The Cp statistic is more useful than the Cpk statistic since it can better account for non-centered distributions.TrueFalse

Answer: 11.76

Step-by-step explanation:  you have to divide by 12 everything and multiply by 6 and you can get the answer

Answer:

[tex] v = \frac{1}{3} h\pi \: r { }^{2} \\ = \frac{1}{3} \times 3 \times \pi \times2 ^{2} \\ \frac{1}{3 } \times 3 \times \pi \times 4 \\ \frac{1}{3} \times 12\pi \\ 4\pi \: cm {}^{3} is \: the \: answer[/tex]

the answer is 4 pie cm cube

may I get branliest

Their net pay will be the same as their gross pay, and option (a) No federal income taxes are withheld is the correct answer.

Based on the given tax table, if a single person earns a gross biweekly salary of $780 and claims 6 exemptions, the federal income tax withheld is $0.

To determine the net payback of a person with a gross biweekly salary of $780 and 6 exemptions, we need to use the federal tax table.

Unfortunately, the table is not provided in the question, so we cannot determine the exact amount of federal income tax that will be withheld.

Assuming that the person is paid on a biweekly basis, their annual gross salary would be $20,280 ($780 x 26).

Using the 2021 federal tax tables for single filers, a person with an annual gross salary of $20,280 and 6 exemptions would have a federal income tax liability of $0.

Based on the information provided, it appears that the person's net pay would not change due to federal income tax withheld, as they would not owe any federal income taxes.

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Complete Question:

The following federal tax table is for biweekly earnings of a single person.

A 9-column table with 7 rows is shown. Column 1 is labeled If the wages are at least with entries 720, 740, 760, 780, 800, 820, 840. Column 2 is labeled But less than with entries 740, 760, 780, 800, 820, 840, 860. Column 3 is labeled And the number of withholding allowances is 0, the amount of income tax withheld is, with entries 80, 83, 86, 89, 92, 95, 98. Column 4 is labeled And the number of withholding allowances is 1, the amount of income tax withheld is, with entries 62, 65, 68, 71, 74, 77, 80. Column 5 is labeled And the number of withholding allowances is 2, the amount of income tax withheld is, with entries 44, 47, 50, 53, 56, 59, 62. Column 6 is labeled And the number of withholding allowances is 3, the amount of income tax withheld is, with entries 26, 28, 31, 34, 37, 40, 43. Column 7 is labeled And the number of withholding allowances is 4, the amount of income tax withheld is, with entries 14, 16, 18, 20, 22, 24, 26. Column 8 is labeled And the number of withholding allowances is 5, the amount of income tax withheld is, with entries 1, 3, 5, 7, 9, 11, 13. Column 9 is labeled And the number of withholding allowances is 6, the amount of income tax withheld is, with entries 0, 0, 0, 0, 0, 0, 1.

The following federal tax table is for biweekly earnings of a single person.

A single person earns a gross biweekly salary of $780 and claims 6 exemptions. How does their net pay change due to the federal income tax withheld?

a. No federal income taxes are withheld.

b. They will add $11 to their gross pay.

c. They will subtract $11 from their gross pay.

d. They will add $13 to their gross pay

Answer:

the correct answer is A!

Step-by-step explanation:

I just took the test and got 100%

The area of the darkest shaded region would be 31.32 yd sq.

We know that the circle is a shape consisting of all points in a plane that are given the same distance from a given point called the center.

The area of the circle =πr²

We are given that the radius of circle is 10 yd.

The area of the circle =πr²

= 10 x 10 π

= 100π

Now the area of the octagon will be;

282.84 yd sq.

Therefore, the area of the darkest shaded region is;

area of the circle - area of the octagon

= 100π - 282.84

= 31.32 yd sq.

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To determine which subsets are subspaces of either r3 or p3, we need to check if they satisfy the three conditions for being a subspace:

1. Closure under addition: For any two vectors in the subset, their sum is also in the subset.
2. Closure under scalar multiplication: For any vector in the subset and any scalar, their product is also in the subset.
3. Contains the zero vector: The subset contains the vector of all zeros.

a) The set of all polynomials of degree exactly 3: This subset is a subspace of p3 because it satisfies all three conditions. The sum of two degree-3 polynomials is also a degree-3 polynomial, and a scalar multiple of a degree-3 polynomial is still a degree-3 polynomial. The zero polynomial is also a degree-3 polynomial.

b) The set of all vectors in r3 whose coordinates add up to 0: This subset is a subspace of r3 because it also satisfies all three conditions. The sum of two vectors whose coordinates add up to 0 also has coordinates that add up to 0, and a scalar multiple of such a vector also has coordinates that add up to 0. The zero vector is also in this subset.

c) The set of all polynomials in p3 whose constant term is 1: This subset is not a subspace of p3 because it does not satisfy the closure under addition condition. The sum of two polynomials with constant term 1 may not have a constant term of 1, so it is not closed under addition.

d) The set of all polynomials in p3 whose coefficient of the x^2 term is 0: This subset is a subspace of p3 because it satisfies all three conditions. The sum of two polynomials with a coefficient of 0 for x^2 also has a coefficient of 0 for x^2, and a scalar multiple of such a polynomial also has a coefficient of 0 for x^2. The zero polynomial is also in this subset.

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The true statements regarding the slope will be:

Statement 2 is correct because the slope of PQ is (3-0)/(-1-0)=-3 and the slope of RS is (2-5)/(6-5)=-3, indicating that they have the same slope and are thus parallel.

Statement 3 is correct because the slope of QR is (3-0)/(-1-0)=-3 and the slope of PS is (2-5)/(6-5)=-3, indicating that they have the same slope and are thus parallel.

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Since d satisfies all three properties of an equivalence relation, we conclude that d is indeed an equivalence relation on Z.

To prove that d is an equivalence relation on Z, we need to show that it satisfies three properties: reflexivity, symmetry, and transitivity.

Reflexivity: For any m ∈ Z, we have [tex]m^2 - m^2[/tex] = 0, which is divisible by 3. Therefore, m is related to itself under d, so d is reflexive.

Symmetry: If m d n, then [tex]3 | (m^2 - n^2)[/tex]). This means that there exists an integer k such that [tex]m^2 - n^2 = 3k.[/tex]

Rearranging this equation, we get n^2 - m^2 = -3k, which implies that 3 divides (n^2 - m^2) as well. Therefore, n d m, and d is symmetric.

Transitivity: Suppose m d n and n d p. Then, we have [tex]3 | (m^2 - n^2)[/tex] and [tex]3 | (n^2 - p^2)[/tex].

Adding these two equations, we get   [tex]3 | ((m^2 - n^2) + (n^2 - p^2)),[/tex], which simplifies to [tex]3 | (m^2 - p^2).[/tex] Therefore, m d p, and d is transitive.

Since d satisfies all three properties of an equivalence relation, we conclude that d is indeed an equivalence relation on Z.

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In the right triangle JKL, the statement cosL = 24/25 is not true considering the right use of trigonometric ratios.

The trigonometric ratios is concerned with the relationship of an angle of a right-angled triangle to ratios of two side lengths.

The basic trigonometric ratios includes;

sine, cosine and tangent.

tanL = 24/7 {opposite/adjacent is a correct statement}

cosL = 24/25 {not a correct statement because cosL = 7/25, adjacent/hypotenuse}

tanJ = 7/24 {opposite/adjacent is a correct statement}

sinJ = 7/25 {opposite/hypotenuse is a correct statement}

Therefore, the statement cosL = 24/25 is not true considering the right use of trigonometric ratios.

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Answer:Domain is all real numbers

Step-by-step explanation:

f(x)=x^2

it is a parabola and all parabola’s domains are all real numbers

The Probability density Function of Z is given by:
[tex]f_Z(z)[/tex] = { 2z, 0 ≤ z ≤ 1   , 0  otherwise. }

To find the CDF of Z = |X - Y|, we need to consider two cases:
Case 1: z < 0

If z < 0, then P(Z < z) = 0 since Z is always non-negative.

Case 2: z ≥ 0
If z ≥ 0, then we can express the event {Z < z} in terms of X and Y as follows:
{Z < z} = {(X,Y) : |X - Y| < z}
This event corresponds to a square region in the unit square with vertices at (0,0), (1-z, z), (z,1-z), and (1,1).
The area of this square is [tex]1 - (1-z)^2 = 2z - z^2.[/tex]
Since X and Y are independent and uniformly distributed in [0,1], the joint PDF of (X,Y) is fXY(x,y) = 1 for 0 ≤ x,y ≤ 1, and zero elsewhere.

Therefore, the probability of the event {Z < z} is given by the double integral:

P(Z < z) = ∫[tex]\int {Z < z} f_{XY}(x,y) dxdy[/tex]

= ∫∫|x-y| < z 1 dxdy

[tex]= 2 \int z^0 y^z 1 dxdy[/tex]

= 2∫[tex]z^0[/tex](z-y) dy

= z^2.

Thus, the CDF of Z is given by:

FZ(z) = P(Z ≤ z)

= 0, if z < 0

= z², if 0 ≤ z ≤ 1

= 1, if z > 1.

To find the PDF of Z, we can differentiate the CDF:

fZ(z) = d/dz FZ(z)

= 2z, if 0 ≤ z ≤ 1

= 0, otherwise.

Therefore, the PDF of Z is given by:

[tex]f_Z(z)[/tex] = { 2z, 0 ≤ z ≤ 1

0, otherwise. }

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The correct relationship is n² = 2n.

To finish the combinatorial argument by completing Method 2, we should consider the following:

Method 2:
1. As you mentioned, there are n ways for Arshpreet and Meixuan to choose the same flavor.
2. If they pick different flavors, there are a total of n*(n-1)/2 unique combinations, since this accounts for all the possible flavor pairings without double-counting.

Now, let's combine both parts of Method 2:
Total ways = Ways of choosing the same flavor + Ways of choosing different flavors
Total ways = n + n*(n-1)/2

Since both methods should result in the same number of total ways to order ice cream, we set Method 1 equal to Method 2:

n² = n + n*(n-1)/2

By solving this equation, we can verify if the given partial combinatorial argument holds true:

n² = n + n*(n-1)/2
2n² = 2n + n*(n-1)
2n² = 2n + n² - n
n² = 2n

This result shows that the given partial combinatorial argument (n² = n + 2 - 1 (i – 1)) is incorrect, as the correct relationship is n² = 2n.

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Cohen's d is 0.44, which suggests a medium effect size

Null hypothesis: H0: µ = 4.5 and Alternative hypothesis: Ha: µ > 4.5 (one-tailed test)

The sample mean is M = 5.2 and the sample size is n = 31. The population standard deviation is unknown, so we use the t-distribution.

The standard error of the mean is:

[tex]SE=\frac{\sqrt{\frac{SS}{n-1} } }{\sqrt{n} } = \frac{\sqrt{\frac{-170}{30} } }{\sqrt{31} } = 0.328[/tex]

The t-statistic is:

[tex]t= (\frac{M-µ}{SE}) = (\frac{5.2-4.5}{0.328}) = 2.13[/tex]

Using a one-tailed t-test with a .01 level of significance and 30 degrees of freedom, the critical value is 2.756. Since the obtained t-value (2.13) is less than the critical t-value (2.756), we fail to reject the null hypothesis.

Since we failed to reject the null hypothesis, we cannot conclude that the medication significantly increased flexibility.

Cohen's d can be calculated as:

[tex]d= \frac{(M-µ}{SD} = \frac{5.2-4.5}{\sqrt{\frac{SS}{n-1} } } = \frac{0.84}{1.9} = 0.44[/tex]

Therefore, Cohen's d is 0.44, which suggests a medium effect size.

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The formula for the height above the ground, h(t) is h(t) = 255 sin (π/20 t) + 20.

The amplitude is half the distance between the highest and lowest points, which is (530 - 20)/2 = 255 feet. So A = 255.

The period is 40 minutes, so B = 2π/40 = π/20.

At t = 0 (when we board the Ferris Wheel), we are 20 feet above the ground.

This means there is no phase shift, so C = 0.

The vertical shift is also 20 feet, so D = 20.

Putting it all together, we have:

h(t) = 255 sin (π/20 t) + 20

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Answer:

Sarah receives $2.48 from the cashier

Step-by-step explanation:

Cost of the scooter = $67.52

Money paid by Sarah to the cashier = $70

Sarah receives money = money paid by Sarah - the cost of the scooter

                                      = $70 - $67.52

                                      = $2.48

Sarah receives $2.48 from the cashier.

The experimental probability of the name Grace being​ chosen = 11/108

The theoretical probability of the name Grace being​ chosen = 1/6

We know that formula for the experimental probability of event A is :

P(A) = (Number of occurance of event A) / (Total number of trials)

Here, a name is chosen 108 times and the name Grace is chosen 11 times.

Let event A: the name Grace being​ chosen

the number of occurance of event A = 11

And the Total number of trials = 108

Using above formula the experimental probability would be,

P(A) = 11/108

Here, six different names were put into a hat.

This means that the number of possible outcomes n(S) = 6

And n(A) = 1

So, the theoretical probability would be,

P = n(A)/n(S)

P = 1/6

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The volume enclosed by the torus rho=4sin(φ) for cylindrical or spherical coordinates is V = 32[tex]\pi^{2/3}[/tex].

We can use cylindrical coordinates to find the volume enclosed by the torus.

The torus can be defined in cylindrical coordinates as:

ρ = 4sin(φ)

where ρ is the distance from the origin to a point in the torus, and φ is the angle between the positive z-axis and the line connecting the origin to the point.

To find the volume enclosed by the torus, we integrate over ρ, φ, and z. The limits of integration for ρ and φ are 0 to 4 and 0 to 2π, respectively, since the torus extends from the origin to a maximum distance of 4 and wraps around the z-axis.

For z, we integrate from -√(16-ρ²) to √(16-ρ²), which represents the range of z values that lie on the surface of the torus at a given value of ρ and φ.

The integral for the volume of the torus is:

V = ∫∫∫ ρ dz dφ dρ

where the limits of integration are:

0 ≤ ρ ≤ 4

0 ≤ φ ≤ 2π

-√(16-ρ²) ≤ z ≤ √(16-ρ²)

Evaluating this integral gives the volume of the torus as:

V = 32[tex]\pi^{2/3}[/tex]

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If sales are expressed as a function of the amount spent on advertising, then the dollar amount at which the rate of change of sales goes from increasing to decreasing is called the point of diminishing returns or diminishers returns to scale.

It sounds like you want to know about the relationship between sales, advertising, and the rate of change. Here's an answer incorporating the terms you've mentioned:

If sales are expressed as a function of the amount spent on advertising, the dollar amount at which the rate of change of sales goes from increasing to decreasing is called the inflection point. If 'x' is that dollar amount, then 'x' represents the advertising budget at which the sales growth rate starts to decline.

This point indicates that increasing the amount spent on advertising beyond this dollar amount will result in a decrease in the rate of change of sales. This is known as the diminishers' scale to return.

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Range of the data is 19 and Standard deviation is 10.12

The range of a set of data is the difference between the max and min values, and the standard deviation of the data is the square root of its variance.

The range is the difference between the lowest and highest values in a given set. The Standard Deviation is the square root of the variance.

The data set is :

141, 116, 117, 135, 126, 121

The mean of a set of numbers is the sum divided by the number of terms.

x' = (141 + 116 + 117+ 135 + 126 + 121)/6

x' = 756/6

x' = 126

Now, We have to find the standard deviation of the data set:

[tex]\sigma = \sqrt{\frac{(x-x')^2}{n-1} }[/tex]

Substituting the values

[tex]\sigma=[/tex] (16 √10) /5

= 10.12

Range of the data = Max value - Min value

Range of the data = 19

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Answer:

To draw the missing sides of the trapezoid so that the midsegment has a length of 9 units, you can follow these steps:

Plot the given base segment connecting points (-1,5) and (5,5) on a coordinate plane.

Find the midpoint of the given base segment using the midpoint formula: Midpoint = ((x1 + x2)/2, (y1 + y2)/2), where (x1, y1) and (x2, y2) are the coordinates of the endpoints of the given base segment.

Plot the midpoint found in step 2 on the coordinate plane as the midpoint of the midsegment. Label it.

Draw two perpendicular lines from the midpoint found in step 2, each extending towards the other base of the trapezoid.

The intersection points of the perpendicular lines with the other base of the trapezoid will be the vertices of the missing sides.

Connect the vertices of the missing sides with the endpoints of the given base segment to complete the trapezoid.

Note: The specific length and orientation of the missing sides will depend on the location of the midpoint and the given base segment. There can be multiple valid trapezoids with a midsegment of length 9 units that connect the given bases at the midpoint.

Step-by-step explanation:

The lengths of sides of the unknown are:

The value of x can be obtain as follow:

Sine θ = opposite / hypotenuse

Sine 30 = 29.5 / x

Cross multiply

x × sine 30 = 29.5

Divide both sides by sine 30

x = 29.5 / sine 30

Value of x = 59

The value of y can be obtain as follow:

Tan θ = opposite / adjacent

Tan 30 = 29.5 / y

Cross multiply

y × Tan 30 = 29.5

Divide both sides by Tan 30

y = 29.5 / Tan 30

y = 29.5 ÷ 1/√3

y = 29.5 × √3

Value of y = 29.5√3

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The value of surface area is,

SA = 570 cm²

Given that;

Base of house = 6 cm

And, Height of house = 19 cm

Since, The shape of house is like a prism.

We know that;

Area of Prism is,

SA = 2B + ph,

where B, stands for the area of the base, p represents the perimeter of the base, and h stands for the height of the prism.

Hence, We get;

SA = 2 × (1/2 x 6 × 19) + 2 (6 + 6) × 19

SA = 114 + 456

SA = 570 cm²

Hence, The value of surface area is,

SA = 570 cm²

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The condition that must be imposed on k1 and k2 so that 22 6. +2,02 is an unbiased estimator of θ.

To prove that 22 6. +2,02 is an unbiased estimator of the parameter θ, we need to show that its expected value is equal to θ, i.e.,

E(22 6. +2,02) = θ.

Using the linearity of the expected value operator, we have:

E(22 6. +2,02) = E(k1Ô1 + k2Ô2)

= k1E(Ô1) + k2E(Ô2)

Since both Ô1 and Ô2 are unbiased estimators of θ, we have:

E(Ô1) = E(Ô2) = θ

Substituting these values in the above equation, we get:

E(22 6. +2,02) = k1θ + k2θ

= (k1 + k2)θ

For 22 6. +2,02 to be an unbiased estimator of θ, the above expression should be equal to θ. Therefore, we must have:

(k1 + k2) = 1

This implies that the constants k1 and k2 must satisfy the constraint:

k1 + k2 = 1

Hence, this is the condition that must be imposed on k1 and k2 so that 22 6. +2,02 is an unbiased estimator of θ.

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The better deal is given by the equation A = 18 ounces for 6.60

Given data ,

Let the equation be represented as A

Now , For 18 oz for $6.60

Price per ounce = Total cost / Total ounces = $6.60 / 18 oz ≈ $0.3667 per oz

And , for 12 oz for $4.75

Price per ounce = Total cost / Total ounces = $4.75 / 12 oz ≈ $0.3958 per oz

Comparing the two price per ounce values, we can see that the price per ounce for 18 oz for $6.60 is lower than the price per ounce for 12 oz for $4.75

Hence , the better deal is 18 oz for $6.60

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Based on the information, csc(0) - sin(0) = cot(0) cos(0) is a valid identity.

lim x→0+ csc(x) = ∞

lim x→0- csc(x) = -∞

Recall that cot(0) is undefined, as the cotangent function has a vertical asymptote at x=0. However, we can still simplify the expression by using the limit definition of the cotangent function as x approaches 0:

lim x→0+ cot(x) = ∞

lim x→0- cot(x) = -∞

Since both sides simplify to ∞, we can say that the identity holds.

Therefore, csc(0) - sin(0) = cot(0) cos(0) is a valid identity.

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The 2-D shape used here is a right triangle. When rotated about the axis, this becomes a cone which is 3-D. See the attached.

In mathematics, rotation is a notion that originated in geometry. Any rotation is a movement of a specific space that retains at least one point.

A rotation differs from the following motions: translations, which have no fixed points, and (hyperplane) reflections, which each have a full (n 1)-dimensional flat of fixed points in an n-dimensional space.

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(a) The multiplicative inverse of 36 mod 45 is 4.

(b) The multiplicative inverse of 22 mod 35 is 4.

(c) The multiplicative inverse of 158 mod 331 is 201.

(d) The multiplicative inverse of 331 mod 158 is 119.

To find the multiplicative inverse of a number, we use the following formula:

[tex]a^-1 ≡ b (mod n)[/tex]

Where a is the number whose inverse is to be found, b is the multiplicative inverse of a and n is the modulus.

In this case, we have:

[tex]36^-1[/tex] ≡ b (mod 45) = 4

The multiplicative inverse of 22 mod 35 is 4. To find the multiplicative inverse of a number, we use the formula a * x ≡ 1 mod m where a is the number whose inverse we want to find, x is the inverse of a and m is the modulus.

We can solve this equation using the extended Euclidean algorithm1.

In this case, we have 22 * x ≡ 1 mod 35. Using the extended Euclidean algorithm, we can find that x = 41.

Therefore, the multiplicative inverse of 22 mod 35 is 4.

The multiplicative inverse of 158 mod 331 is 201. The modular multiplicative inverse of an integer a modulo m is an integer b such that the product ab is congruent to 1 with respect to the modulus m 1.

The multiplicative inverse of 331 mod 158 is 119.

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(a) The multiplicative inverse of 36 mod 45 is 4.

(b) The multiplicative inverse of 22 mod 35 is 4.

(c) The multiplicative inverse of 158 mod 331 is 201.

(d) The multiplicative inverse of 331 mod 158 is 119.

How to find the multiplicative inverse?

To find the multiplicative inverse of a number, we use the following formula:

a⁻¹  = b (mod n)

Where a is the number whose inverse is to be found, b is the multiplicative inverse of a and n is the modulus.

a) In this case, we have:

36⁻¹ ≡ b (mod 45) = 4

b) The multiplicative inverse of 22 mod 35 is 4.

To find the multiplicative inverse of a number, we use the formula

a * x ≡ 1 mod m

where a is the number whose inverse we want to find, x is the inverse of a and m is the modulus.

We can solve this equation using the extended Euclidean algorithm1.

In this case, we have 22 * x ≡ 1 mod 35. Using the extended Euclidean algorithm, we can find that x = 41.

Therefore, the multiplicative inverse of 22 mod 35 is 4.

c) The multiplicative inverse of 158 mod 331 is 201.

The modular multiplicative inverse of an integer a modulo m is an integer b such that the product ab is congruent to 1 with respect to the modulus m 1.

d) The multiplicative inverse of 331 mod 158 is 119.

hence, (a) The multiplicative inverse of 36 mod 45 is 4.

(b) The multiplicative inverse of 22 mod 35 is 4.

(c) The multiplicative inverse of 158 mod 331 is 201.

(d) The multiplicative inverse of 331 mod 158 is 119.

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The area of the given rectangle is 322 square miles.

We know that the area of a rectangle is equal to the product between the dimensions. In this case we know that the dimensions of the rectangle are:

Length  = 23 miles.

Width = 14 miles.

Then the area of this rectangle will be a product between these two values, we will get:

Area = (23 mi)*(14 mi)

Area = 322 mi ²

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There are 84 different ways to seat three adults and three children at a circular table such that each child must be next to two adults.

To seat three adults and three children at a circular table such that each child must be next to two adults, we can use the following steps:

There are 2! options for the other two adults and 3! options for children.

The number of ways for two adults and children:

= 2! × 3!

= 2 × 6

= 12 ways to seat them

There are 3 ways to pick the two children, two ways to seat them, and two ways for them to begin the circle, for a total of six options.

The third child has a pair of choices:

6 × 2 so far

Then, there are 3! =6  ways to seat the adults.

6 × 2 × 6 = 72 ways

Putting it all together, the total number of seating arrangements is:

12+72 = 84 ways  

Therefore, there are 84 different ways to seat three adults and three children at a circular table such that each child must be next to two adults.

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One man alone can finish the work in about 1.26 days, and one boy alone can finish the work in about 33.33 days.

Let the work be "1" unit, and let the rate of work of one man be "m" and that of one boy be "b". Then we can set up the following system of equations based on the given information:

8m + 12b = 1/10 (equation 1)

6m + 8b = 1/14 (equation 2)

We have two equations and two unknowns, so we can solve for "m" and "b". First, we'll simplify the equations by multiplying both sides of each equation by the least common multiple of the denominators (10*14 = 140):

112m + 168b = 14 (equation 1, multiplied by 140)

84m + 112b = 10 (equation 2, multiplied by 140)

Now we can solve this system of linear equations using either substitution or elimination. Let's use elimination by multiplying equation 2 by -12 and adding it to equation 1:

112m + 168b = 14

-84m - 112b = -120

28m + 56b = -106

Simplifying, we get:

7m + 14b = -53/2 (equation 3)

Now we can solve for "m" or "b" by using either equation 2 or equation 3. Let's use equation 3:

7m + 14b = -53/2

14m + 28b = -53

7m + 14b = -53/2

Subtracting the bottom equation from the top equation, we get:

-7m - 14b = 53/2

Multiplying both sides by -1, we get:

7m + 14b = 53/2

Adding this equation to equation 3, we get:

21m = -53/2

Solving for "m", we get:

m = -53/42 = -1.26 (rounded to two decimal places)

Now we can use equation 2 to solve for "b":

6m + 8b = 1/1

Substituting "-1.26" for "m", we get:

6(-1.26) + 8b = 1/14

Simplifying and solving for "b", we get:

b = 1/14 - (-7.56)/8 = 0.03 (rounded to two decimal places)

Therefore, one man alone can finish the work in about 1.26 days, and one boy alone can finish the work in about 33.33 days.

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A sample of at least 782 children under age 6 living in West Virginia is needed to estimate the true proportion of children under age 6 living in poverty in West Virginia within 2% with 90% confidence.

We can use the formula:

n = (z^2 * p * q) / E^2

where:

z = z-score for the desired level of confidence (90% confidence corresponds to a z-score of 1.645)

p = estimated proportion (0.30 based on the federal report)

q = 1 - p

E = margin of error (0.02)

Substituting the values, we get:

n = (1.645^2 * 0.30 * 0.70) / 0.02^2 = 781.96

Rounding up to the nearest whole number, we get a sample size of 782. Therefore, a sample of at least 782 children under age 6 living in West Virginia is needed to estimate the true proportion of children under age 6 living in poverty in West Virginia within 2% with 90% confidence.

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