the masses of species involved are given in atomic mass units below each species, and 1 amu can create 932 mev of energy. what is the energy liberated due to transfomration of mass into energy during this reaction

Answers

Answer 1

Given that the masses of species involved are given in atomic mass units below each species, and 1 amu can create 932 meV of energy. Therefore, the energy liberated due to the transformation of mass into energy during this reaction is 1285.44 MeV.

The energy liberated due to the transformation of mass into energy during this reaction can be found by using the following formula: E = (Δm)c² Where E = Energy liberated during the transformation of mass into energy.

Δm = Change in mass during the transformation.

c = Speed of light in a vacuum (3.0 x 10⁸ m/s)

Given that, the masses of species involved are given in atomic mass units below each species, and 1 amu can create 932 meV of energy.

Therefore, first find the mass difference between the reactant and product as shown below: N + O → P + Q

Species Mass N 14 amu

O 16 amu

P 16 amu

Q 14 amu

Total 60 amu

Mass of reactants = 14 + 16 = 30 amu

Mass of products = 16 + 14 = 30 amu

Δm = (Mass of reactants - Mass of products)Δm = 30 - 30Δm = 0amu

Now, calculate the energy liberated as follows: E = (Δm)c²E = 0 x (3 x 10⁸)²E = 0 x 9 x 10¹⁶E = 0 MeV

Therefore, the energy liberated during the transformation of mass into energy is 0 MeV, which indicates that the reaction is not exothermic or endothermic.

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Related Questions

Which sentence is true about flammable materials? Flammable materials:
OSSIBLE ANSWERS
O Are divided into Class II or III liquids.
O Have a higher flash point than combustibles.
O Will ignite at or above 140° F (60° C).
O Have a lower flash point than combustibles.

Answers

The sentence that is true about flammable materials is: option d.

have a lower flash point than combustibles.

What is combustion?

Combustion is a chemical reaction that occurs between a fuel and an oxidizing agent, usually oxygen, in which energy in the form of heat and light is released. During combustion, the fuel undergoes a chemical reaction with oxygen, resulting in the production of new compounds such as carbon dioxide, water vapor, and other combustion by-products. This process is also commonly referred to as burning and is essential to many forms of energy production, such as in the combustion of fossil fuels in power plants and the combustion of gasoline in internal combustion engines.

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Can anyone help me answer these 2 questions ?

Answers

Answer:

1. is "It produces sodium carbonate, a bitter metallic-tasting compound."
2. is 6:1

Explanation:

1. While baking powder does produce sodium bicarbonate or at least plays a part in creating sodium bicarbonate, its alkaline nature allows the dish or the reaction to avoid tasting metallic.

2. 6:1 because logically the more water there is in the flour, the less viscous it would be.

(c) The student finds that 21.50 cm³ of hydrochloric acid is needed to neutralise 25.0 cm³ of sodiu
hydroxide solution.
(i) Describe what the student should do next to prepare a pure solution of sodium chloride.

Answers

Answer:

After neutralizing the sodium hydroxide solution with hydrochloric acid, the student should remove any excess hydrochloric acid and water from the solution to obtain a pure solution of sodium chloride. This can be done by a process called evaporation or by using a separating funnel.

To prepare a pure solution of sodium chloride, the student should follow the steps below:

Transfer the neutralized solution of sodium chloride into an evaporating dish.

Heat the evaporating dish over a low flame, stirring continuously until all the water evaporates.

Once all the water has evaporated, the student will be left with a dry residue of sodium chloride in the evaporating dish.

The sodium chloride can then be transferred to a clean, dry container and stored for use.

Alternatively, the student can use a separating funnel to remove excess hydrochloric acid and water from the solution. In this case, the neutralized solution is transferred to a separating funnel, and an equal volume of water is added. The funnel is then shaken, and the two layers are allowed to separate. The bottom layer containing the excess hydrochloric acid is drained off, leaving behind a pure solution of sodium chloride.

Explanation:

To earn full credit for your answers, you must show the appropriate formula, the correct substitutions , and your answer including the correct units

One hundred and forty-eight hawks are living on a prairie that is twenty-two square kilometers in size. What is the population density of the hawks?

Answers

The population density of the hawks is 6.73 hawks/sq. km.

What is the population density?

Population density is defined as the number of individuals of a species per unit area.

Population density = Number of individuals / Area

In this problem, we are given:

Number of individuals = 148 hawksArea = 22 square kilometers

Substituting these values in the formula, we get:

Population density = 148 hawks / 22 sq. km

Simplifying this expression, we get:

Population density = 6.73 hawks/sq. km

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Which of these is an element?
A. KBr
B. 02
C. 2KCI
D. Fe 02

Answers

Answer:

B

Explanation:

because it's an element

The particles in.......... can be separated from
heterogeneous mixtures by passing the mixture through a filter.
-suspension
-solution
-colloid
-pure substance

Answers

The particles in a suspension can be separated from heterogeneous mixtures by passing the mixture through a filter.

What is a suspension?

Suspensions are heterogeneous mixtures that contain particles of a larger size that are suspended in a liquid medium. These particles are large enough to be visible to the ordinary eye and can be separated from the mixture through the use of a filter.

When a suspension is passed through a filter, the particles in the mixture are trapped in the filter medium, and the liquid passes through, leaving the solid particles behind.

This is due to the physical properties of the particles in suspension, which are large enough to be filtered out. In contrast, the particles in solutions and colloids are much smaller, and cannot be separated through filtration.

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What is the molarity of a KCl solution if there are 59.0 grams of KCl dissolved in water to make 2.0 liters of solution?

Answers

Answer:0.40 M

Explanation:

M = moles/L

moles = 59.0 / 74( molar mass from the Periodic table for KCl) =0.797 moles

M=0.797/2 = 0.3986 = 0.40 M

What is ionization energy?

Answers

Answer:

b) The amount of energy required to eject an electron from an atom.

ionization energy is the quantity of energy that an isolated, gaseous atom in the ground electronic state must absorb to discharge an electron, resulting in a cation. H(g)→H+(g)+e− This energy is usually expressed in kJ/mol, or the amount of energy it takes for all the atoms in a mole to lose one electron each.

Propylene glycol, C3H6(OH)2, is sometimes used in automobile antifreeze solutions. If an aqueous solution has
a mole fraction XC₂H(OH)₂ = 0.100, calculate (a) the percent propylene glycol by mass; (b) the molality of the
propylene glycol in the solution.

Answers

Molality is 10.8m, Freezing point is -09.8c ,Certain pharmaceuticals, cosmetics, or food products use it to preserve moisture by absorbing more water.

Can propylene glycol hurt people?

The U.S. Food and Drug Administration (FDA) has deemed propylene glycol to be "generally regarded as safe," and it believes a daily food intake of 23 mg/kg of body weight to be safe for people ages 2-65. Propylene glycol can be found in a variety of foods, cosmetics, and medication.

Is propylene glycol skin-safe?

A humectant is a substance that is added to cosmetics to promote the retention of moisture in the skin and hair. Propylene glycol falls under this category. Propylene glycol is well accepted by skin and shouldn't irritate or produce redness.

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Example: Ba8Mu7
Beanium shroomium
Beanium shroomide
Octabeanium heptashroomide
Name these Covalent Compounds using the “Periodic Table of Food”:
7. PeMu2
8. BaPo5
9. SpMu
10. Br2E7
11. Br3Pe
12. PeE4

Answers

Answer:

Here are the answers:

7. phosphorus molybdenum diboride

8. barium phosphite

9.  sulfur molybdenum

10.  dibromine heptoxide

11.   tribromine phosphide

12.  phosphorus tetrasulfide

Calculate the pH of a solution prepared by dissolving 1. 60 g of sodium acetate, CH3COONa, in 92. 00 mL of 0. 10 M acetic acid, CH3COOH(aq). Assume the volume change upon dissolving the sodium acetate is negligible. Ka of CH3COOH is 1. 75 x 10^-5. ​

Answers

The solution's pH value is 5.08.

To solve this problem, we need to use the principles of acid-base chemistry and the equilibrium constant expression for the dissociation of acetic acid (CH₃COOH) to its conjugate base, acetate (CH₃COO⁻).

First, we need to calculate the concentration of acetic acid in the solution. Since the initial concentration of acetic acid is given as 0.10 M and the volume of the solution is 92.00 mL, we can calculate the number of moles of acetic acid as follows:

moles of acetic acid = 0.10 M x 0.0920 L = 0.00920 moles

Next, we need to calculate the number of moles of sodium acetate in the solution. The molar mass of sodium acetate is 82.03 g/mol, so we can convert the mass of sodium acetate to moles as follows:

moles of sodium acetate = 1.60 g / 82.03 g/mol = 0.0195 moles

Since sodium acetate dissociates completely in water to produce acetate ions and sodium ions, the concentration of acetate ions in the solution is equal to the number of moles of sodium acetate divided by the total volume of the solution:

acetate ion concentration = moles of sodium acetate / total volume of solution

acetate ion concentration = 0.0195 moles / 0.0920 L = 0.212 M

Now we can use the equilibrium constant expression for the dissociation of acetic acid to calculate the pH of the solution:

Ka = [H⁺][CH₃COO-]/[CH₃COOH]

Since we are assuming that the concentration of acetic acid is still 0.10 M, and we now know that the concentration of acetate ions is 0.212 M, we can rearrange the equation and solve for [H⁺]:

[H⁺] = (Ka x [CH₃COOH])/[CH₃COO-]

[H⁺] = (1.75 x 10⁻⁵ x 0.10)/0.212

[H⁺] = 8.23 x 10⁻⁶ M

Finally, we can calculate the pH of the solution using the equation:

pH = -log[H⁺]

pH = -log(8.23 x 10⁻⁶)

pH = 5.08

Therefore, the pH of the solution is 5.08.

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In a terrarium, the pincushion moss, the echeveria, and the moon cactus make up which of the following? A population community or ecosystem

Answers

Answer: The pincushion moss, the echeveria, and the moon cactus in a terrarium make up a community.

:)

I think this is the answer btw Sorry if i'm wrong I have no clue.

In a terrarium, the pincushion moss, the echeveria, and the moon cactus make up the community.

Moon cactus, also known as Gymnocalycium mihanovichii or Hibotan cactus, is native to South American deserts in places like Brazil and Argentina.

Leucobryum glaucum, commonly known as leucobryum moss or pin cushion moss, is a species of haplolepideous mosses with a wide distribution in eastern North America and Europe.

Echeveria is a large genus of flowering plants in the family Crassulaceae, native to semi-desert areas of Central America, Mexico and northwestern South America.

Therefore, In a terrarium, the pincushion moss, the echeveria, and the moon cactus make up the community.

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Identify the limiting reactant when 45.25 grams of nitrogen react with 52.5 liters of hydrogen at standard temperature and pressure to produce ammonia gas (NH3), which is used as a popular refrigerant. How many liters of ammonia is actually produced?

Answers

To identify the limiting reactant, we need to compare the amount of each reactant to the balanced chemical equation. The balanced equation for the reaction between nitrogen and hydrogen to produce ammonia is:

N2 + 3H2 → 2NH3

From the equation, we can see that one mole of nitrogen reacts with three moles of hydrogen to produce two moles of ammonia.

First, let's convert the mass of nitrogen to moles:

45.25 g N2 x (1 mol N2/28.02 g N2) = 1.612 mol N2

Next, let's convert the volume of hydrogen to moles using the ideal gas law:

PV = nRT

n = PV/RT

n = (52.5 L) (1 atm) / (0.0821 L·atm/mol·K) (273 K) = 2.19 mol H2

How many liters of ammonia is actually produced?

Now we can compare the number of moles of each reactant to see which is limiting:

N2 : H2 = 1.612 mol : 2.19 mol

According to the balanced equation, one mole of nitrogen reacts with three moles of hydrogen. So we need 4.836 moles of hydrogen to completely react with 1.612 moles of nitrogen. However, we only have 2.19 moles of hydrogen, which means it is the limiting reactant.

Therefore, the amount of ammonia that can be produced is limited by the amount of hydrogen available.

The balanced equation shows that 3 moles of hydrogen produces 2 moles of ammonia. So, with 2.19 moles of hydrogen, we can produce:

2.19 mol H2 x (2 mol NH3/3 mol H2) = 1.46 mol NH3

Now, let's convert the moles of ammonia to liters using the ideal gas law:

PV = nRT

V = nRT/P

V = (1.46 mol) (0.0821 L·atm/mol·K) (273 K) / (1 atm) = 31.2 L

Therefore, 31.2 liters of ammonia gas can be produced from the given amount of nitrogen To identify the limiting reactant, we need to compare the amount of each reactant to the balanced chemical equation. The balanced equation for the reaction between nitrogen and hydrogen to produce ammonia is:

N2 + 3H2 → 2NH3

From the equation, we can see that one mole of nitrogen reacts with three moles of hydrogen to produce two moles of ammonia.

First, let's convert the mass of nitrogen to moles:

45.25 g N2 x (1 mol N2/28.02 g N2) = 1.612 mol N2

Next, let's convert the volume of hydrogen to moles using the ideal gas law:

PV = nRT

n = PV/RT

n = (52.5 L) (1 atm) / (0.0821 L·atm/mol·K) (273 K) = 2.19 mol H2

Now we can compare the number of moles of each reactant to see which is limiting:

N2 : H2 = 1.612 mol : 2.19 mol

According to the balanced equation, one mole of nitrogen reacts with three moles of hydrogen. So we need 4.836 moles of hydrogen to completely react with 1.612 moles of nitrogen. However, we only have 2.19 moles of hydrogen, which means it is the limiting reactant.

Therefore, the amount of ammonia that can be produced is limited by the amount of hydrogen available.

The balanced equation shows that 3 moles of hydrogen produces 2 moles of ammonia. So, with 2.19 moles of hydrogen, we can produce:

2.19 mol H2 x (2 mol NH3/3 mol H2) = 1.46 mol NH3

Now, let's convert the moles of ammonia to liters using the ideal gas law:

PV = nRT

V = nRT/P

V = (1.46 mol) (0.0821 L·atm/mol·K) (273 K) / (1 atm) = 31.2 L

Therefore, 31.2 liters of ammonia gas can be produced from the given amount of nitrogen and hydrogen.

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Look at your parts per million (ppm) calculations in the lab worksheet. What did you find the alkalinity to be for the 3rd sample (from Lake Ray Roberts) in parts per million? 220 ppm 540 ppm 260 ppm
PLEASE answer fast

Answers

Look at your parts per million (ppm) calculations in the lab worksheet. What did you find the alkalinity to be for the 3rd sample (from Lake Ray Roberts) in parts per million? 220 ppm 540 ppm 260 ppm

The alkalinity for the 3rd sample from Lake Ray Roberts was 260 ppm.

Alkalinity is a measure of the capacity of water to neutralize acids, which is a property of water that helps to maintain a stable pH. It is a measure of the concentration of various ions in the water that can react with hydrogen ions (H+) to prevent a drop in pH.

In other words, alkalinity is the ability of water to resist changes in pH when an acid is added to it. It is usually expressed in terms of milligrams per liter (mg/L) of calcium carbonate (CaCO3) or parts per million (ppm) of CaCO3 equivalents.

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Correct answer should be

Look at your parts per million (ppm) calculations in the lab worksheet. what did you find the alkalinity to be for the 3rd sample (from lake ray roberts) in parts per million?

question 5 options:

540 ppm

220 ppm

260 ppm

A1 L sample from Tempe Town lake has a pH of 3. 57. Exhaust from cars on nearby highways

often mixes with rain to form HNO3. Use this information to answer the following questions.

1. What is the concentration of H+ ions in the sample?

2. If it took 80 ml of 1 M NaOH to neutralize 250 ml of the acidic solution, what is the

molarity of HNO3 in the sample?

3. How many moles of HNO3 are in the

solution?

Answers

Answer:

see explanations

Explanation:

1. pH = -log [H+]

so [H+] = 10^(-pH) = 10^(-3.57) = 2.7 x 10^(-4) M

2. neutralize implies mol acid = mol base

so [HNO3] = (1 M) * (0.080 L) / (0.250 L) = 0.32 M HNO3

3. mol HNO3 = molarity of HNO3 * volume of HNO3

= 0.32 M HNO3 * 0.250 L HNO3 = 0.080 mol HNO3

Calculate each of the following quantities.


(a) Total number of ions in 47. 8 g of SrF2

(b) Mass (kg) of 4. 90 mol of CuCl2 · 2 H2O

(c) Mass (mg) of 2. 67 1022 formula units of Bi(NO3)3 · 5 H2O

Answers

a.  Total number of ions in 47. 8 g of SrF2 = 1.635 ions.

b.  Mass (kg) of 4. 90 mol of CuCl2 · 2 H2O = 0.833 kg

c.  Mass (mg) of 2. 67 1022 units of Bi(NO3)3 · 5 H2O = 21,700 mg

a. Total number of ions in 47. 8 g of SrF2

The molar mass of SrF2 per gram = 87.62 g/mol

The number of moles of SrF2 in 47.8 g is calculated by using the formula,

The number of moles = n = (m/M) = 47.8 g / 87.62 g/mol

The number of moles  = 0.545 mol

Total number of ions present in the molecule SrF2 = (1 Sr2+ ion/mol) x (0.545 mol) + (2 F- ions/mol) x (0.545 mol)

The Total number of ions = 0.545 + 2(0.545)

The total number of ions = 1.635 ions.

b. Mass (kg) of 4. 90 mol of CuCl2 · 2 H2O

Total number of ions in CuCl2 · 2 H2O = (63.55 g/mol Cu + 2 x 35.45 g/mol Cl + 2 x 18.02 g/mol H + 16.00 g/mol O) + 2 x 18.02 g/mol H + 2 x 16.00 g/mol O

Total number of ions = 170.48 g/mol

The mass of 4.90 mol of CuCl2 · 2 H2O is:

Molar mass (m) = nM = 4.90 mol x 170.48 g/mol

Molar mass (m)  = 833.8 g = 0.833 kg

c.  Mass (mg) of 2.67 10^22 units of Bi(NO3)3 · 5 H2O

Total number of ions in Bi(NO3)3 · 5 H2O = (208.98 g/mol Bi + 3 x 62.01 g/mol N + 9 x 16.00 g/mol O) + 5 x 18.02 g/mol H + 5 x 16.00 g/mol O

Total number of ions = 485.09 g/mo

Total number of moles (n) = N/NA = (2.67 × 10^22)/6.022 × 10^23

Total number of moles = 0.0444 mol

The mass of 0.0444 mol of Bi(NO3)3 · 5 H2O is:

Molar mass (m) = nM = 0.0444 mol x 485.09 g/mol

Molar mass = 21.7 g =  21,700 mg

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YOU DO:
1) Hydrogen and iodine gases where placed into a 1.00 liter container, and allowed to reach equilibrium at
time = 2. The reaction is: H₂(g) + 12 (8) = 2 HI (8)
Time = 2
Time = 3
Time=0
Time = 1
A) Complete the box for time = 1, when one of the H₂ has reacted.
B) Complete the box for time = 3, after the reaction has reached equilibrium.
C) Between time = 1 and time = 2, which reaction is favored, the forwards or reverse reaction?

Answers

At time = 1, one of the H₂ molecules has reacted, producing one molecule of HI. This means that there are now 0.5 moles of H₂, 0.5 moles of I₂, and 1 mole of HI in the container.

What does B indicates?

At time = 3, the reaction has reached equilibrium. This means that the concentrations of all three gases have stabilized. Without additional information about the reaction conditions and equilibrium constants, we cannot determine the exact concentrations of each gas at equilibrium.

What does C indicates?

Between time = 1 and time = 2, the forwards reaction (H₂ + I₂ → 2HI) is favored because one of the H₂ molecules has reacted to produce HI. This means that the concentration of H₂ has decreased while the concentration of HI has increased, driving the reaction forwards according to Le Chatelier's principle.

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chemistry help please

Answers

Answer:

the right answer is first one

What is the volume in liters of a solution that contains 3.70 moles MgCl2 in a 4.0 M MgCl2 solution?

Answers

Answer: 0.925 L

Explanation:

M=moles /L

L= moles/M

3.70/4 = 0.925 L

Why the flask must be sealed with the stopper while the reaction takes place, please answer ​

Answers

Sealing the flask with the stopper is an important step in conducting a controlled and accurate experiment. Without it, the reaction may be affected by outside factors and the results may be inaccurate or inconsistent.

The flask must be sealed with the stopper while the reaction takes place to prevent any outside air or substances from entering the flask and potentially interfering with the reaction. It also helps to prevent any of the reactants or products from escaping the flask, ensuring that the reaction can proceed as intended.

By sealing the flask with the stopper, you can more accurately measure and observe the reaction without any outside factors affecting it. In addition, sealing the flask with the stopper can also help to control the pressure and temperature of the reaction, which can be important for certain types of reactions.

By keeping the flask sealed, you can maintain a consistent environment within the flask and more accurately predict the outcome of the reaction.

Overall, sealing the flask with the stopper is an important step in conducting a controlled and accurate experiment. Without it, the reaction may be affected by outside factors and the results may be inaccurate or inconsistent.

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What causes an object’s speed and or motion to change?

Answers

Answer: An object's speed and motion can be changed by a force acting on it. This is described by Newton's Second Law of Motion, which states that the acceleration of an object is directly proportional to the force applied to it, and inversely proportional to its mass. Therefore, the greater the force applied to an object, the greater its acceleration will be, and the greater the change in speed or motion will be. Additionally, the direction of the force also plays a role in changing an object's motion, as it can cause the object to change direction or rotate.

Your welcome (:

Explanation:

What is the amount of pure substance in 10. 7 g of aluminum? Assume the molar mass of aluminum is 26. 98 g/mol

Answers

This is calculated by dividing the mass of aluminum (10.7 g) by its molar mass (26.98 g/mol), resulting in 0.395 mol.

To find the amount of pure substance (in moles) in 10.7 g of aluminum, we need to divide the given mass by the molar mass of aluminum.

The molar mass of aluminum is given as 26.98 g/mol.

Therefore, the amount of pure substance (in moles) in 10.7 g of aluminum can be calculated as:

moles = mass/molar mass

moles = 10.7 g/26.98 g/mol

moles = 0.396 moles (rounded to three significant figures)

So, there are approximately 0.395 moles of pure substance (aluminum) in 10.7 g of aluminum.

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Calculate the molar/formula mass for each compound. NO2
C6H12O6

Answers

C₆H₁₂O₆ has a molar mass of 180.18 g/mol.

The molar mass of a compound is the mass of one mole of the compound and is expressed in grams per mole (g/mol). To calculate the molar mass of a compound, we sum the atomic masses of all the atoms in the compound.

For NO₂, we have:

Molar mass of N = 14.01 g/mol

Molar mass of O = 16.00 g/mol

Therefore, the molar mass of NO₂ = 14.01 g/mol + 2(16.00 g/mol) = 46.01 g/mol.

For C₆H₁₂O₆ (glucose), we have:

Molar mass of C = 12.01 g/mol

Molar mass of H = 1.01 g/mol

Molar mass of O = 16.00 g/mol

Therefore, the molar mass of C₆H₁₂O₆  = 6(12.01 g/mol) + 12(1.01 g/mol) + 6(16.00 g/mol) = 180.18 g/mol.

Knowing the molar mass is useful in calculating various other properties of the compound, such as the number of moles present in a given mass or the mass of a given number of moles.

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The molar mass of NO2 is 46 g/mol.

The molar mass of C6H12O6 is 180 g/mol.

The atomic masses of all the atoms in a compound's formula are added to determine its molar mass. In order to compute the molar mass of NO2, the atomic masses of one nitrogen atom (14.01 g/mol) and two oxygen atoms (2 x 16.00 g/mol) are added together, yielding a result of 46.01 g/mol.

Glucose is a typical monosaccharide and has the chemical formula C6H12O6. The atomic masses of every atom in the molecule must be added in order to determine the molar mass. Hydrogen, oxygen, and carbon all have atomic masses of 1.01 g/mol, 12.01 g/mol, and 16.00 g/mol, respectively. dividing the atomic mass of each element by the number of atoms in that element.

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Pls pls will give BRAINLYST who has the key for the SOIL TEXTURE TRIANGLE

Answers

A soil texture triangle is used to classify a soil's texture class. The percentages of sand, silt, and clay are scaled on the sides of the soil texture triangle.

What is the apes soil texture triangle?

Clay percentages are read across the triangle from left to right (dashed lines). The soil texture triangle identifies soil based on the amount of clay, silt, and sand. The angle of the numbers indicates the direction of the lines for each type of particle.

Clay lines, for example, go straight across, silt lines run diagonally down, and sand lines run diagonally up. M. Whitney of the USDA invented the textural triangle method in 1911 [21]. The USDA ternary diagram is divided into 12 textural classifications based on soil fraction %.

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Gas A is 0.75 times as fast as gasB.the mass of gas B is 32grams. What is the mass of gas A?

Answers

The molar mass of A is 56.9 g/mol from the calculation below.

What is the Graham's law of diffusion?

The Graham's law of diffusion, also known as Graham's law of effusion, is a scientific principle that describes the relationship between the rate of diffusion or effusion of gases and their molecular weights. It states that "the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molecular weight."

We know that;

RA/RB = √MB/MA

0.75/1 = √32/MA

(0.75)^2 = 32/MA

MA = 32/(0.75)^2

MA = 56.9 g/mol

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Reactions of Carboxylic Acids with Bases
1. Write a balanced equation for each reaction & name the salt formed in each case.
Use shortened structural formulae.
a) ethanoic acid + sodium hydroxide
name of salt.
b) ethanoic acid + calcium hydroxide
name of salt..
c) propanoic acid + ammonium hydroxide
name of salt..
d) methanoic acid + sodium carbonate
name of salt..
e) propanoic acid + sodium hydrogencarbonate
name of salt..
f) ethanoic acid + calcium carbonate
name of salt..
2. Reaction of ethanoic acid with a base produces an ethanoate salt.
Draw the displayed formula of the ethanoate anion.

Answers

Answer:

Balanced equations and names of salts:

a) CH3COOH + NaOH → CH3COONa + H2O (sodium ethanoate)

b) 2CH3COOH + Ca(OH)2 → Ca(CH3COO)2 + 2H2O (calcium ethanoate)

c) C2H5COOH + NH4OH → NH4C2H5COO (ammonium propanoate)

d) 2HCOOH + Na2CO3 → 2NaHCOO + CO2 + H2O (sodium formate)

e) C2H5COOH + NaHCO3 → NaC2H5COO + H2O + CO2 (sodium propanoate)

f) 2CH3COOH + CaCO3 → Ca(CH3COO)2 + CO2 + H2O (calcium ethanoate)

The displayed formula of the ethanoate anion is CH3COO-

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1. What are the five lessons or skills you learned in you're TLE 9-Agri Crops that you valued most

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TLE 9-Agri Crops might teach students important concepts or skills such plant propagation, soil preparation, insect control, irrigation management, and harvesting methods.

The purpose of the TLE 9-Agri Crops course is to introduce students to the basic ideas and procedures involved in crop production. Plant propagation, which includes the reproduction of plants through various ways such as seeds, cuttings, or grafting, is one of the most crucial skills covered in this course. Another crucial idea is soil preparation, which deals with managing the texture, structure, and fertility of the soil to assist plant development. Although irrigation management ensures that crops receive an appropriate quantity of water, insect control is crucial for defending crops against pests that might kill or severely harm them. Last but not least, harvesting techniques are crucial to ensuring a plentiful and high-quality crop.

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silver sulfide (ag2s) is the common tarnish on silver objects. what mass of silver sulfide can be made from 1.53 x 10-3g of hydrogen sulfide (h2s) obtained from a rotten egg?\

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Silver sulfide (Ag2S) is the common tarnish on silver objects. The mass of silver sulfide that can be made from 1.53 x 10^-3g of hydrogen sulfide (H2S) obtained from a rotten egg is 3.67 g.

Let's understand this in detail:

The balanced chemical equation for the reaction is:

2 AgNO3 + H2S → Ag2S + 2 HNO3

The molar mass of H2S is 34.08 g/mol.

1.53 x 10^-3g of H2S = (1 mol / 34.08 g) * (1.53 x 10^-3g) = 4.49 x 10^-5 mol H2S.

From the balanced equation, it is clear that one mole of Ag2S is formed from one mole of H2S.

Therefore, the number of moles of Ag2S formed from 1.53 x 10^-3g of H2S is 4.49 x 10^-5 mol.

The molar mass of Ag2S is 247.8 g/mol. Therefore, the mass of Ag2S formed from 1.53 x 10^-3g of H2S is

(247.8 g/mol) * (4.49 x 10^-5 mol) = 0.0111 g or 11.1 mg.

To convert to grams, divide by 1000:11.1 mg ÷ 1000 = 0.0111 g or 11.1 mg = 1.11 x 10^-2

Therefore, the mass of silver sulfide that can be made from 1.53 x 10^-3g of hydrogen sulfide obtained from a rotten egg is 3.67 g (approx).

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In this system, the equilibrium lies to the , and the reaction favors the

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In this system, the equilibrium lies to the left , and the reaction favors the reactants

What is an equilibrium reaction system?

An equilibrium reaction system refers to a chemical system where the forward and reverse reactions occur at the same rate, resulting in no net change in the concentration of reactants and products over time.

In an equilibrium reaction system, the reactants and products are in a dynamic state where they are constantly interconverting. The equilibrium point is the point at which the concentrations of reactants and products remain constant, and the rate of the forward reaction is equal to the rate of the reverse reaction.

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a gas has a mass of 3175 g and takes up enough space to fill a room that is 2.00 m x 2.00 m x 5.00 m determined what the gas is in g/mL

Answers

To determine the gas in g/mL, we need to calculate the volume of the gas first. We can use the formula for the volume of a rectangular room to find the volume of the room:

Volume = length x width x height = 2.00 m x 2.00 m x 5.00 m = 20.00 m³

Next, we need to convert the mass of the gas from grams to kilograms, since density is usually expressed in units of kg/m³. We can do this by dividing the mass by 1000:

Mass = 3175 g ÷ 1000 = 3.175 kg

Finally, we can calculate the density of the gas using the formula:

Density = Mass ÷ Volume

Density = 3.175 kg ÷ 20.00 m³ = 0.1588 kg/m

To convert the density from kg/m³ to g/mL, we need to multiply by 1000 and then divide by 1000:

Density = 0.1588 kg/m³x 1000 g/kg ÷ 1000 mL/L = 0.1588 g/mL

Therefore, the gas has a density of 0.1588 g/mL. Without additional information, we cannot determine the identity of the gas.

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