Let's begin by listing out the information given to us:
To calculate Takashi's distance from his grandmother's house is given by the formula:
[tex]\begin{gathered} distance=speed\cdot time \\ h=v\cdot t \end{gathered}[/tex]Independent variable refers to the variable that stands by itself and whose value is not affected by the other
Dependent variable refers to the variable whose value is affected by the value of another variable
A. The distance (h) does not change irrespective of Takashi's speed, hence it is the independent variable
B. The coefficient is the speed (v)
C. The constant is time (t)
D. The speed (v) changes with variation in time, hence it is the dependent variable
The net of a cone is shown below. What is the surface area of the cone rounded to the nearest tenth of a square inch? Use π = 3.14.A. 125.6 in²B. 1,256.6 in²C. 175.8 in²D. 251.3 in²
ANSWER
[tex](C)175.8in^2[/tex]EXPLANATION
The surface area of a cone can be found using the formula:
[tex]A=\pi r^2+\pi rl[/tex]where l = slant height
r = radius
The diameter of the cone is given, but we can find the radius since the radius is half the diameter:
[tex]\begin{gathered} r=\frac{D}{2} \\ r=\frac{8}{2} \\ r=4\text{ units} \end{gathered}[/tex]From the figure, the slant height of the cone is 10 units.
Hence, its surface area is:
[tex]\begin{gathered} A=(\pi\cdot4^2)+(\pi\cdot4\cdot10) \\ A=50.24+125.6 \\ A\approx175.8in^2 \end{gathered}[/tex]The answer is option C.
Graph the solution set of the system. -2x-y ≥2 y ≥-2 x ≥-4
The graph of the given equations as;
-2x-y ≥2
The graph of the inequality y ≥-2
The graph of the inequality, x ≥-4
Now, the graph for the set of the system as;
...
Use the figure below to find lateral surface area. Select one: O 92 square inches O 80 square inches O 60 square inches O 86 square inches
Area of the base = 10 x 3 = 30 in^2
Area of the lateral walls = 10 x 2.5 x 2 = 50 in^2
Area of the triangles = 3 x 2 /2 x 2 = 6 in^2
Total area = 30 + 50 + 6
= 86 in^2
The expression below is scientificnotation for what number?4.58x10^-2
Using the exponent rules, 10^-2 can be expressed as follows:
[tex]10^{-2}=\frac{1}{10^2}=\frac{1}{100}[/tex]Substituting into the expression in scientific notation, we get:
[tex]4.58\cdot10^{-2}=4.58\cdot\frac{1}{100}=\frac{4.58}{100}=0.0458[/tex]In how many different ways can a relation be represented?Give an example of each
It is to be noted that a relations in math can be represented in 8 different ways. See the examples below.
What are relations in Math?The relation in mathematics is the relationship between two or more sets of values.
The various types of relations and their examples are:
Empty Relation
An empty relation (or void relation) is one in which no set items are related to one another. For instance, if A = 1, 2, 3, one of the empty relations might be R = x, y, where |x - y| = 8. For an empty relationship,
R = φ ⊂ A × A
Universal Relation
A universal (or complete) relation is one in which every member of a set is connected to one another. Consider the set A = a, b, c. R = x, y will now be one of the universal relations, where |x - y| = 0. In terms of universality,
R = A × A
Identity Relation
Every element of a set is solely related to itself via an identity relation. In a set A = a, b, c, for example, the identity relation will be I = a, a, b, b, c, c. In terms of identity, I = {(a, a), a ∈ A}
Inverse Relation
When one set includes items that are inverse pairings of another set, there is an inverse connection. For example, if A = (a, b), (c, d), then the inverse relation is R-1 = (b, a), (d, c). As a result, given an inverse relationship,
R-1 = {(b, a): (a, b) ∈ R}
Reflexive Relation
Every element in a reflexive relationship maps to itself. Consider the set A = 1, 2, for example. R = (1, 1), (2, 2), (1, 2), (2, 1) is an example of a reflexive connection. The reflexive relationship is defined as- (a, a) ∈ R
Symmetric Relation
If a=b is true, then b=a is also true in a symmetric relationship. In other words, a relation R is symmetric if and only if (b, a) R holds when (a,b) R. R = (1, 2), (2, 1) for a set A = 1, 2 is an example of a symmetric relation. As a result, with a symmetric relationship, aRb ⇒ bRa, ∀ a, b ∈ A.
Transitive Relation
For transitive relation, if (x, y) ∈ R, (y, z) ∈ R, then (x, z) ∈ R. For a transitive relation, aRb and bRc ⇒ aRc ∀ a, b, c ∈ A
Equivalence Relation
If a relation is reflexive, symmetric and transitive at the same time, it is known as an equivalence relation.
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It is found that a relations in math can be represented in 8 different ways.
What are relations?The relation in mathematics is defined as the relationship between two or more sets of values.
There various types of relations and their examples:
An empty relation (or void relation) is one in which no set items are related to one another. if A = 1, 2, 3, one of the empty relations might be R = x, y, where |x - y| = 8.
R = φ ⊂ A × A
Universal Relation; It is one in which every member of a set is connected to one another.
R = A × A
Identity Relation; Every element of a set is solely related to itself via an identity .
In a set A = a, b, c, for example, it is I = a, a, b, b, c, c. I
n terms of identity, I = {(a, a), a ∈ A}
Inverse Relation; When one set of data includes items that are inverse pairings of another set, there is an inverse connection.
For example, if A = (a, b), (c, d), then the inverse is; R-1 = (b, a), (d, c).
R-1 = {(b, a): (a, b) ∈ R}
Equivalence Relation; When a relation is reflexive, symmetric and transitive at the same time, it is calles as an equivalence relation.
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Sioux Falls Christian teacher says that he can drop one of his test score using history to score of 80 185 which one should he drop and white what is his new address
if he removes his lowest score the average increases, then if we remove 80 the new average is
[tex]\frac{100+85}{2}=92.5[/tex]new average is 92.5
^3square root of 1000
Given the following question:
[tex]\sqrt[3]{1000}[/tex][tex]\begin{gathered} \sqrt[3]{1000} \\ \sqrt[3]{1000}=\sqrt[3]{10^3} \\ 10^3=1000 \\ \sqrt[3]{10^3} \\ \sqrt[n]{a^n}=a \\ \sqrt[3]{10^3}=10 \\ =10 \end{gathered}[/tex]Your answer is 10.
You have a bag full of 4 green marbles and 1 blue marble. You pick a marble out at random. If it's blue, you stopbecause you win 20 points. If not, you get another chance. Without replacing the green marble, you pick again. It'sblue, you win 10 points, otherwise you lose 20 points. Let X be the number of points you eam in this game. If you playedthis game 100 times, how many points can you expect to win (or lose)?
As per given by the question,
There are given that, 4 green marbles and 1 blue marble contains in a box and pick a marble at randomly.
Now,
Here pick a marble out at random, so first pick a marble for blue;
Then,
Total number of green marbles is 4, and the total number of blue marble is 1, and;
The total numbers of marbles in a bag is, 4+1=5.
So,
For pick the blue marble from 5 marble,
Now,
[tex]\begin{gathered} 5_{C_1}=\frac{5!}{1!\times(5-1)!} \\ =\frac{5!}{1!\times4!} \\ =\frac{5\times4!}{1!\times4!} \\ =5 \end{gathered}[/tex]Now, for pick the green marble from 5 marbles.
Here, total green marble is 4.
So,
[tex]\begin{gathered} 5_{C_4}=\frac{5!}{4!\times(5-4)!} \\ =\frac{5\times4!}{4!\times1!} \\ =5 \end{gathered}[/tex]Now,
From the question, there are clearly mention that if pick a blue, then stop because you won 20 points.
So,
Probability of the blue marble that won the 20 points.
then,
[tex]\begin{gathered} P(x=20)=\frac{total\text{ number of blue marble}}{\text{total number of marble}} \\ P(x=20)=\frac{1}{5} \end{gathered}[/tex]Now,
There are also mention that, pick a green marbles without replacing and if its blue then win the 10 points,
So,
probability of the blue marbles that won 10 pointss is,
[tex]P(x=10)=\frac{1}{4}[/tex]Now,
Here, find the probability that no points for the first green ball is,
[tex]P(x=0)=\frac{4}{5}[/tex]Now,
If you played this game 100 time, then the probability is,
[tex]\begin{gathered} P(x=0)+_{}P(x=10)+P(x=20)=\frac{4}{5}+\frac{1}{4}+\frac{1}{5} \\ =1.25 \end{gathered}[/tex]now,
For 100 times,
[tex]1.25\times100=125\text{ points.}[/tex]Hence, 125 points can you expect to win.
In a game of cornhole, Sasha tossed a bean bag and it landed at the edge of the hole. The hole can be represented by the equation x^2+ y^2= 5, and the path of the bean bag canbe represented by y = -0.5x^2 -1.5x + 4. To which points could she have tossed her bean bag?(-1,-2) or (-2, 1)(1.-2) or (2,1)(-1,2) or (-2,-1)(1, 2) or (2, -1)
We have two equations, the first is a circle, which we can identify by the characteristic form of the equation:
[tex]x^2+y^2=5[/tex]The second is a quadratic equation:
[tex]y=-0.5x^2-1.5x+4[/tex]We know that Sasha got the bag to land in the edge of the circle defined by the hole, equation 1.
So, to know the points at which the bag landed, we can look for th eintersection of the two equations, which is the same as solving a system of equations:
[tex]\begin{gathered} x^2+y^2=5 \\ y=-0.5x^2-1.5x+4 \end{gathered}[/tex]Since we have been given alternatives, we can check them to get the correct answer.
The first option is (-1,-2) or (-2,1). Since the sign of the alternatives are the only thing that change and the circle equation doesn't differenciate the signs, the best equation to test first is the second one. Let's try that for (-1,-2).
[tex]\begin{gathered} y=-0.5(-1)^2-1.5(-1)+4 \\ y=-0.5+1.5+4=5 \end{gathered}[/tex]We got y = 5, which is not -2, so this alternative is incorrect.
Let's got for the second alternative, (1.-2) or (2,1):
[tex]y=-0.5(1)^2-1.5\cdot1+4=2[/tex]This is also incorrect.
The third alternative is (-1,2) or (-2,-1), we already saw that for x = -1, y = 5, which makes this alternative also incorrect.
Let's check if the last one will be correct, (1, 2) or (2, -1). We already saw that for x = 1, y = 2 in the second equation, let's check if this is also correct for the first:
[tex]\begin{gathered} (1)^2+y^2=5 \\ y^2=5-1=4 \\ y=\pm2 \end{gathered}[/tex]One of the results is y = 2, so this also checks out.
The other point is (2,-1), let's check in both equations:
[tex]\begin{gathered} (2)^2+y^2=5 \\ 4+y^2=5 \\ y^2=1 \\ y=\pm1 \end{gathered}[/tex]Checks out, and:
[tex]\begin{gathered} y=-0.5(2)^2-1.5\cdot2+4 \\ y=-2-3+4=-1 \end{gathered}[/tex]And the "y" checks out too.
So, the correct alternative is the last one: (1, 2) or (2, -1).
Hi, I am testing the service for Brainly. Can you help me find the median for this set of numbers: 3, 4, 15, 27, 53, 54, 68, 77?
To find the median of a set of numbers, the first step is:
1 - Put the numbers in crescent order
This set of numbers is already in crescent order, so we can skip this step
2 - Count how many numbers there are in the set.
In our set we have 8 numbers, so in this case, the median of the set will be the average value between the two central numbers (that is, the fourth and fifth numbers)
The fourth number is 27, and the fifth number is 53, so the median is the average of these two numbers:
[tex]\text{median = }\frac{(27\text{ + 53)}}{2}=\frac{80}{2}=40[/tex]So the median of this set of numbers is 40.
A restaurant serving 150 side dishes of skinless mashed potatoes each day produces two orders of mashed potatoes from each 8 ounce potato. when the skins are discarded, the potatoes have a yield percentage of 90%. However, to reduce waste and promote sales, the potato skins are instead used as an appetizer. what is the edible portion of the potato skins in ounces?
The edible portion of the potato skins in ounces is = 0.8%
What are potatoes?Potatoes are vegetable tubers that can be eaten with the skin when properly cooked.
The number of side dishes of skinless mashed potatoes= 150
Two orders of mashed potatoes = 8 ounce potato.
The potatoes with discarded skin = 90% yield
The potatoe skin= 10% of the 8 ounces
That is;
= 10/100×8
= 80/100 = 0.8 ounce
Therefore, the portion of the potatoes that consists of the skin in ounce is = 0.8 ounce
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Triangle
A
B
C
was dilated with the origin as the center of dilation to create triangle ′′′
A
′
B
′
C
′
. The triangle was dilated using a scale factor of 14
1
4
.
The lengths of the sides of triangle
A
B
C
are given.
Enter the lengths of the sides of triangle ′′′
A
′
B
′
C
′
below.
(Decimal values may be used.)
The lengths of the sides of the Triangle A'B'C' is A'B'=2.25 units , B'C' = 2.75 units , C'A' = 1.25 units .
in the question ;
it is given that
the lengths of the sides of the Triangle ABC is
AB = 9 units
BC = 11 units
CA = 5 units
dilation scale = 1/4
the lengths of the dilated triangle can be found using the formula
(Side length)×(Dilation scale)=Dilated length
So,
A'B' = AB*(1/4)
= 9/4 = 2.25 units
B'C' = BC*(1/4)
= 11/4
= 2.75 units
C'A' = CA*(1/4)
= 5/4
= 1.25 units .
Therefore , the lengths of the sides of the Triangle A'B'C' is A'B'=2.25 units , B'C' = 2.75 units , C'A' = 1.25 units .
The given question is incomplete , the complete question is
Triangle ABC was dilated with the origin as the center of dilation to create triangle A′B′C′. The triangle was dilated using a scale factor of 1/4. The lengths of the sides of triangle ABC are given. Enter the lengths of the sides of triangle A′B'C′ . (Decimal values may be used.)
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Jamal buys a water heater online for $861. If shipping and handling area additional 11% of the price, how many shipping and handling will Jamal pay?
Variable Systems 2solve the following showings steps neatly and organized.
SOLUTION
perimeter of rectangle = 88cm
let the widht be x
now, according to question
lenght = 3x ( as it is triple of width)
formula of rectangle perimeter
88cm = 2* (length + width)
88cm = 2(3x+x)
88cm = 4x (2 will be transported to left )
88/2 cm = 4x
( 2 become in divide as in right it was in multiply)
44 cm = 4x
x= 44/4
x= 11cm
according to question,
width of rectangle = x = 11 cm
The perimeter of a quarter circle is 3.57 kilometers. What is the quarter circle's radius? Use 3.14 for . kilometers Siubmit explain
Given:
It is given that the perimeter of a quarter circle is 3.57 km.
To find :
The radius of the quarter circle.
Explanation :
The perimeter of the quarter circle is
[tex]P=\frac{2\pi r}{4}\text{ }+2r[/tex]Substitute the value of perimeter in the above formula
[tex]3.57=\frac{\pi r}{2}+2r[/tex][tex]3.57=(\frac{3.14}{2}+1)r[/tex][tex]3.57=2.57r[/tex][tex]r=1.39[/tex]Answer
Hence the radius of a quarter circle is 1.39 km.
3 part golden raisin2 parts cashewhow many parts of golden raisins does jose need to make 30 total cups pf trail mix?a. 14 partsb. 18 partsc. 20 partsd. 25 parts
To get 1 cup of pf trail mix, we need to mix 2 parts of cashew and 3 part of golden raisin. This means that to make one cup of pf trail mis, we are using 5 parts in total (2 cashew+3 golden raisin). Then, this means that out of one cup the exactly amount of golden raisin is 3/5 of the cups we have. So, having this fraction in mind, we only need to multiply the total number of cups to calculate the parts we are using. In this case, we have 30 cups. So if we want to calculate the parts of golde raisin we multiply 30 by the previous fraction. That is
[tex]30\cdot\text{ }\frac{3}{5}\text{ = 6 }\cdot\text{ 3 = 18}[/tex]So to make 30 cups of pf trail mix, jose needs 18 parts.
Find the third side in simplest radical form: 25 24
Here, we want to get the length of the third side
Mathematically, we can get this by the use of Pythagoras' theorem
It states that the square of the length of the hypotenuse equals the sum of the squares of the two other sides
Let the missing side be s
From the diagram, we have the hypotenuse as 25 (the hypotenuse is the longest side and it is the side that faces the right angle
We have this as;
[tex]\begin{gathered} 25^2=s^2+24^2 \\ s^2=25^2-24^2 \\ s^2\text{ = 625-576} \\ s\text{ = }\sqrt[]{49} \\ s\text{ = 7} \end{gathered}[/tex]The court ruled that Lox Auto was liable in the death of an employee.The settlement called for the company to pay the employee's widow $60,000 at theend of each year for 20 years. Find the amount the company must set aside today,assuming 5% compounded annually.
We have to calculate the present value PV of a annuity.
The payment is yearly and it is P=60,000.
The interest rate is 5% (r=0.05), compounded annually (m=1).
The number of periods is n=20 years.
Then, we can use the formula for the present value of a annuity:
[tex]\begin{gathered} PV=P\cdot\frac{1-\frac{1}{(1+r)^n}}{r} \\ PV=60000\cdot\frac{1-\frac{1}{1.05^{20}}}{0.05} \\ PV\approx60000\cdot\frac{1-\frac{1}{2.653}}{0.05} \\ PV\approx60000\cdot\frac{1-0.377}{0.05} \\ PV\approx60000\cdot\frac{0.623}{0.05} \\ PV\approx60000\cdot12.462 \\ PV\approx747720 \end{gathered}[/tex]Answer: the company must set aside $747,720.
Which will hold more cake batter; the rectangular pan or two round pans? The volume of the rectangle pan is 234 in 3rd power. Find the volume of the two round pans and choose your decision. Round your answer to the nearest tenth if necessary.
Solution
Given a rectangular pan and two round pans
The volume, V, of the rectangular pan is 234 in³
A round pan is in the form of a cylinder
To find the volume, V, of the a round pan, the formula is
[tex]V=\pi r^2h[/tex]Where
[tex]\begin{gathered} d=8in \\ r=\frac{d}{2}=\frac{8}{2}=4in \\ r=4in \\ h=2in \end{gathered}[/tex]Substitute the variables into the formula above
[tex]\begin{gathered} V=\pi\left(4\right)^2\left(2\right)=100.53in^3\text{ \lparen two decimal places\rparen} \\ V=100.53in^3\text{ \lparen two decimal places\rparen} \end{gathered}[/tex]Since, there are two round pans, the volume of the two round pans will be
[tex]2\times100.53=201.06in^3[/tex]nce, the volume of the two round pans is 201.06 i³.
Since the volume of the two round pans (201.06in³) is less than the volume of the rectangular pan (234in³), the rectangular pan will hold more.
Hence, the answer is rectangular pan (option a)
the coldest temperature ever recorded on earth is 135.8 Fahrenheit below zero recording in Antarctica on July 21st 1983 the hottest temperature ever recorded on earth is 134 Fahrenheit recorded in Death Valley California on July 10th 1913 what is the difference between those two temperature
Let's begin by listing out the information given to us:
The coldest temperature ever recorded on earth (T1) = -135.8 Fahrenheit
The hottest temperature ever recorded on earth (T2) = 134 Fahrenheit
The difference between the two temperature = Hottest - Coldest temperature
[tex]undefined[/tex]What is the value of the number in the hundredths place?8.471A. 0.4B. 0.7 C 0.07D. 0.04
EXPLANATION
The value of the number in the hundreths place is 0.07
Which is the equivalent of 6 14’ 48’’ written in decimal form Round to the nearest thousandth of a degree A. 6.145 B. 6.367 C. 6.247 D. 6.313
Answer
Step-by-step explanation
First, we need to convert the 48'' into minutes. Using the conversion factor: 1' = 60'', we get:
[tex]\begin{gathered} 48^{\prime}^{\prime}=48^{\prime}^{\prime}\cdot\frac{1^{\prime}}{60^{\prime}^{\prime}} \\ 48^{\prime\prime}=\frac{48}{60}^{\prime} \\ 48^{\prime}^{\prime}=0.8^{\prime} \end{gathered}[/tex]Then, 14 minutes and 48 seconds are equivalent to 14 + 0.8 = 14.8 minutes. To convert this amount of minutes into degrees we need to use the conversion factor 1° = 60', as follows:
[tex]\begin{gathered} 14.8^{\prime}=14.8^{\prime}\cdot\frac{1\degree}{60^{\prime}^{\prime}} \\ 14.8^{\prime}=\frac{14.8}{60}\degree \\ 14.8^{\prime}=0.247\operatorname{\degree} \end{gathered}[/tex]In consequence, 6° 14’ 48’’ is equivalent to 6 + 0.247 = 6.247°
why is 10'15 equal to 10'11? explain ur thinking. ___ 10'4
Exponent rule is the following:
[tex]\frac{x^a}{x^b}=x^{a-b}[/tex][tex]\text{Therefore, if for }\frac{10^{15}}{10^4}\text{ a is 15 and b is 4, therefore:}[/tex][tex]\frac{10^{15}}{10^4}=10^{15-4}[/tex][tex]So,\text{ }10^{\mleft\{15-4\mright\}}=10^{11}[/tex]A manager recorded the performance review scores for each employee and placed the results in the bar chart below. All employees received a rating on each of the Evaluation Categories. If Person 6 obtained the highest score possible, what score did Person 3 receive? Use the graph and tables below.EVALUATION CATEGORIESRATINGGeneral Quality of WorkDependabilityJob KnowledgeCommunication SkillsPersonalityManagement AbilityContribution to GroupProductivityAchievement of GoalsRating ScaleSCOREDESCRIPTION5Excellent4Very Good3Good2Fair1Poor253530
SOLUTION
Comparing the graphs and the options, it follows that each line on the graph represents 5 points. This means the person 6 obtained a score of 45, comparing this to the person 3, it means the person 3 obtained a score of 35.
So the answer is 35.
For the rating since person 6 has the highest possible score, which is 45, person 3 score becomes
[tex]\begin{gathered} \frac{35}{45}\times5 \\ =3.88888888 \\ which\text{ is approximately 4} \end{gathered}[/tex]so we can classify person 3 as very good
need help with math
The y intercept is when x = 0.Therefore,
[tex]\begin{gathered} \text{when} \\ x=0 \\ y=0 \end{gathered}[/tex]The vertex can be found below
Need help with 3,4,5,and 6 please. I don’t understand it
4. The triangle has 3 given sides but no angles but we can get the angles using cosine law
[tex]\begin{gathered} \cos R=\frac{t^2+s^2-r^2}{2ts} \\ \cos \text{ R=}\frac{23.7^2+48^2-35^2}{2\times23.7\times48} \\ \cos R=\frac{561.69+2304-1225}{2275.2} \\ \cos R=\frac{1640.69}{2275.2} \\ \cos R=0.7211190225 \\ R=\cos ^{-1}0.7211190225 \\ R=43.8530535482 \\ R=44^{\circ} \end{gathered}[/tex][tex]\begin{gathered} \cos T=\frac{r^2+s^2-t^2}{2rs} \\ \cos T=\frac{35^2+48^2-23.7^2}{2\times35\times48} \\ \cos T=\frac{1225+2304-561.69}{3360} \\ \cos T=\frac{3529-561.69}{3360} \\ \cos T=\frac{2967.31}{3360} \\ \cos T=0.88312797619 \\ T=\cos ^{-1}0.88312797619 \\ T=27.977977493 \\ T=28^{\circ} \end{gathered}[/tex][tex]\begin{gathered} S=180-28-44 \\ S=108^{\circ} \end{gathered}[/tex]From largest to smallest it will be
[tex]\angle S,\angle R\text{ and}\angle T[/tex]last night Danielle had a birthday party. 1/3 of the cake was left over.She wanted to share the left over cake with 4 friends the next day .How much of birthday cake would each get
Solution
For this case we have a total cake representing 1
We also know that 1/3 of the cake was left over so then 1/3
And we want to share to 4 friends so we can do this:
1/3 * 1/4 = 1/12
So then each friend will recieve 1/12
The image point of A after a translation left 2 units and down 5 units is the pointB(-8, -11). Determine the coordinates of the pre-image point A.Submit Answer
Let the coordinates of the pre-image which is point A be (x,y)
The point after the translation left 2 units and down 5 units is B(-8, -11)
To get the x coordinate
we were tolt that the point was move 2 units left
So this implies x = -8+2 = -6
To get the y coordinates, we wre told that the point was moved down 5 units
This implies y = -11+ 5 = -6
Therefore, the coordinates of the pre-image point A is (-6, -6)
ocupo encontrar la x con procedimiento
les regalare coronas!!!!
La variable x asociada al sistema geométrico con dos ángulos alternos externos es igual a 23.
¿Cómo determinar la variable asociada a dos ángulos alternos externos?
En esta pregunta tenemos un sistema geométrico conformado por dos líneas paralelas atravesadas por una tercera línea. Este conjunto incluye dos ángulos alternos externos, que guardan la siguiente relación según la geometría euclídea:
6 · x - 28 = 4 · x + 18
A continuación, despejamos la variable x:
6 · x - 4 · x = 28 + 18
2 · x = 46
x = 23
El valor de la variable x es 23.
ObservaciónNo existen preguntas en español sobre ángulos alternos externos, por lo que se añade una pregunta en inglés.
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what is the correct base and coefficient for the function:
The general form of a logarithmic function is:
[tex]y=a\cdot\log _b(x)[/tex]Where a is the coefficient and b is the base. In the given picture, we can see that the coefficient is equal to 1, while the base is equal to 2.