The area of the shaded region is 20 cm. Find the value of x

Answer:

= 40√6

Step-by-step explanation:

least common multipler of 8,2:8

Answer:

Step-by-step explanation:

Answer:

  11.8 meters

Step-by-step explanation:

The triangle drawn is a right triangle. Two of its side lengths are given. The Pythagorean theorem tells you how those relate to the third side.

The sum of the squares of the legs of the triangle is equal to the square of it hypotenuse.

  (?)² + 34² = 36²

  (?)² + 1156 = 1296 . . . evaluate the squares

  (?)² = 140 . . . . . . . . . . subtract 1156 from both sides

  (?) = √140 . . . . . . . . . take the square root

  (?) ≈ 11.8 . . . meters

The length of the shadow is about 11.8 meters.

Answer:

y = -6x + 70

Step-by-step explanation:

Since the amount of oil in the tank decreases constantly, we need to create a linear function. Using the base form, y = mx + b, we can replace -6 for m because volume decreases by 6 (or increases by -6) each hour, and +70 for b because we start off with 70 liters of oil. So we get y = -6x + 70, with x representing the number of hours, and y representing the volume of oil remaining.

if any doubt leave a comment

The given equation is the best line that approximates the linear

relationship between the midterm score and the score in the final exam.

Reasons:

The given linear regression line equation is; [tex]\hat y[/tex] = 25.5 + 0.82·[tex]\mathbf{\hat x}[/tex]

Where;

[tex]\hat y[/tex] = Final exam score;

[tex]\hat x[/tex] = The midterm score;

AJ score in the first test, [tex]\hat x[/tex] = 90

AJ's actual score in the exam = 99

Required:

The value of AJ's residual

Solution:

By using the regression line equation, we have;

The predicted exam score, [tex]\hat y[/tex] = 25.5 + 0.82 × 90 = 99.3

∴ AJ's residual = 99.3 - 99 = 0.3

AJ's residual = 0.3

Therefore, the correct option is option E;

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Answer:

120 1 062 = × P . giving P = ÷ 120 1 062 . = 106 799

Answer:

8^5^7

Step-by-step explanation:

Multiply the numbers:

4X^2 y^3 x 2x^3 y^4

8^2 ^3 ^3 ^4

Combine Exponents:

8^2 ^3 ^3 ^4

8^5 ^3 ^4

8^5 ^3 ^4

8^5 ^7

Answer:

4x + 6y, 24

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

ty

Step-by-step explanation:

The pounds of steak remaining after the cookout is 3 13/16 pounds

Given:

Total steaks bought = 5 7/8

Steaks used for cookout = 2 1/16

Total steaks remaining = Total steaks bought - Steaks used for cookout

= 5 7/8 - 2 1/16

= 47/8 - 33/16

= (94-33) / 16

= 61/16

= 3 13/16 pounds

Therefore, the pounds of steak remaining after the cookout is 3 13/16 pounds

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Answer:

mom will let you know

Step-by-step explanation:

shes gone

Answer:

n

Step-by-step explanation:

it's simple mathematics that's the way it is

Answer:

32

Step-by-step explanation:

hope this helps :)

Answer:

3 you welcome

Step-by-step explanation:

Answer:

2,663 cm3

Step-by-step explanation:

Answer: 644.4 sq cm

Step-by-step explanation:

First transform the 8.5 and 11.75 into centimeters as that is what you are trying to find do this by multiplying each sum by 2.54

A.)8.5*2.54=21.59 centimeters

B.)11.75*2.54=29.845

C.)Now to find the Area we multiply the two

21.59*29.845=644.35355

Which we an round do 644.4

Answer:

Here is a screenshot of my graph.

Step-by-step explanation:

Answer:  $14.5

Step-by-step explanation: you divide 58 by 4 . each box is 14.5. total cost is $68 if you add postage

Answer:

103

Step-by-step explanation:

detailed explanation is in the diagram above

Answer: A. An infinite number of diameters can be drawn in a circle.

Step-by-step explanation:

There can be an infinite number of lines joining radii to the center. If we are placing 2 radii end-to-ending a circle, then we would have the same length as the diameter. Thus the diameter of the circle is twice as long as the radius. So, infinitely many diameters can be formed in the circle.

I got it from Goog|e, I hope it helps.

Answer:

"Only a limited number of radii can be drawn in a circle"

Step-by-step explanation:

A circles radii is the distance between the center of a circle(It only has one) to the edge of the circle. There is only one radii in a circle. And a circle only has one diameter.

Answer:

9/10

Step-by-step explanation:

Convert: 3/5 * 6/5=18/25

Simplify and Round it towards 9/10

Answer:

Square roots are when you multiply the same number by itself like for example, the square root of 5 is 25, because 5*5=25

Step-by-step explanation:

The value of the root of 2√5 is approximately 2.116.

Here, we have,

To find the root of a number, you can use the concept of radicals.

The "root" refers to the inverse operation of raising a number to a power. For example, the square root (√) is the most common root, and it represents finding a number that, when squared, gives the original number.

To find the root of a number, such as the square root (√), you can use the following notation:

√(2 * √(5))

In this case, we have the square root of (2 times the square root of 5).

To simplify this expression further, we can break it down step by step:

Step 1: Simplify the square root of 5:

√(5) = 2.236 (approximately)

Step 2: Substitute the simplified value back into the original expression:

√(2 * 2.236)

Step 3: Simplify the expression:

√(4.472) = 2.116 (approximately)

Therefore, the root of 2√5 is approximately 2.116.

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Answer:

Rs. 14560

Hope you could get an idea from here.

Doubt clarification - use comment section.

In rectangle ABCD

[tex]\\ \sf{:}\longrightarrow Area=LB[/tex]

[tex]\\ \sf{:}\longrightarrow Area=50(45)[/tex]

[tex]\\ \sf{:}\longrightarrow Area=2250m^2[/tex]

In rectangle PQRS

[tex]\\ \sf{:}\longrightarrow Area=LB[/tex]

[tex]\\ \sf{:}\longrightarrow Area=48(43)[/tex]

[tex]\\ \sf{:}\longrightarrow Area=2064m^2[/tex]

Now

[tex]\\ \sf{:}\longrightarrow Area_{(Path)}=Area_{(ABCD)}-Area_{(PQRS)}[/tex]

[tex]\\ \sf{:}\longrightarrow Area_{(Path)}=2250-2064=186m^2[/tex]

Cost:-

[tex]\\ \sf{:}\longrightarrow 186(40)[/tex]

[tex]\\ \sf{:}\longrightarrow Rs 7440[/tex]

Answer:

tn=a+(n-1)d

Step-by-step explanation:

t1=19

t2=24

t3=29

now,

d=t2-t1=24-19=5

=t3-t2=29-24=5

then,

tn=a+(n-1)d

=19+(n-1)5

=5n+14

[tex]\\ \sf\longmapsto f(x-1)=2x+3[/tex]

How?

[tex]\\ \sf\Rrightarrow f(-3)=f(-2-1)[/tex]

Let's find x then

[tex]\\ \sf\Rrightarrow x-1=-3[/tex]

[tex]\\ \sf\Rrightarrow x=-3+1[/tex]

[tex]\\ \sf\Rrightarrow x=-2[/tex]

[tex]\\ \sf\longmapsto f(-2-1)=2(-2)+3[/tex]

[tex]\\ \sf\longmapsto f(-3)=-4+3[/tex]

[tex]\\ \sf\longmapsto f(-3)=-1[/tex]

Given to us:

[tex](a)\ x^2+3x-2;\ -x^2-3x+2\\\\(b)\ -y^7-10;\ -y^7+10\\\\(c)\ 6z^5+6z^5-6z^4;\ (-6z^5)-(6z^5)+6z^4;\\\\(d)\ x-1;\ -x+1\\\\(e)\ (-5x^2) + (-2x) + (-10);\ 5x^2 - 2x + 10[/tex]

Additive inverse means changing the sign of the number and adding it to the original number to get 0(zero) as our answer.

(a)

[tex]x^2+3x-2;\ -x^2-3x+2)\\x^2+3x-2 +( -x^2-3x+2)\\[/tex] on solving this we will get zero.

hence, this is an additive inverse.

(b)

[tex]-y^7-10;\ -y^7+10\\-y^7-10+( -y^7+10)[/tex]  on solving this we will not be getting zero.

hence, this is not an additive inverse.

(c)

[tex]6z^5+6z^5-6z^4;\ (-6z^5)-(6z^5)+6z^4,\\\\6z^5+6z^5-6z^4+[ (-6z^5)-(6z^5)+6z^4}[/tex]  on solving this we will get zero.

hence, this is an additive inverse.

(d)

[tex]x-1;\ -x+1\\x-1+( -x+1)[/tex]    on solving this we will get zero.

hence, this is an additive inverse.

(e)

[tex]-5x^2 + -2x -10;\ 5x^2 (- 2x) + 10\\-5x^2 + -2x -10+ 5x^2 (- 2x) + 10[/tex]  on solving this we will not be getting zero.

hence, this is not an additive inverse.

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Answer:

-8

Step-by-step explanation:

In order to find the answer to this question you need to use the slope formula, substitute, subtract, and simplify if needed.

[tex](9,5),(4,1) = (x^1,y^1), (x^2,y^2)[/tex]

[tex]m = \frac{y^2-y^1}{x^2-x^1} = \frac{9-1}{4-5}[/tex]

[tex]9-1=8[/tex]

[tex]4-5=-1[/tex]

[tex]= -8[/tex]

Hope this helps.

Answer:

Transitive property

Step-by-step explanation:

When a=c and b=c, a=b

A would be 16+43

B would be 59

C would be 10+49