Physics High School

The momentum of a system is conserved:

I. when no net external force act on the system

II. when no internal forces act on the system

III. always

Answers

Answer 1

Answer:

I. when no net external force act on the system

Explanation:

Suppose you are exerting an external force F on an object, it's velocity keeps increasing. Which means its momentum = velocity * mass is also increasing. In this case the initial momentum of that object is not preserved (but increased).

Answer 2
I think the answer is I.

Related Questions

what is q if 28.6 g of water is heated from 22.0°c to 78.3°c? the specific heat of water is 4.184 j/g·°c.

Answers

Answer:

6736 J

Explanation:

Knowing that Q = cmΔT:

Q = 4.184 J/(g·°C) · 28.6g · (78.3 °C - 22.0 °C) = 6736 J.

HELP!!!!
Which statement describes earthquakes?

They release energy.
They are caused by reduced stress in rocks.
They begin at the epicenter.
They result from movement on Earth’s surface.

Answers

Answer:

A

Explanation:

earthquakes release energy

Answer:

i think it begins at the epicenter

Explanation:

i can remember

pls give brainleist

Which statement describes ionic compounds?

A) ionic compounds are positively charged
B) ionic compounds are neutral
C) ionic compounds are negatively charged

Answers

Answer:the answer is b

Explanation:

This is because in an ionic bond negative and positive bonds are present

Given that 1 pound is equal to 4.45 newton’s what is the weight of a 500N child in pounds?

Answers

Answer:

112.36 pounds

Explanation:

Since 1 pound = 4.45 Newtons, a 500N child in pounds = 500÷4.45 = 112.36 pounds (approximately).

Cart 1 has a mass of 1 kg. Cart 2 has a mass of 2 kg. They are pushed apart by a spring. The spring exerts 2N of force into cart 1. How much force is exerted into cart 2? Explain.

Answers

The force exerted on the cart 2 during the collision is 2 N.

The given parameters:

Mass of cart 1 = m1 = 1 kgMass of cart 2 = m2 = 2kgForce applied on cart 1 = 2 N

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.

[tex]F_1 = -F_2[/tex]

[tex]F_2 = -F_1\\\\F_2 = -2 \ N\\\\|F_2| = 2 \ N[/tex]

Thus, the force exerted on the cart 2 during the collision is 2 N.

Learn more about Newton's third law of motion here: https://brainly.com/question/13874955

Record your observations. Include the data table you created for the lab and a graph based on the data table. Type your answer here:

Answers

To create a graph of the data you collected during the lab, first, organize the data, then select the best type of graph, and finally create the graph.

One of the steps you need to complete after an experiment is to graph your results. This implies organizing the data and creating a diagram to visually represent your findings.

These are the steps you can follow to complete this task:

Organize the data: The first thing you need to do is to understand what were the main factors for example if your experiment measured temperature changes this is the main factor you need to consider. Then try to organize this data in a chart so you can visualize it.Select the type of graph: There are different types of graphs such as:Bar graph.Pie chart.Scatter plot.Among others.

Each of these graphs focuses on specific types of data, and therefore you need to select the one that best fits the data you collected.

Create the graph: Finally, you can create the graph to do this, there are programs like excel that help you create the graph only by entering the data.

Learn more about graphs in: https://brainly.com/question/16192791

Which of the following rivers flows north in eastern Florida?

St. James
St. Johns
Mississippi
Hudson

Answers

St. John’s

_________

o0o0o0o0o0

What is the force applied to a baseball that has a mass of 142kg and has a acceleration of 30m/s to the power of 2

Answers

Mass=m=142kgAcceleration=a=30m/sForce=F

Using Newton's second law

[tex]\\ \sf\Rrightarrow F=ma[/tex]

[tex]\\ \sf\Rrightarrow F=142(30)[/tex]

[tex]\\ \sf\Rrightarrow F=4260N[/tex]

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