The power ratings of several motors are listed in the table. A 2 column table with 3 rows. The first column is labeled motor with entries, brand X, brand Y, brand Z. The second column is labeled Power in watts with entries 7460, 7650, 7580. An advertising agency writes marketing material for a new motor (Brand W) that has a power rating of 7,640 W. Which statement comparing the motors can they truthfully use? Brand W motor can finish any job faster than Brand Y motor can. There’s not a more powerful motor available. Brand W motor does more work each second than Brand X or Brand Z. Every second, Brand W motor does 7,640 N of your toughest work.

Answer:

Energy conservation relies on people cutting back on activities that consume energy—by turning off lights or driving less or using appliances less often.

Explanation:

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Convert second term into kg

131 = 0.131

Term has become:

2.52 + 0.131

The total is:

2.651 kg

Answer:

The fibers of the sweater lose electrons.

Answer:

Both will hit the ground at the same time.

Answer:

ch3sh + 4O2 are the products

Answer:

3^15 / 3^3 = 3^12 * 3^3 / 3^3 = 3^12

The Law of Exponents applies here

3^15 x 3^3 is a product, not a quotient

3^15 x 3^3 = 3^18

Answer:2.86seconds

Explanation:

H=gt^2/2

t=2h/g

Trigonometry allows to find the result for the question about the height of the mountain is:

Trigonometry allows finding relationships between the angles of a right triangle.

         [tex]tan \theta = \frac{y}{x}[/tex]  

Where θ is the angle, y the opposite leg (height) and x the adjacent leg (horizontal distance).

In the attachment we can see a diagram of the system. They indicate that for x  distance the angle is 14.67º  

         tan 14.67 = [tex]\frac{y}{x}[/tex]  

At the other point the angle is 10.38º.

        tan 10.38 = [tex]\frac{y}{x+15860}[/tex]

We look for the horizontal distance (x) with these equations.

        x tan 14.67 = (x + 15860) tan 10.38

        x tan 14.67 / tan 10.38 = x + 15860

        x 1,429 = x + 15860

        x 0.429 = 15860

        x = [tex]\frac{15680}{0.429}[/tex]

        x = 36955.3 ft

We calculate for the height.

        y = x tan 14.67

        y = 36955.3 tan 14.67

        y = 9674.4 ft

In conclusion using trigonometry we can find the result for the height of the mountain is:

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If the wave velocity and frequency of a wave are both doubled, the wavelength will remain the same.

The wavelength of a wave shows the spatial orientation of distance between two successive crest in a wave medium.

The wavelength λ is expressed by using the relation:

[tex]\mathbf{\lambda = \dfrac{v}{f}}[/tex]

Now, if velocity and  frequency of wave is both doubled, the wavelength will   remain the same.

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Answer:

Compound 'A' C5H12 does not react with phenyl hydrazine. Oxidation of 'A' with K2Cr2o7,/H" gives B' (c5H10o). Compound 'B' reacts with phenyl hydrazine but does not give Tollen's test. The

Answer:

The Production Possibilities Curve (PPC) is a model that captures scarcity and the opportunity costs of choices when faced with the possibility of producing two goods or services. Points on the interior of the PPC are inefficient, points on the PPC are efficient, and points beyond the PPC are unattainable.

Explanation:

Answer:

first number is 113 and the second number is 15

Answer:

468.42572 Wavelength In Metres

Explanation:

Answer:

[tex]\huge\boxed{\sf Wavelength= 470\ m}[/tex]

Explanation:

Given Data:

Speed of light = c = 3 × 10⁸ m/s (Constant)

Frequency = f = 640 kHz = 6.4 × 10² × 10³ Hz = 6.4 × 10⁵ Hz

Required:

Wavelength = λ = ?

Formula:

λ = c / f

Solution:

λ = 3 × 10⁸ / 6.4 × 10⁵

λ = 0.47 × 10³

λ = 4.7 × 10² m

λ = 470 m

[tex]\rule[225]{225}{2}[/tex]

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 284 × 9 = 2556

We have the final answer as

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Explanation:

1. A

2. B

3. I don't know this one but my guess is b

Answer:

Answer is 1000kg

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An object is definitely being accelerated when a nonzero net force is acting on it: Option B.

A net force refer to the vector sum of all the forces that are acting on an object or physical body. Thus, a net force is a single force that substitutes the effect of all the forces acting on an object or physical body.

According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass.

This ultimately implies that, an object is definitely being accelerated when a nonzero net force is acting on it.

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Hi there!

Since the crate is being slid at a constant speed, the forces sum to 0 N. In this instance, the following forces occur in the axis of interest:

Wsinθ = downward acceleration along incline due to gravity (N)

Fκ = kinetic friction force along incline (N)

A = applied force (N)

The acceleration due to gravity and friction force act in the same direction, so:

Wsinθ + Fκ = A

Solve for sinθ using right triangle trigonometry:

sinθ = O/H = 3/6 = 0.5

Rearrange the equation for the force of kinetic friction and solve:

Fκ = A - 0.5W

Fκ = 30.4 - 20 = 10.4 N

Now, recall that:

Work = Force × displacement (W = F × d)

Since the box's displacement is in the same axis as the force but OPPOSITE direction, we must use:

W = Fdcosθ

Angle between displacement and friction force is 180°.

cos(180) = -1

Work done by friction = -Fd = -10.4(6) = -62.4 J

After the series of powerful storm systems of the 2005 Atlantic hurricane season, as well as after Hurricane Patricia, a few newspaper columnists and scientists brought up the suggestion of introducing Category 6, and they have suggested pegging Category 6 to storms with winds greater than 174 or 180 mph (78 or 80 m/s).

Answer:

Terms in this set (7) Which element forms more compounds than all the other elements combined? Carbon.

Explanation:

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Answer:

I think A

Explanation:

Answer:

The distance of one lap on this track from the start line to the finish line is 400 meters. Two laps around the track is 800 meters, half a lap is 200 meters, and so on.

    Remember, displacement is the direction from the starting point and the length of a straight line from the starting point to the ending point. If a runner was going to run 400 meters (one lap around the track), they would start and stop at the same place on the track. Therefore, their displacement would be 0.

Explanation:

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Answer:

[tex]\boxed {\boxed {\sf Gabi \ had \ greater \ displacement}}[/tex]

Explanation:

Displacement is the change in the position of an object.

Abigail runs a complete lap around the track, which is 400 meters. Even though she ran 400 meters, she has no displacement. If she starts and ends at the same spot, there is no change in position.

Gabi runs a 50 meter dash in a straight line. Gabi has 50 meters of displacement. She runs in a straight line and is 50 meters away from where she began.

While Abigail ran the farther distance, Gabi had the greater displacement.

Answer:

Friction is a force that tends to oppose the relative motion between two bodies in contact. Frictional force always acts on a moving body from the direction opposite to the direction of motion. It opposes the motion, and therefore, helps to reduce the speed of the moving object. It is a contact force.

After 3 seconds, the car slows down to

16 m/s + (-2 m/s²) (3 s) = 16 m/s - 6 m/s = 10 m/s

Answer: the group in an experiment that doesn’t get treatment

Explanation:

The pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

The given parameters:

The net force on the pail of water at the top of the vertical circle is calculated as follows;

[tex]T = ma - mg\\\\T = \frac{mv^2}{r} - mg\\\\T + mg = \frac{mv^2}{r} \\\\mv^2 = r(T + mg)\\\\v^2 = \frac{r(T + mg)}{m} \\\\v= \sqrt{\frac{r(T + mg)}{m}} \\\\v = \sqrt{\frac{1 (25\ + \ 2 \times 9.8)}{2}} \\\\v = 4.72 \ m/s[/tex]

Thus, the pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

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The pail’s minimum speed at the top of the circle if no water is to spill out is; v = 4.722 m/s

We are given;

Mass of the pail of water; m = 2000 g = 2kg

Radius of the circle; r = 1 m

Tension exerted by string; T = 25 N

To calculate the net force on the pail of water at the top of the vertical circle, let us take equilibrium of forces to give;

W - T = ma

Where;

W is weight = mg

T is tension on the string

Now, in circular motion, we know that;

Acceleration is; a = v²/r

Thus;

mg - T = m(v²/r)

Making v the subject of the formula gives us;

v = √[(r(T + mg)/m)

Plugging in the relevant values gives;

v = √[(1(25 + (2 * 9.8))/2)

v = 4.722 m/s

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