The table shows the average aduat weight and average life expectancy for 12 dog breeds a. Pint the data as ordered pairs. Describe the shape of the data. Show your work. Average Weight Life Expectancy 125 57. 5 62. 5 49 12 16 12. 3 12 11
Answers
The scatter plot shows that there is no strong correlation between average weight and life expectancy for the 12 dog breeds. The coefficient of correlation for this adult weight data to be -0.123, which is very near to 0.
The adult weight of a person can vary greatly depending on several factors, including genetics, age, gender, height, muscle mass, and overall health. However, a healthy weight range for adults is typically determined by body mass index (BMI), which is calculated by dividing weight in kilograms by height in meters squared.
We can use the average weight as the x-value and the average life expectancy as the y-value to represent the data as ordered pairs. Following are the ordered pairs for the provided data:
(125, 57.5)
(62.5, 49)
(12, 16)
(12.3, 12)
(11, 11)
We may plot these ordered pairs on a scatter plot to show the form of the data. As for the story:
We can observe from the scatter plot that there is no obvious pattern formed by the data points. There is no discernible pattern or connection between the two variables, and the spots are dispersed throughout the plot. As a result, the data's shape can be described as random or dispersed.
We can calculate the correlation coefficient to provide more evidence for this. The variables do not have a linear relationship if the correlation coefficient is close to zero. we can calculate the coefficient of correlation for this data to be -0.123, which is very near to 0.
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Related Questions
whats the answer
x-y=5
3x-2y=12
need to find the x and the y.
Answers
The values of x and y in the system of equations, x - y = 5 and 3x - 2y = 12, are: x = 2 y = -3
How to Solve a System of Equations?Given the system of equations:
x - y = 5 --> eqn. 1
3x - 2y = 12 --> eqn. 2
Rewrite equation 1:
x = 5 + y --> eqn. 3
Substitute x for 5 + y into equation 2:
3(5 + y) - 2y = 12
15 + 3y - 2y = 12
15 + y = 12
y = 12 - 15 [subtraction property]
y = -3
Substitute y = -3 into equation 3:
x = 5 + (-3)
x = 2
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CARD 4
Zoe opens a savings account that
earns annual compound interest. If she
doesn't make any deposits or
withdrawals after her initial deposit,
the balance in the account after x
years can be represented by the
equation below.
b(x)=675(1.045)*
D
Duncan says the
balance in the
account increases at
a rate of 45% each
year.
Daniella says the
balance in the
account increases at
a rate of 4.5% each
year.
Which answer is right
Answers
The correct answer about the savings account that Zoe opened, represented by the equation b(x)=675(1.045)ˣ is B. Daniella says the balance in the account increases at a rate of 4.5% each year.
What is an equation?An equation is a mathematical statement that two or more algebraic expressions (the combination of variables with constants and mathematical operands) are equal or equivalent.
This equation is known as the future value equation, formula, or function.
Initial investment = $675
Compound interest rate = 4.5% (0.045 x 100)
Future value factor = 1.045 (100% + 4.5%)
Based on the future value function above, we can conclude that the compound interest rate is 4.5%, which is equivalent to 0.045 as given in the equation.
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Find the necessary and sufficient conditions for the spiral if α
(t)=(at,bt^2,t^3)
is a cylindrical helix.
decide on the axis at this time.
Answers
In this case, since the curve is not a cylindrical helix, there is no well-defined axis.
A cylindrical helix is a curve in 3D space that follows the path of a cylinder as it is unwrapped along a line. The curve is parameterized by a vector function α(t) = (x(t), y(t), z(t)), where x(t) = r cos(t), y(t) = r sin(t), and z(t) = ht, with r and h being the radius and height of the cylinder, respectively.
In this case, the parameterization of the curve is given by α(t) = (at, bt^2, t^3). To determine if it is a cylindrical helix, we need to check if it follows the path of a cylinder as it is unwrapped along a line.
First, let's look at the z-coordinate, which corresponds to the height of the curve. We see that it is a cubic function of t, which means that the curve is not a horizontal line and it does not lie in a plane. This suggests that the curve may be a helix.
Next, let's look at the x and y-coordinates. The x-coordinate is a linear function of t, which means that it varies uniformly along the curve. The y-coordinate, on the other hand, is a quadratic function of t, which means that it changes faster than the x-coordinate.
This indicates that the curve may be a spiral, which is a type of helix that has an additional circular motion in the x-y plane as it moves along the z-axis. To confirm that the curve is a spiral, we need to check that the radius of the circle traced out by the curve in the x-y plane is constant.
To find the radius, we can take the derivative of the x and y-coordinates with respect to t:
dx/dt = a
dy/dt = 2bt
The radius of the circle is given by:
r = sqrt(x^2 + y^2) = sqrt(a^2 + 4b^2t^2)
We can take the derivative of r with respect to t to see if it is constant:
dr/dt = 4bt/sqrt(a^2 + 4b^2t^2)
We see that dr/dt is not constant, which means that the radius of the circle traced out by the curve is changing as it moves along the z-axis. Therefore, the curve is not a spiral.
In summary, the necessary and sufficient conditions for the curve to be a cylindrical helix are:
The z-coordinate of the curve is a linear function of t, i.e., z(t) = ht.
The radius of the circle traced out by the curve in the x-y plane is constant.
In this case, the curve does not satisfy condition 2, which means that it is not a cylindrical helix.
The axis of the curve is the line along which the cylinder is unwrapped. In this case, since the curve is not a cylindrical helix, there is no well-defined axis.
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how to rationalise root 3-1/5
Answers
[tex] \sqrt{ \frac{3 - 1}{5} } = \sqrt{ \frac{2}{5} } = \frac{ \sqrt{2} }{ \sqrt{5} } = \frac{ (\sqrt{2} )}{ (\sqrt{5}) } \frac{( \sqrt{5})}{ (\sqrt{5} )} = \frac{ \sqrt{10} }{5} [/tex]
The answer is V10/5
Consider a volleyball net that consists of a mesh with m squares on the horizontal dimension
and n squares on the vertical. What is the maximum number of strings that can be cut before
the net falls apart into two pieces? Solve the problem as a network problem.
Answers
The maximum number of strings that can be cut before the volleyball net falls apart into two pieces, considering a mesh with m squares on the horizontal dimension and n squares on the vertical dimension, is min(m+1, n+1).
To determine the maximum number of strings that can be cut before the volleyball net falls apart into two pieces, considering the mesh has m squares on the horizontal dimension and n squares on the vertical dimension, we can solve this as a network problem. Here's a step-by-step explanation:
1. Visualize the volleyball net as a graph with nodes representing the intersections of the strings and edges representing the strings themselves.
2. Observe that there are (m+1) nodes horizontally and (n+1) nodes vertically. This is because each square has a node at each corner, so there is an additional node on each side.
3. To separate the net into two pieces, you need to cut all the strings along a specific row or column of the mesh.
4. The maximum number of strings you can cut will be the minimum number of strings needed to cut through the entire mesh either horizontally or vertically.
5. If you choose to cut the strings horizontally, there will be (m+1) strings to cut for each row. Similarly, if you choose to cut the strings vertically, there will be (n+1) strings to cut for each column.
6. Compare the number of strings to cut in both directions, and choose the direction with the minimum number of strings to cut.
7. The maximum number of strings that can be cut before the net falls apart into two pieces is the minimum between (m+1) and (n+1).
So, the maximum number of strings that can be cut before the volleyball net falls apart into two pieces, considering a mesh with m squares on the horizontal dimension and n squares on the vertical dimension, is min(m+1, n+1).
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5. At practice, a soccer athlete warmed up for 8 minutes, participated in drills for 45
minutes, and scrimmaged for 17 minutes. How many total minutes of activity did this
soccer athlete complete during this practice?
110
Answers
Answer:
The soccer athlete completed 70 minutes of activity during this practice.
Step-by-step explanation:
mark brainliest
What is the equation of the following line? Be sure to scroll down first to see
all answer options.
O A. y=-¹1-x
OB. y = 2x
OC. y = 4x
O D. y = ¹/x
O E. y = -2x
F. y=x
(-4,8)
-10
10
-10-
(0,0)
10
Answers
The equation of the following line include the following: E. y = -2x .
How to determine an equation of this line?In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):
y - y₁ = m(x - x₁)
Where:
x and y represent the data points.m represent the slope.First of all, we would determine the slope of this line;
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Slope (m) = (8 - 0)/(-4 - 0)
Slope (m) = 8/-4
Slope (m) = -2.
At data point (-4, 8) and a slope of -2, a linear equation for this line can be calculated by using the point-slope form as follows:
y - y₁ = m(x - x₁)
y - 8 = -2(x + 4)
y - 8 = -2x - 8
y = -2x
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A 15-cm × 20-cm printed circuit board whose components are not allowed to come into direct contact with air for reliability reasons is to be cooled by passing cool air through a 20-cm-long channel of rectangular cross section 0. 2 cm × 14 cm drilled into the board. The heat generated by the electronic components is conducted across the thin layer of the board to the channel, where it is removed by air that enters the channel at 15°C. The heat flux at the top surface of the channel can be considered to be uniform, and heat transfer through other surfaces is negligible. The velocity of the air at the inlet of the channel does not exceed 4. 95 m/s and the surface temperature of the channel remains under 50°C. Assume that the flow is fully developed in the channel. 77777 Air 3W 15°C Air channel 0. 2 cm x 14 cm Electronic components the properties of air at a bulk mean temperature at 25C p=1. 184 kg/m k = 0. 02551 W/m°C v=1. 562x10 m/s Cy=1007 J/kg. °C Pr=0. 7296 also Nu=8. 24 Calculate the maximum total power of the electronic components that can safely be mounted on this circuit board?
Answers
The maximum total power of the electronic components that can safely be mounted on this circuit board is 4.2 W.
The maximum total power of the electronic components that can safely be mounted on the circuit board is determined by the amount of heat that can be removed from the channel by the air flow without exceeding the maximum allowable temperature of 50°C on the channel surface.
To calculate the maximum total power of the electronic components, we need to determine the heat transfer rate from the channel to the air flow
where Q is the heat transfer rate, h is the convective heat transfer coefficient, A is the surface area of the channel, and ΔT is the temperature difference between the channel surface and the air.
The convective heat transfer coefficient can be calculated using the Nusselt number correlation for flow inside a rectangular channel:
Nu = 8.24
h = 8.240.02551 /0.2 = 1.048 W/m
where L is the channel's hydraulic diameter, equal to [tex]2*(0.2*14)/(0.2+14)[/tex] = 0.278 cm = 0.00278 m.
The surface area of the channel is A = 20.220 + 20.214 + 14[tex]*20[/tex] = 120.8 cm[tex]^2[/tex] = 0.01208 [tex]m^2.[/tex]
The temperature difference between the channel surface and the air is ΔT = 50°C - 15°C = 35°C.
Therefore, the maximum heat transfer rate from the channel to the air flow is:
Q = hAΔT = 1.0480.0120835 = 0.0042 kW
This means that the maximum total power of the electronic components that can be safely mounted on the circuit board is:
P = Q = 0.0042 kW = 4.2 W
Therefore, the maximum total power of the electronic components that can safely be mounted on this circuit board is 4.2 W.
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5 1/3 divided by 3/4
Answers
Answer:
The answer to your problem is, [tex]7\frac{1}{9}[/tex]
Step-by-step explanation:
Calculation process:
= [tex]\frac{16}{3}[/tex] ÷ [tex]\frac{3}{4}[/tex]
= [tex]\frac{16}{3}[/tex] × [tex]\frac{4}{3}[/tex]
= [tex]\frac{16*4}{3*3}[/tex]
= [tex]\frac{64}{9}[/tex] = [tex]7\frac{1}{9}[/tex]
Thus the answer to your problem is, [tex]7\frac{1}{9}[/tex]
A traffic engineer developed the continuous function R, graphed above, to model the rate at which vehicles pass a certain intersection over an 8-hour time period, where R(t) is measured in vehicles per hour and t is the number of hours after 6:00 AM. According to the model, how many vehicles pass the intersection between time t = 0 and time t = 8? A. 1400 B. 1600 C. 14,400 D. 44,800
Answers
the total area under the curve is 2400.
To find the number of vehicles that pass the intersection between time t = 0 and time t = 8, we need to calculate the definite integral of the function R(t) from t = 0 to t = 8:
∫(0 to 8) R(t) dt
Looking at the graph of R(t), we can see that it consists of two parts: a rectangle with base 2 and height 600, and a triangle with base 6 and height 400. The area of the rectangle is 2 x 600 = 1200, and the area of the triangle is (1/2) x 6 x 400 = 1200. Therefore, the total area under the curve is 2400.
So, the number of vehicles that pass the intersection between time t = 0 and time t = 8 is:
∫(0 to 8) R(t) dt = 2400
Since R(t) is measured in vehicles per hour, this means that 2400 vehicles pass the intersection between time t = 0 and time t = 8. Therefore, the answer is 2400, which is not one of the given answer choices.
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QUESTION 10 During oxygen consumption measurement the participants VO2 was 1004 L/min and VCO2 was 0.932 min. What was the participants RER at that point in time? Give your answer to 4 decimal places
Answers
The participant's RER at that point in time was approximately 0.0009 (rounded to 4 decimal places).
To calculate the participant's Respiratory Exchange Ratio (RER) at that point in time, you will use the formula:
RER = VCO2 / VO2
Given the participant's VO2 was 1004 L/min and VCO2 was 0.932 L/min, plug these values into the formula:
RER = 0.932 / 1004
Now, divide 0.932 by 1004:
RER ≈ 0.0009
So, the participant's RER at that point in time was approximately 0.0009 (rounded to 4 decimal places).
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draw the graph of polynomial function
Answers
The graph of the polynomial function that passes through the points P(−2,2) and Q(1,0) is added as an attachment
Drawing the graph of polynomial functionFrom the question, we have the following parameters that can be used in our computation:
The graph passes through the points P(−2,2) and Q(1,0)
Assuming the graph is a linear function
So, we have
y = mx + c
Where
c = y when x = 0 and m = slope
This gives
-2m + c = 2
m + c = 0
Subtract the equations
So, we have
-3m = 2
m = -2/3
Solving for c, we have
-2/3 + c = 0
Evaluate
c = 2/3
So, the equation is f(x) = -2/3x + 2/3
See attachment for the graph
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Complete question
Draw the graph of polynomial function f(x) containing the points P(−2,2) and Q(1,0)
You measure 21 textbooks weights, and find they have a mean weight of 72 ounces. Assume the population standard deviation is 5.4 ounces. Based on this, construct a 90% confidence interval for the true
Answers
The 90% confidence interval for the true mean weight of the textbooks is approximately (70.062 ounces, 73.938 ounces).
Given that you measured 21 textbooks and found a mean weight of 72 ounces with a population standard deviation of 5.4 ounces, we can follow these steps:
1. Identify the sample size (n), sample mean (X), population standard deviation (σ), and confidence level (90%).
n = 21
X = 72 ounces
σ = 5.4 ounces
Confidence level = 90%
2. Determine the critical value (z) for a 90% confidence interval. For a 90% confidence interval, the critical value (z) is 1.645.
3. Calculate the standard error (SE) using the formula [tex]SE = \frac {σ }{\sqrt{n} }[/tex].
[tex]SE = \frac{5.4}{\sqrt{21} } = 1.177[/tex]
4. Calculate the margin of error (ME) using the formula ME = z * SE.
ME = 1.645 * 1.177 = 1.938
5. Construct the confidence interval using the formula: X ± ME.
Lower limit = 72 - 1.938 = 70.062
Upper limit = 72 + 1.938 = 73.938
Based on your measurements, the 90% confidence interval for the true mean weight of the textbooks is approximately (70.062 ounces, 73.938 ounces).
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Find the mean, median, interquartile range and mean absolute deviation of the set of numbers. Round to the nearest tenth, if necessary. 1, 1, 4, 8, 9, 3, 8 please help
Answers
Answer:
mean- 4.9
median- 4
interquartile range- 7
Step-by-step explanation:
Hope this helps! :)
Use the information given in Exercises 8 - 10 to find the necessary confidence bound for the binomial proportion P. Interpret the interval that you have constructed. 99% upper bound, n = 55, x = 24
Answers
The 99% upper bound for the binomial proportion P is 0.790. To find the necessary confidence bound for the binomial proportion P, we can use the formula: Upper bound = x/n + Zα/2√(x/n(1-x/n))
In this case, we are looking for a 99% upper bound, so Zα/2 = 2.576. Plugging in the given values, we get:
Upper bound = 24/55 + 2.576√(24/55(1-24/55))
= 0.526 + 2.576(0.100)
= 0.790
Therefore, the 99% upper bound for the binomial proportion P is 0.790.
Interpreting the interval, we can say that we are 99% confident that the true proportion of whatever we are measuring (which is represented by P) is no higher than 0.790. In other words, we can be fairly certain that the actual proportion falls within the interval from 0 to 0.790.
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!!!!!! I need help asap
Answers
Answer:
3.2
Step-by-step explanation:
Answer:
pythagorean theorem !!!!!!
Step-by-step explanation:
0.8²+1.6²=3.2²
0.64+2.56=10.24
THAT means the distance is
[tex] \sqrt{10.24} [/tex]
=3.2miles
The circle centered at Q is a scaled copy of the circle centered at R.
a. Find the scale factor.
ingrese su respuesta.....
840
Answers
The scale factor of the dilation of the circles is 5
What is the scale factor of the dilation?From the question, we have the following parameters that can be used in our computation:
The circles
From the circles, we have the following parameters
Diameter of big circle Q = 20
Diameter of the small circle R = 4
Using the above as a guide, we have the following:
Scale factor of the dilation = Radius of big circle/Radius o the small circle
So, we have
Scale factor of the dilation = 20/4
Evaluate
Scale factor of the dilation = 5
Hence, the scale factor of the dilation is 5
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Howto prove for root test convergence for complex number.
Answers
To prove convergence for the root test with complex numbers, we use the same approach as with real numbers.
Let's consider a series ∑an with complex terms. We can apply the root test by taking the nth root of the absolute value of each term, which gives us:
lim (n→∞) ∛|an|
If this limit is less than 1, then the series converges absolutely. If it is greater than 1, then the series diverges.
To prove convergence for the root test, we need to show that this limit is less than 1. We can do this by expressing the complex number an in polar form, such that an = rn*e^(iθn), where rn is the magnitude of an and θn is its argument.
Then, taking the nth root of the absolute value of an, we get:
|an|^1/n = (rn)^(1/n)
We can express rn as |an|*cos(θn) + i*|an|*sin(θn), and take the nth root of each term separately:
|an|^1/n = [(|an|*cos(θn))^2 + (|an|*sin(θn))^2]^(1/2n)
= |an|^(1/n) * [(cos(θn))^2 + (sin(θn))^2]^(1/2n)
= |an|^(1/n)
Since the limit of |an|^(1/n) is the nth root of the magnitude of the series, we can rewrite the root test as:
lim (n→∞) ∛|an| = lim (n→∞) |an|^(1/n)
If we can show that this limit is less than 1, then we have proven convergence for the root test with complex numbers.
One way to do this is to use the fact that |an|^(1/n) ≤ r, where r is the radius of convergence of the series. This inequality follows from Cauchy's root test, which applies to both real and complex numbers.
Therefore, if the radius of convergence of the series is less than 1, then the limit of |an|^(1/n) is also less than 1, and the series converges absolutely.
In summary, to prove convergence for the root test with complex numbers, we express each term in polar form and take the nth root of its magnitude. We then show that the limit of these roots is less than 1 by using Cauchy's root test and the radius of convergence of the series.
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Assignment Booklet 5 2 thematics 30-2 2. Solve each equation and identify the non-permissible values. Record the answers as exact values (no decimals!) harks) 2. a. 1 + X 4 х 1 b. 3n-1 3n +6 + 2 n
Answers
The non-permissible values are any values of n that would make the original equation undefined. In this case, there are no such non-permissible values.
a.
The given equation is:
[tex]1 + x^4 = x[/tex]
Rearranging terms, we get:
[tex]x^4 - x + 1 = 0[/tex]
To solve this equation, we can use the quartic formula:
x = [ -b ± sqrt( b^2 - 4ac ) ] / 2a
Here, a = 1, b = -1, and c = 1, so we have:
x = [ -(-1) ± sqrt( (-1)^2 - 4(1)(1) ) ] / 2(1)
x = [ 1 ± sqrt( -3 ) ] / 2
Since the discriminant is negative, the solutions are complex:
x = [ 1 ± i*sqrt(3) ] / 2
Therefore, the non-permissible values are any values of x that would make the original equation undefined. In this case, there are no such non-permissible values.
b.
The given equation is:
3^(n-1) / (3^n + 6) + 2^n = 0
To solve for n, we can start by simplifying the first term:
3^(n-1) / (3^n + 6) = 3^(-1) / (1 + 2*3^(-n))
Substituting this into the original equation, we get:
3^(-1) / (1 + 2*3^(-n)) + 2^n = 0
Multiplying both sides by (1 + 23^(-n)), we get:
3^(-1) + 2^n(1 + 2*3^(-n)) = 0
Simplifying, we get:
2^n + 2*3^(n-1) = 0
Dividing both sides by 23^(n-1), we get:
(1/2)(1/3)^n + 1 = 0
Multiplying both sides by -2 and taking the logarithm of both sides, we get:
n = log(2/3) / log(3) - log(2)
Therefore, the solution is:
n = log(2/3) / log(3) - log(2)
The non-permissible values are any values of n that would make the original equation undefined. In this case, there are no such non-permissible values.
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How do i solve for x?
Answers
Answer:
78° + 95° + (2x + 115)° + 72° = 360°
(2x + 360)° = 360°, so x = 0.
Find the diameter of circle O
Answers
The diameter of the circle is determined as 20.12 units.
What is the radius of the circle?The radius of the circle is calculated by applying the following formula as shown below;
The let the distance between 9 and center of the circle O = x
The radius of the circle, r = 9 + x --- (1)
Draw a line from circumference from point 10 to center O, this line is the radius = r
Apply Pythagoras theorem;
r² = 10² + x² ------ (2)
From the first equation, recall, r = 9 + x
(9 + x)² = 10² + x²
81 + 18x + x² = 100 + x²
81 + 18x = 100
18x = 100 - 81
18x = 19
x = 19/18
x = 1.06
The radius of the circle = 9 + x
r = 9 + 1.06
r = 10.06
The diameter of the circle = 2r
= 2 x 10.06
= 20.12 units
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Lines b and care parallel. Which pair of angles are alternate exterior angles?
OA. 27 and 28
OB. 21 and 22
OC. 23 and 26
OD. 21 and 28
SUBMIT
Answers
angle 1 and angle 8 are alternate exterior angles.
option D.
What are alternate exterior angles?Alternate exterior angles are pairs of angles that are located on opposite sides of a transversal line intersecting two parallel lines, and their values are equal.
These angles are positioned in such a way that they are outside of the two parallel lines, but on opposite sides of the transversal.
For the given diagram, the alternate exterior angles are determined as;
angle 1 and angle 8 are alternate exterior angles.
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General Chemistry Homework(2) Calculate the following: 1- molecular mass for the compound CgH10N402? Answer M for CgH10N402 (g/mol)= 2-Determine the percent composition for the element C, H, N, O in the compound CgH10N402? Answer %C= %H= %N= %0= 3- The total Percent composition for all the element in the compound CgH10N402? Answer The total Percent= + %
Answers
The total percent composition for all the elements in the compound CgH10N402 is 61.73%.
To calculate the molecular mass of CgH10N402, we need to add up the atomic masses of all the atoms in the compound. The atomic masses can be found on the periodic table.
The molecular formula indicates that the compound contains:
1 carbon atom (C) with atomic mass of 12.01 g/mol
10 hydrogen atoms (H) with atomic mass of 1.01 g/mol
1 nitrogen atom (N) with atomic mass of 14.01 g/mol
4 oxygen atoms (O) with atomic mass of 16.00 g/mol
Molecular mass (M) = (1 x 12.01) + (10 x 1.01) + (1 x 14.01) + (4 x 16.00) = 162.14 g/mol
Therefore, the molecular mass for the compound CgH10N402 is 162.14 g/mol.
To determine the percent composition of each element in the compound, we need to divide the mass contribution of each element by the total molecular mass and multiply by 100%.
Percent composition of C:
Mass contribution of C = 1 x 12.01 g/mol = 12.01 g/mol
% C = (12.01 g/mol / 162.14 g/mol) x 100% = 7.41%
Percent composition of H:
Mass contribution of H = 10 x 1.01 g/mol = 10.10 g/mol
% H = (10.10 g/mol / 162.14 g/mol) x 100% = 6.23%
Percent composition of N:
Mass contribution of N = 1 x 14.01 g/mol = 14.01 g/mol
% N = (14.01 g/mol / 162.14 g/mol) x 100% = 8.63%
Percent composition of O:
Mass contribution of O = 4 x 16.00 g/mol = 64.00 g/mol
% O = (64.00 g/mol / 162.14 g/mol) x 100% = 39.46%
Therefore, the percent composition for the element C, H, N, O in the compound CgH10N402 are:
%C = 7.41%
%H = 6.23%
%N = 8.63%
%O = 39.46%
The total percent composition for all the elements in the compound must add up to 100%.
Total percent composition = %C + %H + %N + %O = 7.41% + 6.23% + 8.63% + 39.46% = 61.73%
Therefore, the total percent composition for all the elements in the compound CgH10N402 is 61.73%.
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Find mLMN.
5 cm
N
M
L
14.3 cm
Answers
Applying the formula for the length of an arc, the measure of angle LMN is approximately: 164°.
What is the Length of an Arc?The length of an arc (s) = ∅/360 × 2πr, where r is the radius of the circle.
Given the following from the image attached below, we have:
Reference angle (∅) = m<LMN
length of an arc (s) = 14.3 cm
Radius (r) = 5 cm
Plug in the values:
∅/360 × 2π × 5 = 14.3
∅/360 × 10π = 14.3
∅/360 = 14.3/10π
∅ = 14.3/10π × 360
∅ ≈ 164°
The measure of angle LMN ≈ 164°
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7. Use the following figure to answer questions a-d.
a. Find the perimeter of the figure if the following is true:
a = x + 7
b = 2x + 2
C = 8x
d = x + 10
b. What is the perimeter of the figure in part
(a) if x = 4
c. What is the perimeter of the figure in part (b)
if x = 2 ?
d. Find the perimeter of the figure if the following
is true:
a = x2
b = 4x + 8
c = 2x²
d = x
Answers
a) The perimeter of the figure [tex]p = 12x + 19[/tex]
b) The perimeter of the figure when [tex]x = 4[/tex] is 67 units.
c) The perimeter of the figure when[tex]x = 2[/tex] is 43 units
d) The perimeter of the figure is [tex]3x^2 + 5x + 8[/tex] units.
a) The perimeter P of the figure is the sum of the lengths of its sides:
[tex]P = a + b + c + d[/tex]
Substituting the given expressions for a, b, c, and d in terms of x, we get:
[tex]P = (x + 7) + (2x + 2) + (8x) + (x + 10)[/tex]
[tex]= 12x + 19[/tex]
b) Substituting x = 4, we get:
[tex]P = 12x + 19[/tex]
[tex]= 12(4) + 19[/tex]
[tex]= 67[/tex]
Therefore, the perimeter of the figure when [tex]x = 4[/tex] is 67 units.
c) Substituting [tex]x = 2,[/tex] we get:
[tex]P = 12x + 19[/tex]
[tex]= 12(2) + 19[/tex]
[tex]= 43[/tex]
Therefore, the perimeter of the figure when[tex]x = 2[/tex] is 43 units.
d) Substituting the given expressions for a, b, c, and d in terms of x, we get:
[tex]P = x^2 + (4x + 8) + 2x^2 + x[/tex]
[tex]= 3x^2 + 5x + 8[/tex]
Therefore, the perimeter of the figure when[tex]a = x^2, b = 4x + 8, c = 2x^2,[/tex] and [tex]d = x[/tex] is [tex]3x^2 + 5x + 8[/tex] units.
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y1= sin(x) y2= sin(2x) y3= sin(3x) % 1st plot is to be red and dashed % 2nd plot is to be blue and solid % 3rd plot is to be black and dotted The plot ranges from -6 to 6 in steps of 0.2. Use enough steps so that the plots are smooth. You must include a title ('Multiple Plots'), X-axis label ('x'), y-axis label ('Sine functions') and also a legend ('sin(x)', 'sin(2x)', 'sin(3x)'). In additional, use the grid on and axis equal command.
Answers
To create a plot with three different sine functions, we can use MATLAB code that includes the "plot" function, as well as specific parameters to set the ranges, colors, and styles of each line. First, we need to set up the x-axis range using the "range" function, which takes in the minimum, maximum, and step size values. In this case, we want the range to be from -6 to 6 with steps of 0.2, so we can write:
x = (-6:0.2:6);
Next, we can define each y value using the sine function and the corresponding multiple of x. For example, y1 corresponds to sin(x), so we can write:
y1 = sin(x);
Similarly, we can define y2 and y3 as:
y2 = sin(2*x);
y3 = sin(3*x);
Now, we can use the "plot" function to create a graph with all three sine functions plotted together. We want each function to be plotted with a different color, style, and legend label, so we can specify these parameters in the "plot" function call. Specifically, we want:
- y1 to be plotted in red and dashed
- y2 to be plotted in blue and solid
- y3 to be plotted in black and dotted
- a legend to be added with the labels 'sin(x)', 'sin(2x)', and 'sin(3x)'
- a title to be added with the label 'Multiple Plots'
- an x-axis label to be added with the label 'x'
- a y-axis label to be added with the label 'Sine functions'
Here is the complete code:
x = (-6:0.2:6);
y1 = sin(x);
y2 = sin(2*x);
y3 = sin(3*x);
plot(x, y1, 'r--', 'LineWidth', 1.5, 'DisplayName', 'sin(x)');
hold on;
plot(x, y2, 'b-', 'LineWidth', 1.5, 'DisplayName', 'sin(2x)');
plot(x, y3, 'k:', 'LineWidth', 1.5, 'DisplayName', 'sin(3x)');
title('Multiple Plots');
xlabel('x');
ylabel('Sine functions');
legend('show', 'Location', 'northwest');
grid on;
axis equal;
The "hold on" command ensures that all three plots are shown on the same graph. The "LineWidth" parameter sets the width of each line, and the "DisplayName" parameter sets the label for each line in the legend. Finally, the "grid on" and "axis equal" commands add a grid to the graph and ensure that the x and y axes are scaled equally.
Overall, this code will create a graph with three smooth sine functions plotted together, each with a different color, style, and legend label.
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Why are t value larger than the corresponding z value?
Answers
The t-value is generally larger than the corresponding z-value because the t-distribution has heavier tails than the standard normal distribution. This means that the t-distribution has more probability in the tails than the standard normal distribution. As a result, the critical values for the t-distribution are larger than the corresponding critical values for the standard normal distribution.
Another reason for this difference is that the t-distribution takes into account the variability of the sample mean, which is estimated using the sample standard deviation. In contrast, the standard normal distribution assumes that the population standard deviation is known and fixed.
When the sample size is small, the t-distribution is more appropriate because it accounts for the additional uncertainty introduced by estimating the population standard deviation from the sample. As the sample size increases, the t-distribution approaches the standard normal distribution, and the difference between the t-value and the corresponding z-value decreases.
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the melting point of each of 16 samples of a certain brand of hydrogenated vegetable oil was determined, resulting in a sample mean of 94.32. assume the distribution of melting point is normal with a population standard deviation of 1.20. does the true mean melting point differ from 95? use a significance level of 0.01
Answers
We do not have enough evidence to conclude that the true mean melting point differs from 95 at a significance level of 0.01.
To determine if the true mean melting point differs from 95, we can use a one-sample t-test with a significance level of 0.01.
The null hypothesis is that the true mean melting point is equal to 95, and the alternative hypothesis is that the true mean melting point is different from 95.
We can calculate the t-statistic using the formula:
t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))
where sample size is 16, sample mean is 94.32, hypothesized mean is 95, and sample standard deviation is the same as the population standard deviation of 1.20.
Plugging in these values, we get:
[tex]t = (94.32 - 95) / (1.20 / \sqrt{(16)} ) = -2.6667[/tex]
Using a t-distribution table with 15 degrees of freedom (n-1=16-1), and a two-tailed test at a significance level of 0.01, the critical t-value is ±2.947.
Since our calculated t-value of -2.6667 falls within the acceptance region (-2.947 < -2.6667 < 2.947), we fail to reject the null hypothesis.
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which of the following situations can use the binomial probability distribution? group of answer choices a sampling of 100 parts to determine whether or not they meet specifications.
Answers
The situation that can use the binomial probability distribution is a sampling of 100 parts to determine whether or not they meet specifications.
The binomial probability distribution is used to model the probability of a certain number of successes in a fixed number of independent trials, where each trial has only two possible outcomes: success or failure. In the given situation, each part in the sample either meets the specifications (success) or does not (failure), which makes it a binomial experiment.
To use the binomial probability distribution, we need to know the probability of success (p) and the number of trials (n). In the given situation, we can determine the probability of a part meet specifications based on the given specifications, and the number of trials is fixed at 100, as we are sampling 100 parts.
Using the binomial probability distribution, we can calculate the probability of a certain number of parts meeting specifications out of the 100 sampled parts. This can be useful in determining whether the sample meets the expected specifications or if there are any issues with the manufacturing process.
In summary, the binomial probability distribution can be used in the given situation of sampling 100 parts to determine whether or not they meet specifications, as it involves a fixed number of independent trials with only two possible outcomes.
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Pls help y’all I’m struggling
Answers
The area of the square is 49 in². (third option)
The area of the circle is 75.39 in². (fourth option)
The area of the shaded portion is 26.39 in².(first option)
What are the area of the shapes?A square is a quadrilateral with four equal sides.
Area of a square = length²
7² = 49 in²
A circle is a bounded figure which points from its center to its circumference is equidistant.
Area of a circle = πr²
Where :
π = pi = 3.14R = radius3.14 x 4.9² = 75.39 in²
Area of the shaded portion = area of circle - area of square
75.39 in² - 49 in² = 26.39 in²
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