\ x=\frac{-6\pm2\cdot\sqrt[]{3}}{4} \\ x_1=\frac{-6+2\sqrt[]{3}}{4}=\frac{-3+\sqrt[]{3}}{2} \\ x_2=\frac{-6-2\sqrt[]{3}}{4}=\frac{-3-\sqrt[]{3}}{2} \end{gathered}[/tex]

Answer:

Exact form:

[tex]x=\frac{-3-\sqrt[]{3}}{2},\frac{-3+\sqrt[]{3}}{2}[/tex]

Decimal form:

[tex]x=-2.37,\text{ -0.63}[/tex]

what is the slope of a line perpendicular to this linewhat is the slope of a line parallel to this line

Answers

Answer:

• Slope perpendicular to the line: 8/5

,

• Slope parallel to the line: –5/8

Explanation

Given

[tex]5x+8y=7[/tex]

To know the result, it is better if we work with the slope-intercept form:

[tex]y=mx+b[/tex]

Then, to get this kind of form we have to isolate y from the given equation:

[tex]8y=7-5x[/tex][tex]y=\frac{7-5x}{8}[/tex][tex]y=-\frac{5}{8}x+\frac{7}{8}[/tex]

Thus, in this case, m = –5/8 and b = 7/8.

Perpendicular lines have negative reciprocal lines:

[tex]m_2=-\frac{1}{m_1}[/tex]

where m₁ is the slope of line 1 and m₂ is the line perpendicular to line 1.

Then, replacing the values:

[tex]m_2=-\frac{1}{-\frac{5}{8}}[/tex][tex]m_2=\frac{8}{5}[/tex]

Finally, the slopes of parallel lines are the same, meaning:

[tex]m_2=m_1[/tex]

where m₁ is the slope of line 1 and m₂ is the line parallel to line 1.

Jordan’s of Boston sold Lee Company of New York computer equipment with a $7,000 list price. Sale terms were 4/10, n/30 FOB Boston. Jordan’s agreed to pay the $400 freight. Lee pays the invoice within the discount period. What does Lee pay Jordan’s?

Answers

see that you have come to us today regarding a sale issue.
I’m sorry to hear about your issues. When a vendor invoice includes terms of 4/10, n/30, the "4" represents 4% of the amount owed, the "10" represents 10 days, the "n" represents the word "net," and the "30" represents 30 days. The terms 4/10, n/30 indicate that the buyer may take an early payment discount of 4% of the amount owed if the amount owed is remitted within 10 days instead of the normal 30 days. In other words, the buyer can choose either of the following:
Pay within 10 days and deduct 4% of the net amount owed (the invoice amount minus any authorized returns and/or allowances), or
Pay in 30 days and take no discount.
Free On Board (FOB) Contract is a trade term requiring the seller to deliver goods on board a vessel designated by the buyer. When used in trade terms, the word "free" means the seller has an obligation to deliver goods to a named place for transfer to a carrier. That is not relevant to the price though.
So Lee would be paying $7000 with a 4% discount; or $280 off. So Lee would pay $6,720 if Jordan pays the freight.
I do certainly hope you find this information helpful. My goal is to make sure you are satisfied with the information provided. In the event you have any further questions or need further information, I am going to be available for the next few hours.

A recycle bucket weighs 3.5 lb at the beginning of the school year in August. At the beginning of December it weighed 21.5 lb. Determine the weight gain per month.

Answers

Answer:

4.5 pounds

Step-by-step explanation:

21.5 - 3.5 = 18

We divide that by 4 (Aug., Sept, Oct. Nov.)

18/4 = 4.5

Answer:

6.144

Step-by-step explanation:

10. Calculate the circumference of cylinder that is 34cm tall and has a volume of560cm#9

Answers

The Solution.

By formula, the volume of the planet (sphere) is given as below:

[tex]V=\frac{4}{3}\pi r^3[/tex]

In this case,

[tex]\begin{gathered} V=5.10^{18}km^3 \\ r=\text{?} \end{gathered}[/tex]

Substitting these given values into the formula above, we can solve for r, the radius of the planet.

[tex]\frac{4}{3}\pi r^3=5(10^{18})[/tex]

Dividing both sides by

[tex]\frac{4}{3}\pi[/tex]

We get

[tex]r^3=\frac{5\times10^{18}}{\frac{4}{3}\pi}=\frac{5\times10^{18}}{4.188790205}[/tex]

Taking the cube root of both sides, we have

[tex]\begin{gathered} r=\sqrt[3]{(}\frac{5\times10^{18}}{4.188790205})=(1.060784418\times10^6)km^{} \\ Or \\ r=1060784.418\text{ km} \end{gathered}[/tex]

Thus, the correct answer is 1060784.418km.

Gina want to estimate the total of three bills she has to pay. the bills are for $125,$115,and $138. Gina wants to make sure that she has enough money. she wants the estimate to be greater than the total of the bills. should she round to the nearest ten or hundred

Answers

The bills are:

125

115

138

Since she wants an estimate that is greater than the actual total, she can round these numbers to the nearest ten.

125 will be rounded to the next tens, which is 130

115 will also be rounded to the next tens, which is 120

138 gets bumped to the next tens, that is 140

The total estimate is the sum of the 3 estimates we just made. That is:

130 + 120 + 140 = $390

A system of equations is shown below:Equation A: 3c = d − 8Equation B: c = 4d + 8Which of the following steps should be performed to eliminate variable d first?Multiply equation A by −4.Multiply equation B by 3.Multiply equation A by 3.Multiply equation B by 4.

Answers

We have the following: system of equations:

A: 3c=d-8

B: c=4d+8

To eliminate variable d first, if we want to use elimination method, we need to have variable d in both equations with the same coefficient but with different signs.

As in equation B, the coefficient of d is 4, then we need to have in equation A a coefficient of -4 for variable d.

Then the answer is we need to multiply equation A by -4.

Which equation could be represented by the number line? A. 3 OB.-4 5=1 OC. 1+ -5)= OD. -3+4 -1

Answers

According to the given number line, we have to go back from the second point to the first point 4 spots. In other words, the equation has to include a sum with -4.

Therefore, the answer is A since it's expressing an initial number 3, then the sum with -4.

Can anybody help me out with this? I would really appreciate it! I don't need a huge explanation just the answer and a BRIEF explanation on how you got it.

Answers

The range of the following function is

[tex]\mleft\lbrace y>1\mright\rbrace[/tex]

We can also call the range of a function an image, the range or image of a function is a set, we can see this set looking at the graph and see which values of y the function have, remember that we can have the same y value for different x value, looking at our graph we can see that this function comes from high y values, have a vertex on (3,1), in other words, it stops at y = 1 and then start growing again, and go on repeated values of y, then we can say that the image (values of y that the function assumes) is all values bigger than 1, therefore {y > 1}.

Suppose that $6000 is placed in an account that pays 19% interest compounded each year. Assume that no withdrawals are made from the account.

Answers

We are going to use the formula for the compound interest, which is

[tex]A=P\cdot(1+\frac{r}{n})^{nt}[/tex]

A = the future value of the investment

P = the principal investment amount (the initial deposit or loan amount)

r = the annual interest rate (decimal)

n = the number of times that interest is compounded per unit t

t = the time the money is invested or borrowed for

Replacing the values in the first question we have:

[tex]\begin{gathered} A=P\cdot(1+\frac{r}{n})^{nt} \\ A=6000,r=0.19,n=1,t=1 \\ A=6000\cdot(1+\frac{0.19}{1})^1=7140 \end{gathered}[/tex]

Answer for the first question is : $7140

Then, replacing the values in the second question we have:

[tex]\begin{gathered} A=P\cdot(1+\frac{r}{n})^{nt} \\ A=6000,r=0.19,n=1,t=2 \\ A=6000\cdot(1+\frac{0.19}{1})^2=8497 \end{gathered}[/tex]

Answer for the second question is : $8497

May I please get help finding the length to this. I tried many times.m but I couldn’t find answer for it

Answers

Both triangles are similar, so:

[tex]\frac{x}{3}=\frac{6}{4.5}[/tex]

Solving for x:

4.5x = 3(6)

4.5x = 18

x = 4

helpppppppppppppppppppppppppppppp

Answers

De el puo Le je qua 510

skill issue hahahahahhaahahhahaha

A bug is moving along a straight path with velocity v(t)= t^2-6t+8 for t ≥0. Find the total distance traveled by the bug over interval [0,6].

Answers

Answer

Explanation

Given:

A bug is moving along a straight path with velocity

[tex]V(t)=t^2-6t+8\text{ }for\text{ }t>0[/tex]

What to find:

The total distance traveled by the bug over interval [0, 6].

Solution:

To find the total distance traveled by the bug over interval [0, 6], you first integrate v(t)= t² - 6t + 8

[tex]\begin{gathered} \int_0^6t^2-6t+8 \\ \\ [\frac{t^3}{3}-\frac{6t^2}{2}+8t]^6_0 \\ \\ (\frac{t^3}{3}-3t^2+8t)^6-(\frac{t^{3}}{3}-3t^2+8t)^0 \\ \\ (\frac{6^3}{3}-3(6)^2+8(6))-(\frac{0^3}{3}-3(0)^2+8(0)) \\ \\ (\frac{216}{3}-3(36)+48)-(0-0+0) \\ \\ 72-108+48-0 \\ \\ =12\text{ }units \end{gathered}[/tex]

f (x) = 4x^2+2x+6find the value of the discriminate of f and how many distinct real number zeros f has.

Answers

The Solution:

Given:

Required:

To find the discriminant of f.

By formula, the discriminant (D) is:

[tex]D=b^2-4ac[/tex]

Where:

[tex]\begin{gathered} a=4 \\ b=2 \\ c=6 \end{gathered}[/tex]

Substitute:

[tex]\begin{gathered} D=2^2-4(4)(6)=4-96=-92 \\ No\text{ real root since D}<0 \end{gathered}[/tex]

Therefore, the correct answers are:

Discriminant = -92

No distinct real root.

You are taking 2 shirts(white and red) and 3 pairs of pants (black, blue, and gray) on a trip. How many different choices of outfits do you have?

Answers

6 because 2 times 3 = 6

the line that passes through point (-1,4) and point (6,y) has a slope of 5/7. find y.

Answers

Question: the line that passes through the point (-1,4) and point (6,y) has a slope of 5/7. find y.

Solution:

By definition, the slope of a line is given by the formula:

[tex]m\text{ = }\frac{Y2-Y1}{X2-X1}[/tex]

where m is the slope of the line and (X1,Y1), (X2,Y2) are any two points on the line. In this case, we have that:

(X1,Y1) = (-1,4)

(X2,Y2) = (6,y)

m = 5/7

thus, replacing the above data into the slope equation, we get:

[tex]\frac{5}{7}\text{= }\frac{y-4}{6+1}\text{ }[/tex]

this is equivalent to:

[tex]\frac{5}{7}\text{= }\frac{y-4}{7}\text{ }[/tex]

By cross-multiplication, this is equivalent to:

[tex]\text{5 = y-4}[/tex]

solving for y, we get:

[tex]y\text{ = 5+ 4 = 9}[/tex]

then, we can conclude that the correct answer is:

[tex]y\text{ =9}[/tex]

find the solution of this system of equations-7y=-34-2x2x+4y=10

Answers

we have the system

-7y=-34-2x ------> equation A

2x+4y=10​ ------> equation B

In the equation A

Multiply by -1

-2x+7y=34------> new equation A

Adds new equation A and equation B

-2x+7y=34

2x+4y=10

------------------

7y+4y=34+10

11y=44

y=4

Find the value of x

Substitute the value of y in equation A or equation B

2x+4(4)=10​

solve for x

2x+16=10

2x=10-16

2x=-6

x=-3

therefore

the solution is the point (-3,4)

What is the average rate of change of the function f(x) = 2x^2 + 4 over the interval (-4,-1] ?

Answers

The average rate of change is:

[tex]\frac{f(-1)-f(-4)}{-1+4}=\frac{f(-1)-f(-4)}{3}[/tex][tex]f(-1)=2(-1^2)+4=6[/tex][tex]f(-4)=2(-4^2)+4=2(16)+4=36[/tex]

then computing the first formula, the average rate of change of f(x) is

[tex]\frac{6-36}{3}=-10[/tex]

Given the functions f(x) = x ^ 2 + 3x - 1 and g(x) = - 2x + 3 determine the value of (f + g)(- 2)

Answers

Start by finding (f+g)(x)

[tex](f+g)(x)=(x^2+3x-1)+(-2x+3)[/tex]

simplify the equation

[tex]\begin{gathered} (f+g)(x)=x^2+(3x-2x)-1+3 \\ (f+g)(x)=x^2+x+2 \end{gathered}[/tex]

then, replace x by -2

[tex]\begin{gathered} (f+g)(-2)=(-2)^2+(-2)+2 \\ (f+g)(-2)=4-2+2 \\ (f+g)(-2)=4 \end{gathered}[/tex]

(C3) In how many distinct ways can theletters of the word LILLYPILLY bearranged?A. 3.628.800B. 480C. 7.560D. 120.960.

Answers

We have:

L = 5 L's

I = 2 I's

P = 1 P

Y = 2 Y's

so:

[tex]\frac{10!}{5!2!2!}=7560[/tex]

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