In order to solve the equation for y, we just need to isolate the variable y in one side of the equation. So we have:
[tex]\begin{gathered} \frac{1}{3}x+y=4 \\ y=4-\frac{1}{3}x \end{gathered}[/tex]So the answer is y = 4 - 1/3 x
I need your help know
Given the following data
Base area of the cone = 6cm
Height of the cone = 9 cm
The volume of a cone is given as
[tex]\begin{gathered} V\text{ = }\frac{1}{3}\cdot\text{ }\pi\cdot r^2\cdot\text{ h} \\ \text{where }\pi\text{ = 3.14},\text{ r = 6cm , and h = 9cm} \\ V\text{ = }\frac{1}{3}\cdot\text{ 3.14 }\cdot6^2\cdot\text{ 9} \\ V\text{ = }\frac{1}{3}\text{ x 3.14 x 36 x 9} \\ V\text{ = }\frac{3.14\text{ x 36 x 9}}{3} \\ V\text{ = }\frac{1017.36}{3} \\ V=339.1cm^3 \end{gathered}[/tex]what are the coordinates of the focus of the conic section shown below (y+2)^2/16-(x-3)^2/9=1
Given the function of the conic section:
[tex]\mleft(y+2\mright)^2/16-\mleft(x-3\mright)^2/9=1[/tex]This conic section is a hyperbola.
Use this form below to determine the values used to find vertices and asymptotes of the hyperbola:
[tex]\frac{(x-h)^2}{a^2}\text{ - }\frac{(y-k)^2}{b^2}\text{ = }1[/tex]Match the values in this hyperbola to those of the standard form.
The variable h represents the x-offset from the origin b, k represents the y-offset from origin a.
We get,
a = 4
b = 3
k = 3
h = -2
A. The first focus of a hyperbola can be found by adding the distance of the center to a focus or c to h.
But first, let's determine the value of c. We will be using the formula below:
[tex]\sqrt[]{a^2+b^2}[/tex]Let's now determine the value of c.
[tex]\sqrt[]{a^2+b^2}\text{ = }\sqrt[]{4^2+3^2}\text{ = }\sqrt[]{16\text{ + 9}}\text{ = }\sqrt[]{25}[/tex][tex]\text{ c = 5}[/tex]Let's now determine the coordinates of the first foci:
[tex]\text{Coordinates of 1st Foci: (}h\text{ + c, k) = (-2 + 5, 3) = 3,3}[/tex]B. The second focus of a hyperbola can be found by subtracting c from h.
[tex]\text{ Coordinates of 2nd Foci: (h - c, k) = (-2 - 5, 3) = -7,3}[/tex]Therefore, the conic section has two focus and their coordinates are 3,3 and -7,3.
In other forms, the foci of the hyperbola is:
[tex]\text{ }(h\text{ }\pm\text{ }\sqrt[]{a^2+b^2},\text{ k) or (-2 }\pm\text{ 5, 3)}[/tex]Therefore, the answer is letter B.
Answer :It's A lol
Step-by-step explanation:
Solve. Your answer should be in simplest form. 2/5 (−3/7)
Answer:
2/5 (-3/7) = -6/35 ≅ -0.1714286
Step-by-step explanation:
and that’s how you do it
Add: 2/5 + 3/7 = 2 · 7/5 · 7 + 3 · 5/7 · 5 = 14/35 + 15/35 = 14 + 15/35 = 29/35.
It is suitable to adjust both fractions to a common (equal, identical) denominator for adding, subtracting, and comparing fractions. The common denominator you can calculate as the least common multiple of both denominators - LCM(5, 7) = 35. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 5 × 7 = 35. In the following intermediate step, it cannot further simplify the fraction result by canceling.
In other words - two fifths plus three sevenths is twenty-nine thirty-fifths.
Which measurement is closest to the area of the triangle in square centimeters? A 63 cm2 B 42.75 cm2 С 35.5 cm2 D 31.5 cm2
The measurement shows that the base of the triangle is approximately 7 cm
while the height is approximately 9cm
The area of the triangle is given by
[tex]\text{Area = }\frac{1}{2}\text{ x base x height}[/tex][tex]\begin{gathered} \text{Area =}\frac{1}{2}\text{ x 7 x 9} \\ \text{Area = }\frac{63}{2}cm^2 \\ \\ \text{Area = 31.5cm}^2 \end{gathered}[/tex]Option D is the closest to the answer
what is 6!3! over 2!5!
Answer:
16
Step-by-step explanation:
6!3!
-------
2!5!
(1 × 2 × 3 × 4 × 5 × 6)(1 × 2 × 3)
--------------------------------------------
(1 × 2)(1 × 2 × 3 × 4 × 5)
(720)(6)
-------------------
(2)(120)
4320
------------ = 18
240
I hope this helps!
solve 6 + 5 on the sqr root of 249 - 2x = 7
ANSWER
x = 124
EXPLANATION
First we have to clear the term that contains x in the equation. In this case, this term is the second term. So we have tu subtract 6 from both sides of the equation:
[tex]\begin{gathered} 6-6+\sqrt[5]{249-2x}=7-6 \\ \sqrt[5]{249-2x}=1 \end{gathered}[/tex]Then, we have to eliminate the root. Note that in the expression inside the root there are two terms. To do this, we have to apply the "opposite" operation on both sides of the equation, which in this case is exponent 5:
[tex]\begin{gathered} (\sqrt[5]{249-2x})^5=1^5 \\ 249-2x=1 \end{gathered}[/tex]Now we do something similar to the first step. We want to leave on one side of the equation only the term that contains x and the rest on the other side. To do this we can either add 2x on both sides, or subtract 249 from both sides. We'll apply the first option because then we'll have a positive coefficient for x:
[tex]\begin{gathered} 249-2x+2x=1+2x \\ 249=1+2x \end{gathered}[/tex]However, we now have to subtract 1 from both sides of the equation:
[tex]\begin{gathered} 249-1=1-1+2x \\ 248=2x \end{gathered}[/tex]Finally, to find x, we have to divide both sides by 2:
[tex]\begin{gathered} \frac{248}{2}=\frac{2x}{2} \\ 124=x \end{gathered}[/tex]Hence, the solution to the equation is x = 124.
Find sin 2x, cos 2x, and tan 2x if tan x= -3/2 and x terminates in quadrant IV.
• sin 2x = -12/13
,• cos 2x = -5/13
,• tan 2x = 12/5
Explanation:Given that
[tex]\tan x=-\frac{3}{2}[/tex]Then
[tex]\begin{gathered} \sin2x=\frac{2\tan x}{1+\tan^2x} \\ \\ =\frac{2(-\frac{3}{2})}{1+(-\frac{3}{2})^2}=\frac{-3}{\frac{13}{4}} \\ \\ =-3\times\frac{4}{13}=-\frac{12}{13} \end{gathered}[/tex][tex]\begin{gathered} \cos2x=\frac{1-\tan^2x}{1+\tan^2x}=\frac{1-(-\frac{3}{2})^2}{1+(-\frac{3}{2})^2} \\ \\ =\frac{1-\frac{9}{4}}{1+\frac{9}{4}}=\frac{-\frac{5}{4}}{\frac{13}{4}}=-\frac{5}{4}\times\frac{4}{13}=-\frac{5}{13} \end{gathered}[/tex][tex]\begin{gathered} \tan2x=\frac{2\tan x}{1-\tan^2x}=\frac{2(-\frac{3}{2})}{1-(-\frac{3}{2})^2} \\ \\ =\frac{-3}{1-\frac{9}{4}}=\frac{-3}{-\frac{5}{4}}=-3\times\frac{-4}{5}=\frac{12}{5} \end{gathered}[/tex]The mean height of women in a country (ages 20-29) is 63.6 inches. A random sample of 70 women in this age group are selected. What is the probability that the mean height for the sample is greater than 64 inches?Assuming sigma= 2.53 inches
We have a mean of 63.6 inches and a standard deviation of 2.53 inches. We want to find the probability for our random sample to have a greater mean than 64 inches. We can do that by finding the probability of getting women higher than 64 inches in the original group. To do that, we're going to use a z-table.
First, let's convert 64 inches to a z-score:
[tex]\begin{gathered} z(64)=\frac{64-\mu}{\sigma/\sqrt[]{n}}=\frac{64-63.6}{2.53/\sqrt[]{70}}=\frac{0.4\sqrt[]{70}}{2.53}=1.32278265065\ldots \\ z(64)\approx1.32 \end{gathered}[/tex]Using a right z-table, we have
This z-table gives us the area between the middle of the bell curve and our desired value.
This means, the probability of getting a sample higher than our value, will be 0.5 minus the probability given by the z-table.
[tex]0.5-0.4066=0.0934[/tex]Then, we have our result.
[tex]P(\bar{x}>64)=0.0934[/tex]identify the rate, base and portion.What percent of 126 is 44.1
In this problem, we have that
Base=126 (represents the 100%)
Portion=44.1
Find out the percentage
100/126=x/44.1
solve for x
x=(100/126)*44.1
x=35%
The percentage is 35%
(b) The area of a rectangular window is 3740 cmcm?If the length of the window is 68 cm, what is its width?Width of the windoow
Step 1
The area of a rectangle = Length x width
Step 2
Parameters given include
Area of rectangular window= 3740 square cm
Length of window = 68cm
Step 3
Substitute and solve
[tex]\begin{gathered} 3740\text{ = 68 x width} \\ \text{width = }\frac{3740}{68}\text{ = 55cm} \end{gathered}[/tex]Therefore, the width of the window = 55 cm
Samuel and Kathleen deposit $700.00 into a savings account which earns 4% interestcompounded monthly. They want to use the money in the account to go on a trip in 2 years.How much will they be able to spend?
To find how much they will be able to spend, we have to use the compoud interest formula, so:
[tex]\text{Amount}=700000\cdot(1+0.04)^{24}[/tex][tex]Amount=1794312.92[/tex]A choir concert platform consists of 6 rows. The number of performers increases by 2 witheach successive row. How many performers are there in all if the back row has 36performers?A 48B 84C 186D 372
In this problem, we have the sequence
inverse sequence
36,34,32,30,28,26
The sum is equal to
S=36+34+32+30+28+26
S=186
The answer is option CIn this problem, we have the sequence
inverse sequence
36,34,32,30,28,26
The sum is equal to
S=36+34+32+30+28+26
S=186
The answer is option CWhat is the sign of mlio Choose 1 answer: Positive Negative Neither positive nor negative the sum is zero.
The sign will be positive.
The cost of a laptop computer decreased from $600 to $480. By what percentage did the cost of the computer decrease?
Initial value= $600
new value = $ 480
[tex]\begin{gathered} =\frac{600-480}{480}\times100 \\ =\text{ }\frac{120}{480}\times100 \\ =\text{ 25\%} \end{gathered}[/tex]25% decrease is the answer
Inside. Make sure you don’t enter any spaces in your answers. This answer needs to be rounded to the nearest hundredth.
ANSWER
c = 14.14
EXPLANATION
To find the length of side AB, which is the hypotenuse of the right triangle ABC, we have to apply the Pythagorean Theorem,
[tex]AB^2=AC^2+BC^2[/tex]Replace the known values and solve for c,
[tex]c^2=10^2+10^2=100+100=200\Rightarrow c=\sqrt{200}\approx14.14[/tex]Hence, the value of c is 14.14, rounded to the nearest hundredth.
3.2 Similar FiguresIf ASRT - ACBD, find the value of x.Show all work.Hint: Don't let your eyes deceive you pay attention tothe similarity statement.
Find the ratio of corresponding sides:
SRT to CBD =
70/50 = 1.4
SR / 60 = 1.4
SR = 60 x 1.4
SR = 84
84= 11x-4
Solve for x:
84+4 = 11x
88= 11x
88/11 = x
8=x
May I please get help with this. For I have tried multiple times but still can’t get the right answer or the triangle after dilation?
Solution:
Given the triangle ABC as shown below:
To draw the image,
step 1: Determine the coordinates of the vertices of the triangle.
In the above graph,
[tex]\begin{gathered} A(6,7) \\ B(9,9) \\ C(8,6) \end{gathered}[/tex]step 2: Evaluate the new coordinates A'B'C' of the triangle after a dilation centered at the origin with a scale factor of 2.
After a dilation centered at the origin with a scale factor of 2, the iniatial coordinates of the vertices of the triangle are multiplid by 2.
Thus,
[tex]\begin{gathered} A(6,7)\to A^{\prime}(12,14) \\ B(9,9)\to B^{\prime}(18,18) \\ C(8,6)\to C^{\prime}(16,12) \end{gathered}[/tex]step 3: Draw the triangle A'B'C'.
The image of the triangle A'B'C' is as shown below:
hi I need on this. $6000 invested at 5.5% interest, compounded annually. how how would i have in 6years?
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
principal = $6000
rate (interest) = 5.5%
time = 6 years
Step 02:
compound interest:
n = annually
n = 1
r = 5.5 % = 5.5 / 100 = 0.055
A = amount
[tex]A\text{ = P \lparen1 + r/n\rparen}^{nt}[/tex][tex]A\text{ = 6000 * \lparen1 + }\frac{0.055}{1})\placeholder{⬚}^{1*6}[/tex][tex]A\text{ = 6000 * \lparen1.3877\rparen = 8273.06}[/tex]The answer is:
$8273.06
What value n makes the eauqation n x 3/4 = 3/16
Answer:
N = 1/4
Step-by-step explanation:
Okay, so 1/4 is equal to N.
3/4 x1/4=3/16
Erin is buying produce at a store. She buys c cucumbers at $0.89 each and a apples at $0.99 each. What does the expression 0.89c + 0.99a represent? The expression represents the
One cucumber costs $0.89, so with Erin buys "c" cucumbers, the price he will pay for the cucumbers is the unitary price (0.89) times the number of cucumbers ("c"), so the price is 0.89c.
One apple costs $0.99, so with Erin buys "a" apples, the price he will pay for the apples is the unitary price (0.99) times the number of apples ("a"), so the price is 0.99a.
Then, to find the final price Erin will pay, we just need to sum both prices: all the cucumbers and all the apples:
Final price = 0.89c + 0.99a
So the expression represents the final price (or cost) Erin will pay for all products.
Ingrid is preparing a budget. She is first calculating her income. She makes $2,000 a month as a tutor, but she is going to school to become a lawyer who will eventually make close to $10,000 a month. What is the BEST thing for Ingrid to do to prepare an accurate budget?A. She should use the difference between both incomes--$8,000.B. She should average both incomes and use $6,000.C. She should use her future income of $10,000.D. She should use her current income of $2,000.
Given:
Ingrid is preparing a budget. She is first calculating her income.
She makes $2,000 a month as a tutor.
And she is going to school to become a lawyer.
Eventually, she will make close to $10,000 a month
So, the best thing is to calculate her earnings when she becomes a lawyer.
So, the answer will be option A
She should use the difference between both incomes--$8,000.
The confidence interval on estimating the heights of students is given as (5.4, 6.8). Find the sample mean of the confidence interval. A.6.8B.6.1C. 5.4D. 0.7
Solution
- The formula for finding the sample mean from the confidence interval is given below
[tex]\begin{gathered} \text{Given the Confidence interval,} \\ (A_1,A_2) \\ \\ \therefore\operatorname{mean}=\frac{A_1+A_2}{2} \end{gathered}[/tex]- Thus, we can find the sample means as follows
[tex]\begin{gathered} A_1=5.4 \\ A_2=6.8 \\ \\ \therefore\operatorname{mean}=\frac{5.4+6.8}{2} \\ \\ \operatorname{mean}=\frac{12.2}{2} \\ \\ \operatorname{mean}=6.1 \end{gathered}[/tex]Final Answer
The sample mean is 6.1 (OPTION B)
Use the give right triangle to find ratios. In reduced form, for sin A, cos A, and tan A
From the figure given, if theta = A
opposite = 28 and hypotenuse =53
substitute the values into the formula
[tex]\sin A=\frac{28}{53}[/tex][tex]\cos A=\frac{adjacent}{\text{hypotenuse}}[/tex][tex]\cos A=\frac{45}{53}[/tex][tex]\tan \theta=\frac{opposite}{adjacent}[/tex][tex]\tan A=\frac{28}{45}[/tex]Find the slope of the line in the graph below using: rise m= 0 6 -2)
Given data:
The given graph of the line.
The slope of the line passing through (4, 0) and (12, 2) is,
[tex]\begin{gathered} m=\frac{2-0}{12-4} \\ =\frac{2}{8} \\ =\frac{1}{4} \end{gathered}[/tex]Thus, the solpe of the line is 1/4.
Step-by-step explanation:
Given data:
The given graph of the line.
The slope of the line passing through (4, 0) and (12, 2) is,
\begin{gathered}\begin{gathered} m=\frac{2-0}{12-4} \\ =\frac{2}{8} \\ =\frac{1}{4} \end{gathered}\end{gathered}
m=
12−4
2−0
=
8
2
=
4
1
Thus, the solpe of the line is 1/4.
The table below shows the relationship between the number of hours a student studied and theirgrade on a certain test.
It is necessary to adjust the given points of the graph to a line. The general form of the equation of a line is given by:
y = mx + b
where m is the slope of the line and b is the y-intercept of the line.
To calculate the slope m, use the following formula:
[tex]undefined[/tex]Go on the head 120 eggs delivered to her bakery she used to 98 eggs to bake cakes which equation can she use find the number of eggs r she has left
Yolanda has 120 eggs, but she used 98 eggs
r represents the equation for the number of eggs that she left:
To find this, subtract the total of eggs by the eggs used
Then, r = 120 - 98
i need help solving this with the statements and reasons
Given that:
[tex]\bar{AB}\mleft\Vert \mright?\bar{DC}[/tex]To prove that:
[tex]\Delta ABE\cong\Delta\text{CDE}[/tex]We know that congruent parts of congruent triangles are congruent
[tex]\angle\text{AEB }\cong\angle CDE\text{ (vertically opposite angles)}[/tex]Given that E is the midpoint of AC, therefore,
[tex]\begin{gathered} EA=EC\text{ } \\ EB=ED \end{gathered}[/tex]By the SAS congruency theorem as illustrated above, it is sufficient to prove that the triangles are congruent
is A square with a perimeter of 38 units is graphed on a coordinate grid. The square dilated by a scale factor of 0.8 with the origin as the center of dilation. If (x,y) represents the location of any point on the original square, which ordered pair represents the coordinates of the corresponding point on the resulting square? 0 (0.8x, 0.8y) 0 (x + 38, y + 38) O (x + 0.8, y + 0.8) O (38x, 38y)
Answer:
(0.8x, 0.8y)
Step-by-step explanation:
in a dilation with the origin as the center all point coordinates are multiplied by the scaling factor.
Dave and his brother. Theo, are selling cookies by the pound at the school bake sale Dave sold 14 84 pounds of cookies and Theo sold 21.45 pounds of cookies How many pounds did they sell altogether? A 35 29 OB 36 39 C36 25 0 D. 36 29
For tis problem we have that Dave sold 14.84 pounds of cookies and Theo sold 21.45 pounds of cookies.
If we want to find the total of pounds that they sold together we just need to add the two values and we have:
[tex]14.84+21.45=36.29\text{pounds}[/tex]The reason is because 0.84+0.45=1.29
14+21=35. And finally 35+1.29=36.29
And the best answer for this case would be D. 36.29
please help ………………. …………. ………… i already have the answer for part A but im having trouble with Parts B and C
In part B we must perform the following operation:
[tex](5a^3+4a^2-3a+2)+(a^3-3a^2+3a-9)[/tex]The key here is to group the terms according to the power of a they have:
[tex](5a^3+4a^2-3a+2)+(a^3-3a^2+3a-9)=(5a^3+a^3)+(4a^2-3a^2)+(-3a+3a)+(2-9)[/tex]Then, we can use the distributive property of the multiplication but in reverse:
[tex]b\cdot a+c\cdot a=(b+c)\cdot a[/tex]If we do this in each of the terms between parenthesis we get:
[tex]\begin{gathered} (5a^3+a^3)+(4a^2-3a^2)+(-3a+3a)+(2-9)= \\ =(5+1)a^3+(4-3)a^2+(-3+3)a-7 \\ (5+1)a^3+(4-3)a^2+(-3+3)a-7=6a^3+a^2-7 \end{gathered}[/tex]Then the answer for part B is:
[tex]6a^3+a^2-7[/tex]In part C we must simplify:
[tex](4y^3-2y+9)-(2y^3-3y^2+4y+7)[/tex]Here is important to remember that a negative sign before a parenthesis means that you have to change the sign of all the terms inside it. Then we have:
[tex](4y^3-2y+9)-(2y^3-3y^2+4y+7)=4y^3-2y+9-2y^3+3y^2-4y-7[/tex]Now we can do the same thing we did in part B, we group the terms according to the powers of y:
[tex]4y^3-2y+9-2y^3+3y^2-4y-7=(4y^3-2y^3)+3y^2+(-2y-4y)+(9-7)[/tex]Then we apply the distributive property in reverse:
[tex]\begin{gathered} (4y^3-2y^3)+3y^2+(-2y-4y)+(9-7)=(4-2)y^3+3y^2+(-2-4)y+2 \\ (4-2)y^3+3y^2+(-2-4)y+2=2y^3+3y^2-6y+2 \end{gathered}[/tex]Then the answer for part C is:
[tex]2y^3+3y^2-6y+2[/tex]