Answer: Um, a little feedback would help, cause I'm new but if you are thanking someone, let me know and i'll thank them for you, any other questions?
Explanation:
Over 30 day period, a lake surface area is 1260 acres. The inflow is 36 cfs, thee outflow is 30 cfs. Seepage loss is 1.5 in. The total precipitation is 4.0 in. Evaporation loss is 6.0 in. Determine the water level change (inch) for the lake during this period.
Answer:
-0.1 inches
Explanation:
The net inflow is ...
36 cfs -30 cfs = 6 cfs
The number of seconds in 30 days is ...
(3600 s/h)(24 h/da)(30 da) = 2,592,000 . . . . seconds/(30 days)
Then the volume of inflow is ...
(6 ft^3/s)(2,592,000 s) = 15,552,000 ft^3
The number of square feet in 1260 acres is ...
(1260 ac)(43560 ft^/ac) = 54,885,600 ft^2
So, the increase in depth due to the inflow is ...
(15,552,000 ft^3)/(54,885,600 ft^2) ≈ 0.283353 ft ≈ 3.4002 in
__
The net change in water level is then ...
inflow - seepage + precipitation - evaporation
3.4 in -1.5 in +4.0 in -6.0 in = -0.1 in
The water level change in the period is -0.1 inch.
Explain the conditions under which galvanic corrosion occurs
Answer:
Explanation:
Galvanic corrosion occurs when two dissimilar metals are immersed in a conductive solution and are electrically connected. One metal (the cathode) is protected, whilst the other (the anode) is corroded. The rate of attack on the anode is accelerated, compared to the rate when the metal is uncoupled.
A tank with a volume of 40 cuft is filled with a carbon dioxide and air mixture. The pressure within the tank is 30 psia at 70oF. It is known that 2 lb of carbon dioxide was placed in the tank. Assume that air is 80% nitrogen and 20% oxygen and use the ideal gas laws. Calculate ,
The correct responses are;
(i) Weight percent of nitrogen: 58.6%
Weight percent of oxygen: 14.65%
Weight percent of carbon dioxide: 29.59%
(ii) Volume percent of nitrogen: 64.38%
Weight percent of oxygen: 14.1%
Weight percent of carbon dioxide: 21.53%
(iii) Partial pressure of nitrogen: 19.314 psia
Partial pressure of oxygen: 4.23 psia
Partial pressure of carbon dioxide: 6.459 psia
(iv) Partial pressure of nitrogen: 19.314 psia
Partial pressure of oxygen: 4.23 psia
Partial pressure of carbon dioxide: 6.459 psia
(v) The average molecular weight is approximately 32.02 g/mole
(vi) At 20 psia, 60 °F, the density is 0.11275 lb/ft.³
At 14.7 psia, 60 °F, the density is 0.0844 lb/ft.³
At 14.7 psia, 32 °F, the density is 0.0892 lb/ft.³
(vii) The specific gravity of the mixture 0.169
Reasons:
The volume of the tank = 40 ft.³ = 1.132675 m³
Content of the tank = Carbon dioxide and air
The pressure inside the tank = 30 psia = 206843 Pa
The temperature of the tank = 70 °F ≈ 294.2611 K
Mass of carbon dioxide placed in the tank = 2 lb.
Percent of nitrogen in the tank = 80%
Percent of oxygen in the tank = 20%
(i) 2 lb ≈ 907.1847 g
Molar mass of carbon dioxide = 44.01 g/mol
Number of moles of carbon dioxide = [tex]\displaystyle \mathbf{ \frac{907.1847 \, g}{44.01 \, g/mol}} \approx 20.613 \, moles[/tex]
Assuming the gas is an ideal gas, we have;
[tex]\displaystyle n = \mathbf{\frac{206843\times 1.132674}{8.314 \times 294.2611} }\approx 95.7588[/tex]
The number of moles of nitrogen and oxygen = 95.7588 - 20.613 = 75.1458
Let x represent the mass of air in the mixture, we have;
[tex]\displaystyle \mathbf{ \frac{0.8 \cdot x}{28.014} + \frac{0.2 \cdot x}{32}}= 75.1458[/tex]
Solving gives;
x ≈ 2158.92 grams
Mass of the mixture = 2158.92 g + 907.1847 g ≈ 3066.1047 g
[tex]\displaystyle Weight \ percent \ of \ nitrogen= \frac{0.8 \times 2158.92}{3066.105} \times 100 \approx \underline{58.6 \%}[/tex]
[tex]\displaystyle Weight \ percent \ of \ oxygen = \frac{0.8 \times 2158.92}{3066.105} \times 100 \approx \underline{14.65\%}[/tex]
[tex]\displaystyle Weight \ percent \ of \ carbon \ dioxide = \frac{907.184}{3066.105} \times 100 \approx \underline{29.59\%}[/tex]
ii.
[tex]\displaystyle Number \ of \ moles \ nitrogen= \frac{0.8 \times 2158.92 \, g}{28.014 \, g/mol} \approx 61.65\, moles[/tex]
[tex]\displaystyle Number \ of \ moles \ oxygen= \frac{0.2 \times 2158.92 \, g}{32 \, g/mol} \approx 13.5\, moles[/tex]
Number of moles of carbon dioxide = 20.613 moles
Sum = 61.65 moles + 13.5 moles + 20.613 moles ≈ 95.763 moles
In an ideal gas, the volume is equal to the mole fraction
[tex]\displaystyle Volume \ percent \ of \ nitrogen= \frac{61.65}{95.763} \times 100 \approx \underline{64.38 \%}[/tex]
[tex]\displaystyle Volume \ percent \ of \ oxygen = \frac{13.5}{95.763} \times 100 \approx \underline{14.1\%}[/tex]
[tex]\displaystyle Volume \ percent \ of \ carbon \ dioxide = \frac{20.613 }{95.763} \times 100 \approx \underline{21.53\%}[/tex]
(iv) The partial pressure of a gas in a mixture, [tex]P_A = \mathbf{X_A \cdot P_{total}}[/tex]
Partial pressure of nitrogen, [tex]P_{N_2}[/tex] = 0.6438 × 30 psia ≈ 19.314 psia
Partial pressure of oxygen, [tex]P_{O_2}[/tex] = 0.141 × 30 psia ≈ 4.23 psia
Partial pressure of carbon dioxide, [tex]P_{CO_2}[/tex] = 0.2153 × 30 psia ≈ 6.459 psia
(v) The average molecular weight is given as follows;
[tex]\displaystyle Average \ molecular \ weight = \frac{3066.105\, g}{95.7588 \, moles} = 32.02 \, g/mole[/tex]
(vi) At 20 psia 70 °F, we have;
Converting to SI units, we have;
[tex]\displaystyle n = \frac{137895.1456\times 1.132674}{8.314 \times 294.2611} \approx 63.84[/tex]
The number of moles, n ≈ 63.84 moles
The mass = 63.84 moles × 32.02 g/mol ≈ 2044.16 grams ≈ 4.51 lb
[tex]\displaystyle Density = \frac{4.51\ lb}{40 \ ft.^3} \approx \underline{0.11275\, lb/ft.^3}[/tex]
When the pressure is 14.7 psia = 101352.93 Pa, and 60 °F
[tex]\displaystyle n = \frac{101352.9\times 1.132674}{8.314 \times 288.7056} \approx 42.8247[/tex]
The mass = 47.8247 moles × 32.02 g/mol ≈ 1531.35 grams = 3.376 lb.
[tex]\displaystyle Density = \frac{3.376 \ lb}{40 \ ft.^3} \approx \underline{ 0.0844\, lb/ft.^3}[/tex]
When the pressure is 14.7 psia = 101352.93 and 32 °F
[tex]\displaystyle n = \frac{101352.9\times 1.132674}{8.314 \times 273.15} \approx 50.5482[/tex]
The mass = 50.5482 moles × 32.02 g/mol ≈ 1618.55 grams = 3.568 lb.
[tex]\displaystyle Density = \frac{3.568 \ lb}{40 \ ft.^3} \approx \underline{ 0.0892 \, lb/ft.^3}[/tex]
(vii) [tex]\displaystyle The \ specific \ gravity \ of \ the \ mixture \ = \frac{\frac{3066.1047\, g}{40 \, ft.^3} }{1.00} = \frac{\frac{6.7596 \, lbs}{40 \, ft.^3} }{1.00} \approx \underline{0.169}[/tex]
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The section 5(a)(1) of the osh act is commonly known as
Answer:
general duty clause
Explanation:
Question 10 of 25: Select the best answer for the question. 10. In a series RC circuit, if the resistance is 8,000 ohms and X is 6,000 ohms, what is the impedance of the circuit O A. 8,600 ohms O B. 10,000 ohms O C. 14,000 ohms O D. 9,200 ohms Mark for review (Will be highlighted on the review page) << Previous Question Next Question >> M LL 5 - 1080 acer
Answer:
B. 10,000 ohms
Explanation:
|8000 +j6000| = √(8000² +6000²) = 1000√(64 +36) = 1000√100 = 10,000
The impedance is 10,000 ohms.
All of the following are employment requirements for a technician EXCEPT:
Select one:
a. Being drug and alcohol free
b. Having all of your ASE certifications
c. Having a clean driving record
O d. Having honesty, integrity, reliability, and quality
Answer:
I think it would be C but im not sure sorry if its wrong
Describe the first case where the power of synthesis was used to solve design problems.
The first case where the power of synthesis was applied was in Chile when they had to put 100 families in houses around 40m².
It should be noted that the power of architecture is the fact that it can synthesize a complex entry to a problem.
Chilean architect Alejandro used this in building more than several houses for the poorest communities in Chile. His rigorous and innovative design approach used a social framework that laid a precedent within the profession.
During this period in Chile, a normal middle-class home was about 80m² but he built his in 40m² and it was a good home that managed the resources that were available.
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12. How will the temperature change in a room with an open refrigerator door, once equilibrium is established
Answer:
then back into the room
Explanation:
If you leave the door open, heat is merely recycled from the room into the refrigerator, then back into the room. A net room temperature increase would result from the heat of the motor that would be constantly running to move energy around in a circle.
A fully charged battery with 6 cells should indicate
Answer:
Battery Voltage
Voltage refers to the amount of electrical potential your battery holds. The standard automotive battery in today's vehicles is a 12-volt battery. Each battery has six cells, each with 2.1 volts at full charge. A car battery is considered fully charged at 12.6 volts or higher.
Lateral runout can be felt in the steering wheel even when the vehicle is
Select one:
a. At slower speeds
b. Just starting to move away from a stop
C. Just coming to a stop
d. Stopped
Lateral runout is felt in the steering wheel even at slower speeds. It leads to riding vibration and therefore poor ride quality.
Lateral runout refers to the side-to-side movement of the car's rotor as it rotates, which is caused by the off-center deviation of the rotor.
Lateral runout leads to riding vibration and therefore it is associated with poor ride quality.
Lateral runout can be properly quantified by using a dial indicator, which is a precision device used to measure linear displacements.
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4. What is the ampacity of 8-gage copper wire?
O A. 45 amps
OB. 30 amps
O C. 50 amps
O D. 25 amps
As part of the overall systems engineering process, there are a variety of software development methods, but the three most common at DoD are the Waterfall Approach, the Incremental Approach, and the ______________ Approach.
The three most common software development methods are the Waterfall Approach, the Incremental Approach, and the SPIRAL Approach. These methods depend on the team size and specific goals.
Software development is the sequential procedure that involves the division of the work into smaller and parallel stages in order to improve software design and product management.
The software development methods depend on both the team size and specific objectives.
The most common methodologies for software development include:
Waterfall Spiral Incremental Agile Continuous integrationLearn more about software development here:
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Which of the following is a measurement at the nominal level?
A-personal income in a year
B-student grades
C-the color of a person's hair (blond, brunette, redhead)
D-temperature
Answer:
A-personal income in a year this is the answer
Describe two fundamental reasons why flexural strength should depend on porosity
Answer: The elastic modulus and flexural strength are found to decrease with increased porosity. Fractography studies have been undertaken to identify the role of the pores on the fracture path. The deflection and cracking behavior of concrete structure depend on the flexural tensile strength of concrete. Many factors have been shown to influence the flexural tensile strength of concrete, particularly the level of stress, size, age and confinement to concrete flexure member, etc.
Explanation:
How can we honor what we value and care about in a world of disruptive technologies like AI?
Answer: Well, that's a good question. When we look around us, we tend to see what technology has done for us, and how far it is taking us. It might be disruptive, but without it there would be no high tech military weapons, and then how would we defend ourselves? There would be no technology entertainment and without that, life would be very dull. In answering your question, we can be thankful for what it is and how far it has been taking us in life.
Explanation: Please mark a brainliest if correct it helps and have meery holidays!
how many times greater is the value of the 2 of the 270413 than the valuce of the 2 in 419427?
6.03 Discussion: Then & Now - Safety
Discussion Topic
I'm Done
In this unit, you have learned about the evolution of the industry’s machines, through both technology and innovation. These improvements have reduced risk and injury to the Operating Engineers.
Choose one innovation or device.
Explain why you think that technology is the most important advancement in Operating Engineers’ safety.
Answer:
Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.
10. Which is of the following is not used in the
testing/analysis step?
A. Engineering notebooks.
B. Multiview drawings.
C. 3-D modeling software.
D. CNC machines.
A CNC machine stands for Computer Numerically Controlled Machine, they are used to Machine objects in hence create items, machine parts from prototypes. Hence the CNC machines are not used for testing/Analysis
D. CNC machines.
In Engineering the following items are basically needed for and during test/Analysis
Engineering notebooks: This is used to write down importance observations and findingsMulti-view drawings: This is also needed to visualise prototypes from different perspective or views3-D modelling software: e.g AutoCad , Autodesk Inventor, Revit to mention a few can be used to design and analyse project even before their actual implementation or designLearn more:
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What are minerals made of?
NO LINKS PLEASE
A. Different substances
B. Liquid substances
C. Two or more substances
D. The same substance throughout
Answer:
the answer I know is A. different substances. hope this helps :).
Explanation:
just always study hard and God bless.
Write a program that computes the square footage of a house given the dimensions of each room.Have the program ask the user how many rooms in the house and then request the dimensions of eachroom. Display the resulting total square footage.
An unknown relative passes away and bequeaths upon you a small tract of land in Amherst. You decide to build a two-story storage facility to make the best of your bequest. But your self-storage dream is in jeopardy due to a 10 meter thick layer of soft clay (N<4) on the site. You put on your best geotechnical engineer hat, hire a driller to pull up some samples, and send them off to a lab for a consolidation test. The report indicates that the clay is a dark grey, slightly sweet, kaolinite blend with a cy = 1x10-7 mº/s, single-drained, and an ultimate settlement of 0.73 meters. It does not make financial sense to install deep foundations, so you are interested in how long it will take to consolidate the clay layer using a passive load.
How long will it take for settlements of 25, 50, and 65 cm to occur?
If you need to build within the next 12 months and have at least 65cm of settlement to be viable, does it make sense to proceed?
Answer: It does make sense, because I've been involved in these careers and have a long family line of them. And other questions?
Explanation:
Who is responsible for shielding a welding arc to protect
the eyes and skin of all persons in the working area?
Answer:
manager and supervisor
Explanation:
How to make this circuit for simulating on Proteus.
I need help finding a good selling for a 71 Ford mustang hardtop coupe price This isn't really a school question but it's the only place I know we're I can ask questions so I'll give it a go
Answer:
you know you could use like quora or yahoo answers
Help! Please explain also. Thank you
Answer:
17A) 52mm
17B) 132mm
17C) 67mm
18.) 34
Explanation:
For 17)
Each distance is determined by the total distances surrounding it. For example, 17A is 73mm - 21mm, which is 52mm.
For 18)
Set up the problem as an algebraic expression:
a + b + c + d = 115
Since you know 3 of the values, you can plug them in and subtract them from 115, which turns into 34.
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(1) What are the available methods for crop establishments in the field?
(2) Give a conceptual sketch for a seeder to establish soybean seeds in an
agricultural field of dry zone in Sri Lanka (Use software where
necessary/or a hand sketch with detail).
(3) Discuss the advantages of the seed dibbling mechanism and list the
crops that can be used dibbler.
A
(4) Discuss the key points to enhance agricultural productivity using the
fertilizer applicators.
(5) Calculations: Calibration of a seed drill
Number of furrows = 5
Spacing between the furrows = 8 cm
Diameter of the ground wheel = 0.65 m
Number of rotations of the ground wheel = 300
Weight of seed collected = 20 kg
Calculate the seed rate in kg/ha
The average number of seeds dropped per one revelation =6
Calculate the
(1) seed rate and
(ii)
hole to hole spacing
Answer:
1) Therefore it was so much more than one answer my headwhy does my man bun not have its own erodynamics
Answer:
umm okay for starters I have no clue lol.
what is aerodynamics????
What is the first step in the decision-making process?
Answer: identify your decision. relize you need to make a decision.
Explanation:
Find the mean deviation of the set of numbers
(a) 12, 6, 7, 3, 15, 10, 18,5
Answer:
4.25
Explanation:
The mean deviation is how far, on average, all values are from the middle. To do that, we subtract each element from the mean of the elements, take their absolute values, and then divide by the number of elements in the set. Here's the formula: [tex]\sum\frac{|x-\mu|}{n}[/tex]
Here the mean is 9.5, the count n = 8, so the mean deviation is 4.25
a. State the functions of the followings
a. Commutator
b. Armature core
c. Field system
d. Brushes
e. Armature winding
Answer:
a. State the functions of the followingsa. Commutator:
the commutator reverses the current direction with each turn serving as a mechanical rectifier to convert the alternating current from the windings to unidirectional direct current in the external load circuit.
b. Armature core
Armature core is a physical structure made up of silicon steel stampings. The core is laminated to keep iron losses low. Armature winding is the main current carrying winding where we either provide(electric supply to motor) or extract e.m.f(collect electric power from generator).
c. Field system
The field winding basically form an electromagnet, that produces field flux within which the rotor armature of the DC motor rotates, and results in the effective flux cutting
d. Brushes
The function of brushes is that the brushes conduct current between stationary wires and moving parts of the electric Generator.
e. Armature winding
The winding wound on the core is given current through a DC supply. This current-carrying winding as under the influence of the magnetic field develops a force that develops a rotational torque. This torque enables the machine to rotate.
[tex] \bold \pink{ \underline{hope \: it \: helps}}[/tex]