The cost, c(x) in dollars per hour of running a trolley at an amusement park is modelled by the function [tex]c(x) = 2.1x {}^{2} - 12.7x + 167.4[/tex]Where x is the speed in kilometres per hour. At what approximate speed should the trolley travel to achieve minimum cost? A. About 2km/h B about 3km/h C about 4km/D about 5km/hr

Answers

Answer 1

The equation is modelled by the function,

c(x) = 2.1x^2 - 12.7x + 167.4

The general form of a quadratic equation is expressed as

ax^2 + bx + c

The given function is quadratic and the graph would be a parabola which opens upwards because the value of a is positive

Since x represents the speed, the speed at which the he


Related Questions

Solve for x using the quadratic formula.3x^2 +10x+8=3

Answers

The quadartic equation is 3x^2+10x+8=3.

Simplify the quadratic equation to obtain the equation in standard form ax^2+bx+c=0.

[tex]\begin{gathered} 3x^2+10x+8=3 \\ 3x^2+10x+5=0 \end{gathered}[/tex]

The coefficent of x^2 is a=3, coefficient of x is b=10 and constant term is c=5.

The quadartic formula for the values of x is,

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

Substitute the values in the formula to obtain the value of x.

[tex]\begin{gathered} x=\frac{-10\pm\sqrt[]{(10)^2-4\cdot3\cdot5}}{2\cdot3} \\ =\frac{-10\pm\sqrt[]{100-60}}{6} \\ =\frac{-10\pm\sqrt[]{40}}{6} \\ =\frac{-10\pm2\sqrt[]{10}}{6} \\ =\frac{-5\pm\sqrt[]{10}}{3} \end{gathered}[/tex]

The value of x is,

[tex]\frac{-5\pm\sqrt[]{10}}{3}[/tex]

A man realizes he lost the detailed receipt from the store and only has the credit card receipt with theafter-tax total. If the after-tax total was $357.06, and the tax rate in the area is 8.2%, what was the pre-tax subtotal?

Answers

Answer: the pre-tax subtotal is $330

Explanation:

Let x represent the pre tax total

If the tax rate in the area is 8.2%, it means that the amount of tax paid is

8.2/100 * x = 0.082x

pretax total + tax = after tax subtotal

Given that after tax subtotal is $357.06, then

x + 0.082x = 357.06

1.082x = 357.06

x = 357.06/1.082

x = 330

the pre-tax subtotal is $330

Write a quadratic function whose graph passes through (3,6) and has the vertex (-2,4) what is the value of Y

Answers

The representation of a quadratic eqauation in vertex form is

[tex]y=a(x-k)^2+h[/tex]

The given vertex is,

[tex](k,h)=(-2,4)[/tex]

And the given point through which the graph passes is,

[tex](x,y)=(3,6)[/tex]

Substitute the values in the formula of quadratic equation.

[tex]\begin{gathered} 6=a(3-(-2))+4 \\ 6=a(3+2)+4 \\ 6=5a+4 \\ 5a=6-4 \\ 5a=2 \\ a=\frac{5}{2} \end{gathered}[/tex]

Hence, the equation in vertex form will be,

[tex]\begin{gathered} y=\frac{5}{2}(x-(-2))+4 \\ y=\frac{5}{2}(x+2)+4 \end{gathered}[/tex]

How do I find the gif and distributive property

Answers

By using the GCF and distributive property, the sum of 15+27 = 42

The expression is

15 + 27

GCF is the greatest common factor, the greatest common factor is the highest number that divides exactly into two or more numbers.

The distributive property states that multiplying the sum of two or more variables by a number will produce the same result as multiplying each variables individually by the number and then adding the products together.

The expression is

= 15 + 27

= 3(5 + 9)

= 3 × 14

= 42

Hence, by using the GCF and distributive property, the sum of 15 + 27 = 42

Learn more about distributive property here

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Radicals and Exponents Identify the choices that best completes the questions 3.

Answers

3.- Notice that:

[tex]\sqrt[]{12}=\sqrt[]{4\cdot3}=2\sqrt[]{3}\text{.}[/tex]

Therefore, we can rewrite the given equation as follows:

[tex]2\sqrt[]{3}x-3\sqrt[]{3}x+5=4.[/tex]

Adding like terms we get:

[tex]-\sqrt[]{3}x+5=4.[/tex]

Subtracting 5 from the above equation we get:

[tex]\begin{gathered} -\sqrt[]{3}x+5-5=4-5, \\ -\sqrt[]{3}x=-1. \end{gathered}[/tex]

Dividing the above equation by -√3 we get:

[tex]\begin{gathered} \frac{-\sqrt[]{3}x}{-\sqrt[]{3}}=\frac{-1}{-\sqrt[]{3}}, \\ x=\frac{1}{\sqrt[]{3}}\text{.} \end{gathered}[/tex]

Finally, recall that:

[tex]\frac{1}{\sqrt[]{3}}=\frac{\sqrt[]{3}}{3}\text{.}[/tex]

Therefore:

[tex]x=\frac{\sqrt[]{3}}{3}\text{.}[/tex]

Answer: Option C.

1. Is this figure a polygon?2. Is this polygon concave or convex?3. Is this polygon regular, equiangular, Equilateral, or none of these?4. What is the name of this polygon?

Answers

A polygon is a closed shape with straigh sides, then

2. Is the figure a polygon? YES.

Since the figure is a polygon

1a. Is this polygon concave or convex? It is concave. A concave polygon will always have at least one reflex interior angle, tha is, it has on interior angle greater than 180 degrees.

1b. Is this polyogn regular, equiangular, equilateral or none of these? The marks on the picture mean that all the sides have the same length. This is the definition of equilateral. Then the answer is equilateral.

1c. What is the name of this polygon? We can see it has 4 equal sides and is concave, then his name is Concave Equilateral Quadrilateral.

At one time, it was reported that 27.9% of physicians are women. In a survey of physicians employed by a large health system, 45 of 120 randomly selected physicians were women. Is there sufficient evidence at the 0.05 level of significance to conclude that the proportion of women physicians in the system exceeds 27.9%?Solve this hypothesis testing problem by finishing the five steps below.

Answers

SOLUTION

STEP 1

The hull hypothesis can written as

[tex]H_0\colon p=0.279[/tex]

The alternative hypothesis is written as

[tex]H_1\colon p>0.279[/tex]

STEP 2

The value of p will be

[tex]\begin{gathered} \hat{p}=\frac{X}{n} \\ \hat{p}=\frac{45}{120}=0.375 \\ \text{where n=120, x=}45 \end{gathered}[/tex]

STEP3

From the calculations, we have

[tex]\begin{gathered} Z_{\text{cal}}=2.34 \\ \text{Z}_{\text{los}}=0.05 \end{gathered}[/tex]

We obtained the p-value has

[tex]\begin{gathered} p-\text{value}=0.0095 \\ \text{level of significance =0.05} \end{gathered}[/tex]

STEP4

Since the p-value is less than the level of significance, we Reject the null hypothesis

STEP 5

Conclusion: There is no enought evidence to support the claim

Mark is roofing an old gymnasium that measures 270’x390’, and needs to calculate how many “squares “ he will need.(1 “square=100 ft square). The gym’s roof is a standard gable roof with 3’ of overhang on all sides. The roof angle measures 22.55 degrees from horizontal. How many squares of roofing does mark need ?

Answers

First, because of the roof having an inclination, we need to calculate the lenght of the surface we want to roof. The width will be the same.

Let's take a look at the situation:

Since we're on a right triangle, we can say that:

[tex]\cos (22.25)=\frac{G}{R}[/tex]

Solving for R,

[tex]\begin{gathered} \cos (22.25)=\frac{G}{R}\rightarrow R\cos (22.25)=G \\ \\ \Rightarrow R=\frac{G}{\cos (22.25)} \end{gathered}[/tex]

Since we already know that the lenght of the gym's floor is 390',

[tex]\begin{gathered} R=\frac{390^{\prime}}{\cos (22.25)} \\ \\ \Rightarrow R=421.38^{\prime} \end{gathered}[/tex]

We get that the lenght of the surface we want to roof is 421.38'

Now, let's take a look at the surface we want to roof:

Since the roof is a standard gable roof with 3’ of overhang on all sides, we add 6' to each dimension:427

Our total roofing area would be:

[tex]427.38^{\prime}\cdot276^{\prime}=117956.88ft^2[/tex]

We then divide this total area by the area of one of our "squares":

[tex]\frac{117956.88}{100}=1179.56[/tex]

We round to the nearest integer from above, since we can't buy a fraction of a square.

(this is called ceiling a number)

[tex]1179.56\rightarrow1180[/tex]

Therefore, we can conclude that Mark needs 1180 squares of roofing.

What is the vertex of the parabola with thefunction rule f(x) = 5(x − 4)² + 9?

Answers

The equation f(x) = a(x - h)^2 + k gives the vertex of the parabola--it is (h, k).

In this question, h = 4 and k = 9. So the vertex is at (4, 9).

how to get standar form from point 1,4 and a slope of 5

Answers

[tex]m=5[/tex][tex]y=mx+b[/tex][tex]x=1[/tex][tex]y=4[/tex][tex]b=y-mx[/tex][tex]b=4-(5)(1)=-1[/tex][tex]y_{}=5x-1[/tex]

The seventh term of a geometric sequence is 1/4 The common ratio 1/2 is What is the first term of the sequence?

Answers

Answer:

16

Explanation:

The equation for the term number n on a geometric sequence can be calculated as:

[tex]a_n=a_{}\cdot r^{n-1}[/tex]

Where r is the common ratio and a is the first term of the sequence.

So, if the seventh term of the sequence is 1/4 we can replace n by 7, r by 1/2, and aₙ by 1/4 to get:

[tex]\frac{1}{4}=a\cdot(\frac{1}{2})^{7-1}[/tex]

Then, solving for a, we get:

[tex]\begin{gathered} \frac{1}{4}=a(\frac{1}{2})^6 \\ \frac{1}{4}=a(\frac{1}{64}) \\ \frac{1}{4}\cdot64=a\cdot\frac{1}{64}\cdot64 \\ 16=a \end{gathered}[/tex]

So, the first term of the sequence is 16.

I don't get any of this help me please

Answers

Using scientific notation, we have that:

a) As an ordinary number, the number is written as 0.51.

b) The value of the product is of 1445.

What is scientific notation?

An ordinary number written in scientific notation is given as follows:

[tex]a \times 10^b[/tex]

With the base being [tex]a \in [1, 10)[/tex], meaning that it can assume values from 1 to 10, with an open interval at 10 meaning that for 10 the number is written as 10 = 1 x 10¹, meaning that the base is 1.

For item a, to add one to the exponent, making it zero, we need to divide the base by 10, hence the ordinary number is given as follows:

5.1 x 10^(-1) = 5.1/10 = 0.51.

For item b, to multiply two numbers, we multiply the bases and add the exponents, hence:

(1.7 x 10^4) x (8.5 x 10^-2) = 1.7 x 8.5 x 10^(4 - 2) = 14.45 x 10².

To subtract two from the exponent, making it zero, we need to multiply the base by 2, hence the base number is given as follows:

14.45 x 100 = 1445.

More can be learned about scientific notation at https://brainly.com/question/16394306

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Find the length of AB given that DB is a median of the triangle AC is 46

Answers

ANSWER:

The value of AB is 23

STEP-BY-STEP EXPLANATION:

We know that AB is part of AC, and that DB cuts into two equal parts (half) since it is a median, therefore the value of AB would be

[tex]\begin{gathered} AB=\frac{AC}{2} \\ AB=\frac{46}{2} \\ AB=23 \end{gathered}[/tex]

true or false 16/24 equals 30 / 45

Answers

True.

Given:

The equation is, 16/24 = 30/45.

The objective is to find true or false.

The equivalent fractions can be verified by, mutiplying the denominator and numerator of each fraction.

The fractions can be solved as,

[tex]\begin{gathered} \frac{16}{24}=\frac{30}{45} \\ 16\cdot45=24\cdot30 \\ 720=720 \end{gathered}[/tex]

Since both sides are equal, the ratios are equivalent ratios.

Hence, the answer is true.

Could I assistance receive some on this question it’s very confusing

Answers

We need to translate the vertex F of triangle BDF. When we translate it 2 units to the left and 4 units down, we obtain the point F'.

We know that triangle BDF has vertices B(4,3), D(6,3), and F(6,1).

The first coordinate of each point represents its x-coordinate (the distance from the y-axis). And the second coordinate of each point represents its y-coordinate (the distance from the x-axis).

So, this triangle is shown below:

Now, we need to translate the point F 2 units to the left, to obtain the redpoint below. And then translate it 4 units down, to obtain F' (the yellow point):

Therefore, the F' has coordinates:

F'(4,-3)

The ship leaves at 18 40 to sail to the next port.
It sails 270 km at an average speed of 32.4 km/h
Find the time when the ship arrives.

Answers

Answer:

Step-by-step explanation:

Given:

t₁ = 18:40 or  18 h 40 min

S = 270 km

V = 32.4 km/h

____________

t₂ - ?

Ship movement time:

t = S / V = 270 / 32.4 ≈ 8.33 h = 8 h 20 min

t₂ = t₁ + t = 18 h 40 min + 8 h 20 min

40 min + 20 min = 60 min = 1 h

18 h +8 h = 26 h    =  24 h + 2 h

2 h + 1 h = 3 h

t₂ = 3:00

The ship will arrive at the destination port at 3:00 the next day.

Answer:

32.4 - 27.0 = 5.4

18.40 + 54 =

7hrs:34mins

The ship arrived at

7:34pm

Rewrite 20 - 4x³ using a common factor.
O 4x(5-x²)
O4(5 - 4x³)
02x(10-2x²)
02(10-2x³)

Answers

Answer:

[tex]20 - 4 {x}^{3} = 4(5 - {x}^{3} )[/tex]

Rewrite 4x + 16 using a common factor.

Answer 4(x + 4)

a.a + 0 = 0Additive Identityb. Multiplicative IdentityCommutative Property of Additiond. Associative Property of AdditionC.

Answers

Answer:

a. Additive Identity

Explanation:

Given the equation:

[tex]a+0=a[/tex]

When zero(0) is added to 'a', the result is still 'a'.

The number 0 is the additive identity of 'a'.

Find the missing quantity with the information given. Round rates to the nearest whole percent and dollar amounts to the nearest cent% markdown = 40Reduced price = $144$ markdown = ?

Answers

The given information:

% mark up = 40

Reduced = $144

Markdown = ?

The formula for percentage markup is given as

[tex]\text{ \%markup }=\frac{markup}{actual\text{ price}}\times100[/tex]

Let the actual price be x

Hence,

Reduced price = 60% of actual price

[tex]60\text{\% of x = 144}[/tex]

Solving for x

[tex]\begin{gathered} \frac{60x}{100}=144 \\ x=\frac{144\times100}{60} \\ x=240 \end{gathered}[/tex]

Therefore, actual price = $240

Inserting these values into the %markup formula gives

[tex]40=\frac{\text{markup}}{240}\times100[/tex]

Solve for markup

[tex]\begin{gathered} 40=\frac{100\times\text{markup}}{240} \\ 40\times240=100\times\text{markup} \\ \text{markup}=\frac{40\times240}{100} \\ \text{markup}=96 \end{gathered}[/tex]

Threefore, markup = $96

Wayne has a bag filled with coins. the bag contains 7 quarters,8 dimes,3 nickels, and 9 pennies. he randomly chooses a coins from the bag. what is the probability that Wayne chooses a quarter or nickel?

Answers

Wayne has a bag filled with coins.

Number of quarters = 7

Number of dimes = 8

Number of nickels = 3

Number of pennies = 9

So, the total number of coins is

Total = 7 + 8 + 3 + 9 = 27

What is the probability that Wayne chooses a quarter or nickel?

How many coins are either quarter or nickel?

quarter or nickel = 7 + 3 = 10

So, the probability is

[tex]P(quarter\: or\: nickel)=\frac{10}{27}[/tex]

Therefore, the probability that Wayne chooses a quarter or nickel is 10/27

In exercises 1 and 2 , identify the bisector of ST then find ST

Answers

Given: The line segment ST as shown in the image

To Determine: The bisector of ST and the value of ST

Solution

It can be observed from the first image, the bisector of ST is line MW

[tex]\begin{gathered} ST=SM+MT \\ SM=MT(given) \\ MT=19(given) \\ Therefore \\ ST=19+19 \\ ST=38 \end{gathered}[/tex]

For the second image, the bisector of ST is line LM

[tex]\begin{gathered} ST=SM+MT \\ SM=3x-6 \\ MT=x+8 \\ SM=MT(given) \\ Therefore \\ 3x-6=x+8 \\ 3x-x=8+6 \\ 2x=14 \\ x=\frac{14}{2} \\ x=7 \end{gathered}[/tex][tex]\begin{gathered} SM=3(7)-6=21-6=15 \\ MT=7+8=15 \\ ST=SM+MT \\ ST=15+15 \\ ST=30 \end{gathered}[/tex]

For first exercise, the bisector is MW, ST = 38

For the second exercise, the bisector is LM, ST = 30r

Using the equation and the ordered-pairs found previously, plot the points on the graph that would best satisfy theequation.y= 2^x

Answers

Given the following equation:

[tex]y=x^2[/tex]

We will graph the given function using the points that will be written in ordered-pairs.

The given function is a quadratic function with a vertex = (0, 0)

We will graph the points using five points

The vertex and 4 points, 2 points before the vertex and 2 points after the vertex.

So, we will substitute x = -4, -2, 2, 4

[tex]\begin{gathered} x=-4\rightarrow y=16 \\ x=-2\operatorname{\rightarrow}y=4 \\ x=2\operatorname{\rightarrow}y=4 \\ x=4\operatorname{\rightarrow}y=16 \end{gathered}[/tex]

So, the points are: (-4, 16), (-2, 4), (0, 0), (2, 4), (4, 16)

The graph using the points will be as follows:

What is the current population of elk at the park?

Answers

Given the following function:

[tex]\text{ f\lparen x\rparen= 1200\lparen0.8\rparen}^{\text{x}}[/tex]

1200 represents the initial/current population of elk in the national park.

Therefore, the answer is CHOICE A.

Finding a specify term of a geometric sequence given the common ratio and first term

Answers

Explanation

A geometric sequence is defined as:

[tex]\begin{gathered} a_1=a*r^0=a*r^{1-1}, \\ a_2=a*r^1=a*r^{2-1}, \\ a_3=a*r^2=a*r^{3-1}, \\ ... \\ a_7=a*r^6=a*r^{7-1}, \\ ... \end{gathered}[/tex]

Where r ≠ 0 is the common ratio and a ≠ 0 is the first term of the sequence.

From the statement, we know that r = 2/3 and the first term is a = 5.

Replacing these numbers in the expression of the 7th term, we get:

[tex]a_7=5*(\frac{2}{3})^6=5*\frac{64}{729}=\frac{320}{729}.[/tex]Answer

320/729

Jason is making bookmarks to sell to raise money for the local youth center. He has 29 yards of ribbon, and he plans to make 200 bookmarks.Approximately how long is each bookmark, in centimeters?

Answers

The Solution:

The correct answer is 13.26 centimeters.

Explanation:

Given that Jason has 29 yards of ribbon, and he plans to make 200 bookmarks.

We are asked to find the approximate length (in centimeters) of each bookmark.

Step 1:

Convert 29 yards to centimeters.

[tex]\begin{gathered} \text{ Recall:} \\ \text{ 1 yard = 91.44 centimeters} \end{gathered}[/tex]

So,

[tex]29\text{ yards = 29}\times91.44=2651.76\text{ centimeters}[/tex]

Step 2:

To get the length of each bookmark, we shall divide 2651.76 by 200.

[tex]\text{ Length each bookmark = }\frac{2651.76}{200}=13.2588\approx13.26\text{ centimeters}[/tex]

Therefore, the correct answer is 13.26 centimeters.

2. Assume that each situation can be expressed as a linear cost function and find the appropriate cost function. (a) Fixed cost, $100; 50 items cost $1600 to produce. (b) Fixed cost, $400; 10 items cost $650 to produce. (c) Fixed cost, $1000; 40 items cost $2000 to produce. (d) Fixed cost, $8500; 75 items cost $11,875 to produce. (e) Marginal cost, $50; 80 items cost $4500 to produce. (f)Marginal cost, $120; 100 items cost $15,800 to produce. (g) Marginal cost, $90; 150 items cost $16,000 to produce. (h) Marginal cost, $120; 700 items cost $96,500 to produce.

Answers

Given:

Cost function is defined as,

[tex]\begin{gathered} C(x)=mx+b \\ m=\text{marginal cost} \\ b=\text{fixed cost} \end{gathered}[/tex]

a) Fixed cost = $100, 50 items cost $1600.

The cost function is given as,

[tex]\begin{gathered} C=\text{Fixed cost+}x(\text{ production cost)} \\ x\text{ is number of items produced} \\ \text{Given that, }50\text{ items costs \$1600} \\ 1600=100\text{+50}(\text{ production cost)} \\ \text{production cost=}\frac{1600-100}{50} \\ \text{production cost}=30 \end{gathered}[/tex]

So, the cost function is,

[tex]C=30x+100[/tex]

b) Fixed cost = $400, 10 items cost $650.

[tex]\begin{gathered} 650=400+10p \\ 650-400=10p \\ p=25 \\ \text{ Cost function is,} \\ C=25x+400 \end{gathered}[/tex]

c) Fixed cost= $1000, 40 items cost $2000 .

[tex]\begin{gathered} 2000=1000+40p \\ p=25 \\ C=25x+1000 \end{gathered}[/tex]

d) Fixed cost = $8500, 75 items cost $11,875.

[tex]\begin{gathered} 11875=8500+75p \\ 11875-8500=75p \\ p=45 \\ C=45x+8500 \end{gathered}[/tex]

e) Marginal cost= $50, 80 items cost $4500.

In this case we know the value of m = 50 .

Use the slope point form,

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ (x_1,y_1)=(80,4500) \\ y-4500=50(x-80) \\ y=50x-4000+4500 \\ y=50x+500 \\ C=50x+500 \end{gathered}[/tex]

f) Marginal cost=$120, 100 items cost $15,800.

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ (x_1,y_1)=(100,15800) \\ y-15800=120(x-100) \\ y=120x-12000+15800 \\ y=120x+3800 \\ C=120x+3800 \end{gathered}[/tex]

g) Marginal cost= $90,150 items cost $16,000.

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ (x_1,y_1)=(150,16000) \\ y-16000=90(x-150) \\ y=90x-13500+16000 \\ y=90x+2500 \\ C=90x+2500 \end{gathered}[/tex]

h) Marginal cost = $120, 700 items cost $96,500

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ (x_1,y_1)=(700,96500) \\ y-96500=120(x-700) \\ y=120x-84000+96500 \\ y=120x+12500 \\ C=120x+12500 \end{gathered}[/tex]

THIS IS URGENT
A line includes the points (2,10) and (9,5). What is its equation in point-slope form?
Use one of the specified points in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.

Answers

Answer:

Step-by-step explanation:

y = 13x -12

gus bought 2/3 pound of turkey and 1/4 pound of ham.The tukey cost 9 dollars per pound, and the ham cost 7 dollars per pound.In all,how much did Gus spend?

Answers

From the information given,

gus bought 2/3 pound of turkey. If tukey costs 9 dollars per pound, it means that the cost of 2/3 pound of turkey is

2/3 x 9 = 6

gus bought 1/4 pound of ham. If ham costs 7 dollars per pound, it means that the cost of 1/4 pound of ham is

1/4 x 7 = 7/4 = 1.75

Total amount spent = amount spent on turkey + amount spent on ham

Total amount = 6 + 1.75

Total amount = $7.75

1. Write the equation of a line perpendicular to thex 5and that passes through thepoint (6,-4).line y

Answers

The line we want has a slope that is the negative reciprocal of the slope of the line

y = -(1/2)x - 5

The slope of this line is -1/2. So, the slope of its perpendicular lines is 2. Therefore, their equations have the form:

y = 2x + b

Now, to find b, we use the values of the coordinates of the point (6, -4) in that equation:

-4 = 2*6 + b

-4 = 12 + b

b = -4 - 12 = -16

Therefore, the equation is y = 2x - 16.

What is the y-intercept of the line x+2y=-14? (0,7) (-7,0) (0,-7) (2,14)

Answers

[tex]\begin{gathered} \text{First, we need to isolate y} \\ 2y=-x-14 \\ y=\frac{-x-14}{2} \\ y=\frac{-x}{2}-\frac{14}{2} \\ y=-\frac{x}{2}-7 \\ -7\text{ represents the y-intercept} \\ \text{When you write as a point it would be (0, -7)} \end{gathered}[/tex]

Other Questions
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