suppose you have 4 pairs of socks and 4 pairs of shoes. if you can wear any combination of socks and shoes, including mismatched pairs, how many different possible footwear choices can you make

The most conservative cutover method when converting to a new system is the Phased Cutover.

This method allows for the implementation of the new system in multiple stages, thereby reducing risk. First, the new system is installed and tested. Next, a small portion of data is moved to the new system.

After data is moved, the new system is tested again. This process is repeated until all data has been moved and tested, and the new system is running smoothly.

Once the new system is running successfully, the old system is discontinued.

The phased cutover method ensures that the new system is functioning correctly, and gives time for system users to get used to the new system, before the old system is turned off.

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Answer:

£320 000

Step-by-step explanation:

Let x = original price of the boat.

When you reduce a price by 15%, what percent remains in the sale price?

100% - 15% = 85%

After reducing the price of the boat by 15%, the sale price is 85% of the original price.

85% of x = £272 000

0.85x = 272 000

Divide both sides by 0.85

x = 320 000

Answer: £320 000

We can expect approximately 90 mosquitoes in the trap at the end of the 13-week mosquito season.

Based on the given data, we can observe that the number of mosquitoes is increasing over time, and the increase is not constant. So, it would be unreasonable to continue counting individual mosquitoes after a certain point.

To estimate the number of mosquitoes at the end of the 13-week mosquito season, we can assume that the rate of increase remains constant over time. Using this assumption, we can find the average increase in mosquitoes per week, which is the difference between the number of mosquitoes in the last week and the number in the first week, divided by the number of weeks:

Average increase = (27 - 8) / 3 = 6.33

Then, we can use this average increase to estimate the number of mosquitoes in the 13th week:

Number of mosquitoes in the 13th week = 27 + 6.33 × 10 = 90.3

Since we cannot have a fraction of a mosquito, we can round this estimate to the nearest whole number.

Therefore, we can expect approximately 90 mosquitoes in the trap at the end of the 13-week mosquito season.

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The expression 3x³y² - 9xz⁴ + 8y²z have no GCF greatest common factor but the terms 3x³y² and 8y²z have GCF equal to y².

The GCF defines the highest common factor present in between given two or more numbers or algebraic expressions.

we shall determine the GCF greatest common factor for the algebraic expression 3x³y² and 8y²z as follows:

3x³y² = y² × 3x³

8y²z = y² × 8z

both terms 3x³y² and 8y²z have y² common to them, so we can write;

3x³y² + 8y²z = y² × 3x³ + y² × 8z

3x³y² + 8y²z = y²(3x³ + 8z)

In conclusion, the expression 3x³y² - 9xz⁴ + 8y²z have no GCF greatest common factor but the terms 3x³y² and 8y²z have GCF equal to y².

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the range of the function is at least $400 plus $50 for each month after the purchase. The average monthly cost of owning the cell phone can be represented as:

C(t) = 400 + 50t

Where t is the number of months after the purchase.

Since C(t) is a linear function, its range is all real numbers greater than or equal to 400, since the initial cost of the phone is 400 and the monthly cost is a positive constant. Therefore, the range of C(t) is:

Range of C(t) = {C(t) | C(t) ≥ 400} or [400, ∞)

In other words, the range of the function is all possible average monthly costs of owning the phone, which is at least $400 plus $50 for each month after the purchase.

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Using trigonometric relations we can see that u = 4.28m

First we can find the length of the shared side using the trigonometric relation:

tan(56°) = x/1.65m

1.65m*tan(56°) = x

2.45m = x

Then the length of the bottom side of the right triangle in the right side is iven by:

tan(43°) = 2.45m/y

Solving for y:

y =  2.45m/tan(43°)

y = 2.63m

Then the length of u is:

u = 1.65m + 2.63m = 4.28m

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the number of more 4's printed than 8's is 188 - 59 = 129.

We can approach this problem by counting the number of times the digit 4 appears and the number of times the digit 8 appears in the page numbers from 1 to 488.

First, let's count the number of times the digit 4 appears. We can break down the counting into three cases:

The digit 4 appears in the units place (page numbers 4, 14, 24, ..., 484): there are 49 such page numbers (from 4 to 484, incrementing by 10).

The digit 4 appears in the tens place (page numbers 40 to 49, 140 to 149, ..., 440 to 449): there are 50 such page numbers.

The digit 4 appears in the hundreds place (page numbers 400 to 488): there are 89 such page numbers.

Thus, the total number of times the digit 4 appears is 49 + 50 + 89 = 188.

Next, let's count the number of times the digit 8 appears. We can break down the counting into two cases:

The digit 8 appears in the tens place (page numbers 80 to 89, 180 to 189, ..., 480 to 489): there are 50 such page numbers.

The digit 8 appears in the hundreds place (page numbers 800 to 880): there are 9 such page numbers.

Thus, the total number of times the digit 8 appears is 50 + 9 = 59.

Therefore, the number of more 4's printed than 8's is 188 - 59 = 129.

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The need for capital by the Sport Bat Corporation will spread through the financial system as it interacts with banks, investors, and the broader financial markets.

When the Sport Bat Corporation needs to borrow $2 million to upgrade their equipment, they will likely seek a loan from a financial institution, such as a bank. The bank will evaluate the creditworthiness of the company and may require collateral or a personal guarantee before approving the loan.

Once the loan is approved, the bank will add the Sport Bat Corporation's loan to their portfolio of assets. The bank may choose to sell the loan to other investors, such as insurance companies or pension funds, to diversify their portfolio and manage risk.

These investors will then receive the interest payments on the loan as a source of income. The loan may be bundled together with other loans and sold as a package, called a securitization, to other investors in the financial markets, thus representing the spread of the loan throughout the financial system.

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Answer:

(x+6)(x+6)

[tex]x^2+12x+36[/tex]

(x+8)(x-5)

[tex]x^{2}+3x-40\\[/tex]

(x-5)(x-2)

[tex]x^{2}-7x+10[/tex]

Step-by-step explanation:

Brainliest pls hope it helped^^

Answer:

a) x^(2)+12x+36

b) x^(2)+3x-40

c) x^(2)-7x+10

Step-by-step explanation:

The percent that reported mushroom as their favorite from the pizza shop survey would be 10 %.

The percent that instead reported cheese or pepperoni as their favorite is 62.5 %.

Out of 400 people, the number that would say their favorite was sausage is 50 people .

The percent that prefer mushroom would be:

= Number of those who chose mushroom / Number surveyed

= 8 ( 35 + 8 + 15 + 12 + 10 )

= 8 / 80

= 10 %

The percentage that instead chose cheese or pepperoni:

= ( 15 + 35 ) / ( 35 + 8 + 15 + 12 + 10 )

= 50 / 80

= 62.5 %

The number out of 400 that would be expected to choose sausage :

= 10 / ( 35 + 8 + 15 + 12 + 10 ) x 400

= 50 people

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Scale Factor is equal to [tex]\frac{2}{3}[/tex]. Length of EH is equal to 16 units and length of AB is equal to 9.

4. A scale factor is the ratio of the scales of an original object and a new object.

Scale factor = Ordinated dimension / original dimension

Scale factor = [tex]\frac{10}{15}[/tex]

Scale factor = [tex]\frac{2}{3}[/tex]  (or) 0.67

5. Length of EH

Scale factor = [tex]\frac{EH}{AD}[/tex]

[tex]\frac{EH}{AD}[/tex] = [tex]\frac{2}{3}[/tex]

[tex]\frac{EH}{24} = \frac{2}{3}[/tex]

EH = 2 * 8

EH = 16 units

6. Length of AB

Scale factor = [tex]\frac{EF}{AB}[/tex]

[tex]\frac{EF}{AB}[/tex] = [tex]\frac{2}{3}[/tex]

[tex]\frac{6}{AB} = \frac{2}{3}[/tex]

AB = 3 * 3

AB = 9 units.

Therefore, Scale Factor is equal to [tex]\frac{2}{3}[/tex]. Length of EH is equal to 16 units and length of AB is equal to 9.

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The analysis of the data to obtain the best fit line equations that model the data, indicates;

5. a. Quadratic

b. y = -0.1179·x² + 2.1124·x + 4.215

c. Please find the completed chart showing the predicted values and the  in the residuals in the following section.

6. a. A linear model may not be appropriate for the data in the residual plot

b. 4

c. 5

4. a. The exponential model of the function is; y = 100·e^(-0.124·t)

b. The weight after 8 weeks is about 37.1 grams

c. The sample will be 4 grams in about 26 weeks

5. a. The equation is; y = 22.703·x + 2.5733

b. The predicted y-value at x = 10 is; y = 229.60

c. The first time is about x ≈ 3.54

The best fit line is a line that is drawn through a set of data points in such a way that it minimizes the sum of squared errors of the data.

5. The best fit model can be obtained by plotting a scatter plot of the graph, which indicates that the best fit line resembles the shape of a parabola.

Therefore;

a. The best fit equation is; Quadratic

b. The best fit equation, obtained using technology is; y = -0.1179·x² + 2.1124·x + 4.215

The square of the correlation coefficient is; R² = 0.9584

The chart can be filled with the best fit equation as follows;

[tex]\begin{tabular}{ | c | c | c | c | c | }\cline{1-4}Distance (foot) & Height (foot) & Predicted Value &Residual \\ \cline{1-4}0 & 4 & 4.215 & -0.215 \\\cline{1-4}2 & 8.4 & 8.16588 & 0.23412 \\\cline{1-4}6 & 12.1 & 13.23804 & -1.13804 \\\cline{1-4}9 & 14.2 & 14.56626 & -0.36626\\\cline{1-4}12 & 13.2 & 13.77228 & -0.57228 \\\cline{1-4}13 & 10.5 & 13.03602 & -2.53602 \\\cline{1-4}15 & 9.8 & 10.8561 & -1.0561 \\\cline{1-4}\end{tabular}[/tex]

The predicted value are obtained by plugging in the x-value into the best fit equation and the residuals is the difference between the actual value and the predicted value.

6. a. A residual plot can be used to as assessment with regards to meeting the assumptions of a linear regression model.

A residual plot that is randomly scattered about zero indicates that a linear model is appropriate for the data.

The data points in the residual plot are not expressed as being randomly scattered around zero.

The pattern that exists in the residual plot indicates that the values are positive for x-values that are either low or high, and the middle x-values have a negative residuals. Therefr;

b. The number of positive residuals = 4

c. The number of negative residuals = 5

4. The general form of the exponential model of a function, y = A × e^(-k·t)  can be used to find the function for the data as follows;

A = The initial amount = The value at 0 = 100

y = The amount of radioactive material at a given time t

e = Euler's number = 2.71828

The datapoints in the table indicates;

88.3 = 100 × e^(-k × 1)

k = -㏑(0.883) ≈ 0.124

The exponential model is therefore; y = 100 × e^(-0.124·t)

b. The weight of the sample after 8 weeks can be obtained by plugging in t = 8 in the exponential function for the weight of the radioactive substance as follows;

y = 100 × e^(-0.124 × 8) ≈ 37.1

The weight of the sample after 8 weeks is about 37.1 grams

c. When the sample is 4 grams we get;

y = 4

4 = 100 × e^(-0.124 × t)

e^(-0.124 × t)  = 4/100 = 1/25

-0.124 × t = ln(1/25) = -ln(25)

t = ln(25)/0.124 ≈ 26

t ≈ 26 weeks

Therefore; The weight will be 4 grams after approximately 26 weeks

5. A linear regression can be performed using MS Excel to obtain the equation that models the data as follows;

y = 22.703·x + 2.5733

The square of the regression coefficient is; R² = 0.9995

a. The most appropriate equation to model the data in the table is; y = 22.703·x + 2.5733

b. The y-value when x = 10 can be predicted by plugging in x = 10 into the  model equation for the data as follows;

y = 22.703 * 10 + 2.5733 ≈ 229.60

Therefore;

c. The first time the y-value is 83, can be found by setting y = 83 in the equation and solve for x as follows;

83 = 22.703·x + 2.5733

22.703·x = (83 - 2.5733)

x = (83 - 2.5733)/22.703 ≈ 3.54

Therefore, the first time the y-value is 83 is when x is approximately 3.54

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Diego can make 56 bags with each bag containing 8 brownies and 12 cookies.

To package both items, he can divide the items into groups of 8 brownies and 12 cookies. He will then make 56 of these groups, ensuring each bag contains 8 brownies and 12 cookies.

Diego has 48 brownies and 64 cookies to package. To make the same combination of items in each bag, he needs to group the items into groups of 8 brownies and 12 cookies.

This can be done by dividing the 48 brownies into 6 groups of 8, and the 64 cookies into 5 groups of 12. He then needs to combine these two groups together, making 56 total bags.

Each of these bags will contain 8 brownies and 12 cookies. This is one way of packaging both items so that each bag has the same combination.

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Yes, the value of 0.75 to 0.83 for a 95% confidence interval is plausible.

A confidence interval is a range of values that has a 95% chance of containing the true population parameter, which in this case is the population proportion (p).

A 95% confidence interval has a margin of error of 5%. Thus, a range of 0.75 to 0.83 has a 95% chance of containing the true population proportion p.

The 95% confidence interval is an estimated range of values which is calculated from sample data, with a 95% chance of containing the true population parameter, p. To calculate the confidence interval, the confidence level and the margin of error must be known.

The confidence level is the probability that the confidence interval will contain the true population parameter, and the margin of error is the amount that the sample statistic can differ from the true population parameter.

A 95% confidence level has a margin of error of 5%, meaning that the sample statistic can be up to 5% away from the true population parameter.

In this case, the 95% confidence interval for the population proportion is 0.75 to 0.83. This means that the range of 0.75 to 0.83 has a 95% chance of containing the true population proportion p, and is thus a plausible value for the population proportion.

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The two numbers that multiply to give 24 and add to give -11 are -3 and -8.

To find these numbers, you can use a system of equations. Let x and y be the two numbers. Then we have:

We can use the second equation to solve for one of the variables in terms of the other. For example, we can solve for x:

x + y = -11

x = -11 - y

We can then substitute this expression for x into the first equation:

xy = 24

(-11 - y)y = 24

Expanding and rearranging, we get:

y^2 + 11y + 24 = 0

This is a quadratic equation that we can solve using factoring or the quadratic formula. Factoring, we get:

(y + 3)(y + 8) = 0

So either y + 3 = 0 or y + 8 = 0. This means that y can be -3 or -8. Substituting each of these values into x = -11 - y, we get:

If y is -3, then x is -11 - (-3) = -8

If y is -8, then x is -11 - (-8) = -3.

Translated question "Numbers that multiply to give me 24 and add to give me -11"

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The number of  pounds that he will have left over from 11 3/7 pounds is  4 2/7

To find out how many bags of granola Alex can fill, we need to divide the total amount of granola he made by the amount of granola in each bag.

We can convert 11 3/7 pounds to an improper fraction:

11 3/7 pounds  = 80/7 pounds

Also, we have

2 2/3 pounds  = 8/3 pounds

Now we can divide the total amount of granola by the amount in each bag:

(80/7) ÷ (8/3)

To divide fractions, we invert the second fraction (change it to its reciprocal) and multiply:

(80/7) × (3/8)

Simplifying, we get:

(80 x 3) / (7 x 8) = 30/7

Divide

(80 x 3) / (7 x 8) = 4 2/7

Hence, the bags is 4 2/7

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As per the given statement, the quadratic equation is to be used to find the exact solutions to this equation, and the quadratic equation is given by [tex]ax² + bx + c = 0[/tex].

To solve the quadratic equation, we can use the quadratic formula given by[tex]x = (-b ± sqrt(b² - 4ac)) / 2a[/tex] Where x is the variable, a, b, and c are coefficients with a ≠ 0, and sqrt is the square root symbol.To find the exact solutions to this equation, we can use the quadratic formula with a = 2, b = 6, and c = 12.

Substituting these values in the quadratic formula, we get

[tex]x = (-6 ± sqrt(6² - 4 × 2 × 12)) / 2 × 2= (-6 ± sqrt(36 - 96)) / 4= (-6 ± sqrt(-60)) / 4= (-6 ± i√60) / 4= (-3 ± i√15) / 2[/tex]

Hence, the exact solutions to the given equation are [tex](-3 + i√15) / 2 and (-3 - i√15) / 2.[/tex]

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The aquarium tank that holds 190 liters of water equals to 50.15 gallons. Therefore, the answer to the given problem is 50.15 gallons.

Conversion factors are the ratios that describe the numerical relationship between two units of measurement.

The conversion factor of liters to gallons is 1 gallon is 3.8 liters.

Therefore, by multiplying the given value of liters by the conversion factor of liters to gallons, we can convert liters to gallons.

190 liters x 1 gallon/3.8 liters = 50.15 gallons

Thus, the aquarium tank that holds 190 liters of water equals to 50.15 gallons.

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A large bag contains marbles of different colors. there are 10 red marbles, 5 blue marbles and 7 yellow marbles. when selecting 3 marbles without replacement, the probability of selecting 3 red marbles is 1/54.

The probability of selecting 3 red marbles is 1/54.What is a probability?

Probability refers to the likelihood or chance of an occurrence. The probability of an event occurring is the ratio of the number of favourable outcomes to the total number of possible outcomes.

A fraction or a decimal is used to express it.The total number of marbles in the bag is 10 + 5 + 7 = 22 marbles.

There are ten red marbles in the large bag, so the number of ways to select 3 red marbles from ten red marbles is:

[tex]10C_3 = (10 \times 9 \times 8) / (3 \times 2 \times 1) = 120[/tex]

There are 22 marbles in the bag, therefore, the total number of ways to pick 3 marbles from 22 is:

[tex]22C_3 = (22 \times 21 \times 20) / (3 \times 2 \times 1) = 1540[/tex]

Hence, the probability of choosing 3 red marbles out of the 22 marbles in the bag without replacement is:120/1540 = 1/54

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Therefore, the distance between the two points is simply the difference in their x-coordinates, this makes sense since both points lie on the same horizontal line, and so the vertical distance between them is zero.

Distance is a numerical measurement of how far apart two objects or points are from each other. It is a scalar quantity that is usually expressed in units of length, such as meters, kilometers, miles, or feet. Distance is often used in physics, mathematics, and engineering to describe the spatial separation between two objects or points. It is also used in everyday language to describe how far away something is, such as the distance between two cities or the distance from a person's house to their workplace.

By the question.

The distance between two points on a coordinate plane can be found using the distance formula:

distance =[tex]\sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-x_{1}^{2} ) }[/tex]

In this case, the two points are (0, b) and (a, b). We can substitute these values into the distance formula:

distance = [tex]\sqrt{(a-0)^{2}+(b-b)^{2} }[/tex]

distance = [tex]\sqrt{a^{2}+0 }[/tex]

distance = a

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Step-by-step explanation:

The side opposite to the 4 degree angle is 18 m

The side adjacent the 4 degree angle is x

tan(4) = opposite / adjacent

adjacent = opposite / (tan(4))

adjacent = 18 / tan(4)

adjacent = 257.41

Tyee can afford to rent the car for at most 2 days while staying within his budget.

Let x be the number of days Tyee can rent the car within his budget.

The total cost of renting the car will be the sum of the daily rental fee and the cost of miles driven:

Total cost = rental fee + (cost per mile x miles driven)

Using the given information, we can write the inequality:

74.90x + 0.13(175)x ≤ 210

Simplifying the expression, we get:

74.90x + 22.75x ≤ 210

97.65x ≤ 210

x ≤ 2.15

Therefore, Tyee can afford to rent the car for at most 2 days while staying within his budget.

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The dimensions that will produce the maximum enclosed area for two adjacent rectangular safe play areas of equal size with 200 feet of fencing is 100 feet by 100 feet.

To solve this problem, use the area of a rectangle formula A = lw, where l is the length and w is the width.

Since the two play areas must be of equal size, let's call the length and width l and w, respectively.

We know that the total length of fencing is 200 feet, so l + w = 200 feet.

We can then solve for l by rearranging the equation as l = 200 - w.

We then substitute this into the area equation to get A = (200 - w)w.

To maximize the area, differentiate this equation to get A' = w - 200.

Set this to 0 and solve for w to get w = 100. Since l + w = 200, l = 100 as well.

Therefore, the maximum enclosed area is produced by dimensions of l = 100 feet and w = 100 feet.

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Since the sequence is always decreasing and cannot go below the lower bound, it becomes increasingly closer to the lower bound, and thus converges to a limit.

A sequence is said to be decreasing if each term is smaller than the previous one, and bounded below if there exists a lower bound such that no term in the sequence is smaller than this bound. In this case, the sequence is decreasing and bounded below by 0.

When a sequence is both decreasing and bounded below, it must have a limit because the terms cannot continue to decrease indefinitely, as they cannot go below the lower bound (in this case, 0). This means that as we progress through the terms of the sequence, the difference between consecutive terms will decrease and eventually approach a constant value.

The limit of a sequence is a value that the terms of the sequence approach as they get closer and closer to the end. In this situation, the limit is the smallest possible value that the sequence can approach, without going below the lower bound.

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The lower quartile of the given set of numbers 4, 6, 7, 8, 10, 12, 20 is 6. So, correct option is B.

To find the lower quartile of a set of numbers, we first need to arrange them in ascending order. The given numbers are: 4, 6, 7, 8, 10, 12, 20.

Next, we divide the data set into four equal parts. The lower quartile is the median of the lower half of the data set. In this case, the lower half is 4, 6, and 7.

To determine the median of the lower half, we need to find the middle value. Since we have an odd number of data points in the lower half, the middle value is the single value between the two extremes. In this case, the median is 6.

This corresponds to option (b) in the given choices: 6.

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The total amount of money shared between Rui Feng and Vishal is 154 dollars.

Let's assume that the amount of money shared between Rui Feng and Vishal is x dollars.

According to the given ratio, the amount of money received by Rui Feng is 5/14 of the total amount, and the amount received by Vishal is 9/14 of the total amount.

We are also given that Rui Feng receives 44 dollars less than Vishal. We can express this as:

9/14 x - 5/14 x = 44

Simplifying the equation, we get:

4/14 x = 44

Multiplying both sides by 14/4, we get:

x = 154

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The outcomes of the statistical analysis can give medical professionals and patients important knowledge regarding the possible advantages of the new procedure.

The study of random events or phenomena is the focus of the mathematical field of probability. It is a way to gauge how likely something is to happen. It is represented by a number between 0 and 1, where 0 denotes the event's impossibility and 1 denotes its certainty. There are numerous ways to calculate probabilities, including utilizing theoretical or mathematical models, empirical data, and experimental data.

given

A statistical analysis would be useful to evaluate the effectiveness of the novel technique to the standard procedure based on the study's design.

The recovery periods of the two patient groups might be compared using statistical techniques like hypothesis testing and confidence intervals to assess the efficacy of the new therapy.

Researchers can establish whether the new approach is statistically significantly superior than the usual procedure in terms of minimizing recovery time by comparing the recovery times of the two groups.

The outcomes of the statistical analysis can give medical professionals and patients important knowledge regarding the possible advantages of the new procedure.

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If the square of Ethan's age is added to Jordan's age, the result is [tex]56[/tex], which equals Ethan's age. The answer is that Ethan is [tex]6[/tex] years old.

A person's birth date is compared to the day on which their age has to be computed as part of the age calculation process. The age of the individual is calculated by subtracting the person's age from the given date. Provided Date - Birthdate is used to compute age.

A person's age is merely a measurement of how long they have been living. These metrics don't adequately describe who you are or what you have accomplished. At any age, either old or young, one may do anything.

The solution states that [tex]56[/tex] is equal to [tex]4[/tex] times Jordan's age multiplied by the square of Ethan's age. This may be expressed as an equation:

[tex]x^2 + 4(x-1) = 56[/tex]

Simplifying the equation:

[tex]x^2 + 4x - 4 = 56[/tex]

[tex]x^2 + 4x - 60 = 0[/tex]

We can solve this quadratic equation by factoring:

(x+10)(x-6) = 0

Therefore, [tex]x = -10[/tex] or [tex]x = 6[/tex]. We can discard the negative value since age cannot be negative, so Ethan's age is [tex]6[/tex].

To check, we can substitute x=6 into the original equation:

[tex]6^2 + 4(6-1) = 36 + 20 = 56[/tex]

So the solution is Ethan is [tex]6[/tex] years old.

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There are 100,000 possible five-digit student ID numbers that can be created if repeat digits are allowed (10^5).

However, if repeats are not allowed, there are only 9 x 9 x 9 x 9 x 9 = 590,490 possible student ID numbers that can be created (9^5).

The reason for the difference is that when repeats are allowed, you can use the same digit multiple times, for example "11111".

When repeats are not allowed, you can only use each digit once, for example "12345". The possible permutations of the digits 0-9 increase as more digits are added to the ID number, meaning that the more digits there are, the more possible combinations there are.

Therefore, when repeats are not allowed, the number of possible combinations is reduced significantly. In the case of five-digit student ID numbers, the difference is almost twofold.

To know more about combinations click on below link:

https://brainly.com/question/20211959#

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Answer:

x = 80

y = 160

Step-by-step explanation:

The sum of all arc measures that make up a circle is 360°. Therefore:

[tex]\implies 200^{\circ} + y^{\circ} = 360^{\circ}[/tex]

[tex]\implies 200^{\circ} + y^{\circ} - 200^{\circ} = 360^{\circ} - 200^{\circ}[/tex]

[tex]\implies y^{\circ} = 160^{\circ}[/tex]

[tex]\implies y=160[/tex]

If a tangent and a chord intersect at a point on a circle, then the measure of each angle formed is one-half the measure of its intercepted arc.

Therefore, according to the Tangent and Intersected Chord Theorem, the measure of angle x is equal to half of the measure of arc y:

[tex]\implies x^{\circ}=\dfrac{1}{2} y^{\circ}[/tex]

[tex]\implies x^{\circ}=\dfrac{1}{2} \cdot 160^{\circ}[/tex]

[tex]\implies x^{\circ}=80^{\circ}[/tex]

[tex]\implies x=80[/tex]

[tex]\hrulefill[/tex]