the prompt is in the photo

The Prompt Is In The Photo

Answers

Answer 1

By using the given box and whisker plot, the number of students that earned a score from 77 and 90 is: N. 13.

What is a box and whisker plot?

A box and whisker plot is also referred to as boxplot and it can be defined as a type of chart that can be used to graphically represent the five-number summary of a data set with respect to locality, skewness, and spread.

In Mathematics, the five-number summary of any box and whisker plot include the following:

MinimumFirst quartileMedianThird quartileMaximum

What is an interquartile range?

IQR is an abbreviation for interquartile range and it can be defined as a measure of the middle 50% of data values when they are ordered from lowest to highest.

Mathematically, interquartile range (IQR) is the difference between first quartile (Q₁) and third quartile (Q₃):

IQR = Q₃ - Q₁

Based on the given box and whisker plot, we can logically deduce the following quartile ranges:

Third quartile, Q₃ = 90

First quartile, Q₁ = 77

Now, we can calculate the interquartile range (IQR) is given by:

Interquartile range, IQR = Q₃ - Q₁

Interquartile range, IQR = 90 - 17

Interquartile range, IQR = 13

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Related Questions

F(x)=1/x g (x)=x-4 can you evaluate (golf)(0)? Explain why or why not.

Answers

If f(x) = 1/x  and g(x) = x-4 , then (gof)(0) cannot be evaluated as the function becomes not defined .

In the question

it is given that the functions

f(x) = 1/x

and g(x) = x-4

to find g=(gof)(x) ,

(gof)(x) = g(f(x))

= g(1/x)               ... because f(x) = 1/x

= 1/x - 4               ....because  g(x) = x-4

On simplifying further , we get

= (1-4x)/4x

On substituting x=0 , we get

gof(0) = (1-0)/4(0)

= 1/0

which is not defined , hence cannot be evaluated.

Therefore , if f(x) = 1/x  and g(x) = x-4 , then (gof)(0) cannot be evaluated as the function becomes not defined .

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six reduced by the product of 5 and h

Answers

6 - 5h is the answer to your question

Been looking for help for 2 hrs hopefully you can help

Answers

Given:

[tex]\begin{gathered} \mu=19.9 \\ \sigma=33.1 \\ n=40 \end{gathered}[/tex]

To Determine:

[tex]P(X>8.9)[/tex]

Solution

[tex]\begin{gathered} P(X>z) \\ z=\frac{x-\mu}{\sigma}=\frac{8.9-19.9}{33.1}=\frac{-11}{33.1}=-0.3323 \end{gathered}[/tex][tex]P(X>8.9)=1-P(X<8.9)=1-0.36982=0.63018[/tex]

Hence, P(x>8.9) = 0.6302 (nearest 4 d. p)

in order to clean her aquarium Stephanie much remove half of the water the garden measures 30 inches long 16 inches wide and 12 inches deep the aquarium is currently completely full with volume of water in cubic inches must Stephanie remove?

Answers

Hello!

30in long (length)

16in wide (width)

12in deep (height)

First, we have to calculate the volume when the aquarium is full of water, using the formula:

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a regular octagon has an area of 49 m 2 . find the scale factor of this octagon to a similar octagon with an area of 100 m 2

Answers

Given,

The area of the regular octagon is 49 square metre.

The area of the another regular octagon is 100 square metre.

[tex]\begin{gathered} \text{Scaling factor=}\frac{\sqrt{\text{area of regular polygon}}}{\sqrt[]{\text{area of another regular plogon}}\text{ }} \\ \text{Scaling factor=}\frac{\sqrt[]{\text{4}9}}{\sqrt[]{\text{1}00}\text{ }} \\ \text{Scaling factor=}\frac{7}{10\text{ }} \end{gathered}[/tex]

Here, the scaling factor of the regualar octagon is 7:10

Hence, the scaling factor is 7:10.

The standard normal curve is grafted below. Shade the region under the standard normal curve to the left of x=1.00Use the table to find the area under the standard normal curve to the left of x=1.00

Answers

Explanation

Part A

The shaded area under the standard normal curve to the left of z=1.00 can be seen below.

Part B

Using the z table, the area under the standard normal curve to the left of z.=1.00 is

Answer: 0.8413

what is the driving distance between the police station and Art Museum

Answers

First, locate the coordinate points (x,y) of each place, by looking at the graph:

Police station = (0,-4)

Art museum = (6,1)

Apply the distance formula:

[tex]D=\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex]

Replacing:

[tex]D=\sqrt[]{(6-0)^2+(1-(-4))^2}=\sqrt[]{6^2+5^2}=\sqrt[]{36+25}=\sqrt[]{61}=7.81[/tex]

Paulina bought a used car as she was entering college and planned to trade it in when she graduated four years later. She had learned in her high school financial algebra class that the average used car depreciated at an annual rate of 15%. If she had paid $13,900 for her car, how much can she expect to get when it is time for her to trade it in for a new car?

Answers

1st year

depreciable value: $13900

annual depreciation: $13900*15% = $2085

2nd year

depreciable value: $13900 - $2085 = $11815

annual depreciation: $11815*15% = $1772.25

3rd year

depreciable value: $11815 - $1772.25 = $10042.75

annual depreciation: $10042.75*15% = $1506.41

4th year

depreciable value: $10042.75 - $1506.41 = $8536.34

annual depreciation: $8536.34*15% = $1280.45

Final value: $8536.34 - $1280.45 = $7255.89

1. ¿Qué expresiones a continuación se pueden usar para encontrar el área del prisma rectangular de abajo? ¡ELIJA TODOS LOS QUE SE APLIQUEN! Nota: Puede probarlos todos para asegurarse de que sean iguales. * 15 (5x2x3) + (2x3x3) (5x2) + (5x2) + (5x2) + (5x2) 5x2x2 2 (5x2) + 2 (5x2) + 2 (2x2)

Answers

We need to find the area of the prism given in the following image:

You need to add the surfaces of ALL rectangles in the image (recall that the area of a rectangle is : Base x Height)

So for this prism we have:

FOUR rectangles that measure 5 x 2

and also TWO small squares of area 2 x 2

So we need to select all the formulas they give you that read like the addition of the two above:

(5x2) + (5x2) + (5x2) + (5x2) + (2x2) + (2x2)

It can also be written as:

2 (5x2) + 2 (5x2) + 2 (2x2)

Fiona is making a banner in the shape of a triangle for a school project. She graphs the banner on a coordinate plane with vertices at P(0, 4) , Q(2, 8) , and R(−3, 6) . She wants to reflect the banner over the line x=1. Identify the image of the banner reflected in the line x=1.

Answers

The coordinates of the banner after the reflection across x = 1 is P'(2, 4), Q'(0, 8), and R'(5, 6)

How to determine the coordinates of the banner after the reflection?

From the question, the coordinates are given as

P(0, 4), Q(2, 8), and R(−3, 6)

The line of reflection is given as

x = 1

The rule of reflection across the line x = 1 is represented as

(x, y) = (-x + 2, y)

When the above rule is applied, we have

P'(2, 4), Q'(0, 8), and R'(5, 6)

This means that the coordinate of the image are P'(2, 4), Q'(0, 8), and R'(5, 6)

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Martha's video game rental plan costs $18 per month. Which tableshows the sum of the amounts that Martha will pay for her video gamerental plan over the next 5 months?

Answers

Let's complete a table with the amounts of cost per month:

Month Sum od cost

1 18

2 2 * 18 = 36

3 3 * 18 = 54

4 4 * 18 = 72

5 5 * 18 = 90

So, please select the table that is correct

which of the following is true?Blaine and Cruz made an error in picking their first steps.Cruz made and error in picking his first step All three made an error because the right side equals -1.All three chose a valid first step toward solving the equation.

Answers

Given data:

The given expression is 4/7 (7-n)=-1.

Aaron starts with multiplying 7/4 on both sides, Blaine starts with distributive property by multiplying 4/7 with 7 and -u, Cruz starts by dividiing 4/7 on both sides.

Thus, all of them are correct, correct option is last one.

Answer: d

Step-by-step explanation: yw

Can I Plss get some help I got stuck I don’t know how to find x

Answers

Using Sine of angles to evaluate for x

The formula is,

[tex]sin\theta=\frac{Opposite}{Hypotenuse}[/tex]

Given:

[tex]\begin{gathered} Opposite=x \\ Hypotenuse=19 \\ \theta=21^0 \end{gathered}[/tex]

Therefore,

[tex]\begin{gathered} sin21^0=\frac{x}{19} \\ \therefore x=19\times sin21^0 \end{gathered}[/tex]

Simplify

[tex]x=6.80899\approx6.81\text{ \lparen2 decimal places\rparen}[/tex]

Hence,

[tex]x=6.81[/tex]

A bookstore sells a college algebra book for $90. If the bookstore makes a profit of 25% on each sale,what does the bookstore pay the publisher for each book?

Answers

Okay, here we have this:

Considering the provided information, we obtain that:

The total price = Commission of the bookstore + Payment to the publisher

Replacing:

$90=$90(0.25)+Payment to the publisher

Payment to the publisher=$90-$90(0.25)

Payment to the publisher=$90-$22.5

Payment to the publisher=$67.5

Finally we obtain that the bookstore pay $67.5 to the publisher for each book.

What is the value of x? 20/72=x/360

Answers

[tex]\begin{gathered} \frac{20}{72}=\frac{x}{360} \\ \text{You simplify the left hand side of the equation},\text{ i.e divide by 4} \\ \frac{5}{18}=\frac{x}{360} \\ \text{You cross multiply and you now have} \\ 5\times360=18x \\ \text{Divide both sides by 18 which is the coefficient of x} \\ 5\times20=x \\ 100=x \end{gathered}[/tex]

The value of x = 100

How would these look graphed ? Look at image attached .

Answers

These are two lines intersected ,in one point

One is positive inclined, the other negative.

Then now GRAPH

THEN BOTH LINES INTERSECT AT

From the diagram below, given the side lengths marked, and if we know that < C is congruent to < F, we can say that ___

Answers

SAS Similarity Theorem: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar.

AC is proportional to DE while BC is proportional to FE, but F is not the included angle between those sides, therefore, those triangles are not similar by SAS.

The Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. Since we have information only about one of the angles, ASA also doesn't apply.

For two triangles to be congruent, all of their measures must be congruent, which is not the case of our triangles.

The answer is option d. The two cannot be proven to be similar.

40% of what number is 26? Please show work!

Answers

65

1) To find that, we need to write an equation:

[tex]x(0.4)=26[/tex]

Note that we rewrote that 40% as 0.4.

2) Now, let's solve it

[tex]\begin{gathered} x0.4=26 \\ \frac{0.4x}{0.4}=\frac{26}{0.4} \\ x=65 \end{gathered}[/tex]

3) So the 26 is 40% of 65

Which equation is equivalent to: 3r=78+14 ?A. −3r=−78+14B. 3r−14=78C. 3r=78−14D. −3r=78−14

Answers

Given[tex]3r=78+14[/tex][tex]3r-14=78[/tex]The final answerOption B

4. A teacher can only make 3000 copies in a month. If a teacher-has-made 2700 copies so far this month, what percentage of her copies has she used?

Answers

In order to determine the percentage, let x as the percentage. Then, you can write:

[tex]\frac{x}{100}\cdot3000=2700[/tex]

factor x/100 is the percentage in decimal form. The product of this factor and 3000 equals 2700.

Solve for x and simplify:

[tex]x=\frac{2700}{3000}\cdot100=90[/tex]

Hence, teacher has used 90% of the copies.

400 meters to 350 meters increase or decrease

Answers

[tex]\begin{gathered} \text{percent change = }\frac{new-old}{|old|}\times100=\frac{350-400}{400}\times100 \\ =-\frac{50}{400}\times100=-\frac{5000}{400}=-12.5 \end{gathered}[/tex]

In this case we have a negative change, therefore decrease

answer: decrease

need help asap look at attachmen

Answers

The rectangle has a width of 7 yards and a length of 42 yards.

How to find the length and width?

For a rectangle of length L and width W, the perimeter is:

P  = 2*(L + W)

Here we know that:

L = 6*W

P = 98yd =  2*(L + W)

Then we have the system of equations:

L = 6*W

98yd =  2*(L + W)

If we substitute the first equation into the second one, we get:

98yd = 2*(6*W + W)

98yd = 14*W

98yd/14 = W = 7yd

So the width is 7 yards, and the length is 6 times that, so:

L = 6*7yd = 42yd

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can you help me solve this in expanded form. 156 X 687 = ?

Answers

Given data:

The given expression is 156x687.

The given expression can be written as,

[tex]\begin{gathered} (100+50+6)(600+80+7)=60000+8000+700+30000+4000+350+3600+480+42 \\ =107172 \end{gathered}[/tex]

Thus, the value of the given expression is 107172.

Your cousin is building a Sandbox for his daughter how much sand will he need to fill the Box? Explain. How much paint will he need to paint all six surface of the sandbox? Explain. 1ft 4ft 6ft not answer choices

Answers

Since the image is a rectangular prism

The volume of the box can be obtained by using the formula:

Volume = l x b x h

The box has a dimension of 1ft x 4ft x 6ft

The volume of the box = 1 x 4 x 6 = 24 cubic feet

Therefore, the volume of sand needed to fill the box will be = 24 cubic feet of sand

The surface area of the box can be obtained using the formula:

2(lb + lh + bh)

= 2(1x4 + 1x6 + 4x6)

=2(4 + 6 + 24)

=2 (34)

= 68 square feet

Therefore a total surface area of 68 square feet needs to be painted

the ratio of the length to the width of a rectangular hall is 5:3. if the width is 1500cm, find the lenght.​

Answers

Answer:Length of the rectangle= 2500 cm

Step-by-step explanation:

The ratio of the length to the width that is- length:width = 5:3

Take x as a common value,

5x= length

3x= width

Width of the rectangle= 1500 cm

3x= 1500 cm

x= 1500/3

x= 500 cm

Length of the rectangle= 5x

x=500 cm

Length= 5*500

=2500 cm

Length of the rectangle= 2500 cm

the cone has a height of 19 mm and the radius of 15 mm what is its volume use pie and round your answer to the nearest hundredth

Answers

Answer

Volume = 4,478.57 mm³

Explanation

The volume of a cone is given as

Volume = ⅓ (πr²h)

where

π = pi = 3.142

r = radius of the cone = 15 mm

h = height of the cone = 19 mm

Volume = ?

Volume = ⅓ (πr²h)

Volume = ⅓ (3.142 × 15² × 19) = 4,478.57 mm³

Hope this Helps!!!

Solve the missing elements for each problem. Use 3.14 for π. Area = πr^2; C=π D

Answers

Given,

Diameter = 32 cm

Radius

We know the radius is half of the diameter. Thus,

[tex]\begin{gathered} r=\frac{32}{2} \\ r=16 \end{gathered}[/tex]

Radius 16 cm

Circumference

The formula is:

[tex]C=\pi D[/tex]

Where

D is the diameter

So,

[tex]\begin{gathered} C=\pi D \\ C=(3.14)(32) \\ C=100.48 \end{gathered}[/tex]

Circumference = 100.48 cm

Area

The formula is:

[tex]A=\pi r^2[/tex]

Where

r is the radius

So,

[tex]\begin{gathered} A=\pi r^2 \\ A=(3.14)(16)^2 \\ A=(3.14)(256) \\ A=803.84 \end{gathered}[/tex]

Area = 803.84 sq. cm.

Find the distance between the points (5,5) and (-3,7). Round your answer to the nearest tenth, if necessary.8.2 units11.8 units3.2 units12.2 units

Answers

The formula for the distance between two points in the plane is:

[tex]d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]

So:

[tex]\begin{gathered} (x_1,y_1)=(5,5) \\ (x_2,y_2)=(-3,7) \\ d=\sqrt[]{(5-(-3))^2+(5-7)^2} \\ d=\sqrt[]{(8)^2+(-2)^2} \\ d=\sqrt[]{64+4} \\ d=\sqrt[]{68} \\ d=8.2462\ldots\approx8.2 \end{gathered}[/tex]

So, the distance is approximately 8.2 units.

Triangle KLM has KL = 28, KM = 28, and LM = 21. What is the area of the triangle?The area of AKLM is about(Simplify your answer. Round to one decimal place as needed.)

Answers

Area = (b * h)/2, b = 21 bu we don't know h, s we have to calculate it

To calculate the height "h" we can use pythagoras with a triangle rectangle with base = 21/2 = 10.5 and hypothenuse = 28, so the height "h" is:

28² = h² + 10.5² ==> h² = 28² - 10.5² = 784 - 110.25 = 673.75

h² = 673.75

h = 25.96

Now that we have the height, the Area of the triangle = (b * h)/2 = (21 * 25.96)/2 = 272.5

Answer:

272.5

Find all X values where the tangent line to the graph of the function…

Answers

Consider the function,

[tex]f(x)=6\sin x+\frac{9}{8}[/tex]

The first derivative gives the slope (m) of the tangent of the curve,

[tex]\begin{gathered} m=f^{\prime}(x) \\ m=\frac{d}{dx}(6\sin x+\frac{9}{8}) \\ m=6\cos x+0 \\ m=6\cos x \end{gathered}[/tex]

The equation of the line is given as,

[tex]y-3\sqrt[]{3}x=\frac{7}{3}[/tex]

This can be written as,

[tex]y=3\sqrt[]{3}x+\frac{7}{3}[/tex]

Comparing with the slope-intercept form of the equation of a line, it can be concluded that the given line has a slope,

[tex]m^{\prime}=3\sqrt[]{3}[/tex]

Given that the tangent to the curve is parallel to this line, so their slopes must also be equal,

[tex]\begin{gathered} m=m^{\prime} \\ 6\cos x=3\sqrt[]{3} \\ \cos x=\frac{\sqrt[]{3}}{2} \\ \cos x=\cos (\frac{\pi}{6}) \end{gathered}[/tex]

Consider the formula,

[tex]\cos A=\cos B\Rightarrow A=2k\pi\pm B[/tex]

Applying the formula,

[tex]x=2k\pi\pm\frac{\pi}{6}[/tex]

Thus, the required values of 'x' are,

[tex]x=2k\pi\pm\frac{\pi}{6}[/tex]

Therefore, options 1st and 2nd are the correct choices.

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