You buy a new commercial stove for $9,000 and estimate that it will enable you to deliver 20 additional meals per night at an average price of $20. Assuming 25% food cost and no additional costs to using the new stove, how long will it take the stove to pay for itself?
Assuming 25 % food cost and no additional costs to using the new stove, The time it will take the stove to pay for itself is 30 days.
Determining the number of daysProfits per meal = $20 - ( 0.25 x20)
Profits per meal = $20 -$5
Profits per meal = $15
Profits for 20 meals = $15 x 20
Profits for 20 meals =$300
Now let determine the number of days
Number of days =$9000 / $300 days
Number of days =30 days
Therefore we can conclude that 30 days is the days that it will take.
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what is 5x6 I need help
Thus, the required solution is 30.
Answer: 30
Step-by-step explanation: 30
If I complete this review, then I will do well on the test. If I do well on the test. If I do well on the test, then I will get an “A” on my progress report. Make a conclusion using the law of syllogism
Law of syllogism:
If p, then q
If q, then r
Conclude:
If p, then r
Given situation:
p: complete this review
q: do well on the test
r: get an “A” on my progress report
If p, then q: If I complete this review, then I will do well on the test
If q, then r: If I do well on the test, then I will get an “A” on my progress report
Conclusion:
If p, then r: If I complete this review, then I will get an “A” on my progress report
if cos ∅=sin 46° find ∅
Answer:
∅ = 44°
Step-by-step explanation:
cos∅ = sin46°
∅ = (90 - 46)°
∅ = 44°
Hope this helps
Give two examples when you would need to know the perimeter and two examples of when you would need to know the area.
Perimeter is the distance around a figure. The instances where we need to find perimeter include
1) The total length of the boundary of a marked field. This would involve adding the distance around it. Both the curved and straight paths
2) The length of barbed wire to be placed on a fence would require us to find the distance round the fence
The area of a shape is the space enclosed within the perimeter of the shape. The instances where we need to find area include
1) The area of a wall is calculated to determine how much paint is needed to paint it. The paint is used per square unit.
2) The area of a field is calculated to determine the cost of mowing it since the cost is calculated per unit square
A business woman buys a new computer for $4000. for each year that she uses it the value goes depreciates by $400 the equation below gives the value y of the computer after x years. What does the x intercept mean in this situation? Find the x intercept. After how many years will the value of the computer be $2000Y=-400x+4000
Step 1: Write the equation
y = -400x + 4000
Step 2:
The intercept in the equation represents time in years.
x-intercept represents the total length of time taken in years for the computer to values to depreciate to $0.
step 3: Find the x-intercept
To find the x-intercept, you will have to find the time taken for the computer value to depreciate to $0.
y = $0
[tex]\begin{gathered} \text{From the equation.} \\ y\text{ = -400x + 4000} \\ 0\text{ = -400x + 4000} \\ 400x\text{ = 4000} \\ x\text{ = }\frac{4000}{400} \\ x\text{ = 10} \end{gathered}[/tex]The x-intercept = 10 years
Step 4:
To find the number of years take for the computer value to depreciate to $2000.
You will substitute the value of y = $2000 and find the value of x.
Therefore
[tex]\begin{gathered} y\text{ = -400x + 4000} \\ 2000\text{ = -400x + 4000} \\ 400x\text{ = 4000 - 2000} \\ 400x\text{ = 2000} \\ x\text{ = }\frac{2000}{400} \\ \text{x = 5 years} \end{gathered}[/tex]It will take 5 years for the value of the computer to depreciate to $2000.
solve the equation and check the solution:7x - 7 = 13 + 12x
we have the equation
7x - 7 = 13 + 12x
solve for x
Group terms
12x-7x=-7-13
Combine like terms
5x=-20
x=-20/5
x=-4Verify
substitute the value of x=-4 in the original expression
7(-4)-7=13+12(-4)
-28-7=13-48
-35=-35 -------> is ok
How many values does the expression 6+ (7 + 3)² have? Write down the values.
Answer:
3
Step-by-step explanation:
6
7
3
The values are the number that compose the expression
The surface area of the solid cone requiring paint rounded to the nearest whole number is how many square centimeters?
In order to calculate the surface area of the cone, first let's calculate its slant height.
If the diameter is 5 cm, the radius is 2.5 cm. Now, using the Pythagorean theorem, we can calculate the slant height s:
[tex]\begin{gathered} s^2=h^2+r^2 \\ s^2=11.4^2+2.5^2 \\ s^2=129.96+6.25 \\ s^2=136.21 \\ s=11.67\text{ cm} \end{gathered}[/tex]Now, we can calculate the surface area using the formula below:
[tex]\begin{gathered} S=\pi rs+\pi r^2^{} \\ S=\pi\cdot2.5\cdot11.67+\pi\cdot2.5^2 \\ S=29.175\pi+6.25\pi \\ S=35.425\pi \\ S=111.29\text{ cm}^2 \end{gathered}[/tex]Rounding to the nearest square centimeter, we have a surface area of 111 cm².
See attached pic for problem. Only need help with #2
SOLUTION
Part 1
The independent variable are the predicting varaible for which other variable are depends on. The are the x- values
Hence
The indepedent varibles is school year
The dependent variable are the responses variables. They are the y-values for which depends on othere values,
Hence
The dependent variable for the data given is
The Tution
Part 2
To find the function, we need to set up the data as given in the table below.
The years has an interval of 1 and each fees difer by 4, the to obtain the x-values we use the mid-point
[tex]x=\frac{\text{lower}+\text{higher}}{2}\text{ for each }[/tex]Hence
The data plot will be
The linear is given by the form
[tex]\begin{gathered} y=ax+b \\ \text{Where }^{} \\ a=561.043,\text{ b=-0.0000}010994 \\ \text{Hence } \\ y=561.043x-0.0000010994 \end{gathered}[/tex]THerefore
The linear regression is y = 561. 043x -0.0000010994
Then for exponenetial we have
[tex]\begin{gathered} y=e^{ax+b} \\ \text{Where } \\ a=0.0286229,b=-47.2727 \\ \text{Hence } \\ y=e^{0.029x-47.27} \end{gathered}[/tex]Hence
The exponential regression is y = e^(0.029x-47.27)
For the power represion we have
[tex]\begin{gathered} y=ab^x \\ \text{Where } \\ a=2.9495\times10^{-21,}b=1.02904 \\ \text{Hence } \\ y=2.9495\times10^{-21,}(1.02904)^x \end{gathered}[/tex]Hence
The power regression is
y= 2.9495 x 10^-21 (1.02904)ˣ
Part 3
The graoh lot for linear function is given below
The graph for the exponential plot is
The graph for the power regression plot is given below as
on the coordinate plane below
As we can see by the picture below, the school is on the point (5, -2).
QUESTION IS IN IMAGE!!! DONT NEED TO SHOW WORK JUST NEED ANSWER!!!!!
Since P is the center of the circle, then the segments PS and PQ are both radii of the circle and have the same measure. Then, the triangle PQS is an isosceles triangle, then, the measures of the angles PQS and QSP must be the same.
Since the sum of the internal angles of a triangle must be equal to 180º, then:
[tex]\begin{gathered} m\angle PQS+m\angle QSP+m\angle SPQ=180º \\ \Rightarrow m\angle PQS+m\angle PQS+113º=180º \\ \Rightarrow2m\angle PQS=180º-113º \\ \Rightarrow2m\angle PQS=67º \\ \Rightarrow m\angle PQS=\frac{67º}{2} \\ \Rightarrow m\angle PQS=33.5º \end{gathered}[/tex]The measure of RQS is the same as the measure of PQS.
Therefore, the answer is:
[tex]m\angle RQS=33.5º[/tex]An earthquake in California measured 3.6 on the Richter scale. Use the formula R=log(A/Ao) to determine approximately how many times stronger the wave amplitude of the earthquake was than .
The correct option regarding how many times stronger the wave amplitude of the earthquake was than the standard wave Ao is given by:
A = 3981Ao.
Ratio of A and AoTo find the ratio of A and Ao, measuring how many times a earthquake measuring R in the Richter scale was than Ao, we have to solve the following logarithmic function:
R=log(A/Ao)
The power of 10 in inverse to the logarithm, hence it is applied to both sides of the expression, as follows:
10^R = 10^log(A/Ao).
Since they are inverses, we can remove the power and the logarithm as follows:
A/Ao = 10^R
Hence the formula for how many times stronger and earthquake is than Ao is given as follows:
A = 10^R Ao
In this problem, the Richter measure of the earthquake was of:
R = 3.6.
Hence the ratio is:
A = 10^(3.6)Ao
A = 3981Ao.
Missing informationThe problems asks how many times stronger the earthquake was than Ao.
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Solve the inequality 8y- 5 < 3
Solve the inequality as you do with equations.
[tex]\begin{gathered} 8y-5<3 \\ 8y<3+5 \\ y<\frac{8}{8} \\ y<1 \end{gathered}[/tex]y is less than 1.
The graph of the solution is:
Marco is a newspaper boy who received a total piecework paycheck of $169.12. He receives 56 cents for every newspaper he delivers. How many newspapers did he deliver?
if he receives 56 cents for each period it means that the multiplication must give the total paid
[tex]0.56\times P=169.12[/tex]where P is the number of newspapers
then, solve for p
[tex]P=\frac{169.12}{56}=302[/tex]he delivered 302 newspapers
PLS HELP ASAP WILL GIVE BRAINLIST
Answer:
65
Step-by-step explanation:
[tex]-4a + 65 = 2a + 5\\60 = 6a\\a = 10\\[/tex]
KJN = 25 degrees
MJN = 25 degrees
KJM = KJN + MJN = 25 + 25 = 50 degrees
total angles = 360 degrees
JKL = (360 - 50 - 50 )/2 = 130 degrees
LKN is half of JKL = 130/2 = 65
Carly actions by-40; + 2) - 107j+2=-40 Step 1Tj = -42 Step 2j=-6 Step 3--Step 1Step 2Step 3Carly did not make a
Carly made a mistake in step 1 because she divided by -4 on the left side but multiplied by -4 on the right side.
On step 1 carly's equation should look like this
[tex]7j+2=-\frac{10}{4}[/tex]Suppose the cost per ton f(x) to build an oil platform of x thousand tons is approximated byf(x)= 62,500 ______ x+125What is the cost per ton for x=30?
Given that
The cost per ton f(x) to build an oil platform of x thousand tons is approximated by
[tex]f(x)=\frac{62500}{x+125}[/tex]The cost per ton for x = 30, i.e f(30) will be
[tex]\begin{gathered} f(x)=\frac{62500}{x+125} \\ f(30)=\frac{62500}{x+125}=\frac{62500}{30+125}=\frac{62500}{155} \\ f(30)=\frac{62500}{155}=403.226\text{ (3 d.p)} \\ f(30)=403.226\text{ (3 d.p)} \end{gathered}[/tex]Hence, the answer is 403.226 (3 d.p)
Factor completely: 3x'2 + 6x + 3a. (3x + 1) (x + 6)b. (3x + 3) (x + 1)c. 3(x + 1)'2d. 3(x + 1) (x-1)the 2s with the commas are exponents
3x^2 + 6x + 3
a= 3
b= 6
c = 3
Find the product of a and c
3x3 = 9
Now, find a product that equal 3x3 and equals be when added
b= 6
3+3 = 6
3x3= 9
Rewrite the expression with the new numbers taking the middle place:
3x^2 +3 x+ 3x +3
Isolate terms and factor out the greatest common factor:
(3x^2 +3 x) + (3x +3)
3x ( x+1) + 3 (x+1)
Factor out x+1 and rewrite:
(3x+3) (x+1)
0.4(2-) 0.2(9 + 7) A)-3 B - 1 C) 3 D) all real numbers
Let us solve the equation to arrange the steps
[tex]-3(4+3x)+5x=-16[/tex]In the first step, we must multiply the bracket by -3 (distributive property)
[tex](-3)(4)_{}+(-3)(3x)=-12-9x[/tex]Then the equation is
[tex]-12-9x+5x=-16[/tex]Now add the like terms on the left side
[tex]\begin{gathered} -12+(-9x+5x)=-16 \\ -12x+(-4x)=-16 \\ -12-4x=-16 \end{gathered}[/tex]Next step, add 12 to both sides
[tex]undefined[/tex]Solve the System of Equations8x + 15y = -1174x + 9y=-75Write your answer as an ordered pair: (x,y)
We have to solve the system of linear equations:
[tex]\begin{gathered} 8x+15y=-117 \\ 4x+9y=-75 \end{gathered}[/tex]We can substract 2 times the second equation for the first equation and solve for y:
[tex]\begin{gathered} (8x+15y)-2(4x+9y)=-117-2(-75) \\ 8x+15y-8x-18y=-117+150 \\ 0x-3y=33 \\ y=\frac{33}{-3} \\ y=-11 \end{gathered}[/tex]Now, we can solve for x:
[tex]\begin{gathered} 4x+9y=-75 \\ 4x+9(-11)=-75 \\ 4x-99=-75 \\ 4x=-75+99 \\ 4x=24 \\ x=\frac{24}{4} \\ x=6 \end{gathered}[/tex]Answer: (x,y)=(6,-11)
Dunoga cycled 15.26 kilometres and then ran 740 metres. What was the total distance he covered in kilometres?
Answer:16 Kilometers
Step-by-step explanation:15.26km+.74km
Dunoga covered a distance of 16 km in total.
What is unit conversion?A unit conversion expresses the same property as a different unit of measurement.
For instance, time can be expressed in minutes instead of hours, while distance can be converted from miles to kilometers, or feet, or any other measure of length.
Given that, Dunoga cycled 15.26 kilometers and then ran 740 meters. We need to find the distance he covered in kilometers,
To find the total distance, we will add the distance he covered by cycle and by running,
But the units of both the distances are not same and to add we need to convert the units,
Since, the answer required in kilometers, so we will convert meter into kilometers,
1 km = 1000 m
Therefore,
740 m = 740 / 1000 = 0.74 km
Therefore, the distance he covered in kilometers = 0.74+15.26
= 16 km
Hence, Dunoga covered a distance of 16 km in total.
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(3x10⁴) (2x10⁵)Find the answer by simplifying
The given expression (3x10⁴) (2x10⁵)
we seperate the terms and collect like terms:
[tex]\begin{gathered} \mleft(3\times10^{4}\mright)(2\times10^{5})\text{ = 3}\times10^{4}\times2\times10^{5} \\ =\text{ 3}\times2\times10^{4}\times10^{5} \end{gathered}[/tex]When multiplying exponent (power) of the same base, the exponenet of the two numbers (base) are added together.
[tex]\begin{gathered} \text{Base = 10 , exponent = 4 and 5} \\ =3\times2\times10^{4+5} \\ =\text{ 6}\times10^9 \end{gathered}[/tex]
Why might It be more useful to have a square root in simplest form rather than a large number under the root or the approximate Value?
Problem
Why might It be more useful to have a square root in simplest form rather than a large number under the root or the approximate Value?
Solution
One possible answer is that if we have the square root in the simplest form we can simplify expression add, subtract and multiply/divide by other quantities. Also with the simplification is easire to understand the value of interest.
Newton's law of cooling is T = A * e ^ (- d * t) + C where is the temperature of the object at time and C is the constant temperature of the surrounding mediumSuppose that the room temperature is 71^ + and the temperature of a cup of tea 160when it is placed on the table. How long will it take for the tea to cool to 120 degrees for k = 0.0595943 Round your answer to two decimal places.
Solution
Given
[tex]\begin{gathered} T=Ae^{-kt}+C\text{ --------\lparen1\rparen} \\ \\ C=71 \\ \\ A=160-71 \\ \\ T=120 \\ \\ k=0.0595943 \end{gathered}[/tex]To find the time, we nee to substitute the C, A, T, and k in (1) and then determine (t
[tex]\begin{gathered} 120=(160-71)e^{-0.0595943t}+71 \\ \\ \Rightarrow\frac{120-71}{160-71}=e^{-0.0595943t} \\ \\ \Rightarrow\frac{49}{89}=e^{-0.0595943t} \\ \\ \Rightarrow-0.0595943t=\ln(\frac{49}{89}) \\ \\ \Rightarrow t=\frac{1}{-0.0595943}\ln(\frac{49}{89})=10.01456\text{ s} \end{gathered}[/tex][tex]t=\frac{10.01465}{60}\text{ mins}=0.17\text{ mins}[/tex]This season, the probability that the Yankees will win a game is 0.59 and theprobability that the Yankees will score 5 or more runs in a game is 0.43. Theprobability that the Yankees lose and score fewer than 5 runs is 0.3. What is theprobability that the Yankees win and score 5 or more runs? Round your answer to thenearest thousandth.
From the information given we conclude that the probability that the Yankees win and score 5 or more scores is 0.43
It is because of the description given in the problem.
For the point P(24,14) and Q(31,17), find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.
STEP 1
Identify what is given and establish what is required.
We are given the coordinates of two points P and Q on the cartesian and are asked to find their midpoint M assuming a straight line is drawn from P and Q
Midpoint between two points is given as:
[tex]\begin{gathered} M=\frac{x_1+x_2}{2},\text{ }\frac{y_1+y_2_{}}{2} \\ \text{Where} \\ x_1,y_{1\text{ }}are\text{ the coordinates of point 1} \\ x_2,y_{2\text{ }}are\text{ the coordinates of point }2 \end{gathered}[/tex]STEP 2
Employ formula while putting the appropriate variables.
We select point P as our point 1 as in the formulae and
We select point Q as our point 2 as in the formulae
This gives us:
[tex]\begin{gathered} M=\frac{24+31}{2},\frac{14+17}{2} \\ M=\frac{55}{2},\frac{31}{2} \\ M=27.5,15.5 \end{gathered}[/tex]Therefore, our midpoint M is(27.5, 15.5)
what is the surface area of the rectangular prism? 1.8 ft 2/5 ft 1/2 ft
Each face of a rectangular prism has a rectangle shape. To calculate the surface area we need to calculate the area of all the faces. Each face appears twice on the prism, on opposite sides so we only need to make three calculations. These are done using the formulas below:
[tex]\begin{gathered} A_1=height\cdot width_{} \\ A_2=length\cdot width_{} \\ A_3=length\cdot height_{} \end{gathered}[/tex]Using the data from the problem we can calculate these areas.
[tex]\begin{gathered} A_1=\text{ 1.8}\cdot\frac{2}{5}=0.72\text{ square ft} \\ A_2=\frac{1}{2}\cdot\frac{2}{5}=0.2\text{ square ft} \\ A_3=1.8\cdot\frac{1}{2}=0.9\text{ square ft} \end{gathered}[/tex]The surface area of the prism is the sum of the areas above multiplied by two.
[tex]\begin{gathered} A_{\text{surface}}=2\cdot(A_1+A_2+A_3) \\ A_{\text{surface}}=2\cdot(0.72+0.2+0.9)=2\cdot1.82=3.64\text{ square ft} \end{gathered}[/tex]Find the set An B.
U = {1, 2, 3, 4, 5, 6, 7, 8)
A = {1, 2, 3, 4)
B = {1, 2, 6}
Step-by-step explanation:
I assume A n B means the intersection of the sets A and B.
that means all the elements that are in A and in B.
that is the set {1, 2}
Find the equation in standard form of lines P that are A) parallel to and B) perpendicular to line L P(1,2); L: 3x-2y=1P(8,7);L: y= -4
To find if two lines are parallel, the slope must be the same.
so m=m
for P(1,2); L: 3x-2y=1
First, solve the equation for y:
3x-2y=1
Subtract both sides by 3x
3x-2y=1
3x-3x-2y =1-3x
-2y=1-3x
Now, divide both sides by -2y
-2y/-2 = 1-3x
y =1/-2 +3x/2
The parallel line using the point P(1,2)
y-y1 =m(x-x1)
Replace the values and solve for y.
y-2=3x/2 -1
y=3x/2+2
So the parallel lines is y=3x/2+2
To find a perpendicular line, when you multiply the slopes the result must be equal to -1.
So:
m1*m2 = -1
Replace m1=3/2
m1*m2 = -1
3x/2* m2 = -1
m2 = -1/(3x/2)
m2 = -2/3
To find the line use:
y-y1 =m(x-x1)
y-2=-2/3(x-1)
y-2=-2x/3 +2/3
y= -2x/3 +8/3
So y= -2x/3 +8/3 is the perpendicular line.