The listed occupations of stockholders of a national computer company included 9% who were housewives. If six of these stockholders are randomly selected, what is the probability that none are housewives?

Answers

Answer 1

Answer:

no se la respuesta

Step-by-step explanation:

no se la respuesta

Answer 2

The probability that none of the six selected stockholders are housewives is,

⇒ 56.8%

The term probability refers to the likelihood of an event occurring. Probability means possibility.

The probability of an event occurring can be calculated by subtracting the probability of the event not occurring from 1.

Given that,

The listed occupations of stockholders of a national computer company included 9% who were housewives.

Since 9% of the stockholders are housewives.

Hence, the probability that a randomly selected stockholder is not a housewife is,

= [tex]1 - 9%[/tex]%

= [tex]1 - 0.09[/tex]

= [tex]0.91[/tex]

So, The probability that none of the six selected stockholders are housewives is,

⇒ [tex](0.91)^6[/tex]

⇒ [tex]0.5678[/tex]

Learn more about the probability visit:

https://brainly.com/question/13604758

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