Sophia is in the business of manufacturing phones. She must pay a daily fixed cost of $200 to rent the building and equipment, and also pays a cost of $100 per phone produced for materials and labor. Make a table of values and then write an equation for C,C, in terms of p,p, representing total cost, in dollars, of producing pp phones in a given day.

I need the equation

Answers

Answer 1

Answer:

C = 100p + 200

Step-by-step explanation:

Because C is the total cost per day, 200 is the y-intercept because it's paid daily. The 100 is the slope since "he pays a cost of $100 per phone produced


Related Questions

I’ve done all the other parts, I simply need you to graph the proabola!

Answers

Given

[tex]y=x^2-4x+3[/tex]

Find

Graph the parabola of the given function

Explanation

[tex]y=x^2-4x+3[/tex]

solve the equation

[tex]\begin{gathered} x^2-4x+3=0 \\ x^2-3x-x+3=0 \\ x(x-3)-(x-3)=0 \\ (x-1)(x-3)=0 \\ x=1,3 \end{gathered}[/tex]

vertex can be found by using the formula,

[tex]-\frac{b}{2a}=-\frac{-4}{2}=2[/tex]

x = 2 , substitute this in equation to get y value,

y = -1

if x = 0 then y =3 and if y= 0 then x = 1, 3

Final Answer

to rent a van a moving company charges $40.00 plus $0.50per miles

Answers

The problem talks about the cost for renting a van, which can be calculated adding $40.00 plus $0.50 for each mile.

The problem asks to wirte an explicit equation in slope-intercept form which can represent the cost of renting a van depending on the amount of miles. Then, the problem asks to find the cost if you drove 250 miles.

What is the equation of a line with slope 7/12 and y-intercept -3?

Answers

The equation of a line in the slope intercept form is expressed as

y = mx + c

where

m represents slope

c represents y intercept

Given that m = 7/12 and c = - 3, the equation of the line would be

y = 7x/12 - 3

Solve graphically by the intersection method. Give the solution in interval notation.5x+2<2x−4

Answers

Answer:

Explanation:

The green line represents 5x + 2

The purple line represents 2x - 4

The orange-colour line represents the intersection of the lines above, which is the solution to the inequality:

5x + 2 < 2x - 4

The intersection is represented by a broken line, to signify the strict < in the equation

Finding the final amount in a word problem on continuous exponential growth or decay

Answers

Given:

The mass of radioactive follows an exponential decay model

The initial mass = 418 kg

Decreases at a rate = r = 4% per day

So, the general formula for the mass will be:

[tex]m=418\cdot(1-0.04)^d[/tex]

where: (m) is the mass after (d) days

So, to find the mass after 2 days, we will substitute with d = 2

so,

[tex]m=418\cdot(1-0.04)^2=418\cdot0.96^2=385.2288[/tex]

rounding to the nearest tenth

so, the answer will be mass after 2 days = 385.2 kg

Describe the two different methods shown for writing the complex expression in standard form. Which method do you prefer? Explain

Answers

The first method simlpy executes the distributive property of multiplication over addition, and the definition of the imaginary number, i.

The second method factored out 4i first then perform the operation on the terms left inside the parenthesis , then executes the distributive property of multiplication over addition and the definition of the imaginary number, i.

I prefer the first method . It's simple and straight forward,

Determine the value of x Round results to an appropriate number of significant digits

Answers

Given

Find

The value of x.

Explanation

length of AB = 22 - 3 = 19

using the trignometric ratios , we have

[tex]\begin{gathered} \sin13\degree=\frac{BD}{AB} \\ \sin13\degree=\frac{\frac{x}{2}}{19} \\ \sin13\degree\times38=x \\ 8.548=x \end{gathered}[/tex]

Final Answer

Therefore , the length of x is 8.548

3. Jeremy asked a sample of 40 8th grade students whether or not they had a curfew. He then asked if they had a set bedtime for school nights. He recorded his data in this two-way frequency table. Bedtime 21 Curfew No Curfew Total No Bedtime Total 4 25 12 16 40 3 15 24 a. What percentage of students surveyed have a bed time but no curfew?

Answers

40 students (the total) represents 100%

To find what percentage represents 3 students (number of students with bedtime but no curfew), we can use the next proportion:

[tex]\frac{40\text{ students}}{3\text{ students}}=\frac{100\text{ \%}}{x\text{ \%}}[/tex]

Solving for x,

[tex]\begin{gathered} 40\cdot x=100\cdot3 \\ x=\frac{300}{40} \\ x=7.5\text{ \%} \end{gathered}[/tex]

Graph the line with the given slope m and y-intercept b.
m = 4,b=-5

Answers

The graph of the linear equation can be seen in the image at the end.

How to graph the linear equation?

The general linear equation is.

y = m*x + b

Where m is the slope and b is the y-intercept.

Here we know that m = 4 and b = -5, so we have:

y = 4*x - 5

To graph this line, we need to find two points.

Evaluating in x = 0 we get:

y = 4*0 - 5 = -5

Evaluating in x = 2 we get:

y = 4*2 - 5 = 8 - 5 = 3

So we have the points (0, -5) and (2, 3), so now we need to graph these points and connect them with a line, the graph can be seen below:

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24) The radius of a circle is 6 inches. What is the area of a sector that has a central angle of 100 degrees 

Answers

Answer

Area of the sector = 31.42 square inches

Explanation

The area of a sector that has a central angle, θ, in a circle of radius r, is given as

[tex]\begin{gathered} \text{Area of a sector = }\frac{\theta}{360\degree}\times(Area\text{ of a circle)} \\ \text{Area of a circle =}\pi\times r^2 \\ \text{Area of a sector = }\frac{θ}{360°}\times\pi\times r^2 \end{gathered}[/tex]

For this question,

θ = central angle = 100°

π = pi = 3.142

r = radius = 6 inches

[tex]\begin{gathered} \text{Area of a sector = }\frac{θ}{360°}\times\pi\times r^2 \\ \text{Area of a sector = }\frac{100\degree}{360\degree}\times3.142\times6^2=31.42\text{ square inches} \end{gathered}[/tex]

Hope this Helps!!!

suppose that the amount of time it takes to build a highway vadies directly with the length of the highway and inversely with the number of workers. suppose also that it takes 300 workers 22 week to build 24 miles of highway. how long will it take 225 to build 27 miles of highway

Answers

[tex]\begin{gathered} \text{Let the length of the highway be represented by L} \\ \text{Let the Time it takes be represented by: T} \\ \text{Let the number of workers be: N} \\ T\text{ }\propto\frac{L}{N} \\ \\ T\text{ =}\frac{KL}{N}------------(1) \\ \\ K\text{ = }\frac{TN}{L}\text{ = }\frac{22\text{ }\times300}{24}\text{ = 275} \\ T\text{ = ?, N = 225},\text{ L = 27} \\ using\text{ equation(1)} \\ T\text{ = }\frac{KL}{N}\text{ = }\frac{275\times27}{225}\text{ = }\frac{7425}{225}\text{ = 33w}eeks \end{gathered}[/tex]

In a charity triathlon, Mark ran half the distance and swam a quarter of the distance when he took a quick break to get a drink of Gatorade he was just starting to bite the remaining 12 miles what was the total distance of the race?

Answers

[tex]\begin{gathered} x=Total\text{ distance} \\ Mark\text{ ran half the distance}=\frac{x}{2} \\ Mark\text{ swam a quarter of the distance}=\frac{x}{4} \\ Mark\text{ will bike 12 miles } \\ Hence \\ \frac{x}{2}+\frac{x}{4}+12=x \\ \frac{3}{4}x+12=x \\ Solving\text{ x} \\ 12=x-\frac{3}{4}x \\ 12=\frac{x}{4} \\ x=12\ast4 \\ x=48 \\ The\text{ total distance of the race was 48 miles.} \end{gathered}[/tex]

Sydney is making bracelets, 3 bracelets require 21 beads. The number of braclets varies directly with the number of beads.
Write an equation in the form of y = ax then find the amount o
beads needed for 32 bracelets.

Answers

Step-by-step explanation:

"varies DIRECTLY with" means there is an y = ax relationship.

y = number of bracelets

x = number of beads

3 = a×21

a = 3/21 = 1/7

now, when we have 32 bracelets

32 = 1/7 × x

32×7 = x = 224

224 beads are needed for 32 bracelets.

Choose the best description of its solution. If applicable, give the solution.

Answers

Given:

[tex]\begin{gathered} -x-3y=-6\ldots\text{ (1)} \\ x+3y=6\ldots\text{ (2)} \end{gathered}[/tex]

Adding equation(1) and equation(2)

[tex]\begin{gathered} -x-3y+x+3y=-6+6 \\ 0=0 \end{gathered}[/tex]

The system has infinitely many solution .

They must satisfy the equation:

[tex]y=\frac{6-x}{3}[/tex]

12"retest: CirclesOASelect the correct answerArc XY located on circle A has a length of 40 centimeters. The radius of the circle is 10 centimeters. What is the measure of the correspondingcentral angle for XY in radians?O B.OC.OD. 34TResetSubmit TestNextReader Tools

Answers

step 1

Find out the circumference

[tex]C=2\pi r[/tex]

where

r=10 cm

substitute

[tex]\begin{gathered} C=2\pi(10) \\ C=20\pi\text{ cm} \end{gathered}[/tex]

Remember that

The circumference subtends a central angle of 2pi radians

so

Applying proportion

Find out the central angle by an arc length of 40 cm

[tex]\begin{gathered} \frac{2\pi}{20\pi}=\frac{x}{40} \\ \\ x=4\text{ rad} \end{gathered}[/tex]

therefore

The answer is 4 radians Option B

Find the volume of a cone with a height of 10cm and diameter of 6cm. Round to the nearest tenth. Use 3.14 for .

Answers

We can find the volume of a cone using the formula

[tex]V=\frac{\pi r^2h}{3}[/tex]

Where

h = height

r = radius

Remember that

[tex]d=2r\Rightarrow r=\frac{d}{2}[/tex]

Therefore, let's find out the radius first, the problem says that the diameter is 6cm, then

[tex]r=\frac{6}{2}=3\text{ cm}[/tex]

The radius is 3cm and the height is 10cm, let's use it in our formula:

[tex]\begin{gathered} V=\frac{\pi\cdot(3)^2\cdot10}{3} \\ \\ V=30\pi \end{gathered}[/tex]

The problem also say to use = 3.14, then the volume is

[tex]\begin{gathered} V=30\cdot3.14 \\ V=94.2 \end{gathered}[/tex]

Therefore, the volume is

[tex]V=94.2\text{ cm}^3[/tex]

Hey I need help on this question so today I want you help me solve it please

Answers

Definitions in Algebra

A variable is a letter or symbol that represent numbers in a general way.

A coefficient is a number that multiplies a variable

A term is a combination of numbers and variables, all of them multiplied.

An exponent represents multiple products, like 2*2*2= 2^3

The answer is shown in the image below:

Shown in the equation are the steps a student took to solve the simple interest formula A=P(1+rt) for r

Answers

Given:

We're given the steps a student took to solve the simple interest formula.

To find:

The algebraic error in student's work.

Step-by-step solution:

Let us first solve the equation and then we will spot the error in the solution:

A = P(1 + rt)

A = p + prt

A - p = prt

A - p / pt = r

Upon comparing both solutions, we can clearly see that the student made a mistake in the second step in the multiplication process.

The student should write A = p + prt in the second step in place of

A = p + rt, because p is multiplied with the whole bracket.

Carrie sold 112 boxes of cookies, Megan sold 126 boxes of cookies, Julie sold 202 boxes of cookies, and Ashton sold 176 boxes of cookies. what was the average number of boxes of cookies sold by each individual

Answers

Answer:

154 boxes.

Explanation:

To calculate the average number of boxes of cookies sold by each individual​, we use the formula:

[tex]\text{Average=}\frac{\text{Sum of all boxes sold}}{\text{Number of individuals}}[/tex]

This gives:

[tex]\begin{gathered} \text{Average}=\frac{112+126+202+176}{4} \\ =\frac{616}{4} \\ =154\text{ boxes} \end{gathered}[/tex]

The average number of boxes of cookies sold by each individual​ was 154 boxes.

What is the APY for money invested at each rate?(A) 14% compounded semiannually(B) 13% compounded continuously

Answers

Answer:

Explanation:

APY means Annual Percentage Yield

The APY is given by the formula:

[tex]\text{APY}=\lbrack(1+\frac{r}{n}\rbrack^n-1[/tex]

where r is the rate (in decimals)

n is the number of times the interest was compounded

A) For the money invested at 14% compounded semiannually

r = 14% = 14/100

r = 0.14

n = 2

Substitute n = 2, r = 0.14

[tex]\begin{gathered} \text{APY = \lbrack{}1+}\frac{0.14}{2}\rbrack^2-1 \\ \text{APY}=\lbrack1+0.07\rbrack^2-1 \\ \text{APY}=\lbrack1.07\rbrack^2-1 \\ \text{APY}=0.1449 \\ \text{APY}=0.1449\times100\text{ \%} \\ \text{APY}=14.49\text{ \%} \end{gathered}[/tex]

B) For the money invested at 13% compounded continuously

The formula G=H⋅R tells us how much gross pay G a person receives for working H hours at an hourly rate of pay R. Find G.H = 37 hours and R = $6The gross pay is $? .

Answers

Given:

a.) H = 37 hours

b.) R = $6

Let's find the gross pay, G:

[tex]\text{ G = H x R}[/tex][tex]=\text{ 37 x 6}[/tex][tex]\text{ G = }222\text{ = \$222}[/tex]

Therefore, the gross pay is $222.

Determine whether the graph shown is the graph of a polynomial function

Answers

the given graph is smooth and its domain is containing all real numbers

so it is a polynomial function.

In scalene triangle ABC shown in the diagram below, m2C = 90°.B.Which equation is always true?sn A = sin Bcos sn A = cos BCanAB4 5 678 9 1011

Answers

inNote: To know which equation is true, then we will have to TEST for each of the choices we are to pick from.

From the tirangle in the image.

[tex]\begin{gathered} 1)\sin \text{ A =}\frac{\text{ Opp}}{\text{Hyp}}\text{ = }\frac{a}{c} \\ \cos \text{ B = }\frac{\text{ADJ}}{\text{HYP}}\text{ = }\frac{a}{c} \\ So\text{ from the above, we can s}ee\text{ that: SinA = Cos B :This mean the choice are equal} \\ \end{gathered}[/tex][tex]\begin{gathered} 2)\text{ To test for the second choice we have..} \\ \text{ Cos A = Cos B} \\ \text{for Cos A =}\frac{\text{Adj}}{\text{Hyp}}\text{ =}\frac{b}{c} \\ \\ \text{for Cos B = }\frac{Adj}{\text{Hyp}}\text{ = }\frac{a}{c} \\ \text{from here we can s}ee\text{ that Cos A }\ne\text{ Cos B : meaning Cos A is not equal to Cos B} \\ \end{gathered}[/tex]

3) To test for the third choice: Sin A = Cos A

[tex]\begin{gathered} \sin \text{ A=}\frac{opp}{\text{Hyp}}\text{ = }\frac{a}{c} \\ \cos \text{ A = }\frac{Adj}{\text{Hyp}}\text{ = }\frac{b}{c} \\ we\text{ can s}ee\text{ that sinA }\ne\text{ cos }A,\text{ This mean they are not equal} \end{gathered}[/tex][tex]\begin{gathered} 4)\text{ To test if: tan A = sin B} \\ \text{ }tan\text{ A = }\frac{opp}{\text{Adj}}\text{ = }\frac{a}{b} \\ \\ \text{ sin B = }\frac{Opp}{\text{Hyp}}\text{ = }\frac{b}{c} \\ so\text{ from what we have, w can s}ee\text{ that tan A }\ne\text{ sinB: Meaning they are not equal.} \end{gathered}[/tex]

Meaning the first choice is the answer that is sin A = CosB

I need help on this i tried and it was wrong

Answers

Given the Division:

[tex]420\div10[/tex]

You can identify that have to divide 420 by 10. This means that you need to move the Decimal Point 1 place to the left. Notice that, if you do this, you get:

[tex]=42.0[/tex]

Notice that now the digit that was placed in the Ones Place, is in the Tenths Place. Therefore, each original digit was shifted one place to the right.

Hence, the answer is:

In Square ABCD, AE = 3x + 5 and BD = 10x + 2.What is the length of AC?

Answers

Let's begin by identifying key information given to us:

We have square ABCD

[tex]\begin{gathered} AE=3x+5 \\ BD=10x+2 \\ BD=2\cdot AE \\ 10x+2=2(3x+5) \\ 10x+2=6x+10 \\ \text{Put like terms together, we have:} \\ 10x-6x=10-2 \\ 4x=8 \\ \text{Divide both sides by ''4'', we have:} \\ \frac{4x}{4}=\frac{8}{4} \\ x=2 \\ \\ \end{gathered}[/tex]

For a square, the diagonals are equal, AC = BD

[tex]\begin{gathered} AC=BD \\ AC=10x+2 \\ x=2 \\ AC=10(2)+2=20+2 \\ AC=22 \end{gathered}[/tex]

A = P + PRT/100Make P the subject from the formula.

Answers

ANSWER

[tex]P=\frac{100A}{100+RT}[/tex]

EXPLANATION

We want to make the subject of the formula in the given equation:

[tex]A=P+\frac{PRT}{100}[/tex]

First, factorize the right-hand side of the equation:

[tex]A=P(1+\frac{RT}{100})[/tex]

Simplify the bracket:

[tex]A=P(\frac{100+RT}{100})[/tex]

Now, divide both sides by the term in the bracket:

[tex]\begin{gathered} \Rightarrow P=A\cdot\frac{100}{100+RT} \\ \Rightarrow P=\frac{100A}{100+RT} \end{gathered}[/tex]

That is the answer.

Unit 6 lesson3 plsss help

Answers

From the triangles ∠ABC ≅ ∠MNP.

Given we have two triangles ABC and PNM

Both triangles have same shape but different angles.

we need to find ∠ABC ≅ ?

we can notice that :

∠A ≅ ∠M

∠B ≅ ∠N

∠C ≅ ∠P

hence these angles are similar to each other.

So,  ∠ABC ≅ ∠MNP.

Hence we get the answer as ∠ABC ≅ ∠MNP.

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How long will it take for an investment of 2900 dollars to grow to 6800 dollars, if the nominal rate of interest is 4.2 percent compounded quarterly? FV = PV(1 + r/n)^ntAnswer = ____years. (Be sure to give 4 decimal places of accuracy.)

Answers

ANSWER :

The answer is 20.3971 years

EXPLANATION :

The compounding interest formula is :

[tex]FV=PV(1+\frac{r}{n})^{nt}[/tex]

where :

FV = future value ($6800)

PV = present value ($2900)

r = rate of interest (4.2% or 0.042)

n = number of compounding in a year (4 : compounded quarterly)

t = time in years

Using the formula above :

[tex]6800=2900(1+\frac{0.042}{4})^{4t}[/tex]

Solve for t :

[tex]\begin{gathered} \frac{6800}{2900}=(1.0105)^{4t} \\ \text{ take ln of both sides :} \\ \ln(\frac{6800}{2900})=\ln(1.0105)^{4t} \\ \operatorname{\ln}(\frac{6800}{2900})=4t\operatorname{\ln}(1.0105) \\ 4t=\frac{\ln(\frac{6800}{2900})}{\ln(1.0105)} \\ t=\frac{\ln(\frac{6800}{2900})}{4\ln(1.0105)} \\ t=20.3971 \end{gathered}[/tex]

How far is the bottom of the ladder from thebottom of the wall? Use the PythagoreanTheorem to determine the solution. Explain howyou found your answer.

Answers

The Pythagorean Theorem is

[tex]c^2=a^2+b^2[/tex]

where

c=hypotenuse=13

a=12

b=x

then we substitute the values

[tex]13^2=12^2+x^2[/tex]

then we isolate the x

[tex]\begin{gathered} x=\sqrt[]{13^2-12^2} \\ x=\sqrt[]{169-144} \\ x=\sqrt[]{25} \\ x=5 \end{gathered}[/tex]

The bottom of the ladder is 5m far from the bottom of the wall

help meeeeeeeeee pleaseee !!!!!

Answers

The values of the functions are:

a. (f + g)(x) = x² + 3x + 5

b. (f - g)(x) = x² - 3x + 5

c. (f * g)(x) = 3x³ + 15x

d. (f/g)(x) = (x² + 5)/3x.

How to Determine the Value of a Given Function?

For any given function, we can evaluate the function by plugging in the equation of each of the functions in the given expression.

Thus, we have the following given functions:

f(x) = x² + 5

g(x) = 3x

a. Find the value of the function for the expression (f + g)(x).

We are required here to add the expression for each of the functions, f(x) and g(x) together, which is:

(f + g)(x) = (x² + 5) + (3x)

(f + g)(x) = x² + 3x + 5

b. Evaluate (f - g)(x) by subtracting the function g(x) from f(x):

(f - g)(x) = (x² + 5) - (3x)

(f - g)(x) = x² - 3x + 5

c. Find (f * g)(x):

(f * g)(x) = (x² + 5) * (3x)

(f * g)(x) = x²(3x) + 5(3x)

(f * g)(x) = 3x³ + 15x

d. Find (f/g)(x):

(f/g)(x) = (x² + 5)/3x

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