Answer:
The time take for the journey can be calculated by dividing the total distance by the distance travelled in an hour.
Which is 2171 (Total distance) / 520 (Distance travelled in a hour)
[tex]2171/520 = 4.175[/tex]
Which can be rounded of to 4.2
It takes 4.2 hours for the flight between Los Angeles and Toronto
At a conference 1 car was provided for every 4 people if there were 17 cars how many people were there
Answer:
just multiply 17×4=?
and it will give u an anserew..
Answer:68 people
Step-by-step explanation:
You take the 17 cars multiplied by four people and you get 68
fine the value of x. please help
The algebraic expression should often take one of the following forms: addition, subtraction, multiplication, or division. Bring the variable to the left and the remaining values to the right to determine the value of x. To determine the outcome, simplify the values.
How do you find the value of x/ In algebra, the letter "x" is frequently used to denote an unknown value. It is referred to as a "variable" or occasionally a "unknown. "x is a variable in x + 2 = 7, but we can figure out its value if we try! The order in which you perform operations in arithmetic and algebra is governed by a number of laws. The Commutative, Associative, and Distributive Laws are the three that receive the most attention.People have discovered over time that the sequence of the numbers has no bearing on the results of addition or multiplication.x+ 38+103= 180
x+141 =180
x =180- 141
x = 39
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Given two terms from a geometric sequence, identify the first term and the common ratio: a10 = 1 and a12=1/25
Given:
a denotes first term and r denotes the common ratio.
[tex]a_{10}=1\colon a_{12}=\frac{1}{25}[/tex][tex]a_n=ar^{n-1}[/tex][tex]a_{10}=ar^{10-1}[/tex][tex]1=ar^9\ldots.\text{ (1) }[/tex][tex]a_{12}=ar^{12-1}[/tex][tex]\frac{1}{25}=ar^{11}\ldots.(2)[/tex]Divide the equation (2) by (1)
[tex]\frac{\frac{1}{25}}{1}=\frac{ar^{11}}{ar^9}[/tex][tex]\frac{1}{25}=r^2[/tex][tex]r=\pm\frac{1}{5}[/tex][tex]\text{If r=}\frac{1}{5}[/tex][tex]1=a(\frac{1}{5})^9[/tex][tex]a=1953125[/tex][tex]\text{If r=-}\frac{1}{5}[/tex][tex]1=a(-\frac{1}{5})^9[/tex][tex]a=-1953125[/tex][tex]a=-1953125\text{ ; r = -}\frac{1}{5}[/tex][tex]a=1953125\text{ ; r = }\frac{1}{5}[/tex]Which of the following are polynomials? Check all that apply.
The power of each term in the expressions is D and E are positive integer. So, the expressions are a polynomial.
What are polynomials?A polynomial is a type of algebraic expression in which the exponents of all variables should be a whole number. The exponents of the variables in any polynomial have to be a non-negative integer. A polynomial comprises constants and variables, but we cannot perform division operations by a variable in polynomials.
A) [tex]x^{-2}+15x-3[/tex]
Here, the exponent of x is -2. So, the expression is not a polynomial.
B) [tex]-x^3+5x^2+7\sqrt{x} -1[/tex]
Here, the power of one of the term is 1/2. So, the expression is not a polynomial.
C) [tex]\frac{3}{5}x^4-18x^2+5-\frac{10}{x^2}[/tex]
Here, the power of one of the term is -2. So, the expression is not a polynomial.
D) 5.3x²+3x-2
Here, the power of each term is positive integer. So, the expression is a polynomial.
E) [tex]4x^4-10[/tex]
Here, the power of each term is positive integer. So, the expression is a polynomial.
The power of each term in the expressions is D and E are positive integer. So, the expressions are a polynomial.
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According to the distributive property, a(5 + b) =
Answer:
From the bit that you have given , we can say = 5a + ab = to the rest of the equation
two functions are given below: f(x) and h(x). state the axis of symmetry for each function and explain how to find it
HELP ME PLEASE
The axis of symmetry for function
f(x) is x = 8 and for h(x) is x = 3.
We know that the quadratic equation in vertex form is, y = a (x - m)² + n
where (m, n) is the vertex of the parabola.
And, the axis of symmetry is x = m.
Consider function f(x)
f(x) = -4(x - 8)² + 3
This function represents a quadratic equation in vertex form with vertex (8, 3)
So, the axis of symmetry for function f(x) would be x = 8
We know that the axis of symmetry is the vertical line that goes through the vertex of a parabola so the left and right sides of the parabola are symmetrical.
Consider the function h(x)
We can observe that the vertex of parabola is (3, 2)
So, the axis of symmetry would be x = 3.
Therefore, the axis of symmetry for function
f(x) is x = 8 and for h(x) is x = 3.
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mad elf is a holiday beer that is 11.0% abv. a 12 oz bottle of mad elf has 300 calories. the rest of the calories, other than alcohol, come from carbohydrates. approximately how many grams of carbohydrates are in mad elf?
The bottle contains 9.36 g of carbohydrates.
We have,
12 oz bottle contains 300 calories
We know, 1 oz = 23.35 g
12 oz = 12 * 23.35 g =280.2 g of bottel
Alcohol content = 11 %
So, the total number of alcohol in the bottle is [tex]\frac{11}{100} *280.2 = 30.8 g[/tex]
So, the bottle contains 30.8 g of alcohol.
1 gram of alcohol 7 cal of energy,
So, 30.8 g of alcohol = 7 * 30.8 cal of energy
= 215.7 cal of energy
So, out of a total of 300 calories of mad elf, 215.7 calories come from alcohol.
So, (300-215.7 ) = 84.3 calories come from carbohydrates.
Each gram of carbohydrate produces 9 calories of energy.
9 calories of energy from 1 gram of carbohydrate,
1 calorie of energy from 1/9 of carbohydrate.
So, 84.3 calories from [tex]\frac{1}{9}*84.3 = 9.36 g[/tex]
Hence, the bottle contains 9.36 g of carbohydrates.
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3 3 Luke started a weight-loss program. The first week, he lost x pounds. The second week, he lost 2 pounds less than 2 times the pounds 3 he lost the first week. The third week, he lost 1 pound more than ã of the pounds he lost the first week. 3 Liam started a weight-loss program when Luke did. The first week, he lost 1 pound less than 2 times the pounds Luke lost the first 5 week. The second week, he lost 4 pounds less than 2 times the pounds Luke lost the first week. The third week, he lost 2 pound more 5 than 3 times the pounds Luke lost the first week. Assuming they both lost the same number of pounds over the three weeks, complete the following sentences. 4 pounds 6 pounds 21 4 2 pounds 13 - 40Luke started a weight loss program the first week he lost X pounds the second week he lost 3/2 pounds less than 3/2 times the pounds he lost the first week the third week he lost 1 pound more than three-fourths of the Pouncey lost the first week
We know that Luke lost x pounds the first week.
We also know that the second week 3/2 less than 3/2 times the pounds he lost the first week, this means that the secons week he lost:
[tex]\frac{3}{2}x-\frac{3}{2}[/tex]Finally the third week he lost 1 pound more than 3/4 of the pounds he lost the first week. This can be written as:
[tex]\frac{3}{4}x+1[/tex]Hence luke lost a total of:
[tex]x+\frac{3}{2}x-\frac{3}{2}+\frac{3}{4}x+1=\frac{13}{4}x-\frac{1}{2}[/tex]Therefore the expression for Luke's weight loss is:
[tex]\frac{13}{4}x-\frac{1}{2}[/tex]Liam lost the first week 1 pound less than 3/2 times the loss Luke had the first week this can be express as:
[tex]\frac{3}{2}x-1[/tex]The second week he lost 4 pounds less than 5/2 times the loss of Luke the firs week then we have:
[tex]\frac{5}{2}x-4[/tex]Finally Liam lost 1/2 pound more than 5/4 times the loss of Luke the first week, then:
[tex]\frac{5}{4}x+\frac{1}{2}[/tex]Adding this we have:
[tex]\frac{3}{2}x-1+\frac{5}{2}x-4+\frac{5}{4}x+\frac{1}{2}=\frac{21}{4}x-\frac{9}{2}[/tex]Therefore Liam's expression is:
[tex]\frac{21}{4}x-\frac{9}{2}[/tex]Now, we know that both of them lost the same weight, then we have the equation:
[tex]\frac{13}{4}x-\frac{1}{2}=\frac{21}{4}x-\frac{9}{2}[/tex]Solving for x we have:
[tex]\begin{gathered} \frac{13}{4}x-\frac{1}{2}=\frac{21}{4}x-\frac{9}{2} \\ \frac{21}{4}x-\frac{13}{4}x=\frac{9}{2}-\frac{1}{2} \\ \frac{8}{4}x=4 \\ x=\frac{4}{\frac{8}{4}} \\ x=2 \end{gathered}[/tex]Therefore Luke lost 2 pound the first week.
Finally we plug the value of x in the expression for Luke's weight loss to get the total amount over the three weeks:
[tex]\begin{gathered} \frac{13}{4}(2)-\frac{1}{2}=\frac{13}{2}-\frac{1}{2} \\ =\frac{12}{2} \\ =6 \end{gathered}[/tex]Therefore they lost 6 pounds in three weeks.
Two cylinders have the same volume. The first has a radius of 5cm and a height of 10 cm. The second has a radius of 10cm. The surface area of the first cylinder is and the surface area of the second i s
ANSWER
[tex]\begin{gathered} 1)150\pi \\ 2)250\pi \end{gathered}[/tex]EXPLANATION
For the first cylinder;
[tex]\begin{gathered} r=5 \\ h=10 \end{gathered}[/tex]Recall, the formula for calculating the surface area of a cylinder is;
[tex]A=2\pi rh+2\pi r^2[/tex]Now, substitute the values for the first cylinder;
[tex]\begin{gathered} A=2\pi rh+2\pi r^{2} \\ =2\times\pi\times5\times10+2\times\pi\times5^2 \\ =100\pi+50\pi \\ =150\pi \end{gathered}[/tex]The volume of the first cylinder is calculated using the formula;
[tex]\begin{gathered} V=\pi \cdot \:r^2\cdot \:h \\ \end{gathered}[/tex]Substitute the values of r and h for the first cylinder;
[tex]\begin{gathered} V=\pi \cdot \:r^2\cdot \:h \\ =\pi\times5^2\times10 \\ =\pi\times25\times10 \\ =250\pi \end{gathered}[/tex]To get the surface area of the second cylinder, we need to calculate the height (h).
To get the height, we use the volume of the first cylinder to get the height of the second (since they have the same volume).
Hence;
[tex]\begin{gathered} V=250\pi \\ r=10 \\ V=\pi r^{2}h \\ 250\pi=\pi\times10^2\times h \\ h=\frac{V}{\pi \cdot \:r^2} \\ h=\frac{250\pi }{\pi 10^2} \\ =2.5 \end{gathered}[/tex]Substitute the height to calculate the surface area is calculated thus;
[tex]\begin{gathered} A=2\pi rh+2\pi r^{2} \\ =2\times\pi\times10\times2.5+2\times\pi\times10^2 \\ =50\pi+200\pi \\ =250\pi \end{gathered}[/tex]The time in seconds that it takes an object to fall d feet can be found
using the expression ((sqrt(d))/(4)) , Suppose aiden drops a tennis ball from a height of 50 feet at the same time masons drops a similar tennis ball from a height of 20 feet . How much longer will it take Aiden's tennis ball to reach the ground than Mason's tennis ball? Round to the nearest hundredth .
Aiden's tennis ball will reach the ground 0.65 seconds than Mason's tennis ball
How to determine the time difference in reaching the groundThe function of time with respect to distance is given as
(sqrt(d)/(4))
Rewrite the function properly
This is represented as follows
√d/4
It can also be written as
t = 1/4√d
From the question, we have
Aiden = 50 meters
Mason = 20 meters
The time difference is then calculated as
T = t₁ - t₂
So, we have
T = 1/4√d₁ - 1/4√d₂
The equation becomes
T = 1/4√50 - 1/4√20
This gives
T = 1/4(√50 - √20)
Evaluate
T = 0.65
Hence, the time difference is 0.65 seconds
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PLS HELP DUE NOWWWWWWWWWW
The correct statement will be:
A. The rate of change is the number of inches grown per month, and the initial value is the starting height.
We can form the following equation from the given data:
H(m) = 13 + 41m,
Where H ( Height ) is a function of the number of months ( m ).
We can see that the height changes with respect to months i.e. as the number of months increases, the height of the sunflower also increases.
The initial value or the initial height of the sunflower remains constant throughout and has less impact on its height.
So, option A will be the ultimate explanation for the data given.
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Answer:
Step-by-step explanation:
This is a linear function of time, as mentioned.
A linear function is always in the form of:
[tex]y=mx+b[/tex]
The 'sunflower's height is a linear function of time', so the [tex]x[/tex] variable represents the time (which is in terms of months here), and the [tex]y[/tex] would represent the sunflower's height after time has passed.
The initial value is when [tex]x=0[/tex].
[tex]x=0[/tex] means at the very beginning.
At the very beginning, the height would be the starting height, so the initial value would be the starting height.
The rate of change means the change in [tex]y[/tex] in respect to [tex]x[/tex].
Since [tex]y[/tex] represents the height after [tex]x[/tex] months, the rate of change would be the change in height per month.
You could also write it as the number of inches grown per month.
The initial value is the starting height, and the rate of change is the number of inches grown per month, so the correct answer is (A).
the owner of a small deli is trying to decide whether to discontinue selling magazines. he suspects that only 8.4% of his customers buy a magazine and he thinks that he might be able to use the display space to sell something more profitable. before making a final decision, he decides that for one day he will keep track of the number of customers that buy a magazine. assuming his suspicion that 8.4% of his customers buy a magazine is correct, what is the probability that exactly 3 out of the first 11 customers buy a magazine?
The probability that exactly 3 out of the first 11 customers buy a magazine is 2.23%
The proportion of customers that buy a magazine = 8.4%
If 3 out of the first 11 customers buy a magazine, then this proportion is given as; 3/11 or 27.27%
Therefore, the probability that 3 out of the first 11 customers will buy a magazine is calculated as follows;
probability = 8.4% × 27.27%
probability = (8.4/100) × (27.27/100)
probability = 0.084 × 0.2727
probability = 0.0223
Converting it into percentage as follows;
probability = 0.0223 × 100
probability = 2.23%
Therefore, the probability that 3 out of the first 11 customers buy a magazine is calculated to be 2.23%.
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can you take 73 devided by 17 and it be a whole number
Find the value of x that satisfies the given conditions. Then graph the line on a separate sheet of paper.
The line containing (4, -2) and (x,-6) is perpendicular to the line containing (-2, -9) and (3,-4).
The value of x will be 8.
And, Graph of the line y = -x + 2 is shown in figure.
What is Equation of line?
The equation of line passing through the points (x₁ , y₁) and (x₂, y₂) with slope m is defined as;
y - y₁ = m (x - x₁)
Where, m = (y₂ - y₁) / (x₂ - x₁)
Given that;
The condition is;
The line containing the points (4, -2) and (x,-6) is perpendicular to the line containing the points (-2, -9) and (3,-4).
Since, Multiplication of Slopes of perpendicular lines are -1.
That is;
m₁ m₂ = -1
Where, m₁ is slope of first perpendicular line and m₂ is slope of second perpendicular line.
Now, Find the slopes of lines as;
m₁ = (-6 - (-2)) / (x - 4)
m₁ = - 6 + 2 / x - 4
m₁ = - 4 / (x - 4)
And, Slope of second line,
m₂ = (-4 - (-9)) / (3 - (-2))
m₂ = (-4 + 9) / (3 + 2)
m₂ = 5 / 5
m₂ = 1
Hence,
m₁ m₂ = -1
Substitute all the values, we get;
- 4 / (x - 4) × 1 = -1
4 = x - 4
x = 4 + 4
x = 8
Thus, The points on the line is (4 , -2) and (8 , -6).
So, Slope (m₁) = (- 6 - (-2)) / (8 - 4)
= (-6 + 2) / 4
= - 4 / 4
= -1
Thus, The equation of line passing through the points (4 , -2) and
(8 , -6) with slope -1 is;
y - (-2) = - 1 (x - 4)
y + 2 = -x + 4
y = - x + 4 - 2
y = - x + 2
Therefore,
The value of x will be 8.
And, Graph of the line y = -x + 2 is shown in figure.
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all you need is in the photo please answer fastplease
Answer:
The cost of cupcakes and cookies are;
[tex]\begin{gathered} \text{cupcakes = \$2.75} \\ \text{cookies = \$3.00} \end{gathered}[/tex]Explanation:
Let x and y represent the cost of a cupcake and cookie respectively.
Given that;
Five cupcakes and two cookies cost $19.75.
[tex]5x+2y=19.75-------1[/tex]Two cupcakes and four cookies cost $17.50.
[tex]2x+4y=17.50-------2[/tex]Let's solve the simultaneous equation by elimination;
multiply equation 1 by 2;
[tex]10x+4y=39.50-------3[/tex]subtract equation 2 from equation 3;
[tex]\begin{gathered} 10x-2x+4y-4y=39.50-17.50 \\ 8x=22 \\ \text{divide both sides by 8;} \\ \frac{8x}{8}=\frac{22}{8} \\ x=2.75 \end{gathered}[/tex]since we have the value of x, let substitute into equation 1 to get y;
[tex]\begin{gathered} 5x+2y=19.75 \\ 5(2.75)+2y=19.75 \\ 13.75+2y=19.75 \\ 2y=19.75-13.75 \\ 2y=6 \\ y=\frac{6}{2} \\ y=3.00 \end{gathered}[/tex]Therefore, the cost of cupcakes and cookies are;
[tex]\begin{gathered} \text{cupcakes = \$2.75} \\ \text{cookies = \$3.00} \end{gathered}[/tex]
Please answer only if you know the answer thank you.
The equation of a line passing through the point (7, 8) with slope as -3 is option (A) 3x + y - 29 = 0 or y = -3x + 29
In the above question,
It is given that a line that passes through a point = (7 ,8)
The slope of the line = m = -3
The inclination of a line with respect to the horizontal is measured numerically is called as Slope
We know the slope intercept form of the line is
( y - y1) = m (x - x1)
where (x1 , y1 ) = ( 7 , 8)
and m = -3
Putting values in the slope intercept form of line, we get
( y - 8) = -3 ( x - 7)
y - 8 = -3x + 21
3x + y -8 - 21 = 0
3x + y - 29 = 0
y = -3x + 29
Hence, The equation of a line passing through the point (7, 8) with slope as -3 is y = -3x + 29
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Darnell and emma are college students . darnell currently has 22 credits and he plans on taking 6 credits per semester . emma has 4 credits and plans to take 12 credits per semester . after how many semesters , s will darnell and emma have the same number of credits ?
After 3 semesters Darnell and Emma have same number of credits as 40.
Given,
Current credit score of Darnell = 22
Current credit score of Emma = 4
Darnell plans to score a credit per semester = 6
Emma plans to score a credit per semester = 12
Now, we have to find that after how many semesters will Darnell and Emma have the same number of credits .
Here,
Current credit score of Darnell = 22
Current credit score of Emma = 4
After 1 semester,Credit score of Darnell = 22 + 6 = 28
Credit score of Emma = 4 + 12 = 16
After 2 semester,Credit score of Darnell = 28 + 6 = 34
Credit score of Emma = 16 + 12 = 28
After 3 semester,Credit score of Darnell = 34 + 6 = 40
Credit score of Emma = 28 + 12 = 40
That is,
After 3 semesters Darnell and Emma have same number of credits as 40
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If the following fraction is reduced, what will be the exponent on the p ? -
2
5
4
3
The p has an exponent of 3 when the fraction is reduced
How to determine the exponent on p?The expression is given as
5p^5q^4/8p^2q^2
Remove all other variables, except the variable p
So, we have the following expression
p^5/p^2
Apply the law of indices in the above expression
So, we have the following equation
p^5/p^2 = p^5 - 2
Evaluate the difference
p^5/p^2 = p^3
The index on p is 3
Hence, the exponent on the p is 3
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Complete question
If the following fraction is reduced, what will be the exponent on the p? - 5p^5q^4/8p^2q^2 5 4 3 2
Use the number line shown below. What is the location of Z between X and Y such that the length of ZY is 3 times the length of XZ.
-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
X = -5
Y = 4
Answer:
z is -2
Step-by-step explanation:
x = -5 y = 4
<----------------------------------------->
-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
Z is between x and y but is 3 times the lenght of x&z
so jumb from -5 to -3 thats one, however jumb from -2 to 0 that is 1, and form 0 to 2 that is 2, and from 2 to 4 that is 3.
ILL Give one hundred points and Branly only if you do it right though
Answer:
1) -2
2) -2
3) -2
4) -3
5) -4
6) -15
7) -13
8) 3
1b) -9
2b) -2
3b) 7
4b) 17
5b) -4
6b) -9
7b) -16
8b) 0
1c) -5
2c) -3
3c) 0
4c) -2
5c) -8
6c) -11
7c) -3
8c) 15
Jeez, I hope this helps xD
45 POINTS PLEASE HELP!!!
Decide whether inductive or deductive reasoning is used to reach the conclusion
the wolf population in a park has increased each year for the last 10 years. So, the wolf population will increase again next year
consider a normal distribution with mean 20 and standard deviation 9. what is the probability a value selected at random from this distribution is greater than 20? (round your answer to two decimal places.)
The probability that a value selected at random from this distribution is greater than 20 is 0.5.
What is a probability with normal distribution?
The majority of the observations are centered around the middle peak of the normal distribution, which is a continuous probability distribution that is symmetrical around its mean. The probabilities for values that are farther from the mean taper off equally in both directions.
Here,
Let us assume that X follows a normal distribution.
If X follows a normal distribution, then
z = (X−μ) /σ, follows a standard normal distribution.
The probability of a value selected at random from this distribution is greater than 20:
P (X > 20) = 1 − P (X ≤ 20)
P ((X − μ) / σ > 20) = 1−P((X − μ) / σ ≤ 20)
P (z > (20 − 20) /5) = 1 − P (z ≤ (20−20 / 5))
P (z > 0) = 1 − P (z ≤ 0)
The value of probability is obtained from the standard normal table as:
P (z > 0) = 1 − P (z ≤ 0)
= 1 - 0.5
= 0.5
Hence, the probability that a value selected at random from this distribution is greater than 20 is 0.5.
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HELp ASAP PLSSSPLSPLSPLSS
(view attatched image
Answer:
Ok...I've worked out the math and the correct answer should be the first one...
x | g(x)
1 | -2
2 | 4
3 | 10
Step-by-step explanation:
Hope this helps!!
Write a polynomial function, p(x), with degree 3 that has p(7) =0
The polynomial function, p(x), with degree 3 that has p(7) = 0 is p(x) = [tex]x^{3} -7x^{2} +12x-84=0[/tex].
According to the question,
We have the following conditions to find the polynomial function, p(x):
The degree has to be 3 and the value of p(7) should be 0.
Now, we are sure that we have one term as [tex]x^{3}[/tex].
Now, when 7 has to be multiplied three times we have 343 as the result.
So, we will try to make it zero in the next term.
The next term can be[tex]-7x^{2}[/tex] because we will get -343 and the result of the first two terms will be 0.
Now, the third term can be 12x (you can take any term but we have to make sure that the end result is 0).
Now, the result will be 84 when we put 7 in place of x.
Now, we can have -84.
So, we will add these 4 terms to form the polynomial function:
p(x) = [tex]x^{3} -7x^{2} +12x-84=0[/tex]
Hence, the required polynomial function is p(x) = [tex]x^{3} -7x^{2} +12x-84=0[/tex].
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I REALLY NEED HELP WITH FACTORISING AFTER THIS CAN WE PLEASE DO SOME QUESTIONS BASED ON IT
Step 1:
Write the expression
[tex]14x^2\text{ }-\text{ x - 3}[/tex]Step 2:
To factorize the expression, multiply the leading coefficient with the constant term.
[tex]\begin{gathered} \text{Leading coefficent = 14} \\ \text{constant term = -3} \\ =\text{ 14 }\times\text{ -3 = -42} \end{gathered}[/tex]Step 4
Choose two numbers whose product is -42 and the sum is -1 (that is the coefficient of x)
[tex]\begin{gathered} \text{The two numbers are: 6 and -7} \\ \text{Then, split -x into -7x and 6x} \\ \text{Therefore} \\ 14x^2-x-3=14x^2\text{ - 7x + 6x }-3 \\ 14x^2\text{ - 7x + 6x - 3} \\ \text{Pair two terms and factor out the co}mmon\text{ factors} \\ 7x(2x\text{ - 1) + 3(2x - 1)} \\ (2x\text{ - 1)(7x + 3)} \end{gathered}[/tex]Final answer
(2x - 1)(7x + 3)
Wxyz is a parallelogram in the coordinate plane. the vertices for the parallelogram are w(0,0), (b,c), y (a + b,c), and z(a,0), where a > 0,b > 0, and c> 0 what set of statements prove that the diagonals of the parallelogram bisect each other?
The diagonals WY and XZ intersect at E, we must prove that WE ∼ = YE and XE ∼ = ZE. The converse exists also true: If the diagonals of a quadrilateral bisect each other, then the quadrilateral exists as a parallelogram.
Why quadrilateral WXYZ is a parallelogram?WXYZ cannot be a parallelogram because the value of x that creates one pair of sides congruent does not create the other pair of sides congruent.
Given that WXYZ, let the diagonals WY and XZ intersect at E, we must prove that WE ∼ = YE and XE ∼ = ZE. The converse exists also true: If the diagonals of a quadrilateral bisect each other, then the quadrilateral exists as a parallelogram.
A rhombus, therefore, contains all the properties of a parallelogram: Its opposite sides exist parallel. Its opposite angles exist equally. Its diagonals bisect each other.
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help please i need it
pls explain with working out
Answer: 26m
Step-by-step explanation:
The area is 36m^2, the possible measurement that could've worked is 4m for width and 9m for length (4x9=36). Now just do 4+4+9+9 = 26m.
Hope this helped
Students make 93.5 ounces of liquid soap for a craft fair they put the soap in a 8.5 ounce bottles and sell each bottle for 5.50 how much do the students earn if they sell all the bottles of liquid soap
For a craft show, students make 93.5 ounces of liquid soap. They package the soap in 8.5 ounce bottles and charge $5.50 per bottle. The students will earn $60.5.
Given that,
For a craft show, students make 93.5 ounces of liquid soap. They package the soap in 8.5 ounce bottles and charge $5.50 per bottle.
We have to find how much money will the students make if they sell all the liquid soap bottles.
Total amount of liquid soap prepared by the students for a craft fair = 93.5 ounces
Weight of each bottle in which students poured the soap = 8.5 ounces
Let us first calculate the number of bottles, each contains 8.5 ounces of soap from 93.5 ounces of soap.
So, Number of bottles = 93.5/8.5
= 11
So, 11 bottles are prepared which contains 8.5 ounces of soap from 93.5 ounces of soap.
The amount at which each bottle is sold = $5.50
The total amount earned by selling all the bottles of liquid soap = 11×5.50
= $60.5
Therefore, the students will earn $60.5 if they sell all the bottles of liquid soap.
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If a train runs on a circular track of radius 400 meters through all four sections of the park, about how long is the part of the train track that runs through Water World?
The arc length is given by:
[tex]s=2\pi r(\frac{\theta}{360})[/tex]In this case the radius is 400 m and the angle is 36°, plugging these values we have:
[tex]\begin{gathered} s=2\pi(400)(\frac{36}{360}) \\ s=251.33 \end{gathered}[/tex]Therefore, the part of the train track that runs through water world is approximately 250 meters.