The spectrum with a continuous spectrum of colors is the emission from a tungsten lamp, and the spectrum with discrete, bright lines is the emission from a deuterium arc lamp.
The spectrum showing the light intensity of the emission from a tungsten lamp is the one with a continuous spectrum of colors, whereas the spectrum showing the light intensity of the emission from a deuterium arc lamp is the one with discrete, bright lines.
The tungsten lamp emits a continuous spectrum because it is a hot solid, and as such, it emits light across a range of wavelengths.
On the other hand, the deuterium arc lamp contains a gas that emits light only at specific wavelengths when excited by an electric current. This results in bright lines at those wavelengths, creating a distinct pattern in the spectrum.
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an electric motor rotating a workshop grinding wheel at 1.20 102 rev/min is switched off. assume the wheel has a constant negative angular acceleration of magnitude 2.06 rad/s2.
The grinding wheel stops turning after 6.10 seconds.
What is angular acceleration?Angular Acceleration is defined as the time rate of change of angular velocity. It is usually expressed in radians per second per second.
To solve this problem, we can use the following kinematic equation:
ωf = ωi + αt
where:
ωi = initial angular velocity
ωf = final angular velocity (zero in this case, since the motor is switched off)
α = angular acceleration (constant negative value in this case)
t = time
We want to find the time it takes for the grinding wheel to come to a stop, so we can rearrange the equation to solve for t:
t = (ωf - ωi) / α
Since ωf = 0 and ωi = (1.20 x 10² rev/min) x (2π rad/rev) / (60 s/min) = 12.57 rad/s, we can substitute these values into the equation:
t = (0 - 12.57) / (-2.06) = 6.10 s
Therefore, it takes 6.10 seconds for the grinding wheel to come to a stop.
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The grinding wheel stops turning after 6.10 seconds.
What is angular acceleration?Angular Acceleration is defined as the time rate of change of angular velocity. It is usually expressed in radians per second per second.
To solve this problem, we can use the following kinematic equation:
ωf = ωi + αt
where:
ωi = initial angular velocity
ωf = final angular velocity (zero in this case, since the motor is switched off)
α = angular acceleration (constant negative value in this case)
t = time
We want to find the time it takes for the grinding wheel to come to a stop, so we can rearrange the equation to solve for t:
t = (ωf - ωi) / α
Since ωf = 0 and ωi = (1.20 x 10² rev/min) x (2π rad/rev) / (60 s/min) = 12.57 rad/s, we can substitute these values into the equation:
t = (0 - 12.57) / (-2.06) = 6.10 s
Therefore, it takes 6.10 seconds for the grinding wheel to come to a stop.
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What are the differences between active galaxies and normal galaxies?
Answer:
An active galaxy emits up to thousands of times more energy than a normal galaxy and long jets of gas can spew forth from the galaxy at nearly the speed of light.
Explanation:
A normal galaxy has a dormant super massive black hole at the center, and it is at a sleeping state after being fed on gas and matter. Whereas an active galaxy also has a super massive black hole at the center and is constantly feeding on gas, matter, stars and other things.
Active galaxies are either quasars, blazars, or radio galaxies. They are significantly more luminous than a normal galaxy because they produce more electro-magnetic radiations across the spectrum from x-rays to radio waves.
Active galaxies have shown to have a smaller number of star forming regions than normal galaxies because of the active nature of the AGN at the center causes high amounts of electromagnetic radiation which disturbs the star forming regions and it would take so much time to form new stars.
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According to Bernoulli's principle, all other things being equal, for a non-viscous incompressible fluid undergoing streamline flow:
b) The greater the density of a fluid, the greater the buoyant force on any object submerged in the fluid.
C) The pressure in a fluid is lower where the fluid is moving faster
D) Air moves faster over an airplane wing than it does under.
E) The deeper the position in an incompressible fluid, the greater the density of the fluid.
The correct statement according to Bernoulli's principle is (C),the pressure in a fluid is lower where the fluid is moving faster.
What is Bernoulli's principle and how does it apply to non-viscous, incompressible fluids that undergo streamline flow?The correct statement according to Bernoulli's principle is (C).
The pressure in a fluid is lower where the fluid is moving faster.
Bernoulli's principle states that for a non-viscous incompressible fluid undergoing streamline flow, the pressure of the fluid decreases as the speed of the fluid increases.
This means that where the fluid is moving faster, the pressure is lower, and where the fluid is moving slower, the pressure is higher. This principle is often used to explain phenomena such as lift on airplane wings and the flow of fluids through pipes.
The other statements in the question are not directly related to Bernoulli's principle. Density does play a role in the buoyant force on an object submerged in a fluid, but this is due to Archimedes' principle.
The speed of air over an airplane wing is related to Bernoulli's principle, but the statement is incomplete and does not fully explain the phenomenon of lift.
The density of a fluid increases with depth, but this is due to gravity and the weight of the fluid above, not Bernoulli's principle.
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these days the theory of the earth's moon's origin that best fits with the facts we have about the moon is: a. the moon came out of the earth b. the moon was formed in the same area of space and at the same time as the earth c. a large object hit the earth and the collision produced a filament of material that condensed to make the moon d. the moon was formed elsewhere and was later captured by the earth e. the moon was the gift of the green cheese producers on mars
The theory of the Moon's origin that best fits with the current scientific understanding is c. a large object hit the Earth and the collision produced a filament of material that condensed to make the Moon. This theory is known as the Giant Impact Hypothesis and is currently the most widely accepted explanation for the formation of the Moon.
It proposes that a Mars-sized body collided with the Earth about 4.5 billion years ago, creating a massive impact that ejected a large amount of material into space. This material then formed a ring around the Earth, which eventually condensed to form the Moon.
This theory is supported by several lines of evidence, including the similar isotopic composition of the Earth and Moon, the Moon's low iron content, and the presence of water on the Moon that is thought to have originated from the Earth's mantle.
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Why do we believe that comets are loosely consolidated, fluffy mixtures of ice and rock?
Comets are believed to be loosely consolidated, fluffy mixtures of ice and rock based on several lines of evidence and observations: Cometary activity: Comets exhibit activity when they approach the Sun,
such as the formation of a coma (a glowing coma or "atmosphere" surrounding the nucleus) and a tail that points away from the Sun. This activity is thought to be caused by the sublimation of ices (such as water, carbon dioxide, and other volatile compounds) from the nucleus, where they transition directly from solid to gas without passing through a liquid phase. This suggests that comets contain a significant amount of volatile ices that can readily vaporize when exposed to sunlight, indicating a relatively low density and loose composition.
Comet structure: Observations of comets that have been visited by spacecraft, such as Comet Halley (visited by the European Space Agency's Giotto spacecraft in 1986) and Comet Wild 2 (visited by NASA's Stardust spacecraft in 2004), have revealed their structure to be porous and loosely consolidated. Images and data from these missions show a rough and irregular surface with cliffs, boulders, and pits, which suggest a "fluffy" or loosely bound structure.
Comet composition: Analysis of the dust and gas particles emitted by comets during their active phases has provided insights into their composition. The presence of water ice, carbon dioxide, and other volatile compounds in cometary samples collected by spacecraft, as well as spectroscopic observations of comets from telescopes,
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A laser beam shines straight up onto a flat, black foil of mass mfind an expression for the laser power p needed to levitate the foil. express your answer in terms of the variable m and appropriate constants.
To levitate the foil, the laser beam must exert enough radiation pressure to counteract the force of gravity on the foil. This radiation pressure is proportional to the intensity of the laser beam, which can be related to its power using the formula:
power = intensity x area
Assuming that the laser beam is circular and has a radius r, the area it covers on the foil is πr^2. Therefore, the power needed to levitate the foil can be expressed as:
p = (mg) / (πr^2)
where m is the mass of the foil, g is the acceleration due to gravity, and π is a constant.
This expression shows that the power needed to levitate the foil is directly proportional to its mass, and inversely proportional to the area covered by the laser beam. This makes intuitive sense, as a larger laser beam will spread the radiation pressure over a larger area, making it less effective at levitating the foil.
In practice, other factors such as the reflectivity of the foil and the absorption properties of the laser beam will also affect the power required to levitate it. However, the above expression provides a good starting point for understanding the basic physics of laser levitation.
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When electromagnetic radiation with wavelength a = 2000 Å is incident on a clean tungsten plate in a vacuum, the maximum kinetic energy observed amongst the electrons ejected is 1.64 eV. Calculate the threshold wavelength above which it will not be possible to eject electrons from tungsten metal. express your answer in nm.
The tungsten metal's ability to expel electrons has a maximum threshold wavelength of 462.5 nm.
What is photoelectric effect?When a substance absorbs electromagnetic radiation, a phenomenon known as the photoelectric effect causes electrically charged particles to be discharged from or within the material.
We can use the photoelectric effect equation to solve this problem:
E = hf - Φ
where:
E = maximum kinetic energy of the ejected electron
h = Planck's constant
f = frequency of the incident radiation
Φ = work function of tungsten (the energy required to remove an electron from the metal)
We can convert the given wavelength a = 2000 Å to frequency using the speed of light c:
f = c / λ = c / (a × 10⁻¹⁰ m) = (3.00 × 10⁸ m/s) / (2000 × 10⁻¹⁰ m) = 1.50 × 10¹⁵ Hz
Now we can substitute the values given into the photoelectric effect equation:
1.64 eV = (6.63 × 10⁻³⁴ J·s)(1.50 × 10¹⁵ Hz) - Φ
Solving for the work function Φ:
Φ = (6.63 × 10⁻³⁴ J·s)(1.50 × 10¹⁵ Hz) - 1.64 eV = 4.30 × 10⁻³⁴ J
The threshold frequency or wavelength is the one where the energy of the photon is just enough to overcome the work function and eject the electron. This occurs when the maximum kinetic energy of the ejected electron is zero. Setting E = 0 in the photoelectric effect equation and solving for the corresponding frequency or wavelength:
0 = hf - Φ
f = Φ / h = 4.30 × 10⁻¹⁹ J / 6.63 × 10⁻³⁴ J·s = 6.49 × 10¹⁴ Hz
λ = c / f = (3.00 × 10⁸ m/s) / (6.49 × 10¹⁴ Hz) = 462.5 nm
Therefore, the threshold wavelength above which it will not be possible to eject electrons from tungsten metal is 462.5 nm.
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The tungsten metal's ability to expel electrons has a maximum threshold wavelength of 462.5 nm.
What is photoelectric effect?When a substance absorbs electromagnetic radiation, a phenomenon known as the photoelectric effect causes electrically charged particles to be discharged from or within the material.
We can use the photoelectric effect equation to solve this problem:
E = hf - Φ
where:
E = maximum kinetic energy of the ejected electron
h = Planck's constant
f = frequency of the incident radiation
Φ = work function of tungsten (the energy required to remove an electron from the metal)
We can convert the given wavelength a = 2000 Å to frequency using the speed of light c:
f = c / λ = c / (a × 10⁻¹⁰ m) = (3.00 × 10⁸ m/s) / (2000 × 10⁻¹⁰ m) = 1.50 × 10¹⁵ Hz
Now we can substitute the values given into the photoelectric effect equation:
1.64 eV = (6.63 × 10⁻³⁴ J·s)(1.50 × 10¹⁵ Hz) - Φ
Solving for the work function Φ:
Φ = (6.63 × 10⁻³⁴ J·s)(1.50 × 10¹⁵ Hz) - 1.64 eV = 4.30 × 10⁻³⁴ J
The threshold frequency or wavelength is the one where the energy of the photon is just enough to overcome the work function and eject the electron. This occurs when the maximum kinetic energy of the ejected electron is zero. Setting E = 0 in the photoelectric effect equation and solving for the corresponding frequency or wavelength:
0 = hf - Φ
f = Φ / h = 4.30 × 10⁻¹⁹ J / 6.63 × 10⁻³⁴ J·s = 6.49 × 10¹⁴ Hz
λ = c / f = (3.00 × 10⁸ m/s) / (6.49 × 10¹⁴ Hz) = 462.5 nm
Therefore, the threshold wavelength above which it will not be possible to eject electrons from tungsten metal is 462.5 nm.
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n lifting the mass by 5.3 cm, what is the work done on the mass by your applied force f? assume the mass is at rest before and after the lifting.
The work done on the mass by the applied force f is approximately 0.052 J.
To find the work done on the mass by the applied force f, we need to use the formula for work:work = force x distance x cos(theta)where force is the applied force, distance is the displacement of the mass, and theta is the angle between the applied force and the direction of displacement.In this case, the mass is lifted vertically, so the angle between the applied force and the direction of displacement is 0 degrees. Therefore, cos(theta) = 1.We are given that the mass is lifted by a distance of 5.3 cm, or 0.053 m. We are not given the value of the applied force, so we cannot calculate the work directly.However, we can use the fact that the work done on the mass is equal to the change in potential energy of the mass:work = delta U = mghwhere m is the mass, g is the acceleration due to gravity, and h is the height the mass is lifted.Assuming that the mass is lifted vertically and has a mass of 1 kg, we can calculate the work done on the mass:work = delta U = mgh = (1 kg)(9.81 m/s^2)(0.053 m) = 0.052 JTherefore, the work done on the mass by the applied force f is approximately 0.052 J.For more such question on mass
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1. the earth's orbit is an ellipse with the sun at one focus. the length of the major axis is 186,000,000 miles and the eccentricity is 0.0167. find the distances from the ends of the major axis to the sun. these are the greatest and least distances from the earth to the sun.
The greatest distance is 94.5 million miles and the least distance is 91.4 million miles from the Sun.
The distance from the Earth to the Sun varies throughout the year due to the elliptical shape of the Earth's orbit.
The length of the major axis is 186,000,000 miles and the eccentricity is 0.0167.
Using Kepler's Laws, we can calculate the greatest and least distances from the Earth to the Sun.
The distance from the Sun to one end of the major axis is known as the aphelion, and it is approximately 94.5 million miles.
The other end of the major axis is known as the perihelion, and it is approximately 91.4 million miles from the Sun.
These distances have a significant impact on the Earth's climate, causing seasonal changes and affecting the planet's overall temperature.
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THIS IS PART OF YOUR PRAC APP:
Given 5.9V and 3.02amps for a rectifier.
If the present voltage output of the rectifier doubles, with all else being equal, calculate current output
A) 5.0A
B) 6.04A
C) 3.02A
D) not enough info
E) 5.9A
The correct answer is B) 6.04A. In a rectifier circuit, the current output is directly proportional to the voltage input, according to Ohm's Law (V = IR), where V is voltage, I is current, and R is resistance.
Given:
Voltage input (before doubling): 5.9V
Current output: 3.02A
If the voltage output of the rectifier doubles, the new voltage output would be 5.9V x 2 = 11.8V (assuming all else remains equal).
Using the current-voltage relationship, we can calculate the new current output:
I = V/R
Where V is the new voltage output (11.8V) and R is the resistance of the rectifier circuit (which remains constant in this case).
Plugging in the values:
I = 11.8V / R
Since we do not have information about the resistance of the rectifier circuit, we cannot determine the exact value of the new current output. Therefore, the correct answer is D) not enough information.
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A sled slides along a horizontal surface on which the coefficient of kinetic friction is 0.25. Its velocity at point A is 7.6m/s and at point B is 4.8m/s . Use the impulse-momentum theorem to find how long the sled takes to travel from A to B.
Using the impulse-momentum theorem, the sled takes 1.46 seconds to travel from point A to point B.
The impulse-momentum theorem relates the impulse acting on an object to its change in momentum. In this problem, we can use this theorem to determine the time it takes for the sled to travel from point A to point B.
First, we need to determine the change in momentum of the sled as it moves from point A to point B. We can do this using the formula:
Δp = mΔv
where Δp is the change in momentum, m is the mass of the sled, and Δv is the change in velocity of the sled.
Δp = mΔv
Δp = m(vB - vA)
Δp = (m)(4.8 m/s - 7.6 m/s)
Δp = -3.6m
The negative sign indicates that the sled is losing momentum as it moves from point A to point B.
Next, we can use the impulse-momentum theorem to relate the change in momentum to the impulse acting on the sled. The impulse is given by the formula:
J = Δp
where J is the impulse.
J = Δp
J = -3.6m
Now, we can use the definition of impulse to relate it to the force acting on the sled and the time it takes for the force to act. The force is given by:
F = ma
where F is the force, m is the mass of the sled, and a is the acceleration of the sled.
The force of kinetic friction acting on the sled is given by:
Ff = μkN
where Ff is the force of friction, μk is the coefficient of kinetic friction, and N is the normal force acting on the sled.
Since the sled is moving horizontally, the normal force is equal to the weight of the sled:
N = mg
where g is the acceleration due to gravity.
Now, we can combine these equations to solve for the time it takes for the sled to travel from point A to point B:
J = FΔt
-3.6m = μkNΔt
-3.6m = μkmgΔt
Δt = -3.6m / (μkmg)
Substituting the given values, we get:
Δt = -3.6m / (0.25)(m)(9.81 m/s²)
Δt = -1.46 s
Since the time cannot be negative, we take the absolute value of the result:
Δt = 1.46 s
Therefore, the sled takes 1.46 seconds to travel from point A to point B.
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The largest planet in the solar system (by mass) is
a. Earth
b. Mars
c. Venus
d. Jupiter
e. Neptune
Answer:
D. Jupiter
Explanation:
The largest planet in the solar system is Jupiter (by Mass)
Braydon is halfway down a small hill on his bike. Which best describes his potential and kinetic energy?
A) He has mostly kinetic energy.
B) He has mostly potential energy.
C) His kinetic energy is increasing.
D) His potential energy is increasing.
Pls help!
Answer:
Explanation:
kinetic energyu inmcrease
What is the best definition for hypothermia? Damage to skin caused by long exposure to freezing temperatures Very low internal body temperature caused by cold temperatures Significantly increased heart rate caused by cold temperatures Elevated blood pressure caused by vigorous exercise
The correct option is B, The best definition for hypothermia is "very low internal body temperature caused by cold temperatures." Hypothermia occurs when the body loses heat faster than it can produce heat, leading to a dangerously low body temperature.
Hypothermia is a medical condition that occurs when the body's core temperature drops below the normal range, usually below 95 degrees Fahrenheit (35 degrees Celsius). It is typically caused by exposure to cold temperatures for extended periods or immersion in cold water.
As the body loses heat faster than it can produce it, various symptoms may develop, including shivering, confusion, dizziness, fatigue, slurred speech, and clumsiness. In severe cases, hypothermia can lead to organ failure, coma, and even death. Treatment for hypothermia involves rewarming the body, either passively or actively, and providing supportive care to address any complications that may arise.
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The planet that has an axis that points roughly straight up, and thus has no seasons to speak of, is:
a. Jupiter
b. Saturn
c. Uranus
d. Neptune
e. you can't fool me, all the giant planets have dramatically different seasons
The planet with an axis that points roughly straight up and thus has no seasons to speak of is Uranus. This unique orientation of Uranus' axis causes its poles to receive almost the same amount of sunlight all year round, resulting in a lack of seasonal variation.
While all the giant planets experience some level of seasonal changes, Uranus stands out as having the most extreme lack of seasonal variation due to its axial tilt.
It's important to note that the other giant planets (Jupiter, Saturn, and Neptune) all have dramatically different seasons due to their axial tilts, which are not as extreme as Uranus'. Jupiter and Saturn have noticeable seasons, but they are less dramatic than those experienced on Earth. Neptune also has seasonal variations, but due to its great distance from the Sun, these changes are less pronounced than those on Uranus.
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What is the major source of meteor shower meteoroids?
Answer:
Most meteoroids are small fragments of rock created by asteroid collisions. Comets also create meteoroids as they orbit the sun and shed dust and debris. When a meteoroid enters Earth's upper atmosphere, it heats up due to friction from the air.
Explanation:
Hope this helped! Please mark me brainliest!
Answer:
Most meteoroids are small fragments of rock created by asteroid collisions. Comets also create meteoroids as they orbit the sun and shed dust and debris. When a meteoroid enters Earth's upper atmosphere, it heats up due to friction from the air.
Explanation:
Complete each sentence using each term once.
g. social exchange
h. conformity
- social category
-. social aggregate
- primary group
-. secondary group
. reference group
- social network
i. groupthink
j. formal organization
k. bureaucracy
1. rationalism
1. A
is an impersonal and goal-
oriented group that involves only a segment of
one's life.
A secondary group is impersonal and goal-oriented in contrast to a major group. It only touches a small portion of its members' life. Secondary organizations arise to carry out a particular task.
Larger and more impersonal secondary groups are frequent. Additionally, they could be time- and task-limited. The roles of these groups are more goal- or task-oriented than emotional, serving an instrumental purpose as opposed to an expressive one. A secondary group can be one's coworkers or other classmates.
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Two trains sound identical horns of frequency 410 Hz. One train is stationary. The other is moving away from an observer, who heats a beat frequency of 35 Hz. How fast is the moving train going?
The speed of the moving train is approximately 33.5 m/s.
The beat frequency is given by the difference in frequency between the two horns, which is equal to the Doppler shift in frequency due to the motion of the moving train. Using the formula for the Doppler effect, we can solve for the speed of the train:
[tex]f_b = f_s\dfrac{(v + v_o)}{(v + v_s)}[/tex]
where [tex]f_b[/tex] is the beat frequency, [tex]f_s[/tex] is the horn frequency, v is the speed of sound, [tex]v_o[/tex] is the observer's speed, and [tex]v_s[/tex] is the speed of the source.
We know that [tex]f_s[/tex] = 410 Hz and [tex]f_b[/tex] = 35 Hz. The speed of sound in air at standard temperature and pressure is approximately 343 m/s. Since the observer is stationary, [tex]v_o[/tex] = 0.
Solving for [tex]v_s[/tex], we get:
[tex]v_s = \dfrac{(f_s + f_b)}{f_s - 1} \times v[/tex]
[tex]v_s[/tex] = ((410 Hz + 35 Hz) / 410 Hz - 1) * 343 m/s
[tex]v_s[/tex] = 33.5 m/s
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a block is on a horizontal surface (a shake table) that is moving back and forth horizontally with simple harmonic motion of frequency 2.0hz. the coefficient of static friction between block and surface is 0.50. how great can the amplitude of the shm be if the block is not to slip along the surface?
Maximum amplitude = (0.50 * 9.8 m/[tex]s^2[/tex]) / (2π * 2.0 Hz)[tex]^2[/tex] ≈ 0.249 m
To prevent the block from slipping along the surface, the maximum amplitude of the simple harmonic motion (SHM) can be determined by considering the maximum value of the centripetal acceleration acting on the block.
The centripetal acceleration required to prevent slipping is given by:
ac = ω^2 * R
where ω is the angular frequency of the SHM and R is the amplitude of the motion.
The maximum static friction force (fs) can be calculated using the coefficient of static friction (μs) and the normal force (N) acting on the block. In this case, the normal force is equal to the weight of the block (mg).
fs = μs * N = μs * mg
Since the centripetal acceleration is provided by the friction force, we have:
ac = fs / m = (μs * mg) / m = μs * g
Setting the centripetal acceleration equal to the maximum value, we get:
μs * g = ω^2 * R
Solving for R:
R = (μs * g) / ω^2
Substituting the given values, with μs = 0.50, g = 9.8 m/s^2, and ω = 2π * 2.0 Hz, we can calculate R:
R = (0.50 * 9.8 m/s^2) / (2π * 2.0 Hz)^2 ≈ 0.249 m or 24.9 cm
Therefore, the maximum amplitude of the SHM can be approximately 24.9 cm to prevent the block from slipping along the surface.
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a and b are two spheres with identical mass and radius. however, they are made of different materials. sphere b is made of a more dense core and a less dense shell around it. compare the moment of inertia of sphere a about its center of mass to the moment of inertia of sphere b about its center of mass? ia. ia > ib ib. ia < ib ic. ia
Spheres A and B have the same mass and radius but are composed of different materials. Sphere B has a denser core and a less dense shell.
Comparing the moment of inertia of spheres A and B. Given that both spheres A and B have identical mass and radius, but sphere B has a more dense core and a less dense shell, we can determine the relationship between their moments of inertia about their centers of mass.
To do this, we'll use the following equation for the moment of inertia of a solid sphere: I = (2/5)MR², where M is the mass of the sphere, R is its radius, and I is its moment of inertia.
For sphere A (uniform density), its moment of inertia can be calculated as:
Ia = (2/5)MaRa²
For sphere B (non-uniform density with a denser core), its moment of inertia can also be calculated using the same equation, but since it has a more dense core and a less dense shell, its moment of inertia will be smaller than that of sphere A. This is because the mass is distributed closer to the center, which reduces the moment of inertia.
So, comparing the moments of inertia for spheres A and B:
Ia > Ib
Thus, the correct answer is (a): Ia > Ib.
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The dot product between two vectors is negative when the angle between the vectors is:A) less than 90 degreesB) between 90 and 180 degreesC) between 30 and 60 degreesD) 90 degreesE) between 0 and 90 degrees
The dot product between two vectors is a scalar value that measures the extent to which the two vectors point in the same direction. The dot product is negative when the angle between the vectors is obtuse, meaning it is greater than 90 degrees.
To understand why this is the case, consider the formula for the dot product:
a · b = |a| |b| cos θ
where a and b are two vectors, |a| and |b| are their magnitudes, θ is the angle between them, and cos θ is the cosine of that angle.
If the angle between the vectors is acute, meaning it is less than 90 degrees, then cos θ is positive and the dot product is positive. If the angle between the vectors is right (90 degrees), then cos θ is 0 and the dot product is 0. However, if the angle between the vectors is obtuse, meaning it is greater than 90 degrees, then cos θ is negative and the dot product is negative.
In summary, the dot product between two vectors is negative when the angle between them is greater than 90 degrees, or when the answer is B) between 90 and 180 degrees.
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The gas state of a substance that is normally a solid or a liquid at room temperature
The gas state of a substance that is normally a solid or a liquid at room temperature occurs when the substance undergoes a phase change from solid or liquid to gas.
This phase change is known as sublimation for solids and evaporation for liquids. The temperature and pressure conditions at which sublimation or evaporation occurs depend on the substance's properties, such as its intermolecular forces and molecular weight. For example, dry ice (solid carbon dioxide) sublimes at -78.5°C and atmospheric pressure, while water (a liquid at room temperature) evaporates at 100°C and atmospheric pressure. The gas state of normally solid or liquid substances has many practical applications, such as in refrigeration, gas storage, and chemical synthesis.
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to experimentally find the moment of inertia ig of a 4-kg connecting rod, the rod is suspended from a cord at a while held horizontal. under this situation, the piezoelectric sensor (an instrument that can be used to measure force) located at b records a force of 14.6 n. this can be used to find the location of the center of mass, g. the cord is then cut, and the force at b drops to 9.3 n in that instant. from this measurement, find ig for the connecting rod.
To find the moment of inertia of a 4-kg connecting rod experimentally, first, the rod is suspended from a cord at point a while held horizontally. A piezoelectric sensor located at point b records a force of 14.6 N under this situation.
This force measurement can be used to determine the location of the center of mass, g, of the connecting rod.
Next, the cord is cut, and the force at point b drops to 9.3 N in that instant. This measurement can be used to calculate the moment of inertia for the connecting rod. The change in force is due to the sudden drop in the rod's potential energy as it falls.
The force of gravity acting on the rod can be calculated using the mass and acceleration due to gravity. The distance between point b and the center of mass g can be calculated using the previous force measurement and the weight of the rod.
With these values, the moment of inertia is of the connecting rod can be calculated using the formula for the moment of inertia of a rigid body rotating about a fixed axis.
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in prob. 9.54, if the cable were given an additional full wrap around the pulley at c and if the worker can apply a force of 50 lb to the cable, determine the largest weight that maybe be lifted at d
If the cable were given an additional full wrap around the pulley at c and the worker can apply a force of 50 lb to the cable, this would effectively double the tension in the cable. Therefore, the tension in the cable would be 2(400 lb) = 800 lb.
To determine the largest weight that may be lifted at d, we need to consider the forces acting on the system. There are two tension forces acting on the cable, one pulling up from d and one pulling down from the weight at c. There is also the weight of the load pulling down.
Using the principle of equilibrium, we can set the sum of the forces in the vertical direction equal to zero. This gives us:
800 lb - Td - W = 0
where Td is the tension force pulling up from d and W is the weight of the load.
Solving for W, we get:
W = 800 lb - Td
To determine the largest weight that can be lifted, we need to find the maximum tension force that the worker can apply to the cable. Since the worker can apply a force of 50 lb, the maximum tension force would be 50 lb multiplied by the number of cables wraps around the pulley at c. Since there is now one additional wrap, the maximum tension force would be:
50 lb x 2 = 100 lb
Therefore, the largest weight that can be lifted is:
W = 800 lb - Td = 800 lb - 100 lb = 700 lb
So the largest weight that can be lifted at d is 700 lb.
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two people, micah and lyra, with different near points are equally close to an object. both inspect the object through the same magnifier by holding the lens close to the eye. micah's near point is located farther away from his eye than lyra's near point is located relative to her eye. micah will experience a larger magnification for which of the following reasons? check all that apply.
Micah and Lyra have different near points and are inspecting an object through the same magnifier. Micah's near point is farther away from his eye compared to Lyra's near point. Micah will experience a larger magnification for the following reasons:
1. Micah's longer near point distance allows him to see the object more clearly through the magnifier, which increases the perceived magnification.
2. Since both are using the same magnifier, the lens properties remain constant. However, Micah's farther near point effectively increases the distance between the object and his eye, resulting in a larger magnification due to the increased distance.
In summary, Micah experiences a larger magnification because his near point is farther away from his eye, allowing him to see the object more clearly and at an effectively greater distance through the magnifier.
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a string has a total length of 5 m and a total mass of 0.01 kg. if the string has a tension of 10n applied to it, what is the speed of a wave on this string in [m/s]?
The wave on the string is moving at a pace of 70.7 m/s.
What is wave?A wave is an energetic disturbance in a medium that doesn't include any net particle motion. Elastic deformation, a change in pressure, an electric or magnetic intensity, an electric potential, or a change in temperature are a few examples.
The speed of a wave on a string can be calculated using the formula:
v = √(T/μ)
where v is the speed of the wave, T is the tension in the string, and μ is the linear density of the string (mass per unit length).
We are given that the string has a total length of 5 m and a total mass of 0.01 kg, so the linear density can be calculated as:
μ = m/length = 0.01 kg / 5 m = 0.002 kg/m
We are also given that the tension in the string is 10 N. Substituting these values into the formula, we get:
v = √(T/μ) = √(10 N / 0.002 kg/m) = √(5000 m^2/s^2)
Simplifying this expression, we get:
v = 70.7 m/s
Therefore, the speed of the wave on the string is 70.7 m/s.
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The Space Shuttle is flying at 2.0 km/hr and lands on the runway. It then slows down to 0.5 km/hr. If this takes
0.25hrs, what is your acceleration?
Answer: acceleration = -1.68 m/s^2
Explanation: First, you need to convert the speeds to meters per second (m/s) since acceleration is typically measured in m/s^2.
2.0 km/hr = 0.56 m/s
0.5 km/hr = 0.14 m/s
Next, you use the formula for acceleration: acceleration = (final velocity - initial velocity) / time
Plugging in the values, we get: acceleration = (0.14 m/s - 0.56 m/s) / 0.25 hr
acceleration = (-0.42 m/s) / 0.25 hr
acceleration = -1.68 m/s^2
Consider an experiment to investigate the specific heat capacity of iron in the following four questions. In this experiment, 175gof iron is always heated up and then added to 75 gof room temperature water. The initial temperature of the iron is 30°C 40°C 60°C or 80°Сin each trial. The sample of water always has an initial temperature of 20°C Multiple trials are run for each initial temperature of the iron sample, and the final temperature of the mixture is recorded. Question 2 5 pts Which of the following options are examples of quantities that were held constant - that is, independent variables that did not vary? Select all that apply. A. The mass of water B. The mass of the iron sample C. The initial temperature of water D. The initial temperature of the iron E.The final temperature of the mixture of water and iron
In this experiment to investigate the specific heat capacity of iron, it is important to identify the independent variables that were held constant throughout the trials.
The mass of water and the mass of the iron sample are examples of quantities that were held constant, as they were always 175g and 75g respectively. The initial temperature of the water was also held constant at 20°C. However, the initial temperature of the iron sample varied in each trial, with options of 30°C, 40°C, 60°C, or 80°C.
Therefore, the initial temperature of the iron sample is not an example of a quantity that was held constant.
The final temperature of the mixture of water and iron is also not a quantity that was held constant, as it was recorded as the dependent variable and varied depending on the initial temperature of the iron sample.
By holding certain variables constant, the experiment can be conducted more accurately and effectively to investigate the specific heat capacity of iron.
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a photon can be absorbed by a system that can have internal energy. assume that a 15 mev photon is absorbed by a carbon nucleus initially at rest. the recoil momentum of the carbon nucleus must be 15 mev/c. (a) calculate the kinetic energy of the carbon nucleus. what is the internal energy of the nucleus? (b) the carbon nucleus comes to rest and then loses its internal energy by emitting a photon. what is the energy of the photon?
(a) The kinetic energy of the carbon nucleus is equal to the absorbed photon's energy.
(b) The energy of the emitted photon is equal to the initial kinetic energy of the carbon nucleus.
(a) To calculate the kinetic energy of the carbon nucleus, we need to use the principle of conservation of momentum. Since the carbon nucleus is initially at rest, its momentum is zero.
When it absorbs the 15 MeV photon, the recoil momentum of the carbon nucleus will be 15 MeV/c. We can convert this momentum into kinetic energy using the equation:
Kinetic Energy = (recoil momentum)^2 / (2 * mass of carbon nucleus)
The mass of a carbon nucleus (approximately 12 atomic mass units) is 12 times the mass of a proton, which is approximately 1.67 × 10^-27 kg. By substituting these values into the equation, we can find the kinetic energy of the carbon nucleus.
(b) After the carbon nucleus comes to rest, it can lose its internal energy by emitting a photon. The energy of this photon will be equal to the internal energy of the nucleus.
Since the internal energy of the nucleus is equal to the kinetic energy it possessed before coming to rest, we can use the value calculated in part (a) as the energy of the emitted photon.
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match the lettered locations on the image, and the corresponding hypothetical locations of the moon relative to earth and the sun, with the type of tide coastal areas on earth would experience there.
The Sun and Moon's gravitational pull has an effect on the tides that affect coastal areas on Earth. High tides are got on by the Moon's bulge of water on the Earth's side that faces the Moon as it circles the Earth.
On the contrary side of the Earth, there is one more lump of water brought about by the divergent power created by the Earth-Moon framework, which likewise prompts elevated tides. There are low tides in the areas in between.
The hypothetical locations of the Moon in relation to the Earth and the Sun, as well as the kind of tide that would affect Earth's coastal areas, are as follows:
Moon New: Between the Sun and Earth is the Moon. As a result, there is a spring tide with high and low tides.
Waxing Bow Moon: The Moon is to the east of the Sun and is partially illuminated. A moderate spring tide is the result of this.
Quarter Moon at First: The Moon is perpendicular to the Sun and only partially illuminated. As a result, the high tides are lower and the low tides are higher during a neap tide.
Gibbous-Waxing Moon: The Moon, which lies to the east of the Sun and receives the majority of its light, A moderate spring tide is the result of this.
New Moon: The Sun and the Moon are on opposite sides of the Earth. As a result, there is a spring tide with high and low tides.
Gibbous-waning Moon: The Moon, lies to the west of the Sun and receives the majority of its light, A moderate spring tide is the result of this.
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