The side-by-side boxplots show consumer ratings of name brand and store brands of peanut butter.
name brands

al The median of name brands peanut butter is
grester thas the median of store
brands. (Hint* greater than or less than)

b) Approximately
% of name brands peanut butter data values are
greater than the median of the store brands peanut butter data values.

The Side-by-side Boxplots Show Consumer Ratings Of Name Brand And Store Brands Of Peanut Butter.name

Answers

Answer 1

a. Median for name brands is greater than the median for store brands data values in the boxplots given.

b. Approximately 75% of the data values of name brands is greater than the median of the data values of store brands.

How to Find the Median of a Data in a Boxplot?

A boxplot displays the distribution of a data such that the median is represented by the vertical line that divides the rectangular box.

25% of a data distribution is represented by the beginning of the edge of the box, while 50% is represented by the median, and 75% is represented by the point at the end of the edge of the box in the boxplot.

Therefore:

a. The median of name brands peanut butter is approximately 82-83.

The median of store brands is approximately less than 80.

Thus, we can conclude that, the median for name brands is greater than the median for store brands.

b. The median for store brands is approximately below 25% of the data values for name brands. Therefore, we would conclude that, approximately 75% of name brands data value are greater, compared to the median of the store brands data value.

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Related Questions

1 Ms. Signer has to buy pencils for her class. She goes to CVS and buys 15 pencils for $2.50. How much did she spend per pencil?*

Answers

She bought pencils for her class. She bought 25 pencils for $2.50 . The amount for each pencil can be computed below

[tex]\begin{gathered} 25\text{ pencils = \$2.50} \\ 1\text{ pencil = ?} \\ \text{cross multiply} \\ \cos t\text{ of each pencil=}\frac{2.50}{25} \\ \text{ cost of each pencil = \$}0.1 \end{gathered}[/tex]

we need to seat 200 people. A table holds 8 people How Many tables do we need ?

Answers

Kyah, this is the solution to the exercise:

People = 200

Capacity of each table = 8 people

In consequence, we need:

Number of tables = People/Capacity of each table

Replacing by the values we know:

Number of tables = 200/8

Number of tables = 25

Use the Pythagorean Theorem to find x, in simplest radical form. 20

Answers

The Pythagorean theorem states that the sum of the squares of the two sides of a right angle is equal to the square of the hypotenuse (longest side).

[tex]\begin{gathered} a^2+b^2=c^2 \\ \text{where }c\text{ is the hypotenuse, and }a\text{ and }b\text{ are the other two sides of a right triangle.} \end{gathered}[/tex]

Given: c = 20, a = 8, and b = x. Find x.

[tex]\begin{gathered} a^2+b^2=c^2 \\ (8)^2+(x)^2=(20)^2 \\ 8^2+x^2=20^2^{} \\ 64+x^2=400 \\ x^2=400-64 \\ x^2=336 \\ \sqrt{x^2}=\sqrt[]{336} \\ x=\sqrt[]{16\cdot21} \\ x=4\sqrt{21}\text{ (final answer)} \end{gathered}[/tex]

Hi, I’m really confused with this question and I’m not sure how to solve it!

Answers

SOLUTION

The figure below would help in answering the question

Let's get the slopes of the line for company G and company H

Slope m is given as

[tex]m=\frac{rise}{run}[/tex]

For company G, we have slope as

[tex]m=\frac{5}{1}=5[/tex]

For Company H, we have

[tex]m=\frac{4}{1}=4[/tex]

From the graph

Cab fare for 1 mile with company G is $7

Cab fare for 10 miles with company H is?

To get this we need to get the equation of the line H

From

[tex]\begin{gathered} y=mx+b \\ where\text{ m is slope and b is the y-intercept, we have } \\ y=4x+2 \end{gathered}[/tex]

Now substituting x for 10 in the equation, we have

[tex]\begin{gathered} y=4x+2 \\ y=4(10)+2 \\ y=40+2 \\ y=42 \end{gathered}[/tex]

Hence the cab fare for 10 miles with Company H is $42

The rate charge per mile by Company G is the slope we got as 5.

Hence the answer is $5 per mile

The rate charge per mile by Company H is the slope we got as 4.

Hence the answer is $4 per mile

Mr. Hanes places the names of four of his students, Joe, Sofia, Hayden, and Bonita, on slips of paper. From these, he intends to randomly select two students to represent his class at the robotics convention. He draws the name of the first student, sets it aside, then draws the name of the second student. Whats the probability he draws he draws Sofia then joe?

Answers

Given:

Total student = 4

Joe, Sofia, Hayden, and Bonita.

Find-:

Probability he draws Sofia then Joe.

Explanation-:

Probability: Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one.

The formula of probability:

[tex]P(A)=\frac{\text{ Number of favorable outcomes to A}}{\text{ Total number of possible outcomes}}[/tex]

For Sofia.

Total number of possible outcomes = 4

Favorable outcomes for Sofia = 1

So probability for Sofia :

[tex]P(S)=\frac{1}{4}[/tex]

After the first student set it aside.

For Joe.

Total number of possible outcomes = 3

A favorable outcome for Joe = 1

So probability for Joe.

[tex]P(J)=\frac{1}{3}[/tex]

So probability for Sofia then joe is:

[tex]\begin{gathered} P=\frac{1}{4}\times\frac{1}{3} \\ \\ P=\frac{1}{12} \end{gathered}[/tex]

A number multiplied by 2/5 is 3/20, Find the number

Answers

Answer:

3/8

Explanation:

Let the number be x.

A number multiplied by 2/5 = (2/5)x

Therefore:

[tex]\frac{2}{5}x=\frac{3}{20}[/tex]

To solve for x, first, we cross-multiply.

[tex]\begin{gathered} 2x\times20=3\times5 \\ 40x=15 \end{gathered}[/tex]

Next, we divide both sides of the equation by 40.

[tex]\begin{gathered} \frac{40x}{40}=\frac{15}{40} \\ x=\frac{3}{8} \end{gathered}[/tex]

The number is 3/8.

Learn with an example v Sharon has a red ribbon and an indigo ribbon. The red ribbon is 6 1/4 inches long. The indigo ribbon is 6 1/4 inches longer than the red ribbon. How long is the indigo ribbon?

Answers

Let R be the length of the red ribon and let I be the length of the indigo ribbon. We have that the red ribbon is 6 1/4 inches long, then:

[tex]R=6\frac{1}{4}=\frac{25}{4}[/tex]

Then, the indigo ribbon is 6 1/4 inches longer than the red ribbon. Then we have:

[tex]I=R+6\frac{1}{4}[/tex]

therefore:

[tex]I=\frac{25}{4}+\frac{25}{4}=\frac{50}{4}=\frac{25}{2}=12\frac{1}{2}[/tex]

finally, we have that the indigo ribbon is 12 1/2 inches long

What are all the rational roots of the polynomial f(x) = 20x4 + x3 + 8x² + x - 12?

Answers

Answer:

All the rational roots of the polynomial f(x) = 20x4 + x3 + 8x2 + x - 12 are 3/4 and -4/5.

Solve triangle EFG with the given parts.f = 17.78, F = 27.3°, G = 102.1°

Answers

STEP - BY - STEP EXPLANATION

What to find?

g, E and e

Given:

Step 1

Find the measure of side g using the sine ratio.

[tex]\begin{gathered} \frac{sinF}{f}=\frac{sinG}{g} \\ \\ \frac{sin27.3}{17.78}=\frac{sin102.1}{g} \\ \\ gsin27.3=17.78sin102.1 \\ \\ g=\frac{17.78sin102.1}{sin27.3} \\ \\ g\approx37.9 \end{gathered}[/tex]

Step 2

Find angle E.

[tex]E+F+G=180(sum\text{ of interior angle in a triangle\rparen}[/tex][tex]\begin{gathered} E+27.3+102.1=180 \\ \\ E=180-102.1-27.3 \\ \\ E=50.6° \end{gathered}[/tex]

Step 3

Find side e using the sine ratio.

[tex]\begin{gathered} \frac{sinE}{e}=\frac{sinF}{f} \\ \\ \frac{sin50.6}{e}=\frac{sin27.3}{17.78} \\ \\ esin27.3=17.78sin50.6 \\ \\ e=\frac{17.78sin50.6}{sin27.3} \\ \\ e\approx29.96 \end{gathered}[/tex]

ANSWER

g=37.9

E=50.6°

e = 29.96

What’s the correct Answer answer asap for brainlist please

Answers

Answer:

A. accuracy

Step-by-step explanation:

precise means to be accurate

rectangle rstw has diagonals RT and SW that intersect at Z. If RZ= 5x+8 and SW= 11x-3 find the value of x.

Answers

Answer:

19

Explanation:

We know that the diagonals of a rectangle are always equal, therefore RT = SW.

So if RZ = 5x + 8 and SW = 11x - 3, lets's go ahead and find x as shown below;

[tex]\begin{gathered} 2(5x+8)=11x-3 \\ 10x+16=11x-3 \\ 16+3=11x-10x \\ 19=x \\ \therefore x=19 \end{gathered}[/tex]

9km 87 m equals

option A = 9.087km
option B= 90.87km
option c = 0.9087km
option D= 908.7km
option e= none of these


please don't give wrong answer ​

Answers

Answer is A. 9.087km

Reason

1m = .001 km

Formula - divide m by 1000

87m = .087 km

Add the 9 km = 9.087 km

Convert 253 inches to yards using dimensional analysis.

Answers

As given by the question

There are given that the 253 inches

Now,

To convert the inches to yards, multiply the value in inches by the conversion factor 0.0277777787.

So,

[tex]253\times0.0277777787=7.0277778.[/tex]

Hence, the value of the given inches is 7.0278 yards.

I’m not firmiliar with the sun or difference of cubes (HW assignment)

Answers

Given:

[tex]125r^3-216[/tex]

Find-: Factor using the formula of the sum or difference of cube.

Sol:

Factoring sum and differences of cubs is:

[tex]\begin{gathered} x^3-y^3=(x-y)(x^2+y^2+xy) \\ \\ x^3+y^3=(x+y)(x^2+y^2-xy) \end{gathered}[/tex]

Apply for the given information.

[tex]\begin{gathered} =125r^3-216 \\ \\ =(5r)^3-(6)^3 \end{gathered}[/tex][tex]\begin{gathered} x^3-y^3=(x-y)(x^2+y^2+xy) \\ \\ (5r)^3-(6)^3=(5r-6)((5r)^2+(6)^2+(5r)(6)) \\ \\ =(5r-6)(25r^2+36+30r) \end{gathered}[/tex]


College students are offered a 6% discount on a textbook that sells for
$32.50. If the sales tax is 6%, find the cost of the textbook including the sales
tax.

Answers

32.383 is  the cost of the textbook including the sales tax.

How does sales tax work?

Government-imposed consumption taxes on the purchase of goods and services are known as sales taxes. A typical sales tax is imposed at the moment of sale, paid for by the shop, and then given to the government.

The original price of the textbook = $32.50

Also, the discount percentage = 6%

Thus, the price of the textbook after discount = 32.50 - 6 % of 32.50

                                           = 32.50 - 6 * 3250/100

                                           = 32.50 - 1.95

                                            = 30.55

Now, the sales tax = 6 %

Hence, the cost of the textbook including sales tax

                                                                                = 30.55 + 6 % of 30.55

                                                                           = 30.55 + 6 * 30.55/100

                                                                        = 30.55 + 1.833

                                                                        = 32.383

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Riley read 1 book in 2 months. If she reads at a constant rate, how many books did she read in one month? Give your answer as a whole number or a FRACTION in simplest form.On the double number line below, fill in the given values, then use multiplication or division to find the missing value.

Answers

To find out the unit rate

Divide the total books by the total months

so

1/2=0.5 books per month

the answer is 0.5 books per month

In the double number line

we have

books 0 0.5 1

months 0 1 2

Stephanie dilated the rectangle below and dimensions of the image were 24 ft by 6ft. What was the scale of the factor used?

Answers

In order to determne the scale factor, calculate the quotient in between the lengths of the sides of the rectangles, as follow:

32 ft/24 ft = 4/3

8 ft/ 6 ft = 4/3

Hence, the scale factor is 4/3

If the area of the rectangle is 4836 square feet find the length of the rectangle

Answers

Solution

- Let the length of the rectangle be x

- Let the width of the rectangle be y.

- Thus, we can interpret the lines of the question as follows:

[tex]\begin{gathered} \text{ The length is 30 less than 6 times the width can be written as} \\ x=6y-30\text{ (Equation 1)} \\ \\ \text{The area of the rectangle is 4836. This is written as:} \\ xy=4836\text{ (Equation 2)} \end{gathered}[/tex]

- Now, let us solve these two equations simultaneously.

- We shall proceed by solving the system of equations graphically.

- Wherever the graphs of Equation 1 and Equation 2 intersect represents the solution to the system of equations

- The plot of the equations is given below

- Observe that the graphs cross at two points. The first point is positive and the other, negative.

- Since we cannot have negative lengths (x) or width (y), we can discard the negative coordinates.

- Thus, the length (x) and width (y) are given below:

[tex]\begin{gathered} \text{length(x)}=156 \\ \text{width(y)}=31 \end{gathered}[/tex]

Final Answer

The length of the rectangle is 156 feet

Find the equation of the linear function represented by the table below in slope-intercept form. Answer: y=

Answers

Answer:

y = 2x + 6

Explanation:

The slope-intercept form of a linear equation can be found as:

[tex]y=m(x-x_1)+y_1[/tex]

Where m is the slope and it is calculated as:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

And (x1, y1) and (x2, y2) are values from the table. So, we can replace (x1, y1) by (0,6) and (x2, y2) by (1, 8):

Then, the slope is:

[tex]m=\frac{8-6}{1-0}=\frac{2}{1}=2[/tex]

Therefore, the equation of the line is:

[tex]\begin{gathered} y=2(x-0)+6 \\ y=2x+6 \end{gathered}[/tex]

So, the answer is y = 2x + 6

The half life of titanium - 44 , a radioactive isotope, is 63 years. If a substance starts out with 1000 kg of titanium- 44( round all the answers to the nearest hundredth of a kilogram or year) A) how much titanium- 44 will remain after 441 years ? B) how long will it be before there is only 1 kg of titanium- 44 ?

Answers

a)

Every 63 years, the amount of titanium halves.

441 years later means how many halving?

441/63 = 7 halving

We start off with 1000 and do 7 halving to get the amount of Titanium-44 after 441 years.

[tex]\begin{gathered} 1000(\frac{1}{2})^7 \\ =7.8125 \end{gathered}[/tex]

after 441 years, the amount of titanium remaining would be 7.8125 kg

b)

Let's find the point where the remaining titanium would be 1 kg.

That would be:

[tex]1=1000(\frac{1}{2})^t[/tex]

t is the time we are looking for. We can solve this using Ln(natural log):

[tex]\begin{gathered} 1=1000(\frac{1}{2})^t \\ 0.001=\frac{1}{2}^t \\ ln(0.001)=\ln (\frac{1}{2}^t) \\ \\ t=\frac{\ln (0.001)}{\ln (\frac{1}{2})} \\ t=9.965 \end{gathered}[/tex]

There is basically 9.965 halving. That would make the years approximately:

9.965 * 63 (half life) = 627.795 years (approx)

I need help with this problem.

Answers

Using tangent function:

[tex]\begin{gathered} \tan (\theta)=\frac{opposite}{adjacent} \\ \tan (T)=\frac{16}{32}=\frac{1}{2}=0.5 \end{gathered}[/tex]

Given a regular octagon and a regular nonagon, which one has the greater interior angle?(Type your answer as the name of the polygon)

Answers

Answer:

Nonagon

Explanation:

Each of the interior angles of a polygon is calculated using the formula:

[tex]\frac{180^0\mleft(n-2\mright)}{n}[/tex]

An Octagon has 8 sides, therefore:

[tex]\begin{gathered} Each\; \text{Interior Angle=}\frac{180^0(8-2)}{\square} \\ =\frac{180\times6}{8} \\ =\frac{1080^0}{8} \\ =135^0 \end{gathered}[/tex]

A Nonagon has 9 sides, therefore:

[tex]\begin{gathered} Each\; I\text{nterior Angle=}\frac{180^0(9-2)}{9} \\ =\frac{180\times7}{9} \\ =\frac{1260^0}{9} \\ =140^0 \end{gathered}[/tex]

Therefore, the nonagon has a greater interior angle.

11) What is the area of the composite figure? *7 points6 ftT T2 ft5 ft3ft220O 212223

Answers

Answer: 22

Step-by-step explanation:

The resale value V, in thousands of dollars, of a boat is a function of the number of years since the start of 2011, and the formula isV = 10.5 - 1.1t.(a) Calculate V(3).________thousand dollarsExplain in practical terms what your answer means.This means that the resale value of the boat will be______thousand dollars at the start of the year_______(b) In what year will the resale value be 6.1 thousand dollars?______(c) Solve for t in the formula above to obtain a formula expressing t as a function of V. t=______(d) In what year will the resale value be 2.8 thousand dollars?_______

Answers

Answer

a) V (3) = 7.2 thousand dollars.

In practical terms, the resale value of the boat will be 7.2 thousand dollars at the start of the year 2014.

b) t = 4years.

The resale value will be 6.1 thousand dollars in the year 2015.

c) t = 9.545 - 0.909V

d) t = 7 years.

7 years after the start of 2011 = 2018.

Explanation

We are given that the resale value (V), in thousands of dollar, of a boat is given as

V = 10.5 - 1.1t

where t = number of years since the start of 2011.

a) We are told to calculate V(3).

V = 10.5 - 1.1t

t = 3

V = 10.5 - 1.1 (3)

V = 10.5 - 3.3

V = 7.2 thousand dollars.

In practical terms, the resale value of the boat will be 7.2 thousand dollars at the start of the year 2014.

b) In what year will the resale value be 6.1 thousand dollars.

V = 10.5 - 1.1t

what is t when V = 6.1

6.1 = 10.5 - 1.1t

1.1t = 10.5 - 6.1

1.1t = 4.4

Divide both sides by 1.1

(1.1t/1.1) = (4.4/1.1)

t = 4 years.

4 years afther the start of 2011 = 2015.

c) We are asked to solve for t and obtain a formula expressing t as a function of V.

V = 10.5 - 1.1t

1.1t = 10.5 - V

Divide through by 1.1

[tex]\begin{gathered} \frac{1.1t}{1.1}=\frac{10.5}{1.1}-\frac{V}{1.1} \\ t=9.545-\frac{V}{1.1} \\ t=9.545-0.909V \end{gathered}[/tex]

t, expressed in terms of V, is t = 9.545 - 0.909V

d) We are now asked to calculate in what year will the resale value be 2.8 thousand dollars.

t = 9.545 - 0.909V

t = 9.545 - 0.909 (2.8)

t = 9.545 - 2.545

t = 7 years.

7 years after the start of 2011 = 2018.

Hope this Helps!!!

use properties of operations to write an equivalent expression. will sand image

Answers

Use properties of operations to write equivalent expressions

WRITING EQUIVALENT EXPRESSIONS USING PROPERTIES

Commutative Property of Addition :

When adding, changing the order of the numbers does not change the sum. ...

Commutative Property of Multiplication : ...

Associative Property of Addition : ...

Associative Property of Multiplication : ...

Distributive Property :

2.8 w + 5.6

= 2.8 ( w + 2 ) ----------- OPTION B

Determine the missing coordinates in the ordered pair (-1,?) so that it will satisfy the given equation

Answers

we have the equation

2x-3y=4

Remember that

if the ordered pair is a solution of the given equation, then the ordered pair must satisfy the given equation

we have the ordered pair (-1,a)

substitute the given coordinates in the equation

2(-1)-3(a)=4

-2-3a=4

solve for a

3a=-2-4

3a=-6

a=-2

therefore

the missing coordinate is -2

What is the value of x in the proportion2 1/4 = 1 1/2_________x = 3 3/5A. 2 2/5B. 5 2/5C. 8 1/10D. 12 3/20

Answers

First, we transform the mixed fractions

[tex]\begin{gathered} 2\frac{1}{4}=2+\frac{1}{4}=\frac{8}{4}+\frac{1}{4}=\frac{9}{4} \\ 1\frac{1}{2}=1+\frac{1}{2}=\frac{2}{2}+\frac{1}{2}=\frac{3}{2} \\ 3\frac{3}{5}=3+\frac{3}{5}=\frac{15}{5}+\frac{3}{5}=\frac{18}{5} \end{gathered}[/tex]

Then, we use cross multiplication

[tex]\begin{gathered} \frac{\frac{9}{4}}{x}=\frac{9}{4}\times\frac{1}{x}=\frac{9}{4x} \\ \frac{\frac{5}{2}}{\frac{18}{5}}=\frac{3}{2}\times\frac{5}{18}=\frac{15}{36} \end{gathered}[/tex]

so, we have

[tex]\frac{9}{4x}=\frac{15}{36}[/tex]

Finally, we solve for x, we multiply x on both sides

[tex]\begin{gathered} \frac{9}{4x}x=\frac{15}{36}x \\ \frac{15}{36}x=\frac{9}{4} \\ x=\frac{\frac{9}{4}}{\frac{15}{36}} \\ x=\frac{9}{4}\times\frac{36}{15} \\ x=\frac{9\times9\times4}{15\times4} \\ x=\frac{81}{15} \\ x=\frac{27}{5} \end{gathered}[/tex]

Since 27/5 = 5+2/5.Then,

[tex]x=5\frac{2}{5}[/tex]

Then the answer is the second one.

Just give me the answer please, my device is at 10%

Answers

Solve for x

We can use sine

[tex]\begin{gathered} \sin 48^0=\frac{x}{17} \\ \text{Cross multiply} \\ x=17\times\sin 48^0 \\ x\text{ =17}\times0.7431448 \\ x=12.6\text{ } \end{gathered}[/tex]

(If there is more than one answer, use the "or" button.)Round your answer(s) to the nearest hundredth.A ball is thrown from a height of 141 feet with an initial downward velocity of 21 ft/s. The ball's height h (in feet) after t seconds is given by the following.h = 141 - 21t - 16t ^ 2How long after the ball is thrown does it hit the ground?

Answers

Solution:

Given:

[tex]h=141-21t-16t^2[/tex]

To get the time the ball hit the ground, it hits the ground when the height is zero.

Hence,

[tex]\begin{gathered} At\text{ h = 0;} \\ h=141-21t-16t^2 \\ 0=141-21t-16t^2 \\ 141-21t-16t^2=0 \\ 16t^2+21t-141=0 \end{gathered}[/tex]

To solve for t, we use the quadratic formula.

[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{where;} \\ a=16,b=21,c=-141 \\ t=\frac{-21\pm\sqrt[]{21^2-(4\times16\times-141)}}{2\times16} \\ t=\frac{-21\pm\sqrt[]{441+9024}}{32} \\ t=\frac{-21\pm\sqrt[]{9465}}{32} \\ t=\frac{-21\pm97.288}{32} \\ t_1=\frac{-21+97.288}{32}=\frac{76.288}{32}=2.384\approx2.38 \\ t_2=\frac{-21-97.288}{32}=\frac{-118.288}{32}=-3.6965\approx-3.70 \end{gathered}[/tex]

Since time can't be a negative value, we pick the positive value of t.

Therefore, to the nearest hundredth, it takes 2.38 seconds for the ball to hit the ground.

Give the point-slope form of the equation of the line that is perpendicular to y= -4x/5+10 and contains P(5,6)

Answers

You have to write the equation of a line perpendicular to

[tex]y=-\frac{4}{5}x+10[/tex]

That crosses the point (5, 6)

A caracteristic of a line permendicular to another one is that its slope pf the perpendicular line is the negative inverse of the slope of the first line.

So for example if you have two lines:

1_ y=mx+b

and

2_ y=nx+c

And both lines are perpendicular, the slope of the second one will be the negative inverse of the slope of the first one, that is:

[tex]n=-\frac{1}{m}[/tex]

The slope of the given line is m=-4/5

The negative inverse is

[tex]-(\frac{1}{-\frac{4}{5}})=-(-\frac{5}{4})=\frac{5}{4}[/tex]

Now that you know the slope of the perpendicular line, use it along with the given point (5, 6)

in the slope-point formula:

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-6=\frac{5}{4}(x-5) \end{gathered}[/tex]

Other Questions
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