Subtract these mixed numbers.

16 11/12 - 14 2/12

2 3/4
3 2/4
4 1/4

The statement which correctly describes the data set include the following:

D. the data is bivariate and numerical.

In Mathematics, a bivariate data can be defined as a type of data set which comprises information that are based on two (2) variables, usually two types of related data.

In Mathematics and statistics, a numerical data can be defined as a type of data set that is primarily expressed in numbers only. This ultimately implies that, a numerical data simply refers to a type of data set consisting of numbers (numerals), rather than words or letters.

Thus, In conclusion, we can logically deduce that the given data set is both bivariate and numerical.

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Answer:

70/200

Step-by-step explanation:

1/8+1/20

5/40+2/40

70/200

Answer:

the answer isnt on there but i got 27/40.....

Step-by-step explanation:

1 cake + 4 kids = 4 pieces of cake

Ana ( one full piece)  + Benito ( one full piece) = 2/4 or 1/2

so we already know half the cake is gone.

Carlos ate half, so 1/2 of 1/4 equals 1/8

Diana ate 1/5 of her's, so 1/5 of 1/4 equals 1/20

now, we add.

1/4 + 1/4 + 1/8 + 1/20 = 27/40

$1,560

To calculate simple interest, we use the formula:

Simple interest = Principal * Rate * Time

Given that Bianca invested $6,500 at a rate of 3%, the principal is $6,500 and the rate is 0.03 (since 3% is equivalent to 0.03 as a decimal).

We are asked to find the simple interest after 8 years, so the time is 8 years.

Using the formula, we get:

Simple interest = $6,500 * 0.03 * 8

Simple interest = $1,560

Therefore, the simple interest on Bianca's investment will be $1,560 after 8 years.

The confidence interval:

Lower Endpoint: 6.418

Upper Endpoint: 6.782

To construct the confidence interval, we can use the formula:

CI = x ± z(σ/√n)

Where:

x = sample mean = 6.6

σ = population standard deviation = 2.3

n = sample size = 432

z = z-score for 90% confidence level = 1.645 (from the standard normal distribution table)

Plugging in the values, we get:

CI = 6.6 ± 1.645(2.3/√432)

CI = 6.6 ± 0.182

Therefore, the 90% confidence interval for the true mean number of reproductions per hour for the bacteria is:

Lower Endpoint: 6.418

Upper Endpoint: 6.782

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Rotter Partners is planning a major investment, and to ensure that the investment is profitable, it is essential to understand the expected profit from the investment. The probability distribution of profits from similar investments indicates that the expected profit (mx) can be calculated as the weighted average of profits, where the weights are the probabilities associated with each profit level.

Based on the given probability distribution, the expected profit (mx) can be calculated as follows:

mx = (1 x 0.1) + (1.5 x 0.2) + (2 x 0.4) + (4 x 0.2) + (10 x 0.1)
mx = 0.1 + 0.3 + 0.8 + 0.8 + 1
mx = 2.7

Therefore, the expected profit from the investment is $2.7 million. This estimate is valuable to Rotter Partners as it can help them make informed decisions about the investment. If the expected profit is lower than the cost of the investment, then the investment may not be worthwhile. On the other hand, if the expected profit is higher than the cost of the investment, then the investment is likely to be profitable. In any case, the expected profit is a useful metric for assessing the potential success of the investment.

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The 9th term of this geometric sequence 10, 40, 250, 1250, ....​ include the following: 655,360.

In Mathematics, the nth term of a geometric sequence can be calculated by using this mathematical equation (formula):

aₙ = a₁rⁿ⁻¹

Where:

Next, we would determine the common ratio as follows;

Common ratio, r = a₂/a₁

Common ratio, r = 40/10

Common ratio, r = 4

For the 9th term, we have:

a₉ = 10(4)⁹⁻¹

a₉ = 655,360.

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To determine how many litres of each ingredient (X and Y) should be added to every 10,000 litres of plant feed to minimize costs while meeting the additive requirements.

Here's a step-by-step explanation using the given information:

1. Define the variables:
Let x = litres of ingredient X
Let y = litres of ingredient Y

2. Formulate the constraints based on the additive requirements:

Additive A: 2x + 8y ≥ 480
Additive B: 5x + 10y ≥ 800
Additive C: 10x + 4y ≥ 640
Storage constraint: x ≤ 120, y ≤ 120

3. Set up the objective function to minimize cost:
Cost = 25x + 50y

4. Solve the linear programming problem using the constraints and the objective function. You can use graphical methods, the Simplex method, or software tools to find the optimal solution.

5. The optimal solution will provide the number of litres of ingredient X (x) and ingredient Y (y) that should be added to every 10,000 litres of plant feed to minimize costs while satisfying the given constraints.

Keep in mind that this is a mathematical model and real-life situations might require adjustments or additional considerations.

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The ratio of total number of sunflowers to the total number of flowers in her garden is 12/27.

A ratio is an expression which compares the two quantities. It can be expressed as a fraction.

Given that Mariam has 15 orchids and 12 sunflowers in her garden, then we can conclude that;

total number of flowers in her garden = 15 + 12

                                                               = 27

Thus,

the ratio of total number of sunflowers to the total number of flowers in her garden = (total number of sunflowers)/ (total number of flowers)

            = 12 / 27

The required ratio is 12/ 27.

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the answer to your math question is (−2,−27)

Answer:

(-2,-27)

Step-by-step explanation:

use the formula

x = b/2a

to find the maximum and minimum

Answer:

3x + 5x = 96

8x = 96, so x = 12

There are currently 3(12) = 36 pens and 5(12) = 60 pencils in the box, so 60 - 36 = 24 more pens should be put in the box.

Jonathan and Seth both had a time per lap of 2 minutes, which means they swam at the same rate.

To determine who swam at the same rate, we need to calculate the time per lap for each swimmer. This can be done by dividing the time by the number of laps.

Jonathan: 4 ÷ 2 = 2 minutes per lap

Julian: 1 ÷ 1 = 1 minute per lap

Seth: 6 ÷ 3 = 2 minutes per lap

Bennett: 21 ÷ 7 = 3 minutes per lap

Taylor: 7 ÷ 4 = 1.75 minutes per lap

From the calculations, we can see that Jonathan and Seth both had a time per lap of 2 minutes, which means they swam at the same rate.

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The credit-card purchase price of the item after a 4% discount is $87.50.

To find the credit-card purchase price of the item, we need to first calculate the amount of discount offered for paying in cash. This can be done by multiplying the cash price by the discount rate:

$84 x 0.04 = $3.36

This means that the discount offered for paying in cash is $3.36. To find the credit-card purchase price, we need to add this discount amount back to the cash price:

$84 + $3.36 = $87.36

Therefore, the credit-card purchase price of the item is $87.36. However, this is not the final answer because we need to round it to the nearest cent. The nearest cent is $87.50 since $87.36 is closer to $87.50 than it is to $87.49.

Therefore, the credit-card purchase price of the item is $87.50.

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" Here, "a large sum of money" is the subject, "was credited" is the verb.

The sentence pattern refers to the structure of the sentence in terms of its basic elements such as subject, verb, object, complement, etc. Here are the answers to each question:

i. The sentence pattern of "The pirate sold me a boat" is SVDO (Subject-Verb-Direct Object), where "pirate" is the subject, "sold" is the verb, and "boat" is the direct object, and "me" is the indirect object.

vii. The sentence pattern of "Laughter is the best medicine" is SVA (Subject-Verb-Adjective), where "laughter" is the subject, "is" is the verb, and "the best medicine" is the adjective complement.

viii. The correct sentence is "Cats and dogs do not get along." Here, "Cats and dogs" is the subject, "do not get along" is the verb phrase.

ix. The correct sentence is "Both his brothers as well as Rishi are interested in agriculture." Here, "his brothers as well as Rishi" is the subject, "are interested" is the verb.

x. The correct sentence is "A large sum of money was credited in my account." Here, "a large sum of money" is the subject, "was credited" is the verb.

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From mass unit conversion where using a numeric constant ( 0.001), the total weight of vegitables ( carrots and beans) in a bag is equals to the 3.420 kilograms.

A unit conversion is used to expresses the same property as a different unit of measurement. Unit conversion is a process with serval steps that involves multiplication or division by a numerical factor called conversion factor. So, there are different unit conversions charts like mass unit conversation, length unit conversion etc. Now, we have, a bag contains carrots and beans.

Weight of carrots in bag = 3 kg

weight of beans in bag = 420 grams

We have to determine total weight that bag contains. As we see both weights are present in different units ( i.e, kg and grams). Using unit conversion, 1 kilogram = 1000 grams

=>[tex] 1 gram= \frac{1}{1000}=0.001 kg[/tex]

So, 420 grams = 420× 0.001 = 0.420 kg

Total weight of vegitables in bag = weight of carrots + weight of beans

= 3 kg + 0.420 kg

= 3.420 kg

Hence, required value is 3.420 kilograms.

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And then write:

Y(s) = (-4X(s))/s

Let's take a step-by-step approach to solving this problem.

First, we are given the differential equation:

y'' + 4y = 0

To solve this using Laplace transforms, we take the Laplace transform of both sides:

L{y'' + 4y} = L{0}

Using the linearity property of the Laplace transform and the fact that L{y''} = s^2Y(s) - s*y(0) - y'(0), we can simplify this to:

s^2Y(s) - s*y(0) - y'(0) + 4Y(s) = 0

Next, we solve for Y(s):

Y(s)(s^2 + 4) = s*y(0) + y'(0)

Y(s) = (s*y(0) + y'(0))/(s^2 + 4)

To find the partial fraction decomposition of Y(s), we factor the denominator:

s^2 + 4 = (s + 2i)(s - 2i)

And then use partial fractions to write:

Y(s) = (a/(s + 2i)) + (b/(s - 2i))

To solve for a and b, we multiply both sides by the denominators:

Y(s)(s + 2i)(s - 2i) = a(s - 2i) + b(s + 2i)

And then substitute s = -2i and s = 2i to get two equations:

a(-4i) = -2iy(0) + y'(0) - b(4i)

a(4i) = 2iy(0) + y'(0) + b(4i)

Solving for a and b, we get:

a = (y(0) + 2iy'(0))/(4i)

b = (y(0) - 2iy'(0))/(4i)

Now, we can write the partial fraction decomposition of Y(s):

Y(s) = ((y(0) + 2iy'(0))/(4i))/ (s + 2i) + ((y(0) - 2iy'(0))/(4i))/(s - 2i)

To find y(t), we need to take the inverse Laplace transform of Y(s). We can use the partial fraction decomposition to do this:

y(t) = (1/2)*(y(0)cos(2t) + (y'(0)/2)sin(2t))

Now, we move on to the second part of the problem, which is to use Laplace transforms to solve the initial value problem:

x(0) = 0, y(0) = 0

We are given the following system of differential equations:

x' = y

y' + 4x = 0

Taking the Laplace transform of both equations, we get:

sX(s) = Y(s)

sY(s) + 4X(s) = 0

Solving for Y(s) and X(s), we get:

Y(s) = X(s)/s

X(s) = -4Y(s)/s

To find the partial fraction decomposition of X(s) and Y(s), we factor the denominators:

sY(s) + 4X(s) = 0

sX(s) = Y(s)

s(sY(s) + 4X(s)) = 0

sX(s) = Y(s)

s^2Y(s) + 4sX(s) = 0

sX(s) = Y(s)

And then write:

Y(s) = (-4X(s))/s

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The car must achieve an acceleration of 120 mi/h² at some point between 2:00pm and 2:10 pm.

To find the acceleration the car must achieve using the Mean Value Theorem (MVT), we need to follow these steps:
1. Calculate the change in speed.
2. Calculate the change in time.
3. Apply the MVT to find the acceleration.
Step 1: The car's speedometer reads 50mph at 2:00 pm and 70mph at 2:00 pm. The change in speed is 70mph - 50mph = 20mph.
Step 2: The change in time is 10 minutes, which we need to convert to hours. To do this, divide 10 by 60 (since there are 60 minutes in an hour). So, 10/60 = 1/6 hour.
Step 3: Apply the MVT. The MVT states that there must be a point in time where the average acceleration equals the instantaneous acceleration. The average acceleration (a) can be found using the formula a = Δv/Δt. Here, Δv is the change in speed (20mph) and Δt is the change in time (1/6 hour).
So, a = (20mph) / (1/6 hour) = 20 * 6 = 120 mi/h².

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The solutions of the given expressions are as follows :

(a) (x^2+3x+9) / (x^2+9x+18) = x+2

(b) x ≈ 0.004 or x ≈ 0.056

(c)  we have two solutions: x = 0 or x = V8 (cube root of 8)

a. To divide *3-27 by 9-x^2, we can first factor both  expressions :
*3-27 = 3*(-9)
9-x^2 = (3-x)(3+x)
So we have:

(*3-27) / (9-x^2) = (3*(-9)) / ((3-x)(3+x))

To divide x^2+3x+9 by x^2+9x+18, we can use long division or synthetic division. Using long division, we have:

         x + 2
 -------------------
x^2 + 9x + 18 | x^2 + 3x + 9
         -x^2 - 2x
         ----------
                x + 9
                -x - 9
                -------
                      0

So we have:

(x^2+3x+9) / (x^2+9x+18) = x+2

b. To solve V3x + 2-27x = 0, we can first isolate the radical:

V3x = 27x - 2

Then we can square both sides:

3x = (27x - 2)^2

Expanding the right side and simplifying, we get:

3x = 729x^2 - 108x + 4

Bringing everything to one side, we have:

729x^2 - 111x + 4 = 0

Using the quadratic formula, we get:

x = (111 ± V(111^2 - 4*729*4)) / (2*729)

x ≈ 0.004 or x ≈ 0.056

c. To solve 3x^7 - 24x^4 = 0, we can factor out x^4:

3x^4(x^3 - 8) = 0

So we have two solutions:

x = 0 or x = V8 (cube root of 8)

Note that the equation has a total of seven roots (since it is a seventh-degree equation), but we only found two of them. The other five roots are complex numbers.

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In order to identify labeled points that do not lie on the x-y plane, several methods can be utilized.

The software tools MATLAB, Python's Matplotlib or Excel can be used to create a 3D plot of the labeled points. Through this approach, non-planar points become easily recognizable. It is possible to label points with different colors or symbols, based on their classification which would provide an added advantage in noticing any types of pattern or trends.

An alternate route involves having access to equation(s) of the fitted plane (e.g., by means of linear regression). Herein lies the ability to measure the distance between each point and the plane using the point-to-plane distance formula. Based upon fitting, if any point has substantial distance from the plane then it is likely to be situated off the plane.

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Answer:  is x=3

Step-by-step explanation:

Answer:

The awnser is 9

Step-by-step explanation:

1 × 9 = 9 9 dovided by 7 = -2 + 8 is 6 6 times 0 is 0 0 + 1 = 1 1 × 6 = 6

Note that this prompt examines the given data using scatter plot whose details is analyzed below.

1) The scatter plot showing the relationship between the numbers of points scored and the numbers of rebounds is attached.

2) The association between the numbers of points scored and the numbers of rebounds is a positive one. This means that generally, there is a tendency to get more points when the number of rebounds is high.

3) No, we cannot conclude that greater numbers of points scored cause

greater or lesser numbers of rebounds. This would be an inverse relationship which contradicts our findings above.

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Answer:

Step-by-step explanation:

You want the common ratio and first 3 terms of a decreasing geometric progression with the sum of the first three terms being 7, and their product being 8.

Let the first term be represented by x, and let r represent the common ratio. Then the first three terms are ...

  x, xr, xr²

Their sum is ...

  7 = x +xr +xr²

Their product is ...

  8 = (x)(xr)(xr²) = (xr)³

Taking the cube root of the product equation, we have ...

  2 = xr

Substituting this into the first equation, we have ...

  7 = x +2 + 2r

  5 = x +2r   ⇒   x = 5 -2r

And substituting back into the above, we get ...

  2 = (5 -2r)(r)

  2r² -5r +2 = 0

  (2r -1)(r -2) = 0

  r = 2 or 1/2

We want r < 1, so r = 1/2.

  x = 5 -2(1/2) = 4

For x = 4, r = 1/2, the first three terms are ...

  x, xr, xr² = 4, 2, 1

__

Additional comment

The equations are nicely solved by a graphing calculator. In the attached, we used y instead of r. We want the solution with y<1.

The two solutions give rise to terms 4, 2, 1 (decreasing) or 1, 2, 4 (increasing).

1. I imagine buying 100 shares of Amazon.com Inc. on January 3, 2020, when the stock price was $93.75, investing $9,375.  

Today, October 31, 2022, the stock price of Amazon.com Inc. is $102.44.

2. The real return on my investment in Amazon.com Inc was a net loss of  7.12% or $667.60.

3. The company I selected to buy its stock three years ago was Amazon.com Inc.

4. I decided on Amazon.com Inc., hoping to earn spectacular returns since it is a multinational technology company.

5. When I consider the actual return on the stock investment in Amazon.com Inc., I think it was an unwise investment.

6. The investment returned a negative real value because I realized less than I initially invested; I actually lost about $667.60 overall.

Stock investment is the purchase of shares for an ownership interest in a publicly-listed company.

The investor makes the investment with the hope that the investee will grow and perform well over some period, enabling the investor to earn some real returns (in the form of dividends and capital appreciation).

Purchase of 100 shares Jan. 3, 2020 = $9,375 (100 x $93.75)

Sales of 100 shares Oct. 31, 2022 = $10,244 (100 x $102.44)

Tax (10%) = $1,024.40 ($10,244 x 10%)

Inflation (3%) = $307.32 ($10,244 x 3%)

Administration fee on sales (2%) = $204.88 ($10,244 x 2%)

Real Returns in dollars = $8,707.40 ($10,244 - $1,024.40 - $307.32 - $204.88)

Loss on returns = $667.60 ($8,707.40 - $9,375)

Loss percentage = 7.12% ($667.60/$9,375 x 100)

Unfortunately, Amazon.com Inc. did not pay any dividends during the period of my investment, and I really lost funds to taxes, inflation, and administration fees when I sold it.

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The approximate probability that between 12 and 20 patients, inclusive will experience weight gain as a side effect is 0.4147.

Normal approximation can be used to approximate the binomial distribution when the sample size is large enough (n >= 30) and the probability of success (p) and failure (q=1-p) are not too small or too large. In this case, we have a sample size of 500, which is sufficiently large, and the probability of success (p=0.03) and failure (q=0.97) are not too small or too large.

To approximate the probability that 15 or fewer users will experience weight gain as a side effect, we can use the normal approximation to the binomial distribution with mean (μ) = np = 500 x 0.03 = 15 and standard deviation (σ) = sqrt(npq) = sqrt(500 x 0.03 x 0.97) = 3.814. Then, we can use the normal cumulative distribution function (normalcdf) to calculate the probability that X ≤ 15, where X is the number of users who experience weight gain.

normalcdf(–1E99,15.5,15, 3.814) = 0.5522

Therefore, the approximate probability that 15 or fewer users will experience weight gain as a side effect is 0.5522.

To approximate the probability that 24 or more users experience weight gain as a side effect, we can use the normal approximation to the binomial distribution with the same mean and standard deviation as before. Then, we can use the normal complementary cumulative distribution function (normalccdf) to calculate the probability that X ≥ 24.

normalccdf(23.5,15,3.814) = 0.0097

Therefore, the approximate probability that 24 or more users experience weight gain as a side effect is 0.0097.

To approximate the probability that between 12 and 20 patients, inclusive will experience weight gain as a side effect, we can use the normal approximation to the binomial distribution with the same mean and standard deviation as before. Then, we can use the normal cumulative distribution function (normalcdf) to calculate the probability that 12 ≤ X ≤ 20.

normalcdf(11.5,20.5,15,3.814) = 0.6081 - 0.1934 = 0.4147

Therefore, the approximate probability that between 12 and 20 patients, inclusive will experience weight gain as a side effect is 0.4147.

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The probability that a randomly selected adult has an IQ greater than 134.4 is 0.025 or 2.5%

To find the probability that a randomly selected adult has an IQ greater than 134.4, we need to calculate the z-score and then find the corresponding area under the standard normal distribution curve.

The z-score is calculated as: [tex]z= \frac{x-μ}{σ}[/tex]

where x is the IQ score, μ is the mean IQ score, and σ is the standard deviation of IQ scores.

Substituting the given values, we get:

[tex]z = \frac{(134.4 - 101.1)}{17}[/tex]

z = 1.96

Using a standard normal distribution table, we find that the area to the right of z = 1.96 is approximately 0.025. Therefore, the probability that a randomly selected adult has an IQ greater than 134.4 is 0.025 or 2.5%.

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Result:

Probability that a student studied for 5 hours = C. 0.23

The find out the probability a student studied for 5 hours:

Divide the number of students who studied for 5 hours by the total number of students surveyed:

Probability = Number of students who studied / Total number of students surveyed

Given:

Number of students who studied for 5 hours = 7

Total number of students surveyed = 1 + 3 + 2 + 5 + 9 + 7 + 3 = 30

Therefore, probability for a student studied for 5 hours =

7 / 30 = 0.23 or 23%.

So, option C. 0.23 is correct.

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The transformation of the triangle is given by

a) ∠Y → ∠Q

b) ∠X → ∠P

c) YZ → QR

d) XZ → PR

e) ΔZXY → ΔRPQ

Given data ,

Let the first triangle be represented as ΔXYZ

Now , let the second triangle be represented as ΔPQR

Now , a sequence of rigid motions to map ΔXYZ to ΔPQR

So , the series of transformation for the triangle is given by

a) ∠Y → ∠Q

b) ∠X → ∠P

c) YZ → QR

d) XZ → PR

e) ΔZXY → ΔRPQ

Hence , the transformation is solved

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First, we can simplify the equation by isolating the variable on one side:

2√x + 6 - 3 = 19

2√x + 3 = 19

2√x = 16

√x = 8

Now we can square both sides of the equation to isolate x:

(√x)² = 8²

x = 64

Therefore, the solution to the equation 2√x + 6 - 3 = 19 is x = 64, which corresponds to answer choice (e).

Hope this helped (:

Answer: B

Step-by-step explanation:

Hope this helps! :)

This is because the function f(t) is a constant function, which is an even function and has no odd component.

The half-range Fourier series is a representation of a periodic function over a finite interval, where the function is assumed to be even or odd. In the case of the function f(t) = 0, the function is even and the interval is from 0 to π.

(a) The half-range cosine series:

To find the half-range cosine series, we first need to find the Fourier coefficients:

[tex]a_0 &= \frac{2}{\pi} \int_0^{\pi} f(t) dt = \frac{2}{\pi} \int_0^{\pi} 0 dt = 0 \a_n &= \frac{2}{\pi} \int_0^{\pi} f(t) \cos(nt) dt = \frac{2}{\pi} \int_0^{\pi} 0 \cos(nt) dt = 0 \\[/tex]

Since all the Fourier coefficients are zero, the half-range cosine series for f(t) is:

[tex]$\begin{align*}f(t) &= \frac{a_0}{2} + \sum_{n=1}^{\infty} a_n \cos(nt) \&= 0\end{align*}$[/tex]

b) The half-range sine series:

To find the half-range sine series, we need to find the Fourier coefficients:

[tex]b_n &= \frac{2}{\pi} \int_0^{\pi} f(t) \sin(nt) dt = \frac{2}{\pi} \int_0^{\pi} 0 \sin(nt) dt = 0 \\[/tex]

Since all the Fourier coefficients are zero, the half-range sine series for f(t) is:

[tex]$\begin{align*}f(t) &= \sum_{n=1}^{\infty} b_n \sin(nt) \&= 0\end{align*}$[/tex]

Therefore, both the half-range cosine series and the half-range sine series for f(t) are zero. This is because the function f(t) is a constant function, which is an even function and has no odd component.

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Fill in each blank so that the resulting statement is true: A function f has an inverse that is a function if there is no vertical line that intersects the graph of f at more than one point. Such a function is called a/an injective function or a one-to-one function.

A function is injective if every distinct input produces a distinct output. Geometrically, this means that the function does not repeat any output values . If there is a vertical line that intersects the graph of f at more than one point, then the function fails to be injective, since two distinct input values will produce the same output value. In this case, the function does not have an inverse that is a function.

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Full Question ;

Fill in each blank so that the resulting statement is true. A function f has an inverse that is a function if there is no ____ line that intersects the graph of f at more than one point. Such a function is called a/an ____ function.