Square ABCD is inscribed in a circle with radius 20 m . What is the area of the part of the circle outside of the square
Answers
ANSWER:
456 square meters
STEP-BY-STEP EXPLANATION:
The first thing is to represent the problem in the following figure:
To calculate the area of the part of the circle outside of the square, we must calculate the area of the circle and subtract the area of the inscribed square.
To calculate the area of the square, we plant the following, taking into account that the diagonal of the square is equal to twice the radius and the sides equal to the radius times the root of two, like this:
Knowing the value of the side of the square, we can directly calculate the area of the part of the circle outside of the square, subtracting the corresponding areas like this:
[tex]\begin{gathered} A=A_C-A_S_{} \\ A=\pi\cdot r^2-\mleft(r\cdot\sqrt{2}\mright)^2 \\ \text{replacing} \\ A=3.14\cdot20^2-\mleft(20\cdot\sqrt{2}\mright)^2 \\ A=1256-800 \\ A=456 \end{gathered}[/tex]The area of the part of the circle outside of the square is equal to 456 square meters
Related Questions
Which value of x proves that the two triangles above are similar? 42.7 ft 26.7 ft 10 ft 25.6 ft
Answers
Explanation
Step 1
we have two triangles
ACE and BCD
if the triangles are similar, then the ratio of the sides must be the same:
[tex]\begin{gathered} \frac{\text{red line}}{purple\text{ line}}=\frac{blue\text{ line}}{\text{green line}} \\ \text{replacing} \\ \frac{16+x}{32}=\frac{x}{20} \end{gathered}[/tex]Step 2
solve for x
[tex]\begin{gathered} \frac{16+x}{32}=\frac{x}{20} \\ \text{cross multiply} \\ 20(16+x)=32\cdot x \\ 320+20x=32x \\ \text{subtrac 20x in both sides} \\ 320+20x-20x=32x-20x \\ 320=12x \\ \text{divide both sides y 12} \\ \frac{320}{12}=\frac{12x}{12} \\ \text{ x=26.66} \end{gathered}[/tex]rounded
[tex]x=26.7\text{ }[/tex]I hope this helps you
a teacher asks 15 students to estimate an answer to a question the answers or 1, 5, 5, 6, 7, 8, 10, 12 the correct estimate is 7 the teacher wants to calculate how far of the estimate were by finding the absolute value of the difference between each estimate and the answer which estimate was off by the most
Answers
We have the following estimations:
1, 5, 5, 6, 7, 8, 10, 12
The absolute value between each estimate and the answer is calculated as:
Estimate Absolute
Answer value
1 |1-7| = |-6| = 6
5 |5-7| = |-2| = 2
5 |5-7| = |-2| = 2
6 |6-7| = |-1| = 1
7 |7-7| = |0| = 0
8 |8-7| = |1| = 1
10 |10-7| = |3| = 3
12 |12-7| = |5| = 5
So, the estimated answer that was off by the most is 1.
Question 8 of 10According to this diagram, what is tan 62°?
Answers
In this problem, we want to determine tangent of 62 degrees.
Recall the identity of tangent:
[tex]\tan\theta=\frac{\text{ opposite side}}{\text{ adjacent side}}[/tex]We are given the triangle:
Since we are referencing 62 degrees, the arrow pointing away from the 62 degrees is headed toward the opposite side. Therefore, the opposite side is 15, and the adjacent side is 8.
[tex]\tan62=\frac{15}{8}[/tex]Tangent of 62 degrees is 15/8.
Find the principal which amounts to #5,000 at simple interestin 5 years at 2% per annum
Answers
To answer this we have to apply the simple interest formula:
I =P x r x t
Where:
I= interest
P= Principal
R= Interest rate ( in decimal form)
t = time (years)
Replacing with the values given:
Interest= I
Principal = ?
Interest rate = 2/100 =0.02
time= 5 years
I = P x 0.02 x 5
I= 0.1P
Amount= P+I
A = P+0.1P
5,000= P+0.1P
5,000= 1.1P
5,000/1.1 =P
4,545.45 =P
8 O 6 4. N Which function is graphed? 2. 4 6 8 -8 -6 -4 -2 0 -2 -6 O A. Y- (x² + 4, x=2 1-x+4,452 (x² + 4, x2 OD. V- x + 4, x32 1-x+4,4
Answers
The given curve is parabola and its last point is on the x axis at x = 2
So, the equation of curve is :
[tex]x^2+4,x<2[/tex]In the equation of line,
The line start from x = 2 so, x ≥ 2
So, Equation of line is : -x + 4, x ≥ 2
Answer : B)
[tex]y=\begin{cases}x^2+4,x<2 \\ \square \\ -x+4,\text{ x}\ge2\end{cases}[/tex]Given the following information, determine which lines, if any, are parallel. State the converse that justifies your answer.
Answers
1. angle j and k.
Due to the Converse of Corresponding Angles Postulate, j || k.
2. Angles 2 and 5 are the alternating inner angles of the lines j and k. Given that angle 2 = angle 5,
The Converse of Alternate Interior Angles Theorem states that j || k.
J || K converse alternative interior angles.
what are parallel angles?similarly
3. angle 3 = angle 10 The exterior angles of the lines l and m, respectively, are angle 3 and angle 10. Since the Converse of Alternate Exterior Angles Theorem states that angle 3= angle 10, l || m.
converse alternative exterior angles l || m.
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What is special about a unit circle? How does this help us when finding the six trigonometric ratios?
Answers
Answer:
A circle is a closed geometric figure without any sides or angles. The unit circle has all the properties of a circle, and its equation is also derived from the equation of a circle. Further, a unit circle is useful to derive the standard angle values of all the trigonometric ratios.
Step-by-step explanation:
Make a tree diagram, Please complete number 18.Please be quick, I am in a hurry.
Answers
Explanation:
The question wants us to list out all the possible outcomes in question 18
From the question
We have a spinner that has 5 possible outcomes
[tex]\mleft\lbrace\text{Red, Orange, Green, Purple, Yellow}\mright\rbrace[/tex]The outcomes of flipping a coin are
[tex]\begin{gathered} \mleft\lbrace\text{Head, Tail}\mright\rbrace\text{ } \\ \text{which can be written as} \\ \mleft\lbrace H,T\mright\rbrace \end{gathered}[/tex]Thus, to get the possible outcomes, we will have
Mr. Ocana drove 15 miles to go to work last week. Due to construction on the road, this week he drove 21 miles to go to work. What is the percent increase in the number of miles he drove to work this week? О 40% 50% ООО 60% O 70%
Answers
ANSWER:
40%
STEP-BY-STEP EXPLANATION:
In this case, what we must do is calculate the percentage that represents 21 miles, assuming that 100% is 15 miles, like this
[tex]21\cdot\frac{100}{15}=140\text{\%}[/tex]Now we subtract 100% from this value, like this:
[tex]140\text{\%}-100\text{\%}=40\text{\%}[/tex]Given the following piecewise function, determine the value of g(4) - 3g(3).
Answers
Piecewise Function
We are given the piecewise function shown in the figure.
We are required to calculate g(4) - 3g(3).
First, we calculate g(4). Since 4 is greater than 3, we use the second function:
[tex]g(4)=4^4+4^2+4-3=273[/tex]Now we need to calculate g(3). We use the same function because 3 is greater or equal to 3:
[tex]g(3)=3^4+3^2+3-3=90[/tex]Now we calculate:
g(4) - 3g(3) = 273 - 3*90 = 273 - 270 = 3
Answer: 3
Speeds of Cars (in miles per hour)Intersection 1Intersection 2十十十十18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34• Part 1: Find the range of intersection 1 as a way to measure the variability of the data, showing your work. Remember, range isfound by taking the largest value minus the smallest value. (2 points)• Part 2: Find the range of intersection 2 as a way to measure the variability of the data, showing your work. Remember, range isfound by taking the largest value minus the smallest value. (2 points)
Answers
PART 1)
Range of intersection 1
(Max value - Min value )=
Largest value = 31 , Lowest value = 26
Then range1 is 31 - 26 = 5 miles /hour
Now PART 2:)
Maximum value= 27
Minimum value = 22
Then range2 is 27-22 = 5 miles/hour
I need help on this and no this isn't a quiz
Answers
Concept:
Parallel planes are planes in the same three-dimensional space that never meet.
Parallel Lines or parallel Segments are always the same distance apart, they will never meet.
skew lines are two lines that do not intersect and are not parallel.
Question: Name a plane parallel to plane PQR:
Answer: plane JKL
Question: Name a segment parallel to segment KP:
Answer: segment OJ
Question: Name a segment that is skew to OJ
Answer: segment SR
Maria jogs 5 laps of a football field that
is 100 m by 50 m. How far does she jog?
Answers
Answer:
1500 m
Step-by-step explanation:
given that the field is 100m by 50m we can find that the perimeter of the field is 300m. if she jogged 300m 5 times she would have jogged 1500m
Which set can represent the side lengths of a right triangle?
Answers
The set that represents a right triangle has to satisfy Pythagorean's Theorem where the greatest side is the hypothenuse. Let's evaluate each of them until we get the right set.
[tex]\begin{gathered} 7^2=6^2+(\sqrt[]{21})^2 \\ 49=36+21 \\ 49=57 \end{gathered}[/tex][tex]\begin{gathered} (5\sqrt[]{3})^2=7^2+5^2 \\ 25\cdot3=49+25 \\ 75=74 \end{gathered}[/tex][tex]\begin{gathered} (2\sqrt[]{5})^2=4^2+2^2 \\ 4\cdot5=16+4 \\ 20=20 \end{gathered}[/tex]As you can observe, set B satisfies the theorem.
Hence, B is the answer.Fido ran away from home at a speed of 5 mi/hour. He ran in a straight line. After a while he decided to go back home for dinner so turned around and walked home along the same path he had run on. He walked at 2 mi/hour. The walk home took one hour longer than the run did. How long did Fido run?
Answers
Distance = Speed x time
For the run; speed = 5 mi/hr, time = t
For the walk: speed= 2 mi/hr, time = t + 1
Since he walked on a straight line and he returned following the same path
Distance travelled for the run = distance travelled for the walk
Distance for run: 5 x t = 5t
Distance for walk : 2 (t + 1) =2t + 2
Thus , 5t = 2t + 2
5t - 2t = 2
3t = 2
t = 2/3 hour = 2/3 x 60 minutes = 2x 20 = 40 minutes
He took him 40 minutes to run
Dan's dog walking job pays $15 per hour his job as a car wash attendant pays $400 each week Dan wants to know how many hours he needs to spend walking dogs to earn more than $520 in a week. Which three equalities can model this situation? select all the correct answers.
Answers
Answer:
520<400+15x
15x>120
15x+400>520
Explanation:
Pay of Dan's car wash attendant job =$400 per week
The amount he earns per hour walking dogs = $15
Let the number of hours spent walking dogs in a week = x
Therefore, total earning for walking dogs =$15x
Since he wants to earn more than $520, we have that:
[tex]15x+400>520\text{ (Option F)}[/tex]We can rewrite this as:
[tex]520<400+15x\text{ (Option B)}[/tex]If we collect like terms, we have:
[tex]\begin{gathered} 520-400<15x \\ 120<15x \\ \implies15x>120\text{ (Option C)} \end{gathered}[/tex]So the inequalities are:
0. 520<400+15x
,1. 15x>120
,2. 15x+400>520
Little help here please
Answers
Step-by-step explanation:
as the intersection angles of parallel lines with a third line are the same for both parallel lines (and then vice versa for the other pair of parallel lines), we have a lot of equal angles here.
not to forget : the sum of all angles around a single point on one side of a line is always 180°.
51 = (y + z)
(6z + 9y) = x
x + (x + z) = x + 51 = 180°
x = 129°
we have now
y + z = 51
9y + 6z = 129
so,
z = 51 - y
9y + 6(51 - y) = 129
9y + 306 - 6y = 129
3y = -177
y = -59
z = 51 - y = 51 - -59 = 51 + 59 = 110
the value of z that makes j and k parallel is 110.
In parallelogram PQRS, diagonals PR and QS intersect at point T.Which statement would prove PQRS is a rhombus?PT > QTPT QTPR QSSTQT
Answers
We can have more arguments to prove that PQRS is a rhombus, but, the argument that we will use here is:
Let's look at the first statement, we have
[tex]PT>QT[/tex]That's not correct, it would just prove that QR/2 > PS/2,
[tex]PR=QS[/tex]This statement implies
[tex]\begin{gathered} PR^2=QS^2 \\ \\ PS^2+SR^2=PQ^2+QR^2 \end{gathered}[/tex]We cannot conclude that
[tex]PS=SR=PQ=QR[/tex]The next statement is
[tex]PT=QT[/tex]A rhombus can have different diagonals, and in fact they have. Then let's go to the next one
[tex]ST=QT[/tex]That also not exactly says it's a rhombus, it's a pallelogram property.
[tex]\angle SPT=\angle QPT[/tex]By doing that we have that the diagonal bissects the angle
That implies that the angle b is also bissect.
The last statment is
[tex]\angle PTQ=\angle STR[/tex]That's literally the vertex angle, it's true always, not only in that case, therefore the only possible answer is
[tex]\angle SPT=\angle QPT[/tex]Pro
Hello. I would like help with problem. Quick answer is OK.Thank you
Answers
not continuous, 2 holes. Option A is correct
Explanations;For a function to be continuous, the left hand limit of a function must be equal to the right hand limit at the point x = a
From the graph shown you can see that the limit of the function from the left is not equal to the limit of the function from the right at x = 0. Therefore, we can conclude that there are discontinuities at x = 0.
You can also see that the function has 2 holes at (0, 0) and (0, -1).
18. The surface area of a cone is 12611 square meters. The diameter of the 5 points cone's circular base is 22 meters. What is the lateral area of the cone? Round your answer to the hundredths place value. * A 1 5 7 1 +/- B 5 -- C С 3 2 6 7 3 +/- D 1 4 7 0 2 7 +/-
Answers
data
Area = 126pi m^2
diameter = 22
TA = pi r h + pir^2
126pi = LA + pi(11)^2
LA = 126pi - 121pi
LA = 5pi
Letter B.
Fill in the gaps to factorise the expression.
2x^2+7x+3
Answers
The factorised form of the expression given in the task content is; 2x² + 7x + 3 is; (2x + 1) (x + 1).
Factorisation of quadratic expressions.It follows from the task content that the factorised form of the expression is to be determined.
On this note, the factorised form of the expression is as follows;
2x² + 6x + x + 3.
By grouping terms; we have;
(2x² + 6x) + (x + 3).
Factorise two terms each at as follows;
2x(x + 1) + 1(x+3)
(2x + 1) (x + 1)
Therefore, the factorised form of the expression; 2x² + 7x + 3 is; (2x + 1) (x + 1).
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hey can anyone help me on this im failing school xd
Answers
slope of line is -3 for points (1,0) and (0,3)
What is Slope of Line?The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.
The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.
The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is
m=y₂-y₁/x₂-x₁
From graph let us take two points (1, 0) and (0, 3)
x₁=1, x₂=0, y₁=0,y₂=3
Substitute these values in slope formula
m=3-0/0-1
m=3/-1
m=-3
Hence slope of line is -3.
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Which of the following sets of ordered pairs lies on the y-axis of a coordinate grid?
Answers
Solution
for this case the point that lies on the y axis need to satisfy that the x coordinate must be:
x= 0
then the best solution would be:
(0, -4)
west high schools population is 250 students fewer than twice the population of east high school. the two schools have a total of 2858 students. how many students attend east high school?
Answers
From properties of linear equation, 1036 students attend east high school.
What is linear equation?
An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation.
Let east high school have x students
West high school have 2x - 250
Total count of students from both the schools are 2858 students.
Then we get
x + 2x-250 = 2858
=> 3x - 250 = 2858
=> 3x = 2858 + 250
=> 3x = 3108
=> x = 3108/3
=> x = 1036
Therefore, 1036 students attend east high school.
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You spin the spinner once. What is P(2 or odd)?
Answers
Answer:
P(2 or odd)=1
Explanation:
The spinner has 3 parts.
The probability of spinning a 2:
[tex]P(2)=\frac{1}{3}[/tex]The probability of spinning an odd number (1, 3):
[tex]P(\text{odd)}=\frac{2}{3}[/tex]Therefore:
[tex]\begin{gathered} P(2\text{ or odd)=}\frac{1}{3}+\frac{2}{3} \\ =\frac{3}{3} \\ =1 \end{gathered}[/tex]Solve the system using addition. Use pencil and paper. Explain why the addition method is a good choice for solving the system. If you wanted to solve for x first, is the addition method still a good choice? Explain. X-4.6y = - 8.8 -x+2.9y = 3.7 The solution is. (Type an order
Answers
Can I please have help finding the answer? I am really struggling!
Answers
Given: An AP whose first term is -20 and a common difference of 3.
Required: To determine the 119th term of the AP.
Explanation: An AP with the first term, a, and with a common difference, d, is of the form-
[tex]a,a+d,a+2d,...,a+(n-1)d[/tex]where n is the number of terms in the AP.
The following formula gives the nth term of the AP-
[tex]a_n=a+(n-1)d[/tex]Here it is given that-
[tex]\begin{gathered} a=-20 \\ d=3 \\ n=19 \end{gathered}[/tex]Substituting these values into the formula for nth terms as-
[tex]a_{19}=-20+(19-1)3[/tex]Further solving-
[tex]\begin{gathered} a_{19}=-20+54 \\ =34 \end{gathered}[/tex]Final Answer: The 19th term of the AP is 34.
Help me pleaseeee quicklyyyyy
Answers
∠6 and ∠5 are alternative interior angle thus the measure of angles ∠5 = 45° , ∠6 = 45° ,∠7 = 45° and ∠8 = 135°.
What is an angle?An angle is a geometry in plane geometry that is created by 2 rays or lines that have an identical terminus.
The identical endpoint of the two rays—known as the vertex—is referenced as an angle's sides.
Angles 1,2,7 are the interior angles of a triangle and we know that the sum of all interior angles inside a triangle is 180°.
Therefore, ∠1 + ∠2 + ∠7 = 180°
Given, ∠1 = 70° and ∠2 = 65°
∠7 = 180° - (70 + 65) = 45°
Now, ∠8 = 180 - ∠7 ⇒ ∠8 = 135°
Now, ∠7 = ∠6 (vertical opposite angle) so ∠6 = 45°
∠6 = ∠5 (alternative interior angle) so ∠5 = 45°
Hence "∠6 and ∠5 are alternative interior angle thus the measure of angles ∠5 = 45° , ∠6 = 45° ,∠7 = 45° and ∠8 = 135°".
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jamals lawn is shaped like a square with an area of 224.9ft2 .which measurement is closest to the side length of his lawn in feet
Answers
We use the formula for the area "A" of a square with equal sides of length "l":
[tex]A=l^2[/tex]Since we know the value of the area is:
[tex]A=224.9ft^2[/tex]We substitute that value into the formula for the area:
[tex]224.9ft^2=l^2[/tex]Next, we take the square root of both sides of the equation:
[tex]\sqrt[]{224.9ft^2}=\sqrt[]{l^2}[/tex]On the right side, the exponent and the square root will cancel, and we will get "l", and on the left side, we calculate the square root:
[tex]14.99ft=l[/tex]Which can be rounded to the closest value, that is 15 ft.
Answer: 15 feet
Writing the equation of the line through two given points(1,-3) (5,-1). y=mx+b form
Answers
Given points (1,-3) and (5,-1).
Since the slope of the line passing through two points
[tex](x_1,y_1)(x_2,y_2)[/tex]The slope of the equation is
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-1-(-3)}{5-1} \\ m=\frac{2}{4} \\ m=\frac{1}{2} \end{gathered}[/tex]Therefore, the slope of the line is 1/2.
Now, use the slope and the point (1,-3) to find the y-intercept.
[tex]\begin{gathered} y=mx+c \\ -3=\frac{1}{2}\times1+c \\ c=-3-\frac{1}{2} \\ c=-\frac{-7}{2} \end{gathered}[/tex]Write the equation in slope-intercept form as
[tex]\begin{gathered} y=mx+c \\ y=\frac{1}{2}x-\frac{7}{2} \end{gathered}[/tex]