Stress that has a beneficial effect on us is called

red depicts alkali metals, green depicts alkaline earth metals, blue depicts transition metals, and purple depicts inner transition metals.

alkali metal, any of the six chemical elements that make up Group 1 (Ia) of the periodic table—namely, lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).

Group 2A of the periodic table are the alkaline earth metals: beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra). They are harder and less reactive than the alkali metals of Group 1A.

transition metal, any of various chemical elements that have valence electrons—i.e., electrons that can participate in the formation of chemical bonds—in two shells instead of only one.

The period 6 inner transition metals (lanthanides) and period 7 are actinides.

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Answer:

[tex]{ \tt{ {v}^{2} = {u}^{2} + 2as}} \\ { \tt{20 = 0 + (2 \times a \times 100)}} \\ { \tt{20 = 200a}} \\ { \tt{a = 0.1 \: {ms}^{ - 2} }}[/tex]

Answer:An antenna is an array of conductors, that is connected to the receiver or transmitter.

It transmits and receives radio waves in the horizontal directions or in a particular direction.

It may include a parasitic elements, and reflectors that can serve to direct the radio waves into a beam like pattern or some other patter.

Explanation:

It will not capture modulated radio waves.

Answer:

One idea is how, on an astronomical level, the planets can be observed to spread apart continuously.

Explanation:

Throughout various studies, many have observed that the planets continuously grow distant from each other. In fact, it is observed through our technological advances that the very galaxies are slowly drifting apart. Thus, indicating there must have been some big bang to set these galaxies and planets in motion.

Answer:

The pelican was travelling at approximately [tex]9.5\; {\rm m\cdot s^{-1}}[/tex] when it dropped the fish.

The fish hit the water at approximately [tex]16\; {\rm m\cdot s^{-1}}[/tex].

(Assumption: air resistance on the fish is negligible; [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].)

Explanation:

During the descent:

Since acceleration in the vertical direction is constant, make use of the SUVAT equation [tex]x = (1/2)\, a\, t^{2} + v_{0}\, t[/tex] to find the duration [tex]t[/tex] of the descent:

Rearrange this equation to find the duration of the descent, [tex]t[/tex]:

[tex]\begin{aligned} t &= \sqrt{\frac{2\, x}{a}} \\ &= \sqrt{\frac{2 \times 7.8\; {\rm m}}{9.81 \; {\rm m\cdot s^{-2}}} \\ &\approx 1.261\; {\rm s}\end{aligned}[/tex].

The vertical speed of the fish right before impact would be:

[tex]\begin{aligned} v_{y} &= a\, t \\ &\approx 9.81\; {\rm m\cdot s^{-2}} \times 1.261\; {\rm s} \\ &\approx 12.37\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].

In the horizontal direction, the speed of the fish was constant- same as the initial speed of the pelican. The fish travelled a horizontal distance of [tex]x = 12.0 \; {\rm m}[/tex] within the [tex]t \approx 1.26\; {\rm s}[/tex] of the descent. As a result, the horizontal velocity of the fish would be:

[tex]\begin{aligned} v_{x} &= \frac{x}{t}\\ &\approx \frac{12.0\; {\rm m}}{1.261\; {\rm s}} \\ &\approx 9.52\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].

Hence, the initial speed of the pelican would be approximately [tex]9.5\; {\rm m\cdot s^{-1}}[/tex].

Thus, right before impact:

Apply the Pythagorean Theorem to find the overall velocity of the fish at that moment:

[tex]\begin{aligned} v &= \sqrt{{v_{x}}^{2} + {v_{y}}^{2}} \\ &\approx \sqrt{{(9.52\; {\rm m\cdot s^{-1}})}^{2} + {(12.37\; {\rm m\cdot s^{-1}})}^{2}} \\ &\approx 16\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

In other words, the fish would hit the water at approximately [tex]16\; {\rm m\cdot s^{-1}}[/tex].

The total displacement of the object was 7.5 meters.

There's a relation between the common movement analysis graphs that we can always use. These relations are the following:

The derivative (slope) of a displacement vs. time graph gives you the function of speed vs. time. Also, when you take the speed vs. time graph and find its derivative, you will get the acceleration function of the observed body.

Now, doing to opposite of derivation (integration), we are able to calculate the displacement of an object when we integrate the function of velocity vs. time. This is not a complicated process when we have a linear function, because integration is just calculating the area under the curve or line of a graph.

In this case, the graph forms a right triangle with the x axis, therefore, we are able to calculate displacement by finding the area under the line of the graph. It could also be made with integration, we are going to do it with both processes as they are both used, and in some cases you have to strictly use one of the 2 in order to get the most precise answers.

When we observe the line, we can crearly tell that the area under the graph constitutes a right triangle. Hence, the area under the graph is given by the following formula:

[tex]A=\frac{bh}{2}[/tex]

Substitute the values and calculate.

(Check attached image 1 to see where the values of b and h are taken from).

[tex]A=\frac{(5)(3)}{2}\\ \\A=7.5[/tex]

Hence, the total displacement of the object was 7.5 meters.

In this method, we'll need to find the equation of the line and then generate and solve a definite integral.

Take 2 points from the line.

(0, 0) and (5, 3).

Find the slope.

Formula: [tex]m=\frac{y_{2} -y_{1} }{x_{2}- x_{1} }[/tex]

[tex]m=\frac{3-0}{5-0}= \\ \\m= \frac{3}{5}[/tex]

Find the equation of the line.

Formula: [tex]y-y_{1} =m(x-x_{1} )[/tex]

[tex]y-(0) =\frac{3}{5} (x-(0) )\\ \\y=\frac{3}{5} x\\ \\[/tex]

Integrate within the interval of interest (from 0 to 5).

[tex]\int\limits^5_0 {(\frac{3}{5} x)} \, dx \\ \\=\frac{3}{5} x^{2} *\frac{1}{2} \\ \\=\frac{3}{10} x^{2} \\\\ (\frac{3}{10} (5)^{2})-(\frac{3}{10} (0)^{2})\\ \\(\frac{3}{10} *25)-(0)\\ \\\frac{75}{10} \\ \\7.5[/tex]

Once again, the total displacement of the object was 7.5 meters.

The supplied statement states that B has the dimensions L/T².

Measurements like length, width, or height are referred to as dimensions. When you discuss an object or location's dimensions, you're referring to its size and proportions.

Dimensions include length, breadth, and height. One dimension is that of a line, two dimensions are those of a square, and three dimensions are those of a cube (3D).

Just rearranging the equation will get the dimensions.

x = Bt² ----> B= x/t²

Now you are told that x is displacement (L) and t is time (T) so sub these in.

B= L/T² Therefore the dimensions are L/T².

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There is no such things as an exact measurement there can never be a perfect instrument or measurer.

The term measurement has to do with the process of obtaining the value of a quantity. We know that measurements are done in order to give us an idea of the magnitude of a quantity. In every measurement, there is an instrument that is used for the measurement. For instance, if I want to measure length, I may have to use a meter rule to do it.

Now, there are two ways that error could be introduced into a measurement;

1) By the instrument that is used

2) By the error of the measurer

Hence, there is no such things as an exact measurement there can never be a perfect instrument or measurer.

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Answer:

The mass of the person is 56.83 kg

Explanation:

W= 557 N

We know that acceleration due to gravity (g)= 9.8 m/s^2

Now,

W= mass * acceleration due to gravity

557=m * 9.8

m= 557/9.8

m= 56.83

Answer:

her mass is 55.7 Kg.

Explanation:

Weight = Mass × Acceleration

N =ma [a= g for gravitational force acting down word]

N=Mg

find M so make mass become the subject therefore,

Mass = force / gravitational acceleration [let g=10m/s^2]

m=557 / 10

m= 55.7 kg

The number of electrons that must be removed from object A and placed on object B is 1.24 * [tex]10^{19}[/tex]

We know that,

E = k [tex]q_{1}[/tex] [tex]q_{2}[/tex] / r²

where,

E = Electrostatic force

k = Coulomb's constant

[tex]q_{1}[/tex], [tex]q_{2}[/tex] = Point charges

r = Distance between two charges

Given that,

[tex]q_{1}[/tex] = 2 + ne C

[tex]q_{2}[/tex] = - 2 - ne C

r = 3 cm

k = 9 * [tex]10^{9}[/tex] N m² / C²

E = - 68 N ( Since it is attractive )

- 68 = 9 * [tex]10^{9}[/tex] ( 2 - ne ) ( - 2 + ne ) / ( 3 * [tex]10^{-2}[/tex] )²

68 * [tex]10^{-4}[/tex] / 3 * [tex]10^{9}[/tex] = ( 2 - ne )²

2.27 * [tex]10^{-12}[/tex] = ( 2 - ne )²

1.5 * [tex]10^{-6}[/tex] = 2 - ne

ne = 1.98

n = 1.98 / 1.6 * [tex]10^{-19}[/tex] = 1.24 * [tex]10^{19}[/tex]

The given problem is an electrostatic attractive force because the two point charges are unlike charges. If the charges are like, then the electrostatic force will be repulsive.

Therefore, the number of electrons that must be removed from object A and placed on object B is 1.24 * [tex]10^{19}[/tex]

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According to the given statement The dimension of a, b and c is LT⁻² , L and T.

She took exact measurements of the room's length, width, height, and depth in one direction (for example, the distance between the ceiling and the floor of a room). The space was unexpectedly small in all three of its dimensions. Dimensions include length, breadth, and height. One dimension is that of a line, two dimensions are those of a square, and three dimensions are those of a cube (3D).

According to the principle of dimensional homogenity

Dimension of v = dimension of at  =  dimension of  b/t+c

​Dimension of a =   [tex]\frac{[\mathrm{v}]}{[\mathrm{t}]}=\frac{\mathrm{LT}^{-2}}{\mathrm{~T}}=\left[\mathrm{LT}^{-2}\right][/tex]

Dimension of b = [v][t]=[LT −1 T]=[L]

Dimension of c = [t]=[T]

According to the given statement The dimension of a, b and c is LT⁻² , L and T.

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Your weigh on the star methuselah is 38 pounds.

For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That's because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.

The element mercury has the atomic number 80 and the symbol Hg. Formerly called hydrargyrum from the Greek words Hydor (water) and Argyros, it's also known as quicksilver (silver). the sole other metallic element that is known to be liquid at standard circumstances for temperature and pressure is the halogen bromine, while metals like cesium, gallium, and rubidium melt just above temperature. Mercury may be a heavy, silvery d-block element.

Worldwide deposits of mercury, primarily as cinnabar, are found (mercuric sulfide). Grinding either synthetic mercuric sulfide or natural cinnabar yields the red color vermilion.

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Answer:

(a) The electric potential at a point midway between the charges is 160 V.

(b) The potential energy of the pair of charges is -2.4x10⁻⁷ J.

What is electrical potential energy?

The effort necessary to assemble a system of point charges by bringing them close together, as in the system from an infinite distance, is defined as the electric potential energy of the system. Alternatively, the electric potential energy of any given charge or system of charges is defined as the total work performed by an external agent in moving the charge or system of charges from infinity to the current configuration without acceleration.

Explanation:

The electric potential at a point between two point charges Q₁ = +6.00nC and Q₂ = -2.00 nC separated by 45.0 cm is found to be 160 V and the potential energy of the pair of charges is -2.4 x 10⁻⁷ J.

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The bike is travelling at 22.5 m/s after 2.5 s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a = (v – u) / t

a = (15 – 0) / 5

a = 3 m/s²

a = (v – u) / t

3 = (v – 15) / 2.5

Cross multiply

v – 15 = 3 × 2.5

v – 15 = 7.5

Collect like terms

v = 7.5 + 15

v = 22.5 m/s

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(a) Time taken by the stone to fall into the water will be t = 2.99 sec

(b) The speed with which the stone strikes the water will be v=32.91 m/s

(a)

As the stone is kicked horizontally so that the initial velocity of the stone will be [tex]v_{0} = 0[/tex]

For finding the time taken by the stone to fall into the water will be found using the following equation

[tex]y=v_{0}t + \frac{1}{2}at^{2}[/tex]

[tex]y= \frac{1}{2}at^{2}[/tex]

[tex]t=\sqrt{\frac{2y}{a} }[/tex]

[tex]t=\sqrt{\frac{2*(-44 m)}{(-9.8 m/m^{2} )} }[/tex]

[tex]t=2.99 s[/tex]

Time taken by the stone to fall into the water will be t = 2.99 sec

(b)

Since the ball was thrown horizontally, its velocity in the horizontal axis is constant and equal to its beginning velocity.

[tex]v_{0x} = v_{0} = 15 m/s[/tex]

Final velocity at vertical axis is

[tex]v_{y} = v_{0y} + at[/tex]

[tex]v_{y} = at[/tex]

therefore,

time = 2.99 sec

[tex]v_{y} = (-9.8 m/s^{2})(2.99 sec)\\ v_{y} = -29.3 m/s^{}[/tex]

The final velocity is,

[tex]v_{}=\sqrt{v_{0x} ^{2} + v_{y} ^{2} }[/tex]

[tex]v_{}=\sqrt{(15 m/s) ^{2} + (-29.3 m/s) ^{2} }[/tex]

v=32.91 m/s

The speed with which the stone strikes the water will be v=32.91 m/s

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The final velocity of the bicycle with initial velocity 7.6m/s and acceleration 4.2 m/s² is 28.4 m/s.

What is Velocity?

velocity is defined as the displacement per unit time.

What is Acceleration?

Acceleration is defined as the rate of change of velocity per unit time

i.e.

acceleration = (final velocity (v)-initial velocity)/time taken (t)

given:

initial velocity of the bicycle (u) = 7.6m/s

acceleration of the bicycle (a)=4.2m/s²

displacement of the bicycle=89m

using newtons third law of motion :

v²-u²=2×a×s

using the given value in question we get

v² = (7.6)²+2×4.2×89

v=28.4 m/s

the final velocity of the bicycle with initial velocity 7.6m/s and acceleration 4.2 m/s² is 28.4 m/s.

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The distance travelled in that month is 870.92 miles

We'll begin by calculating the circumference of the tyre. This can be obatined as follow:

C = 2πr

C = 2 × 3.14 × 13

C = 81.64 in

63360 inches = 1 mile

Therefore,

81.64 inches = (81.64 inches × 1 mile) / 63360 inches

81.64 inches = 0.00129 mile

Distance = number × circumference

Distance = 0.00129 × 675135

Distance = 870.92 miles

Thus, the distance travelled in that month is 870.92 miles

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Knowing that Newton's first law is the law of inertia.

The law of inertia helps us when we have problems with bodies that are motionless or moving at constant speed.

The first law tells us that: "A body remains at rest or moves with constant speed if a resultant force equal to zero acts on it."

If the body is at rest or moves with constant speed without acceleration, then the sum of the forces in both the x, y or z axis is equal to zero.

Answer:

Velocity is distance + direction / time

so your answer is

75 km north / 1.5 hours

75/1.5  km north/ hours =

50 km / hours north

The resultant displacement is 32.4 m due west of south.

The term displacement has to do with the change in the position of a body in a particular direction. Displacement is a vector quantity. We have to find the resultant displacement algebraically;

Hence;

Resultant displacement = √((26.5)^2 + 18.7)^2

Resultant displacement = 32.4 m due west of south

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Answer:

There are a few ways that traffic lights can sense the presence of a car. One way is by using inductive loops that are installed on the road. These loops detect changes in the magnetic field caused by a car passing over them. Another way is by using infrared sensors that detect the heat signature of a car.

Explanation:

Hope this helps!

Based on the data attached, the option of the conclusion that could be made from this data is option B. It snows less in Green Bay than in Kalamazoo on average.

.

The term snows is known to be a kind of a small white crystals of ice that is known to be formed as a result of  direct water vapor of the air.

It is known to be a measure or a mass of snowflakes that is said to have  fallen to earth.

Therefore, from the data, one can see that the snow fell a lot in Buffalo and from it one can also see that Kalamazoo has almost times 2 of the snow in Green Bay.

Therefore, Based on the data attached, the option of the conclusion that could be made from this data is option B. It snows less in Green Bay than in Kalamazoo on average.

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The final speed of the race car, given the data is 49 m/s (Option C)

The acceleration of an object is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

With the above formula, we can determine the final velocity of the car. Details below:

a = (v – u) / t

0.8 = (v – 33) / 20

Cross multiply

v – 33 = 0.8 × 20

v – 33 = 16

Collect like terms

v = 16 + 33

v = 49 m/s

Thus, the final velocity of the car is 49 m/s (Option C)

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Answer: gravity of earth = 9.8 n/s , new weight of the body on other planet = mg = 1.913 ×6×9.8=112..5

Explanation:

That would be the proportion between the difference and the total of the two amplitudes (when they are in phase, or as they say, "add coherently") (when they are out of phase or "add destructively").

The amplitude of a wave is the maximum displacement of a particle on the medium from its rest point. The distance between the rest and the crest can be thought of as the amplitude. Measuring the amplitude from the rest position to the trough position is another method of determining it.

The height between the center line and the peak is known as the amplitude (or to the trough). Alternatively, we might multiply the height from highest to lowest places by 2.

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The distance traveled by the object from its initial position is 384 cm.

Distance is the sum of an object's movements, regardless of direction. Without respect to the object's starting or finishing positions, distance can be defined as the amount of space it has traveled.

An object is moving in a straight path.

The speed of the object from its initial position is 12.8 cm/s.

The object is moving for 05 minutes.

Then, t = 0.5 min = 0.5 × 60 = 30 seconds.

Now, the speed of an object is the distance of the object per unit time.

Therefore,

s = d / t

d = s × t

d = ( 12.8 cm/s ) × ( 30 s )

d = 384 cm

Hence, the object's position from its initial position is 384 cm.

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Answer: a place in space where gravity pulls so much that even light can not get out.

Answer:

black holes are holes that can suck this world with its high gravity

If the voltage of the power supply is increased by a factor of 3 and the resistance was held constant, the new current will be 0.008 A or 8 mA

Power is the rate at which work is done. Electrical power is measured in Watt.

Given that a circuit is wired with a power supply, a resistor and an ammeter (for measuring current). The ammeter reads a current of 24 mA Determine the new current if the voltage of the power supply was increased by a factor of 3 and the resistance was held constant

Let the

From the power formula, power will always be constant. That is, initial power will be the same with new power

Since P = IV

24/1000 V = I × 3V

0.024V = 3IV

V cancels out

3I = 0.024

I = 0.024/3

I = 0.008 A

Therefore, the new current will be 0.008 A.

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The skateboarder will travel a distance of 9.19 m

We know that,

a = ( v - u ) / t

Δv = ( v + u ) / 2 ( If acceleration is constant )

Δv = d / t

where,

a = Acceleration

v= Final velocity

u = Initial velocity

t = Time taken

d = Displacement

Δv = Average velocity

Given that,

u = 1.8 m / s

a = 1.5 m / s²

t = 2.5 s

a = ( v - u ) / t

1.5 = ( v - 1.8 ) / 2.5

v = 3.75 + 1.8

v = 5.55 m / s

Δv = ( 5.55 + 1.8 ) / 2

Δv  = 3.675 m / s

d = Δv * t = 3.675 * 2.5

d = 9.19 m

If the initial and final velocity is known, average velocity can be calculated by taking the average value of initial and final velocity, if the acceleration is constant.

Therefore, the skateboarder will travel a distance of 9.19 m

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