The control center of human body is * 1/1 heart
brain  
liver
  We have ________ sense organs * 1/1
6
4
5    
Which energy we get by burning of fuels * 1/1
Solar
Heat
  Light
  Sources of energy that can be used again and again will never run out * 1/1 Non renewable energy Renewable energy   Running water   What is called structure that build on rivers to get electricity * 1/1 Dam   Check dam Tunnel   Which nutrients protect us from diseases * 1/1 Carbohydrate Vitamin and Mineral   Protein   When is the best time of the day to water your lawn * 1/1 Early morning and late evening   Afternoon Night   Which of these ways to wash the car saves the most water? * 1/1 Wash it in the driveway with the garden hose Drive it into the lake Take it through a car wash that recycles water     Why do we keep food and vegetables in refrigerator? * 1/1​

Answers

Answer 1
The brain: the control center of the body.5. The sense organs — eyes, ears, tongue, skin, and nose — help to protect the body.Key Concept: When fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. A fuel is a substance that provides energy as a result of a chemical change.However, scientists are continually addressing these challenges, working to improve feasibility and reliability of renewable resources. Renewable resources include biomass energy (such as ethanol), hydropower, geothermal power, wind energy, and solar energy.Many dams are built for more than one purpose; for example, water in a single reservoir can be used for fishing, to generate hydroelectric power, and to support an irrigation system. Water-control structures of this type are often designated multipurpose dams.Antioxidants — such as vitamins C and E and carotenoids, which include beta-carotene, lycopene and lutein — help protect healthy cells from damage caused by free radicals.Water in the early morning – between 6 a.m. and 10 a.m. Midday watering leads to wasteful evaporation, while nighttime watering causes droplets to cling to grass overnight, increasing the chance of lawn diseases.Use a bucket instead of a continuous water flow from a hose. If you are using a hose, use one which has a spray handle that automatically shuts off the nozzle as you leave it. According to the Department of Environment, Maryland, USA, a 100 gallon car wash reduces to 30 gallons in such an arrangement.We refrigerate food to keep bacteria, yeasts, and molds from the favorable temperature they need to grow. The moisture-control available in many refrigerators also helps slow the deterioration of foods, so that two of the three favorable situations for microorganism growth are eliminated.

Related Questions

The linear distance traveled by a wheel of radius 50cm after 99 complete revolutions is?

1)99m
2)210m
3)311
4)433

Answers

Answer:

3) 311 m

Explanation:

Circumference = 2πR = π m/rev

99 rev(π m/rev) = 99π m or about 311 meters

Saturn's mass is 5.68 x 1024 kg and its radius is 6.03 x 107 m. A. Calculate the gravitational field strength at Saturn's surface. (2 marks) B. Calculate the force of gravity at Saturn's surface on an object with a mass of 50 kg.

Answers

Hi there!

A.

We can calculate the gravitational field strength using the following equation:

[tex]g = \frac{Gm_p}{r^2}[/tex]

G = Gravitational Constant

mp = mass of planet (kg)

r = radius (m)

Plug in the given values:

[tex]g = \frac{(6.67*10^{-11})*(5.68*10^{24})}{(6.03*10^7)^2} = \boxed{0.104 N/kg}[/tex]

B.

The force can be calculated using:

[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]

Plug in the values:

[tex]F_g = \frac{(6.67*10^{-11})(5.68*10^{24})(50)}{(6.04*10^7)^2} = \boxed{5.209N}[/tex]

Answer:

[tex]\boxed {\boxed {\sf g=0.104 \ N/kg \ and \ F_g= 5.2 \ N }}[/tex]

Explanation:

A. Gravitational Field Strength

The gravitational field strength can be calculated using the following formula:

[tex]g= \frac{Gm}{r^2}[/tex]

G, or the universal gravitational constant, is 6.67 × 10⁻¹¹ N*m²/kg². The mass of Saturn is 5.68 × 10²⁴ kilograms. The radius of Saturn is 6.03×10⁷ meters.

Substitute these values into the formula.

[tex]g= \frac{ (6.67 \times 10^{-11} \ N*m^2/kg^2) (5.68 \times 10^{24} \ kg)}{(6.03 \times 10^{7} \ m )^2}[/tex]

Multiply the numerator and square the denominator.

[tex]g= \frac{ 3.78856 \times 10^{14} \ N *m^2/kg }{3.63609 \times 10^{15} \ m^2}[/tex]

Divide.

[tex]g= 0.1041932405 \ N/kg[/tex]

The original measurements of mass and radius have 3 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 1 in the ten-thousandth place tells us to leave the 4 in the thousandth place.

[tex]\boxed {g \approx 0.104 \ N/kg}[/tex]

B. Force of Gravity

The force of gravity is calculated using the following formula:

[tex]F_g= mg[/tex]

The mass of the object is 50 kilograms. We just calculated the gravitational field strength, which is 0.104 Newtons per kilogram. Substitute these values into the formula.

[tex]F_g= (50 \ kg)(0.104 \ N/kg)[/tex]

Multiply. The units of kilograms cancel.

[tex]\boxed {F_g=5.20 \ N}[/tex]

what is the acceleration of the cart at t=8 seconds?
a) 0 m/s^2
b) 10 m/s^2
c) 20 m/s^3
d) -20m/s^2​

Answers

ANSWER:

What is the acceleration of the cart at t=8 seconds?

a) 0 m/s^2b) 10 m/s^2c) 20 m/s^3d) -20m/s^2

Hence the answer us letter a) 0 m/s^2.

That's all I know, Hope it help :)

if the Periodic time of an oscillating object Triples then its frequency will?​

Answers

Answer:

it would decrease

Explanation:

f=1/T

To get the dimmest bulbs with two batteries and two bulbs you would connect the batteries in ____ and the bulbs in ____.

Answers

Answer:

batteries in parallel connection and bulbs in serial connection

To get the dimmest bulb with two batteries and two bulbs you would connect the batteries in parallel and the bulbs in series.

What is Parallel and series circuits?

When two-terminal components and electrical networks that can be connected in series or parallel. This will result in two terminals in the electrical network, and may themselves participate in a series or parallel topology. When a two-terminal "object" is an electrical component or electrical network is a matter of perspective.

A circuit is said to be in series when the same current flows through all the components in the circuit where the current has only one path. A circuit is said to be parallel when there are multiple paths for the electric current to flow through it where the components which are part of the parallel circuit will have a constant voltage across all their ends.

Thus, to get the dimmest bulb with two batteries and two bulbs you would connect the batteries in parallel and the bulbs in series.

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Accelerations are produced by

A. Masses
B.accelerations
C. Velocities
D.unbalanced, net forces

Answers

The correct answer is D.
Acceleration is produced by a net force on an object.

73 ml of water is followed by 25 ml of juice. What is the percent strength of juice?

Answers

Total liquid: 73 + 25 = 98 ml

Percent juice = (25/98) x 100 = 25.5 %

How does friction help us in walking.​

Answers

Depending on the position and angle of our foot, this reaction contact force applied on our foot helps us to move forward as well as saves us from slipping and falling. This is how friction helps walking, in simple words.

difference between speed and velocity​

Answers

Answer:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

Explanation:

please help me
please help me
please help me​

Answers

Answer:

do it got a picture

on the edge

Explanation:

What is discordant characteristic ?

Answers

[tex] \: \: \: \: [/tex]

being at variance; disagreeing

or incongruous: discordant opinions. disagreeable to the ear; dissonant; harsh.

hope it helps

[tex] \: \: \: \: \: [/tex]

dissimilar with respect to one or more particular characters

A small, free-to-rotate magnet is placed in a strong magnetic field. In what orientation will it come to rest

Answers

Answer:

South-North

Explanation:

An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time?

Free-fall Acceleration is -10 m/s^2

Answers

Answer:

Explanation:

s = s₀ + v₀t + ½at²

s = 0 + 0(15) + ½(6)(15²)

s = 675 m

Not sure what the free fall acceleration is needed for, but if the object is dropped from a high enough point, it will travel in 15 seconds

s = ½10(15²) = 2250 m  if air resistance is ignored

is a fuel cell a primary or secondary cell

Answers

Answer:

Enrol in our 50 studyscore masterclass. Click here! Fuel cells are a type of primary cell in that they are not recharged, However, they are unique because they never run out, if the reactants are constantly supplied.

If the voltage across a 5-F capacitor is 2*e^-3
V find the current and the power

Answers

Answer correct in this picture………….

a student lifts a toy car from a bench and places the toy car at the top of a slope describe an energy transfer that occurs when the student lifts the toy car from the bench and places the toy car at the top of the slope.

Answers

Answer:

Assuming there are no energy losses due to friction or drag, the gravitational potential energy will change into kinetic potential energy as the car reaches the bottom of the slope.

G.P.E = m*g*h

K.E = (m*v^2)/2

where

m = mass of toy car (kg)

g = gravity (m/s^2)

h = heigh of your car from the bottom (m)

v = velocity of the toy car as it reaches the bottom (m/s)

Equate K.E to G.P.E

G.P.E = K.E

m*g*h = (m*v^2)/2

make v the subject of the formula

v = (2*g*h)^(1/2)

Substitute g = 9.81 m/s^2 and h = 2m into the equation to get v

v = (2*9.81*2)^(1/2)

v = 6.264 m/s

Carbon tetrachloride (CCl4) is diffusing through benzene (C6H6), as the drawing illustrates. The concentration of CCl4 at the left end of the tube is maintained at 1.71 x 10-2 kg/m3, and the diffusion constant is 21.9 x 10-10 m2/s. The CCl4 enters the tube at a mass rate of 5.86 x 10-13 kg/s. Using these data and those shown in the drawing, find (a) the mass of CCl4 per second that passes point A and (b) the concentration of CCl4 at point A.

Answers

We have that for the Question "find (a) the mass of CCl4 per second that passes point A and (b) the concentration of CCl4 at point A."

Answers:

Mass of CCI_4 per second = [tex]5.86*10^{-13} kg/s[/tex] Concentration of CCI_4 = [tex]12.6*10^{-3}kg/m^3[/tex]

From the question we are told

The concentration of [tex]CCl_4[/tex] at the left end of the tube is maintained at 1.71 x 10-2 kg/m3, and the diffusion constant is 21.9 x 10-10 m2/s. The CCl4 enters the tube at a mass rate of 5.86 x 10-13 kg/s

 

A) the mass flow rate of CCI_4 as it passes point A is the same as the mass flow rate at which CCI_4 enters the left end of the tube

Therefore, the mass flow rate of CCI_4 at point A

=  [tex]5.86*10^{-13} kg/s[/tex]

B) From Fick's law

[tex]\deltaC = \frac{mL}{DAt}\\\\ Assume L = 5*10^{-3}, A = 3*10^{-4}\\\\\deltaC = \frac{5.86*10^{-13} * 5*10^{-3}}{21.9*10^{-10} * 3*10^{-4}}\\\\\deltaC = 4.46*10^{-3}kg/m^3[/tex]

Then,

[tex]Concentration = 1.71*10^{-2} - 4.46*10^{-3}\\\\= 12.6*10^{-3}kg/m^3[/tex]

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A man is whirling a 0.25 kg ball on a 1.5 m long string at 3 m/s. Find the centripetal acceleration of this ball.

Question 2 options:

0.5 m/s2

13.5 m/s2

6 m/s2

2 m/s2

Answers

The centripetal acceleration of this ball is equal to 12 [tex]m/s^2[/tex]

Given the following data:

Diameter = 1.5 mSpeed, V = 3 m/s.Mass = 0.25 kg

Radius = [tex]\frac{Diameter}{2} = \frac{1.5}{2} = 0.75 \;meters[/tex]

To find the centripetal acceleration of this ball:

The acceleration of an object along a circular track is referred to as centripetal acceleration.

Mathematically, the centripetal acceleration of an object is given by the formula:

[tex]A_c = \frac{V^2}{r}[/tex]

Where:

Ac is the centripetal acceleration.r is the radius of the circular track.

V is the velocity of an object.

Substituting the given parameters into the formula, we have;

[tex]A_c = \frac{3^2}{0.75}\\\\A_c = \frac{9}{0.75}\\\\A_c = \frac{9}{0.75}[/tex]

Centripetal acceleration = 12 [tex]m/s^2[/tex]

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What is the relationship between balancing equations and the law of conservation of matter

Answers

Every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. Therefore, there must be the same number of atoms of each element on each side of a chemical equation.

help :”)
a skydiver jumps out of a plane and falls for 45 seconds before deploying his parachute. how far did he fall?

Answers

Answer:

200 feet

Explanation:

A gold doubloon 6.1 cm in diameter and 2.0 mm thick is dropped over the side of a pirate sheep.  When it comes to rest on the ocean floor at a depth of 770 m, how much has its volume changed?​

Answers

The definition of volume modulus and the variation of pressure with depth allows to find the result for the variation of the volume of the coin is:

ΔV = 2.15 10⁻⁸ m³

The pressure with the depth is given by the relation

         P = P₀ + ρ g h

Where P is the pressure, ρ is the density anf h depth.

The size of the bodies is determined by the distance of their atomic and molecular bonds, therefore the size of the bodies changes under external interations, in the case of hydrostatic pressure a constant called volumetric modulus is defined.

            [tex]B = - \frac{\Delta P}{\frac{\Delta V}{Vo} } \\\Delta V = - \frac{\Delta P }{B} \ V_o[/tex]

Where ΔP is the pressure change, V₀ and V are the volume change and the initial volume of the body, the negative sign is introduced so that the volumetric modulus is a positive quantity.

They indicate the diameter and thickness of the coin (d = 6.1 cm and e =0.20 cm) on the sea surface and the depth to which it is submerged

h = 770 m

Let's look for the volume of the coin.

          V₀ = π r² h = [tex]\pi \ \frac{d^2}{4} \ e[/tex]  

          V₀ = [tex]\pi \ \frac{0.061^2 }{4} \ 0.002[/tex]  

          V₀ = 5.84 10-6 m³

Let's find the pressure at the depth of y = 770 m,  the density of sea water is ρ = 1025 kg / m³, the pressure at the surface is the atmospheric pressure P₀ = 1 10⁵ Pa, the volumetric modulus of water is B = 0.21 10¹⁰ Pa.

          P = 1 10⁵ + 1025 9.8 770

          P = 1 10⁵ + 7,735 10⁶

          P = 7.84 10⁶ Pa

Let's calculate

          ΔV =[tex]- \frac{1 \ 10^5 - 7.84 \ 10^6 }{0.21 \ 10^{10}} \ 5.845 \ 10^{-6}[/tex]  

          ΔV = 2.15 10-8 m³

In conclusion using the definition of volume modulus and the variation of pressure with depth we can find the result for the variation of the volume of the coin is:

ΔV = 2.15 10-8 m³

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A race car traveling at 100 m/s enters an unbanked turn of 400 m radius. The coefficient of (static) friction between the tires and the track is 1.1. The track has both an inner and an outer wall. Which statement is correct

Answers

Answer:

The race car will crash into the outer wall

Explanation:

max fr = μsN = 1.1 mg = 11 m

mv2/R = m(100)2/(400) = 25 m > fr

Suppose a ball is thrown vertically upward (positive direction) from an initial height LaTeX: h_0 with initial velocity LaTeX: v_0. Find the position function LaTeX: s(t) of the ball after LaTeX: t seconds assuming the gravitational acceleration LaTeX: g is a positive constant pointing downward (negative direction).

Answers

After time t, the position function of the ball is determined as [tex]y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2[/tex]

The given parameters;

initial velocity of the ball, = [tex]v_0[/tex]initial position of the ball, = [tex]h_0[/tex]acceleration due to gravity, = g

The position function of the ball after time t, is calculated as follows;

[tex]y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2[/tex]

The negative sign of acceleration of due to gravity is because the ball is moving upward against gravity.

Thus, after time t, the position function of the ball is determined as [tex]y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2[/tex]

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Does it appear that true average HAZ depth is larger for the high current condition than for the nonhigh current condition

Answers

Answer:

The data suggest that the true mean HAZ depth is larger when the current setting is higher.

the c component of vector a is 5.3 units, and it’s y component is -2.3 units. the angle that vector a makes with the +x axis is closest to
110
160
23
340
250

Answers

Answer:

340

Explanation:

Sorry I don't know how to do this one yet, I just found the answer in a textbook.

The angle that vector a makes with the +x axis is closest to 23.

What is direction of a vector?

The direction of a vector is represented tangent of angle equal to the ratio of the y component and the x component of the vector quantity.

tangent of angle = y/x

angle = tan⁻¹ (-2.3/5.3)

angle = 23.46°

Thus, the angle that vector makes with +x is 23.

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Which region of electromagnetic spectrum will provide photons of the least energy

Answers

Answer:

Explanation:

Radio waves

Radio waves have photons with the lowest energies. Microwaves have a little more energy than radio waves. Infrared has still more, followed by visible, ultraviolet, X-rays and gamma rays.

The center of gravity of a loaded truck depends on how the truck is packed. If it is 4.0 m high and 2.4 m wide, and its CG is 2.2 m above the ground, how steep a slope can the truck be parked on without tipping over

Answers

The slope of the road can be given as the ratio of the change in vertical

distance per unit change in horizontal distance.

The maximum steepness of the slope where the truck can be parked without tipping over is approximately 54.55 %.

Reasons:

Width of the truck = 2.4 meters

Height of the truck = 4.0 meters

Height of the center of gravity = 2.2 meters

Required:

The allowable steepness of the slope the truck can be parked without tipping over.

Solution:

Let, C represent the Center of Gravity, CG

At the tipping point, the angle of elevation of the slope = θ

Where;

[tex]tan\left(\theta \right) = \dfrac{\overline{AM}}{\overline{CM}}[/tex]

The steepness of the slope is therefore;

[tex]\mathrm{The \ steepness \ of \ the \ slope}= \dfrac{\overline{AM}}{\overline{CM}} \times 100[/tex]

Where;

[tex]\overline{AM}[/tex] = Half the width of the truck = [tex]\dfrac{2.4 \, m}{2}[/tex] = 1.2 m

[tex]\overline{CM}[/tex] = The elevation of the center of gravity above the ground = 2.2 m

[tex]\mathrm{The \ steepness \ of \ the \ slope}= \dfrac{1.2}{2.2} \times 100 \approx 54.55\%[/tex]

[tex]tan\left(\theta \right) = \mathbf{\dfrac{2.2}{1.2}} = \dfrac{11}{6}[/tex]

[tex]Elevation \ of \ the \ road \ \theta = arctan\left( \dfrac{6}{11} \right) \approx 28.6 ^{\circ}[/tex]

The maximum steepness of the slope where the truck can be parked is 54.55 %.

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1.25 is the closest to 1.04 or not I want to answer please. I think it's true, but I want to prove it scientifically, please.

Answers

Answer/Explanation:

It False, because if You Round Both of them..

1.25= 1.30

1.04= 1.00

it's like, 1 dollar and 4 cents; compared to 1 dollar and 25 cents. Obviously 25 cents is a lot more than 4 cents.

Read the scenario below and answer the question that follows. Randall is hiring cooks for his restaurant. The first applicant is a handsome man with an average resumé and average job experience. The second applicant is a far less attractive man with a slightly above average resumé and above average job experience. Randall decides to hire the first applicant. Based on this information and on Randall’s decision, what might a psychologist conclude about Randall’s social perception? Randall has an unconscious assumption that attractive people are more competent. Randall has a unconscious assumption that unattractive people are bad cooks. Randall has a conscious assumption that attractive people make better cooks. Randall has a conscious assumption that unattractive people are more competent.

Answers

Randall has unconscious assumption that attractive people are more competent

Randall has an unconscious assumption that attractive people are more competent.

What is meant by assumption ?

The term assumption can be described as an unspoken premise that underlies the conclusion.

Here,

The capacity to accurately evaluate and draw conclusions about other individuals based on their overall physical appearance, verbal behaviour, and nonverbal attitudes is referred to as social perception.

Given that, for his restaurant, Randall is employing chefs. The first applicant is a dashing man with an average resume and career history. The second candidate is a far less appealing man with an average to slightly above average resume and work experience. Randall chooses to hire the first candidate.

This shows the social perception of Randall and his unconscious assumptions against unattractive people.

Hence,

Randall has an unconscious assumption that attractive people are more competent.

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science thanks sa points​

Answers

Answer: Are these free point?

Explanation:

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