The admission fee at a local zoo is $1.50 for children and $3.00 for adults. On a certain day, 2400 people enter the zoo and $4,800.00 is collected. How many children and how many adults?​

Answer:

Step-by-step explanation:

c = children

a = adults

2200 people enter the zoo mean :

c + a = 2200

$4,550.00 is collected mean :

1.5 c + 4 a = 4550

Now you must solve system:

c + a = 2200

1.5 c + 4 a = 4550

c + a = 2200 Subtract c to both sides

c + a - c = 2200 - c

a = 2200 - c

1.5 c + 4 a = 4550

1.5 c + 4 ( 2200 - c ) = 4550

1.5 * c + 4 * 2200 - 4 c = 4550

1.5 * c + 8800 - 4 c = 4550

- 2.5 c + 8800 = 4550 Subtract 8800 to both sides

- 2.5 c + 8800 - 8800 = 4550 - 8800

- 2.5 c = - 4250 Divide both sides by - 2.5

c = - 4250 / - 2.5

c = 1700

a = 2200 - c = 2200 - 1700 = 500

1700 children and 500 adults

Proof :

c + a = 1700 = 2200

$ 1.5 * c + $ 4 * a =

$ 1.5 * 1700 + $ 4 * 500 =

$ 2550 + $ 2000 = $ 4550

The number of children and the number of adults are 1600 and 800, respectively.

The allocation of weights to the relevant variables that produce the calculation's optimum is referred to as a direct consequence.

A nearby zoo charges $1.50 for kids and $3.00 for adults to enter. 2400 persons visit the zoo on a certain day, and $4,800.00 is gathered.

Let x be the number of children and y be the number of adults. Then the equation is written as,

x + y = 2400           ...1

1.5x + 3y = 4800

x + 2y = 3200    ...2

Subtract equation 1 from equation 1, then

2y - y = 3200 - 2400

y = 800

Then the value of x is calculated as,

x + 800 = 2400

x = 2400 - 800

x = 1600

The number of children and the number of adults are 1600 and 800, respectively.

More about the solution of the equation link is given below.

https://brainly.com/question/545403

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