Answer:
19÷100×467520=88828.8
88828.8+467520=556348.8
Nearest hundred=$556300
what is this (6x+4)+26=90 ?
Answer:
x=10
Step-by-step explanation:
(6x+4)+26=90
6x+4+26=90
6x+30-30=90-30
6x÷6=60÷6
x=10
Answer:
the answer is X=10
(6x+4)+26=90
6x +30=90
6x= 90÷30
6x=60
X = 60÷6
X= 10
(show work pls and ty)
Find the volume of the triangular prism; do not round.
Answer:
[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]
Step-by-step explanation:
[tex]\textsf{For this problem, we are asked to find the Volume of a Triangular Prism.}[/tex]
[tex]\large\underline{\textsf{What is Volume?}}[/tex]
[tex]\textsf{Volume is the amount of space a figure occupies. Volume is measured in Cubic units.}[/tex]
[tex]\large\underline{\textsf{We are Given;}}[/tex]
[tex]\textsf{The Height is 6.1m. Keep in mind that the Height is the Perpendicular Distance}[/tex]
[tex]\textsf{between 2 bases.}[/tex]
[tex]\textsf{The base is; (4.4 x 2.5).}[/tex]
[tex]\textsf{The Height of the Triangle is 2.5m.}[/tex]
[tex]\large\underline{\textsf{Necessary Formulas;}}[/tex]
[tex]\mathtt{Volume=(Base) \times Height}[/tex]
[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]
[tex]\large\underline{\textsf{For this Problem;}}[/tex]
[tex]\mathtt{Volume=(Triangles' \ Area) \times Height}[/tex]
[tex]\large\underline{\textsf{The area of a Triangle is;}}[/tex]
[tex]\mathtt{Area = \frac{1}{2} (Base \times Height)}[/tex]
[tex]\textsf{Find the area of the base first.}[/tex]
[tex]\large\underline{\textsf{Substitute;}}[/tex]
[tex]\mathtt{Area = \frac{1}{2} (4.4 \times 2.5)}[/tex]
[tex]\boxed{\mathtt{Area = 5.5m^{2}.}}[/tex]
[tex]\textsf{We know the Base, now let's find the volume of the figure.}[/tex]
[tex]\large\underline{\textsf{Substitute;}}[/tex]
[tex]\mathtt{Volume=5.5 \times 6.1}[/tex]
[tex]\boxed{\mathtt{Volume=33.55m^{3}}}[/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textsf{Find the \boxed{\bf volume} of a triangular prism is:}[/tex]
[tex]\mathsf{\dfrac{1}{2}(\boxed{\bf b}ase\times\boxed{\bf h}eight\times\boxed{\bf l}ength) = \boxed{\bf v}olume}[/tex]
[tex]\huge\textsf{Your \boxed{\bf equation} should look like:}[/tex]
[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]
[tex]\huge\textsf{\boxed{\bf Step-by-step} explanation can be:}[/tex]
[tex]\mathsf{volume = \dfrac{1}{2}(4.4\ m \times 2.5\ m\times 6.1\ m)}[/tex]
[tex]\mathsf{volume = \dfrac{1}{2}\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]
[tex]\mathsf{volume = 0.5\times 4.4\ m \times 2.5\ m\times 6.1\ m}[/tex]
[tex]\mathsf{volume = 2.2\ m\times 15.25\ m}[/tex]
[tex]\mathsf{volume = 33.55}[/tex]
[tex]\huge\textsf{Therefore your \boxed{\bf answer} should be:}[/tex]
[tex]\huge\boxed{\mathsf{volume = 33.55m^2}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
A hollow ball is made of rubber that is 2 centimeters thick. The ball has a radius to the outside surface of 6 centimeters.
What is the approximate volume of rubber used to make the ball?
Use 3.14 for pi.
Responses
33.5 cm³
33.5 cm³
267.9 cm³
267.9 cm³
636.4 cm³
636.4 cm³
904.3 cm³
Answer:
636.4 cm³
Step-by-step explanation:
How do you simplify rational expressions
Answer:
Ok so,
Step-by-step explanation:
Step 1: Factor the numerator and the denominator.
Step 2: List restricted values.
Step 3: Cancel common factors.
Step 4: Reduce to lowest terms and note any restricted values not implied by the expression.
PLEASE HURRY IM RUNNING LATE WITH THIS!,
Find the volume of the pyramid. Round to the nearest tenth if necessary.
Answer:
410.6 cubic cm
Step-by-step explanation:
Formula V = (l x w x h) / 3
V = ( 8 x 14 x 11) / 3
V = 1232 / 3
V = 410.6 cubic cm
can someone pls help
Step-by-step explanation:
A triangle has its interior angle sum as 180°
[tex]{ \tt{ \angle R + \angle S + \angle T = 180 \degree}}[/tex]
[tex]{ \colorbox{silver}{input \: angles}} \\ \\ { \tt{31 \degree + (x + 4) \degree + (3x + 9) \degree = 180 \degree}} \\ \\ { \tt{44 + 4x = 180 \degree}} \\ \\ { \tt{4x = 136}} \\ \\ { \tt{x = 34}} \\ \\ { \colorbox{silver}{for \:R }} \\ \\ { \tt{ m\angle S =x + 4 = 34 + 4}} \\ \\ { \boxed{ \tt{m \angle S = 38 \degree}}} \\ \\ { \colorbox{silver}{for \:T }} \\ \\ { \tt{m \angle T = 3x + 9 = (3 \times 34) + 9}} \\ \\ { \tt{m \angle T = 111 \degree}}[/tex]
1.) 25 - 3x = 88
2.) -11 = 7 - x
3.) 95 = -4 + 33x
Answer: hope this helps ♡
1.) x = -21
2.) x = 18
3.) x = 3
Step-by-step explanation:
(minus&minus = plus) (minus&plus = minus) (plus&minus = minus)
1.) 25 - 3x = 88
25 - 25 - 3x = 88 - 25
-3x = 63
-3x ÷ 3 = 63 ÷ 3
-x = 21 → x = -21
2.) -11 = 7 - x
-11 - 7 = 7 -7 -x
-18 = -x
18 = x → x = 18
3.) 95 = -4 + 33x
95 + 4 = -4 + 4 + 33x
99 = 33x
99 ÷ 33 = 33x ÷ 33
3 = x → x = 3
[tex] \text{1 ] 25 - 3x = 88 }[/tex]
[tex] \rm{↣25 - 3x = 88} \\ \rm↣- 3x= 88 - 25 \\ \rm↣- 3x = 63 \\ \rm↣x = \cancel \frac{63}{ - 3} \\ \underline{ \underline{\rm ↣\purple{ \: x = -21 \: }}}[/tex]
[tex] \: [/tex]
_________
[tex] \text{2 ] -11 = 7 - x }[/tex]
[tex] \rm \: ↣-11 = 7 - x \\ \rm↣ -11 - 7 = -x \\ \rm↣ \cancel- 18 = \cancel -x\\\underline{ \underline{ \rm↣ \pink{x = 18}}}[/tex]
[tex] \: [/tex]
_________
[tex] \text { 3 ] 95 = -4 + 33x }[/tex]
[tex] \rm \: ↣ 95 = -4 + 33x \\ \rm↣ 95 + 4 = 33x \\ \rm↣ 99 = 33x \\ \rm ↣ \cancel \frac{99}{33} = x \\ \rm ↣3 = x \\ \underline{ \underline{\rm \color{hotpink}↣x = 3}}[/tex]
[tex] \: [/tex]
━━━━━━━━━━━━━━━━━━━━━━━
hope it helps:)
Choose ALL correct answers.
Which of the following tables are non-linear?
Can someone please help me
100 POINTS HELP PLEASE IM DESPERATE !!!!!!!!!!!!!!!!!!!!
If AB¯¯¯¯¯¯¯¯
is translated right 5
units and down 2
units, what are the coordinates of A′,
the image of point A?
Line Segment A B with coordinates A negative 5, 2 & B negative 2, 6.
Calculate the volume of a cone with a height of 6 inches and a diameter of 6 inches.
Leave your answer in terms of PI
Answer: Volume ≈ 56.55
Step-by-step explanation:
56.54867 is the answer, but I rounded it. I hope this helped! :)
Answer:
18π cubic inches
Step-by-step explanation:
First, we need to find the radius of the cone, which is half of the diameter.
radius = diameter/2 = 6/2 = 3 inches
The formula for the volume of a cone is:
V = 1/3 × π × r^2 × h
where r is the radius of the base of the cone, and h is the height of the cone.
Substituting the values we get:
V = 1/3 × π × 3^2 × 6
V = 1/3 × π × 9 × 6
V = π × 18